If the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation. It is not a carboxylic acid if it does not react with sodium carbonate. A substance is not an alkene or a carboxylic acid if it does not decolorize bromine water and is not acidic.
What is the flowchart for identification of an alkene and carboxylic acid?The following flowchart can be used to recognize an alkene and a carboxylic acid:
1. Start with the hypothetical unknown substance.
2. Use bromine water to test the substance.
a. An alkene is a substance that discolors bromine water.
b. Move on to the following stage if the compound does not lighten bromine water.
3. Use universal indicator paper or litmus paper to test the chemical.
a. The substance might be a carboxylic acid if it is acidic and causes the paper to turn red.
b. Go to the following step if the chemical is not acidic.
4. Use sodium carbonate to evaluate the substance.
a. A substance is a carboxylic acid if it reacts with sodium carbonate to release carbon dioxide gas.
b. The chemical is not a compound if it does not react with sodium carbonate.
Therefore, if the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation.
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Your question is incomplete, most probably the complete question is:
TASK 2 - Pass 2B.P4 Identify an alkene and carboxylic acid using primary observations. To achieve 2B.P4, learners should follow guidance to identify an alkene and a carboxylic acid (for example, ethanoic acid) from primary observations. Learners will be expected to identify an alkene in the way described in 1B.4. For ethanoic acid this is by its pH and its reaction with sodium carbonate. The guidance given to the learners could be in the form of a flowchart.
How many grams of magnesium
sulfate (MgSO4) are dissolved in
0.965 L of a 0.0575 M solution?
Molar Mass Mg: 24.30 g/mol
Molar Mass S: 32.06 g/mol
Molar Mass O: 16.00 g/mol
Answer:6.68
Explanation:
Which contains more reducing sugars, apple or cheese?
Answer:
An apple.
Explanation:
Hope this helps.
A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.926 g H2O are produced. In a separate experiment, the molar mass is found to be 104.1 g/mol. Determine the empirical formula and the molecular formula of the organic compound. Enter the elements in the order C, H, O empirical formula
Answer: The empirical formula and the molecular formula of the organic compound is [tex]CHO[/tex] and [tex]C_4H_4O_4[/tex] respectively.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of [tex]CO_2[/tex] = 21.71 g
Mass of [tex]H_2O[/tex]= 5.926 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 21.71 g of carbon dioxide, =[tex]\frac{12}{44}\times 21.71=5.921g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 5.926 g of water, =[tex]\frac{2}{18}\times 5.926=0.658g[/tex] of hydrogen will be contained.
Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53 g
Mass of C = 5.921 g
Mass of H = 0.658 g
Mass of O = 10.53 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles[/tex]
Mass of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.493}{0.493}=1[/tex]
For H =[tex]\frac{0.658}{0.493}=1[/tex]
For O=[tex]\frac{0.658}{0.493}=1[/tex]
The ratio of C : H: O = 1: 1: 1
Hence the empirical formula is [tex]CHO[/tex].
empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29
Molecular mass = 104.1 g/mol
[tex]n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4[/tex]
Thus molecular formula = [tex]n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4[/tex]
Which of the following describes the role of water in supporting the chemical reactions that occur within various life forms?
It is a non-polar molecule with weak hydrogen boding.
It is critical in the process of cellular respiration.
It has a huge electronegativity difference between its atoms.
It allows sunlight to pass through it.
Answer:
It's critical in the process of cellular respiration
It is critical in the process of cellular respiration; is the correct answer; as water plays a very important role in transportation of oxygen and maintaining cell structure.
What is cellular Respiration ?The process by which organisms combine food molecules with oxygen to form energy , which is used for life sustaining activities is called Cellular Respiration.
Carbon Di-Oxide and Water are produced as by products.
Water acts as a solvent in facilitating the transport of oxygen in respiration.
At the molecular level, water permits everything inside the cell to have the proper structure which is very important for biological processes.
Hence option B , i.e. It is critical in the process of cellular respiration; is the correct answer.
