The Sun is 400 times larger than the Moon, yet since it is 400 times further away from Earth than the Moon, they appear to be the same size in the Earth's sky.
Cancer and diabetes are two common hereditary diseases.
True or False?
which best describes series
Answer:
a single closed path of electrical components including a voltage source
A cliff diver jumps off a 57m cliff and lands in the water 4.3 seconds later, a distance of 2.15m from the cliffs edge. What was the magnitude and direction of his starting velocity
The cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.
The height of the cliff = 57m
The horizontal distance from the cliff = 2.15m
The time is taken = 4.3s
The acceleration due to gravity g = 9.81m/s²
Consider the vertical y-axis
d = 57mWe know the equationd = ut +1/2gt²
57 = u (4.3) + 1/2 (9.81) (4.3)²
57 = 4.3u + 90.69
u = -7.836m/s
The y component of initial velocity is in the upwards direction
Consider the horizontal x-axis
d = 2.15 mWe know the equation, in case of no accelerationd = ut
2.15 = u (4.3)
u = 0.5 m/s
The net velocity is the square root of the summation of the squares of the x and y components of velocity
Net velocity = 7.85m/s
For the direction, tan θ = y/x = 15.67
θ= 86°
So the cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.
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Calculate the time period of simple pendulum whose length is 98.2cm
The time period resulting in oscillations will be 1.986 seconds.
What is the period of oscillation?The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.
The time period of the oscillation is;
[tex]\rm T = 2 \pi\sqrt{\frac{L}{g}} \\\\ \rm T = 2 \times 3.14 \times \sqrt{ \frac{98.2 \ \times 10^{-2} \ m}{9.81 \ m/s^2}} \\\\ T= 1.986 \ sec[/tex]
Hence the time period resulting oscillations will be 1.986 seconds.
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How many electrons or protons are found in: a). +1 C of charge? b). -1 C of charge? c. -1.6 x 10^-6 C of charge? a)
Answer:
50 charges
Explanation:
it will deduct and mutiple it self and divide
a standby generator is connected to 1540 w lamps and a musicians 600w amplifying system how much energy is used if the generator is used for 6 hours
Answer:2140 watts x 6 hours =12.84 kWh. Are you looking for specific type units such as Jules?
A projectile is launched at an angle of 29 degrees above the horizontal with an initial velocity of 36.6 at an unknown height.
The magnitude of the vertical velocity upon returning to its original, unknown height is _____ m/s.
The vertical velocity of the projectile upon returning to its original is 17. 74 m/s
How to determine the vertical velocity
Using the formula:
Vertical velocity component , Vy = V * sin(α)
Where
V = initial velocity = 36. 6 m/s
α = angle of projectile = 29°
Substitute into the formula
Vy = 36. 6 * sin ( 29°)
Vy = 36. 6 * 0. 4848
Vy = 17. 74 m/s
Thus, the vertical velocity of the projectile upon returning to its original is 17. 74 m/s
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two conducting spheres are touched together
Answer:
I think its either A or B. I’m not really sure, don’t listen to me. Read my explanation and it should help you.
Explanation:
When the two conducting spheres are brought together to touch, it is as though they become one single big conductor and the total charge of the two spheres spreads out across the whole surface of the touching spheres. When the spheres are moved apart again, each one is left with half of the total original charge…
X and Y are two identical conducting spheres separated by a distance d. X has a charge of +6µC and Y has a charge of -2µC. The electric force between them is +F (i.e. attractive). The spheres are touched together and are then returned to their original separation d. What is the new value of the force between them? Any help is greatly appreciated. I assumed that since the net charge should remain the same after, there would be no change in the value of the force, but the answer scheme gives the answer as -F/3…
The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme-
tres (mid-infrared light).
(b) What is the wavelength of the light emitted by the object? (c) What type of radiation was originally emitted by the object?
b. The wavelength of light emitted by the object is 233 nm
c. The type of radiation originally emitted by the object is ultraviolet radiation.
