if the ratio of the sides of a triangle are 13:14:15 and its perimeter is 84 cm, find the area of the triangle.​

Answer:

$5.88

Step-by-step explanation:

3 erasers ⇒ $4,41

4 erasers ⇒ $A

A = 4 erasers * $4.41 / 3 erasers

A = $ 5.88

Answer:

see below

Step-by-step explanation:

Proportion:

4.41 is to 3 erasers as   'x' is to 4 erasers:

4.41 /3     =  x / 4       <======this is your proportion

 or rearrange

      4 *  4.41/3   = x  

(this results in x = $ 5.88  for 4 erasers )

Answer:

0.4 bottles can be filled

Step-by-step explanation:

divide the amount that is present by the max amount

the bottle can only hold 5.55 millimeters; therefore the max amount would be 5.55 millimeters.

the amount that is present is 2.22 millimeters.

[tex]\frac{222 millimeters}{555 millimeters} = 0.4[/tex]

0.4 bottles

if the given values are 555 and 222 then the answer is still .4

Answer:

0.4 bottles can be filled

Answer:

3:4

Step-by-step explanation:

We know this because the GCD of 21 and 28 is 7

so we divide both numbers by 7 and get 3 and 4

so the answer is 3:4

Answer:

48

Step-by-step explanation:

Answer:

48

Step-by-step explanation:

edge 2023

The value of x would be 5 for the model 2x+4.

Rearrange unknown terms to the left side of the equation,
[tex]= > 2x-3x = -1 - 4[/tex]

Combine like terms[tex]= -x = -1-4[/tex]

By calculating the sum or difference : -x = -5

Lets divide both sides of the equation by the resulting coefficient 5
So x = 5

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Answer:

(-1,3)

y=5x+8 , y=-4x-1y=5x+8,y=−4x−1

Both sides have y on the left hand side so make the right hand side equal and solve for x

5x+8= -4x-15x+8=−4x−1

To solve for x , add 4x on both sides

9x+8=-19x+8=−1

Subtract 8 on both sides

9x=-99x=−9

Divide by 9 on both sides

x=-1x=−1

Now plug in -1 for x in the first equation and find out y

y=5x+8y=5x+8

y=5(-1)+8y=5(−1)+8

y=-5+8y=−5+8

y=3y=3

Ordered pair is (x,y) that is (-1,3)

Step-by-step explanation:

Mark me as brainliest plsss

Answer:

B.

Step-by-step explanation:

Since all bulbs are connected in series, by opening switch A, you break the series connection, and all bulbs go out.

Answer:

The range is all real numbers.

Step-by-step explanation:

The function shown is a line (and not a horizontal line).

The range is all the y's on the graph or all the y's that can be generated by the equation of the function.

f(x) = 3x + 9

You could put ANY, literally any, number in place of the f(x) and be able to calculate an x for it. Looking at the graph of this line, you could go up and down the y-axis to infinity in either direction, and the graph of the line would be there.

The range is All Real Numbers.

Gracie’s overtime rate of pay would be $635.06.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Gracie earns 17.25/h for a 37.5h week, plus extra for overtime.

For one hour she earns $17.25

For 37.5h she earns = 37.5h x 17.25

                                   = $646.87

The total money she earns = $646.87 + overtime pay

During store inventory, she worked 48.5h. Her gross earnings were $1,471.88.

= 48.5h x 17.25

= $836.625

So, $836.625 + overtime pay = $1,471.88

overtime pay = $1,471.88 - $836.625 = $635.06

Hence, Gracie’s overtime rate of pay would be $635.06.

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The zeroes of the function f(x) = x (x – 8) will be 0 and 8.

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The function is given below.

f(x) = x (x – 8)

The zeroes of the function f(x) is given by the factor equals to zero.

Then we have

      f(x) = 0

x(x – 8) = 0

          x = 0, 8

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All of these questions require one thing: trigonometric functions.

There are 3 main trigonometric functions, which can only be used on right triangles: sine, cosine, and tangent.

Sine = opposite / hypotenuse

Cosine = adjacent / hypotenuse

Tangent = opposite / adjacent

When trying to figure out what function to use, we always start by looking from the angle. Take problem a, for example. Looking from angle E, of which the value is not given, we have the side opposite and the side adjacent. Therefore, we should use the tangent function.

---The hypotenuse is always the longest side of the triangle. It is never considered the opposite or adjacent side.

Let's set up our function with the given information from problem a.

tan(x) = 9.7 / 5.2

---The tangent of an unknown angle is equal to the quotient of the opposite side and the adjacent side.

