In a survey, 54.5% of respondents have portable earbuds and 30% of the respondents who have portable earbuds also have a smart speaker. What is the probability that a respondent has both portable earbuds and a smart speaker? If necessary, round to the nearest hundredth of a percent.

Answer:

A) m∠3 + m∠6 = 90

Step-by-step explanation:

Angles 3 and 6 are complementary angles. This means they add up to 90 degrees. Since you know the angle that is a right angle due to the box, you know these angles add up to 90 degrees

Answer: The stemplot shows that the distribution is unimodal and skewed to the right.

The stem values (tens digits) are:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4

The leaf values (ones digits) are:

5, 5, 6, 6, 6, 7, 7, 8, 8, 8, 8, 9, 9, 0, 0, 0, 1, 1, 1, 2, 2, 3, 3, 7, 9, 9, 9, 2, 2, 4, 8, 2

The data is unimodal because there is one clear peak in the distribution. The data is skewed to the right because the long tail of the distribution extends to the right, with a few large values pulling the mean to the right.

Therefore, the best description of the shape of this distribution is skewed to the right.

Answer:

$140,000

Step-by-step explanation:

7*20,000 = 140,000

Using the given vectors v and w, we found v•w =  66 and v•v = 73.

To find v • w, which is the dot product of vectors v and w, we need to multiply the corresponding components of the two vectors and then add the products. In other words,

v • w = (-8i)(-9i) + (-3j)(-7j)

= 72 + 21

= 93

So, v • w = 93.

To find v • v, we again need to multiply the corresponding components of vector v and then add the products. In other words,

v • v = (-8i)(-8i) + (-3j)(-3j)

= 64 + 9

= 73

So, v • v = 73.

Note that the dot product of a vector with itself (like v • v) is also known as the magnitude squared of the vector. In this case, ||v||² = v • v = 73.

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The minimum grade you need to get a B in the course is given as follows:

x = 80.625.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations, which is also called the cardinality of the data-set.

The grades and their percentages are given as follows:

You want a grade of 80, hence the minimum test average is obtained as follows:

0.15 x 73 + 0.2 x 79 + 0.25 x 84 + 0.4x = 80

47.75 + 0.4x = 80

x = (80 - 47.75)/0.4

x = 80.625.

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The  required area of the rectangle is 8 sq. units

Any mathematical statement with numbers, variables, and an arithmetic operation between them is an expression or algebraic expression. For instance, the expression 4m + 5 is one in which the terms 4m and 5 and the variable m are separated by the arithmetic sign +.

From the diagram

Length = 4 units, width = 2 units

Area of rectangle = length×width

Area of rectangle = 4×2

Area of rectangle = 8 sq. units

Thus, required area of the rectangle is 8 sq. units

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Answer:

108

You rounded to the nearest tens place.

The 0 in the tens place rounds up to 1

Step-by-step explanation: because the digit to the right in the ones place is 8.

110

When the digit to the right is 5 or greater we round away from 0.

108 was rounded up and away from zero to 110

The amount of oil in the lantern at 12 noon is 64.33 ounces

The time can be represented with x and the amount with y

Note that

x = number of hours from 12 noon

So, we have the following ordered pairs

(x, y) = (0, y) (2, 63), (5, 61)

Using the slope formula, we have

(y - 63)/(0 - 2) = (61 - 63)/(5 - 2)

So, we have

(y - 63)/-2 = -2/3

This gives

y - 63 = 4/3

Add 63 to both sides

y = 63 + 4/3

Evaluate

y = 64.33

Hence, the amount in the lantern at 12 noon is 64.33 ounces

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Complete question

A camper lights an oil lantern at 12 noon and lets it burn continuously. Once the lantern is lit, the lantern burns oil at a constant rate each hour. At 2 p.m., the amount of oil left in the lantern is 63 ounces. At 5 p.m., the amount of oil left in the lantern is 61 ounces.

Based on the average rate of oil burning per hour, how much oil, in ounces, was in the lantern at 12 noon?

Answer:

The answer is 576

Step-by-step explanation:

the formula for a right rectangular prism is L*W*H. We know that the height is 4, and the base is 12^2. Which means that the length and width are both 12. So if ew do 12*12*4 you get 576.

The absence of the value 105.0 from the interval shows that the medication therapy significantly reduces wake time.

