Answer:
By walking and stuff, duh.
Explanation:
We walk, motion.
We drive, motion.
We eat, motion.
We talk, motion.
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
2H2(g) + O2(g)
—>2H20(9)
Answer:
ΔH°r = -483.64 kJ
Explanation:
Let's consider the following balanced equation.
2 H₂(g) + O₂(g) ⇒ 2 H₂O(g)
We can calculate the standard enthalpy change of the reaction (ΔH°r) using the following expression.
ΔH°r = ∑ΔH°f(p) × np - ∑ΔH°f(r) × nr
where
ΔH°f: standard heat of formation
n: moles
p: products
r: reactants
ΔH°r = ΔH°f(H₂O(g)) × 2 mol - ΔH°f(H₂(g)) × 2 mol - ΔH°f(O₂(g)) × 1 mol
ΔH°r = (-241.82 kJ/mol) × 2 mol - 0 kJ/mol × 2 mol - 0 kJ/mol × 1 mol
ΔH°r = -483.64 kJ
In gas chromatography, the stationary phase is made up of high molecular weight non-volatile polymer coated on solid support packed inside a column and the mobile phase is an inert gas that carries the volatilized components of the sample mixture through the column toward the detector. The physical form of the stationary (s) and mobile phase (m) in gas chromatography are:
Answer:
liquid (s), gas (m)
Explanation:
In gas chromatography, the phase of stationary would be made of great molecular weight that have non-volatile coated on the packed i.e. inside a column also the mobile phase represent the inert gas that carries the components that should be volatilized.
Now the physical form and the mobile phase is the liquid and the gas
The same would be relevant and considered too
Calculate the mass of each element in the
compound by multiplying its molar mass by the
number of moles of the element present in one
mole of the compound
Mass N =
Mass H =
Mass O =
Answer:
For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively
Explanation:
The computation of the mass of each element is given below:
As we know that
A1 mole of ammonium nitrate i.e. 2 mol N, 4 mol H, 3 mol
Now we multiply each of above by the molar masses
For N
= 14.0 g/mol × 2
= 28.0 gN
For H
= 1.0 g/mol × 4
= 4.0 gN
ANd, for O
= 16.0 g/mol × 3
= 48.0 gN
Hence, For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively
For each of the following precipitation reactions, complete and balance the equation, indicating clearly which product is the precipitate.
a) Ba(NO3)2(aq) + (NH4)2SO4(aq) ->
b)CoCl3(aq) + NaOH(aq) ->
c)FeCl3(aq) + (NH4)2SS(aq) ->
Answer: a) [tex]Ba(NO_3)_2(aq)+(NH_4)_2SO_4(aq)\rightarrow BaSO_4(s)+2NH_4NO_3(aq)[/tex]
b) [tex]CoCl_3(aq)+3NaOH(aq)\rightarrow Co(OH)_3(s)+3NaCl(aq)[/tex]
c) [tex]2FeCl_3(aq)+3(NH_4)_2S(aq)\rightarrow Fe_2S_3(s)+6NH_4Cl(aq)[/tex]
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.
The balanced chemical equations are:
a) [tex]Ba(NO_3)_2(aq)+(NH_4)_2SO_4(aq)\rightarrow BaSO_4(s)+2NH_4NO_3(aq)[/tex]
b) [tex]CoCl_3(aq)+3NaOH(aq)\rightarrow Co(OH)_3(s)+3NaCl(aq)[/tex]
c) [tex]2FeCl_3(aq)+3(NH_4)_2S(aq)\rightarrow Fe_2S_3(s)+6NH_4Cl(aq)[/tex]
state the conditions under which copper reacts with sulphuric (vi) acid and give an equation for the reaction
Answer:
When the metal reacts with hot, concentrated sulphuric acid, the products of the reaction are copper (II) sulphate, sulphur dioxide and water. Cu + 2H2SO4 = CuSO4 + SO2 + 2H2O. This is a typical redox reaction in which the acid is reduced to SO2, but no hydrogen is produced here
Dinitrogen monoxide gas is collected at 12.0°C in an evacuated flask with a measured volume of 10.0 L. When all the gas has been collected, the pressure in
the flask is measured to be 0.070 atm.
