if i poured green solution into another test tube and added some copper pieces to the solution will a displacment action occur

When the circuit is opened, a spark is much more possible.

The primary purpose of an inductor is the storage of energy. This is why an inductor helps to eliminate a spark in a circuit.

In the circuit as described in the question, we know that there is no current when the circuit is closed, the current across the inductor remains constant but rapidly decreases at the opening of the circuit this could lead to a spark.

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Answer: a. hydrogen

This is a fact.

Carbon is the reference taken to assign the atomic mass unit

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Answer:

Electric current

Definition:

The time rate of flow of electric charge, in the direction that a positive moving charge would take and having magnitude equal to the quantity of charge per unit time: measured in amperes.

Everything begins inside in the battery. The battery's zinc metal undergoes oxidation; here is where the flow of electrons into the conductors begins. Electrical field attraction will lead the wire's existing electrons to move towards the battery's positive terminal, and the loose electrons caused by the zinc metal will begin to fill the wire's empty spaces. process continues until the zinc metal's oxidation ceases. At rechargeable batteries, the oxidation-reduction process is also reversed by charging the battery, allowing the stored electrons in the positive terminal to flow back to the zinc metal's negative terminal.

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24.25 moles of NO can be produced using 97 moles of HNO3.

Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Varied elements' atom counts in the reactants and products of unbalanced chemical equations are different.

3 Cu + 8HNO3 g → 3 Cu(NO3)2 + 2 NO + 4 H2O

The number of moles consumed can be calculated using comparing with coefficients in the balanced reaction .

So , from above eq we get that 8 moles of HNO3 are consumed to make 2 moles of NO.

⇒  8 HNO3⇔2 NO

⇒ 1 HNO3⇔ 1/4 NO

This means that for each mole of HNO3 produces 1/4 moles of NO.

So , for 97 moles of HNO3 , [tex]\frac{1}{4} *97[/tex] moles of NO can be made,

So, total moles of NO made are 24.25 moles.

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24.25 moles of NO would be made when 97 moles of [tex]HNO_{3}[/tex] are consumed

Given reaction:

[tex]3 Cu + 8HNO_{3} - > 3 Cu(NO_{3})_{2} + 2 NO + 4 H_{2}O[/tex]

As the given reaction is already balanced so we don't need to balance it

In a balanced chemical reaction the ratio of reactants consumed and products formed always remains constant.

∵ In the given Reaction we can analyse for 8 moles [tex]HNO_{3}[/tex] consumed 2 moles of [tex]NO[/tex] are being produced.

Assuming [tex]x[/tex] moles of [tex]NO[/tex] being produced when [tex]97[/tex] moles [tex]HNO_{3[/tex] produced

∵ Ratio remains constant

⇒[tex]\frac{HNO_{3} Consumed}{NO Produced} = \frac{8}{2} =\frac{97}{x}[/tex]

⇒[tex]x=\frac{97}{4}=24.25[/tex] moles

∴ 24.25 moles of [tex]NO[/tex] would be made.

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This happens because the beaker is open.

The Law of Mass Conservation says that in a close system all the mass and energy should be the same.

If the system is open, as in the case, we can have loss of mass, due to formation of gas, that will leave the beaker to the environment, and we can also have loss of energy, because the system will exchange the energy, as heat, with the environment, causing a loss on the total energy.

Answer:

Its C its C its C

Explanation:

i dislike expert verifeid beacause he wont say C

Answer:

False

Explanation:

Because laws and theories are developed for different purposes, laws never become theories, and theories do not become laws.

Answer:

The percentage composition of a given compound is defined as the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100. Here, the quantity is measured in terms of grams of the elements present.

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Answer:

n

Explanation:

nobody knows

Answer:

chemical because it turned into a new compound

Explanation:

is zinc and hydrogen chloride combining into zinc chloride and hydrogen gas a chemical or physical change?​

physical change is like  boiling, melting, freezing, and shredding

but its still the same compound

chemical is like it turns into something else like a new compound

Zn + 2HCl = ZnCl2 + H2(g)

Metal + Acid → Hydrogen + Acid Anion

new compound forms in this reaction

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Answer:

V = 25.7 L

Explanation:

To find the volume of Argon (Ar), you need to use the Ideal Gas Law equation. This looks like:

PV = nRT

In this formula,

        > P = pressure (atm)

        > V = volume (L)

        > n = number of moles

        > R = constant (0.0821 L*atm/K*mol)

        > T = temperature (K)

While there is a different constant that can be used if you want to keep the pressure in mmHg, there is a more common constant used when the pressure is in atm. So, to find the volume, you need to (1) convert mmHg to atm (by dividing by 760) and then (2) calculate the volume (using Ideal Gas Law).

(Step 1)

600 mm Hg              1 atm
-------------------  x  ---------------------  =  0.789 atm
                              760 mm Hg

(Step 2)

PV = nRT

(0.789 atm) x V = (0.825 mole)(0.0821 L*atm/K*mol)(300 K)

(0.789 atm) x V = 20.32

V = 25.7 L

Enrichment of uranium-235 is done. Hence, option A is correct.

