Answer:
A. G(x) = (x -3)^3 -(x -3)
Step-by-step explanation:
The graph before it was shifted left will be a right-shift of the equation shown. That is accomplished by replacing x with (x-1.5). Then the right-shifted equation is ...
G(x) = ((x-1.5) -1.5)^3 -((x -1.5) -1.5)
G(x) = (x -3)^3 -(x -3) . . . . matches choice A
ADDITIONAL 100 POINTS PLS HELP ASAP follow up question ( first question on log )
Answer:
Hello!
I believe this is what you are looking for:
x=3
33=27
32=9
S=Surface area
V=Volume
L=Length
R=Radius
I hope this helped. If not, please let me know. I will try my best again. :)
Step-by-step explanation:
Which data collection method would provide an unbiased sample?
Answer:
The best data collection method or sampling method to provide an unbiased sample is the random sampling method.
Step-by-step explanation:
There are 5 popular known sampling methods or data collection methods.
1) Random Sampling
In random sampling, each member of the population would have an equal chance of being surveyed. One of the best ways to use random sampling is to give all the members of the population numbers and then use computer to generate random numbers and pick the members of the population with those random numbers.
2) Systematic sampling is easier than random sampling. In systematic sampling, a particular number, n, is counted repeatedly and each of the nth member is picked to be sampled.
3) Convenience Sampling
This is the worst sampling technique. It is also the easiest. In Convenience sampling, the surveyor just picks the first set of members of the population that they find and surveys.
4) Stratified Sampling
Stratified sampling divides the population into groups called strata. A sample is taken from each of these strata using either random, systematic, or convenience sampling.
5) Cluster sampling
Cluster Sampling divides the population into groups which are called clusters or blocks. The clusters are selected randomly, and some members or every element/member in the selected clusters is surveyed.
Hope this Helps!!!
What is the final step in solving the inequality –2(5 – 4x) < 6x – 4?
Answer:
work is shown and pictured
Answer: x<3
Step-by-step explanation:
Which is equivalent to 8−+3
8
x
-
y
+
3
x
?
Answer:
DIDNT UNDERSTAND THE QUESTION PROPERLY BRO..
KEEP THE QUESTION AGAIN
Do You Understand?
D
4.
1. Essential Question How does an equation
show the relationship between variables and
other quantities in a situation?
Answer:
An equation is basically a way to show a relationship of variables (x,y,a,b, etc) and numbers.
Step-by-step explanation:
Answer:
Shown by explanation.
Step-by-step explanation:
An equation shows a relationship between variables and other factors by defining the variables that are dependent and independent and how these dependent variables are related to the independent variables, this is usually as a result of a prescribed experiment where the relationship of this variables are investigated.
Also remember conditions that favour this experiment must be taken into consideration. And the experiment must always be performed under such conditions.
Two positive, consecutive, odd integers have a product of 143.
Complete the equation to represent finding x, the greater integer.
x(x –
) = 143
What is the greater integer?
Step-by-step explanation:
x and x+2 are the numbers
x(x+2)=143
x²+2x-143=0
x²+13x-11x-143=0
x(x+13)- 11(x+13)=0
(x+13). (x-11)=0
x+13=0. x=-13
x-11=0. x=11
A classic counting problem is to determine the number of different ways that the letters of "misspell" can be arranged. Find that number.
Answer:
10,080 different ways that the letters of "misspell" can be arranged.
Step-by-step explanation:
Number of arrangents of the letters of a word:
A word has n letters.
The are m repeating letters, each of them repeating [tex]r_{0}, r_{1}, ..., r_{m}[/tex] times
So the number of distincts ways the letters can be arranged is:
[tex]N_{A} = \frac{n!}{r_{1}! \times r_{2}! \times ... \times r_{m}}[/tex]
In this question:
Misspell has 8 letters, with s and l repeating twice.
