Answer:
friction from the ground rubs on the tire which gives it more force to move forward,
Explanation: without friction the bike wont be able to use the motion to move forward. but the tires start to wear out easily.
When does the ball have the greatest and least amount of potential energy?
Answer:
A ball thrown into the air has the most potential energy when it has reached the highest point above the ground before it begins descending. If we consider the vertical motion only beginning when the ball leaves the thrower’s hand, the ball is exchanging kinetic energy for (gravitational) potential energy. When all of the kinetic energy has been transformed, the ball begins falling, and exchanges it’s potential energy back into kinetic energy. If you ignore air resistance, the ball will land with as much energy as it began with.
What would scientists using classical, Newtonian physics expect to observe
during the photoelectric effect?
A. That enough light of any frequency would cause electrons to flow
O B. That light above a certain frequency would not cause electrons to
flow
O C. That no light would cause electrons to flow
O D. That light below a certain frequency would not cause electrons to
flow
Answer:
A. That enough light of any frequency would cause electrons to flow.
Explanation:
A P E X
Scientists using classical, Newtonian physics expect to observe the photoelectric effect because enough light of any frequency would cause electrons to flow.
What is the photoelectric effect?When a medium receives electromagnetic radiation, electrostatically charged particles are emitted from or inside it.
The emission of ions from a steel plate when light falls on it is a common definition of the effect. The substance could be a solid, liquid, or gas; and the released particles could be protons or electrons.
Scientists using classical, Newtonian physics expect to observe the photoelectric effect because enough light of any frequency would cause electrons to flow.
The flow of the electron is a must to understand the photo electric effect.
Hence option A is correct.
To learn more about the photoelectric effect refer to the link;
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A light wave with a long wavelength has _____ energy.
5. A standing wave in a clothesline has 4 nodes and 3 antinodes. The clothesline is 12 m long and is vibrating
at 0.50 vibrations per second. What is the speed of the wave?
Answer:
v = 4 m / s
Explanation:
In this exercise we are asked to find the speed of the wave, which is described by the expression
v = λ f
in this case the wave has 4 nodes and 3 antinodes, in a length of 12 m
for a standing wave it is satisfied that we have a full wavelength and a half of another
L = λ + ½ λ
L = [tex]\frac{3}{2}[/tex] λ
λ = ⅔ L
Cambien indicates that it has a frequency of
f = 0.5 Hz
we substitute
v = ⅔ L f
let's calculate
v = [tex]\frac{2}{3}[/tex] 12 0.5
v = 4 m / s
Meera doesn't have a night lamp in her room. She covered the bulb of the room with a towel to get a dim light. Has she taken the right step? Justify the answer in simple words
Answer:
* If it is an incandescent lamp, the increase in temperature of the towel could set it on fire,
* If the towel is wet, there could be a short circuit
Explanation:
Covering the lamp with a towel has several problems:
* If it is an incandescent lamp, the increase in temperature of the towel could set it on fire, which could be a danger
* If the lamp is not incandescent, the temperature rise of the towel is not very high,
* If the towel is wet, there could be a short circuit due to the humidity of the lamp with the wet towel
* If the towel is wet when touched, there could be a shock towards the person due to the electrical conduction
Consequently, covering the bulb with a towel is a serious mistake.
How does Borg’s Rating of Perceived Exertion relate to Target Heart Rate?
Answer:
it helps you estimate how hard you're working (your activity intensity). perceived exertion is how hard you think your body is exercising. ratings on the scale are related to heart rate (how hard your heart is working to move blood through your body).
Explanation:
The parasympathetic nervous system is part of the
nervous system.
A. central
B. somatic
C. sympathetic
D. autonomic
Answer:
i believe it’s C. sympathetic
Explanation:
correct me if i’m wrong
1. The spring in a trampoline has been stretched 0.25m and has a spring
constant of 250N/m. How much elastic potential energy is stored
Answer:
250/0.25. * 0.25 =250J
Explanation:
PE=Force*displacement
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (40pts)
Answer:
Explanation:
According to this site, "The purpose of these curved wingtips is to prevent high air pressure above the airplane from flowing over and under the wings."
Hope this helps!