In statistics, mean is a measure of central tendency that represents the average value of a set of data. It is commonly referred to as the "arithmetic mean" or simply the "average." To calculate the mean, you add up all the values in the data set and divide the total by the number of values. For example, if you have the following data set: 2, 5, 8, 9, 12, the mean would be calculated as follows:(2 + 5 + 8 + 9 + 12) ÷ 5 = 7.2 . So the mean of this data set is 7.2. The mean is a useful measure of central tendency because it takes into account all the values in the data set and provides a single representative value that can be used to describe the overall characteristics of the data.

given

For a population receiving pharmacological treatments, the mean wake time was estimated with a 95% confidence interval.

where t/2 is the crucial value from the t-distribution with n-1 degrees of freedom and a confidence level of 95%, and x is the sample mean, s is the sample standard deviation, n is the sample size.

When we enter the provided values, we obtain:

s = 23.3

n = 23

t0.025,22 = 2.074

The mean wake time estimate with a 95% confidence interval for a population receiving medication is thus:

82.1 ± 2.074 * (23.3/√23)

which is equivalent to:

(71.4, 92.8)

The absence of the value 105.0 from the interval shows that the medication therapy significantly reduces wake time.

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Answer:

Step-by-step explanation:

In November 1998, former professional wrestler Jesse “The Body” Ventura was elected governor of Minnesota. Up until right before the election, most polls showed he had little chance of winning. There were several contributing factors to the polls not reflecting the actual intent of the electorate:

Ventura was running on a third-party ticket and most polling methods are better suited to a two-candidate race.

Many respondents to polls may have been embarrassed to tell pollsters that they were planning to vote for a professional wrestler.

The mere fact that the polls showed Ventura had little chance of winning might have prompted some people to vote for him in protest to send a message to the major-party candidates.

But one of the major contributing factors was that Ventura recruited a substantial amount of support from young people, particularly college students, who had never voted before and who registered specifically to vote in the gubernatorial election. The polls did not deem these young people likely voters (since in most cases young people have a lower rate of voter registration and a turnout rate for elections) and so the polling samples were subject to sampling bias: they omitted a portion of the electorate that was weighted in favor of the winning candidate.

SAMPLING BIAS

A sampling method is biased if every member of the population doesn’t have equal likelihood of being in the sample.

So even identifying the population can be a difficult job, but once we have identified the population, how do we choose an appropriate sample? Remember, although we would prefer to survey all members of the population, this is usually impractical unless the population is very small, so we choose a sample. There are many ways to sample a population, but there is one goal we need to keep in mind: we would like the sample to be representative of the population.

Returning to our hypothetical job as a political pollster, we would not anticipate very accurate results if we drew all of our samples from among the customers at a Starbucks, nor would we expect that a sample drawn entirely from the membership list of the local Elks club would provide a useful picture of district-wide support for our candidate.

One way to ensure that the sample has a reasonable chance of mirroring the population is to employ randomness. The most basic random method is simple random sampling.

Answer:

the car's angular speed is 72,000π radians per hour.

the car's linear speed is approximately 100.53 miles per hour.

Step-by-step explanation:

To find the car's angular speed in radians per hour, we can start by finding the angular speed in radians per second.

The formula for angular speed is:

ω = 2πf

where ω is the angular speed in radians per second, and f is the frequency or rate of rotation in revolutions per second.

In this case, the wheel is spinning at a rate of 10 revolutions per second, so:

ω = 2π(10) = 20π radians per second

To convert this to radians per hour, we can multiply by the number of seconds per hour:

20π radians per second × 3600 seconds per hour = 72,000π radians per hour

To find the car's linear speed in miles per hour, we can use the formula:

v = rω

where v is the linear speed, r is the radius of the wheel, and ω is the angular speed in radians per second.

The radius of the wheel is half the diameter, or 9 inches. To convert this to miles, we can divide by 12 and then by 5280:

9 inches ÷ 12 inches per foot ÷ 5280 feet per mile = 0.000142045 miles

Now we can substitute the values we have found:

v = (0.000142045 miles) × (18/2 inches) × (20π radians per second)

v ≈ 100.53 miles per hour

Answer:

(i) 10 revolutions = 10(2π) = 20π radians

10 revolutions/sec =

(20π radians/sec)(3,600 sec/hr) =

72,000π radians/hr

(ii) C = 18π inches

10 revolutions × 18π inches =

180π inches

(180π in./sec)(3,600 sec/hr) =

(648,000π in./hr)(1 mi./63,360 in.)

= 225π/22 miles/hour

= about 32.13 miles/hour

Therefore, the volume of the composite solid is approximately 1357.28 cubic feet, rounded to the nearest hundredth.