Now, solving for the value of x will require a calculator. We'll need to use what's called an inverse trigonometric function. Most calculators have these directly above the regular trigonometric functions, and the inverse functions are accessed using a "second" key.

---Ensure that your calculator is in degrees, not radians!

x = tan^-1(9.7 / 5.2)

x = 61.805 = 62 degrees

Next, let's take a look at problem b. This time, we're solving for a side length instead of an angle. But, we're still going to start by looking from our angle.

Looking from the 38 degree angle, we are given the adjacent side and an unknown hypotenuse. Therefore, we should use the cosine function.

cosine(38) = 53.1 / r

---The cosine of a 38 degree angle is equal to the quotient of 53.1 and an unknown hypotenuse, r.

Use your algebra skills to isolate the variable r.

r * cosine(38) = 53.1

r = 53.1 / cosine(38)

---From here, all you need to do is plug this into your calculator. Since we are solving for a side length (and given an angle), we are just using the regular trigonometric function buttons on the calculator.

r = 67.385 = 67.4 units

Hope this helps!

[tex]15 \leq X \leq 25[/tex] is the equation represents the drivers allotted time (x) to receive a bonus.

An absolute value inequality is an expression with absolute functions as well as inequality signs.

According to the question:

Mathematically absolute value inequality is represented as :

|X -20|≤ 5

Solving the equation using

|z| ≤ a→ -a ≤ z  ≤ a :

here, z = X- 20 and a = 5:

[tex]| X-20| \leq 5\\\\ - 5\leq X-20 \leq 5[/tex]

By Solving X adding 20 on the three sides of the inequality

[tex]-5 + 20 \leq X -20 +20 \leq 5 + 20[/tex]

By simplifying it:

[tex]15 \leq X \leq 25[/tex]

Therefore the equation or inequality which represents the drivers allotted time (x) to receive a bonus [tex]15 \leq X \leq 25[/tex]

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[tex]2^x-3^x=\sqrt{6^x-9^x}\\\\D:6^x-9^x\geq0 \wedge 2^x-3^x\geq0\\D: 6^x\geq 9^x \wedge 2^x\geq3^x\\D:x\leq0 \wedge x\leq 0\qquad(\text{if }a < b \text{ then } a^x < b^x\text{ for } x > 0 \text{ and } a^x > b^x \text{ for } x < 0 )\\D:x\leq 0\\\\(2^x-3^x)^2=6^x-9^x\\(2^x-3^x)^2=3^x(2^x-3^x)\\\\\text{We divide both sides by } 2^x-3^x \text{ assuming }2^x-3^x\not=0\Leftrightarrow x\not=0.\\\\2^x-3^x=3^x\\2^x=2\cdot3^x\\\ln 2^x=\ln (2\cdot3^x )\\x\ln 2=\ln 2+\ln 3^x\\x\ln 2=\ln 2+x\ln 3[/tex]

[tex]x\ln 2-x\ln 3=\ln 2\\x(\ln 2-\ln 3)=\ln 2\\x=\dfrac{\ln 2}{\ln 2-\ln 3}=-\dfrac{\ln 2}{\ln 3-\ln 2}=-\dfrac{\ln 2}{\ln \frac{3}{2}}\approx-1.7[/tex]

For [tex]x=0[/tex], our initial equation is obviously true.

Therefore [tex]x\in\left\{-\dfrac{\ln 2}{\ln \frac{3}{2}},0\right\}[/tex].

Answer to the miscellaneous equation, is x=0 and x=-1.71

Miscellaneous equation are the equations which are not polynomial

The question can be solved by:

Factorising Splitting the terms to find the required solution

Completing the squares, etc

2ˣ - 3ˣ = √(6ˣ - 9ˣ)

Squaring both sides,

2²ˣ+3²ˣ -2.2ˣ.3ˣ=2ˣ.3ˣ - 3²ˣ

2²ˣ+2.3²ˣ -3.2ˣ.3ˣ=0

Factorising the terms,

2ˣ(2ˣ-3ˣ) -2.3ˣ(2ˣ-3ˣ)=0

(2ˣ-3ˣ)(2ˣ-2.3ˣ)=0

Equating the braces to zero,

Either,

2ˣ=3ˣ

x=0

or

2ˣ=2.3ˣ

Taking log on both sides

xln2=ln2+xln3

x=ln2/(ln2-ln3)

  =-1.71

Therefore, x=0 and x=-1.71 is the only solution

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Answer:

f(8) = 9

Step-by-step explanation:

f(x)=(x-5)^2

Let x = 8

f(8)=(8-5)^2

     = 3^2

     = 9

Answer:

Option 1

Step-by-step explanation:

See attached image

Step-by-step explanation:

0.000672, 6.72×10⁵, 67.2×10‐⁴, 672×10⁴

Scientific notation is a way of writing numbers that looks like the following:

[tex]a\times10^n[/tex]

For instance, we can write 2930 in scientific notation.

