I will mark you brainlist!

If you could create an alterrnative source of energy that would save our plant what would it be?

Answers

Answer 1

Oh god someone sent something really bad, I only saw it for a few seconds. Honestly you should re post this question, jeez...

Answer 2
Geothermal Power. Because Geothermal energy is the thermal energy generated and stored in the Earth. Thermal energy is the energy that determines the temperature of matter. The geothermal energy of the Earth's crust originates from the original formation of the planet and from radioactive decay of materials (in currently uncertain) Hope this helped!

Related Questions

Helppp pls yes or no question

Answers

Answer:

yes, should be

Explanation:

This is a hard yes or no question becuase the amplitudes are the same height but in different beating orders.

Answer:

They appear to be about the same height, so the answer is true.

Explanation:

The Hydrogen Spectrum
When a low-pressure gas of hydrogen atoms is placed in a tube and a large voltage is applied to the end of the tube, the atoms will emit electromagnetic radiation and visible light can be observed. If this light passes through a diffraction grating, the resulting spectrum appears as a pattern of four isolated, sharp parallel lines, called spectral lines. Each spectral line corresponds to one specific wavelength that is present in the light emitted by the source. Such a discrete spectrum is referred to as a line spectrum
By the early 19th century, it was found that discrete spectra were produced by every chemical element in its gaseous state. Even though these spectra were found to share the common feature of appearing as a set of isolated lines, it was observed that each element produces its own unique pattern of lines. This indicated that the light emitted by each element contains a specific set of wavelengths that is characteristic of that element.
The first quantitative description of the hydrogen spectrum was given by Johann Balmer, a Swiss school teacher, in 1885, By trial and error, he found that the correct wavelength λ of each line observed in the hydrogen spectrum was given by
1/λ = R ( 1/2^2-1/n^2)
where R is a constant, later called the Rydberg constant, and n may have the integer values 3, 4, 5, If λ is in meters, the numerical value of the Rydberg constant (determined from measurements of wavelengths) s R= 1.097x10^7 m-1
Balmer knew only the four lines in the visible spectrum of hydrogen. Thus, the original formula was written for a limited set of values of T. However, as more techniques to detect other regions of the spectrum were developed, it became clear that Balmer's formula was valid for all values of n. The entire series of spectral lines predicted by Balmers formula is now referred to as the Balmer series
Part A) What is the wavelength of the line corresponding to n =4 in the Balmer series? Express your answer in nanometers to three significant figures .
Part B) What is the wavelength of the line corresponding to n =5 in the Balmer series?

Answers

Answer:

a)   λ = 4.862 10⁻⁷ m,  b)  λ = 4.341 10⁻⁷ m

Explanation:

The spectrum of hydrogen can be described by the expression

         [tex]\frac{1}{\lambda} = R_H ( \frac{1}{n_o^2} - \frac{1}{n^2} ) \ \ \ \ n>n_o[/tex]

in the case of the initial state n = 2 this series is the Balmer series

a) Find the wavelength for n = 4

       

let's calculate

          [tex]\frac{1}{ \lambda}[/tex] = 1,097 10⁷ ([tex]\frac{1}{2^2} - \frac{1}{4^2}[/tex])

          \frac{1}{ \lambda} = 1.097 10⁷ 0.1875 = 0.2056 10⁷

           λ = 4.862 10⁻⁷ m

b) n = 5

           

     \frac{1}{ \lambda} = 1,097 10⁷ ([tex]\frac{1}{2^2} - \frac{1}{5^2}[/tex])

     \frac{1}{ \lambda} = 1.097 10⁷ 0.21 = 0.23037 10⁷

      λ = 4.341 10⁻⁷ m

Why would citizens need to be wary of debris on the road?

Answers

in case they get affected by it

Water from a river or reservoir enters a hydroelectric power plant through a.....????