Volume is a measure of the amount of space occupied by an object or a substance. In other words, it is the three-dimensional space that an object or substance occupies. The SI unit for volume is cubic meters (m³), although other units such as cubic centimeters (cm³) and liters (L) are also commonly used.

Here,

The composite solid is made up of a hemisphere and a cone with the same base radius and height. The volume of the hemisphere is given by (2/3)πr³, and the volume of the cone is given by (1/3)πr²h, where r is the radius and h is the height. Given that the radius is 6 feet and the height is 12 feet, we can find the volumes of the hemisphere and the cone as follows:

Volume of hemisphere = (2/3)π(6³)

= 288π cubic feet

Volume of cone = (1/3)π(6²)(12)

= 144π cubic feet

The total volume of the composite solid is the sum of the volumes of the hemisphere and the cone, which is:

Total volume = Volume of hemisphere + Volume of cone

= 288π + 144π

= 432π

To find the numerical value of this volume, we can use the approximation π ≈ 3.14 and round the result to the nearest hundredth:

Total volume ≈ 432(3.14)

= 1357.28 cubic feet

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B is a 2 by 2 matrix, and the determinant of B written as |B| is equal to -1.

We can find |B|, the determinant of the matrix B by subtracting the multiple of row column and row 2 column 1 from the multiple of row column 1 and row 2 column 2 as follows:

|B| = (-2 × -2) - (1 × 5)

|B| = 4 - 5

|B| = -1.

Therefore, the determinant of the 2 by 2 matrix B written as |B| is equal to -1.

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Thus, the solution set for the cost of each notebook that can be bought by George is:  (0 ≤ x ≤ 6).

A linear equation is a one-variable equation of the a straight line. The variable only has one power, which is 1. Simple algebraic operations are used to solve linear equations in one variable, which can have the form ax+b=0.

Given that:

So, the linear equation follows

Amount for 4 notebooks + Left amount  = total amount

4*x + 12 ≤ 36

4x ≤ 36 - 12

4x ≤ 24

x ≤ 24/4

x ≤ 6

So, (0 ≤ x ≤ 6)

Thus, the solution set for the cost of each notebook that can be bought by George is:  (0 ≤ x ≤ 6).

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The probability that a customer who visited any of the three website designs made a purchase is 4.5%.

To find the probability that a customer who visited any of the three website designs made a purchase, we need to find the average probability of purchase across all three designs.

We can do this by taking the mean of the three probabilities:

Mean probability = (4.5% + 5.2% + 3.8%) / 3

= 13.5% / 3

= 4.5%

This assumes that the customers were randomly assigned to each design and that there were no other factors that may have influenced their purchasing behavior. Additionally, the sample size and duration of the experiment may also affect the accuracy of the results.

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The number of gallons of gas Brynen will use in driving to and from work, during the week, obtained using arithmetic operations is 7 5/7 gallons

Arithmetic operations are operations involving addition, subtraction, multiplication, and division.

The distance Brynen travels each way to his new job = 27 miles

The distance his car gets per gallon of gas = 35 miles

The number of gallons he will use in a week (five days of driving in the week), can therefore, be found by arithmetic operations follows;

The distance Brynen travels = 27 × 2 × 5 = 270 miles

The number of gallons = 270 miles/(35 miles/gallon) = 270/35 = 7 25/35

7 25/35 = 7 5/7

The volume of gas he will use to and from work this week is; 7 5/7 gallons

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Answer:

The discriminant is:

(-3)^2 - 4(1)(18) = 9 - 72 = -63

Since this discriminant is negative, f(x) does not have any real number solutions.

1. Therefore, the exact value of cos(105°) is (√2 - √6)/4.

2. Therefore, the exact value of sin(75°) is (√6 + √2)/4.

3. Therefore, the exact value of tan(105°) is (√3 + 1)/(3 - √3).

4. Therefore, the exact value of cos(105°)cos(15°) is (2 + 2√3)/8.

A branch of mathematics known as trigonometry is concerned with the study of triangles and the correlations between their sides and angles.

It entails computing different triangle measurements and attributes using trigonometric functions including sine, cosine, and tangent.

Trigonometry is an essential component of calculus and other advanced mathematical studies, and it has applications in many disciplines including engineering, physics, navigation, astronomy, and architecture.

1. We can use the formula cos(A + B) = cos(A)cos(B) - sin(A)sin(B) with A = 60° and B = 45°. Then:

cos(105°) = cos(60° + 45°)

= cos(60°)cos(45°) - sin(60°)sin(45°)

= (1/2)(√2/2) - (√3/2)(√2/2)

= (√2 - √6)/4

Therefore, the exact value of cos(105°) is (√2 - √6)/4.

