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the high school concert choir has 7 boys and 15 girls. the teacher needs to pick three soloists for the next concert but all of the members are so good she decides to randomly select the three students for the solos.
a) in how many ways can the teacher select the 3 students?
b) what is the probability that all three students selected are girls
c) what is the probability that at least one boy is selected?

Let's simplify the expression step by step:

25xy * sqrt(81/625 * x^2 * y^2)

= 25xy * (sqrt(81)/sqrt(625) * sqrt(x^2) / sqrt(y^2))

= 25xy * (9/25 * x/y)

= 9xy * 5/5

= 9xy

Therefore, the simplified form of the expression 25xy * sqrt(81/625 x^2y ^2) is option C, 9xy|xy|.

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The value of angle 5 and angle 8 will be 118° and 62° respectively.

Parallel lines are lines that are always the same distance apart and never intersect. In other words, they have the same slope and will never meet or cross each other. The symbol for parallel is ||.

For example, in the Cartesian coordinate system, the equation of a straight line is represented as y = mx + b, where m is the slope of the line and b is the y-intercept. If two lines have the same slope, they are parallel.

The value of angle 5 will be 118. Angle 8 will be:

= 180 - 118

= 62°

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Answer:

To find the face value (p) of the note, we need to use the formula for simple interest:

I = P * r * t

where:

I = interest

P = principal or face value

r = interest rate per year

t = time in years

Since the note has a 6% interest rate and a 150-day term, we need to convert the time to years:

t = 150 / 365

t = 0.41096 years

Now we can solve for the face value:

I = P * r * t

2550 = P * 0.06 * 0.41096

2550 = 0.0246576P

P = 2550 / 0.0246576

P = 103364.99

So the face value (p) of the note is $103,364.99.

To find the interest (i), we can subtract the face value from the balloon payment:

i = 2550 - 103364.99

i = -100814.99

The negative interest result may seem strange, but it's because the balloon payment was higher than the face value of the note. In other words, Averi paid more than the note was worth in order to fully pay off the principal and interest.

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The slope of the line that is represented by the given data in the question is 3/4.

To find the slope of a line, we need to use the formula:

slope = (change in y) / (change in x)

We can choose any two points on the line and use their coordinates to calculate the change in y and the change in x. Let's choose the points (-9, 4) and (7, 16) from the given data.

Change in y = 16 - 4 = 12

Change in x = 7 - (-9) = 16

Plugging these values into the slope formula, we get:

slope = 12 / 16 = 3 / 4

We can also interpret this slope as the rate of change of y with respect to x. For every increase of 1 in x, y increases by 3/4. Similarly, for every decrease of 1 in x, y decreases by 3/4.

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Answer:

Step-by-step explanation:

we can use the laws of exponents, which state that when multiplying terms with the same base, we add their exponents. In this case,both terms have a base of 8, so we can add their exponents of 2/7 and 1/4.

First, let's write 8 as a power of 2: 8 = 2^3. Then we can rewrite the original expression as (2^3)^(2/7) * (2^3)^(1/4). Using the power of a power rule, we can simplify this to 2^(3 * 2/7) * 2^(3 * 1/4).

Next, we can simplify the exponents by finding a common denominator. The smallest common multiple of 7 and 4 is 28, so we can rewrite the exponents as 6/28 and 21/28, respectively. Thus, we have 2^(3 * 6/28) * 2^(3 * 21/28).

Now we can simplify the exponents by multiplying the bases and exponents separately: 2^(18/28) * 2^(63/28). We can simplify the fractions by dividing both the numerator and denominator by 2, giving us 2^(9/14) * 2^(63/28).

Finally, we can add the exponents since we are multiplying terms with the same base: 2^(9/14 + 63/28). We can simplify the exponent by finding a common denominator of 28,

giving us 2^(36/28 + 63/28) = 2^(99/28). This is our final answer, which is an irrational number that is approximately equal to 69.887.

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The cost to alter each dress is $25 and each suit is $30 based on the given set of relations.