To find the wavelength, we need to know what redshift is.
What is redshift?Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.
Redshift is given by z = λ'/λ - 1 where
λ' = observed wavelength and λ = emitted wavelength.Making λ subject of the formula, we have
λ = λ'/(1 + z)
Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).
So,
z = 7.6 and λ' = 2μm(b) What is the wavelength of the light emitted by the object?Substituting the values of the variables into the equation, we have
λ = λ'/(1 + z)
λ = 2μm/(1 + 7.6)
λ = 2μm/8.6
λ = 0.233 μm
λ = 233 nm
So, the wavelength of light emitted by the object is 233 nm
c. What type of radiation was originally emitted by the object?
Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.
So, the type of radiation originally emitted by the object is ultraviolet radiation.
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I need help!1
An ambulence is currently travelling at 15m/s and is accelerating with a constant acceleration of 5m/s^2, the ambulence is attempting to pass a car which is moving at a constant velocity of 30m/s. how far must the ambulence travel until it matches the car's velocity?
Answer:
67.5m
Explanation:
Use the kinematics equation.[tex]\frac{vf^2-vo^2}{2a} =x[/tex]
[tex]vf=30[/tex] [tex]vo=15[/tex] [tex]a=5[/tex]
[tex]\frac{30^2-15^2}{10} =x\\[/tex]
[tex]67.5=x[/tex]
The quotient of 8.4x10° and a number n results in 5.6x 1027. What is the value of n?
1.5x10-18
O 1.5x10
O 1.5x10³
1.5x10¹8
what kinds of investigations might have led to our current understanding of matter and energy? why is it important for scientists to use the same scientific method and consistent measurement units?
The kind of investigations might have led to our current understanding of matter and energy is research and measurement.
It is important for scientists to use the same scientific method and consistent measurement units in order to get the correct value while analayzing.
What is matter?The matter has volume and space occupied.
When conceivable the researcher endeavors to test his speculations via painstakingly planned and controlled tests that will yield quantitative instead of subjective outcomes.
Thus, the kind of investigations might have led to our current understanding of matter and energy is research and measurement.
It is important for scientists to use the same scientific method and consistent measurement units in order to get the correct value while analayzing.
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A.
emotional health : expressing feelings
B.
physical health : respecting others
C.
mental health : living in harmony with the environment
D.
social health : getting adequate sleep
Emissions from alpha decay require the least amount of shielding.
Which best describes why the emissions from alpha decay are so easily blocked compared to the emissions of other types of radioactive decay?
The particles released during alpha decay are called alpha particles. Alpha particles have greater mass and charge than other emitted particles.
Radioactive emissions are the transfer of energy through the flow of particles or waves in a mediumThere are 3 types of radioactive emissions which are alpha, beta and gammaIn alpha radiation, the nucleus emits an alpha particle which is equivalent to a helium nucleusIn beta radiation, an electron is emitted to convert a neutron to a protonIn gamma radiation, the nucleus just loses energySince alpha particles have more mass and charge, they are more ionising and lose more energy at a faster rate and can be blocked easily.
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in which area of the galaxy would you find stars with fairly circular orbits about the galactic center?
Stars with fairly circular orbits about the galactic center is found in the disk
What are stars?Stars are one of the astronomical object that is usually very bright.
A circular orbit star is a star that moves in circular direction and not elliptical orbit which is most common to starts.
Therefore, Stars with fairly circular orbits about the galactic center is found in the disk
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what is the value of v2 below in the series circuit.
Answer:
[tex]\fbox {40 V}[/tex]
Explanation:
The formula we apply :
[tex]\boxed {Voltage = Current \times Resistance}[/tex]
At the point 2, current flowing will be 2A and resistance is 20Ω.
Solving :
V = 2 × 20
V = 40 V
An atom is the most basic particle that represents what type of matter?
OA. Element
OB. Compound
OC. Crystal
OD. Mixture
Answer:
b
Explanation:
If a drag racing motorcyclist has an initial speed of 10 m/s, and then he/she
accelerates for 15 seconds at 15 m/s2, what is the velocity after 15 seconds?
