Answer:
The distance (in miles) by the bus up the hill when its speed decreased to 50 mph is approximately 1.353 miles
Explanation:
The parameters of the motion of the driver are;
The upgrade of the road, θ = 10°
The rate of constant acceleration of the bus driver = 5 ft./s²
The speed of the bus as it begins to go up the hill, v₁ = 80 mph = 117.3228 ft./s
The speed of the driver at a point on the hill, v₂ = 50 mph ≈ 73.32677 ft./s
The acceleration due to gravity, g ≈ 32.1740 ft./s²
Therefore, we have;
The acceleration due to gravity down the incline plane, gₓ = g·sinθ
∴ gₓ = g·sin(θ) ≈ 32.1740 ft./s² × sin(10°) ≈ 5.587 ft/s²
The net acceleration of the bus, on the incline plane, [tex]a_{Net}[/tex] = gₓ - a = 5.587 ft./s² -5 ft./s² = 0.587 ft./s²
The vertical component of the velocity, [tex]v_y[/tex] = v × sin(θ)
∴ [tex]v_y[/tex] = 117.3228 ft./s × sin(10°) ≈ 20.37289 ft./s
vₓ = 117.3228 ft./s × cos(10°) ≈ 115.5404 ft./s
The velocity of the car, v₂, on the inclined plane is given as follows;
v₂ = v₁ - [tex]a_{Net}[/tex] × t
∴ t = (v₁ - v₂)/[tex]a_{Net}[/tex] = (117.3228 ft./s - 73.32677 ft./s)/(0.587 ft./s²) ≈ 74.95 s
The distance covered, 's', is given as follows;
s = v₁·t - 1/2·[tex]a_{Net}[/tex]·t²
∴ s = 117.3228 × 74.95 - 1/2 × 0.587 × 74.95² ≈ 7144.6069 ft.
The distance travelled up the hill, s ≈ 7144.6069 ft. ≈ 1.3531452 miles ≈ 1.353 miles
What is any push or pull on an object called?
Answer:
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.
Explanation:
is 250 000 miles from the earth to the moon" is a qualitative
Observation
TRUE
Or false
Answer:
True
Explanation:
what are the types of energy sources based on
time of replacement ? write down their names
Answer:
solar energy
wind power
geothermal energy
hydraulic power
biomass energy
energy storage
(That's all I know).
what are the importance of regulare
health examination.
Answer:
The purpose of regular health examination is to evaluate health status, screen for risk factors and disease, and provide preventive counseling interventions. The major benefits of regular health examination is early detection of treatable disease.
We assume the foam plate has a positive charge when rubbed with paper towels.
Lift the pan away from the charged plate using the styrofoam cup. Briefly touch the rim of the pan to neutralize it. Place the neutralized pan on the plate and observe the tape rise. When the pan is on the plate, the rim of the plate has a _____________. This means that the pan base is ________________ charged because the net charge on the pan is __________. You know that this must be the case because as you lift the pan with the cup away from the plate, the tape on the rim goes down.
Answer:
POSITIVE CHARGE, NEGATIVE CHARGE, ZERO
Explanation:
To solve this completion exercise, we must remember that charges of the same sign repel each other and in a metallic object (frying pan) the charge is mobile.
Let's analyze the situation when we touch the pan, the charges are neutralized, therefore when we bring the pan to the plate that has a positive charge, it attracts the mobile negative charges in the pan, until it is neutralized, therefore on the opposite side of the pan. pan (edge with a glued tape) is left with a positive charge; therefore the edge and the tape, which is very light, have positive charges and repel each other.
We must assume that the frying pan is insulated so that the net charge is zero, since the induction process.
Consequently the words to complete the sentence are
When the pan is on the plate, the edge of the plate has a _POSITIVE CHARGE_____.
This means that the base of the container is loaded NEGATIVE CHARGE_____ because the net charge of the container is ___ZERO_
The power of a wave comes from the wave's ..
Answer:
waves energy i think
Explanation:
How could being mindful in conversation be helpful?