Answers

Through a dam... hope this helps:)

The most common type of hydroelectric power plant is an impoundment facility. An impoundment facility, typically a large hydropower system, uses a dam to store river water in a reservoir. Water released from the reservoir flows through a turbine, spinning it, which in turn activates a generator to produce electricity.

What is turbine ?

"A turbine is a rotary mechanical device that extracts energy from a fluid flow and converts it into useful work." The work produced by a turbine can be used for generating electrical power when combined with a generator.

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A vertical spring scale can measure weights up to 225 N . The scale extends by an amount of 12.5 cm from its equilibrium position at 0 N to the 225 N mark. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.65 Hz. Ignoring the mass of the spring, what is the mass m of the fish?

Answers

Answer:

The mass of the fish is 6.493 kilograms.

Explanation:

The spring-mass system experiments a Simple Harmonic Motion, then the angular frequency ([tex]\omega[/tex]), in radians per second, is determined by the following equation:

[tex]\omega = 2\pi\cdot f[/tex] (1)

Where [tex]f[/tex] is the frequency, in hertz.

In addition, the mass of the fish ([tex]m[/tex]), in kilograms, is:

[tex]m = \frac{k}{\omega^{2}}[/tex] (2)

Where [tex]k[/tex] is the spring constant, in newtons per meter.

And the spring constant is determined by Hooke's Law:

[tex]k = \frac{F}{\Delta x}[/tex] (3)

Where:

[tex]F[/tex] - Elastic force, in newtons.

[tex]\Delta x[/tex] - Spring elongation, in meters.

If we know that [tex]F = 225\,N[/tex], [tex]\Delta x = 0.125\,m[/tex] and [tex]f = 2.65\,hz[/tex], then the mass of the fish is:

[tex]\omega = 2\pi\cdot f[/tex]

[tex]\omega \approx 16.650\,\frac{rad}{s}[/tex]

[tex]k = \frac{F}{\Delta x}[/tex]

[tex]k = 1800\,N[/tex]

[tex]m = \frac{k}{\omega^{2}}[/tex]

[tex]m = 6.493\,kg[/tex]

The mass of the fish is 6.493 kilograms.

This question involves the concepts of Hooke's Law, and the frequency of spring-mass system.

The mass of the fish is "6.5 kg".

First, we will calculate the angular speed of the system:

[tex]\omega=2\pi f[/tex]

where,

ω = angular speed = ?

f = frequency = 2.65 Hz

Therefore,

[tex]\omega = 2\pi(2.65\ Hz)\\\omega = 16.65\ rad/s\\[/tex]

Now, we will use the Hooke's Law to find out the spring constant of the spring:

[tex]K =\frac{F}{\Delta x}[/tex]

where,

K = spring constant = ?

F = force applied = maximum weight = 225 N

Δx = extension = 12.5 cm = 0.125 m

Therefore,

[tex]k=\frac{225\ N}{0.125\ m}\\\\k = 1800\ N/m\\[/tex]

Now, we will use the formula for the angular speed of a spring-mass system to find out the mass of the fish:

[tex]\omega = \sqrt{\frac{k}{m}}\\\\m = \frac{k}{\omega^2}\\\\m=\frac{1800\ N/m}{(16.65\ rad/s)^2}[/tex]

m = 6.5 kg

Learn more about Hooke's Law here:

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The attached picture illustrates Hooke's Law.

The electric potential at a point in
space is 235 V. If a 0.0485 C
charge is placed there, what will its
potential energy U be?
(Unit = J)

Answers

Answer:

11.3975

Explanation:

Accellus said so

Answer:

11.3975

Explanation:

its for Acellus

A uniform electric field of magnitude 375N/C pointing in the positive x-direction acts on an electron, which is initially at rest.After the electron has moved 3.20cm,what is
(a)the work done by the field on the electron
(b)the charge in potential energy associated with the electron
(c)the velocity of the electron (mass of electron=9.11^-31 kg)

