Therefore, the equation of the line that passes through the points (-3, 6) and (-5, 9) in slope-intercept form is:
y = -3/2 x + 3/2
Step-by-step explanation:
To find the equation of the line that passes through the points (-3, 6) and (-5, 9) in slope-intercept form (y = mx + b), we need to first find the slope of the line using the formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) = (-3, 6) and (x2, y2) = (-5, 9).
m = (9 - 6) / (-5 - (-3))
m = 3 / (-2)
m = -3/2
Now that we have the slope, we can use either of the two given points and the slope to find the y-intercept (b) of the line:
y = mx + b
6 = (-3/2)(-3) + b
6 = 9/2 + b
b = 6 - 9/2
b = 3/2
1. Mrs. Zimmerman is interested in learning about how much time seventh grade students at our school spend outdoors on a typical school day.
Select all the samples that are a part of the population. Justify your reasoning.
. The 20 students in a seventh grade math class.
B. The first 20 students to arrive at school on a particular day.
C. The seventh grade students participating in a science fair put on by the four middle schools in a school district.
D. The 10 seventh graders on the school soccer team.
E. The students on the school debate team.
A, c, D
Step-by-step explanation:
A) we can sample these 7th graders as we are looking to study 7th graders.
b) The first 20 students could be from any grade and so this option wouldn't work.
c) Involves 7th graders.
d) involves 7th graders
E) The students could be any grade level on the debate team so, this option wouldn't work.
PLS HELP ME WITH THIS 2. QUESTIONS, 50 POINTS
( The first 2 images are from the first question, the other one is from the second)
Answer: B g(x)=1/4f(x) odd
Step-by-step explanation:
First Page:
Points from the graph
Points from f(x) points from g(x)
(1,2) (1, 1/2)
(4, 16) (4, 4)
f(x) was multiplied by 1/4 to get to g(x)
Second Page:
Even functions are symmetrical about the y-axis: . Odd functions are symmetrical about the x- and y-axis: f(x)=-f(-x).
lets test for even: does f(x)=f(-x) => f(1)=f(-1) no -2[tex]\neq[/tex]2
see image for plotted points
lets test for odd: does f(x)= -f(-x) => f(1) = -f(-1) yes -2 = -2
Answer:
[tex]\textsf{B)} \quad g(x)=\dfrac{1}{4}f(x)[/tex]
[tex]\textsf{B)} \quad \textsf{odd}[/tex]
Step-by-step explanation:
Functions f(x) and g(x) are exponential functions.
From inspection of the given points on both graphs:
f(4) = 16g(4) = 4When x = 4, the y-value of function f(x) is four times the y-value of function g(x). Therefore, function g(x) is ¹/₄ of function f(x):
[tex]g(x)=\dfrac{1}{4}f(x)[/tex]
[tex]\hrulefill[/tex]
And even function is symmetric about the y-axis:
f(x) = f(-x) for all values of x.According to the table, f(3) = -4 and f(-3) = 4.
Therefore, as f(x) ≠ f(-x), the function is not even.
An odd function is symmetric about the origin:
f(-x) = -f(x) for all values of x.According to the table, f(-3) = 4 and f(3) = -4. So -f(3) = -(-4) = 4.
Therefore, as f(-3) = -f(3), the function is odd.
[tex]\hrulefill[/tex]
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Algebra 1. please help!!
Answer: f(t) = 2.4t - 500
Step-by-step explanation:
So first of all, we need how much she actually profits from each taco. She charges $3.25 per taco, but we cannot forget that it is not free to make a taco in the first place. It costs her $0.85 to make a taco. This means we have to subtract the 85 cents from the 3 dollars 25 cents, which means it ends up being $2.40, or as the answer choices have it, 2.4.
So now we know what the number of tacos is being multiplied by: 2.4.
2.4t is now the profit per taco multiplied by the number of tacos.
But we're not quite done yet.
She has a fixed expense of $500 a month, which means this has to be subtracted from her taco profits to find her true profit.
Putting all of this together, we get f(t)=2.4t - 500.
(t)= (profit per taco)(amount of tacos sold) - (fixed expenses)
the line is parallel to the graph of y=-1/2x-1 and contains the point (-4, 5)
The equation of the line parallel to the graph of y = (-1/2)x - 1 and containing the point (-4, 5) is y = (-1/2)x + 3.