The act, process, or means of keeping something within limits the containment of health costs.

Enrichment is a process of increasing the proportion of fissile isotope found in uranium ore (represented by the symbol 'U') to make it usable as nuclear fuel or the compressed, explosive core of nuclear weapons.

Hence, option A is correct.

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The alkaline earth metals are also referred to as Group 2A. elements are comparable to one another in terms of their electron configurations and thus, their properties.

From beryllium (Be) through radium, the alkaline-earth metals comprise Group 2 of the periodic table (Ra). The alkaline earth metals are so reactive because each of these elements has two electrons in its lowest energy level that they are rarely encountered alone in nature. However, they don't react as quickly as alkali metals do. Compared to the alkali metals, their chemical reactions normally proceed more slowly and generate less heat.

Be :- [He]2S2

Mg:-[Ne]3S2

Ca :-[Ar]4S2

Sr:-[Kr]5S2

Ba:-[Xe]6S2

Ra:-[Rn]7S2

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Group 2A is another name for the alkaline earth metals, which are similar to one another in terms of their electron configurations and thus, their properties.

Group 2 of the periodic table is made up of alkaline-earth metals, starting with beryllium (Be) and ending with radium (Ra). The fact that each of these elements possesses two electrons at its lowest energy level makes the alkaline earth metals extremely reactive, which is why they are rarely found by themselves in nature. They don't respond as quickly, though, as alkali metals do. Their chemical reactions often take longer and produce less heat than those of the alkali metals.

Be:- [He]2S2

Mg:-[Ne]3S2

Ca:-[Ar]4S2

Sr:-[Kr]5S2

Ba:-[Xe]6S2

Ra:-[Rn]7S2

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Answer:

newtons law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of the distance between their centers

Answer:

an object at rest tends to stay at rest

Answer:

b

Explanation:

b is the ketone because it is and that's a fact

Answer:

D

Explanation:

Ketones are a class of organic compounds that have an Oxygen double bonded to the middle of the main carbon chain.

Option A is not a ketone (despite having an Oxygen double bonded to the middle of the main carbon chain) because it has an adjacent single bonded Oxygen in the main carbon chain.  This type of compound is classified as an "Ester".

Option B is not a ketone, but is instead classified as an aldehyde, a group of compounds with their Oxygen double bonded at the end of the main carbon chain.

Option C is not a ketone (despite having an Oxygen double bonded to the middle of the main carbon chain), but is instead classified as an Carboxylic Acid, because it has an adjacent single bonded Oxygen in the main carbon chain, and both of these pieces (with the single bonded O pointing outward) are at the end of the main carbon chain.

Option D is a ketone because it does have an Oxygen double bonded somewhere to the middle of main carbon chain, not at an end, and not with another Oxygen single bonded adjacently in the carbon chain.  Specifically, this ketone is "2-pentanone" or "methyl propyl ketone"

Answer:

0.893mol

Explanation:

n = m ÷ M

= 275 ÷ (23 + 80)

= 2.67 mol

* now use the Mol ratio *

NaBr : FeBr3

6 : 2

2.67 : x

5.67 = 6x

n( FeBr3 ) = 0.893 mol

The temperature of 0.049 moles of a Ne with a pressure of 1.00 atm and a volume of 2.50 L is 621.44K.

The temperature of a given gas can be calculated using the ideal gas law equation:

PV = nRT

Where;

P = pressure = 1.00 atm

V = volume =2.50 L

R = gas law constant = 0.0821 Latm/molK

Mass =1.00 gram

The molar mass of Ne= 20.1797 u

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{1.00}{20.1797}[/tex]

Moles = 0.049mol

T = temperature=?

Putting the value in the equation:

PV = nRT

1.00 atm × 2.50 L = 0.049mol × 0.0821 × T

T = 621.44K

Therefore, the temperature of 0.049 moles of a Ne with a pressure of 1.00 atm and a volume of 2.50 L is 621.44K.

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Cupric oxide (CuO) and cuprous oxide (Cu2O) are the names of two oxides of copper.

Both Cupric oxide (CuO) and cuprous oxide are different from one another because of the presence of number of copper atom. In one compound, copper is bonded with oxygen in 1:1 form whereas in the other compound, the copper is bonded with 2:1 form.

So we can conclude that Cupric oxide (CuO) and cuprous oxide (Cu2O) are the names of two oxides of copper.

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Mass of hydrate + crucible = 47.29 g

Mass of anhydrous salt = 2.7 g

Molar mass of anhydrous salt CuSO4 = 159.5 g

Given,

mass of empty crucible = 42.45 g

mass of hydrate salt= 4.84 g

mass of crucible after first heating = 46.1 g

mass of crucible after second heating= 45.153 g

mass of crucible after third heating= 45.15 g

so, as per the question we need to find...

Mass of hydrate + crucible = ? g

Mass of anhydrous salt = ? g

Molar mass of anhydrous salt CuSO4 = ? g

∴Mass of hydrate + crucible = 42.45 + 4.48 = 47.29 g

The given salt is in hydrate form, to remove water from this molecule we need to perform heating .