Answers

Answer:

a)  W = - 1.92 10⁻¹⁸ J, b)    U = 1.92 10⁻¹⁸ J, c)   v = 2.05 10⁶ m / s

Explanation:

a) Work is defined by

        W = F. x

 the electric force is

         F = q E

we substitute

          W = q E x

where the displacement is parallel to the electric field

all quantities must be in the SI system

         x = 3.20 cm = 0.0320 m

         W = - 1.6 10-19 375 0.0320  

         W = - 1.92 10⁻¹⁸ J

b) potential energy

          U = [tex]k \frac{q_1q_2}{r}[/tex]

the electrical power is

          V = k q₁ / r

we can write this potential as a function of the electric field

           V = -E x

we substitute

           U = -q E x

           U = - (-1.6 10⁻¹⁹) 375 0.0320

           U = 1.92 10⁻¹⁸ J

Observe that the variation of the red potential is equal to the electrical work

c) let's use conservation of energy

starting point

          Em₀ = U = e E x

final point

          Em_f = K = ½ m v²

energy is conserved

          Em₀ = Em_f

          e E x = ½ m v²

          v² = 2 e E x / m

           v = [tex]\sqrt{ \frac{{2 \ 1.6 10^{-19} \ 375 \ 0.0320 } }{9.1 \ 10^{-31} } }[/tex]

           v = [tex]\sqrt{4.2198 \ 10^{12}}[/tex]

           v = 2.05 10⁶ m / s

4. Which point on this position vs. time graph has the fastest speed?
31
Position
Time
Point 1
Point 2
Point 3
Point 4

Answers

Answer:

Since v = (x(2) - x(1)) / t

point 2 obviously has the greatest displacement in a given time

Also, point 2 is the steepest line on this graph.

William B. Hartsfield was a man of humble origins who became one of the greatest mayors of Atlanta. He served as mayor for six terms (1937–41, 1942–61), longer than any other person in the city's history. Hartsfield held office during a critical period when the color line separating the races began to change and the city grew . . . to a metropolitan population of one million. He is credited with developing Atlanta into the aviation powerhouse that it is today . . . . . . . On August 30, 1961, the city peacefully integrated its public schools. As a result, Atlanta began to acquire its reputation as "A City Too Busy to Hate."

–New Georgia Encyclopedia

During Hartsfield’s time in office, Atlanta became known as "A City Too Busy to Hate.” What factors supported this nickname? Check all that apply.

The city integrated its schools.
Atlanta became a leader in aviation.
The economy declined.
The population increased to one million.
Many people served as the city mayor.

Answers

so basically the first answer would be correct, i hope i could help.

Answer:

It's A, B, and D

A. The city integrated its school

B. Atlanta became a leader in aviation

D. The population increased to one million

Explanation:

Fish can adjust their buoyancy with an organ called a swim bladder. The swim bladder is a flexible gas-filled sac; a fish can increase or decrease the amount of gas in its swim bladder so that it stays neutrally buoyant, neither sinking nor floating. Suppose a fish is neutrally buoyant at some depth and then goes deeper. What needs to happen to the volume of air in the swim bladder

Answers

As the fish goes deeper, the volume of air in the swim bladder increases.

What is Buoyant force?Buoyant force is the upward force a fluid exerts on an object.

Buoyant force is calculated using the following formula;

F = ρVg

where;

ρ is the density of the fluid.V is the volume of the fluid displaced.g is acceleration due to gravity.

The volume of the fluid displaced is calculated as follows;

V = Ah

where;

A is the area of the object.h is the depth of the fluid.

Thus, we can conclude that as the fish goes deeper, the volume of air in the swim bladder increases.

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Question below in photo!! Please answer! Will mark BRAINLIEST! ⬇⬇⬇⬇⬇⬇⬇

Answers

its wave length

its wave lenght because how its measure

what is inside a black hole

Answers

[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]

A black hole is a tremendous amount of matter crammed into a very small — in fact, zero — amount of space. The result is a powerful gravitational pull, from which not even light can escape — and, therefore, we have no information or insight as to what life is like inside. A black hole is not empty, It's actually a lot of matter condensed into a single point. This point is known as a singularity.

