hlep with ixl please q.17

Answer:

Step-by-step explanation:

Geometric sequence.

Each term is obtained by multiplying 2. So, it is geometric sequence

2 = 1*2

4 = 2*2

8 = 4 *2

16 = 8 *2

Answer:

Well I'm not sure what your answer choices are but based on the question I can tell you this:

If you have 4 wood and 5 other materials then you have 9 total materials.

So if you have 4 wood then you have a 4/9 chance of choosing wood.

And you have a 5/9 chance of choosing another material

So based on that, you would be more likely to choose another material, that is not wood.

First, rewrite

[tex]\dfrac{x^2+5x+4}{x^2-3x+7} = \dfrac{(x^2-3x+7)+(8x-3)}{x^2-3x+7} = 1 + \dfrac{8x-3}{x^2-3x+7}[/tex]

Next, we have

[tex]\dfrac{x^2-3x+7}{8x-3} = \dfrac x8 - \dfrac{21}{64} + \dfrac{385}{512x-192}[/tex]

so we can further rewrite

[tex]\dfrac{x^2+5x+4}{x^2-3x+7} = 1 + \dfrac1{\frac x8 - \frac{21}{64} + \frac{385}{512x-192}}[/tex]

The idea behind all this is to get the limand into a form resembling the limit definition of the constant e, which is

[tex]\displaystyle e = \lim_{x\to\infty} \left(1+\frac1x\right)^x[/tex]

The next step is to make the substitution,

[tex]y = \dfrac x8 - \dfrac{21}{64} + \dfrac{385}{512x-192}[/tex]

Solving for x gives two solutions,

[tex]x = \dfrac{8y+3\pm\sqrt{64y^2+36y-19}}2[/tex]

but we want to have y approaching infinity, just like in the definition for e, which is achieved only by the solution with the positive square root. (You can check for yourself that the other solution instead approaches 3/4.)

So, our limit is equivalent to

[tex]\displaystyle \lim_{y\to\infty} \left(1+\frac1y\right)^{\frac{8y+3+\sqrt{64y^2+36y-19}}2}[/tex]

[tex]\displaystyle \lim_{y\to\infty} \left(1+\frac1y\right)^{\frac{8y+3+8y\sqrt{1+\frac{36}{64y}-\frac{19}{64y^2}}}2}[/tex]

[tex]\displaystyle \lim_{y\to\infty} \left(1+\frac1y\right)^{4y\left(1+\sqrt{1+\frac{36}{64y}-\frac{19}{64y^2}}\right)+\frac32}[/tex]

[tex]\displaystyle \lim_{y\to\infty} \left(\left(1+\frac1y\right)^y\right)^{4\left(1+\sqrt{1+\frac{36}{64y}-\frac{19}{64y^2}}\right)+\frac32}[/tex]

[tex]\displaystyle \lim_{y\to\infty} \left(\left(1+\frac1y\right)^y\right)^{4\left(1+\sqrt{1+\frac{36}{64y}-\frac{19}{64y^2}}\right)} \cdot \lim_{y\to\infty} \left(1+\frac1y\right)^{\frac32}[/tex]

Next, we use the fact that

[tex]\displaystyle \lim_{x\to\infty} f(x)^{g(x)} = \left( \lim_{x\to\infty}f(x)\right)^{\lim\limits_{x\to\infty}g(x)}[/tex]

Now, the "base" limit is e, while the "exponent" limit is

[tex]\displaystyle \lim_{y\to\infty} 4\left(1+\sqrt{1+\frac{36}{64y}-\frac{19}{64y^2}}\right) = 4(1+\sqrt{1+0+0}) = 8[/tex]

and the remaining limit is simply

[tex]\displaystyle \lim_{y\to\infty} \left(1+\frac1y\right)^{\frac32} = (1+0)^{\frac32} = 1[/tex]

So, we end up with

[tex]\displaystyle \lim_{x\to\infty} \left(\frac{x^2+5x+4}{x^2-3x+7}\right)^x = e^8 \cdot 1 = \boxed{e^8}[/tex]

Answer: 6 days

Step-by-step explanation:

if you make them into common denominators, it would be 6/8, so it would last 6 days

Answer:

6 days.

Step-by-step explanation:

First, make each fraction have a like denominator

3/4 × 2/2 = 6/8

Then, subtract the 1/8 for each day

6/8 - 1/8 = 5/8

You can either write this out can count how many times you do this, or since were subtracting 1/8 every time, and we have 6/8, you can see that there is enough food to feed the dog for 6 days.