So we are taking the substance into the crucible as it is in less quantity.

Here, we performed heating 3 times and note the weight after every heating.

After this, assume that the water is totally evaporated and the remaining salt is in anhydrous form,

∴ Mass of anhydrous salt = 45.15 - 42.45 = 2.7 g

To find the molar mass of anhydrous salt of CuSO4,

atomic weight of Cu = 63.5 g

atomic weight of S = 32 g

atomic weight of O =16 g

∴ molar mass of anhydrous salt of CuSO4 = 63.5 + 32 + (16 ×3)

                                                                   =159.5 gm

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Answer:

C.) 4.85 x 10⁻¹⁹ J

Explanation:

To find the energy, you need to use the following equation:

E = hc / w

In this formula,

-----> E = energy (J)

-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

-----> c = speed of light (3.00 x 10⁸ m/s)

-----> w = wavelength (m)

Once you have converted nanometers to meters, you can plug the given values into the equation and solve.

410 nm                1 m
-------------  x  ----------------------  =  4.10 x 10⁻⁷ m
                        1 x 10⁹ nm

E = hc / w

E = (6.626 x 10⁻³⁴ J*s)(3.00 x 10⁸ m/s) / (4.10 x 10⁻⁷ m)

E = 4.85 x 10⁻¹⁹ J

Answer:

B. the reaction absorbs energy (+ or endothermiic)

Answer:

CO_(2)` molecules removed `= 10^(21)` <br> No. of `CO_(2)` molecules left `= 2.74 xx 10^(21) - 10^(21) = 1.74 xx10^(21)` <br>

Explanation:

The label appears in the organic product and not in the water owing to the fact that water is eliminated as -OCH3 replaces -OH.

Isotopic labelling is one of the methods by which a chemical reaction is studied. In this case, we can see that the reaction occurs with the hemiacetal reacting with a labeled methanol.

By looking at the reaction products we can see that the label appears in the organic product and not in the water owing to the fact that water is eliminated as -OCH3 replaces -OH.

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Answer:

9.519e^-2

Explanation:

To accurately show the number in scientific notation, you need to move the decimal place to the left 2 spaces. Because you are moving the decimal place to the left, the exponent will be a negative number. Because the decimal place moves 2 units to the left, the exponent will be a -2.

Therefore, the answer in correct scientific notation is:

951.9 ----------> 9.519e^-2

The weakness of the rutherford model of the atom that bohr addressed is that

The Rutherford model of the atom proposed by Ernest Rutherford in 1911 shows that the atom is much hollow space with its mass concentrated at the center being surrounded by electrons. It is the planetary model.

The Bohr model of the atom proposed by Neils Bohr in 1913 suggests that

The weakness of the rutherford model of the atom that bohr addressed is that

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The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The term electrolysis has to do with the decomposition of a substance by the passage of a direct current through it.

The ions present in the system are[tex]H^+[/tex], [tex]OH^-[/tex] and [tex]NO_3^-[/tex] ions. The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The half-reaction equation of the reduction is;

[tex]2H^+(aq) + e[/tex] → [tex]H_2(g)[/tex]

The oxidation half-reaction equation is;

[tex]4OH^- (aq)[/tex] → [tex]2H_2O(l) + 4e[/tex]

The overall equation is;

[tex]4H^+(aq) + 4OH^- (aq)[/tex] → [tex]4H_2(g) + 2H_2O(l) + 4e[/tex]

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Answer:

B

Explanation:

The answer is B, O2

O₂ is the limiting reagent.

A limiting reactant is described as the one that will be consumed first in a chemical reaction.

C₁₀H₈ + 12O₂ → 10CO₂ + 4H₂O

Given, Mass of O₂ = 23.3 g

           Mass of C₁₀H₈ = 18.3 g

Molar mass of O₂ = 32 g

No. of moles of O₂ = 32/23.3 = 1.4 moles

Molar mass of C₁₀H₈ = 128 g

No. of moles of C₁₀H₈ = 128/18.3 = 6.9 = 7 moles

According to the equation,

1 mole of C₁₀H₈ yields 10 moles of CO₂. So, 7 moles of C₁₀H₈, give 70 moles of CO₂.

12 moles of O₂ yields 10 moles of CO₂. So, 1.4 moles of O₂ give 1.16 moles of CO₂.

We do know, however, that based on our balanced equation, if we were to totally react all 1.4 moles of O2, we could only produce a maximum of 1.16 moles of CO2. Even while there is enough C10H8 to generate more, the amount of O2 we have is a limiting factor because it will be consumed first.

So, our limiting reactant is O₂.

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If the earth is completely an oxidizing atmosphere, materials would ignite spontaneously when they are exposed to air.

Let us recall that oxidation has to do with an increase in oxidation number. If the earth is left as an oxidizing atmosphere without any attenuation, we can not have pure substances.

Secondly, materials would ignite spontaneously when they are exposed to the oxidizing atmosphere of the earth.

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Answer: Fe2O3

Explanation: By applying crisscross method, the formula will be Fe2O3.