Using Newton's 2nd Law of Motion Formula (F=MA) answer the following.
the net force on a vehicle that is accelerating at a rate of 1.5m/s^2 is 1,800 newtons. what is the mass of the vehicle to the nearest kilogram?

Answers

Explanation:

1200 is your answer for this question

The half-life of argon-44 is 12 minutes. Suppose you start with 20 atoms of
argon-44 and wait 12 minutes. How many atoms of argon-44 will be left?
A. 20 atoms
B. 40 atoms
C. 10 atoms
D. 5 atoms
SUBMIT

Answers

Answer:

C.  10

Explanation:

The half-life of argon-44 is 12 minutes, 10 atoms of argon-44 will be left. The correct option is C.

A radioactive substance's half-life is the amount of time it takes for half of the atoms in a sample to decay.

The half-life of argon-44 in this situation is 12 minutes. Starting with 20 argon-44 atoms, half of them will have disintegrated within 12 minutes, leaving 10 atoms.

This happens because radioactive decay is an exponential process with a constant rate of decay. Every half-life cuts the number of atoms in half.

So, if we waited another 12 minutes, half of the remaining 10 atoms would decay, leaving us with 5 atoms. This process is repeated, with half of the remaining atoms dying with each half-life.

Thus, the correct option is C.

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PLEASE HELP ME WITH THIS ONE QUESTION
A converging lens has a focal length of 40 cm. If an object is placed 50 cm in front of the image, where will the image be formed?

Answers

Answer:

the image will be real and inverted

Consider two identical objects of mass m = 0.250 kg and charge q = 4.00 μC. The first charge is held in place at the origin of a coordinate system, unable to move at all times. The second object is initially placed 3.00 cm along the positive x-axis and is free to move. The moment the second object is released at x = 3.00 cm, what is the acceleration of this second object? This experiment is done far away from other massive objects, in outer space.

Answers

Answer:

a = 640 m/s²

Explanation:

From work-kinetic energy principles,

The net force acting on the second object is the gravitational force and the electric force due to the first object.

So, the gravitational force on the mass is F₁ = Gm₁m₂/r² since m₁ = m₂ = m, U = -Gm²/r²

Also, the electric force on the charge is F₂ = kq₁q₂/r² since q₁ = q₂ = q, U = kq²/r²

The net Force F = ma

So, -F₁ + F₂ = F     (F₁ is negative since it is an attractive force in the negative x -direction and F₂ is positive since it is a repulsive force in the positive x- direction)

-Gm²/r² + kq²/r² = ma

ma = -Gm²/r² + kq²/r²

a = (-Gm²/r² + kq²/r²)/m

a = (-G + kq²/m²)m/r²

Since m = 0.250 kg, q = 4.00 μC = 4.00 × 10⁻⁶ C, r = 3.00 cm = 3.00 × 10⁻² m, G = 6.67 × 10⁻¹¹ Nm²/kg², k = 9 × 10⁹ Nm²/C² and a = acceleration of second mass.

Substituting the variables into the equation, we have

a = (m/r²)(-G + k(q/m)²)]

a = (0.250 kg/{3.00 × 10⁻² m}²)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(4.00 × 10⁻⁶ C/0.250 kg)²)

