The magnitude of the potential difference between A and B is 195 V.
Potential of charge A
The potential of charge A is calculated as follows;
Va = kq/r
where;
k is Coulomb's constantq is magnitude of the charger is the position of the chargeVa = (9 x 10⁹ x 2 x 10⁻⁹) / (0.3)
Va = 60 Volts
Potential of charge BVb = kq/r
Vb = (9 x 10⁹ x -3 x 10⁻⁹) / (0.2)
Vb = -135 Volts
Potential between A and BVAB = VB - VA
VAB = -135 V - 60 V
VAB = -195 V
Thus, the magnitude of the potential difference between A and B is 195 V.
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Q7. A 2kg ball is released from a height of 20m.
What is it velocity when its height has decreased to 5
m?
Answer:
Given,
Mass, m = 2kg
Height or distance, s = 20m
Initial velocity, u = 0m/s
Acceleration due to gravity, g = 10m/s (It is 9.8m/s but can be assumed 10m/s for simplifying calculations)
(Because the object is is just dropped)
Final velocity, v = ?
Solution
v^2 = u^2 + 2as (u^2 means u raised to power 2)
=> v^2 = 0^2 + 2*10*20
=> v^2 = 400
=> v = 20
Thus the velocity just before the body strikes the ground will be 20m/s.
Which explanation best describes a wave?
A.
a disturbance that travels through a medium with a transfer of energy and matter
B.
a disturbance that travels through a medium without a transfer of energy and matter
C.
a disturbance that travels through a medium with a transfer of energy and without a transfer of matter
D.
a disturbance that travels through a medium with a transfer of matter and without a transfer of energy
E.
a disturbance that travels only in the absence of a material medium
Answer:
D
Explanation:
A disturbance that travels through a medium with a transfer of matter and without a transfer of energy best describes a wave. Option D best describes a wave.
What is wave?A wave is a phenomenon that flows across a material medium without leaving any lasting mark. Mechanical or electromagnetic waves can be used to classify it. Transverse and longitudinal are the two main forms.
Wave motion that is parallel to the wave direction is described as longitudinal wave.
A wave is a disturbance that moves across a medium with a transfer of matter , but not an energy transfer.
A disturbance that travels through a medium with a transfer of matter and without a transfer of energy best describes a wave.
Hence, option D best describes a wave
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The vector matrix [6 -2] is rotated at different angles. Match the angles of rotation with the vector matrices they produce.
Answer:
Hello your question is incomplete hence I will give you a general answer as regards rotation of vector matrix assuming angle of rotation = [tex]\frac{\pi }{4}[/tex]
answer :
angle of rotation = [tex]\frac{\pi }{4}[/tex]
vector matrix produced = attached below
Explanation:
lets assume the vector matrix [ 6, -2 ] is rotated clockwise by an angle of [tex]\frac{\pi }{4}[/tex]
The resultant matrix = attached below
Result of the rotation = attached below
attached below is the detailed solution
Answer: I got it right on Edmentum
Explanation: Answers attached below
A pendulum is constructed from a heavy metal rod and a metal disk, both of uniform mass density. The center of the disk is bolted to one end of the rod, and the pendulum hangs from the other end of the rod. The rod has a mass of =1.0 kg and a length of =49.8 cm. The disk has a mass of =4.0 kg and a radius of =24.9 cm. The acceleration due to gravity is =9.8 m/s2.
The pendulum is held with the rod horizontal and then released. What is the magnitude of its angular acceleration at the moment of release?
The magnitude of the angular acceleration of the pendulum at the moment of release is; α = 18.45 rad/s²
We are given;
Mass of rod; m = 1 kg
Length of rod; L = 49.8 cm = 0.498 m
Mass of Disk; M = 4 kg
Radius of disk; r = 24.9 cm = 0.249 m
Let us first calculate the torque acting from the formula;
τ = mg(L/2) + MgL
Thus;
τ = (1 × 9.8 × (0.498/2)) + (4 × 9.8 × 0.498)
τ = 21.96 N.m
Using parallel axis theorem, we can find the moment of inertia about the given axis as;
I = (mL²/3) + ½MR² + ML²
Plugging in the relevant values gives;
I = (1 * 0.498²/3) + ½(4 * 0.249²) + (4 * 0.498²)
I = 1.19 kg.m²
The angular acceleration is given by the formula;
α = I/τ
α = 21.96/1.19
α = 18.45 rad/s²
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Which of the following is NOT a human blood type?
a.
