Answer: 140.625
Explanation: Because energy gained due to damped motion and needs to be absorbed
A car travels with speed 3 m/s for the first half distance of the journey and with speed 6 m/s for the remaining half. What is the average speed of the entire journey?
(1) 6 m/s
(2) 18 m/s
(3) 9 m/s
(4) 4 m/s
Explanation:
hope this gives u a little hint!!!!
The average speed of the entire journey is 4 m/s.
The given parameters:
Initial speed of the car, u = 3 m/sFinal speed of the car, v = 6 m/sLet the total distance of the journey = d
The time taken for the first half of the journey is calculated as follows;
[tex]t_1= \frac{d}{v_1} = \frac{d}{3} [/tex]
The time taken for the second half of the journey is calculated as follows;
[tex]t_2 = \frac{d}{v_2} = \frac{d}{6} [/tex]
The average speed of the entire journey is calculated as follows;
[tex]v = \frac{d + d}{t_1 + t_2} \\\\ v = \frac{2d}{d/3 \ + \ d/6} \\\\ v = \frac{2d}{d/2} \\\\ v = \frac{4d}{d} \\\\ v = 4 \ m/s[/tex]
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A ball hangs on a rope of 0.30 m. The ball is pushed horizontally so that it has a speed of 1.1 m/s. What angle does the rope make with the vertical when the ball's kinetic energy is halved
This question involves the concepts of the law of conservation of energy, Pythagora's Theorem, kinetic energy, and potential energy.
The rope makes an angle of "26.2°" with the vertical when the ball's kinetic energy is halved.
First, we will find the initial kinetic energy of the ball:
[tex]K.E = \frac{1}{2}mv^2\\\\K.E=\frac{1}{2}(m)(1.1\ m/s)^2\\\\K.E = (0.605\ m^2/s^2) m[/tex]
Now, half of this kinetic energy is left at the final point. Therefore, according to the law of conservation of energy, the other half must be converted to the potential energy of the ball:
[tex]P.E=\frac{1}{2}K.E\\mgh'=\frac{1}{2}(0.605\ m^2/s^2)m\\\\h'=\frac{0.3025\ m^2/s^2}{9.81\ m/s^2}\\\\h' = 0.031\ m[/tex]
This h' is the height of the ball above the ground the final position, as shown in the picture attached.
Applying Pythagora's Theorem to the right angled triangle shown in the attached picture we have:
[tex]Cos\theta = \frac{Base}{Hypotenuse}=\frac{h}{l}[/tex]
where,
θ = angle of rope with vertical = ?
l = legth of rope = 0.3 m
h = l - h' = 0.3 m - 0.031 m = 0.27 m
Therefore,
[tex]Cos\theta=\frac{0.27\ m}{0.3\ m}\\\\\theta = Cos^{-1}(0.89721)[/tex]
θ = 26.2°
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(b) The block takes time tup to slide up the ramp a distance x The block then takes time down to slide back down to the bottom of the ramp, where it has speed up. Is flows greater than equal to
or less tup?
tdown >tup -tdown = tup .tdown
In a clear, coherent paragraph-length response that may also contain figures and/or equations, explain your reasoning. If you need to draw anything other than what you have shown in part (a) to
assist in your response, use the space below. Do NOT add anything to the figures in part (a).
Newton's second law allows finding the result for the comparison of the rise and fall times of the block on the ramp is:
The acceleration of the two processes is the same, if the initial velocity is equal, the times are equal.
Newton's second law establishes a relationship between the net force, the masses and the acceleration of the bodies.
∑ F = m a
Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.
The reference system is a coordinate system with respect to which the forces are drawn, in the attached we can see a free body diagram of the block going up and down the ramp, in this case the x axis is parallel to the ramp and the y axis it is perpendicular.
Let's use trigonometry to find the components of weight.
sin θ = [tex]\frac{W_x}{W}[/tex]
cos θ = [tex]\frac{W_y}{W}[/tex]
Wₓ = W sin θ
[tex]W_y[/tex] = W cos θ
Let's write Newton's second law for each axis.
