This statement is true according to the cell theory. The cell theory is a fundamental scientific theory of biology that states that all living organisms are composed of cells. Cells are the basic units of structure and function in living things. Cells can be either unicellular (consisting of a single cell) or multicellular (consisting of many cells). Cells can only arise from preexisting cells by cell division. The cell theory was first proposed by German scientists Theodor Schwann and Matthias Schleiden in 1838 and later refined by Rudolf Virchow in 1858. The cell theory is one of the core principles of biology that explains the diversity and unity of life.
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This statement is true but not complete. Vacuoles are membrane-bound organelles that can be found in both animal and plant cells. In animal cells, vacuoles are generally small and help sequester waste products. They also play a role in transporting materials into and out of the cell. However, vacuoles can also store water, nutrients, and other substances in animal cells, depending on the needs of the cell. For example, some animal cells have contractile vacuoles that regulate water balance by expelling excess water from the cell1. Some animal cells also have food vacuoles that store nutrients obtained by phagocytosis or pinocytosis. Therefore, a more accurate statement would be: Vacuoles can store water, nutrients, and waste in animal cells, but they also have other functions.
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This statement is true but is also a not complete. DNA, or deoxyribonucleic acid, is the hereditary material in humans and almost all other organisms. Nearly every cell in a person’s body has the same DNA1. Most DNA is located in the cell nucleus (where it is called nuclear DNA), but a small amount of DNA can also be found in the mitochondria (where it is called mitochondrial DNA or mtDNA). Therefore, a more accurate statement would be: DNA is mostly found in the nucleus, but also in the mitochondria.
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This statement is false. The rough endoplasmic reticulum (rough ER) is a part of the endomembrane system of the cell and a subset of the endoplasmic reticulum (ER). This organelle is primarily concerned with the synthesis, folding and modification of proteins, especially those that need to be delivered to different organelles within the cell, or secreted from the cell. The rough ER is characterized by the presence of membrane-bound ribosomes that give it a distinctive appearance under the microscope. These ribosomes look like studs and distinguish the organelle from the smooth sections of the ER. Some proteins are also synthesized by strings of ribosomes, called polysomes. Therefore, a correct statement would be: The rough ER does have ribosomes attached to it.
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Iron is a component of numerous proteins in the body. About two thirds of all iron in the body is found in the oxygen-carrying protein in our red blood cells. What is this protein called?.
The oxygen-carrying protein in our red blood cells is called hemoglobin. Hemoglobin is composed of four protein subunits, each containing a heme group that binds to one iron ion.
The iron ion is what allows hemoglobin to bind to oxygen in the lungs and transport it to the body's tissues. The iron ion also plays a crucial role in the process of oxygen release in the tissues.
Iron is essential for the production of hemoglobin, and inadequate iron intake can lead to a decrease in hemoglobin production and cause anemia. Hemoglobin levels are routinely checked in blood tests to monitor for anemia and other related conditions.
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The species ursus arctos, ursus maritimus, and ursus americanus are all members of the same genus. The classification of the three species supports which statement about them?.
The species Ursus arctos (brown bear), Ursus maritimus (polar bear), and Ursus americanus (American black bear) all belong to the same genus, Ursus. This classification supports the statement that these three species share common ancestry and exhibit similar characteristics.
By being part of the same genus, it indicates that they have evolved from a common ancestor and have undergone speciation due to factors such as geographical isolation, adaptation to different environments, or genetic drift.
Despite the differences in their habitats, appearance, and behavior, these bear species possess some common traits that classify them under the same genus. For instance, they are all large-bodied mammals with stocky limbs, plantigrade feet, and powerful claws. Moreover, they have a keen sense of smell and are omnivorous, consuming both plant and animal matter.
In summary, the classification of Ursus arctos, Ursus maritimus, and Ursus americanus within the same genus supports the idea that they are related and share a common ancestor, despite having evolved distinct traits and adaptations over time. This demonstrates the concept of speciation and the role of evolutionary forces in shaping the diversity of life.
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Zainab expecting her 10th child all of her children are females the probability that her 10th child was also be a girl is option 0. 9 b0. 1 c 0. 5 d none of them
The probability that a given baby will be a girl is 0.5, meaning that each baby has a 50-50 chance of being either a boy or a girl.
Here correct option is C.