What is the equation of the parallel line?The formula for equation of line is expressed as;
y = mx + b
Where m is slope and b is y-intercept.
Given the equation of the graph
y = (-1/2)x - 1
The equation of a line parallel to the graph of y = (-1/2)x - 1 will have the same slope as the given line, which is -1/2.
Now. using the point-slope form, we can find the equation of the line that passes through the point (-4, 5) with slope -1/2:
y - y1 = m(x - x1)
y - 5 = (-1/2)(x - (-4))
y - 5 = (-1/2)x - 2
y = (-1/2)x + 3
Therefore, the equation of the parallel line is y = (-1/2)x + 3.
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The circle at each end of the court that surrounds the free throw line is the same size as the jump ball circle. (In other words, they have the same radius. ) What is the area of the rectangle (called the lane) whose length is 19 feet and whose width is the free throw line?
So the area of the rectangle (or lane) whose length is 19 feet and whose width is the free throw line, together with the two circles at each end of the court that surround the free throw line, is approximately 450.39 square feet.
What is the length of the rectangle and how many free throw line square feet?Since the circle at each end of the court that surrounds the free throw line is the same size as the jump ball circle, they both have the same radius. Let's call this radius "r".
The diameter of the circle is equal to the width of the lane, which is the same as the width of the free throw line. Therefore, the diameter of the circle is also 12 feet (the width of the free throw line is always 12 feet).
We know that the area of a circle is given by the formula A = πr^2, so the area of each circle is πr^2.
The rectangle (or lane) has a length of 19 feet and a width of 12 feet. Therefore, its area is simply the product of its length and width, which is:
A = 19 feet * 12 feet
A = 228 square feet
Since there are two circles, the total area of the circles is 2πr^2.
We know that the diameter of the circle is equal to the width of the lane, which is 12 feet. Therefore, the radius is half of the diameter, or:
r = 12 feet / 2
r = 6 feet
Now we can calculate the area of the circles:
A = 2πr^2
A = 2π(6 feet)^2
A = 72π square feet
Therefore, the total area of the rectangle and circles (or lane and circles) is:
A_total = A_rectangle + A_circles
A_total = 228 square feet + 72π square feet
A_total ≈ 450.39 square feet
So the area of the rectangle (or lane) whose length is 19 feet and whose width is the free throw line, together with the two circles at each end of the court that surround the free throw line, is approximately 450.39 square feet.
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are 4(5k – 3) and 14k – 8 equivalent
help please
Answer: No they are not
Step-by-step explanation:
Distribute the 4 from the left equation into the parenthesis.
you would get 20k - 12
that is not equivalent to 14k - 8
Inga is solving 2x2 + 12x – 3 = 0. Which steps could she use to solve the quadratic equation? Select three options. 2(x2 + 6x + 9) = 3 + 18 2(x2 + 6x) = –3 2(x2 + 6x) = 3 x + 3 = Plus or minus StartRoot StartFraction 21 Over 2 EndFraction EndRoot 2(x2 + 6x + 9) = –3 + 9
Answer:
Inga can use the following steps to solve the quadratic equation 2x^2 + 12x - 3 = 0:
Divide both sides by 2 to simplify the equation: x^2 + 6x - 3/2 = 0.Add 3/2 to both sides to eliminate the constant term on the left-hand side: x^2 + 6x = 3/2.Complete the square by adding (6/2)^2 = 9 to both sides: x^2 + 6x + 9 = 3/2 + 9.Factor the left-hand side as a perfect square: (x + 3)^2 = 27/2.Take the square root of both sides, remembering to include both the positive and negative square roots: x + 3 = ±√(27/2).Simplify the square root: √(27/2) = (√27/√2) = (3√3/√2).Subtract 3 from both sides: x = -3 ± (3√3/√2).Rationalize the denominator by multiplying the numerator and denominator of the second term by √2: x = -3 ± (3√6/2).Therefore, the steps that Inga could use to solve the quadratic equation are:
2(x^2 + 6x + 9) = -3 + 2(9) (Option 1)
2(x^2 + 6x) = 3 (Option 2)
x + 3 = ±√(27/2) (Option 3)
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Dilate the figure by the scale factor. Then enter
the new coordinates.
(-1. 4)
A
K = 3
SB
(3,2)
1962,-2)
A’ ([?], []).