You can see if the person your talking to and being mindfull they will see respect towards you or they see you as a mindful person.It shows a person that you care.
Explanation:
Cloudy days tend to have a greater range of temperatures than clear days. True or false?
Answer:
true
Explanation:
Answer:
true
Explanation:
A makeshift sign hangs by a wire that is extended over an ideal pulley and is wrapped around a large potted plant on the
roof as shown in the figure below. When first set up by the shopkeeper on a sunny and dry day, the sign and the pot are in
equilibrium. The mass of the sign is 27.5 kg, and the mass of the potted plant is 67.5 kg.
Plant
sale
today!
(a) Assuming the objects are in equilibrium, determine the magnitude of the static friction force experienced by the
potted plant.
N
(b) What is the maximum value of the static friction force if the coefficient of static friction between the pot and the
roof is 0.707?
N
Answer:I know the answer for B cus I’m doing the same problem. For B, you would only take the coefficient of friction given and then multiply it by the Normal Force, which in this case is the same as the Gravitational Force.
Explanation:
Mr. Voytko wants to know how high in meters he can lift an 0.3 kg apple with 7.35 joules?
Answer:
the height above the ground through Mr. Voytko lifted the apple is 2.5 m.
Explanation:
Given;
energy of Mr. Voytko, E = 7.35 J
mass of the apple, m = 0.3 kg
Apply the principle of conservation of energy.
Energy of Mr. Voytko = Potential energy of the apple due to its height above the ground.
E = mgh
where;
h is the height above the ground through Mr. Voytko lifted the apple.
g is acceleration due to gravity = 9.8 m/s²
h = E / (mg)
h = 7.35 / (0.3 x 9.8)
h = 2.5 m
Therefore, the height above the ground through Mr. Voytko lifted the apple is 2.5 m.
Given that Carbon-14 has a half-life of 5700 years, determine how long it would take for
this reduction to occur.
Answer:It will take about 3000 years
Explanation:
Two charged particles exert a force of 0.042 N on each other. Suppose that the particles are moved such that they are now one-eighth as far apart. What is the new force between the particles?
Answer:
New force = 2.688 N
Explanation:
Given that,
Two charged particles exert a force of 0.042 N on each other.
Let the initial distance is r. Later the particles are moved such that they are now one-eighth as far apart.
New distance, r' = (r/8)
The force between particles is given by :
[tex]F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{8})^2}\\\\F'=\dfrac{kq_1q_2}{\dfrac{r^2}{64}}\\\\F'=64\times \dfrac{kq_1q_2}{r^2}\\\\F'=64\times F\\\\F'=64\times 0.042\\\\F'=2.688\ N[/tex]
So, the new force is 2.688 N.
A 69.0 kg ice skater moving to the right with a velocity of 2.61 m/s throws a 0.22 kg snowball to the right with a velocity of 25.2 m/s relative to the ground. (a) What is the velocity of the ice skater after throwing the snowball
Answer:
0.08m/s
Explanation:
Given data
M1= 69kg
v1= 2.61m/s
M2= 0.22kg
v2= 25.2m/s
Before snowball is thrown:
Total mass of skater + snowball = 69+ 0.22 = 69.22kg
Total Momentum of skater + snowball = mv = 69.22 x 2.61 = 180.7 kgm/s
After snowball is thrown:
Let's call the velocity of the skater V.
Total momentum = momentum of skater + momentum of snowball
=69.22V + (5.544)
= 69.22V + 5.544
So:
180.7 = 69.22V+5.544
180.7- 5.544= 69.22V
175.156= 69.22V
V= 175.156/69.22
V = 2.53m/s
The total momentum after catching the snowball is mV or:
(69.0 + 0.22) x V
So:
5.544= 69.22V
V= 5.544/69.22
V=0.08m/s
The velocity of the ice skater after throwing the snowball is 0.08m/s
HELP PLS!