The pressure due to the liquid on an object immersed in that liquid is 4500 Pa
The density of the liquid is 900 kg/m.
What is the depth of the object below the surface of the liquid ?
Answer:
The depth of the object below the surface of the liquid is 0.510 meters.
Explanation:
The hydrostatic pressure ([tex]P[/tex]), measured in pascals, experimented by the object is directly proportional to density of the fluid ([tex]\rho[/tex]), measured in kilograms per cubic meter, gravitational acceleration ([tex]g[/tex]), measured in meters per square second, and depth of the object ([tex]h[/tex]), measured in meters. That is:
[tex]P = \rho\cdot g \cdot h[/tex] (1)
If we know that [tex]P = 4500\,Pa[/tex], [tex]\rho = 900\,\frac{kg}{m^{3}}[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the depth of the object is:
[tex]h = \frac{P}{\rho\cdot g}[/tex]
[tex]h = \frac{4500\,Pa}{\left(900\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]
[tex]h = 0.510\,m[/tex]
The depth of the object below the surface of the liquid is 0.510 meters.
The depth of the object below the liquid's surface will be
"0.510 m".
Pressure and DensityAccording to the question,
Object immersed, P = 4500 Pa
Density of liquid, ρ = 900 kg/m³
Acceleration due to gravity, g = 9.8 m/s²
We know the relation,
→ Hydrostatic pressure (P) = ρ.g.h
or,
Depth will be:
→ h = [tex]\frac{P}{\rho .g}[/tex]
By substituting the values,
= [tex]\frac{4500}{900\times 9.8}[/tex]
= [tex]\frac{4500}{8820}[/tex]
= 0.510 m
Thus the above answer is appropriate.
Find out more information about pressure here:
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Sticky crashes': A 700 kg car is traveling at 10 m/s. It hits a 300 kg car that is parked. Their bumpers lock and the two roll forward together. With what velocity do they roll forward?
Answer:
7 m/s
Explanation:
Find the total mass
m1+m2 = total mass
700kg+300kg = 1000kg
Find the velocity of each mass
v1 = 10m/s
v2 = 0m/s
Find the combined momentum
m1v1 + m2v2 = mfvf
(700)(10)+(300)(0)=(1000)(vf)
7000=1000(vf)
7=vf
So the velocity of the two cars rolling together is 7 m/s
.A 0.6 kg basketball is thrown straight up at a velocity of 4 m/s. What is the initial kinetic energy of the basketball?
Answer:
the initial kinetic energy of the basket ball is 4.8 J
Explanation:
The computation of the initial kinetic energy of the basket ball is shown below:
As we know that
Initial kinetic energy is
[tex]= \frac{1}{2}mv^2 \\\\= \frac{1}{2}\times 0.6 \times (4m/s)^2\\\\= \frac{1}{2}\times 0.6 \times 16m/s^2\\\\= 4.8 J[/tex]
Hence, the initial kinetic energy of the basket ball is 4.8 J
State keplers law........
Answer:
There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its
Which of these labels can be used for speed. Hint: There are 3.
Answer:
Everything Except Sec/mi and Days/Year
Explanation:
Remember, Spees= Distance/Time
Answer:
What you did is right. It is m/sec , km/mi and mi/hr
13. Using Newton's 2nd law, explain why it takes more force to push a 50 kg adult than a 25 kg child along the same surface.
Need help please in physics
Answer:
the switching circuitry is opened the soft iron armature is replaced to tasty le macha the switching circuitry is closed explain what happens when the switch circuit is a wonder you know about the characteristics of open to close this which right take the example of an electric generator for an electric motor which rotates in half rotation and change the armature and just try it ok I am sorry
A toy remote car drives in a circle. It makes 2 revolutions in 20 seconds. What is the period of the object?
Answer:
T = 10 seconds
Explanation:
Given that,
A remote car makes 2 revolutions in 20 seconds.
We need to find the period of the object.
It means, it will make [tex]\dfrac{2}{20}=0.1\ \text{revolutions/second}[/tex] .
lt T be the period of the object. So,
[tex]T=\dfrac{1}{0.1}\\\\T=10\ s[/tex]
It will take 10 seconds for one revolution.