O
c.
B
b.
AB
d.
R
Answer:
d. R
Explanation:
There are 4 main types of blood – A, B, AB and O.
Blood is the most important component of our life. It is a fluid connective tissue which consists of plasma, blood cells and platelets. It circulates throughout the body and delivers oxygen. Among the given options R is not a blood type. The correct option is D.
What are blood types?It was Karl Landsteiner who discovered the ABO blood group system. There are 4 main blood groups, they are A, B, AB and O. Your blood group is determined by the genes you inherit from your parents. Each blood group may be either RhD positive or RhD negative.
Blood group A has antigens on the red blood cells with anti-B antibodies in the plasma. Blood group B has B antigens with anti-A antibodies in the plasma. The blood group O has no antigens but both antibodies are present whereas AB has no antibodies.
Group O is the universal donor and AB is universal recepient.
Thus the correct option is D.
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What is quantum physics?
Answer:
A fundamental theory that provides a description of the physical properties of nature at the scale of atoms and subatomic particles.
Explanation:
5. You are pulling a rubber sneaker along concrete
a. Calculate force of static friction between your sneakers (2kg) and sidewalk if coefficient of
static friction is 0.9
Answer:
Fs = 17.66 N
Explanation:
The force of static friction is given by the following formula:
[tex]F_s = \mu R = \mu W\\[/tex]
where,
Fs = The force of static friction = ?
μ = coefficient of static friction = 0.9
W = weight of sneakers = mg
m = mass of sneakers = 2 kg
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]F_s = \mu mg\\F_s = (0.9)(2\ kg)(9.81\ m/s^2)\\[/tex]
Fs = 17.66 N
I WILL REPORT YOU IF YOU ANSWER WITH LINK!!! WILL GIVE BRAINLIEST
You have two identical bowling balls that are 1.00 m apart as measured from their centers. There is an attractive force of gravity between them due to their mass. When a net charge of +0.40 nC is placed on each bowling ball, the force exerted by the electrostatic forces exactly balances the force of gravity on the bowling balls resulting in a net charge of zero. The formula for the electrostatic force is similar to the formula for the gravitational force. There is a constant that is multiplied by the magnitude of each of the two charges and divided by the square of the distance between them. What two conclusions can you draw from this information?
CHOOSE 2 ANSWERS
Answer:
I think is is
Explanation:
B and C why because i have a gut feeling
calculate the speed of atrain
that travels 540 meters in 30
seconds?
Answer:
The train is traveling 18 meters per second.
Explanation:
540/30 = 18
To check your answer do 18 * 30 and it equals 540
5.
What is gravity?
a) A force
D b) Energy
c) A push
d) All of them
science
A). force
hope it helps and your day will be full of happiness
A box of weight 20N rests on a horizontal floor. A maximum horizontal force of 6N is required to move the box along the floor .If the weight of 10N is added to the box , find the minimum horizontal force required to move the box.
10 You are given the following list of vo-
lumes: 0.45 m3; 375 cm3; 75 cL; 0.6 dm3.
a. Express all the volumes of the list in
liters.
b. Arrange these volumes in a descending
order.
