in which area of the galaxy would you find stars with fairly circular orbits about the galactic center?

The degree measure of angle ∠ bac will be 70°. Option C is correct.

The angle is the distance between the intersecting lines or surfaces. In addition, the angle is expressed in degrees. The angle is 360 degrees for a full revolution.

Given expression;

[tex]\rm cos^{-1}(\frac{3.4}{10})=x \\\\ x = cos^{-1}(0.34) \\\\ x = 70.12^0[/tex]

The degree measure of angle ∠bac will be 70°.

Hence option C is correct.

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Answer:

70 Degrees

Explanation:

Geometry B E2020!! :3

Answer:

zero

Explanation:

Because if the object is not in motion then it only posseses potential energy not kinetic energy

Answer:

See below

Explanation:

vertical velocity=13.9 sin 25

When it hits the ground  y = 0

0 = vo t - 1/2 a t^2

0    =  13.9 sin 25  t   - 1/2 (9.81)t^2  

0 = 13.9 sin 25 - 1/2 (9.81) t        shows t = 1.1976  ~ 1.2 sec

horizontal speed x time = distance

13.9 cos 25   x   1.1976 =15 .1 meters    

The point along the line connecting the two charges is the total electric field due to the two charges equal to zero will be 0.3056.

The electric field strength is defined as the ratio of electric force and charge. The field's direction is determined by the direction of the force acting on the positive charge.

The megnitude of the electric field for charge 1 is;

[tex]\rm E_1 = (9 \times 10^9 )\times \frac{0.700 \times 10^{-9}}{x^2}[/tex]

The megnitude of the electric field for charge 1 is;

[tex]\rm E_2 = 9.0 \times 10^9 \times \frac{9.00 \times 10^{-9}}{(1.80-x)^2}[/tex]

The net electric field at point p is;

[tex]\rm \frac{0.700}{x^2} = \frac{9.00}{(1.40-x)^2} \\\\( \frac{1.40-x}{x} )^2 = \frac{9.00}{0.700} \\\\\ \frac{1.40-x}{x}=3.58 \\\\ \frac{140}{x} -1=3.58\\\\\ \frac{140}{x}=3.58+1\\\\ x=0.3056 \ m[/tex]

Hence, the point along the line connecting the two charges is the total electric field due to the two charges equal to zero will be 0.3056.

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The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three. Option B is correct.

Assume the side length of the cube under consideration is L units. The volume of the cube is then equal to L³ cubic units.

The volume of a cube is;

V = L³

Ubes have equal-length sides. The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three.

Hence option B is correct.

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Answer:

chemical energy, Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic

Explanation:

hope it will help you

Answer:

will you mark brainliest.

Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force between them the power of the gravitational pressure among gadgets relies upon on factors, mass and distance. the pressure of gravity the loads exert on every other.

Gravitational pressure -an appealing pressure that exists among all items with mass; an item with mass draws every other item with mass; the value of the pressure is immediately proportional to the loads of the 2 items and inversely proportional to the rectangular of the gap among the 2 items.

Since the gravitational pressure is immediately proportional to the mass of each interacting items, greater large items will entice every different with a more gravitational pressure. So because the mass of both item increases, the pressure of gravitational appeal among them additionally increases.

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It is much easier to balance a thing that has a large base of support and a low center of gravity. The object won't topple over as a result of little center of gravity wobble because of the wide base and low center of gravity. Therefore, balancing a nail on its base as opposed to its tip would be simpler.

Answer:

a?

Explanation:yes it is a

A car initially traveling at 15.0 m/s accelerates at a constant rate of 4.50 m/s2 over a distance of 45.0 m, the time taken to cover this distance  is mathematically given as

t = 2.24 s

Generally, the equation for Kinematic relation is mathematically given as

S = ut + (1/2)at^2

Therefore

45 = 15t + 2.25 t^2

2.25 t^2 + 15 t -45 = 0

t = 2.24 s

In conclusion, the time is taken to cover this distance

t = 2.24 s

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Given that one marble is twice as heavy as the other, the correct statement is: the heavier marble has twice as much kinetic energy as the lighter one

KE = PE = mgh

KE₁ = mgh

KE = PE = mgh

KE₂ = 2mgh

KE₂ / KE₁ = 2mgh / mgh

KE₂ / KE₁ = 2

Cross multiply

KE₂ = 2 × KE₁ =

KE₂ = 2KE₁

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#a

This is because red color has higher wavelength and it can clear universe and our atmosphere better,

This has the same reason as how we can see only red color during sunset.

