Answer:
Question of the Day: How do computers use input and output to get and give the information that they need to solve problems? Typing on a Keyboard (Input) Makes Letters Appear on a Screen (Output) Moving a Mouse or Touch Screen (Input) Changes What Appears on the Screen (Output)
A 500.0-mL buffer solution is 0.100 M in HNO2 and 0.150 M in KNO2. Determine if each addition would exceed the capacity of the buffer to neutralize it.
a. 250 mg NaOH
b. 350 mg KOH
c. 125 g HBr
d. 1.35g Hl
Answer:
no one additions exceed the capacity of the buffer
Explanation:
given
Volume buffer = 500.0 mL = 0.5 L
mol HNO₂ = 0.5 L × 0.100 mol/L = 0.05 mol HNO₂
mol NO₂⁻ = 0.5 L × 0.150 mol/L = 0.075 mol NO₂⁻
solution
we know when any base more than 0.05 (HNO2) than exceed buffer capacity
and when any base more than 0.075 (KNO2) than exceed buffer capacity
when we add 250 mg NaOH (0.250 g)
than molar mass NaOH =40 g/mol
and mol NaOH = 0.250 g ÷ 40g/mol
mol NaOH = 0.00625 mol
0.00625 mol NaOH will be neutralized by 0.00625 mol HNO₂
so it would not exceed the capacity of the buffer.
and
when we add 350 mg KOH (0.350 g)
than molar mass KOH =56.10 g
and mol KOH = 0.350 g ÷ 56.10 g/mol
mol KOH = 0.0062 mol
here also capacity of the buffer will not be exceeded
and
now we add 1.25 g HBr
than molar mass HBr = 80.91 g/mol
and mol HBr = 1.25 g ÷ 80.91 g/mol
mol HBr = 0.015 mol
0.015 mol Hbr will neutralize 0.015 mol NO₂⁻
so the capacity will not be exceeded.
and
we add 1.35 g HI
molar mass HI = 127.91 g/mol
so mol HI = 1.35 g ÷ 127.91 g/mol
mol HI = 0.011 mol
capacity of the buffer will not be exceed
A gas expands from 285 mL to 789 mL at constant temperature. How much work is done by the gas (joules) if it expands against a constant pressure of 6.00 atm?
Answer:
-306j
Explanation:
For this question we define an equation:
W = -Pext(Vj-Vi)-----> eqn 1
P = 6atm
Vi = 285 ml
We convert it to litre
= 285/1000 mL
= 0.285 L
Vj = 789 mL
When converted to litre
= 789/1000 mL
= 0.789 L
These values are all going to be put values in the eqn 2 above
W = -Pext(Vj-Vi)
W = -6.0x (0.789L - 0.285L)
W = -3.024
W = -3.024 x 101.33 J
This gives us the answer
W = -306 J
Thank you!
Answer: -306 J
How many atom of oxygen are in 2mole of O2
Answer:
12.044 × 10²³ atoms of oxygen
Explanation:
Given data:
Number of atoms of oxygen = ?
Moles of oxygen = 2 mol
Solution:
Avogadro number:
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms of oxygen
2 mole × 6.022 × 10²³ atoms of oxygen / 1 mole
12.044 × 10²³ atoms of oxygen
Calculate the number of C atoms in 0.716 mole of C?
Answer:
The answer is 4.31 × 10²³ C atoms
Explanation:
The number of C atoms can be found by using the formula
N = n × Lwhere n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.716 × 6.02 × 10²³
We have the final answer as
4.31 × 10²³ C atomsHope this helps you
What is a lubricant? How does it
impact the force of friction when
applied to a surface?
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL. M solution
Answer:
[tex]M_2=3.34x10^{-3}M[/tex]
Explanation:
Hello!
In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:
[tex]M_1V_1=M_2V_2[/tex]
Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:
[tex]M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M[/tex]
Best regards!
Naming inconic compounds and lots of iconic naming
if you just look up the answer it comes up btw!!
have a great day
The maximum speed limit on a highway is 55 miles per hour. What is that speed in meters per second? (mi = 1.609 km)
Answer:
24.5872 meters per second
Rouned 24.6 or 25
If a sample containing 18.1 g of NH3 is reacted with 90.4 g of
Cuo, which is the limiting reactant? How many grams of N2
will be formed?