Volumes can be transfered to liters only when their measurement units are dm³. a) Which means that: 0.45m³=450dm³ you move the decimal place three places to the right because m³ is larger measurement unit than dm³. 375 cm³ = 0.375 dm³; 75cl = 0.75l because of the prefix centi. 0.6dm³ = 0.6 dm³
So it will be 450l; 0.375l; 0.75l; 0.6l
b) 450l>0.75l>0.6l>0.375l
0.45m³>75cl>0.6dm³>375cm³
I hope i didn't make a mistake, but it would be good if somebody else answered too, so you can compare the answers and see if i made a mistake
The given volumes in liter will be 450 L, 0.375 L, 0.75 L, 0.6 L and the arrangement in descending order will be 450 L > 0.75 L > 0.6 L > 0.37 L .
What is Volume?Every three-dimensional item takes up space in some way. The volume of this area is what is used to describe it. The area covered within an entity's three-dimensional bounds is referred to as its volume. The object's size is another name for it.
As per the given information in the question,
a.
The given volume in a meter cube is 0.45.
Unit conversion:
1 m³ = 1000 L
So, 0.45 m³ = 0.45 × 1000
= 450 L
The given volume in a centimeter cube is 375.
Unit conversion:
1 cm³ = 0.001 L
375 cm³ = 0.001 × 375
= 0.375 L.
The given volume in a centiliter cube is 75.
Unit conversion:
1 cl³ = 0.01 L
75 cl³ = 75 × 100
= 0.75 L
The given volume in the decimeter cube is 0.6.
1 dm³ = 1 L
0.6 dm³ = 0.6 L
b.
So, the volumes in descending order will be,
450 L > 0.75 L > 0.6 L > 0.37 L or,
0.45 m³ > 75 cl³ > 0.6 dm³ > 375 cm³
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7. A 3.0 kg object travels vertically at a constant
velocity of 1.5 m/s. What is the increase in
gravitational potential energy after 5.0 s?
Answer:
220.7
Explanation:
distance traveled is 1.5*5=7.5m
PE gain is MGH=3*9.81*7.5=220.7
Archerfish are tropical fish that hunt by shooting drops of water from their mouths at insects above the water’s surface to knock them into the water, where the fish can eat them. A 65-g fish at rest just at the surface of the water can expel a 0.30-g drop of water in a short burst of 5.0 ms. High-speed measurements show that the water has a speed of 2.5 m/s just after the archerfish expels it. What is the average force the fish exerts on the drop of water?
(a) 0.00015 N;
(b) 0.00075 N;
(c) 0.075 N;
(d) 0.15 N.
Answer:
(d) 0.15 N
Explanation:
mass of the fish, m₁ = 65 g = 0.065 kg
initial velocity of the fish, u₁ = 0
mass of water expelled by the fish, m₂ = 0.30 g = 0.0003 kg
time during which the water was expelled, t = 5.0 ms = 5.0 x 10⁻³ s
velocity of the water, v = 2.5 m/s
The magnitude of force of the exerted water is equal to the magnitude of force the fish exerted on the water.
The magnitude of force of the exerted water is calculated as follows;
[tex]F = ma = m\frac{v}{t} \\\\F = \frac{mv}{t} \\\\F = \frac{m_2 \ \times \ v}{t} \\\\F = \frac{0.0003 \ \times \ 2.5}{5 \times 10^{-3}} \\\\F = 0.15 \ N[/tex]
The correct option is D.
Therefore, the average force the fish exerts on the drop of water is 0.15 N.
is ice a fluid at room temperature?
Answer:
Ice is the solid state of water, a normally liquid substance that freezes to the solid state at temperatures of 0 °C (32 °F) or lower and expands to the gaseous state at temperatures of 100 °C (212 °F) or higher.
Explanation:
Suppose you take a whole apple pie (because pie is better than cake!!) How do the shape, taste, and the weight of the whole pie compare with the shape, taste, and weight of all the slices together?
Answer:
I ATE APPLE PIE YESTERDAY
Explanation:
What 2 environments once existed where the Grand Canyon is located today?
The entire park area is considered to be a semi-arid desert, but distinct habitats are located at different elevations along the 8,000-foot elevation gradient. Near the Colorado River, riparian vegetation and sandy beaches prevail.
Can anyone help please
Answer:
Option C, the current is constant through the wire.