So
[tex]N_{A} = \frac{8!}{2!2!} = 10080[/tex]
10,080 different ways that the letters of "misspell" can be arranged.
A student works at an on- campus job Monday through Friday. The student also participates in intramural volleyball on Tuesdays and Thursdays. Given Events A and B, are the two events mutually exclusive? Explain your answer.
Event A: On a random day of the week, the student is working at their on-campus job.
Event B: On a random day of the week, the student is playing intramural volleyball.
Answer:
No, the events are not mutually exclusive because they share the common outcomes of the student working and playing volleyball on certain days.
Step-by-step explanation:
A and B are mutually exclusive events if they cannot occur at the same time. This means that A and B do not share any outcomes and P(A AND B)=0.
In this case, A and B have outcomes in common since the student both works and plays volleyball on Tuesdays and Thursdays. Thus, the events are not mutually exclusive.
Solve for y=x squared -18 solve for x
Step-by-step explanation:
[tex]y = {x}^{2} - 18 \\ y + 18 = {x}^{2} \\ square \: root \: both \: sides \: \\ \sqrt{y + 18} = \sqrt{ {x}^{2} } [/tex]
[tex]x = \sqrt{y + 18} [/tex]
Answer:
√y + 18 = x
Step-by-step explanation:
Let us solve it now.
y = x² - 18
Take -18 to the left side
y + 18 = x²
Now remove the square of x
√y + 18 = x
A recent national survey found that parents read an average (mean) of 10 books per month to their children under five years old. The population standard deviation is 5. The distribution of books read per month follows the normal distribution. A random sample of 25 households revealed that the mean number of books read last month was 12. At the .01 significance level, can we conclude that parents read more than the average number of books to their children
Answer:
Step-by-step explanation:
Null hypothesis: u = 10
Alternative hypothesis: u =/ 10
Using the formula: t = (x - u) / (s /√n)
Where x = 12, u = 10, s = 5 and n = 25
t= (12-10) / (5/√25)
t = (2)/(5/5)
t = 2/1= 2
t = 2.0
At a 0.01 level of significance with a degree of freedom of 24, the p-value is 0.0569, which is greater than 0.01 we will fail to reject the null and conclude that parents do not read more than the average number of books to their children
Homework: Section 1.2 Applications Linear
Score: 0 of 1 pt
8 of 10 (7 complete)
1.2.31
How many quarts of pure antifreeze must be added to 4 quarts of a 10% antifreeze solution to obtain a 20% antifreeze solution?
quart(s) of pure antifreeze must be added.
(Round to the nearest tenth as needed)
Answer:
q = 0.5 quarts of 100% antifreeze
Step-by-step explanation:
q = quarts of pure antifreeze
Set this up as a weighted combination of the mixtures.
(100%)(q) + (10%)(4) = (20%)(q + 4)
100q + 40 = 20(q + 4)
5q + 2 = q + 4
4q = 2
q = 0.5 quarts of 100% antifreeze
Multiply or divide as indicated.
10x^5 divide 2x^2
Answer:
5x^3(to the power of 3)
Step-by-step explanation:
10x^5/2x^2
divide the 10/2 like normal to get 5
x^5/x^2 (subtract the powers 5-2 when dividing powers)
you would get 5x^3
Please help! Correct answer only, please! Consider the matrix shown below: Find the determinant of the matrix Q. A. -67 B. -65 C. 65 D. 67
Answer: d) 67
Step-by-step explanation:
[tex]determinant\ \left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&j\end{array}\right] = a\cdot det\left[\begin{array}{cc}e&f\\h&j\end{array}\right] -\ b\cdot det\left[\begin{array}{cc}d&f\\g&j\end{array}\right] +\ c\cdot det\left[\begin{array}{cc}d&e\\g&h\end{array}\right][/tex]
[tex]determinant\ \left[\begin{array}{ccc}2&3&4\\-3&2&1\\5&-1&6\end{array}\right] \\\\\\= 2\cdot det\left[\begin{array}{cc}2&1\\-1&6\end{array}\right] -\ 3\cdot det\left[\begin{array}{cc}-3&1\\5&6\end{array}\right] +\ 4\cdot det\left[\begin{array}{cc}-3&2\\5&-1\end{array}\right]\\\\\\=2[2(6)-1(-1)]-3[-3(6)-1(5)]+4[3(-1)-2(5)]\\\\\\=2(13)-3(-23)+4(-7)\\\\\\=26+69-28\\\\\\=\large\boxed{67}[/tex]
Use the zero product property to find the solutions to the equation x2 – 9 = 16.