Answer:
3.64g
Explanation:
Given parameters:
Mass of NH₃ = 18.1g
Mass of Cu₂O = 90.4g
Unknown:
Limiting reactant = ?
Mass of N₂ formed = ?
Solution:
The reaction equation is given as:
Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O
The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of Cu₂O = 2(63.6) + 16 = 143.2g/mol
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles of Cu₂O = [tex]\frac{18.1}{143.2}[/tex] = 0.13moles
Number of moles of NH₃ = [tex]\frac{90.4}{17}[/tex] = 5.32moles
From this reaction;
1 mole of Cu₂O combines with 2 mole of NH₃
So 0.13moles of Cu₂O will combine with 0.13 x 2 mole of NH₃
= 0.26moles of NH₃
Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;
Mass of N₂;
Mass = number of moles x molar mass
1 mole of Cu₂O will produce 1 mole of N₂
0.13 mole of Cu₂O will produce 0.13 mole of N₂
Mass = 0.13 x (2 x 14) = 3.64g
When comparing plant and animal cells which statement is least accurate?
Plant cells have a cell wall and animal cells do not.
Plant cells have chloroplasts and animal cells do not.
Plant cells have a large central vacuole and animal cells do not.
Plant cells have cell membranes and animal cells do not.
Which statement best explains how organ systems work together to remove wastes?
D is your answer correct.
The circulatory system carries carbon dioxide away from cells and respiratory system removes from the body. The correct option is D.
What is organ system?A group of organs that cooperate to carry out one or more functions is known as an organ system in biology. Each organ in a plant or animal body is composed of certain tissues and serves a specific purpose.
They can aid in gas exchange, waste removal, nutrient acquisition and transportation, illness sensing, and disease protection for the body.
The superior vena cava and the inferior vena cava are two significant veins that carry oxygen-poor, carbon dioxide-rich blood back to the right side of the heart.
The blood is then transported to the lungs via the pulmonary artery, where it absorbs oxygen and exhales carbon dioxide.
Thus, the correct option is D.
For more details regarding organ system, visit:
https://brainly.com/question/3507490
#SPJ2
How many chlorine atoms are there in 2 molecules of ICl?
Answer: 38 chlorine atoms are in 3 molecules of HCI
Explanation:
If an atom has 25 protons how many electrons will it have orbiting its nucleus?
ОО
O 25
O 12
Electrons don't orbit the nucleus
Answer:
If the atom is nuetral it will have 25 electrons as there is the same number of electrons and protons if the atom is nuetral. Yes electrons do orbit the nucleas. Electrons orbit in orbitals which have corresponding energy levels.
Explanation:
I have a masters in Algebra II
A very new item just arrived in the market. It is very good for construction, and other things. Now, this item has chemicals, and in every drop, there are 400 grams of NaCI. If there are 10 drops in this item, how many grams of NaCI are in one bottle?
Answer: 4,000 grams of NaCI
Explanation:
We know that there are 400g of NaCI in one drop.
This bottle has 10 drops of this item.
So, we have to multiply the amount of NaCI in a drop by the amount of drops.
400 x 10 = 4,000.
The answer to the question is 4,000. Hope this helps!
The combustion of ethane (C 2 H 6 ) produces carbon dioxide and steam.
2C 2 H 6 (g)+7O 2 (g) 4CO 2 (g)+6H 2 O(g)
How many moles of CO 2 are produced when 5.95 mol of ethane is burned in an excess of oxygen?
CO₂ produced : 11.92 moles
Further explanationReaction
2C₂H₆ (g)+7O₂ (g) ⇒4CO₂ (g)+6H₂O(g)
mol ratio C₂H₆ : CO₂ = 2 : 4
moles of CO₂ :
[tex]\tt \dfrac{4}{2}\times 5.95=11.92~moles[/tex]
The enthalpy change of reaction 1 is -114 kJ mol-1
reaction 1
2NaOH(aq) + H2SO4(aq)
→ Na2SO4(aq) + 2H2O(1)
By using this information, what is the most likely value for the enthalpy change of reaction 2?
reaction 2
Ba(OH)2(aq) + 2HCl(aq) → BaCl2(aq) + 2H2O(1)
Answer:
-114kJ mol-1
Explanation:
Definition of the enthalpy change of neutralization: the energy released with the formation of 1 mole of water when neutralization takes place between an acid and a base.
Since both reactions yield the same number of moles of water, the answer should be -114kJ mol-1.