B'(]], [])
C), D
Dilating the figure by a scale factor of 3, the new coordinates are:
A' (-3, 12)
B' (9, 6)
C' (5886, -6)
D (unknown)
To dilate a figure by a scale factor, we need to multiply the coordinates of each point by the scale factor. Given the scale factor K = 3, we can dilate the figure using the formula:
New x-coordinate = K * original x-coordinate
New y-coordinate = K * original y-coordinate
Let's apply this to the given coordinates:
(-1, 4)
New x-coordinate = 3 * (-1) = -3
New y-coordinate = 3 * 4 = 12
A' (-3, 12)
(3, 2)
New x-coordinate = 3 * 3 = 9
New y-coordinate = 3 * 2 = 6
B' (9, 6)
(1962, -2)
New x-coordinate = 3 * 1962 = 5886
New y-coordinate = 3 * (-2) = -6
C' (5886, -6)
Dilating the figure by a scale factor of 3, the new coordinates are:
A' (-3, 12)
B' (9, 6)
C' (5886, -6)
D (unknown)
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The sum of twice a nuber,n, and 14 is 30.
2x+14=30
2x =30-14
2x=16
x =8
Answer:
8
Step-by-step explanation:
Twice means 2 so twice a number,n, means 2 times n thus 2n
sum means add so, 2n + 14
"is" means equal so 2n + 14 = 30
Solve for n:
2n=16
N=8
Find the absolute maximum and absolute minimum values off on the given interval. f(x) = 3x^4 – 4x^3-12x^2 + 1, {-2, 3] absolute minimum value
absolute maximum value
The absolute maximum value of f(x) on the interval [-2,3] is 201 and occurs at x = -2, and the absolute minimum value of f(x) on the interval [-2,3] is -79 and occurs at x = 2.
To find the absolute maximum and absolute minimum values of f(x) on the interval [-2,3], we need to first find the critical points of the function and evaluate the function at these points as well as at the endpoints of the interval.
To find the critical points, we need to find where the derivative of the function equals zero or does not exist. Taking the derivative of f(x), we get:
f'(x) = 12x^3 - 12x^2 - 24x
Setting this equal to zero and factoring out 12x, we get:
12x(x^2 - x - 2) = 0
Using the quadratic formula to solve for x^2 - x - 2 = 0, we get:
x = -1, 0, 2
These are our critical points.
Now we evaluate f(x) at the critical points and the endpoints of the interval:
f(-2) = 201
f(-1) = 6
f(0) = 1
f(2) = -79
f(3) = 16
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Do you pay less at Payless? Mary Ann and Abigail were shopping for prom shoes and wondered
how the prices at Payless compared to the prices
at Famous Footwear. At each store, they randomly
selected 30 pairs of shoes and recorded the price of
each pair. The table shows summary statistics for
the two samples of shoes. 28
Store
Mean
SD
Famous Footwear
$45. 66
$16. 54
Payless
$21. 39 $7. 47
Do these data provide convincing evidence at the
0. 05 significance level that shoes cost less
, on
average, at Payless than at Famous Footwear?
a =
To test whether shoes cost less on average at Payless than at Famous Footwear, we can conduct a two-sample t-test for the difference in means.
The null hypothesis is that there is no difference in the mean prices between the two stores, and the alternative hypothesis is that the mean price at Payless is less than the mean price at Famous Footwear.
We can calculate the t-statistic using the formula:
t = [tex](x1 - x2 - 0) / sqrt(s1^2/n1 + s2^2/n2)[/tex]
where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.
Substituting the values given in the table, we get:
t =[tex](21.39 - 45.66 - 0) / sqrt((7.47^2/30) + (16.54^2/30))[/tex] = -10.78
The degrees of freedom for this test is (30-1) + (30-1) = 58.
Using a t-table or calculator, we find the p-value to be very small, much less than 0.05.
Therefore, we reject the null hypothesis and conclude that there is convincing evidence at the 0.05 significance level that shoes cost less on average at Payless than at Famous Footwear.
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Write an exponential function in the form y=ab^xy=ab x that goes through points (0, 13)(0,13) and (5, 416)(5,416)
The exponential function in the form y = [tex]ab^x[/tex] that goes through the points (0, 13) and (5, 416) is y = 13 * [tex]2^x[/tex].