2. We can use the formula sin(A + B) = sin(A)cos(B) + cos(A)sin(B) with A = 45° and B = 30°. Then:

sin(75°) = sin(45° + 30°)

= sin(45°)cos(30°) + cos(45°)sin(30°)

= (√2/2)(√3/2) + (√2/2)(1/2)

= (√6 + √2)/4

Therefore, the exact value of sin(75°) is (√6 + √2)/4.

3. We can use the formula tan(A + B) = (tan(A) + tan(B))/(1 - tan(A)tan(B)) with A = 60° and B = 45°. Then:

tan(105°) = tan(60° + 45°)

= (tan(60°) + tan(45°))/(1 - tan(60°)tan(45°))

= (√3 + 1)/(3 - √3)

Therefore, the exact value of tan(105°) is (√3 + 1)/(3 - √3).

4. We can use the formula cos(A + B) = cos(A)cos(B) - sin(A)sin(B) with A = 60° and B = -45°. Then:

cos(105°)cos(15°) = cos(60° - 45°)cos(15°)

= [cos(60°)cos(-45°) - sin(60°)sin(-45°)]cos(15°)

= [(1/2)(√2/2) - (√3/2)(-√2/2)]cos(15°)

= (√2 + √6)/4 * cos(15°)

= (√2 + √6)/4 * (√6 + √2)/4

= (2 + 2√3)/8

Therefore, the exact value of cos(105°)cos(15°) is (2 + 2√3)/8.

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If local city government wants to display the ages of the city citizen, It would be better to organize the data using a histogram.

A histogram is a graph that shows the distribution of a set of continuous data. The ages of city citizens can be considered as continuous data, as there are many possible values for age within a certain range.

A dot plot, on the other hand, is a graph that shows the distribution of a set of discrete data. Discrete data are values that can only take on specific, isolated values, like shoe sizes or the number of siblings a person has.

A histogram would be more effective for displaying the distribution of the ages of city citizens because it can show the range of ages in a more continuous manner, and provide a more precise representation of the frequency of the different age groups.

A dot plot, on the other hand, would be less effective, as it could be difficult to represent every age value as a single dot, and the resulting graph may not provide a clear indication of the distribution of ages.

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The area of the training field that has the shape of a rectangle and two semicircle would be = 9,755.46m²

To calculate the area of the training field, the area of the rectangle and the two semicircles should be determined and added together.

The area of rectangle = length×width

where:

length = 96m

width = 66m

area of rectangle = 66×96 = 6,336m²

Area of the two semicircle = Area of a circle = πr²

radius = diameter/2 = 66/2 = 33m

area of a circle= 3.14×33×33 = 3419.46m²

Therefore the area of the training field = 6,336m²+3419.46m² = 9,755.46m²

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The areas of the trapezoids is,

A = 48 sq units.

Since, The formula to find the area of a trapezoid of a trapezoid is,

⇒ A = 1/2(b₁ + b₂ )h.

Hence, it is stated that the height of each unit is 2.

Now let's substitute the variables in the formula with the actual bases and heights as;

A = 1/2(8 + 4)8,

A = 6 × 8,

A = 48 sq units.

Thus, the areas of the trapezoids is,

A = 48 sq units.

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The equation of the quadratic with a directrix of x = 2 and vertex of (0 , 0)  is: y² =  -8x

The equation of the quadratic with a directrix of y = 4 and vertex of (1, 3)  is: (x - 1)² = -4 (y - 3)

Quadratic equation when the directrix is at x direction is of the form:

(y - k)² =  4P (x - h)

OR

standard vertex form, x = a(y - k)² + h     where a = 1/4p

The vertex

v (h, k) = (0, 0)

P in this problem, is the distance between the vertex and the directrix

P = 0 - 2 = -2

substitution of the values into the equation gives

(y - k)² =  4P (x - h)

(y - 0)² =  4 x -2 (x - 0)

y² =  -8x

Quadratic equation when the directrix is at y direction is of the form:

(x - h)² =  4P (y - k)

OR

standard vertex form, y = a(x - h)² + k     where a = 1/4p

The vertex

v (h, k) = (1, 3)

P in this problem, is the distance between the vertex and the directrix

P = 3 - 4 = -1

substitution of the values into the equation gives

(x - h)² =  4P (y - k)

(x - 1)² =  4 * -1 (y - 3)