(LOOK AT THE PICTURE)
A squirrel drops an acorn onto the head of an unsuspecting dog. The acorn falls 20 m before it lands on the dog. Ignore air resistance. How many seconds did the acorn fall?
Answer:
2 seconds
Explanation:
From the question,
Applying the equation of motion for a body falling under gravity
s = ut+1/2gt²................................. Equation 1
Where, s = hieght of fall, u = initial velocity, t = time, g = acceleration due to gravity.
Given: s = 20 m, u = 0 m/s, t = ?, g = 10 m/s²
Substitute these values into equation 1
10 = 0(t²)+1/2(10×t)
10 = 5t
Solve for t
5t/5 = 10/5
t = 2 seconds
How much time does it take a dropped object to fall 180 m on Earth?
18 s
36 S
10 s
6s
Answer:
6s
Explanation:
Assume it is dropped from rest and the gravitational acceleration is 10
By the equation of motion under constant acceleration:
[tex]s=ut+\frac{1}{2} at^2[/tex]
180 = (0)t+10(t^2)/2
t = 6 or -6 (rejected)
t = 6 s
A 60 kg student weighs 600 N.
He does a bungee jump.
Calculate the change in gravitational potential energy as the student falls 50 m.
Give the unit.
Will give brainliest!
Answer:
30 000 J/Nm
Explanation:
60 x 10 x 50
=600 x 50
=30000 J/Nm
The change in gravitational potential energy of the student is 18000 Joule.
What is gravitational potential energy?
The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.
Given parameters:
Mass of the student: m = 60 kg.
Weighs of the student: W = 600 N.
the student falls h =50 m.
Hence, change in gravitational potential energy of the student =
Weighs of the student × change in height
= 600 N × 30 m
= 18000 Joule.
So, the change in gravitational potential energy of the student is 18000 Joule.
Learn more about potential energy here:
https://brainly.com/question/24284560
#SPJ2
what is the relation of pressure of a liquid with its depth and density?
Answer:
★ Pressure and depth have a directly proportional relationship. This is due to the greater column of water that pushes down on an object submerged. Conversely, as objects are lifted, and the depth decreases, the pressure is reduced.
Explanation:
Hope you have a great day :)
When talking about the products of photosynthesis, why is it a HUGE issue when a vast amount of the rainforests is dying along with vast amounts of forests from fires/deforestation? Remember, we know that this hurts the ecosystems of animals living there, but what else does it effect?
Question 5 options:
the creation of too much smoke
the creation of carbon dioxide
the creation of carbon monoxide
the creation of oxygen
Answer:
the creation of oxygen
Explanation: i just took the k12 test :)
You are standing on the bottom of a lake with your torso above water. Which statement is correct?
a. You feel a buoyant force only when you momentarily jump up from the bottom of the lake.
b. There is a buoyant force that is proportional to the weight of your body below the water level.
c. There is a buoyant force that is proportional to the volume of your body that is below the level of the water.
d. There is no buoyant force on you since you are supported by the lake bottom.
Answer:
c. There is a buoyant force that is proportional to the volume of your body that is below the level of the water.
Explanation:
Buoyancy can be defined as a force which is created by the water displaced by an object.
Simply stated, buoyancy is directly proportional to the amount of water that is being displaced by an object.
Hence, the greater the amount of water an object displaces; the greater is the force of buoyancy pushing the object up.
The buoyancy of an object is given by the formula;
[tex] Fb = pgV [/tex]
[tex] But, \; V = Ah [/tex]
[tex] Hence, \; Fb = pgAh [/tex]
Where;
Fb = buoyant force of a liquid acting on an object.
g = acceleration due to gravity.
p = density of the liquid.
v = volume of the liquid displaced.
h = height of liquid (water) displaced by an object.
A = surface area of the floating object.
The unit of measurement for buoyancy is Newton (N).
In this scenario, you are standing on the bottom of a lake with your torso above water. Thus, there is a buoyant force that is proportional to the volume of your body that is below the level of the water.