Let us represent the dresses as x and suit as y. Forming the equation for both customers.

Cost of one dress × number of dress +

Cost of one suit × number of suit = total cost

2x + y = 80 : equation 1

x + 3y = 115 : equation 2

Multiply equation with 1

6x + 3y = 240 : equation 3

Subtract equation 2 from equation 3

6x + 3y = 240

- x + 3y = 115

5x = 125

x = 125/5

x = $25

Keep the value of x in equation 2 to find the value of y

25 + 3y = 115

3y = 115 - 25

3y = 90

y = 90/3

y = $30

Hence, the altering cost of each is $25 and $30.

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The complete question is -

A tailor charges set amounts for alterations on dresses and suits. One customer has 2 dresses and 1 suit altered for a total of $80. Another customer has 1 dress and 3 suits altered for a total of $115. How much does it cost to alter each dress?

The expressions represent the same cost after the discount of 40%.

How to show that the two expressions 295 - 295(0.40) and 295(1 - 0.40) represent the same cost after the discount?

To show that the two expressions 295 - 295(0.40) and 295(1 - 0.40) represent the same cost after the discount, we can use the distributive property of multiplication over addition or subtraction.

The distributive property states that for any real numbers a, b, and c:

a(b + c) = ab + ac

a(b - c) = ab - ac

So, we can apply the distributive property as follows:

295 - 295(0.40)

= 295(1) - 295(0.40) [Multiplying 295 by 1]

= 295(1 - 0.40) [Using the distributive property]

Therefore, both expressions represent the same cost after the discount of 40%.

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The driver could have traveled up to 5 miles for the delivery.

Let's denote the number of miles the driver traveled by "m".

According to the problem, the delivery service charged $1.25 for the delivery itself, and $0.75 for each mile traveled. This can be written as:

Total cost = $1.25 + $0.75 * m

We know that the service charged the customer $5.75, so we can set up an equation:

$5.75 = $1.25 + $0.75 * m

Solving for m, we get:

[tex]m = ($5.75 - $1.25) / $0.75 = 5[/tex]

To represent this on a number line, we can draw a line labeled from 0 to 5, with tick marks at each integer value.

We can label the tick mark at 0 as "0 miles" and the tick mark at 5 as "5 miles".

We can also indicate that the cost of the delivery increases as we move to the right by drawing an arrow pointing to the right, and labeling it "increasing cost".

Here's an example of what the number line might look like:

                   0         1         2         3         4         5

                    |---------|---------|---------|---------|---------|

                    0 miles                                            5 miles

                    increasing cost  ⟶

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Using the linear model, we can predict that a 100 mg dose of the experimental drug would cause a change in the patient's blood pressure of 540 mmHg.

An equation is a mathematical statement that expresses the equality of two expressions. It consists of two expressions, one on the left side and one on the right side, which are connected by an equals sign (=). Equations are fundamental to mathematics, and are used to solve many problems. In addition, equations can also be used to describe physical laws, such as Newton's law of gravity.

10 + 2(20) + 3(30) + 4(100)

= 10 + 40 + 90 + 400

= 540 mmHg

The linear model suggests that a 100 mg dose of the experimental drug would cause a change in the patient's blood pressure of 540 mmHg. This can be seen by using the linear equation 10 + 2x + 3x + 4x. Here, the first coefficient of 10 represents the change in blood pressure for a 10 mg dose, the second coefficient of 2 represents the change in blood pressure for each additional 10 mg dose, the third coefficient of 3 represents the change in blood pressure for each additional 20 mg dose, and the fourth coefficient of 4 represents the change in blood pressure for each additional 30 mg dose.

For example, if the patient was given a 40 mg dose, the equation would be 10 + 2(20) + 3(30), which would yield a change in blood pressure of 140 mmHg. Similarly, if the patient was given a 50 mg dose, the equation would be 10 + 2(20) + 3(30) + 4(10), which would yield a change in blood pressure of 190 mmHg.