x= -3 or x = 3
x= -6 or x = -3
Ox= -5 or x = 5
O x= 7 or x = 1
Answer:
x = ±5
Step-by-step explanation:
x^2 – 9 = 16
Add 9 to each side
x^2 – 9+9 = 16+9
x^2 = 25
Take the square root of each side
sqrt(x^2) = ±sqrt(25)
x = ±5
Answer:
[tex]x = 5 \: \: \: or \: \: x = - 5[/tex]
Step-by-step explanation:
[tex] {x}^{2} - 9 = 16 \\ {x}^{2} = 16 + 9 \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5 \\ x = - 5[/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
The functions r and s are defined as follows. r(x)=2x-1 s(x)=-2x^2-2 Find the value of s(r(-4)).
Answer:
s(r(-4)) = -164
Step-by-step explanation:
r(x) = 2x - 1
s(x) = -2x^2 - 2
r(-4) = 2(-4) - 1 = -8 - 1 = -9
s(r(-4)) = s(-9) = -2(-9)^2 - 2 = -2*81 - 2 = -162 - 2 = -164
Hope this helps!
If a function f(x) is defined as 3x2 + x + 2, what is the value of Lim h-0 f(x+h)-f(x)/h? A. 3x + 1 B. 3x + 2 C. 6x + 1 D. 6x + 2
Answer:
[tex] f(x+h) = 3(x+h)^2 +(x+h) +2= 3(x^2 +2xh+h^2) +x+h+2[/tex]
[tex]f(x+h) = 3x^2 +6xh +3h^2 +x+h+2= 3x^2 +6xh +x+h+ 3h^2 +2[/tex]
And replacing we got:
[tex] lim_{h \to 0} \frac{3x^2 +6xh +x+h+ 3h^2 +2 -3x^2 -x-2}{h}[/tex]
And if we simplfy we got:
[tex] lim_{h \to 0} \frac{6xh +h+ 3h^2 }{h} =lim_{h \to 0} 6x + 1 +3h [/tex]
And replacing we got:
[tex]lim_{h \to 0} 6x + 1 +3h = 6x+1[/tex]
And the bet option would be:
C. 6x + 1
Step-by-step explanation:
We have the following function given:
[tex] f(x) = 3x^2 +x+2[/tex]
And we want to find this limit:
[tex] lim_{h \to 0} \frac{f(x+h) -f(x)}{h}[/tex]
We can begin finding:
[tex] f(x+h) = 3(x+h)^2 +(x+h) +2= 3(x^2 +2xh+h^2) +x+h+2[/tex]
[tex]f(x+h) = 3x^2 +6xh +3h^2 +x+h+2= 3x^2 +6xh +x+h+ 3h^2 +2[/tex]
And replacing we got:
[tex] lim_{h \to 0} \frac{3x^2 +6xh +x+h+ 3h^2 +2 -3x^2 -x-2}{h}[/tex]
And if we simplfy we got:
[tex] lim_{h \to 0} \frac{6xh +h+ 3h^2 }{h} =lim_{h \to 0} 6x + 1 +3h [/tex]
And replacing we got:
[tex]lim_{h \to 0} 6x + 1 +3h = 6x+1[/tex]
And the bet option would be:
C. 6x + 1
Answer:
6x+1
Step-by-step explanation:
Plato :)
What’s the correct answer for this question? Select all that Apply
Answer:
B and G
Step-by-step explanation:
Square and rectangle
A rectangular field has an area of 1,764 m(squared). The width of the field is 13 m more than the length. What is the perimeter of the field?