The statement for the enthalpy change of reaction 2 is "-114 kJ"
What is enthalpy change?The change in enthalpy (ΔH) is a quantity of heat of a system. The enthalpy change is the amount of heat that enters or exits a system during a reaction.
One equivalent of hydrogen ions is neutralised with one equivalent of hydroxide ions in the reaction 1,
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
The change in enthalpy is given as -114 kJ.
Two equivalents of hydrogen ions are neutralised with two equivalents of hydroxide ions in the reaction 2,
Ba(OH)2 + H2SO4 (aq) → BaSO4 (s) + 2H2O (l)
But, that primary ionic reaction is same for both the reaction in which hydrogen ion combines with hydroxide ion to generate a water molecule. So, the enthalpy change of reaction 1 would be exactly same as for reaction 2.
The neutralization enthalpy comes out to be -114 kJ.
Hence the correct answer is -114 kJ.
Learn more about enthalpy change here
https://brainly.com/question/4526346
#SPJ2
Consider the following set of replicate measurements: Set A: 3.6 , 4.2 , 6.5 , 5.5 , 4.9 . The median is
2 points
4.2
5.2
6.5
3.6
5.5
4.9
Answer:
the median i think it is 6.5
Scientists discover remains of wooden structures near a Celtic runes site. What kind of testing will indicate when the stones were moved into place by the Celts?
Carbon dating
Radioactive dating
Answer:
Carbon
Explanation:
Bc i got this question on my test
Answer:
A. Carbon dating
Explanation:
I took the test proof
A. The chemical formula for iron (III) sulfate is Fe2(SO4)3. How many atoms of each element are present?
2 iron, 3 sulfur, 12 oxygen
3 iron, 3 sulfur, 12 oxygen
2 iron, 1 sulfur, 4 oxygen
6 iron, 3 sulfur, 12 oxygen
B.How many moles of hydrogen are in 1.8 mole(s) of quinine?
Express your answer using two significant figures.
C. How many moles of carbon are in 5.4 moles of quinine?
Express your answer using two significant figures.
D. How many moles of nitrogen are in 2.0×10−2 mole of quinine?
Express your answer using two significant figures.
Answer:
A. 2 Fe, 3 S and 12 O
B. 43 moles of H
C. 1.0×10² moles of C
Explanation:
A. Formula for iron (III) sulfate is Fe₂(SO₄)₃
This salt has 2 atoms of iron and 3 sulfates, so in total we have:
2 Fe, 3 S and 12 O
Pay attention to the subscripts
B. Formula for quinine is: C₂₀H₂₄N₂O₂
If we continue with the example before we can say that 1 mol of Iron (III) sulfate contains 2 moles of Fe, 3 moles of S and 12 moles of O
Then, 1 mol of quinine contains 24 moles of H
So 1.8 moles of quinine, may contain (1.8 . 24) /1 = 43 moles of H
C. 1 mol of quinine contains 20 moles of C
5.4 moles of quinine may contain (5.4 . 20) /1 = 1.0×10²
(As the answer must be in 2 significant figures and the real answer is 108, I had to use scientific notation)
160 g or an element with a molar mass of 40 = __ moles?
Answer:
4 moles
Explanation:
The formula of finding moles is
moles = mass / molar mass, therefore
moles = 160 g / 40 g/mol = 4 moles
i need help ):
soo.. help me ! please (:
Answer:
23 Sandwiches
6 slices of bread
0 slices of cheese
Explanation:
brainliest pls:)
Based on your lab report, provide the chemical reaction that occurs in Benedict's test for the following molecule.
Explanation:
I DONT UNDERSTAND WHAT U WANT TO SAY
b. Elements in the same period have what in common? (Look at the table)
Answer:
Elements in the same period have the same number of valence electrons as each other.
HURRY PLSsss if right gets brilliant
Answer: C hope this helps Have a wonderful day :)
Explanation:
An object with a mass of 6.3 kg has a force of 7.1 newtons applied to it. What is the resulting acceleration of the object?
Answer:
thank you for asking question
Answer:
correct the answer below is correct !!
Explanation:
Element X consist of two isotopes with masses of 62.9 and 64.9. The relative atomic mass of the element is 63.6. What is th
e percentage abundance of the lighter isotope? Show your working out.