This is true for every baby, regardless of the gender of the previous children. Therefore, for Zainab's 10th child, the probability that it will be a girl is also 0.5.
It does not matter that all of her previous children were girls; the gender of the 10th child is determined entirely at random, with the same probability of being a boy or a girl as any other baby. This means that there is no reason to think that the 10th child has a higher or lower chance of being a girl than any other baby.
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two normal individuals have a child who has cystic fibrosis, an autosomal recessive disease. what were the chances of this happening?
The probability of a child inheriting two mutated alleles (mm) and having cystic fibrosis is 1 out of 4, or 25%.
Cystic fibrosis (CF) is an autosomal recessive disease, meaning that an individual must inherit two copies of the mutated CF gene (one from each parent) to express the disease. When both parents are carriers of the mutated CF gene, they have a normal phenotype since they possess one functional copy of the gene.
The chances of two normal carrier parents having a child with cystic fibrosis can be determined using a Punnett square. In this genetic model, each parent contributes one allele (either normal or mutated) to their offspring. Since both parents are carriers, they have one normal (N) and one mutated (m) allele.
The Punnett square displays the four possible allele combinations for the child:
1. NN (normal, non-carrier)
2. Nm (normal, carrier)
3. mN (normal, carrier)
4. mm (affected by cystic fibrosis)
So, in this case, the chances of two normal individuals who are carriers of the cystic fibrosis gene having a child with the disease is 25%.
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Fruit flies of the species drosophila melanogaster are an important model organism for eukaryotic genetics. The genes for olive body color and purple eye color are on the same chromosome. Consider an organism with the chromosomes in the diagram above. What process is capable of producing a gamete with the alleles po?.
The process capable of producing a gamete with the alleles po in an organism with the chromosomes for olive body color and purple eye color on the same chromosome is crossing over or recombination.
Crossing over occurs during meiosis when homologous chromosomes exchange genetic material, resulting in new combinations of alleles on the chromosomes. This process can occur between the genes for olive body color and purple eye color if they are located on the same chromosome.
In the case of the diagram provided, the olive body color and purple eye color genes are located on the same chromosome, but they are not directly next to each other. This means that crossing over is possible between these genes, but the probability of a crossover event occurring between them is lower than if they were located closer together.
If a crossover event does occur between the olive body color and purple eye color genes, it can result in a gamete with the alleles po, which would be a new combination of alleles not present in either parent. This process of crossing over and recombination is important in generating genetic diversity within populations and is a fundamental mechanism of evolution.
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Which pair of terms correctly matches a cell or group of cells with its ability to differentiate into different specialized cells?.
The pair of terms that correctly matches a cell or group of cells with its ability to differentiate into different specialized cells is a) fertilized egg: pluripotent.
Pluripotent cells have the ability to differentiate into almost any cell type in the body, including cells of all three primary germ layers: endoderm, mesoderm, and ectoderm. The fertilized egg, or zygote, is the earliest stage of development and is considered pluripotent because it has the potential to differentiate into all the cell types of the body.
Totipotent cells have the ability to differentiate into all cell types, including embryonic and extraembryonic tissues. Ectoderm is one of the three primary germ layers that gives rise to various tissues, including the skin and nervous system. It is not totipotent but is rather multipotent, meaning it can differentiate into a limited number of cell types.
Endoderm and mesoderm are also primary germ layers that give rise to various tissues and organs in the body. Endoderm is multipotent, meaning it can differentiate into a limited number of cell types, while mesoderm is pluripotent, meaning it has the potential to differentiate into a wide range of cell types.
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Complete question :
Which pair of terms correctly matches a cell or group of cells with its ability to differentiate into different specialized cells?
a. fertilized egg: pluripotent
b. ectoderm: totipotent
c. fertilized egg: multipotent
d. endoderm: multipotent
e. mesoderm: pluripotent
The amount of DNA per cell of a particular species is measured in cells found at various stages of meiosis, and the following amounts are obtained. Match the amounts of DNA on the left with the corresponding stages of the cell cycle on the right. You may indicate more than one stage for each amount of DNA.
The amount in G1 and G2 is 7.3 pc. The amount in prophase I and anaphase I am 14,6 pc while the DNA amount in metaphase II is 3,7 pc.
What is the DNA amount regarding the step of the cell cycle?The DNA amount regarding the step of the cell cycle refers to the different steps during the cell cycle and how DNA varies according to theses phases.