O 30 m/s
O235 m/s
O225 m/s
Answer:
235 m/s
Explanation:
v = u + at
where v = final speed,
u = initial speed (10 m/s),
a = acceleration (15 m/s²),
t = time taken (15 s).
Substituting into the formula:
v = 10 + (15 x 15)
v = 10 + 225
v = 235 m/s
A rare butterfly (0.01 kg) is slowly flapping its wings and moving across a road. An unsuspecting driver in a large car (1000 kg) going very fast makes a sharp turn and runs directly into the butterfly. The butterfly smashes against the windshield (of course) but the car keeps moving down the road. Which object has the greater force: The butterfly or the car?
Both the butterfly and the large car will have equal forces but in opposite direction.
Newton's third law of motion
Newton's third law of motion states that action and reaction are equal and opposite. That is, the force exerted on an object is equal to the reaction experienced by the object.
Fa = - Fb
where;
Fa is the force exerted by the large carFb is the force of the butterflyThus, both the butterfly and the large car will have equal forces but in opposite direction.
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Magnification of the image is formed by a mirror is -1.25,then answer the following questions
1. Mention the position of the object on the principle access
2. What kind of mirror is used to get the image
3. Mention the characteristics of the image
4. What is the height of the image if the object size is 2 cm
Answer:
below
Explanation:
1. in front of the mirror
2. convex mirror
3.upright and diminished
4.magnification= image height÷object height
-1.25=i.h÷2
ih=-1.25×2
i.h=-2.5
Ramu,the gardener,is trying to pull out weeds. however,he has to apply great force.why do you think he has to apply to much force?
Answer:
Roots are basically hooked into the ground?
Explanation:
Maybe you could comment here the choices if it's multiple choice.
Samuel pushes against a door with a force of 10N, but the door doesn't move. Has Samuel done work on the door?
No, Samuel hasn't done work, Since the door doesn't move.
What is work done?Work is said to be done when an applied force moves an object over a given distance.
W = Fd
where;
W is work doneF is the applied forced is the distanceSince the door doesn't move, we can conclude that Samuel hasn't done work.
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The Volume Of a Body weighing is 1200 kg is 250000 [tex]cm^{3}[/tex] Find ITs density.
Write With Formula
Answer:
[tex]\boxed {Density = 4800 kg/m^{3}}[/tex]
Explanation:
Formula :
[tex]\boxed {Density = \frac{Mass (kg)}{Volume (m^{3})}}[/tex]
Convert volume into standard unit :
⇒ 250000 cm³ × 10⁻⁶
⇒ 0.25 × 10⁶ × 10⁻⁶
⇒ 0.25 m³
Solve for density :
⇒ Density = 1200 kg / 0.25 m³
⇒ Density = 1200 × 4 kg/m³
⇒ Density = 4800 kg/m³
Select the correct location on the image.
Identify the magnetic north pole of Earth’s magnet.
The magnetic north pole of the earth's magnet is in the geographic south pole.
There are two magnetic and geographic poles each, north and southThe two geographic poles are the locations where the earth's axis of rotation passes through which is imaginaryThe magnetic north and south poles are not the same as the geographic north and south polesIn a compass, the needle points to the magnetic north poleBy convention, the magnetic north pole corresponds to the geographic south poleThe magnetic south pole corresponds to the geographic north poleThe magnetic field lines of a magnet start from the magnetic north pole and end at the magnetic south poleThe magnetic north pole of the earth's magnet is the geographic south pole.
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Which of the following differentiates an audiologist from an anthropologist?
An audiologist uses empirical evidence to determine treatment.
An audiologist uses empirical evidence to determine treatment.
An audiologist examines physical characteristics of humans.
An audiologist evaluates communication methods.
An audiologist analyzes observed behaviors.
The statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans. That is option C.
Who is an audiologist?Audiologist is an individual that specializes in the diagnosis, treatment and management of hearing loss and balance disorders in adults and children.