Therefore, using the linear model, we can predict that a 100 mg dose of the experimental drug would cause a change in the patient's blood pressure of 540 mmHg.

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The linear model predicts that a 100 mg dose of the investigational drug will raise the patient's heart rate by 540 mmHg.

A mathematical statement that expresses the equality of two expressions is known as an equation. It comprises of two expressions that are joined together by the equals sign (=), one on the left side and one on the right. Equations are essential to mathematics and are frequently used to resolve issues. Moreover, equations can be utilised to explain natural laws like Newton's law of gravity.

10 + 2(20) + 3(30) + 4(100)

= 10 + 40 + 90 + 400

= 540 mmHg

The linear model predicts that a 100 mg dose of the investigational drug will raise the patient's heart rate by 540 mmHg.

Using the linear equation 10 + 2x + 3x + 4x, this may be observed. In this case, the first coefficient of 10 denotes the change in blood pressure for a dose of 10 mg, the second coefficient of 2, the change for each additional dose of 10 mg, the third coefficient of 3, the change for each additional dose of 20 mg, and the fourth coefficient, the change for each additional dose of 30 mg.

For instance, if the patient received a dose of 40 mg, the equation would be 10 + 2(20) + 3(30), resulting in a 140 mmHg change in blood pressure. The calculation would be 10 + 2(20) + 3(30) + 4(10) if the patient received a 50 mg dose, which would result in a 190 mmHg change in blood pressure.

As a result, we can infer from the linear model that a 100 mg dose of the experimental medication would result in a 540 mmHg change in the patient's blood pressure.

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The largest two digit number that is divisible by both 6 and 8 that is Dexter's number is equals to the ninty-six.

Two digit numbers : 2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99. They cannot start from zero. We have specify that Mr. Phil asks his students to determine the largest 2 -digit number that is divisible by both 6 and 8. Let the dexter's two digit number be 'x'.

From the above list of 11 numbers the largest number that is multiple of 2 and 3 both. That is 96. So, the students answer is 91. The answer of one of his student is less than 5 the correct number. Hence, required value is 96.

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The temperature of City A and City B on that day was 4°C and 3°C respectively.

Let x represent the temperature of city A and y represent the temperature of city B.

Four times the temperature of City A was 7° C more than three times the temperature of City B, hence:

4x = 3y + 7

4x - 3y = 7       (1)

The temperature of City A minus three times the temperature of City B was −5° C, hence:

x - 3y = -5        (2)

From both equations, solving simultaneously:

x = 4, y = 3.

The temperature of City A and City B on that day was 4°C and 3°C respectively.

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Answer:

[tex] \sqrt{ \frac{2}{3} } + \sqrt{6} \\ = \frac{ \sqrt{2} }{ \sqrt{3} } + \sqrt{6} \\ = \frac{ \sqrt{2} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } + \sqrt{6} \\ = \frac{ \sqrt{6} }{3} + \sqrt{6} \\ = \frac{ \sqrt{6} }{3} + \frac{3 \sqrt{6} }{3} \\ = \frac{ 4\sqrt{6} }{3} [/tex]

Using the conditional probability, the value of P(A|B)P(A∣B), rounding to the nearest thousandth, is 0.758

To find P(A|B), we use the formula:

P(A|B) = P(A and B) / P(B)

Substituting the given values, we get:

P(A|B) = 0.652 / 0.86

P(A|B) = 0.758

Rounding to the nearest thousandth, we get:

P(A|B) = 0.758

Alternatively, to find the value of P(A|B), we can use the conditional probability formula:

P(A|B) = P(A and B) / P(B)

Given the values in your question, we have:
P(A and B) = 0.652
P(B) = 0.86

Now we can plug these values into the formula:

P(A|B) = 0.652 / 0.86 = 0.7575

Rounding to the nearest thousandth, the value of P(A|B) is approximately 0.758.

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A. The proportion we can set up is: c/a = d/b, and B. x = (c * b) / a. This gives us the value of x in terms of the lengths of the other segments.