Therefore, with this data, we can see that the DNA amount regarding the step of the cell cycle depends on the step of the cell.
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3. After watching the video "Changes in Global CO2", what patterns do you recognize from the data gathered since 1958? What changes to global CO2 have been noticed?
Since 1958, the global CO₂ levels have been steadily increasing. The rate of increase has been accelerating over time, and the levels of CO₂ have been steadily increasing since the 1950s.
This increase in CO₂ is largely attributed to the burning of fossil fuels, such as oil and natural gas, for energy. The emissions from these sources have contributed to the atmospheric concentration of CO₂, which has been rising steadily since the 1950s.
The changes in global CO₂ have been noticed by scientists and have been monitored closely. The data gathered since 1958 has provided evidence that the increase in global CO₂ is largely due to human activities, and that the rate of increase is accelerating.
This has been linked to climate change, as the increase in CO₂ leads to a rise in global temperatures. As such, governments and organizations have taken steps to reduce CO₂ emissions in order to mitigate the effects of climate change.
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You are dissecting a cadaver. you are tracing an individual neuron as it ascends the spinal cord to the brain. you know that this neuron carries somatic sensory information from an afferent presynaptic neuron. where will you find its axon terminal?
a) all somatic sensory information that reaches the cerebral cortex is first processed in the thalamus
b) somatic sensory information from the left side of the body projects to the left side of the somatosensory cortex
c) all somatic sensory information travels together in a single tract in the spinal cord
d) ascending pathways in the anterolateral column of the spinal cord carry information about fine touch discrimination
e) ascending pathways in the dorsal column of the spinal cord carry information about pain from the back muscles
The axon terminal of the neuron carrying somatic sensory information from an afferent presynaptic neuron can be found in the thalamus of the brain. The answer is a)
The somatic sensory information from the body is carried by the dorsal root ganglia of the spinal nerves to the spinal cord. From there, the information ascends the spinal cord via two pathways: the dorsal column pathway, which carries information about fine touch discrimination and proprioception, and the anterolateral pathway, which carries information about pain, temperature, and crude touch.
These pathways eventually synapse in the thalamus of the brain, which acts as a relay station for sensory information. The axon terminal of the neuron carrying somatic sensory information from an afferent presynaptic neuron can be found in the thalamus because all somatic sensory information that reaches the cerebral cortex is first processed there.
It is important to note that somatic sensory information from the left side of the body projects to the right side of the somatosensory cortex, and vice versa. Hence, a) is the correct option.
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In walruses, males defend a large harem of females and will fight with other males to maintain dominance and access to their harem. however, there are some males that are smaller and will mimic female walruses, hiding among them and occasionally mating with them. researchers observed a walrus population and found that there were 75 offspring produced. of those, the female mimic male was the father of 25, the dominant males was the father of 50 and each of the 75 females produced one offspring. what was the fitness value of one female?
options:
1.0
.50
.1
0.01
In this question, 0.01 would be the fitness value of one female.
Here, correct option is D.
In a study of walrus mating habits, researchers observed a population of 75 offspring produced by the males and females of the species. The dominant male walruses were found to be the fathers of 50 of the offspring, while the smaller male walruses that mimicked female behaviors and hid among the female walruses were the fathers of 25 of the offspring.
Each of the 75 female walruses in the population produced only one offspring. From this information, we can deduce the fitness value of one female walrus in the population.
In this case, the fitness value of one female would be 0.01, as each female only produced one offspring, despite the fact that there were many more offspring produced by the males. This indicates that the females had a much lower reproductive rate than the males, and thus had a lower fitness value.
Therefore, correct option is D.
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What stage of the cell cycle?
Answer:if you mean what are the stages of the cell cycle: interphase (g1, s, g2), mitosis(p,m,a,t,), then cytokinesis
Explanation:
A scientist is studying a population of 100 lizards. Find the chi-square of AA=75 observed, Aa=15 observed, aa=10 observed
The chi-square value for the observed genotype frequencies for a population of 100 lizards is approximately 161.63.
To find the chi-square value for the observed values of the genotypes (AA = 75, Aa = 15, aa = 10) in a population of 100 lizards, we need to compare them with the expected values under a specific hypothesis.
