How are scientific evidence and scientific conclusions related?
A.
Scientific evidence is based on scientific conclusions.

B.
Scientific conclusions are based on scientific evidence.

C.
Scientific conclusions must be made before examining scientific evidence.

D.
Scientific evidence and scientific conclusions are the same thing.

Answer:

BaCl₂·(H₂O)₂

Explanation:

The reaction that takes place is:

The information given by the problem tells us that 5.00 g of reactant were consumed. Of those 5.00 g, 4.26 g were converted into BaCl₂, this means that the other 0.74 g were converted into water.

We convert 0.74 g of water into moles, using its molar mass:

Then we convert 4.26 g of BaCl₂ into moles:

We can write these results as (BaCl₂)₀.₀₂·(H₂O)₀.₀₄. We multiply those coefficients by 50 in order to make them integers, and we're left with:

Answer:

Copper, Water, and Oxygen

Explanation:

Because they are compounds and compounds are pure substances <3

Answer: copper

Explanation: because all of the atoms that make up copper are copper i.e its not a compound or mixture. not made od molecules

Answer:

[tex]$MnO^-_4$[/tex]  is a strong oxidizing agent.

Explanation:

The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of [tex]$ReO^-_4$[/tex].

Also, since the molecular orbitals are derived primarily from  3d orbitals of [tex]$MnO^-_4$[/tex] are lower in energy than the corresponding MO's of   [tex]$ReO^-_4$[/tex], [tex]$MnO^-_4$[/tex]  is better able to accept the electrons.

So it is a better oxidizing agent.

The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.

The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.

The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.

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Answer:

[tex]Ka=\frac{[SO_3]^2}{[O_2]^3} \\\\Kb=\frac{[SO_3]^3}{[SO_2][O_2]^{1/2}}[/tex]

Explanation:

Hello!

In this case, according to the reactions:

a.) 2 S(s) 3 O2(g) ⇔ 2 SO3(g) Ka

b.) SO2(g) + 1/2 O2(g) ⇔ SO3(g) Kb

Thus, according to the law of mass action, we can write Ka and Kb as follows:

[tex]Ka=\frac{[SO_3]^2}{[O_2]^3} \\\\Kb=\frac{[SO_3]^3}{[SO_2][O_2]^{1/2}}[/tex]

Whereas solid carbon is not inserted in the equilibrium expression.

Best regards!

Answer:

3 hours

Explanation:

To know the the correct answer to the question given above, it is important we know the definition of half-life.

The half-life of a substance is simply defined as the time taken for half the substance to decay.

Considering the diagram given above, the initial mass of the substance is 100 g.

Half of the initial mass = 100 / 2 = 50 g

Now, we shall determine the time from the graph taken to get to 50 g.

Considering the diagram given above, the time taken to get to 50 g is 3 hours.

Therefore, the half-life of the material is 3 hours.

Answer:

(4) concentrated and supersaturated

Explanation:

At 50.°C, 90g of KNO3 lies above the solubility curve [on the Regents Reference Table G]. This indicates that the solution is supersaturated, meaning it contains more solute than will naturally dissolve, and was formed when a saturated solution cooled. Furthermore, the percent concentration of this solution is 90% KNO3 making this solution concentrated. This can be calculated using the formula for mass percent concentration.

Percent Mass = Mass of Solute (g) x 100

                         Mass of Solution (g)

Given solution is considered as concentrated and supersaturated.

Supersaturated solutions are those solutions in which no. of dissolved solute is more and added to the saturated solution of that solute.

In the question given that,

Weight of solute or KNO₃ = 90 g

Weight of solvent or water = 100 g

Temperature = 50°C

According to the solubility curve, given solution is supersaturated because it contains excess amount of solute and it is concentrated because solute in dissolve in the saturated solution at nearly high temperature and after cooling we get the consistent solution.

Hence, option (4) is correct i.e. given solution is concentrated and supersaturated.

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Solution :

Structure I

The formal charge on both Carbon (C) atom is = 4 valance [tex]$e^-$[/tex] - bonds = 0

Formal charge (O) = 6 V.E - 2 bonds - 4 non bonding electrons = 0

Formal charge on (N) = 5 V.E - 3 bonds - 2 non bonding electrons = 0

F.C. on H = 1 V.E. - 1 bond = 0

Overall charge on the molecule = 0 charge

Structure II

Formal charge on both C atom = 4 valence [tex]$e^-$[/tex] - 4 bonds = 0

Formal charge (O) = 6 V.E. - 1 bonds - 6 non bonding electrons = -1 charge

Formal charge on (N) = 5 V.E. - 4bonds - 0 non bonding electrons = +1 charge

F.C on H = 1 V.E. - 1 bond = 0

Overall charge on the molecule = +1 -1

                                                     = 0 charge

Answer:

Plastic is better because it doesn't melt in the microwave but aluminum burns in the microwave

Explanation:

Answer:

this some next level stuff homie

Explanation:

imma just guess 7?

