I NEED HELP ASAP, If you help me I’ll give you Brainlist [Calorimetry and specific heat lab]
I don’t know how to calculate the error %
The formula is:
%Error = [I Accepted value-Experimental value I / Experimental value] x 100 can someone please PLEASE help me :(

Answer: 182.87 grams of hydrogen are necessary to react completely with 853.42g of nitrogen.

Explanation:

The balanced chemical reaction is :

[tex]N_2+3H_2\rightarrow 2NH_3[/tex]

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]  

[tex]\text{Number of moles of nitrogen}=\frac{853.42g}{28g/mol}=30.479moles[/tex]

According to stoichiometry:

1 mole of [tex]N_2[/tex] react with = 3 moles of [tex]H_2[/tex]

30.479 moles of [tex]N_2[/tex] will react with=[tex]\frac{3}{1}\times 30.479=91.437moles[/tex] of [tex]H_2[/tex]

 Mass of [tex]H_2[/tex] =[tex]moles\times {\text {Molar mass}}=91.437mol\times 2g/mol=182.87g[/tex]

Thus 182.87 grams of hydrogen are necessary to react completely with 853.42g of nitrogen.

Answer:

my answer I think is tetrahedral

Answer:hey did you ever get an answer? I need it for this exam

Explanation:

Answer:

It's D, it is the horizon that contains the least humus.

Explanation:

I just did the test

The  statement which correctly describes the soil horizon is option B. The horizon B contains the the smallest rock pieces. It is also called the subsoil layer.

Soil horizon contains different layers of soil which are classified based on the composition of the soil and the presence of rocks within the soil. The primary level of the soil is rich in humus. The decomposed of matter of plants and animals are called humus. On which the plants are growing.

The secondary level of soil horizon or the subsoil level contains some small rocks also onto which the roots of plants does not adhere so much. The third level of soil horizon contains bigger rocks with small gaps between them.

The last layer of the soil horizon is called bedrock layer containing bigger rocks with no significant gaps between them It is called the bedrock layer.

To find more on soil horizon, refer here:

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Answer:

Uniformitarianism is the idea that the natural processes operating today are the same as the natural processes that operated in the past

Answer

5.6 L

Explanation:

whatever you start with, you end with the same amount.

(LAW OF CONSERVATION)

The amount of oxygen and gasoline that can be produced is 5.6 liters

The question above is answered with the law of conversation of mass. This law of conversation of mass states that  no form of energy can be destroyed, instead it is changed from one form to another type of form.

In this law, it is expected that you end with the same amount you started with. According to the question above, since the amount that you started  with is 5.6 liters then you will end with 5.6 liters also.

Please see the link below for more information

https://brainly.com/question/13383562?referrer=searchResults

Answer:

Frost Wedging - Hot and dry

Clay Formation - Cold and Wet

Dissolving - Cold, and dry

Explanation:

The frost wedging happen when the climatic condition is hot and dry. The dry weather compensates the heat and the rock wedging happens quickly. For clay formation the weather has to be cold and wet. The cold weather will make the sand indulge with rock particles resulting in the clay formation.

Answer:

7.34684 × 10^23 atoms

Explanation:

Well, one mole is basically

6.022 × 10^23 atoms. So 1.22 moles would be

6.022 × 10^23 ⋅ 1.22 atoms.

6.022 × 10^23 ⋅ 1.22 = 7.34684 × 10^23 atoms

The total number of atoms in 1.22 moles of magnesium is 7.34 × 10²³.

Given:

1.22 moles of magnesium

[tex]1 \text{ mole}= 6.022*10^{23}\text{ atoms}\\\\1.22 \text{ moles}= 1.22*6.022*10^{23}\text{ atoms}\\\\1.22 \text{ moles}=7.34*10^{23}\text{ atoms}[/tex]

So, the total number of atoms in 1.22 moles of magnesium is 7.34 × 10²³.

Learn more:

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Answer:

multiply

Explanation:

multiplacation

Answer:

The student should have multiplied the molar mass, which was not found, by the number of moles to get an answer of 925grams of Ca(OH)2.

Please find the correct step below

Explanation:

According to the question attached, the student was asked to find the mass in grams of a 12.5mol of Ca(OH)2.

Using the formula;

mole = mass ÷ molar mass

Molar mass of Ca(OH)2 = 40 + (16 + 1)2

= 40 + 17(2)

= 40 + 34

= 74g/mol

From the above formula;

Mass in grams = mole × molar mass

Mass (g) = 12.5 × 74

Mass (g) = 925grams of Ca(OH)2.