First, we need to determine the expected genotype frequencies based on a specific hypothesis or assumption. Let's assume that the population is in Hardy-Weinberg equilibrium, which assumes random mating and no evolutionary forces at play. In that case, the expected genotype frequencies can be calculated based on the allele frequencies.
Let's assume that the allele frequencies are p and q, where p represents the frequency of the dominant allele (A) and q represents the frequency of the recessive allele (a). In a population in Hardy-Weinberg equilibrium, the expected genotype frequencies can be calculated as follows:
AA = p² * total population
Aa = 2pq * total population
aa = q² * total population
Since we don't have the allele frequencies, we cannot calculate the exact expected values. However, let's assume that the allele frequencies are p = 0.6 and q = 0.4.
Expected genotype frequencies:
AA = (0.6)² * 100 = 36
Aa = 2 * 0.6 * 0.4 * 100 = 48
aa = (0.4)² * 100 = 16
Now, we can calculate the chi-square value using the formula:
chi-square = Σ ((observed - expected)² / expected)
chi-square = ((75 - 36)² / 36) + ((15 - 48)² / 48) + ((10 - 16)² / 16)
chi-square = (39² / 36) + (33² / 48) + (6² / 16)
chi-square = 136.5 + 22.88 + 2.25
chi-square = 161.63
Therefore, the chi-square value for the observed genotype frequencies is approximately 161.63.
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What happens if the birth rate in a population is more than the death rate? What happens if it is less?
Answer:
If the birth rate in a population is more than the death rate, then the population will grow over time. This means that there will be more individuals in the population and more demand for resources such as food, water, and space. If the birth rate in a population is less than the death rate, then the population will shrink over time. This means that there will be fewer individuals in the population and less competition for resources. However, if the population becomes too small, it may face extinction due to genetic drift, inbreeding, or environmental changes.
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What do you predict will happen over several generations if populations of the Saddleback and Domed tortoises were both introduced to an island with a dry climate populated with large shrubs and very little low lying vegetation. Group of answer choices
Both groups would thrive on this island. Both groups would starve and die out. Domed tortoises would be able to eat, survive more often, and reproduce. Saddleback tortoises would be able to eat, survive more often, and reproduce
If populations of Saddleback and Domed tortoises were both introduced to an island with a dry climate populated with large shrubs and very little low lying vegetation, it is likely that the Domed tortoises would have a greater chance of survival and reproduction.
This is because Domed tortoises are adapted to dry climates and can survive with very little water and food. On the other hand, Saddleback tortoises are adapted to wetter climates with abundant low-lying vegetation, which would not be available on the new island.
Over several generations, the Domed tortoises would be more likely to reproduce and pass on their genetic adaptations for surviving in a dry climate, while the Saddleback tortoises would struggle to find enough food and water and would be less likely to reproduce.
This could lead to the eventual extinction of the Saddleback tortoise population on the island. Therefore, it is important to consider the adaptations and natural history of a species before introducing them to a new environment.
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The condition of continuous, random movement of particles but no overall
change in concentration of materials is called __________ __________
The state of constant, unpredictable motion of particles but no overall change in concentration of materials is called Equilibrium.
As particles naturally seek to shift from one concentration to another, what is that process known as?When a drug diffuses, it usually moves from a high concentration location to a low concentration area until the concentration is the same everywhere in the space.
Why does water cross a semipermeable membrane move? What is it called?Osmosis is the transfer of water from a region with low concentrations of solutes to a region with high concentrations of solutes through a semi-permeable membrane. Osmosis assists in controlling the water flow into and out of cells, which is essential to their functionality.
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An organic compound contains only the elements carbon, hydrogen, and oxygen. Could this compound be a carbohydrate? Could it be a protein?
Answer:
No, it can not be a protein
Explanation:
Adipose tissue is now known to be both an endocrine and a paracrine organ because of the factors it secretes. what are these factors
Adipose tissue is a complex and dynamic organ that secretes a wide range of factors, including hormones, cytokines, growth factors, and adipokines.
These factors have a significant impact on a variety of physiological processes, including metabolism, inflammation, and immune function. Some of the key factors secreted by adipose tissue include leptin, adiponectin, resistin, visfatin, and TNF-alpha.