Answer:
170m
Step-by-step explanation:
The answer to the above question is letter d which is 170 m. To get the 170 m, kindly check the below solution:
x^2 + 13x = 1764 so x = -49 and 36, we take 36 as its the positive value. And the other side is 49. Now use 2(l+b) to find perimeter. You get (36+49)*2 = 170
The probability of winning on a slot machine is 5%. If a person plays the machine 500 times, find the probability of winning at least 30 times. Group of answer choices Greater than 0.60 Between 0.20 and 0.40 Between 0.01 and 0.20 Between 0.40 and 0.60 Almost 0
Answer:
Between 0.01 and 0.20
Step-by-step explanation:
I am going to use the normal approximation to the binomial to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].
In this problem, we have that:
[tex]n = 500, p = 0.05[/tex]
So
[tex]\mu = E(X) = np = 500*0.05 = 25[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{500*0.05*0.95} = 4.8734/tex]
Find the probability of winning at least 30 times.
Using continuity correction, this is [tex]P(X \geq 30 - 0.5) = P(X \geq 29.5)[/tex]. So this is 1 subtracted by the pvalue of Z when X = 29.5. Then
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{29.5 - 25}{4.8734}[/tex]
[tex]Z = 0.92[/tex]
[tex]Z = 0.92[/tex] has a pvalue of 0.8212
1 - 0.8212 = 0.1788
So the correct option is:
Between 0.01 and 0.20
If the size of the sample to be used in a particular test of attributes has not been determined by utilizing statistical concepts, but the sample has been chosen in accordance with random selection procedures
A) No inferences can be drawn from the sample.
B) The auditor has committed a nonsampling error.
C) The auditor may or may not achieve the desired risk of assessing control risk too low.
D) The auditor will have to evaluate the results by reference to the principles of discovery sampling.
E) The auditor may or may not achieve the desired
Answer:
C) The auditor may or may not achieve the desired risk of assessing control risk too low.
Step-by-step explanation:
In a concept of risk sampling, if the sample size is chosen randomly in accordance with random selection procedures, the auditor may or may not achieve the desired risk of assessing risk too low. In other words the auditor may or may not achieve desired precision. This is because a samole chosen randomly may not represent the true population.
This depends largely on the sample size. If the sample size selected is too small, the allowance for sampling risk will be larger than what is required because it will lead to a large standard error of the mean
What is the volume of a cone with a height of 27 cm
and a radius of 13 cm? Round your answer to the
nearest tenth.
V=
Answer: V=4778.4 cm³
Step-by-step explanation:
[tex]V=\pi r^2\frac{h}{3}[/tex] is the formula for volume. Since we are given the height and radius, we can directly plug it into the equation
[tex]V=\pi (13)^2(\frac{27}{3})[/tex]
[tex]V=169\pi (9)[/tex]
[tex]V=1521\pi[/tex]
[tex]V=4778.4cm^3[/tex]
The equation h = 7m + 8 models the growth of a plant after it was put into a flowerbed. If
m is the number of months since it was planted and h is the plant's height in
centimeters, which statement is valid?
The vertical axis on a graph would
represent the number of months the plant
has been in the flowerbed.
The height of the plant is the dependent
variable.
The domain of the function represents the
height of the plant.
The variable m could be represented as
f(h).
Answer:
2
Step-by-step explanation:
the vertical axis would be h, the plant's height, and the horizontal axis would be m, the number of months. This would make statement 2 the only valid statement.
statement 1: Incorrect, as the vertical axis is the height
statement 2: correct, as h depends on m
statement 3: incorrect, as the domain is the horizontal and represents the number of months
statement 4: incorrect, as h = f(m)
The cost of a circular table is directly proportional to the square of the radius. A circular table with a radius of 50cm costs £60. What is the cost of a circular table with a radius of 75cm? Show all your working
Answer:
£135 is the correct answer.