Answer:

not sure sorry

Explanation:

Answer:

1. Gases may be compressed

2. Gases expand when less pressure is applied.

3. Gases can be mixed.

4. Gases exert a constant pressure on its container walls.

5. Gases have low densities.

Answer:

1 / 2 of her money would be left

Explanation:

Tammy spent 2/5 of her savings on a watch. She then spent 1/6 of the remainder on a bag. What fraction of her money did she have left?

Taking the question bits by bit;

Tammy spent 2/5 of her savings on a watch

Amount Spent = 2/5

Remainder = 1 - 2/5 = 3/5

She then spent 1/6 of the remainder on a bag

Amount Spent = 1/6  *  3/5 = 1/2  *  1/5  = 1 /10

Total amount spent = 2/5 + 1 /10 =   (4 + 1 ) / 10 = 5 / 10 = 1 / 2

Amount left = 1 - 1 /2 = 1 / 2

Answer:

5.5 L

Explanation:

First we convert 10 g of propane gas (C₃H₈) to moles, using its molar mass:

Then we use the PV=nRT formula, where:

1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

Answer:

B. bacteria

Explanation:

they are responsible for the fixation of nitrogen

Answer:

the answer is B bacteria

Answer:

B

Explanation:

Answer: The specific heat capacity of metal is [tex]1.31J/g^0C[/tex]

Explanation:

[tex]Q_{absorbed}=Q_{released}[/tex]

As we know that,  

[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]

[tex]m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)][/tex]      

where,

[tex]m_1[/tex] = mass of metal = 35 g

[tex]m_2[/tex] = mass of water = 220 g

[tex]T_{final}[/tex] = final temperature = [tex]30^0C[/tex]

[tex]T_1[/tex] = temperature of metal = [tex]130^oC[/tex]

[tex]T_2[/tex] = temperature of water = [tex]25^oC[/tex]

[tex]c_1[/tex] = specific heat of metal = ?

[tex]c_2[/tex] = specific heat of water =  [tex]4.184J/g^0C[/tex]

Now put all the given values in equation (1), we get

[tex]m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)][/tex]

[tex]35\times c_1\times (30-130)^0C=-[220g\times 4.184\times (30-25)][/tex]

[tex]c_1=1.31J/g^0C[/tex]

Therefore, the specific heat capacity of metal is [tex]1.31J/g^0C[/tex]

Answer:

The new volume of gas would be 30 L.

Explanation:

This is an example of a Combined Gas Laws problem.

Cl2 = 70.9 g/mol

=

[tex]21.4 \: mol \times \frac{70.9 \: g}{1 \: mol} = 1517.26 \: g[/tex]

Answer: because the tablet is already crushed and is easy for the organism to absorb instead of having to break it down

Explanation:

Answer:

letter B is the answer

Explanation:

just take a look at the atoms

Answer:

B.) Only elements have one kind of atom.

Explanation:

An element consists of only one type of atom, while a compound consists of two or more types of elements

Using the proportions of the amount of the molecules, we can convert from any reagent or product to any other reagent or product. In the context of this reaction, for every mole of N2 and every 3 moles of H2 we obtain 2 moles of NH3.

Answer: c

Explanation:

Answer:  Edmentum question:

The following graph shows the barometric pressure over the course of the day in Bellingham. What effect will this trend likely have on cloud cover and precipitation over the city?

a scatter plot showing the barometric pressure of an area, with air pressure on the y-axis and time on the x-axis

Explanation: edmentum answer:  

In the graph, barometric pressure is decreasing. The drop in pressure represents a low-pressure system. This type of system will cause an increase in cloud cover and precipitation.

Answer:

15.26 cm³

Explanation:

La densidad de una sustancia se define como su masa por unidad de volumen:

densidad = masa/volumen

Tenemos los siguientes datos de la barra de hierro:

masa = 160 g

volumen = 20,35 cm³

Por lo tanto, la densidad de la barra de hierro es:

densidad = 160 g/20,35 cm³ = 0.786 g/cm³

El volumen de 12 gramos de hierro se calcula utilizando el dato de masa (12 g) y la densidad calculada:

densidad = masa/volumen  ⇒ volumen = masa/densidad

                                                                 = 12 g/(0.786 g/cm³)

                                                                 = 15.26 cm³