Henry sends his hawk with a message to his uncle. The hawk flies out against the wind and returns with the wind, spending 3 hours on the whole trip. How far is Henry's uncle from Henry if the speed of the wind is 5 mph, and the hawk flies 50 mph in quiet weather?

Answer:

Distance between Henry and his uncle is 74.25km.

Step-by-step explanation:

Speed of Hawk with wind = 50+5

                                           =55km/hr

Speed of Hawk against wind = 50-5

                                               =45km/hr

we know that ,

        [tex]Distance = speed \times time[/tex]

Let the distance between Henry and uncle is d,

According to the question ,

[tex]\frac{d}{55} + \frac{d}{45} = 3[/tex]

[tex]\frac{9d + 11d}{495} =3[/tex]

[tex]20d = 3\times 495[/tex]

[tex]d =\frac{3\times495}{20}[/tex]

d= 74.25km

Hence , the answer is 74.25km

The relation between speed, time, and distance is used. Then the distance between Henry's uncle from Henry is 74.25 miles.

The distance covered in an hour is called speed. it is a scalar quantity.

The concept of relative speed is used when two or more bodies moving with some speed are considered.

Henry sends his hawk with a message to his uncle.

The hawk flies out against the wind and returns with the wind, spending 3 hours on the whole trip.

We know the relation

[tex]\rm speed = \dfrac{distance }{time}[/tex]

Let the distance between Henry's uncle from Henry be x.

The time of the trip is during the traveling remains constant. That is

[tex]\rm T = T_1 + T_2\\\\T = \dfrac{x}{v_1} + \dfrac{x}{v_2}[/tex]

The speed of the wind is 5 mph, and the hawk flies 50 mph in quiet weather. Then we have

[tex]\rm v_1 = 50 - 5 = 45\\\\v_2 = 50 + 5 = 55[/tex]

Then

[tex]\begin{aligned} \rm \dfrac{x}{45} + \dfrac{x}{55} &= 3\\\\\rm \dfrac{9x + 11x }{495} &= 3\\\\\rm 9x + 11x &= 1485\\\\\rm 20x &= 1485\\\\\rm x &= 74.25 \end{aligned}[/tex]

Thus, the distance between Henry's uncle from Henry is 74.25 miles.

More about the speed link is given below.

https://brainly.com/question/862972

According to a study published in the New England Journal of Medicine, overweight people on low-carbohydrate and Mediterranean diets lost more weight and got greater cardiovascular benefits than people on a conventional low-fat diet (The Boston Globe, July 17, 2008). A nutritionist wishes to verify these results and follows 30 dieters on the low-carbohydrate and Mediterranean diets and 30 dieters on the low-fat diet. These data (measured in pounds) can be found on the text website, labeled Different Diets. Let Low-carb or Mediterranean and Low-fat diets represent populations 1 and 2, respectively. Use Table 2.
Low-carb Low-carb/
Mediterrean Diets Low- Fat diet Mediterreand diet Low-fat Diet
9.5 6.5 6.8 5.9
8.1 5.8 9.1 6.9
10.4 9.9 9.4 9.1
11.9 5.1 10.2 8.0
11.8 8.0 9.5 8.9
12.6 6.3 9.5 3.4
6.7 6.3 9.4 4.6
9.6 4.4 12.0 6.2
11.6 5.7 9.9 4.6
8.4 5.9 9.7 6.7
9.0 6.8 9.2 4.6
7.5 5.1 13.0 7.1
7.2 6.3 11.3 11.0
8.5 5.5 13.6 4.5
8.8 5.5 9.0 3.9
a.Set up the hypotheses to test the claim that the mean weight loss for those on low-carbohydrate or Mediterranean diets is greater than the mean weight loss for those on a conventional low-fat diet.
H0: ?1 ? ?2 ? 0; HA: ?1 ? ?2 > 0
H0: ?1 ? ?2 = 0; HA: ?1 ? ?2 ? 0
H0: ?1 ? ?2 ? 0; HA: ?1 ? ?2 < 0
b-1.Using the appropriate commands in Excel, find the value of the test statistic. Assume that the population variances are equal and that the test is conducted at the 5% significance level. (Round your answer to 2 decimal places.)
Test statistic
b-2. What is the critical value and the rejection rule?
Reject H0 if tdf < -1.672.
Reject H0 if tdf < -2.002.
Reject H0 if tdf > 2.002.
Reject H0 if tdf > 1.672.
c. At the 5% significance level, can the nutritionist conclude that overweight people on low-carbohydrate or Mediterranean diets lost more weight than people on a conventional low-fat diet?
No
Yes
Low-carb/Mediterrean Diets Low-fat Diet
9.5 6.5
8.1 5.8
10.4 9.9
11.9 5.1
11.8 8
12.6 6.3
6.7 6.3
9.6 4.4
11.6 5.7
8.4 5.9
9 6.8
7.5 5.1
7.2 6.3
8.5 5.5
8.8 5.5
6.8 5.9
9.1 6.9
9.4 9.1
10. 2 8
9.5 8.9
9.5 3.4
9.4 4.6
12 6.2
9.9 4.6
9.7 6.7
9.2 4.6
13 7.1
11.3 11
13.6 4.5
9 3.9

If a =3.6 and b=10 then ab=

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