Step-by-step explanation:
Let C be the cost of table.
And let R be the radius of table.
Cost of table is directly proportional to square of radius.
As per question statement:
[tex]C\propto R^{2}[/tex] or
[tex]C=a\times R^2 ....... (1)[/tex]
where [tex]a[/tex] is the constant to remove the [tex]\propto sign[/tex].
It is given that
[tex]C_1 =[/tex] £60 and [tex]R_1 = 50\ cm[/tex]
[tex]C_2 = ?[/tex] when [tex]R_2= 75\ cm[/tex]
Putting the values of [tex]C_1[/tex] and [tex]R_1[/tex] in equation (1):
[tex]60=a \times 50^2 ....... (2)[/tex]
Putting the values of [tex]C_2[/tex] and [tex]R_2[/tex] in equation (1):
[tex]C_2=a \times 75^2 ....... (3)[/tex]
Dividing equation (2) by (3):
[tex]\dfrac{60}{C_2}= \dfrac{a \times 50^2}{a \times 75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{50^2}{75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{2^2}{3^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{4}{9}\\\Rightarrow C_2 = 15 \times 9 \\\Rightarrow C_2 = 135[/tex]
So, £135 is the correct answer.
Find the constant of variation k for the direct variation 3x+5y=0
Answer:
-3/5
Step-by-step explanation:
3x+5y=0
Subtract 3x from each side
3x+5y-3x=0-3x
5y = -3x
Divide each side by 5
5y/5 = -3x/5
y = -3/5 x
A direct variation is y = kx
y = -3/5 x
The constant of variation is -3/5
There are 1760 yards in one mile about how many miles will a runner have to run
Answer:
3
I used to be an olimpic runner and I ran the 400 all the time and I did cross country
Can someone please help me with this question the first one
A certain manufactured product is supposed to contain 23% potassium by weight. A sample of 10 specimens of this product had an average percentage of 23.2 with a standard deviation of 0.2. If the mean percentage is found to differ from 23, the manufacturing process will be recalibrated.
a. State the appropriate null and alternate hypotheses.
b. Should the process be recalibrated? Explain.
c. Compute the P-value.
Answer:
(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 23%
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] [tex]\neq[/tex] 23%
(b) We conclude that the mean percentage is different from 23 and the manufacturing process will be re-calibrated.
(c) P-value is 0.6%.
Step-by-step explanation:
We are given that a certain manufactured product is supposed to contain 23% potassium by weight.
A sample of 10 specimens of this product had an average percentage of 23.2 with a standard deviation of 0.2.
Let [tex]\mu[/tex] = mean percentage of potassium by weight.
(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 23% {means that the mean percentage is equal to 23 and the manufacturing process will not be re-calibrated}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] [tex]\neq[/tex] 23% {means that the mean percentage is different from 23 and the manufacturing process will be re-calibrated}
The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean percentage = 23.2
s = sample standard deviation = 0.2
n = sample of specimens = 10
So, the test statistics = [tex]\frac{23.2-23}{\frac{0.2}{\sqrt{10} } }[/tex] ~ [tex]t_9[/tex]
= 3.162
The value of t test statistic is 3.162.
Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -2.262 and 2.262 at 9 degree of freedom for two-tailed test.
(b) Since our test statistic doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that the mean percentage is different from 23 and the manufacturing process will be re-calibrated.
(c) The P-value of the test statistics is given by;
P-value = P( [tex]t_9[/tex] > 3.162) = 0.006 or 0.6%
(a) Null Hypothesis, [tex]H_o:\mu[/tex]: = 23%
Alternate Hypothesis, [tex]H_A:\mu\neq[/tex] : 23%
(b) We conclude that the mean percentage is different from 23 and the manufacturing process will be re-calibrated.