A) The corresponding sides in similar triangles are proportional, so we can use this fact to set up a proportion between the sides of triangles BED and BCA. Let's call the length of segment BC "a", the length of segment AC "b", the length of segment BE "c", and the length of segment DE "d".
The proportion we can set up is:
c/a = d/b
This is because we know that triangle BED is similar to triangle BCA, so the ratio of the lengths of their corresponding sides must be the same.

B) We can now use the proportion to solve for x, which is the length of segment DE. We can start by cross-multiplying the proportion:
c * b = d * a
Then, we can isolate for x by dividing both sides by the coefficient of x:
x = (c * b) / a
This gives us the value of x in terms of the lengths of the other segments.

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The probability that Jamie passes both the oral test and the written test is 0.5168, or 51.68%.

To find the probability that Jamie passes both the oral test and the written test, we can use the conditional probability formula: P(A and B) = P(A|B) * P(B), where A represents passing the oral test and B represents passing the written test.

From the given information:
- The probability of passing the oral test, P(A), is 0.56.
- The probability of passing the written test, P(B), is 0.68.
- The probability of passing the oral test, given that the candidate passes the written test, P(A|B), is 0.76.

Now, using the conditional probability formula:
P(A and B) = P(A|B) * P(B)
P(A and B) = 0.76 * 0.68

Calculating the product:
P(A and B) = 0.5168

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There are approximately 5500 dimes in the jar. A) 5.5 x 103 dimes.

To determine the number of dimes in the jar, we can divide the total mass of the dimes by the mass of each dime.

Total mass of dimes = 1.265 x 10 grams

Mass of each dime = 2.3 grams

Let "x" be the number of dimes in the jar. Then, we can set up the following equation:

x(2.3 grams) = 1.265 x 10 grams

Simplifying this equation, we get:

x = 1.265 x 10 / 2.3

x ≈ 5500

It is important to that this calculation assumes that all dimes have the same mass, and that there are no other objects in the jar.

the actual number of dimes may vary slightly due to measurement error or variability in the mass of each dime.

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Step-by-step explanation:

Expressions are collection of algebric equetion and equal sighn and used for expresion of mankind problems like items, money and other mankind problem.

to know length by using degree but most of the time for the archtechture. soon

Answer:

x=137

Step-by-step explanation:

sqrt(x+7)=12

x+7=144

x=137

The limit of A. x^(2^x) as x approaches 0 is 1, and the limit of B. 2^x - 1 as x approaches 0 is ln 2.

A. To find the limit of A. x^(2^x) as x approaches 0, we can take the natural logarithm of both sides and use the fact that ln(1 + a) is approximately equal to a for small values of a. This gives us:

ln(A. x^(2^x)) = 2^x ln x

ln(A. x^(2^x)) / ln x = 2^x

Taking the limit as x approaches 0, the right-hand side goes to 1, and using the continuity of the natural logarithm, we have:

ln(A) = 0

A = 1

Therefore, the limit of A. x^(2^x) as x approaches 0 is 1.

B. To find the limit of B. 2^x - 1 as x approaches 0, we can use L'Hopital's Rule:

lim x→0 (2^x - 1)

= lim x→0 (ln 2 * 2^x / ln 2)

= ln 2 * lim x→0 (2^x / ln 2)

= ln 2 * (lim x→0 e^(x ln 2) / ln 2)

= ln 2 * (lim x→0 e^(x ln 2 - ln 2) / (ln 2 - ln 2))

= ln 2 * (lim x→0 e^(ln 2 * (x - 1)) / 1)

= ln 2 * e^0

= ln 2

Therefore, the limit of B. 2^x - 1 as x approaches 0 is ln 2.

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1. Congruent triangles:
a) Triangle EAB and Triangle ECD
b) Triangle EAC and Triangle EBD

2. Triangle EAB ≅ Triangle ECD and Triangle EAC ≅ Triangle EBD by ASA Congruence Postulate.

In this scenario, we have two concentric circles and four tangents drawn from point E to these circles, creating points of tangency A, B, C, and D.