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(16 × 10⁻⁶ C/kg)²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(256 × 10⁻¹² C²/kg²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 2304 × 10⁻³ Nm²/kg²  ]

a = (0.250 kg/9.00 × 10⁻⁴ m)(2.304 Nm²/kg²)

a = 0.576 Nm²/kg /9.00 × 10⁻⁴ m²

a = 0.064 × 10⁴N/kg

a = 64 × 10 N/kg)

a = 640 m/s²

Answer it with 1 reason.1.Mirrors having a curved reflecting surface are called as:
a.Plane mirror
b.Spherical mirror
c.Simple mirror
d.None of above
2.Type of spherical mirror are:
aConcave
b.Convex
c.both A and B
d.none of the above
3.Spherical mirror with reflecting surface curved inwards is called ……………
a. convex mirror.
b. concave mirror
c. curved mirror
d. none of the above
4.Spherical mirror with reflecting surface curved ………………… is called concave mirror.
a.Outwards
b.Inwards
c.Backwards
d.none of the above
5.The center of reflecting surface of a spherical mirror is known as……………
a.Pole
b.Aperture
c.Axis
d.Curvature​

Answers

1 a. Spherical Mirror

2. Both A and B

3. Concave mirror

4.Inwards

5. Pole.

These are your answer. You can mark me Brainliest. Thanks.

hope it helps you have a good day

Explanation:

spherical mirror

both A and B

inwards

pole

The solar glare of sunlight bouncing off water or snow can be a real problem for drivers. The reflecting sunlight is horizontally polarized, meaning that the light waves oscillate at an angle of 90 degrees with respect to a vertical line. At what angle relative to this vertical line should transmission axis of polarized sunglasses be oriented, if they are to be effective against solar glare

Answers

Answer:

Explanation:

The light waves in the reflected sunlight are horizontally polarized, which illustrates that they oscillate at a [tex]90^o[/tex] angle related to a vertical line.

Depending on the condition of the height of the light, the glare can be almost entirely horizontally polarized. Furthermore, all reflections from over-water surfaces are partially polarized. The water becomes more translucent when using polarized sunglasses.

If polarized sunglasses are to be efficient against solar glare, the transmission axis should be positioned at an angle of [tex]\theta = 45^{o}[/tex]

Electricity involves transfer of charge. The charge(s) involved in electrical forces are composed of which?
- Protons
- Neutrons
- Electrons
- Quarks
- Protons & Electrons

Answers

Electrons
......,,,,,,,,

A 0.156-kg ball is hung vertically from a spring. The spring stretches by 4.18 cm from its natural length when the ball is hanging at equilibrium. A child comes along and pulls the ball down an additional 5cm, then lets go. How long (in seconds) will it take the ball to swing up and down exactly 4 times, making 4 complete oscillations before again hitting its lowest position

Answers

Answer:

The answer is "[tex]=2.72 \ seconds \\\\[/tex]"

Explanation:

Using formula:

[tex]kr=mg \\\\k=\frac{0.156 \times 9.8}{0.418}\\\\[/tex]

  [tex]=3.65741627\ \frac{N}{M}\\\\=3.65\ \frac{N}{M}\\\\[/tex]

Calculating the time period:

[tex]T=2\pi \sqrt{\frac{m}{k}}\\\\[/tex]

   [tex]= 2 \pi \sqrt{\frac{0.156}{3.65}}\\\\= 2 \times 3.14 \sqrt{\frac{0.156}{3.65}}\\\\= 6.28 \sqrt{\frac{0.156}{3.65}}\\\\=6.28 \times 0.108210508\\\\=0.67956199\\\\=0.68\\\\[/tex]

The time to calculating the 4 oscillation:

[tex]\to 4T=4\times 0.68 =2.72 \ seconds \\\\[/tex]

The time taken by the spring to complete 4 complete oscillations will be t=2.72 sec

What are oscillations?

Oscillation is the process of repeating variation of the quantity or the recitative or periodic variations with respect to the time.

Here it is given that

mass =0.156 kg

stretch x= 4.18 cm

Now from the formula

[tex]kx=mg[/tex]

[tex]k= \dfrac{0.156\times 9.81}{0.418}[/tex]

[tex]k=3.65\ \frac{N}{m}[/tex]

Now the time period will be calculated as:

[tex]T=2\pi\sqrt{\dfrac{m}{k}[/tex]

[tex]T=2\pi\sqrt{\dfrac{0.156}{3.65}[/tex]

[tex]T=6.28\times 0.108210508[/tex]

[tex]T=0.68\ sec[/tex]

Now for the 4 oscillations the total time will be

[tex]T=4\times 0.68=2.72\ sec[/tex]

Hence the time taken by the spring to complete 4 complete oscillations will be t=2.72 sec

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Calculate the force of an object that has a mass of 10kg and an acceleration of 4m/s²
A-40N
B-8N
C-2.5N
D-0.4N

Answers

The answer is A-40N.