(c) P-value is 0.6%.
What is a null hypothesis?The hypothesis that there is no significant difference between specified populations, any observed difference being due to sampling or experimental error.
We are given that a certain manufactured product is supposed to contain 23% potassium by weight.
A sample of 10 specimens of this product had an average percentage of 23.2 with a standard deviation of 0.2.
Let = mean percentage of potassium by weight.
(a) Null Hypothesis, [tex]H_o:\mu[/tex]: = 23% {means that the mean percentage is equal to 23 and the manufacturing process will not be re-calibrated}
Alternate Hypothesis, [tex]H_A:\mu\neq[/tex]: 23% {means that the mean percentage is different from 23 and the manufacturing process will be re-calibrated}
The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;
[tex]TS=\dfrac{X-\mu}{\frac{s}{\sqrt{n}}}[/tex] ~ [tex]t_{n-1}[/tex]
where, = sample mean percentage = 23.2
s = sample standard deviation = 0.2
n = sample of specimens = 10
So, the test statistics = [tex]\dfrac{23.2-23}{\frac{0.2}{\sqrt{10}}}[/tex] ~ [tex]t_g[/tex]
= 3.162
The value of t test statistic is 3.162.
Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -2.262 and 2.262 at 9 degree of freedom for two-tailed test.
(b) Since our test statistic doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that the mean percentage is different from 23 and the manufacturing process will be re-calibrated.
(c) The P-value of the test statistics is given by;
P-value = P( [tex]t_g[/tex] > 3.162) = 0.006 or 0.6%
Hence ,
(a) Null Hypothesis, [tex]H_o:\mu[/tex]: = 23%
Alternate Hypothesis, [tex]H_A:\mu\neq[/tex] : 23%
(b) We conclude that the mean percentage is different from 23 and the manufacturing process will be re-calibrated.
(c) P-value is 0.6%.
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I will give brainiest to the first to answer. The what
of the following set of data is 5.
13, 7, 9, 5, 2, 3, 5, 4, 10, 12
Answer:
it is the mode.
Step-by-step explanation:
i. e 5 is the most occuring number in the set of data listed above
what is the least common denominator of 4 7/9 and 2 2/3
Answer:
9
Equivalent Fractions with the LCD
4 7/9 = 43/9
2 2/3 = 24/9
For the denominators (9, 3) the least common multiple (LCM) is 9.
Therefore, the least common denominator (LCD) is 9.
4 7/9 = 43/9 × 1/1 = 43/9
2 2/3 = 8/3 × 3/3 = 24/9
Hope this helps :)
The least common denominator of 4 7/9 and 2 2/3 is 9.
Given data:
To find the least common denominator (LCD) of 4 7/9 and 2 2/3, we need to first convert both fractions to their equivalent forms with a common denominator.
The given fractions are:
4 7/9 = 4 + 7/9
2 2/3 = 2 + 2/3
To find a common denominator, we need to find the least common multiple (LCM) of the denominators 9 and 3, which is 9.
Now, let's convert the fractions to their equivalent forms with a denominator of 9:
4 7/9 = (4 * 9)/9 + (7/9) = 36/9 + 7/9 = 43/9
2 2/3 = (2 * 9)/9 + (2/3) = 18/9 + 2/3 = 20/9
The fractions 4 7/9 and 2 2/3 are now expressed with a common denominator of 9.
Hence, the least common denominator (LCD) of 4 7/9 and 2 2/3 is 9.
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Sarah wants to refurbish her shop.
She is quoted £2500 for the refurbishment, with a 20% discount to be taken off.
What is the final cost of the refurbishment after the discount?
Answer:
2000
Step-by-step explanation:
2500 / 100 = 25 (1%)
25 X 20 =500 (20%)
2500 - 500 =2000