To write an exponential function in the form y = [tex]ab^x[/tex] that goes through the points (0, 13) and (5, 416), follow these steps:
1. Use the point (0, 13) to determine the value of a. Since the x-coordinate is 0, we have y = a * b⁰, which simplifies to y = a. Therefore, a = 13.
2. Use the point (5, 416) to determine the value of b. Plug in the values for x and y, as well as the value of a we just found: 416 = 13 * b⁵.
3. Solve for b: b⁵ = 416 / 13 = 32. Taking the fifth root of both sides, we get b = 2.
So, the exponential function in the form y = [tex]ab^x[/tex] that goes through the points (0, 13) and (5, 416) is y = 13 * [tex]2^x[/tex].
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A triangular prism is 36 millimeters long and has a triangular face with a base of 36 millimeters and a height of 24 millimeters. The other two sides of the triangle are each 30 millimeters. What is the surface area of the triangular prism?
The surface area of the triangular prism is
5752 square millimetersHow to find the surface area of the triangular prismThe surface area of the triangular prism is
= area of the two side rectangles + area of the base rectangles + area of the 2 triangles
= 2 * 36 * 30 + 36 * 36 + 2 * 1/2 * 36 * 24
= 2160 + 1296 + 1296
= 5752 square millimeters
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HELPPPPP FAST PLEASEEEE
Answer:
AEC is similar to BDC in terms of the type of triangle
That's all I can really say
I hope this helps :)
A ramp at a dog park is made of three sections. The incline and decline pieces are the same length, 13√37 inches. The center is 10√41 inches long. What is the total length of the ramp? Give your answer as a radical expression.
The total length of the ramp is 222.18 inches
How to find the total length?Let's denote the length of the incline and decline pieces by x, and use the given information to form an equation in terms of x:
Length of incline + length of decline = 2(13√37) inches
= 26√37 inches
The total length of the ramp is the sum of the lengths of all three sections:
Total length = Length of incline + Length of center + Length of decline
Total length = 26√37 inches + 10√41 inches
Total length = 222.18 inches
Therefore, the total length of the ramp is 222.18 inches
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Find the inverse for each relation: 4 points each 1. {(1,‐2), (2, 3),(3, ‐3),(4, 2)}
When the mortgage is completely paid off for Mark and Lynne’s house, it will be 3 times as old as it is now. If they have 12 years left on the mortgage, how old is the house right now?
The house is currently 6 years old.
It is mentioned that when the mortgage is completely paid off for Mark and Lynne's house, it will be 3 times as old as it is now. They have 12 years left on the mortgage.
Let's denote the current age of the house as x. When the mortgage is paid off, the house will be x + 12 years old (since they have 12 years left on the mortgage). At that point, the house will be 3 times its current age, so we can write the equation:
x + 12 = 3x
Now we can solve for x:
12 = 2x
x = 6
So, the house is currently 6 years old.
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how many times can 2 go into 1742? please its for my homework due tomorrow
Ross Times, the student newspaper of Ross College, printed a "What do you think?" column feature asking: "Do you think that the college is doing enough to provide student parking?" Anyone could mail in a response or use the paper's Web site to respond. In all, 126 answers were received.
This is an example of:
(a) a voluntary response sample.
(b) a multistage sample.
(c) a simple random sample.
(d) a convenience sample.
(e) the placebo effect
The answer is (d) a convenience sample.
This is because the sample is not randomly selected from the population of all students at Ross College. Instead, it relies on individuals who are willing and available to respond to the question through the methods provided by the newspaper.
Therefore, the sample is more likely to be composed of individuals who feel strongly about the issue of student parking or who have had particularly positive or negative experiences with it, rather than being representative of the entire population of Ross College students.
In conclusion, the Ross Times student newspaper's feature column asking for opinions on the provision of student parking at Ross College represents a convenience sample of responses, and may not be representative of the entire population of Ross College students.
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Find the sum of all the integers between 100 and 400 that are multiples of 6.
Answer:
The sum of all numbers divisible by 6 between 100 and 400 is 12450.
Step-by-step explanation:
I think this is correct.
If it isn't, I'm sorry.
PLS HELP ASAP 50 POINTS AND BRAINLEIST!!!
Explain how the arc BX, central angle BCX, and inscribed BNX are connected. what are the relationships between them?