Case 1. block slides down.
x- axis
Wₓ = ma
mg sin θ = ma
a = g sin θ
Case 2. block rises
X axis
- Wₓ = m a
- m gsin θ = a
a = - g sin θ
We can see that the acceleration is the same in two two cases, if the block has the same initial speed, the rise and fall time is the same.
y = v₀ t - ½ a t²
y = ½ a t²
In conclusion using Newton's second law we can find the result for the comparison of the rise and fall times of the block on the ramp is:
The acceleration is the same, if the initial velocity is the same, the times of going up and down are the same.
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Three cars (car F, car G, and car H) are moving with the same velocity, and slam on the brakes. The most massive car is car F, and the least massive is car H. Assuming all three cars have identical tires, which car travels the longest distance to skid to a stop
Answer:
depends on how they are made and what there made with
Explanation:
i know that the larger one might be the one to stop and skidd but so would the little one because it can go faster than the larger on because it has less mass and it will speed fast and then slowly slow down
A 2.0 kg block is pushed 1.0 m at a constant velocity up a vertical wall by a constant force
applied at an angle of 27.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s
If the coefficient of kinetic friction between
the block and the wall is 0.30, find
a) the work done by the force on the block.
b) the work done by gravity on the block.
c) the magnitude of the normal force between
the block and the wall.
.
Answer:
(a) The work done by frictional force is 7.0 J
(b) The work done by gravity is 8.9 J.
(c) The magnitude of the normal force on the block and the wall is 17.5 N.
The given parameters;
mass of the block, m = 2 kg
distance moved by the block, d = 1.0 m
angle of inclination of the force, θ = 27⁰
coefficient of friction, μ = 0.4
The normal force on the block is calculated as follows;
The frictional force is calculated as;
The work done by frictional force is calculated as follows;
The work done by gravity is calculated as follows;
The magnitude of the normal force on the block and the wall
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matter comprises all of them and among them are independent. what are they
Matter is composed of elementary particles i.e. quarks and leptons.
Matter is composed of elementary particles i.e. quarks and leptons.Matter is composed of elementary particles which is called quarks and leptons. Quarks consist of protons, neutrons and electrons. All observable matter is made up of up quarks, down quarks and electrons.
Matter is composed of elementary particles i.e. quarks and leptons.Matter is composed of elementary particles which is called quarks and leptons. Quarks consist of protons, neutrons and electrons. All observable matter is made up of up quarks, down quarks and electrons.Lepton is an elementary particle consist of half-integer spin that does not undergo strong interactions. Leptons exist on two main classes i.e. charged leptons, and neutral leptons. Electron, electron neutrino, muon, muon neutrino, tau and tau neutrino are the six types of leptons.
What are electromagnetic waves?
A:Waves that have different colors and can travel through
the emptiness of space.
B:Waves that can travel through the emptiness of space
very slowly
C:Waves that can travel through the emptiness of space
and stops when it gets close to the earth's
atmosphere.
D:Waves that can travel through the emptiness of space,
at the speed of light.
Answer:
Electromagnetic waves are waves which can travel through the vacuum of outer space. Mechanical waves, unlike electromagnetic waves, require the presence of a material medium in order to transport their energy from one location to another
Answer:
Electromagnetic waves are waves which can travel through the vacuum of outer space. Mechanical waves, unlike electromagnetic waves, require the presence of a material medium in order to transport their energy from one location to another
Hope it's Helpful for all
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what temperature change on the kelvin scale is equivalent to a 10 degree change on the celsius scale
Answer:
Fahrenheit scale
Explanation:
just guess equivalent to 10 degree
Use the equation for motion to answer the question.
An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?
A. 30 m
B. 60 m
C. 32 m
4. 17 m
Equation Below:
The final position of the object would be 17 meters , therefore the correct answer is option D.