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The map shows the movement pattern for major ocean currents. What ideas do you have about what might make ocean
currents move?
Please help
Answer:
Currents are physical occurrences or factors that put motion into oceans, making them move back and forth.
Such factors include but may exceed the following:
WindVariation in water mass densities (this is caused by alterations in temperature and salinity levels)GravityEarthquakes or stormsWhen there is movement in ocean currents, heat, nutrients, water oxygen levels are also affected.
Cheers
How many moles of iron will be produced from 6.20 moles of carbon monoxide reacting with excess iron oxide
Explanation:
..........................m
Based on the picture of the map, why does Buenos Aries have a higher ocean surface temperature than Cape Town even though they have the same latitude?
with a well labeled diagram explain the stages of meiosis and mitosis
Answer:
hope that helps
What is the Electron Center Geometry of a CH3 carbon.
Answer:
tetrahedral geometry
CHCH2O- CH2CH3Explanation:
There are several centers of interest. Each carbon with all single bonds is the center of a tetrahedral geometry.
How many moles of Mg(OH)2(aq) would be required to neutralize 6.0 mol HCl(aq)?
Answer:
[tex]3.0molMg(OH)_2[/tex]
Explanation:
Hello there!
In this case, for these types of acid-base neutralizations, it is crucial to firstly set up the chemical reaction taking place between the acid and the base; in this case HCl and Mg(OH)2 respectively, whose products are obtained by switching around the anions and cations as shown below:
[tex]HCl(aq)+Mg(OH)_2(aq)\rightarrow MgCl_2(aq)+H_2O(l)[/tex]
Which must be balanced to accurately predict the mole ratio on the reactants side:
[tex]2HCl(aq)+Mg(OH)_2(aq)\rightarrow MgCl_2(aq)+2H_2O(l)[/tex]
Whereas we can see a 2:1 mole ratio of the acid to the base; thus, the moles of Mg(OH) required for the neutralization of 6.0 moles of HCl turn out to be:
[tex]6.0molHCl*\frac{1molMg(OH)_2}{2molHCl} \\\\=3.0molMg(OH)_2[/tex]
Best regards!
Consider this statement: Earth is the only source of gravity in the solar system. Do you agree? Give
your reasons.
Answer:
Explanation:
You're kidding, right?
Earth is a puny little planet stuck in the Milky Way which is not a particularly large galaxy that has millions of stars with many times more our gravitational influence.
We are very lucky that the gravitational force is so weak. Were it not, We would be pulled in every direction imaginable and swallowed many times by larger and larger black holes until our existence could never be traced.
We would be like 1 electron in all the atoms of the Universe combined. There's no end to the size and scope of the forces involved if the gravitational force were even a small bit larger than what it is now.
4. How many moles of NaOH(s) would be required to react with 1.90 g of Cu(NO3)2 (aq)
according to the balanced equation:
Cu(NO3)2(aq) + 2 NaOH(aq) → Cu(OH)2(s) + 2 NaNO3(aq)
Answer:
2.03 x 10⁻² mol NaOH
Explanation:
First step for these questions is to ensure the reaction is balanced, then use the periodic table to determine the molar mass for the reactant you are given. Use the ratio from the balanced equation and dimensional analysis to solve. See attached image
HELP ME PLEASE ITS DUE TODAY
Answer:
Explanation:
S2Si
O2
C2H4
N2
CBr4
S2
I think these are correct
As NH4Cl dissolves in water, and cools the solution,
a. delta H is negative, and delta S is negative
b. delta H is positive, and delta S is negative
c. delta H is negative, and delta S is positive
d. delta H is positive, and delta S is positive
Answer:
D. delta H is positive, and delta S is positive
Methane (CH4) undergoes combustion. Which products form? please help will give brainliest if correct
Answer:
B. CO₂ and H₂O.
Explanation:
When any organic substance undergoes complete combustion, it produces carbon dioxide (CO₂) and water (H₂O).
In the case of methane, the balanced reaction is:
CH₄ + 2O₂ → CO₂ + 2H₂OWith the above information in mind the correct answer is option B. CO₂ and H₂O.