Calculate the mass and number of moles of dinitrogen monoxide gas that were collected. Round your answer to 2 significant digits.
mass: 1
mole: mol
?
Answer:
0.030 moles N2O and 1.3 grams N2O
Explanation:
Attatched is an image of the explanation. Hope this helps!
Can somebody please help me!!!!
Answer:
Friston to energy
Explanation:
Friction to Energy as its a energy stooping the object form moving
When water evaporates from a plant's leaves, this process is
called
Answer:
transpiration
Explanation:
Answer:
Transpiration
Explanation:
Is carbon moving into the air moving out of the air or both
Answer:
Carbon is moving into the air
What is the molarity of a 9.0 L solution that contains 0.500 mol HCl?
A.8.29 M
B.0.879 M
C.0.018 M
D.0.056 M
Answer: 0.056
Explanation:
The molarity of the solution is the ratio of the number moles of solute to the volume of solution. Hence, the molarity of the given solution is 0.056 M. Thus, option D is correct.
What is molarity ?Molarity is a common term used to express the concentration of a solution . It is the ratio of the number of moles of solute to the volume of solution in liters.
Given that,
volume of HCl solution = 9 L
no. of moles of HCl = 0.50 moles.
Then,
molarity = no.of moles/volume in L
M = 0.50 Moles/9 L
= 0.056 M.
Therefore, the molarity of the solution is 0.056 M.
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After she explains commensalism to her friend, Hailey tries to think of an example of it. Which of the following is an example of commensalism?
fleas and and a dog
barnacles on a whale
a human and chicken pox
a bee and a flower
Answer:
bernacles on a while.
Explanation:
These crustaceans stick to the bodies of baleen whales during their larval stage, when they are still able to swim, and establish a commensal relationship with the mysticetes, since they neither harm nor benefit the host that hosts them, whom they will accompany throughout their lives. .
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
4HCl(g) + O2(g)—>2H2O(g) + 2Cl2(g)
Answer:
ΔH°r = -114.40 kJ
Explanation:
Let's consider the following balanced equation.
4 HCl(g) + O₂(g) ⇒ 2 H₂O(g) + 2 Cl₂(g)
We can calculate the standard enthalpy change of the reaction (ΔH°r) using the following expression.
ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)
where
ΔH°f: standard heat of formation n: moles p: products r: reactantsΔH°r = 2 mol × ΔH°f(H₂O(g)) + 2 mol × ΔH°f(Cl₂(g)) - 4 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(O₂(g))
ΔH°r = 2 mol × (-241.82 kJ/mol) + 2 mol × 0 kJ/mol - 4 mol × (-92.31 kJ/mol) - 1 mol × 0 kJ/mol
ΔH°r = -114.40 kJ
How many grams of aluminum chloride are produced when 5.96 grams of aluminum are reacted with excess chlorine gas? Start with a balanced equation.
Answer:
29.47 g of AlCl₃.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2Al + 3Cl₂ —> 2AlCl₃
Next, we shall determine the mass of Al that reacted and the mass of AlCl₃ produced from the balanced equation. This can be obtained as follow:
Molar mass of Al = 27 g/mol
Mass of Al from the balanced equation = 2 × 27 = 54 g
Molar mass of AlCl₃ = 27 + (35.5× 3)
= 27 + 106.5
= 133.5 g/mol
Mass of AlCl₃ from the balanced equation = 2 × 133.5 = 267 g
SUMMARY:
From the balanced equation above,
54 g of Al reacted to produce 267 g of AlCl₃.
Finally, we shall determine the mass of AlCl₃ produced by the reaction of 5.96 g of Al. This can be obtained as follow:
From the balanced equation above,
54 g of Al reacted to produce 267 g of AlCl₃.
Therefore, 5.96 g of Al will react to produce = (5.96 × 267)/54 = 29.47 g of AlCl₃.
Thus, 29.47 g of AlCl₃ were obtained from the reaction.
Convert 0.809 mol AlCl3 to formula units AlCl3.
Answer:
133.340538.