What are the three equations of motion?There are three equations of motion given by Newton
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem, an object has a starting position of 2 meters, a starting velocity of 15 meters/second, and is moving at a constant speed.
The initial position of the object = 2 meters
The object is moving at a constant speed of 15 meters/second.
The final position of the object after 1 second = 2 +15×1
= 17 meters
Thus, the final position of the object would be 17 meters, therefore the correct answer is option D.
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A car is parked on a 20 degree hill. It has a mass of 1550 kg. What is the frictional force on the car?
Answer:
Explanation:
The friction force must balance (acting up slope) the weight component of the car (acting down slope)
Ff = mgsinθ
Ff = 1550(9.8)sin20
Ff = 5,195.28597...
Ff = 5200 N
18. (II) Tarzan plans to cross a gorge by swinging in an arc
from a hanging vine (Fig. 5-42).
If his arms
are capable of
exerting a force of 1150 N on
the vine, what is the maximum
speed he can tolerate at the
lowest point of his swing? His
mass is 78 kg and the vine is
4.7 m long.
Answer:his weight plus the centripetal force must equal 1170 N
Explanation:
83.0 [g + (v^2 / r)] = 1170
v^2 / 18.0 = (1170 / 83.0) - 9.81
Scale 1:21 pound 3 cm how deep is real pond
Answer:
The real pond is 63 centimeters deep.
Explanation:
hope this helps. . .<3
if you have a kinetic energy of 1470 J, and you are 60kg mass and 0 m above the ground, what is you velocity?
KE = 1/2 · m · v²
1470 = (1/2 · 60) · (v²)
v² = 1470 / 30
v² = 49
v = √49
v = 7 m/s
(Note: Kinetic energy has nothing to do with height above ground.)
Four people are pulling on a box with the forces shown below. If there are no other forces on the box, in what direction will it move?
toward the right side of the page
toward the bottom of the page
directly toward Arthur
directly toward Diane
Answer:
go to the website jiksha
Explanation:
A spring has K=24 N/m, we put in its end an object with 4 kg, if we pull the object 0.5 m then leave it, what would be the speed in 0.3 m from the balance point.
Answer:
Velocity- v=10m/s south Speed- v=10m/s
Explanation:
the salar measurement of how fast an object is moving.
Velocity- v=10m/s south :
The vector rate of change of position.
Speed- v=10 m/s : the salar measurement of how fast an object is moving.
The velocity of the mass of 4 kg at 0.5 m is 1.732 m/sec. And the velocity of the mass of 4 kg at 0.3 m is 1.34 m/sec.
What is energy conversion?The sum of kinetic energy and the potential energy of the body is constant. which is the energy of the remains conserved. This is known as energy conversion.
A spring has K=24 N/m.
We put in its end an object with 4 kg.
If we pull the object 0.5 m. Then the velocity will be given by the conservation of energy.
[tex]\begin{aligned} \rm K.E \ of \ mass &= \rm P.E. \ of \ spring\\\\ \dfrac{1}{2} m v^2 &= \dfrac{1}{2} kx^2\\\\\dfrac{1}{2}*4*v^2 &= \dfrac{1}{2} * 24 * 0.5\\\\v^2 &= 3\\\\v &= \sqrt{3} \\\\v &= 1.732 \ \ \rm m/sec \end{aligned}[/tex]
The speed at 0.3 m from the balance point. Then the velocity will be given by the conservation of energy.
[tex]\begin{aligned} \rm K.E \ of \ mass &= \rm P.E. \ of \ spring\\\\ \dfrac{1}{2} m v^2 &= \dfrac{1}{2} kx^2\\\\\dfrac{1}{2}*4*v^2 &= \dfrac{1}{2} * 24 * 0.3\\\\v^2 &= 1.8\\\\v &= \sqrt{1.8} \\\\v &= 1.34 \ \ \rm m/sec \end{aligned}[/tex]
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A student is participating in the hammer throw. The student rotates in uniform circular motion with the mass rotation 2.3 m away from the center of rotation. Refer to the information and diagram shown above. The student athlete can rotate so that the
object is moving with a speed of 10 m/s.