The body weighing 8kg moves in a straight line uniformly accelerated with an acceleration of 3m / s? on a horizontal surface, under the action of force 60N.Find a) What is the friction force acting on the body) The coefficient of friction between the body and the surface where it moves
Answer:
pls explain this to me
Explanation:
I will not answer it
both answers are here in the picture
1. A sailboat moves north for a distance of 20.0 km when blown by a wind from the exact southwest with a force of 3.50 x 10^4 N. The sailboat travels the distance in 2.5 h. a) How much work was done by the wind? b) What was the wind’s power? Your response should include all of your work and a free-body diagram. Answer:
2. A worker applies 170 N of force on a lever to lift a 1250 N crate 0.10 m. a) If the lever is 100% efficient, how far does he need to push his side? Your response should include all of your work. Answer:
3. A sailor pushes a 160.0 kg crate up a ramp that is 2.50 m high and 15.0 m long onto a loading dock. He exerts a 620.0 N force parallel to the ramp. a) What is the mechanical advantage of the ramp? b) What is the efficiency of the ramp? Your response should include all of your work and a free-body diagram. Answer:
Answer:
1. The work done by the wind was 2.475 x 20^8 J.
The wind’s power was 4.4 x 10^5 W.
F = 3.50 x 10^4 N
S = 20.0 km = 20^4 m
W = 3.50 x 10^4 N x 20^4 m x cos 45 = 3.960 x 10^9 J
2.5 h = 9000 s
3.960 x 10^9/9000 = 4.4 x 10^5
2. If the lever is 100% efficient, the worker needs to push his side 0.735 m.
efficiency = work output/work input x 100
100 = 1250 x 0.1/170d x 100
100/100 = 125/170d
1 = 125/170d
170d = 125
d = 125/170
d = 0.735 m
3. work = force x distance
work = 620 x 15 = 9300 J
work = (160)(9.8)(2.50) = 3920 J
160 x 9.8 = 1568 N
1568/620 = 2.529
mechanical advantage = 2.529
(3920/9300) x 100% = 42.151
efficacy = 42.15%
A dipole is centered at the origin, with its axis along the axis, so that at locations on the axis, the electric field due to the dipole is given by E = (0, 1/4 pi epsilon_0 2qs/gamma^3, 0) v/m The charges making up the dipole are q_1 = +4 nC and q_2 = nC, and the dipole separation is s = 8 mm. What is the potential difference along a path starting at location p_1 = (0, 0.04, 0) m and ending at location P_2 = (0, 0.05, 0) m?
Answer:
Explanation:
Given that:
[tex]q_1 = + 4nC \\ \\ q_2 = -4nC \\ \\ q = 4nC[/tex]
[tex]P_1 = (0,0.04,0) m\\\\ P_2 = (0,0.05,0) m[/tex]
As [tex]q_1[/tex] [tex]\text{is nearer to }[/tex][tex]P_1 \& P_2[/tex] then [tex]q_2,q_1[/tex] [tex]\text{is positive, Thus}[/tex], [tex]E \limits^{\to}[/tex][tex]\text{ will be along the positive X-axis.}[/tex]
Recall that:
[tex]E ^{\to} = \dfrac{-dV}{dr}\implies E_y = \dfrac{-dV}{dy} \\ \\ = \int^{P_2}_{P_1}dV = -\int \limits ^{(0.05)}_{(0.04)}E_y \ dy \\ \\ \implies (V_{P_2}}-V_{(P_1)}) = \dfrac{-2q_5}{4 \pi \varepsilon _o} \int \limits ^{(0.05)}_{(0.04)} \dfrac{dy}{y^3} \\ \\ \implies (V_{P_2}}-V_{(P_1)}) = \dfrac{-2q_5}{4 \pi \varepsilon _o} \Big[ \dfrac{-1}{2y^2} \Big]^{0.05}_{0.04} \\ \\ \implies (V_{P_2}}-V_{(P_1)}) = \dfrac{q_5}{4 \pi \varepsilon _o} \Big[\dfrac{1}{y^2}\Big] ^{0.05}_{0.04}[/tex]
[tex]\\ \\ \implies (V_{P_2}}-V_{P_1}) = \dfrac{(4\times 10^{-9})(8\times 10^{-3})}{4 \pi (8.854 \times 10^{-12})} \Big [\dfrac{1}{(0.05)^2}-\dfrac{1}{(0.04)^2} \Big ]V \\ \\ (V_{P_2}}-V_{P_1}) = \mathbf{-64.71 \ volts}[/tex]
How to calculate the power of electricity from P=W/t
Answer:
One joule also equals the energy required to move an electric charge of one coulomb through an electric potential difference of one volt (J = C · V). Power (P) is the rate at which energy is transferred or converted. Thus, power equals work divided by time (P = W / t).