Explanation:
The answer is 133.340538. We assume you are converting between grams AlCl3 and mole. You can view more details on each measurement unit: molecular weight of AlCl3 or mol This compound is also known as Aluminium Chloride. The SI base unit for amount of substance is the mole.
Question 13
A hot air balloon has a pressure of 0.715 atm while the temperature outside is 30
degreeſ C. What will the pressure be if the temperature drops to 10 degrees C while
volume remains constant? Do not write units in the answer. Make sure to convert
temperature values to Kelvin.
Answer:
0.668 atm
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 0.715 atm
Initial temperature (T₁) = 30 °C
Final temperature (T₂) = 10 °C
Volume = constant
Final pressure (P₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 30 °C
Initial temperature (T₁) = 30 °C + 273
Initial temperature (T₁) = 303 K
Final temperature (T₂) = 10 °C
Final temperature (T₂) = 10 °C + 273
Final temperature (T₂) = 283 K
Finally, we shall determine the final. This can be obtained as follow:
Initial pressure (P₁) = 0.715 atm
Initial temperature (T₁) = 303 K
Final temperature (T₂) = 283 K
Final pressure (P₂) =?
P₁ / T₁ = P₂ / T₂
0.715 / 303 = P₂ / 283
Cross multiply
303 × P₂ = 0.715 × 283
303 × P₂ = 202.345
Divide both side by 303
P₂ = 202.345 / 303
P₂ = 0.668 atm
Thus, the final pressure of the hot air balloon is 0.668 atm
Write the Ground state electron configuration of Ca using the noble-gas shorthand notation
Answer:
[Ar] 4s2
Explanation:
The noble gas that comes before Ca is Ar, so that's what you'll use for the noble-gas shorthand part of it. Ca has two additional electrons in the 4s orbital, hence the 4s2.
The ground state electronic configuration of calcium using noble gas short hand notation is [Ar]4s².
What is noble gas short hand notation ?Noble gas short hand notation comprises of the symbol of the last noble gas which is prior to the concerned atom which is followed by the configuration of the electrons which remains.
This notation helps in shortening of electronic configuration which is otherwise huge for elements with high atomic numbers.This is possible cause it uses the preceding noble gas configuration which accounts for that many electrons and the remaining electrons are filled in the next higher sub shell.
For calcium, preceding noble gas is argon which accounts for 18 electrons and for remaining two electrons they are placed in 4s sub shell thus making the total count of electrons to 20.
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What does evaporation produce?
a precipitation
b rain or snow
C water vapor
d condensation
Answer:
C water vapor.
or saturated water vapor ( steam )
How does the entropy change in the reaction 2C3H6(g) + 9O2(g) → 6C02(g) + 6H2O (g)?
I will mark brainliest!! Thank you so much!!
Answer:
The entropy increases!!!
Explanation:
a pex
The entropy increases in the reaction.
What is entropy?Entropy is defined as the measure of the disorder of a system.Entropy is an extensive property of a thermodynamic system, to put it in simple words, its value changes depending on the amount of matter that is present.Entropy is denoted by the letter S and has units of joules per kelvin (JK−1)The entropy increases in the reaction if the total number of product molecules are greater than the total number of reactant molecules.
2C3H6(g) + 9O2(g) → 6C02(g) + 6H2O (g)
In the above reaction, the product molecules are greater than the reactant molecules. Hence, entropy increases.
Hence, we can conclude that option A is the answer.
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Of the 8 planets, why does the sun have the most gravitational attraction to Mercury?
Answer:
It is the closest sir.
Have an amazing day and enjoy. P.S Good luck!
Explanation:
Let's chek the orders where mercury and rest planets present
MercuryVenusEarthMarsJupiterSaturnUranusNeptuneMercury is closest to sun so gravitational force is most
If DG for a reaction equals zero, the reaction
a. is spontaneous.
b. is at equilibrium.
c. may or may not be spontaneous.
d. is not spontaneous.
Answer: If [tex]\Delta G[/tex] for a reaction equals zero, the reaction is at equilibrium.
Explanation:
When a thermodynamic closed system tends to do the maximum amount of non-expansion work then the energy used to do this work is called Gibb's free energy.