A. Calculate the acceleration necessary to maintain uniform circular motion.
B. If the length of the chain is increased, doubling the distance from the athlete to the
mass, By what factor will the acceleration of the ball change if the speed remains
unchanged?
C. The net force that causes the centripetal acceleration of an object in a circular motion is the_?
D. What happens to the centripetal acceleration of the ball if its mass is doubled?
The centripetal acceleration relations and Newton's second law we can find the results for the questions about the change in centripetal acceleration when changing the conditions of motion are:
A. The centripetal acceleration is: a = 43.5 m / s²
B. The radius is doubled, the centripetal acceleration is halved.
C. The force that creates the movement is called the centripetal force.
D. If the mass is doubled, the centripetal acceleration is halved.
Kinematics studies the motion of bodies, in the case of rotational motion, it looks for relationships between the angle, the angular velocity and the angular acceleration.
The centripetal acceleration of the body is
a = [tex]\frac{v^2 }{r}[/tex]
A. Indicate the velocity of the body v = 10 m/s and the radius of the circle r=2.30 m. Let's calculate the centripetal acceleration is:
a = [tex]\frac{10^2}{2.3}[/tex]
a = 43.5 m / s²
B. The radius is doubled, ask the change in acceleration
r₂ = 2 r₀
a₂ = [tex]\frac{v^2}{r_2}[/tex]
a₂ = [tex]\frac{v^2}{2 r_o}[/tex]
a₂ = ½ a₀
[tex]\frac{a_2}{a_o} = \frac{1}{2}[/tex]
Let's calculate
a₂ = ½ 43.5
a₂ = 21.75 m / s²
C. The force that maintains the movement is called the centripetal force and it was directed towards the center of the circle.
We use Newton's second law.
F = m a
F = 43.5 m
whera m is the body mass.
D. Question what happens to the acceleration centripetal if we double the mass.
We assume that the force applied by the athlete remains constant, let's write Newton's second law.
F = ma a
a = F / m
the mass is
m = 2 m₀
we substitute
a = [tex]\frac{F}{2m_o}[/tex]
a = ½ a₀
a = 21.75 m / s²
we see that doubling the mass the acceleration is reduced by half.
In conclusion, using the cenripetal acceleration relations and Newton's second law we can find the results for the questions about the change in centripetal acceleration when changing the conditions of motion are:
A. The centripetal acceleration is: a = 43.5 m / s²
B. The radius is doubled, the centripetal acceleration is halved.
C. The force that creates the movement is called the centripetal force.
D. If the mass is doubled, the centripetal acceleration is halved.
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When the pinball is 2.5 m above its initial location (on the way up), find its linear and angular speeds.
Answer:When the pinball is 2.5 m above its initial location (on the way up), find its linear and angular speeds.
Explanation:
sorry need answers
A car accelerate uniformly from rest at
[tex]5ms { - 2} [/tex]
Determine its speed after 10 s
Answer:
69km per sc
Explanation:
This mathematical model describes the changes that occur in a sample of
water as its temperature increases. Based on this model, how do you expect
the motion of the molecules in ice to compare with the motion of molecules
in water vapor
200°C
Vaporization
150°C
melting
100°C
Temperature (°C)
water vapor
50°C
liquid water
0°C
-50°C
10
20
ice
30 40
Time (min)
50
60
70
O
A. This model does not provide enough data to answer the question
B. I expect the molecules in water vapor to move more quickly than
the molecules in ice.
a
C. I expect the molecules in ice to move more quickly than the
Answer:
I think it might be (a) if that helps
April stands on a flat surface. If she has a mass of 72 kg, what is the normal
force acting on her?