Explanation:
Ok, so we know that as larger cross-section we have, smaller resistance, so makes sense to think that the current will be larger in the first piece of wire.
But now let's think in a simpler case.
Suppose that in the image we see pipes, and through these pipes, there is water flowing.
You would say that the water flow in WX is larger than the current in XY?
No, it can´t be, the volume of water that leaves WX in a lapse of time Δt, must be the exact same volume of water that enters XY in that lapse of time, then the water flow is constant.
The only thing that can happen is that the velocity at which the water moves in WX is smaller than the velocity at which the water moves in the other parts.
The same thing happens here, the current will be constant, and the thing that changes is the velocity at which the electrons flow in each part of the wire.
So if you actually had a wire like this, you would see that the thinner parts heat a lot more than the others, and this happens because the electrons in those parts have a lot more kinetic energy.
The correct graph is C.
o reduce the drag coefficient and thus to improve the fuel efficiency, the frontal area of a car is to be reduced. Determine the amount of fuel and money saved per year as a result of reducing the frontal area from 18 to 14 ft2. Assume the car is driven 12,000 mi a year at an average speed of 55 mi/h. Take the density and price of gasoline to be 50 lbm/ft3 and $3.10/gal, respectively; the density of air to be 0.075 lbm/ft3, the heating value of gasoline to be 20,000 Btu/lbm; and the overall efficiency of the engine to be 30 percent. Take the drag coefficient as CD
Complete question
To reduce the drag coefficient and thus to improve the fuel efficiency, the frontal area of a car is to be reduced. Determine the amount of fuel and money saved per year as a result of reducing the frontal area from 18 to 14 ft2. Assume the car is driven 12,000 mi a year at an average speed of 55 mi/h. Take the density and price of gasoline to be 50 lbm/ft3 and $3.10/gal, respectively; the density of air to be 0.075 lbm/ft3, the heating value of gasoline to be 20,000 Btu/lbm; and the overall efficiency of the engine to be 30 percent. Take the drag coefficient as CD=0.3 for a passenger car.
Answer:
22.22%
$57
Explanation:
From the question we are told that
Initial area of frontal area [tex]a_1=18ft^2[/tex]
Final area of frontal area [tex]a_2=14ft^2[/tex]
Distance covered a year [tex]D=12000mile[/tex]
Average speed a year [tex]V_{avg}=55mile/h[/tex]
Density [tex]\rho=50 lbm/ft3[/tex]
Price [tex]P= $3.10/gal[/tex]
Density of air [tex]\rho_{air} 0.075 lbm/ft3[/tex]
Heating value of gasoline [tex]Q=20,000 Btu/lbm[/tex]
Efficiency [tex]\eta=30\%[/tex]
Drag coefficient [tex]CD=0.3[/tex]
[tex]\triangle A=18-14ft^2=4ft^2[/tex]
Generally the equation for drag force [tex]C_D[/tex] is mathematically given as
[tex]F_D=\frac{C_DAPV^2}{2}[/tex]
[tex]F_D=\frac{0.3*18*0.075*(80.685^2)*A}{2}[/tex]
[tex]F_D=73.24Alb[/tex]
where [tex]v=55mil/h*1.467=80.685ft/s[/tex]
Generally the equation for work done W is mathematically given as[tex]W=F_D*L[/tex]
where [tex]L=12000mile*5280[/tex]
[tex]L=63360000[/tex]
[tex]W=73.24A*63360000[/tex]
[tex]W=4.6*10^9A[/tex]
Generally the equation for overall efficiency [tex]\eta[/tex] is mathematically given as
where
[tex]W_{req}=required\ gasoline\ power\ efficiency[/tex]
[tex]\eta=\frac{W}{W_{req}}[/tex]
[tex]W_{req}=\frac{W}{\eta}[/tex]
[tex]W_{req}=\frac{4.6*10^9}{0.3}[/tex]
[tex]W_{req}=1.55*10^{10}A[/tex]
Generally the equation for reduction fee with change in frontal area [tex]\triangle M[/tex] is mathematically given as
[tex]\triangle M =\triangle Vgasoline*cost[/tex]
Where
[tex]\triangle Vgasoline= volume\ reduction\ of\ gasoline[/tex]
[tex]\triangle Vgasoline=\frac{E_{req}}{H*P}[/tex]