The thing being described is shaped like a ring with five parts. Inside the ring, there are two special types of bonds. This has a sulfur that is positively charged and has one unshared pair, also it has an NH group with one unshared pair.

Compound B is a substance that is made up of two or more different elements or molecules.

The thing being described has a ring with six members and three pi bonds. It has an oxygen atom with an extra proton and one extra electron. This substance is not aromatic.

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Explanation:

Molar mass

96.09 g/mol

glad to help....

Answer:

60.88%

Explanation:

The balanced equation of the reaction is given as;

2 AgNO3 (aq) + BaCl2 (aq) → 2 AgCl (s) + Ba(NO3)2 (aq)

Since AgNO3 is in excess, the limiting reactant is BaCl2. From the reaction;

1 mol of BaCl2 produces 2 mol of AgCl

Converting to masses;

Mass = Number of mol * Molar mass

BaCl2;

Mass = 1 * 208.23 g/mol = 208.23 g

AgCl;

Mass = 2 * 143.32 g/mol = 286.64 g

208.23 g BaCl2 produces 286.64 g of AgCl

x g BaCl2 produces 7.123 g of AgCl

Solving for x;

x = 7.123 * 208.23 / 286.64 = 5.1745 g

Mass percent = Mass / Total mass of Mixture  * 100

Mass Percent = 5.1745 / 8.500 = 0.6088 * 100 = 60.88%

Answer:

3.0g remain

Explanation:

The half-life is defined as the time required for a reactant to decrease its concentration in exactly the half of the initial amount of reactant. Having this in mind:

In one half-life, the mass will be:

24.0g / 2 = 12.0g

In two half-lifes:

12.0g / 2 = 6.0g

And in three half-lifes, the mass that remain is:

6.0g / 2 =

Answer: [tex]K_a[/tex] for the acid is [tex]3.34\times 10^{-4}[/tex]

Explanation:

[tex]HC_9H_7O_4\rightarrow H^+C_9H_7O_4^-[/tex]

 cM              0             0

[tex]c-c\alpha[/tex]        [tex]c\alpha[/tex]          [tex]c\alpha[/tex]  

Give c = 0.328 M and [tex]pH=1.987[/tex]

[tex]1.987=-log[H^+][/tex]

[tex][H^+]=0.0103[/tex]

[tex][H^+]=c\times \alpha[/tex]

[tex]0.0103=0.328\times \alpha[/tex]

[tex]\alpha=0.0314[/tex]

So dissociation constant will be:

[tex]K_a=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]

Putting in the values we get:

[tex]K_a=\frac{(0.328\times 0.0314)^2}{(0.328-0.328\times 0.0314)}[/tex]

[tex]K_a=3.34\times 10^{-4}[/tex]

Answer:

109988 grams per second

Explanation:

To solve this problem first we convert 9503 metric tons into grams, keeping in mind that:

Meaning that:

Then we calculate how many seconds are there in one day:

Finally we calculate the consumption rate:

Answer:

The answer is option D

Explanation:

This is because Mrs. Linde resolves the conflict by committing to a new life with Krogstad, which develops the theme that new beginnings are always possible.

The conflict in this passage develops a theme, as Mrs. Linde resolves the conflict by committing to a new life with Krogstad, which develops the theme that new beginnings are always possible. Option D.

A conflict is defined as a battle or disagreement. A dispute over parenting techniques is an example of conflict, the two parties not seeing eye to eye.

In conclusion, The passages conflict develops the theme that new beginnings are always possible.

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Answer:

No pain, no gain is a proverb that means in order to make progress or to be successful, one must suffer. This suffering may be in a physical or mental sense. The phrase no pain, no gain was popularized in the 1980s by the American actress, Jane Fonda.

Answer:

A

Explanation:

has properties that are different from the original substances.

Answer:

the limiting reactant is HBr

Explanation:

if you tried to make the products using 12 mol Al and 12 mol HBr, the HBr will run out first

Answer: The molecular formula will be [tex]H_{16}NOCl[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of H = 5.80 g

Mass of N = 20.16 g

Mass of O = 23.02 g

Mass of Cl = 51.02 g

Step 1 : convert given masses into moles.

Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.80g}{1g/mole}=5.80moles[/tex]

Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{20.16g}{14g/mole}=1.44moles[/tex]

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.02g}{16g/mole}=1.44moles[/tex]

Moles of Cl =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{51.02g}{35.5g/mole}=1.44moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = [tex]\frac{5.80}{1.44}=4[/tex]

For N = [tex]\frac{1.44}{1.44}=1[/tex]

For O = [tex]\frac{1.44}{1.44}=1[/tex]

For Cl = [tex]\frac{1.44}{1.44}=1[/tex]

The ratio of H: N: O: Cl= 4: 1: 1: 1

Hence the empirical formula is [tex]H_4NOCl[/tex]

The empirical weight of [tex]H_4NOCl[/tex] = 4(1)+1(14)+ 1(16) + 1(35.5)= 69.5 g.