Answer:
[tex]\overset{\frown}{BX}=\angle BCX=2\angle BNX[/tex]
Step-by-step explanation:
A chord is a straight line joining two points on the circle.
Therefore, the chords in the given diagram are BN and XN.
An inscribed angle is the angle formed (vertex) when two chords meet at one point on a circle.
Therefore, the inscribed angle in the given diagram is BNX.
An intercepted arc is the arc that is between the endpoints of the chords that form the inscribed angle.
Therefore, the intercepted arc in the given diagram is BX.
The radius is a straight line joining the center to a point on the circle.
Therefore, the radii in the given diagram are CB and CX.
The central angle of a circle is the angle formed at its center by two radii.
Therefore, the central angle in the given diagram is BCX.
[tex]\hrulefill[/tex]
The measure of the central angle of a circle is equal to the measure of the corresponding intercepted arc. Therefore:
[tex]\angle BCX=\overset{\frown}{BX}[/tex]
According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc. Therefore:
[tex]\angle BNX=\dfrac{1}{2}\overset{\frown}{BX}[/tex]
So the relationship between the arc BX, the central angle BCX and the inscribed angle BNX is that both the arc and central angle are equal to twice the inscribed angle:
[tex]\overset{\frown}{BX}=\angle BCX=2\angle BNX[/tex]
The diagonals of quadrilateral ABCD intersect at E(0,2). ABCD has vertices at A(1,6) and B(-2,4). What must be the coordinates of C and D to ensure that ABCD is
a parallelogram?
Answer:
C = (-1, -2)
D = (2, 0)
Step-by-step explanation:
You want the coordinates of points C and D in parallelogram ABCD such that point E(0, 2) is the intersection of the diagonals. Given points are A(1, 6) and B(-2, 4).
ParallelogramThe diagonals of a parallelogram bisect each other. This means the point of intersection of the diagonals is the midpoint of each:
E = (A +C)/2 . . . . . . . . . . . . . . . E is the midpoint of AC
C = 2E -A = 2(0, 2) -(1, 6)
C = (-1, -2)
and
D = 2E -B = 2(0, 2) -(-2, 4) . . . . . using the same pattern
D = (2, 0)
Can someone please help me ASAP? It’s due tomorrow.
Answer: m*n
Step-by-step explanation:
Bilquis is trying to find the height of a radio antenna on the roof of a local building. She stands at a horizontal distance of 29 meters from the building. The angle of elevation from her eyes to the roof (point A) is 17°, and the angle of elevation from her eyes to the top of the antenna (point B) is 31º. If her eyes are 1. 51 meters from the ground, find the heigh[of the antenna (the distance from point A to point B). Round your answer to the nearest meter if necessary.
The height of the antenna is approximately 17 meters.
To solve for the height of the antenna, we need to use trigonometry. Let's call the height of the antenna "h".
First, we need to find the distance from point A to point B. We can use the angle of elevation from her eyes to the roof (17°) and the horizontal distance from the building (29m) to find the height of the building.
tan(17°) = height of building / 29m
height of building = 29m * tan(17°)
height of building = 8.20m
Now we can use the height of the building and the angle of elevation from her eyes to the top of the antenna (31°) to find the distance from point A to point B.
tan(31°) = h / 29m + 8.20m
h = (29m + 8.20m) * tan(31°)
h = 15.51m
Finally, we need to add the height of Bilquis' eyes to the height of the antenna to find the total height.
total height = h + 1.51m
total height = 17.02m
Therefore, the height of the antenna is approximately 17 meters.
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A company manufactures and sells x microwaves per month. The monthly price-demand equation is: p(x) = 280 – 0.4z (a) Assuming that the manufacture would like to charge between $100 and $500 for microwaves, find the price that maximizes the revenue. (b) What is the maximum revenue from selling microwaves?
The price that maximizes revenue for the given monthly price-demand equation with price range between $100 and $500 is $220.
(b) The maximum revenue from selling microwaves can be found by multiplying the price that maximizes revenue by the corresponding quantity of microwaves sold. Using the price-demand equation p(x) = 280 - 0.4x, we can find the quantity that corresponds to the price that maximizes revenue as follows:p(x) = 280 - 0.4x220 = 280 - 0.4x0.4x = 60x = 150Therefore, the quantity that corresponds to the price that maximizes revenue is x = 150. The maximum revenue can be found by multiplying the price and quantity:Revenue = Price * QuantityRevenue = $220 * 150Revenue = $33,000Therefore, the maximum revenue from selling microwaves is $33,000.