A cylinder containing the air comprises the systemm. Cycle is completed as follows : (i) 82000 N-m of work is done by the piston on the air during compression stroke and 45 kJ of heat are rejected to the surroundings. (ii) During expansion stroke 100000 N-m of work is done by the air on the piston. Calculate the quantity of heat added to the system؟?
Answer & Explanation:
1 N-m = 1 Joule
So 82 kJ of energy put into the system during (i).
45 kJ of heat leaves the system, so 82 kJ - 45 kJ = 37 kJ is remaining.
(ii) requires 100 kJ of energy but only 37 kJ is available, so 100 kJ - 37 kJ = 63 kJ of heat energy must be added to the system.
The heat given would be equal to the heat emitted from the system and by providing some external source of energy the volume or temperature of the system may increase.
The amount of heat added to the system is 63kJ.
The energy can be estimated as:
Given,
Work done by piston = 82000 NmHeat rejected in surrounding = 45 kJWork done during expansion stroke = 100000 NmQuantity of added heat = ?During compression stroke:
Work done by the piston [tex]\rm (W_{1-2})[/tex] = - 82000Nm or - 82kJHeat rejected to the system [tex]\rm (Q_{1-2})[/tex] = - 45kJWe know that,
[tex]\rm Q_{1-2} = (U_{2} - U_{1}) + W[/tex]
Therefore,
[tex]\begin{aligned}-45 &= \rm (U_{2} - \rm U_{1}) + (-82)\\\\\rm (U_{2}-U_{1}) &= 37\rm (U_{2} - U_{1}) = 37\; kJ \end{aligned}[/tex] (equation 1 )
During Expansion system:
Work done by the piston [tex]\rm (W_{2-1})[/tex] = 100000 Nm or 100 kJ
Now putting values in the equation:
[tex]\begin{aligned}\rm Q_{2-1} &= \rm U_{1} - U_{2} + W\\\\&=\rm (U_{1} - U_{2}) + W\end{aligned}[/tex]
Substituting value from equation 1:
[tex]\begin{aligned}\rm Q_{2-1} &= - 37+100\rm \;kJ\\&= 63\rm \; kJ\end{aligned}[/tex]
Therefore, 63kJ of energy is added to the system.
To learn more about the laws of thermodynamics follow the link:
https://brainly.com/question/15839384
TWO forces, one of 12N and another or 24N
act on body in such a way that they make an angle of 90° with each other. Find the resaltant of two forces.
Answer:
26.833 N
Explanation:
The computation of the resaltant of two forces is shown below:
Given that
Force A = 12N
Force B = 24N
Based on the above information
Resultant R is
[tex]=\sqrt{A^2 + B^2 + 2AB \times cos \theta}\\\\=\sqrt{144 + 576 + 2\times 24\times 12\times cos90^{\circ}}\\\\=\sqrt{144+576+576\times 0}\\\\=\sqrt{720}[/tex]
=26.833 N
A 3.0-kilogram mass is traveling in a circle of
0.20-meter radius with a speed of 2.0 meters per
second. What is its centripetal acceleration?
(1) 10. m/s
(3) 60. m/s2
(2) 20. m/s2
(4) 6.0 m/s2
Answer:
[tex]a=20\ m/s^2[/tex]
Explanation:
Given that,
The mass of an object, m = 3 kg
The radius of a circle, r = 0.2 m
The speed of the object, v = 2 m/s
We need to find the centripetal acceleration. Its formula is given by :
[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{0.2}\\\\a=20\ m/s^2[/tex]
So, the centripetal acceleration is [tex]20\ m/s^2[/tex].
Glenn shoots an arrow at a 30.0 degree angle. It has a velocity of 65.0 m/s.
How far will the arrow travel? *
Answer:
The horizontal distance traveled by the projectile is 373.36 m.
Explanation:
Given;
angle of projection; θ = 30⁰
initial velocity of the projectile, u = 65 m/s
The horizontal distance traveled by the projectile or range of the projectile is calculated as;
[tex]R = \frac{u^2 \times sin(2\theta)}{g} \\\\R = \frac{65^2 \times sin(2\times 30^0)}{9.8}\\\\R = \frac{4225\times sin(60)}{9.8} \\\\R = 373.36 \ m[/tex]
Therefore, the horizontal distance traveled by the projectile is 373.36 m.