Answer:

Step-by-step explanation:

you first have to find two points that pass directly through the graph in this case we have (1,4) and (4,-4)

Now we use y2-y1 divided by x2-x1

in this case -4 - 4 (y2-y1) and 4 - 1 (x2-x1)

giving you -8 and 3

so try putting -8/3 as your answer this is what i would put sorry if it is incorrect

Answer:

-5.25

Step-by-step explanation:

There are 4 tick marks between every next integer, so you know that they are counting at a value of 0.25 per tick mark. D is at negative 5 plus negative 0.25, with D's position being at -5.25

Answer:

[tex]\frac{x^2+19x-56}{4x^2-32x}[/tex]

Step-by-step explanation:

To add two fractions we need a common denominator. Just by looking at the two, there are no common factors. This means the denominator would be the product of the two: 4x(x-8). In order to obtain this, we multiply the first fraction by (x-8)/(x-8) - 1, and the second by 4x/4x - 1:

[tex]\frac{x+7}{4x} *\frac{x-8}{x-8} +\frac{5}{x-8}*\frac{4x}{4x}[/tex]

We can use the distributive property to simplify:

[tex]\frac{x^2-x-56}{4x(x-8)} +\frac{20x}{4x(x-8)}[/tex]

The sum of the two is:

[tex]\frac{x^2+19x-56}{4x^2-32x}[/tex]

Answer:

2062 4/11

Step-by-step explanation:

Okay so assuming 2003 4/11 is a mixed number, we just add:

2003 4/11 + 59 = 2062 4/11

Hope this helps:)

Answer:

2556 feet squared

Step-by-step explanation:

Area is calculated by multiplying length times width. 71x36=2556

Answer:

Step-by-step explanation:

This is an isosceles triangle, since XY and ZY are the same length. That means by the Isosceles Triangle Theorem, angle X and angle Z are congruent. Since the measures of a triangle by the Triangle Angle-Sum Theorem have to add up to equal 180 degrees, then angle Y, the vertex angle, measures

180 - 34 - 34 which is 112, choice A.

the answer is A. 112 hope this helps

Answer:

1,200

Step-by-step explanation:

3x2=6 and 6x200=1,200

Answer:

mn

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let x be the number of hours worked

Let C = the charge made by the first company

Let c  = the charge made by the second company

You want to know when the costs will be =.

Equations

C = 376 + 12x

c = 280 + 15x

Solution

Make the two right sides equal

376 + 12x = 280 + 15x            Subtract 12x from both sides

376 = 280 + 15x - 12x             Combine like terms on the right

376 = 280 + 3x                       Subtract 280 from both sides

376 - 280 = 3x                        Combine

96 = 3x                                    Divide both sides by 3

32 = x

Each company would have to work 32 hours to get the same amount to be charged.

C = 376 + 12x

C = 376 + 12*32

C = 376 + 384

C = 760

The amount each would charge is 760

9514 1404 393

Answer:

Step-by-step explanation:

The translation of a parent function f(x) by (h, k) gives the function ...

  g(x) = f(x -h) +k . . . . . h units right, k units up

Reflection across the x-axis multiplies the function value by -1.

__

a) The square root function is translated 4 left and 2 down. The equation of the graph is ...

  y = √(x +4) -2

__

b) The equation of the parabola is reflected across the x-axis and translated right 2 and down 3.

  y = -(x -2)^2 -3

Answer:

2 hours 6 minutes

Step-by-step explanation:

40% of 315 is 126 [miles]

126 miles = 126 minutes, since he went at 60 miles per hour [one mile per minute]

126 minutes = 2 hours 6 minutes

So, 2 hours 6 minutes, or 126 minutes.

Answer:

it's a negative answer Because there's one negative and one positive and if there are your two negatives that makes a positive and it's also the same with two positives

Answer:

-0.9³

Step-by-step explanation:

that's the answer hope it helps

Answer:

(-0.9)×(-0.9)×(-0.9)

(-0.9)^3

Answer:

[tex]y = \frac{4}{3} x - 4[/tex]

Hope it helped:)

Answer:

Recipes 1 and 3 will make the same amount

Step-by-step explanation:

In pictures answered .

Answer:

  $13,259.30

Step-by-step explanation:

The account balance with compound interest is ...

  A = P(1 +r/n)^(nt)

  A = $12,000(1 +0.05/12)^(12·2) ≈ $13,259.30 . . . . will be owed in 2 years

__

It's a straight compound interest problem. "No payments for 2 years" means the account continues to accrue compounded interest. It's basically a future-value problem, as opposed to an amortization or annuity problem where payments are involved.

Answer:

It is 15 but I don't know what the steps are since I took a test on this question and failed to get the right answer.

Answer:

For 9., the answer is x = -6

For 10., the answer is x = 6

For 11., the answer is x = -7

For 12., the answer is x = -6

Hello! The missing number is -1.

Notice that we add 1 every time:

-3+1=-2

-2+1=-1

-1+1=0

Hope this helps!

~Just a felicitous girlie

#HaveAnAwesomeDay

[tex]SilentNature :)[/tex]