The expression for [tex]\Delta G[/tex] can be written as follows.
[tex]\Delta G = \Delta H - T \Delta S[/tex]
where,
[tex]\Delta H[/tex] = enthalpy change
T = temperature
[tex]\Delta S[/tex] = entropy change
This means that [tex]\Delta G[/tex] is the difference between heat released in a process and the amount of heat released in a reversible manner for the same process. So, when the value of of [tex]\Delta G[/tex] comes out to be equal to zero then it means no heat is released or absorbed.
Hence, the reaction is stable or at equilibrium.
Thus, we can conclude that the value of [tex]\Delta G[/tex] = 0 then it means that the reaction is at equilibrium.
A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:
Fe2O3(s) + 3 H2(
92Fe(s) + 3 H2O(9)
Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation
of H2O(g) is
kJ/mol.
Answer: The standard enthalpy of formation of [tex]H_2O(g)[/tex] is -252.1 kJ/mol.
Explanation:
The balanced chemical reaction is,
[tex]Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)[/tex]
The expression for enthalpy change is,
[tex]\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactantss}][/tex]
Putting the values we get :
[tex]\Delta H=[2\times H_f{Fe}+3\times H_f{H_2O}]-[1\times H_f{Fe_2O_3}+3\times H_f{H_2}][/tex]
[tex]67.9kJ=[(2\times 0)+(3\times H_f{H_2O})]-[(1\times -824.2kJ/mol)+3\times 0kJ/mol)][/tex]
[tex]H_f{H_2O}=-252.1kJ/mol[/tex]
Thus standard enthalpy of formation of [tex]H_2O(g)[/tex] is -252.1 kJ/mol.
Can somebody please help me!!!
Answer:
speed
Explanation:
Speed is the rate at which something moves. The speed of light is faster than the speed of sound.
The activation energy for the gas phase decomposition of isobutyl bromide is 211 kJ.
(CH3)2CHCH2Br(CH3)2C=CH2 + HBr
The rate constant at 686 K is 1.04×10-3 /s. The rate constant will be 1.24×10-2 /s at __kj
Answer:
whatttttttttttttttt do you meam
What is the volume of a 5.00 molar solution containing 20 moles of 0.40 10.0L 0.010L
Answer:
Volume of solution = 4 liter
Explanation:
Given:
Molarity = 5 M
Number of moles = 20 moles
Find:
Volume of solution
Computation:
Moles of solute mixed per litre of solution is known as molarity. A 1 M sample is the one in which 1 molecule of solvent is soluble in one liter of solution volume.
M = Mol / L
5 = 20 / L
Volume of solution = 4 liter
A 10.0-mL sample of sulfuric acid, H2SO4, from a battery of an old car is diluted to 100.0 mL, and a 10.00-mL aliquot (portion) of the diluted acid is then titrated with 0.2500 M NaOH solution. If the concentration of H2SO4 in the original battery was 3.25 M, how many milliliters (mL) of the NaOH solution is required to titrate the sulfuric acid present in the 10.0-mL portion of dilute acid solution
Answer:
26.0 mL
Explanation:
The reaction that takes place is:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂OFirst we calculate the molar concentration of the diluted sulfuric acid solution, using the C₁V₁=C₂V₂ formula:
3.25 M * 10.0 mL = C₂ * 100 mLC₂ = 0.325 MNow we calculate how many H₂SO₄ moles would there be in 10.00 mL of this diluted solution, using the definition of molarity:
0.325 M * 10.00 mL = 3.25 mmol H₂SO₄Then we convert 3.25 mmoles of H₂SO₄ into mmoles of NaOH, using the stoichiometric coefficients of the balanced reaction:
3.25 mmol H₂SO₄ * [tex]\frac{2mmolNaOH}{1mmolH_2SO_4}[/tex] = 6.5 mmol NaOHFinally we calculate the required volume of the NaOH solution, using the definition of molarity:
6.5 mmol NaOH / 0.2500 M = 26.0 mLCalculate the percent error, with correct sig figs, in the atomic weight if the mass of a Zn electrode increased by 0.3681 g and 6.514x10-3 moles of Zn was produced. Select the response with the correct Significant figures. You may assume the molar mass of elemental zinc is 65.38 g/mol. Refer to Appendix D as a guide for this calculation.