First, write all the given values in scientific notation:

Now, let's compare the values of n, and organize the numbers from least to greatest:

[tex]6.72\times10^{-4}[/tex]

[tex]6.72\times 10^{-3}[/tex]

[tex]6.72\times10^5[/tex]

[tex]6.72\times 10^6[/tex]

Finally, rewrite all the numbers as their given format:

[tex]0.000672[/tex]

[tex]67.2\times 10^{-4}[/tex]

[tex]6.72\times10^5[/tex]

[tex]672\times 10^4[/tex]

[tex]0.000672[/tex]

[tex]67.2\times 10^{-4}[/tex]

[tex]6.72\times10^5[/tex]

[tex]672\times 10^4[/tex]

Answer: A

Step-by-step explanation:

[tex]\frac{dy}{dx}=\frac{1+x}{xy} \\ \\ y \text{ } dy=\frac{1+x}{x} \text{ } dx \\ \\ y \text{ } dy= \left(\frac{1}{x}+1 \right) \text{ } dx \\ \\ \int y \text{ } dy=\int \left(\frac{1}{x}+1 \right) \text{ } dx \\ \\ \frac{y^{2}}{2}=\ln \left| x \right|+x+C[/tex]

Substituting in the initial condition,

[tex]\frac{(-2)^{2}}{2}=\ln \left|1 \right|+1+C\\\\2=1+C\\\\C=1[/tex]

So,

[tex]\boxed{\frac{1}{2}y^{2}=\ln \left|x \right|+x+1}[/tex]

Answer:

[tex]\textsf{A.} \quad \dfrac{1}{2}y^2=\ln|x|+x+1[/tex]

Step-by-step explanation:

To solve the differential equation:

Rearrange the given equation to get all the terms containing y on the left side, and all the terms containing x on the right side:

         [tex]\dfrac{dy}{dx}=\dfrac{1+x}{xy}[/tex]

[tex]\implies y\dfrac{dy}{dx}=\dfrac{1+x}{x}[/tex]

[tex]\implies y\:dy=\dfrac{1+x}{x}\:dx[/tex]

[tex]\implies y\:dy=\dfrac{1}{x}+\dfrac{x}{x}\:dx[/tex]

[tex]\implies y\:dy=\left(\dfrac{1}{x}+1\right)\:dx[/tex]

Integrate both sides:

[tex]\displaystyle \implies \int y\:dy=\int \left(\dfrac{1}{x}+1\right)\:dx[/tex]

[tex]\implies \dfrac{1}{2}y^2=\ln|x|+x+C[/tex]

Find the value of C using the given values of x and y:

when x = 1, y = -2

[tex]\implies \dfrac{1}{2}(-2)^2=\ln|1|+1+C[/tex]

[tex]\implies 2=0+1+C[/tex]

[tex]\implies C=1[/tex]

Substitute the found value of C:

[tex]\implies \dfrac{1}{2}y^2=\ln|x|+x+1[/tex]

The range of the given function will lie from ( -0.333,0) to ( 0,1).

A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

Given that:-

When we plot the graph of the function we will see that the straight line will cut the x-axis at point (-0.333 ) and the y-axis cut at ( 0,1 ) the points between the two points will be the solutions of the equation.

Therefore range of the given function will lie from ( -0.333,0) to ( 0,1).

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Answer:i think the answer is B

Step-by-step explanation:

Answer:

17.50 × 0.35 = 6.13

Step-by-step explanation:

Answer:

That would be $11.37

Step-by-step explanation:

First Multiply the discount and the original price

17.50(0.35)=  6.125 = 6.13

Use that answer and subtract it from the original price

17.50 - 6.13 = 11.37

Option D is correct the face value is the price that must be paid to the issuer to buy it at the time it is issued.

If the bond issuer doesn't default, face value, also known as par value, is the sum that is paid to a bondholder at the bond's maturity date. Bonds offered on the secondary market do, however, change in response to interest rates.

Therefore Option D is correct the face value is the price that must be paid to the issuer to buy it at the time it is issued.