#b

[tex]\boxed{\sf z=\dfrac{ \lambda-\lambda_o}{\lambda_o}}[/tex]

lambda_o be x

Put values

[tex]\\ \rm\Rrightarrow 7.6=\dfrac{2\times10^{-6}-x}{x}[/tex]

[tex]\\ \rm\Rrightarrow 7.6=\dfrac{2\times 10^{-6}}{x}-1[/tex]

[tex]\\ \rm\Rrightarrow 8.6=\dfrac{2\times 10^{-6}}{x}[/tex]

[tex]\\ \rm\Rrightarrow x=0.23\times 10^{-6}m[/tex]

[tex]\\ \rm\Rrightarrow x=0.23\mu m[/tex]

Answer:

If a sound increases 5 db, the sound becomes three times louder.

Explanation:

The vector which shows the velocity of the yo-yo at this moment is A and is denoted as option A.

This is referred to the rate of change of distance with time and the unit is metre per seconds.

A shows the direction of motion is same as the direction of velocity and is the tangent at that particular point hence why it was chosen as the most appropriate choice.

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The statements that describe a benefit of the scientific method are as follows:

Thus, the correct options are B, C, and D.

The scientific method may be defined as a strategy of research in which a problem is recognized, relevant data is collected, a conjecture is composed of this data, and the assumption is empirically tested to determine the outcome of particular research.

The scientific method never explains or provides an answer to any question immediately because it consists of a scripted format with certain parameters.

The scientific method uses the identical vocabulary for sharing information with one another in particular terminology.

Therefore, it is well described above.

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Step-by-step explanation:      

Step 1: Formula

10.0 = Meters

800 = Newtons

4.0 = Centre of Gravity

Explanation in words (Short Form)

-  We know all the formulas and that we are calculating the least force being applied. We know that balancing the pole at (A) with the weight of the gravity will equal more force at B times 10. So the answer will be 320 N because the B force will equal 3200. If we divide 3200 by 10. The answer will result as 320. So the final answer for this question is 320N

Answer:  

Balancing the pole at A with the weight acting at the centre of gravity = 800(4) Force at B multiplied by 10 = 3200 divided by 10 equals 320N

= 320N

Hope this helps.

Taking into account the definition of density, the volume of the metal block is 3 m³.

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density=\frac{mass}{volume}[/tex]

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

In this case, you know that:

Replacing in the definition of density:

[tex]5000 \frac{kg}{m^{3} } =\frac{15000 kg}{volume}[/tex]

Solving:

volume×5000 [tex]\frac{kg}{m^{3} }[/tex]= 15000 kg

volume= [tex]\frac{15000 kg}{5000 \frac{kg}{m^{3} }}[/tex]

volume= 3 m³

In summary, the volume of the metal block is 3 m³.

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Answer:

See below

Explanation:

3 minutes = 180 seconds

v f = at  =  .5 m/s^2 * 180 s = 90 m/s

Distance =  1/2 a t^2 = .5 * .5 * 180^2 = 8100 m

The Milky Way, a member of the "Local Group," is different than other galaxies in the universe. First, it is brighter than most galaxies that we have been able to see. Second, the Milky Way is a barred spiral galaxy; unlike typical spiral galaxies, barred spiral galaxies have flat discs in their centers.

Answer:

The Milky Way Galaxy, is a spiral galaxy, meaning that there are multiple arms spiraling in toward the middle of the galaxy. Are there any other galaxies in the universe shaped like the Milky Way Galaxy?

Answer:

3586

Explanation:

by using formula s=it+0.5at^2

Answer:

[tex]\fbox {Velocity = 60 m/s, Distance = 3600 m}[/tex]

Explanation:

Part (i) : Velocity at end of 2 minutes

Equation used ⇒ [tex]\boxed {v = u + at}[/tex]

⇒ t = 2 minutes = 2 x 60 = 120 seconds

⇒ v = 0 + (0.5)(120)

⇒ v = 60 m/s

Part (ii) : Distance covered

Equation used ⇒ [tex]\boxed {S = \frac{v^{2}-u^{2}}{2a}}[/tex]

⇒ S = (60)² - (0)² / 2(0.5)

⇒ S = 3600 m

The answer to the question is 1.125  Newton

Formula for electrostatic force is F = ( K q1 q2 )/ r²

where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.

Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.