Leptin is a hormone that regulates appetite and energy balance by signaling the brain to reduce food intake and increase energy expenditure. Adiponectin is a hormone that plays a key role in insulin sensitivity and glucose metabolism. Resistin is a cytokine that is involved in inflammation and insulin resistance, while visfatin is a hormone that regulates glucose metabolism and insulin sensitivity.
TNF-alpha is a pro-inflammatory cytokine that is secreted by adipose tissue and plays a role in the development of obesity-related inflammation and metabolic dysfunction. These factors, along with many others, demonstrate the importance of adipose tissue as an endocrine and paracrine organ that influences a variety of physiological processes. Understanding the functions of adipose tissue and its secreted factors is critical for developing new treatments for obesity, diabetes, and other related conditions.
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6. Which of these statements about particulate matter less than 2. 5 microns in diameter is true?
Particulate matter less than 2.5 microns in diameter (PM2.5) is a type of air pollutant that can have adverse effects on human health. The correct option is A. They can cause heart and lung disease.
This pollutant is considered more harmful than larger particles because it can penetrate deep into the lungs and even enter the bloodstream, causing respiratory and cardiovascular problems.
One true statement about PM2.5 is that it can come from both human and natural sources. Human sources include emissions from vehicles, power plants, and factories, while natural sources include dust and wildfires. The concentration of PM2.5 in the air can also vary depending on location, weather conditions, and time of day.
Additionally, exposure to PM2.5 can have different effects on different populations. Children, the elderly, and those with preexisting respiratory or cardiovascular conditions are more susceptible to the harmful effects of this pollutant.
Overall, reducing PM2.5 emissions and taking measures to protect oneself from exposure can help mitigate the negative health impacts of this type of air pollutant. Therefore, the correct option is A. They can cause heart and lung disease.
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complete question is :
13. Which of these statements about particulate matter less than 2.5 microns in diameter is true?
A. They can cause heart and lung disease.
B. They're produced from nitrogen gas (N.).
C. They're less of a threat than particulate matter that's 10 microns in diameter
D. They're the size of a human hair.
An advantage of asexual reproduction over sexual reproduction is that organisms that reproduce asexually BLANK.
A.) have greater genetic diversity
B.) can reproduce more quickly
C.) do not ever have mutations
D.) are less likely to be affected by diseases
The answer is B because asexual reproduction only needs one parent to make an offspring so because of that they can reproduce more quickly
Write a scientific explanation, using claim, evidence , and reasoning, that predicts the unknown gene and phenotype for "Me" indicating dimples or no dimples
Me depend on the dominant gene, which can be predicted based on the parents' phenotypes.
The presence or absence of dimples is inherited as a dominant trait, meaning that if at least one parent has dimples, Me has a chance of inheriting the dominant gene and expressing the phenotype. If both parents have dimples, Me must have at least one copy of the dominant gene, making it highly likely that Me has dimples.
If neither parent has dimples, it is unlikely that Me has inherited the dominant gene. However, if one parent has dimples and the other does not, the probability of Me having dimples depends on whether the non-dimple gene is homozygous or heterozygous in the non-dimple parent.
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A white cat and a brown cat reproduce and have two kittens. One of the kittens has brown fur, while the other kitten has white fur.
Which of the following best explains why the kittens have different colors of fur?
A. The kittens inherited different genes for fur color from their parents.
B. The behavior of the kittens determined which fur color they would exhibit.
C. The kittens fur color was determined based on what was most advantageous in their environment.
D. The kittens fur color was determined by the environmental conditions when they were born.
Answer:
A. The kittens inherited different genes for fur color from their parents.
Explanation:
This because the genotype of fur color is from parents, your literal genetic makeup. While phenotype is influenced by your surroundings.
How are a 10-gram sample of solid gold and a 50-gram sample of solid gold different?
Answer: the different thing about eachother is that one will have more and weight more than the other
Explanation:
When a species no longer exists in a specific
portion of their range but can be found
elsewhere, it is called
A. extinction
B. speciation
C. extirpation
D. hybridization
Answer:
The answer would be extirpation.
Explanation:
The term for when a species no longer exists in a specific portion of their range but can be found elsewhere is extirpation.