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A rectangular mural measures 1 meter by 3 meters. Rebekah creates a new mural that is 0. 5 meters longer. What is the perimeter of Rebekah's new mural?
The perimeter of Rebakh's new mural is 9 meters.
Rebakh has created a new mural which is a rectangle. It is a two-dimensional shape with length and breadth. The original rectangular mural was having dimensions of 1 meter by 3 meters, but the mural Rebekah created was 0.5 meters longer than the original one.
So, now the new mural created by Rebakh has a width of (3 + 0.5 ) = 3.5 meters and a length of 1 meter. The perimeter is defined as the total length of the four sides of the rectangle. To find the perimeter, we will add up the length and width of the rectangle and multiply it by 2. The perimeter of the new mural, in this case, is 1 + 1 + 3.5 + 3.5 = 9 meters.
Therefore, the perimeter of Rebakh's new mural is 9 meters.
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80.0% complete
question
a customer wants you to enlarge a photo to 234 its current height. the photo’s current height is 314 inches. what should its enlarged height be, in inches?
If the photo’s current height is 314 inches, the enlarged height should be approximately 547.6 inches (rounded to one decimal place), which is 80.0% larger than the current height.
To calculate the enlarged height, you need to find out the percentage increase in height from the current height to the desired height.
The desired height is 234 inches, which is 234/314 = 0.744 or 74.4% of the current height.
To find the actual enlarged height, you need to increase the current height by 74.4%.
Enlarged height = current height + (current height x percentage increase)
Enlarged height = 314 + (314 x 0.744)
Enlarged height = 314 + 233.616
Enlarged height = 547.616
Therefore, the enlarged height should be approximately 547.6 inches (rounded to one decimal place), which is 80.0% larger than the current height.
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Calculate the derivative of the following function, 4 y=sin(cos (8x)) ) Find the critical points of the following function f(x) = xVx+6"
The critical points of f(x) are x = -3 and x = 4.
Derivative of 4y = sin(cos(8x)):
We can find the derivative of the given function using the chain rule of differentiation. Let u = cos(8x), then we have:
y = sin(u)
dy/du = cos(u) (derivative of sin(u))
du/dx = -8sin(8x) (derivative of cos(8x) using chain rule)
dy/dx = dy/du * du/dx = cos(cos(8x)) * (-8sin(8x))
Therefore, the derivative of 4y = sin(cos(8x)) is:
dy/dx = -32sin(8x)cos(cos(8x))
Critical points of f(x) = x√(x+6):
To find the critical points of f(x), we need to find where the derivative of the function is equal to zero or undefined.
f(x) = x√(x+6)
f'(x) = (√(x+6) + x/2√(x+6))
To find the critical points, we need to set f'(x) equal to zero and solve for x:
(√(x+6) + x/2√(x+6)) = 0
Multiplying both sides by 2√(x+6), we get:
2x + 6 = -x√(x+6)
Squaring both sides, we get:
4[tex]x^2[/tex] + 24x + 36 = [tex]x^3[/tex] + 6[tex]x^2[/tex]
Rearranging, we get:
[tex]x^3[/tex] + [tex]2x^2[/tex] - 24x - 36 = 0
We can solve this cubic equation using numerical methods or by factoring.
By testing values, we can see that x = -3 is a root of the equation. Dividing the equation by (x+3), we get:
[tex]x^2[/tex]- x - 12 = 0
This quadratic equation can be factored as (x-4)(x+3) = 0.
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In which of the following situations does order matter? Select all that apply
Answer:
Locker and Phone number
Step-by-step explanation:
Gym student grouped together with no thought doesnt matter, lunch menu doesn't need order, and a classroom seating chart doesn't really matter
A 6 in.
D
X
F 6 in. G
The calculated value of x in the right triangle is 6
Calculating the value of xfrom the question, we have the following parameters that can be used in our computation:
The right triangle
Where we have
x/6 = 6/x
To solve this equation, we can use the property of cross-multiplication.
So for the equation x/6 = 6/x, we can cross-multiply as follows:
x/6 = 6/x
x * x = 6 * 6
x^2 = 36
To solve for x, we need to take the square root of both sides of the equation:
√(x^2) = √36
x = 6
The value of x is 6
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