[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]
if
[tex]20000btu/ibm=20000*778.169*32.2(1bm.ft^2/s)[/tex]
[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]
[tex]\triangle Vgasoline=0.61859A[/tex]
Therefore
[tex]\triangle M =0.61859A*3.10[/tex]
if [tex]1ft^2=7.48gal[/tex]
[tex]\triangle M =0.61859(4)*3.10*7.48[/tex]
[tex]\triangle M = \$ 57.671[/tex]
Generally the equation for reduction of fuel [tex]F_r[/tex]is mathematically given as
[tex]F_r=\frac{\triangle A}{\triangle i}*100[/tex]
where
[tex]\triangle i=18ft^2[/tex]
[tex]F_r=\frac{4}{18}*100[/tex]
Fuel reduction price by reducing front area is 22.22%
Money saved per year is $57
what is energy and types of energy
You have probably noticed that carrying a person in a pool of water is much easier than carrying a person through air. To understand why, find the buoyant force exerted by air and by water on the person. Assume the average volume of a person is 0.092 m3, and that the person is submerged in air and water respectively. (Give the magnitude.)
air: ________
water :_______
Answer:
The answer is "0.91238 and 744.8"
Explanation:
In this scenario it is easier to take a person to the water-pool than to transport the people in the air, as the person's strength is increased by water upwards:
[tex]f_b \to m \to mg =person \\\\F_B \ in\ air = v\ & air\ g \\\\[/tex]
[tex]=0.076 \times 1.225 \times 9.8 \\\\ =0.91238 \ N\\\\[/tex]
[tex]F_B \ in \ water = v \& water \ g \\\\[/tex]
[tex]=0.076 \times 1000 \times 9.8\\\\= 744.8 \ N\\[/tex]
A helicopter carrying Dr. Evil takes off with a constant upward acceleration of 7.0 m/s2m/s2. Secret agent Austin Powers jumps on just as the helicopter lifts off the ground. After the two men struggle for 11.0 ss, Powers shuts off the engine and steps out of the helicopter. Assume that the helicopter is in free fall after its engine is shut off, and ignore the effects of air resistance. Part A What is the maximum height above ground reached by the helicopter
Answer:
[tex]H_t= 725.8[/tex]
Explanation:
From the question we are told that:
Acceleration of Dr Evil [tex]a=7.0m/s^2[/tex]
Struggle time [tex]t=11s[/tex]
Generally the Newton's equation for Height traveled is mathematically given by
[tex]s = ut +\frac{1}{2} at2[/tex]
[tex]s = 7*121/2[/tex]
[tex]s= 423.25[/tex]
Generally the Newton's equation for Velocity at given time is mathematically given by
[tex]v= u+at \\ v= 0+7*11[/tex]
[tex]v= 77 m/s[/tex]
Generally the Newton's equation for Total Height [tex]H_t[/tex] is mathematically given by
[tex]v^2= u2+2as\\ v^2=772+2x(-9.8)s \\ s = 5929/19.6[/tex]
[tex]s=302.5m[/tex]
Therefore the total height is given as
[tex]H_t=423.3+302.5[/tex]
[tex]H_t= 725.8[/tex]
Is it acceleration speed or velocity
Answer:
1st speed 2.velocity 3.speed4.velocity5.velocity6.speed
528 nm light passes through a single slit. the second (m=2) diffraction minimum occurs at an angle of 3.48 degrees. what is the width of the slit
Answer:
1.74
Explanation:
right on acellus
Answer:
1.74
Explanation:
acellus
After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. The rockets explode high in the air and the sound travels out uniformly in all directions. If the sound intensity is 1.67 10-6 W/m2 at a distance of 233 m from the explosion, at what distance from the explosion is the sound intensity half this value
Answer:
the distance is 315.3696 m
Explanation:
The computation of the distance is given below:
Given that
Sound intensity = 1.67 × 10^-6 W/m^2
And, the distance = 233 m
Now as we know that
Power = Intensity × surface area
1.67 × 10^-6 × 4π(233)^2 = 1.67 × 10^-6 ÷ 2× 4π × d^2
d^2 = 2 × (223)^2
= √2 × 223
= 315.3696 m
Hence, the distance is 315.3696 m
PLEASE HELPPPPPP <333
Answer:
Explanation:
The answer is C i think
If a gas turned into a solid without going through the liquid state and how do you reverse it?