1. Pairs of congruent triangles:
a) Triangle EAB and Triangle ECD
b) Triangle EAC and Triangle EBD

2. Showing congruence for each pair:

a) To show that Triangle EAB and Triangle ECD are congruent, we can use the following information:
- EA and EC are both radii of the larger circle, so EA = EC (congruent radii).
- AB and CD are tangents to the smaller circle, so the segments are parallel and form corresponding angles at points A and C. Thus, Angle EAB and Angle ECD are congruent (alternate interior angles).
- EB and ED are both radii of the smaller circle, so EB = ED (congruent radii).
With this information, we can prove Triangle EAB ≅ Triangle ECD using the Angle-Side-Angle (ASA) Congruence Postulate.

b) To show that Triangle EAC and Triangle EBD are congruent, we can use the following information:
- EA and EB are both radii of the larger circle, so EA = EB (congruent radii).
- AC and BD are tangents to the larger circle, so the segments are parallel and form corresponding angles at points A and B. Thus, Angle EAC and Angle EBD are congruent (alternate interior angles).
- EC and ED are both radii of the smaller circle, so EC = ED (congruent radii).
With this information, we can prove Triangle EAC ≅ Triangle EBD using the Angle-Side-Angle (ASA) Congruence Postulate.

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The equation that can be used to determine the number of people (x) who can go to the amusement park is:

207.50 = 5 + (33.75 × x).

To determine the number of people (x) who can go to the amusement park, we need to create an equation using the given information. We know that they have $207.50 to spend, parking costs $5, and each ticket costs $33.75 per person (including tax).

We can represent the total cost of the trip as the sum of the cost for parking and the cost of the tickets for x number of people. The equation would be:

Total Cost = Cost of Parking + (Cost of Tickets per Person × Number of People)

Since we know the total cost is $207.50, the cost of parking is $5, and the cost of tickets per person is $33.75, we can plug in these values:

207.50 = 5 + (33.75 × x)

This equation can be used to determine the value of the variable x, the number of people who can go to the amusement park. To find the value of x, simply solve the equation by isolating the variable x.

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According to the given standard deviation, the engineer would need a sample size of at least 75 wires to estimate the mean length to within 0.025 feet with 99% confidence.

To estimate the mean length of the wires being cut, the engineer needs to determine the sample size needed to achieve a certain level of confidence and level of precision. In this case, the engineer wants to estimate the mean length to within 0.025 feet with 99% confidence. This means that there is a 99% chance that the true population mean falls within the estimated range.

To determine the sample size needed, the engineer can use a formula that takes into account the desired level of confidence, level of precision, and the standard deviation of the population. The formula is:

n = (z² x s²) / E²

Where:

n = sample size needed

z = z-score for desired level of confidence (99% = 2.58)

s = standard deviation of the population (0.15 feet)

E = level of precision (0.025 feet)

Plugging in the values, we get:

n = (2.58² x 0.15²) / 0.025²

n = 74.83 ≈ 75

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The bank needs to buy and sell 20,000 dollars.

To calculate the amount of American dollars that should be bought and sold by the bank to earn a profit of Rs 9000, we first need to determine the exchange rate difference between the buying and selling rates:

Exchange rate difference = selling rate - buying rate

Exchange rate difference = Rs 117.30 - Rs 116.85

Exchange rate difference = Rs 0.45

This means that for every dollar bought and sold by the bank, there is a difference of Rs 0.45. To earn a profit of Rs 9000, we need to find out how many dollars the bank needs to buy and sell to make this amount of profit.

Let X be the amount of American dollars the bank needs to buy and sell to earn a profit of Rs 9000.