(x - 1)² = -4 (y - 3)

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The values of x, y, and z based on the system of equations will be (-2,4,7).

x + 3y + 5z = 45

6x - 3y + 2z = - 10

------------------------add

7x + 7z = 35

6x - 3y + 2z = -10

-2x + 3y + 8z = 72

----------------------add

4x + 10z = 62

7x + 7z = 35....multiply by 4

4x + 10z = 62...multiply by -7

---------------------

28x + 28z = 140 (result of multiplying by 4)

-28x - 70z = - 434 (result of multiplying by -7)

--------------------add

- 42z = - 294

z = -294/-42

z = 7

4x + 10z = 62

4x + 10(7) = 62

4x + 70 = 62

4x = 62 - 70

4x = - 8

x = -8/4

x = -2

x + 3y + 5z = 45

-2 + 3y + 5(7) = 45

-2 + 3y + 35 = 45

3y + 33 = 45

3y = 45 - 33

3y = 12

y = 12/3

y = 4

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Solve the following system of equations algebraically for all values of x,y and z

x+3y+5z=45

6x-3y+2z=-10

-2x+3y+8z=72

Thus, 9 percent of the total dance tickets available is found to be purchased in advance.

Although the usage of percent and percentage differs slightly, they both signify the same thing. It is customary to use percent or the symbol (%) along with a numerical value. One tenth of something is one percent.

Given data:

Total dance tickets = 200

Advanced purchased tickets = 18

Let x be the percentage of advance booked tickets.

Then,

x% of 200 = 18

x*200 / 100 = 18

2x = 18

x = 18/2

x = 9%

Thus, 9 percent of the total dance tickets available is found to be purchased in advance.

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Total area to paint: (15 + 10) - 1.5 = 23.5 sq ft

Calculate the area of each wall, subtract the door area, and sum the areas.

Front and back walls: (3 * 2.5) * 2 = 15 sq ft

Next, we calculate the area of the side walls:

Side walls: (2 * 2.5) * 2 = 10 sq ft

Door area: 1.5 * 1 = 1.5 sq ft

Total area to paint: (15 + 10) - 1.5 = 23.5 sq ft

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The Complete Question

Kara wants to paint the four outside walls of her dog's house, excluding the roof and door. The dog house measures 3 feet in length, 2 feet in width, and 2.5 feet in height. The door is 1.5 feet tall and 1 foot wide. What is the area of the surface she needs to paint?

The maximum profit that for the equation p(x) = 2800x - 85x² - x³ - 109000 is $672500

An exponential equation is an expression that shows how numbers and variables using mathematical operators.

Given the profit function:

p(x) = 2800x - 85x² - x³ - 109000

The profit is maximum at:

p'(x) = 0

p(x) = 2800 + 170x - 3x²

2800 + 170x - 3x² = 0

x = 70

p(70) = 2800(70) - 85(70)² - (70)³ - 109000 = 672500

The maximum profit is $672500

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Answer:

To determine the longest rod that can be carried to the loading dock, we want to find the shortest distance from point T to line segment CD. We can use the Pythagorean theorem for this.

First, we need to find the equation of the line containing segment CD. We can find the slope of the line CD as:

m = (y2 - y1) / (x2 - x1) = (36 - 48) / (48 - 0) = -12/48 = -1/4

where (x1, y1) = (0, 48) and (x2, y2) = (48, 36).

Using point-slope form, we get the equation of the line CD as:

y - 48 = (-1/4)(x - 0)

y = (-1/4)x + 48

Now, we can find the perpendicular distance from point T to the line CD as follows:

d = |(-1/4)(30) + 72 - 48| / sqrt((-1/4)^2 + 1)

d = 42 / sqrt(17) ≈ 10.21

Therefore, the longest rod that can be carried to the loading dock is approximately 10.2 inches long (rounded to the nearest tenth of an inch).

The polygons that can be formed by the intersection of a plane and a cylinder either parallel or perpendicular to the base include :

If a plane intersects three distinct vertices of the cube while bypassing any other vertices, a triangle is produced. To visualize this, suppose a corner of the cube were removed with a knife; picture that cut surface as a triangle.

On the other hand, if a plane coincides with four points on the cube and outlines a square shape, it creates what's called a "square cross-section." This transpires when said plane parallels one side of the cube while intersecting only the midpoints of its opposite face's edges.

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Full question is:

Select all the polygons that can be formed by the intersection of a plane and a cylinder either parallel or perpendicular to the base

A triangle

B square

C. rectangle

D pentagon

E circle