The molecular weight = 278 g/mole

Now we have to calculate the molecular formula.

[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{278}{69.5}=4[/tex]

The molecular formula will be=[tex]4\times H_4NOCl=H_{16}NOCl[/tex]

Answer:

In a chemical reaction, only the atoms present in the reactants can end up in the products. No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

Answer:

A log burning to ashes is a chemical change.

Explanation:

Answer:

Chemical Change

Explanation:

Burning of wood is a chemical change as new substances which cannot be changed back [e.g. carbon dioxide] are formed. For example, if wood is burned in a fireplace, there is not wood anymore but ash.

Answer:

37.7 atm

Explanation:

Using the relation;

(P + an^2/V^2) (V - nb) = nRT

(P + an^2/V^2) = nRT/(V - nb)

a = 0.0341 atm dm^2 Mol^2

b = 0.0237 dm/mol

P = nRT/(V - nb) - an^2/V^2

P = [4.3 * 0.082 * 325 / (3.6 - (4.3 * 0.0237))] - (0.0341 * (4.3^2))/(3.6^2)

P = 114.595/(3.498) - 0.0487

P = 37.7 atm

Answer:

The percent dissociation would increase

Explanation:

Percent dissociation is the ratio of amount dissociated to the initial concentration.

Decreasing the concentration of the solution leads to an increase in percent dissociation.

Answer:

[Kr] 4d10 5s2 5p4

Explanation:

The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5

However the question requested for the configuration of I+.

I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4

Using Noble gas shorthand representation, we have;

[Kr] 4d10 5s2 5p4

Explanation:

The reaction is given as;

Br2(g) + Cl2(g) ----> 2BrCl(g)

From the equation;

1 mol of Br2 reacts with 1 mol of Cl2

Converting the masses given to moles, using the formular;

Number of moles = Mass / Molar mass

Br2;

Number of moles = 33.7 g / 159.808 g/mol = 0.21088 mol

Cl2;

Number of moles = 13.0 g / 70.906 g/mol = 0.18334 mol

From the values;

0.18334 mol of Cl2 would react with 0.18334 mol of Br2 with an excess of 0.02754 mol of Br2

What is the maximum amount of bromine monochloride that can be formed? __________grams

1 mol of Cl2 produces 2 mol of Bromine Monochloride

0.18334 mol of Cl2 would produce x

Solving for x;

x = 0.18334 * 2 = 0.36668 mol

Converting to mass;

Mass = Number of moles * Molar mass = 0.36668 mol * 115.357 g/mol

Mass = 42.299 g

What is the FORMULA for the limiting reagent?

The limiting reagent is Cl2 as it determines the amount of product formed. The moment the reaction uses up Cl2, the reaction stops.

What amount of the excess reagent remains after the reaction is complete? __________grams

The excess reagent is Br2

The number of moles left is;

0.02754 mol of Br2

Converting to mass;

Mass = Number of moles * Molar mass = 0.02754 mol  * 159.808 g/mol

Mass = 4.401 g

Answer:

I would say C) Survive

An organism will survive, move or die if there is a change to its ecosystem. Therefore, option (D) is correct.

An ecosystem contains all the organisms and the physical environment with which they interact.  The biotic and abiotic components are connected together through energy flows and nutrient cycles. Energy injects into the system through photosynthesis into plant tissue.

Animals play an important role by feeding the plants in the movement of matter and energy through the system.  Decomposers release carbon back into the atmosphere and facilitate nutrient cycling by breaking down dead organic matter.

External and internal factors control the ecosystem. External factors such as climate control the overall structure of an ecosystem but are not influenced by the ecosystem. Internal factors are controlled such as decomposition, shading, root competition, disturbance, succession, and the types of species present.

The change in the ecosystem makes the organism to adapt the environment in order to survive, move to a new place or die.

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Answer:

violet

Explanation:

just violet

oh and you spelled "COLER" wrong, its color or colour if you live somewhere else

Answer:

No, you can not calculate the solubility of X in water at 17 0C.

Explanation:

Solubility refers to the amount of a substance that dissolves in 1000 L of water.

To calculate the solubility of a solute in water, all the water is evaporated and the solid is carefully collected, washed, dried and weighed. The mass of solid obtained can now be used to calculate the solubility of the solute in water as long as there was no loss in mass of solid during the experiment.

In this case, the student threw away part of the solid that precipitated. As a result of this, the mass of solid obtained at the end of the experiment is not exactly the total mass of solute that dissolved in the solvent. Hence, the solubility of X in water at 17 0C can not be accurately calculated.

Answer:

3 Ni + Fe(NO₃)₃ --> 3 Ni(NO₃) + Fe

Explanation:

In this question, the reactants are;

Solid Nickel and Iron nitrate. This is represented as;

Ni and Fe(NO3)3

The equation of the reaction is given as;

3 Ni + Fe(NO₃)₃ --> 3 Ni(NO₃) + Fe

The option that closely matches this is;

Option D. (Although the reaction is not balanced)