Profit = Exchange rate difference × X

Rs 9000 = Rs 0.45 × X

To calculate the amount of American dollars that should be bought and sold by the bank to earn a profit of Rs 9000, we first need to determine the exchange rate difference between the buying and selling rates:

Exchange rate difference = selling rate - buying rate

Exchange rate difference = Rs 117.30 - Rs 116.85

Exchange rate difference = Rs 0.45

This means that for every dollar bought and sold by the bank, there is a difference of Rs 0.45. To earn a profit of Rs 9000, we need to find out how many dollars the bank needs to buy and sell to make this amount of profit.

Let X be the amount of American dollars the bank needs to buy and sell to earn a profit of Rs 9000.

Profit = Exchange rate difference × X

Rs 9000 = Rs 0.45 × X

To solve for X, we can divide both sides by 0.45:

X = Rs 9000 ÷ Rs 0.45

X = 20,000

Therefore, the bank needs to buy and sell 20,000 American dollars to earn a profit of Rs 9000.

To calculate the amount of American dollars the bank needs to buy and sell, we first need to determine the exchange rate difference between the buying and selling rates. This is done by subtracting the buying rate from the selling rate. The resulting exchange rate difference gives us the profit the bank earns for every dollar bought and sold.

Next, we use the exchange rate difference to calculate the amount of American dollars needed to earn a profit of Rs 9000. We set up an equation where the profit is equal to the exchange rate difference multiplied by the amount of American dollars bought and sold. We solve for X, which represents the amount of American dollars needed to earn the profit of Rs [tex]9000.[/tex]

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The given ordered pairs (4, 0.5), (2.5, 4.5), (0.5,3), and (2, 0) are plotted on the coordinate plane as shown in the graph below.

From the question, we are to plot the given ordered pairs on the coordinate plane

To plot the given ordered pairs, we will determine the location of the point on the coordinate plane

We will look at the first number in the ordered pair (the x-coordinate) and find that value on the x-axis. Also, we will look at the second number (the y-coordinate) and find that value on the y-axis.

Now, we will plot the point where the x-coordinate and y-coordinate intersect. The point is represented by a dot.

The ordered pairs are plotted on the coordinate plane as shown in the graph below.

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Without a specific set of scatterplots to examine, I can provide some general guidelines for labeling scatterplots based on their association:

1. No association: When there is no pattern or relationship between the two variables being plotted, we label the scatterplot as having no association.

2. Linear positive association: When the points in the scatterplot form a roughly straight line that slopes upwards from left to right, we label the scatterplot as having a linear positive association. This means that as the value of one variable increases, the value of the other variable also tends to increase.

3. Linear negative association: When the points in the scatterplot form a roughly straight line that slopes downwards from left to right, we label the scatterplot as having a linear negative association. This means that as the value of one variable increases, the value of the other variable tends to decrease.

4. Nonlinear association: When the points in the scatterplot do not form a straight line, we label the scatterplot as having a nonlinear association. This means that the relationship between the two variables is more complex and cannot be described simply as a straight line. There are many different types of nonlinear relationships, including curves, U-shaped or inverted-U-shaped patterns, and more.

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To simplify the expressions and arrange the terms by their degree, we can write:

$\longrightarrow\sf\textbf\:f(x)\:= -x^4\:+\:2x^2\:-\:5x\:+\:3$

$\longrightarrow\sf\textbf\:=\:-x^4 + 2x^2 - x - 4x + 3$

$\longrightarrow\sf\textbf\:=\:-x(x^3 - 2x + 1) - 4x + 3$

$\longrightarrow\sf\textbf\:g(x)\:=\:x^4 + 4x^2 + 2x + 1$

$\longrightarrow\sf\textbf\:x^4 + 4x^2 + 2x + 1 - 2 + 2$

$\longrightarrow\sf\textbf\:x^4 + 4x^2 + 2x - 1 + 2$

$\longrightarrow\sf\textbf\:x^4 + 4x^2 + 2x - 1 + 2$

$\longrightarrow\sf\textbf\:x^4 + 4x^2 + 2x + 1 - 2$

$\longrightarrow\sf\textbf\:(x^2 + 1)^2 - 2$

Therefore, we can express the simplified forms of ${\sf{\textbf{f(x)}}}$ and ${\sf{\textbf{g(x)}}}$ as:

$\longrightarrow\sf\textbf\:f(x)\:=\:-x(x^3 - 2x + 1) - 4x + 3$

$\longrightarrow\sf\textbf\:g(x)\:=\:(x^2 + 1)^2 - 2$

[tex]\huge{\colorbox{black}{\textcolor{lime}{\textsf{\textbf{I\:hope\:this\:helps\:!}}}}}[/tex]

[tex]\begin{align}\colorbox{black}{\textcolor{white}{\underline{\underline{\sf{Please\: mark\: as\: brillinest !}}}}}\end{align}[/tex]

[tex]\textcolor{blue}{\small\textit{If you have any further questions, feel free to ask!}}[/tex]

[tex]{\bigstar{\underline{\boxed{\sf{\textbf{\color{red}{Sumit\:Roy}}}}}}}\\[/tex]

Yes, Mark is correct he believes that doubling one of the dimensions would double the volume of his toolbox.

Volume refers to the space occupied by a 3-Dimensional space. The volume of a cuboid is given by:

V = l * b * h

where l is the length

b is the breadth

h is the height

V = 9 * 6 * 7

= 378 cubic inches

If we double any of the dimensions, like

By doubling the 9 we get

V = 18 * 6 * 7

= 756 cubic inches

By doubling the 6 we get

V = 9 * 12 * 7

= 756 cubic inches

By doubling the 7 we get

V = 9 * 6 * 14

= 756 cubic inches

Then the volume of the toolbox is doubled as shown above.

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The theoretical probability of rolling a one or two on a number cube is 2/5 or 0.4.

To find the theoretical probability of rolling a one or two on a number cube, we need to determine the number of outcomes that correspond to rolling a one or two, and divide that by the total number of possible outcomes.

From the table, we can see that Alexandria rolled a one or two a total of 24 times out of 60 rolls. This means that the probability of rolling a one or two is: P(1 or 2) = 24/60

Simplifying the fraction by dividing both the numerator and denominator by the greatest common factor, we get: P(1 or 2) = 4/10

This can be further reduced to: P(1 or 2) = 2/5

Therefore, the theoretical probability of rolling a one or two on a number cube is 2/5 or 0.4.

In summary, the theoretical probability is the expected probability of an event occurring, based on mathematical reasoning. Here, we used the number of favorable outcomes to calculate the probability of rolling a one or two, and expressed the answer as a fraction in simplest form.

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Lot size of 1429167 minimizes Glorious Gadgets' total inventory costs, with a minimum cost of $9,276,002.

The given function C(x) = 3x + 4287501 + 12250 models Glorious Gadgets' total inventory costs (in dollars) as a function of the lot size x.

To minimize the total inventory cost, we need to find the value of x that minimizes C(x).

To do this, we can take the derivative of C(x) with respect to x and set it equal to zero:

C'(x) = 3

Setting C'(x) = 0, we get:

3 = 0

This is not possible, which means that C(x) has no local minimum or maximum.

Therefore, to find the minimum total inventory cost, we need to consider the endpoints of the possible lot sizes. Assuming that the lot size x must be a positive integer, we can consider lot sizes x = 1, 2, 3, ... , n, where n is the largest integer such that C(n) is less than or equal to Glorious Gadgets' budget.

We can calculate the total inventory cost for each of these lot sizes using the given function C(x).

For example, when x = 1,

we have:

C(1) = 3(1) + 4287501 + 12250 = 4299754

Similarly, we can calculate C(x) for each of the other lot sizes.

Once we have found the minimum cost, we can determine the corresponding lot size.

The minimum cost occurs when x = 1429167, and the corresponding minimum cost is:

C(1429167) = 3(1429167) + 4287501 + 12250 = 9,276,002

Therefore, Glorious Gadgets should order a lot size of 1429167 to minimize their total inventory costs, and the minimum total inventory cost is $9,276,002.

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