Answer:
it is 50%
Explanation:
62.9x50=3145
64.9x50=3245
3245+3145=6390
6390/100=63.9
2. Suppose 13.7 g of C2H2 reacts with 18.5 g O2 according to the reaction below. C2H2(g) + O2(g) → CO2(g) + H2O(ℓ) a. What is the mass of CO2 produced? b. What is the limiting reagent?
Answer:
Mass of CO₂ produced = 20.328 g
Oxygen is limiting reagent.
Explanation:
Given data:
Mass of C₂H₂ = 13.7 g
Mass of O₂ = 18.5 g
Mass of CO₂ produced = ?
What is limiting reagent = ?
Solution:
Chemical equation:
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O
Number of moles of C₂H₂:
Number of moles = mass /molar mass
Number of moles = 13.7 g/ 26.04 g/mol
Number of moles = 0.526 mol
Number of moles of O₂:
Number of moles = mass /molar mass
Number of moles = 18.5 g/ 32 g/mol
Number of moles = 0.578 mol
Now we will compare the moles of CO₂ with C₂H₂ and O₂
C₂H₂ : CO₂
2 : 4
0.526 : 4/2×0.526 = 1.052
O₂ : CO₂
5 : 4
0.578 : 4/5×0.578 = 0.462
The number of moles of CO₂ produced by O₂ are less thus oxygen will be limiting reactant.
Mass of CO₂ produced:
Mass = number of moles × molar mass
Mass = 0.462 mol × 44 g/mol
Mass = 20.328 g
In an aqueous solution, a 0.100 M solution of glucose is prepared with a total volume of 0.150 Liters. If the molar mass of glucose is 180.16 g/mol how many grams must the solution contain?
Answer:
2.70 g of glucose.
Explanation:
The following data were obtained from the question:
Molarity of the glucose solution = 0.1 M
Volume of solution = 0.15 L
Molar mass of glucose = 180.16 g/mol
Mass of glucose =.?
Next, we shall determine the number of mole of glucose in the solution. This can be obtained as follow:
Molarity of the glucose solution = 0.1 M
Volume of solution = 0.15 L
Mole glucose =?
Molarity = mole /Volume
0.1 = Mole of glucose /0.15
Cross multiply
Mole of glucose = 0.1 × 0.15
Mole of glucose = 0.015 mole
Finally, we shall determine the mass of glucose in the solution as follow:
Mole of glucose = 0.015 mole
Molar mass of glucose = 180.16 g/mol
Mass of glucose =.?
Mole = mass /molar mass
0.015 = mass of glucose /180.16
Cross multiply
Mass of glucose = 0.015 × 180.16
Mass of glucose = 2.70 g
Therefore, the solution contains 2.70 g of glucose.
The grams that the solution must contain is :
- 2.70 g of glucose.
Mole ConceptGiven:
Molarity of the glucose solution = 0.1 M
Volume of solution = 0.15 L
Molar mass of glucose = 180.16 g/mole
Molarity of the glucose solution = 0.1 M
Volume of solution = 0.15 L
Molarity = mole /Volume
0.1 = Mole of glucose /0.15
Mole of glucose = 0.1 × 0.15
Mole of glucose = 0.015 mole
Mole of glucose = 0.015 mole
Molar mass of glucose = 180.16 g/mol
Mass of glucose =.?
Mole = mass /molar mass
0.015 = mass of glucose /180.16
Mass of glucose = 0.015 × 180.16
Mass of glucose = 2.70 g
The solution contains 2.70 g of glucose.
Learn more about "Mole":
https://brainly.com/question/1269011?referrer=searchResults
please help me out I need some ideas for cell city project or comic strip by tonight or if you did it already lemme copy it={
Answer:
Can you give me your snap, so I can send you the foto
Which functional group is found in an ESTER?
R
R
O=O
R
OR
O
R- OH
R-NH2
Answer:
its hydroxy and alkoxy
Explanation:
ester is mainly formed by substitution reaction of carboxylic acid and alcohol
The esters are generally produced as a result of the reaction called esterification. They are generally derived from carboxylic acids. The functional group present in ester is OR. The correct option is E.
The chemical compounds which are derived from an acid either organic or inorganic in which at least -OH ( hydroxyl group ) is replaced by an -O- alkyl group ( alkoxy ) group are called esters. Generally an ester can be represented as R - C = O - OR.
The chemical compounds that are formed by the reaction of an acid and alcohol by losing water molecule can be defined as the esters.
To know more about esters, visit;
https://brainly.com/question/30404138
#SPJ7