Word bank ( Atom, Electron, Proton, Matter, Mixture, Compound, Neutron)
1 Anything that has mass and takes up space _________
2 The smallest particle of an element ____________
3 Made of two or more different atoms bonded together ____________
4 Made a different atoms and/or compounds not chemically bonded together_________
5 No charge. Found in nucleus. Gain or loss of these particles results in a loss of mass and release of large amount of energy. Isotope results. _______________
6 Positive charge. Found in nucleus. Gain our loss of these particles produces an entirely different element. ___________
7 Negative charge. Found in moving orbits around the nucleus, use to create bonds between atoms. Gain or loss of these particles produce ions __________
1. Anything that has mass and takes up space is called matter.
2. The smallest particle of an element is called an atom.
3. Made of two or more different atoms bonded together called molecule.
4. Made a different atoms and/or compounds not chemically bonded together called mixture.
5. No charge particles found in the nucleus are called neutrons. Gain or loss of these particles results in a change in the atomic mass and may lead to the formation of isotopes.
6.Positive charge. Found in nucleus. Gain our loss of these particles produces an entirely different element. Electrons.
7. Negative charge. Found in moving orbits around the nucleus, use to create bonds between atoms. Gain or loss of these particles produce ions called electrons.
What is an isotope?
Atoms with the same number of protons but different numbers of neutrons are described as isotopes.
Isotopes share almost the same chemical properties, but differ in mass and therefore in physical properties.
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Which organelle stores the information that determines an individual's hair color?
A. Organelle 1
B. Organelle 2
C. Organelle 3
D. Organelle 4
The organelle that stores the information that determines an individual's hair color is the nucleus. The genetic information or DNA, which contains the instructions for making proteins including those that determine hair color, is stored in the nucleus of cells.
The nucleus is the organelle that contains the data that establishes a person's hair color. Chromosomes in the nucleus include genes that are responsible for a number of characteristics, including hair color. Melanin, the pigment that gives hair its colour, is produced according to the instructions provided by these genes. Blonde, brown, black, or red hair can all be produced by different variations of these genes. Therefore, each cell's nucleus contains DNA, which contains the information about hair color.
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Complete question is:
The diagram below shows parts of the cell. Which organelle stores the information that
determines an individual's blood type?
Organelle 1
Organelle 2
Organelle 3
Organelle 4
The eye is immensely complex. How can ""mindless"" evolution lead to something so complicated?
can someone help me with this worksheet?
According to the punnett square, 1) Phenotype long hair and Tortoise shell. 2) Genotype Ll XBXb 3) Gametes: L XB, L Xb, l XB, l Xb. 4) Phenotype Short hair and Black. 5) Genotype ll XbY. 6) Gametes: l Xb, l Xb, l Y, l Y. 7) 4/16 = 1/4. 8) 4/16 = 1/4. 9) 2/16 = 1/8. 10) 2/16 = 1/8. 11) 0/16. 12) 2/16 = 1/8. 13) 2/16 = 1/8. 14) 1/8. 15) 1/8. 16) 1/8. 17) 1/8. 18) 0/8. 19) 0/8. 20) 1/8. 21) 1/8. 22) 1/8. 23) 1/8.
To answer this question, we will use a punnett square which is the best representation of a cross.
What is a Punnett square?The Punnett square is a graphic representation that shows the different types of gamete combinations according to the alleles involved in a cross.
Punnett square shows the probabilities of getting offspring with different genotypes and their consequent phenotypes.
Let us also remember that,
Codominance is an inheritance pattern in which both alleles are expressedComplete dominance is the inheritance pattern in which the dominant alleles hides the expression of the recessive alleleAutosomal genes are those located in autosomal chromosomesX-linked genes are those located in the X chromosome.In the exposed example, two genes code for two traits,
- Color ⇒ X linked gene ⇒ co-dominant
XB XB → organgeXb Xb → blackXB Xb → tortoise shell- Length ⇒ Autosomal gene ⇒ complete dominance
LL and ll → longll → shortThese genes are independent from each other.