When the combustion is incomplete, carbon monoxide (CO) is produced as well.
Answer:
B. CO₂ and H₂O!
The Moon shines white light on Earth. Is the Moon a good blackbody
radiator? Why?
O A. Yes, because the light from the Moon comes from the Sun, which
is a blackbody radiator
B. No, because white light is only one wavelength of light, not a range
of wavelengths
O C. No, because the Moon reflects most of the Sun's light rather than
absorbing it
O D. Yes, because each night the Moon warms up enough to emit
visible light at a range of wavelengths
Answer:
C.) No, because the Moon reflects most of the Sun's light rather than
absorbing it
Explanation:
:p
Which of the following is not among the elements to include on your note cards?
I. a number to identify the card and link it to a bibliography card
II. the subject (if you know what it is)
III. publishing information about the work in question
IV. your notes
A. II
B. I
C. IV
D. III
Answer:
c
Explanation:
Answer:
The answer is C
Explanation:
hellooooooooooooooooooooo
Answer:
hiiiiiiiiiiiiiiiiiiiiiiiii THANK YOU SO MUCH FOR THE POINT
Q) Briefly describe how body systems work all together
Answer:
Your bones and muscles work together to support and move your body. Your respiratory system takes in oxygen from the air. ... Your circulatory system carries oxygen, water, and nutrients to cells throughout your body. Wastes from the cells are eliminated by your respiratory system, your excretory system, and your skin.
Explanation:
Lenses are made to have different focal points. What two properties of a lens
affect the focal length?
A. Where the object is located
O B. Whether the image is virtual or real
O C. The material the lens is made from
O D. The centers of curvature of the two sides of the lens
Consider the balanced chemical equation
4B(s) + 302 (g)► 2B203(s)
What mole ratio would you use to calculate how many moles of oxygen gas would be needed to react completely with a given number of moles of boron?
A. 3 mol O2
/ 4 mol B
B. 4 mol O2/
3 mol B
C. 3 mol O2/
2 mol B
D.
2 mol O2
/ 3 mol B
Answer:
A
Explanation:
The coefficents are used when determining mole ratio. So just look in front of O and B
the ratio is 3/4
you cna use this in stoich as well
Choose the appropriate electron configuration for an element that has electrons in six orbitals.
Group of answer choices
1s2 2s2 2p6 3s2 3p6
1s2 2s2 2p6 3s2 3p4
1s2 2s2 2p6 3s1
1s2 2s2 2p5
Answer:
pagtoon og imo dotsExplanation:
pagtoon og imo dotsIn solution, strong acids and bases ionize completely, but weak acids and bases ionize only partially.
Answer:
A weak acid is one that does not dissociate completely in solution; this means that a weak acid does not donate all of its hydrogen ions (H+) in a solution. ... Therefore, the concentration of H+ ions in a weak acid solution is always less than the concentration of the undissociated species, HA.
Explanation:
Hope it helps
FOLLOW MY ACCOUNT PLS PLS
When 3.915 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.74 grams of CO2 and 3.913 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 54.09 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.
Answer: The empirical formula and the molecular formula of the hydrocarbon is [tex]C_2H_3[/tex] and [tex]C_4H_6[/tex] respectivley.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_y+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' are the subscripts of Carbon, hydrogen
We are given:
Mass of [tex]CO_2[/tex] = 12.74 g
Mass of [tex]H_2O[/tex]= 3.913 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 12.74 g of carbon dioxide, =[tex]\frac{12}{44}\times 12.74=3.474g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 3.913 g of water, =[tex]\frac{2}{18}\times 3.913=0.435g[/tex] of hydrogen will be contained.
Mass of C = 3.474 g
Mass of H = 0.435 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.474g}{12g/mole}=0.289moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.435g}{1g/mole}=0.435moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.289}{0.289}=1[/tex]
For H =[tex]\frac{0.435}{0.289}=1.5[/tex]
The ratio of C : H = 1: 1.5
The whole number ratio will be = 2: 3
Hence the empirical formula is [tex]C_2H_3[/tex].