Answer:
the percent error is -13.5%
Explanation:
Given the data in the question;
Exact atomic weight = 65.38 g/mol
For approx
increased mass = 0.3681 g
moles = 6.514 x 10⁻³
we know that; moles = mass / (Atomic mass )
so
Atomic mass_[tex]_{approx[/tex] = mass / moles
Atomic mass_[tex]_{approx[/tex] = 0.3681 / 6.514 x 10⁻³
Atomic mass_[tex]_{approx[/tex] = 56.509
so approx atomic weight = 56.51 g/mol
we know that;
% error = ( [approx - exact] / exact ) × 100
we substitute
% error = ( [56.51 - 65.38] / 65.38 ) × 100
% error = (-8.87 / 65.38 ) × 100
% error = ( -0.1356684 ) × 100
% error = -13.5%
Therefore, the percent error is -13.5%
PLZZZ HELP CHEMISTRY QUESTION DOWN BELOW IMAGE SHOWWN BELOW
A transverse wave is observed to be moving along a lengthy rope. Adjacent crests are positioned 2.4 m apart. Exactly six crests are observed to move past a given point along the medium in 9.1 seconds. Determine the frequency of these waves
Answer:
f = 0.65 hz
Explanation:
Given that,
The distance between adjacent crests, wavelength = 2.4 m
6 crests are observed to move past a given point along the medium in 9.1 seconds.
We need to find the frequency of these waves.
We know that,
Frequency = no. of waves per second.
[tex]f=\dfrac{6}{9.1}\ Hz\\\\=0.65\ Hz[/tex]
So, the frequency of these waves is equal to 0.65 Hz.
Why are weather front boundaries turbulent?
Answer:
Answer Below Hope Its Correct.
Explanation:
A weather front is a transition zone between two different air masses at the Earth's surface. Each air mass has unique temperature and humidity characteristics. Often there is turbulence at a front, which is the borderline where two different air masses come together. The turbulence can cause clouds and storms.
Instead of causing clouds and storms, some fronts just cause a change in temperature. However, some storm fronts start Earth's largest storms. Tropical waves are fronts that develop in the tropical Atlantic Ocean off the coast of Africa. These fronts can develop into tropical storms or hurricanes if conditions allow.
Fronts move across the Earth's surface over multiple days. The direction of movement is often guided by high winds, such as Jet Streams. Landforms like mountains can also change the path of a front.
There are four different types of weather fronts: cold fronts, warm fronts, stationary fronts, and occluded fronts.
A 15.0 mL solution of Sr(OH)2 is neutralized with 29.8 mL of 0.350 M
HCI. What is the concentration of the original Sr(OH)2 solution?
Answer:
[Sr(OH)₂] = 0.699 M in Sr(OH)₂ sol'n (1 sig. fig)
Explanation:
Concentrated-1 Sr(OH)₂ = M₁ = unknown Concentration-2 HCl = M₂ = 0.350M
Volume of Concentrate = V₁ = 15ml Volume of Diluted = V₂ = 29.8ml
Using the Dilution Equation
Molarity x Volume of Concnt'd Soln = Molarity x Volume of Diluted Soln
From definition of molarity (M) = moles solute / volume of solution in Liters
=> moles solute = Molarity x Volume in liters*
*Note: if volume units are the same on both sides of the dilution equation then one may retain the volume in ml.
M₁ x V₁ = M₂ x V₂
=> 15ml · [Sr(OH)₂] = 30ml X 0.350M HCl soln
=> [Sr(OH)₂] = 29.8ml X 0.350M / 15ml = 0.695333... (calculator answer)
=> [Sr(OH)₂] = 0.7 M in Sr(OH)₂ sol'n (1 sig. fig)
__________________________________
work check:
M₁ x V₁ = M₂ x V₂
0.6953M x 15ml = 0.35M x 29.8ml
10.43 moles = 10.43 moles QED