A. 441 N.
B. 296 N
C. 625 N
D. 706 N
Answer:
706
Explanation:
IF she is on or near the surface of Earth at the time, then ...
... Her WEIGHT is (mass) (gravity) = (72 kg) (9.8 m/s²) = 705.6 Newtons
... The surface under her feet exerts a normal force, upward,
against her feet.
... If the upward normal force is NOT 705.6 Newtons, then the
NET force on the bottom of her feet is not zero, and her feet are
accelerating, either up or down.
... But she is just standing there, not accelerating either up or down.
... Therefore, the NET force on the bottom of her feet must be zero.
... The normal force acting upward against her feet must be exactly
equal to her weight ... 705.6 Newtons.
Answer:
Explanation:
72(9.8) = 706 N upward.
Hello, 80 Points! Please help me! There are three questions below, each question has three options which will be listed.
Use the graph to answer the questions.
What does the bump in the graph represent?
- energy levels of the products
- energy levels of the reactants
- activation energy
The energy of the products is ________than the energy of the reactants.
- the same as
- lower
- higher
What type of reaction does the graph represent?
- endothermic
- exothermic
- endothermic with a catalyst
- exothermic with a catalyst
Answer:
Explanation:
the bump is activation energy
product energy is lower than that of the reactants so the reaction is
An exothermic reaction.
Rather difficult to determine if a catalyst assist is present because we would need to have a comparison between activation energy with and without catalyst.
The bump in the graph represents activation energy, the energy of the products is lower than the energy of the reactants, and this reaction is an exothermic reaction. Thus, the correct options for 1, 2, and 3 are C, B, and B, respectively.
What is an exothermic reaction?
An exothermic reaction is a chemical reaction which requires the transfer of energy to or from the surroundings. When energy is transferred to the surrounding or Universe, this is called an exothermic reaction, and as a result the temperature of the surroundings increases.
In the given graph, the bump represents the activation energy of the reaction which is required to form the product molecules.
In the given reaction, the energy of the products is lower than the energy of the reactants and thus, the reaction is an example of exothermic reaction.
Therefore, the correct options for 1, 2, and 3 are C, B, and B, respectively.
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answer plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Answer:
I kind of do not get this but I think I know the answer it should be choice B
Explanation:
Answer:
it is B, a wave is not a thing of its own it is a disturbance, so unless it is an em wave it must go through something if that makes sense lol
drag's top accleration is 60 m/s 2 if it start from the rest at starting line how fast will it be going after 3 secondes
Answer:
Explanation:
v = at
v = 60(3)
v = 180 m/s
What happened to the Western Africa empires?
Answer:
they died lol XD Gang op.....
The Israelites were led to freedom by Adam after 400 years of bondage. True or False?
Answer:
False
Explanation:
Moses led them out of Egypt and through the desert. His general, Joshua, then took over.
what is displacement
Answer:
Displacement is the absolute value of the difference between the initial position and the final position.
What is net force 200N air and 600N gravity
PLEASE HELP !
i’ll make you brainiest!’
find the maximum velocity of a roller coaster with a mass of 2,250 kg when it reaches the bottom of a 90 meter drop.
Show Work!
Answer:
gravitational potenetial energy =ℎ
Explanation:
none
How to calculate refractive index
Refractive index 'n' = sin incidence / sin refection
Refractive index has no unit.
a particle having a charge of 1.20C experiences a force of 4.20 N at a certain point another negatively charged particle experiences a force towards right when kept at the same point which of these best represents the electric field at the point
The electric field experienced by the charge particle at the given point is 3.5 N/C.
The given parameters;
charge of the particle, q = 1.2 Cforce experienced by the particle, F = 4.2 NThe electric field experienced by the charge particle is calculated as;
[tex]E = \frac{F}{q} \\\\E = \frac{4.2}{1.2} \\\\E = 3.5 \ N/C[/tex]
Thus, the electric field experienced by the charge particle at the given point is 3.5 N/C.
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