The empirical weight of [tex]C_2H_3[/tex] = 2(12.01)+3(1.008)= 27.04 g.
The molecular weight = 54.09 g/mole
Now we have to calculate the molecular formula.
[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{54.09}{27.04}=2[/tex]
The molecular formula will be=[tex]2\times C_2H_3=C_4H_6[/tex]
Can you list some examples for each of the three domains of bacteria, archaea, and eukarya?
Answer: bacteria: e Coli
Explanation:
The bacteria and archaea are microorganisms. Escheria coli, staphylococcus aureus etc are examples of bacteria. Different types of archaea includes bathyarchaeota, thermoproteota etc. Eukaryotes are multicellular organisms such as plants, fungi, animals etc.
What are eukaryotes?Eukaryotes are multicellular organisms with developed cellular organization and developed nucleus. All the higher level organisms such as humans, animals, fungi, plants etc are eukaryotes.
Microorganisms such bacteria are single celled organisms and they are called unicellular having only one cell without a developed nucleus.There are many types of bacteria based on their structure and functions such as spirulina, staphylococcus, vibrio coli etc.
Archaea is another type of unicellular organism which first classified as type of bacteria, but later they are included in a new class of domain. They are natural methanogens that is they produce methane gas. Some examples are bathyarchaeota, thermoproteota etc.
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What is the kinetic energy of a bicycle with a mass of 11 kg traveling 8 m/s?
What is the kinetic energy of a bicycle with a mass of 11 kg traveling 8 m/s ?
Answer:-Mass (m) of a bicycle is = 11 kg
Speed (v) of a bicycle is = 8 m/s
Kinetic energy (K.E) of a bicycle is = ?
Since, we know,
[tex] { \boxed{\rm \red {K.E \: = \frac{1}{2} mv²}}} [/tex][tex] \bf K.E \: = \frac{1}{2} \: × \: 11 \: kg \: × \: (8 \: m/s)² [/tex]
[tex] \bf K.E \: = \frac{1}{2} \: × \: 11 \: kg \: × \: 64 \: m²/s²[/tex]
[tex] \bf K.E \: = \frac{704}{2} \: kg \: m²/s² [/tex]
[tex] \bf K.E \: = \: 352 \: kg \: m²/s² [/tex]
The kinetic energy (K.E) of a bicycle is 352 kg m²/s². [Answer]Which statement describes the appearance of a
temperature-vs.-time graph?
A horizontal line shows that the temperature
increases at a constant rate over time.
O. A vertical line shows that the temperature
decreases at a constant rate over time.
Horizontal lines where the temperature is
constant during phase changes connect
upward-sloping lines where the temperature
increases.
Horizontal lines where the temperature
increases are connected by upward-sloping
lines where the temperature is constant for
each phase.
Answer: C. Horizontal lines where the temperature is constant during phase changes connect upward-sloping lines where the temperature increase.
Explanation:
Answer:
C
Explanation:
Famous people who talked about plastic water bottles
An alpha particle is an ionized helium nucleus, consisting of 2 protons and 2 neutrons bound together. When alpha particles are beamed toward a thin metal foil, most of them pass through, undergoing a small deflection, while a small fraction of them bounce back at much larger angles in excess of 90 degrees relative to their incoming direction. The reason this happens is that Group of answer choices
Answer:
Due presence of empty as well as heavy particles.
Explanation:
The main reason for this is the presence of empty spaces as well as heavy particles in the nucleus of Helium atom. Most of the beam pass through the helium atom due to the presence of empty spaces in the atom whereas some beams deflect from the helium atom because both repel each other due to same charge i.e. positive charge. Few beams of light bounce back with an angle of 90 degree due hitting with the nucleus where heavy particles such as neutron and proton are present.
What solid figure has two bases, but no lateral faces?
cylinder
rectangular prism
triangular prism
cone
Answer:
it is cylinder as it has two bases but no lateral faces.