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The correct answer is option B which is ( 5 / 3)

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division

The value will be calculated as:-

[tex]5\times \dfrac{1}{3}[/tex]  =  [tex]\dfrac{5}{3}[/tex]

1.67  = 1.67

Therefore the correct answer is option B which is ( 5 / 3)

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Answer:

Which one does not belong to the group

Answer:5.5

Step-by-step explanation:first we have to plus 4 and 7 and then we to divide the answer we get by 2 because there are only 2 digits and then the mean is 5.5

hope it helps

Using translation concepts, the method that Howard could have used to determine the coordinates of the vertices of the image is:

(x,y) -> (-x,y).

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

A reflection over the y-axis can be described according to the following rule:

(x,y) -> (-x,y).

Hence this rule can be applied to find the vertices.

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The equation given is matched with the respective vertex forms.

The standard equation for a circle is given by

(x-h)² + (y-k)² = r²

The equation given in the question are

x² + y²  − 4x + 12y − 20 = 0

(x − 6)²  + (y − 4)²  = 56

x²  + y²  + 6x − 8y − 10 = 0

(x − 2)²  + (y + 6)²  = 60

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

5x²  + 5y²  − 10x + 20y − 30 = 0

(x+3)²  + (y-4)²  = 35

2x²  + 2y²  − 24x − 16y − 8 = 0

(x-1)²  + (y+2)²   = 11

The first equation is

x² + y²  − 4x + 12y − 20 = 0

It can be written ad

x² -4x + 4 - 4 +y²+12y +36-36 -20 = 0

(x-2)² +(y+6)²= 60

The second equation is

x²  + y²  + 6x − 8y − 10 = 0

x² +6x +9-9 +y²  -8y +16-16 -10 = 0

(x+3)²  + (y-4)²  = 35

The third equation is

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

The fourth equation is

5x²  + 5y²  − 10x + 20y − 30 = 0

(x-1)²  + (y+2)²   = 11

The fifth equation is

2x²  + 2y²  − 24x − 16y − 8 = 0

(x − 6)²  + (y − 4)²  = 56

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Here, ΔTPQ is isosceles and TO is the angle bisector of ∠PTO.

[∵ TP=TQ = Tangents from T upon the circle]

⠀⠀⠀⠀⠀⠀⠀⠀∴ OT⊥PQ

⠀⠀⠀

___________________________________________

[tex]\longmapsto{}[/tex]By Applying Pythagoras Theorem in ∆OPR :

OR = √OP² - PR²

OR = √5² - 4²

OR = 3cm

__________________________________________

Now,

[tex]\leadsto[/tex]∠TPR + ∠RPO = 90° (∵TPO=90°)

[tex]\leadsto[/tex]∠TPR + ∠PTR (∵TRP=90°)

[tex]\leadsto[/tex]∴ ∠RPO = ∠PTR

⠀⠀

∴ Right triangle TRP is similar to the right triangle PRO. [By A-A Rule of similar triangles]

⟼[tex]\frac{TP}{PO} = \frac{RP}{RO} [/tex]

⟼[tex]\frac{TP}{5} = \frac{4}{3} [/tex]

⟼[tex]TP= \frac{20}{3} [/tex]

⠀⠀⠀⠀⠀

Answer: In the first week, Micah bought 11 gallons of gas,

and in the second week, he bought 8 gallons of gas

Step-by-step explanation:

In the first week, Micah bought x gallons of fuel at $2.39/gallon

In the second week, he bought (x - 3) gallons at $2.49/gallon

Formulating an equation and solving for x gallons of fuel:

x × 2.39 + (x - 3) × 2.49 = 46.21

2.39x + x × 2.49 − 3 × 2.49 = 46.21

2.39x + 2.49x − 7.47 = 46.21

4.88x − 7.47 = 46.21

4.88x = 53.68

[tex]\frac{4.88x}{4.88} = \frac{53.68}{4.88}[/tex]

x = 11

Therefore,

In the first week, Micah bought 11 gallons of gas

In the second week, he bought (11 - 3) = 8 gallons of gas

The correct expression is : [tex]\frac{4 cm }{1 year}[/tex] x [tex]\frac{10 mm}{1 cm}[/tex] x [tex]\frac{ 1 year }{365 days}[/tex]

What is the correct expression?

The first step is to convert year to days.

1 year = 365 days

The next step is to convert cm to mm.

1cm = 10 mm

4 x 10 = 40mm

Now, divide 40 mm by 365 days

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