Identify the angles (congruent vs supplementary

Step-by-step explanation:

We need to find the area of the shaded region. We see that the region next to that has a central angle of 120°. Also we know that angle in a straight line is 180° . So the measure of central angle of that shaded region will be 180° - 120° = 60° . Now we can use the formula of area of sector to find out the area of the shaded region.

[tex]\tt\to Area = \dfrac{\Theta}{360^o}\times \pi r^2 \\\\\tt\to Area = \dfrac{60^o}{360^o}\times \pi (8cm)^2 \\\\\tt\to Area =\dfrac{\pi \times 64}{6}cm^2\\\\\to\boxed{\orange{\tt Area_{(Shaded)}= 10.66\pi cm^2}}[/tex]

Answer:

13 pears in the 21st bag

Step-by-step explanation:

mean = total number of pears/total number of bags

8 = x/21

x = 168

number of pears in 20 bags = (6 x 2) + (7 x 6) + (8 x 9) + (9 x 1) + (10 x 2)

= 155

number of pears in the 21st bag = 168 - 155

= 13

Answer:

Top left

Step-by-step explanation:

It’s the only one with a data point very far from the rest

Answer:

its diff for all of is but it deff right

Step-by-step explanation:

k12 right

Answer:

113 degrees

its really hard to explain it on this app

Step-by-step explanation:

[tex]x = 10 \\ \\ y = 10 \sqrt{2} \\ \\ \cos(45) = \frac{ \sqrt{2} }{2} [/tex]

Answer:

third one down

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Open ended circle because there is not a line under the > and n > 3 means n is greater than 3.

Answer:

180 seconds

Step-by-step explanation:

1 minute = 60 seconds

120 * 3 = 360

60 * 3 = 180

Answer:

60.5

Step-by-step explanation:

assuming that each small squares is 1 × 1

[tex]\frac{1}{2} \times base \times height\\\\\frac{1}{2} \times 11 \times 11\\ \\\frac{121}{2}\\\\60.5 unit ^2[/tex]

Answer:

0.0475

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

In a large company, the proportion of employees who were promoted during the last year was 0.10.

This means that [tex]p = 0.1[/tex]

100 employees

This means that [tex]n = 100[/tex]

Mean and standard deviation:

[tex]\mu = E(X) = np = 100*0.1 = 10[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.1*0.9} = 3[/tex]

What is the probability that at least 15 of them were promoted during the last year?

This is [tex]P(X \geq 15)[/tex], which is 1 subtracted by the pvalue of Z when X = 15. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{15 - 10}{3}[/tex]

[tex]Z = 1.67[/tex]

[tex]Z = 1.67[/tex] has a pvalue of 0.9525

1 - 0.9525 = 0.0475.

0.0475 is the answer.

Answer:

A

Step-by-step explanation:

Given

P(t) = 60 [tex](3)^{\frac{t}{2} }[/tex]

Then

P(1) = 60 × [tex]3^{\frac{1}{2} }[/tex] = 60[tex]\sqrt{3}[/tex]

P(2) = 60 × 3 = 180

P(3) = 60 × [tex]3^{\frac{3}{2} }[/tex] = 60 ×[tex]\sqrt{3^{3} }[/tex] = 60 × 3[tex]\sqrt{3}[/tex] = 180[tex]\sqrt{3}[/tex]

P(4) = 60 × 3² = 60 × 9 = 540

P(5) = 60 × [tex]3^{\frac{5}{2} }[/tex] = 60 × [tex]\sqrt{3^{5} }[/tex] = 60 × 9[tex]\sqrt{3}[/tex] = 540[tex]\sqrt{3}[/tex]

P(6) = 60 × 3³ = 60 × 27 = 1620

From these 6 results we see that

P(3) = 3 × P(1)

P(4) = 3 × P(2)

P(5) = 3 × P(3)

P(6) = 3 × P(4)

The predicted number of organisms triples every 2 days → A

Hi, check the comment.  It is the answer.  I wrote my own comment and rated myself 1.0 for no reason lol!! (Oh mah gawd I was joking this is not the answer, do NOT take this as your answer!