In the diagrams, the solid green line represents Earth's rotational axis and the dashed red line represents the magnetic field axis. Which diagram accurately shows Earth's magnetic field?
Answer: Picture 2 or B!!!!!

Answers

Answer:

B

Explanation:

the answer as said is picture 2

How does the principle of electromagnetism explain the interaction between Earth’s magnetic field and the solar wind? I get that the magnetosphere deflects solar wind, and that solar wind is electrically charged particles from the sun, so electricity is interacting with magnetism, but how does that let electromagnetism explain it?? and please dont just tell me that the magnetosphere just reflects solar particles. tell me how electromagnetism fits into it.

Answers

Answer:

Explained below.

Explanation:

Electromagnetism is defined as the study of the electromagnetic force that takes place between two or more electrically charged particles.

Now, in electromagnetic interaction, the charged particles tend to interact in an electromagnetic manner through the process of exchanging photons. Therefore, it was concluded from various experiments that the magnetic fields lines of forces were always closed, thereby eliminating the possibility of any magnetic monopole in such a manner that within a particular magnetic field, there will be two poles and in the solar system, the electromagnetic attraction between earth magnetic field and solar wind will be by way of a field.

Kelly is riding a bicycle, moves with an initial velocity of 5 m/s. Ten seconds later, she is moving at 15 m/s. What is her acceleration?

Answers

Answer:

her acceleration is 1 m/sec

Explanation:

The following information is given in the question

The initial velocity is 5 m/s

After 10 seconds, she would be moved at 15 m/s

We need to find the acceleration

As we know that

Acceleration = Change in speed ÷ time

Acceleration = (15 - 5) ÷ (10)

= 1 m/sec

Hence, her acceleration is 1 m/sec

The same would be considered  

A painter can paint 2 small rooms and a balcony in 50 hours. If a small room takes twice as long to paint as a balcony, how long will it take him to paint 1 small room plus 3 balconies​

Answers

Explanation:

ddhjdkdjjjkjkjkkkkkkkkk

Waldo needs to know how much force to apply in order to move a 4000-kg object at 2 m/S2. Which law should he refer to
A.
first law
B.
second law
C.
third law
D.
law of gravity

Answers

Answer:

B . Second law

Explanation:

According to second law:

Net Force acting on the body produce acceleration. The magnitude acceleration of the body is directly proportional to net force and inversly proportional to the mass.

Mathematically:

                   a = [tex]\frac{F}{m}[/tex]

and

                   F = ma

So according to the given condition Waldo should use Second law.

someone please help!! tysm

Answers

Hi there!

[tex]\large\boxed{5N}[/tex]

From the given diagram, 20 N is going left, and 15 N is going right.

To find the net force, we must subtract the two since the two forces go in opposite directions:

20 N - 15 N = 5N.

20N-15N
5N
hope this helps

Black holes result from

Answers

Answer:

supernova explosion or death of massive star

Explanation:

"Most black holes form from the remnants of a large star that dies in a supernova explosion."

supergiant stars
a.) form from red giants
b.) fuse hydrogen into carbon
c.) form planetary nebulae
d.) form supernovas

Answers

Answer:

d.) form supernovas

Explanation:

Learned this in physical school last year

-2 m
2m-2m
Determine the reactions on the beam as shown.
270 kN
67.5 KN.m
0.3 m
760
B
-2.1 m
3 m-
-1.2 m

Answers

Report this clown who put the first answer he’s trying to get your ip
Other Questions
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