Answer:
put it in a volcano
Explanation:
A 5- kg object experiences forces as shown in the diagram. Which statement best describes the motion of the object
Answer: D. The object would have an acceleration of 6 m/s/s to the right.
Explanation:
I got it right on USA test prep
PLEASE HELP ME IN THE QUESTION !!
a. 75 kg, The mass of an object is the amount of matter that constitutes that object and is independent of the acceleration of gravity and is constant under any circumstances.
_________________________________
b. Weight = mass × gravity acceleration
♡ On the Earth : Weight = 75 × 10
Weight = 750 N
♡ On the Venus : Weight = 75 × 8.87
Weight = 665.25 N
You are designing a solenoid to produce a 2.0-kG magnetic field. You wish to wrap your insulated wire uniformly around a cardboard tube that is 8.0 cm in diameter and 58 cm in length, and you have a power supply that will allow you to pass a current of 2.5 A through the solenoid. Determine the total length of wire you will need in order to build the solenoid you have designed.
Answer:
92.7 km
Explanation:
Since the magnetic field due to a solenoid is given by B = μ₀Ni/L where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, N = number of turns of solenoid, L = length of cardboard tube = 58 cm = 0.58 m, , i = current in wire = 2.5 A and l = length of wire.
So, N = BL/μ₀i
Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T
So, substituting the variables into the equation, we have
N = BL/μ₀i
N = 0.2 T × 0.58 m/(4π × 10⁻⁷ H/m × 2.5 A)
N = 1.16 Tm/(31.416 × 10⁻⁷ HA/m)
N = 0.0369 × 10⁷ turns
N = 0.0369 × 10⁷ turns
N = 3.69 × 10⁵ turns
length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m
So, l = NC
= NπD
= πND
= π × 3.69 × 10⁵ turns × 0.08 m
= 0.9274 × 10⁵ m = 9.274 × 10⁴ m
= 92.74 × 10³ m
= 92.74 km
≅ 92.7 km
The total legnth of the wire to built a solenoid will be 92.7 km
What is solenoid?A solenoid is a electromagnet in which the wires are wounded on the outer surface of the soft iron and then the current is passed so due to flow of the current the magnetic field generated around the wire.
Since the magnetic field due to a solenoid is given by
B = μ₀Ni/L
where
μ₀ = permeability of free space = 4π × 10⁻⁷ H/m,
N = number of turns of solenoid,
L = length of cardboard tube = 58 cm = 0.58 m, ,
i = current in wire = 2.5 A and
l = length of wire.
Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T
So, substituting the variables into the equation, we have
[tex]N=\dfrac{BL}{\mu_oI}[/tex]
[tex]N=\dfrac{0.2\times 0.58}{4\pi\times 10^{-7} \times 2.5}[/tex]
[tex]N=\dfrac{1.16}{31.416\times 10^{-7}}[/tex]
N = 0.0369 × 10⁷ turns
N = 0.0369 × 10⁷ turns
N = 3.69 × 10⁵ turns
length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m
So, l = NC
= NπD
= πND
= π × 3.69 × 10⁵ turns × 0.08 m
= 0.9274 × 10⁵ m = 9.274 × 10⁴ m
= 92.74 × 10³ m
= 92.74 km
≅ 92.7 km
Hence the total legnth of the wire to built a solenoid will be 92.7 km
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