Electrostatic force between q1 and q3

r will be 0.500 + 0.500 = 1 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²

F₁₃ = 2.25  × 10⁻¹ N

Electrostatic force between q2 and q3

r will be 0.500 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²

F = (225 × 10⁻³) / (25 × 10⁻²)

F₂₃ = 9 × 10⁻¹ N

Total force on q3 will be F₁₃ + F₂₃

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 11.25  × 10⁻¹ ) N

Total force on q3 =  1.125  N

Thus after solving we got the net force on q3 as 1.125  Newton

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The material used before doubling will produce light at a frequency of 0.056 Hz.

The number of times a wave occurs repeatedly in a second is known as frequency.

The formula provides the frequency as,

[tex]\rm v = \lambda \times f \\\\\ \rm f = \frac{v}{\lambda} \\\\ \rm f = \frac{3 \times 10^8}{532 \times 10^-9} \\\\ \rm f = 3 \times 10^{12} \\\\ f= 0.056 \ Hz[/tex]

Therefore, the material used before doubling will have an output light frequency of 0.056 Hz.

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Answer:

Answer 740 H z, 1110 H z, 1480 H z

Explanation:

The F sharp note (370 Hz) makes the next three harmonics with frequencies of 740 Hz, 1110 Hz, and 1480 Hz, respectively.

It is necessary to have an understanding of the relationship between harmonics and the fundamental frequency in order to calculate the frequencies of the following three harmonics produced by the note F sharp, which has a pitch of 370 Hz.

The fundamental frequency, denoted by f1, is the first harmonic and corresponds to the frequency of the note (F sharp in this example) when it was initially played. Its pitch is 370 hertz.

The fundamental frequency (f1) is multiplied by two to get the second harmonic frequency (f₂), which is written as f₂ = 2 × f1.

The frequency of the third harmonic (f₃) is equal to three times the frequency of the fundamental tone, or f₃ = 3 × f₁.

The frequency of the fourth harmonic, denoted by f₄, is equal to four times the frequency of the fundamental tone. f₄ = 4 × f₁

If we know that the fundamental frequency, or f₁, is 370 hertz, then we can figure out the frequencies of the following three harmonics, which are as follows:

f₂ = 2 × 370 Hz, which equals 740 Hz

f₃ = 3 times 370 Hz, which equals 1110 Hz; f₄ = 4 times 370 Hz, which equals 1480 Hz

Following the frequency of the F sharp note (370 Hz), the next three harmonics produced have frequencies of 740 Hz, 1110 Hz, and 1480 Hz respectively.

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Hi!

Inside an electric motor, permanent magnets are set onto a ring surrounding a coil of wire. The communicater mother is what makes it spin

Explanation:

An atmosphere (atm) is a unit of measurement equal to the average air pressure at sea level but liquid pressure is exerted on the surface of an object in a liquid.

And they also differ in formulas. We can calculate atmospheric pressure in two ways. First we can get the atmospheric pressure by an instrument called barometer. And the second one is by usin this formula, atmospheric pressure = density of mercury x acceleration due to gravity x height of column of mercury. But this equation will only work if the atmospheric pressure is being measured by mercury.

But the formula for liquid pressure is defferent and the instrument used to measure the liquid pressure is also defferent.

The instrument used to measure the liquid pressure is pressure gauge. And the formula for the liquid pressure is density x height x gravity. Please give me a like and thank me.

please.

Answer:

a) 22.2 N

Explanation:

To find load effort. Identify load, efficiency and velocity ratio (VR)

Here given:

Effort :

[tex]\rightarrow \sf \dfrac{MA}{VR} = \dfrac{Load \ \div \ efficiency }{VR} = \dfrac{100 \div 75 \% }{6} = 22.22 \ N[/tex]

Answer:

B.1/2v1 that's the answer

The statement which best describes Deena's error is: B. Include the area of the rectangle under the line to find displacement for constant acceleration.

A velocity vs. time graph can be defined as a type of graph that is used to graphically represent the rate of change of velocity of an object with respect to time.

Based on the information provided in the table shown (see attachment), the statement which best describes Deena's error is her not including of the area of the rectangle under the line, so as to enable her find displacement for constant acceleration.

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Complete Question:

Deena made a chart to summarize features of a velocity vs. time graph for objects with constant acceleration and objects with constant velocity.

Which best describes Deena's error?

A. The line for constant velocity is not horizontal; it is diagonal and slopes downward.

B. Include the area of the rectangle under the line to find displacement for constant acceleration.

C. Find acceleration by finding the area of the rectangle above the line.

D. Find velocity by calculating the slope of the line.