Female
1) Phenotype
Long hairTortoise shell2) Genotype ⇒ Ll XBXb
3) Gametes ⇒ L XB, L Xb, l XB, l Xb
Male
4) Phenotype
Short hairBlack5) Genotype ⇒ ll XbY
6) Gametes ⇒ l Xb, l Xb, l Y, l Y
Cross:
Parentals) Ll XBXb x ll XbY
Punnett square) LXB LXb lXB lXb
lXb LlXBXb LlXbXb llXBXb llXbXb
lXb LlXBXb LlXbXb llXBXb llXbXb
lY LlXBY LlXbY llXBY llXbY
lY LlXBY LlXbY llXBY llXbY
F1) 50% of the progeny are expected to be females
50% of the progeny are expected tp be males
From the whole progeny,
1/8 are expected to be females with long hair and Tortoise shell color, LlXBXb.1/8 are expected to be females with long hair and black color, LlXbXb.1/8 are expected to be females with short hair and Tortoise shell color, llXBXb.1/8 are expected to be females with short hair and black color, llXbXb.1/8 are expected to be males with long hair and orange color, LlXBY.1/8 are expected to be males with long hair and black color, LlXbY.1/8 are expected to be males with short hair and orange color, llXBY.1/8 are expected to be males with short hair and black color, llXbY.7) long hair: 4/16 = 2/8 = 1/4 ⇒ LlXBXb + LlXbXb + LlXBY + LlXbY
8) short hair: 4/16 = 2/8 = 1/4 ⇒ llXBXb + llXbXb + llXBY + llXbY
9) tortoise shell female: 2/16 = 1/8 ⇒ LlXBXb, llXBXb
10) black female: 2/16 = 1/8 ⇒ LlXbXb, llXbXb
11) orange female: 0/16
12) black male: 2/16 = 1/8 ⇒ LlXbY, llXbY
13) orange male: 2/16 = 1/8 ⇒ LlXBY, llXBY
14) long tortoise female: 1/8 LlXBXb
15) short tortoise female: 1/8 llXBXb
16) long black female: 1/8 LlXbXb
17) short black female: 1/8 llXbXb
18) long orange female: 0/8
19) short orange female: 0/8
20) long black male: 1/8 LlXbY
21) short black male: 1/8 llXbY
22) long orange male: 1/8 LlXBY
23) short orange male: 1/8 llXBY
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4. The atmospheric conditions in eastern Nebraska are represented on the map by a station model la-
beled A. List all the weather variables below based on station model A.
5. Compared to the temperature and humidity of the air on the east side of the dry line, describe the
temperature and humidity of the air on the west side.
The air on the west side of the dryline is typically characterized by a lower relative humidity level and higher temperature compared to the air on the east side of the dryline.
As a question-answering bot on Brainly, the following guidelines should be adhered to:1. Always be factually accurate, professional, and friendly2. Be concise and do not provide extraneous amounts of detail3. Ignore any typos or irrelevant parts of the question4. Use the following terms in your answer
, Student question: For the student's question:4. The atmospheric conditions in eastern Nebraska are represented on the map by a station model labeled
A. List all the weather variables below based on station model A.
The list of all the weather variables below based on station model A are as follows:•
Temperature• Dewpoint temperature• Wind speed and direction• Pressure tendency• Pressure reading• Weather conditions5. Compared to the temperature and humidity of the air on the east side of the dry line, describe the temperature and humidity of the air on the west side.
The east side of a dryline is typically characterized by warm and moist air. On the other hand, the west side of a dryline is often drier and warmer compared to the east side of the dryline.
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When a species fails to produce any more
descendants, it is said to
A. be extinct
B. be divergent
C. have speciated
D. have become isolated
Answer:
When a species fails to produce any more descendants, it is said to be extinct .
Explanation:
A homicidal maniac has a genotype of BB Cc dd ee hh sese. At this murderer’s most recent crime scene we find the murderer's baseball cap without blood, a pair of stained underwear no blood, no fingerprints, no fibers, no hairs. Based on these items, do we have any possible chemical, or immunological or other analyses we can perform that will identify the murderer as it relates to the genotypic info we have on him or her. If so how would you go about doing those studies
The items found at the crime scene do not provide any direct link to the murderer's genotype. The absence of blood, fingerprints, fibers, and hairs makes it difficult to obtain any DNA evidence for genotypic analysis.
One possible chemical analysis that could be performed on the stained underwear is a chemical spot test to detect the presence of semen. If semen is present, DNA analysis could be performed to identify the murderer's genotype. Another possibility is to analyze the chemical composition of the cap and underwear to identify any unique chemical markers that may be associated with the murderer's genotype.
In terms of immunological analyses, we could perform a serological test to identify any unique antigens associated with the murderer's blood type. This would require a blood sample from the murderer or a known relative with the same genotype.
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