An anthropologist is also an individual that studied the past and present experiences of individuals.
Therefore, the statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans.
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The equation to calculate density is D = m/v. For a liquid substance, which item increases as heat is applied?
volume
density
mass
density and volume
Answer:
See below
Explanation:
Things generally expand when heated ....so volume increases while mass remains the same .....this will cause the value of density to decrease
What is the volume of the cone?
Answer:
42.417 cm³
Explanation:
The formula to find the volume of a cone is :
V = [tex]\frac{1}{3}[/tex] × π r² h
Here,
r ⇒ radius ⇒ 3 cm
h ⇒ height ⇒ 4.5 cm
Let us find it now.
V = [tex]\frac{1}{3}[/tex] × π r² h
V = [tex]\frac{1}{3}[/tex] × π × 3 × 3 × 4.5
V = [tex]\frac{1}{3}[/tex] × π × 9 × 4.5
V = [tex]\frac{1}{3}[/tex] × π × 9 × 4.5
V = [tex]\frac{1}{3}[/tex] × π × 40.5
V = [tex]\frac{1}{3}[/tex] × 3.142 × 40.5
V = [tex]\frac{1}{3}[/tex] × 127.251
V = 42.417 cm³
Question 9 of 34
When you graph displacement versus time (a displacement-time graph), what
variable is on the y-axis?
O A. Speed
OB. Displacement
C. Time
O D. Velocity
SUBMIT
Answer:
Option B) Displacement
The work function for magnesium is
3.70 eV. What is its cutoff frequency?
Hint: 1 eV 1.60 x 10-19 J
[ ? ] × 10⁰ ² ) Hz
]
The cut off frequency of the magnesium atom is obtained as 8.9 * x 10^18 Hz.
What is the cut off frequency?The cut off frequency is the lowest frequency of the incident ray at which photoelectric effect occurs.
Given that;
1 eV gives 1.60 x 10-19 J
3.70 eV gives 3.70 eV * 1.60 x 10-19 J/1 eV
= 5.92x 10^-19 J
Now;
Wo = hfo
fo = Wo/h
fo = 5.92x 10^-19 J/6.6 * 10^-34
fo = 8.9 * x 10^18 Hz
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Rana writes a summary about a mass on a spring in simple harmonic motion as it moves upward from the equilibrium position toward the maximum positive displacement. as the mass moves upward, the velocity is positive and decreasing while the acceleration is negative and decreasing. what error did rana make? the velocity should be negative, not positive. the acceleration should be positive, not negative. the velocity should be increasing, not decreasing. the acceleration should be increasing, not decreasing.
Answer:
The magnitude of acceleration should be increasing.
Velocity is positive as the mass is moving towards the maximum positive displacement. Velocity would be decreasing. Acceleration is negative as velocity is decreasing. Additionally, the magnitude of acceleration would be increasing (becomes more negative.)
Explanation:
As the mass in this question moves upwards, the displacement of this mass is becoming more positive. Hence, the velocity of this mass would be positive.
In a simple harmonic motion, velocity is:
maximized at the equilibrium position (where displacement is [tex]0[/tex],) and[tex]0[/tex] when displacement is maximized.The mass in this question is moving from [tex]0[/tex] displacement (where velocity is maximized) towards maximum displacement (where velocity is [tex]0[/tex].) Thus, the velocity of the mass would be decreasing.
Since the velocity of this mass is decreasing, the acceleration of this mass would be negative. In a simple harmonic motion, acceleration is:
[tex]0[/tex] at the equilibrium position, andmaximum when displacement is maximized, but opposite to the direction of displacement.The mass in this question is moving from the equilibrium position (where acceleration is [tex]0[/tex]) towards maximum displacement (where acceleration is most negative.) Thus, the magnitude of the acceleration of this mass would be increasing, and the acceleration of the mass would become more negative.
Answer:
the acceleration should be increasing, not decreasing.
or in other words, D.