I found the answer so first reply saying “apple” gets brainliest!!
Answer:
apple
Explanation:
A 450.0 kg roller coaster is traveling in a circle with radius 15.0m. Its speed at point A is 28.0m/s and its speed at point B is 14.0 m/s. At point A the cart is already moving with circular motion. a) Draw free bodydiagramsfor the cartatpointsAand B(two separate free body diagrams). b) Calculate the acceleration of the cartat pointsAandB(magnitude and direction). c) Calculate the magnitude of the normal force exerted by the trackson the cartat point A. d) Calculate the magnitude of the normal force exerted by the tracks on the cart at point B.
Answer:
b) a = 52.26 m / s², a ’= 13.06 m / s², c) N = 2.79 10⁴ N, d) N = 1.89 10³ N
Explanation:
a) In the attached we can see the free body diagrams for the two positions, position A in the lower part of the circle and position B in the upper part of the circle
b) Let's start at point A
Let's use that the acceleration is centripetal
a = v² / r
let's calculate
a = 28² / 15.0
a = 52.26 m / s²
as they relate it is centripetal it is directed towards the center of the circle, therefore for this point it is directed vertically upwards
Point B
a ’= 142/15
a ’= 13.06 m / s²
in this case the acceleration is vertical downwards
c) The values of the normal force
point A
let's use Newton's second law
∑ F = m a
N- W = m a
N = mg + ma
N = m (g + a)
N = 450.0 (9.8 + 52.25)
N = 2.79 10⁴ N
d) Point B
-N -W = m (-a)
N = ma -m g
N = m (a-g)
N = 450.0 (14.0 - 9.8)
N = 1.89 10³ N
Steve is planning his annual Spring Break road trip. He pulls out his map and draws out his route to visit the five locations that he has planned for this year. They go in a counterclockwise loop and he ends up at home, where he started, just in time to start classes again. Whenever he is on the road he travels a constant 60 miles/hour. When Steve adds up the total distance traveled, as measured by his odometer, and divides it by the time that his trip took, he has measured what quantity?
a. His average velocity.
b. His average speed.
c. His instantaneous velocity.
d. His instantaneous speed.
Steve’s average velocity for the whole trip is:______
a. greater than 60 miles/hour.
b. equal to 60 miles/hour.
c. less than 60 mile/hour, but greater than zero.
d. exactly zero.
Answer:
Part 1
Steve is measuring his average speed
Part 2
Average velocity is equal to 60 miles per hour
Explanation:
Part 1
Average velocity is equal to total distance travelled divided by total time taken. It also takes into consideration the change of direction through out the journey.
Hence, Steve is measuring his average speed
Option A is correct
Part 2
Average velocity is equal to 60 miles per hour only because velocity is a vector quantity
Option B is correct
Integrate your expressions for dEx and dEy from θ=0 to θ=π. The results will be the x-component and y-component of the electric field at P
.
Express your answers separated by a comma in terms of some, all, or none of the variables Q
and a and the constants k and π.
Answer:
hello your question is incomplete below is the missing part
Ex = 0
Ey = [tex]\frac{-2kQ}{\pi a^2}[/tex]
Explanation:
Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π
Ex = 0
Ey = [tex]\frac{-2kQ}{\pi a^2}[/tex]
If a 9851.6 kg vw van is moving at a speed of 16.7 m/s, what is the momentum? Round answer to the nearest hundredth
Answer:
the momentum is 164500 kg m/s
Explanation:
The computation of the momentum is shown below:
As we know that
Momentum is
= mass × velocity
= 9851.6 kg × 16.7 m/s
= 164522 kg·m/s
= 164500 kg m/s
hence, the momentum is 164500 kg m/s
what's the speed of the man who runs 10 miles in 2hrs?