I hope it's helpful!
Hi! Can somebody please help?
Answer:
Diagram A will reach the top first.
Explanation:
If it is going straight, it will go slower. The higher the movement speed the faster it is. Hope this helps!
A 5 kg object moving to the right at 4 m/s collides inelastically with a 5 kg object
moving to the left at 4 m/s. The final velocity of both objects will be
Answer:
The linear momentum of a particle with mass m moving with velocity v is defined as
p = mv (7.1)
Linear momentum is a vector . When giving the linear momentum of a particle you must
specify its magnitude and direction. We can see from the definition that its units must be
kg·m
s
. Oddly enough, this combination of SI units does not have a commonly–used named so
we leave it as kg·m
s
!
The momentum of a particle is related to the net force on that particle in a simple way;
since the mass of a particle remains constant, if we take the time derivative of a particle’s
momentum we find
dp
dt = m
dv
dt = ma = Fnet
so that
Fnet =
dp
dt (7.2)
Can anyone help me with this? Will give brainliest if correct!
Answer:
Explanation:
HELP ME WRITE A ONE PAGE ESSAY TO EXPLAIN THE AUTHOR'S PURPOSE IN WRITING HOM SMART ARE ANIMAL
The final velocity of a car is 30m/s. The car is accelerating at a rate of 2.5m/s2
over an 2.8m/s2
8 second period of time. What is the initial velocity of the car?
Answer:
10m/s
Explanation:
Vf=v0+at
30m/s=v0+2.5m/s^2*8s
Solve for v0=10m/s
Sorry for the vague explanation I'm on my phone right now. Hope this still helps!
Initial velocity of the car where final velocity of a car is 30m/s and it is accelerating at a rate of 2.5 [tex]m/s^{2}[/tex] over an 2.8 [tex]m/s^{2}[/tex] 8 second period of time is 10 m/s.
To find the initial velocity of the car, we can use the kinematic equation:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)).
Given the final velocity (v) as 30 m/s, acceleration (a) as 2.5 [tex]m/s^{2}[/tex], and time (t) as 8 seconds, we can plug these values into the equation:
30 m/s = u + (2.5 [tex]m/s^{2}[/tex] * 8 s).
Now, solve for the initial velocity (u):
30 m/s = u + 20 m/s.
Subtract 20 m/s from both sides:
u = 30 m/s - 20 m/s = 10 m/s.
Therefore, the initial velocity of the car is 10 m/s.
To know more about Initial velocity, here
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which is hotter 30celcius or 30farenheit
Answer:
30 celsius
Explanation:
30 celsius = 86 fahrenheit
A car is travelling along a level road. When the velocity of the car is constant, the force of friction on it is
How far does an athlete travel at 10Km/hr in Half hour?
Which of the following is NOT available for drinking
A) groundwater
B) lakes
C) rivers with tributaries
D) frozen ice caps
Answer:
B
Explanation:
lakes are too big or largeTo Play Ice Hockey each player needs
Answer:
If one plays ice hockey he should must have necessary equipment to support his sport. These equipment include Ice Skates,Helmet with Cage and Mouth-guard:, Hockey stick, Hockey pants,Hockey gloves, shoulder pads, elbow pads, Shin Guard:Neck guard and Jockstrap (men) or Pelvic protector (women)
Explanation:
Answer:
If one plays ice hockey he should must have necessary equipment to support his sport. These equipment include Ice Skates,Helmet with Cage and Mouth-guard:, Hockey stick, Hockey pants,Hockey gloves, shoulder pads, elbow pads, Shin Guard:Neck guard and Jockstrap (men) or Pelvic protector (women).
