Graph the linear equation y=2.

Answer:

(1, 2 )

Step-by-step explanation:

Given the 2 equations

y = - 3x + 5 → (1)

5x - 4y = - 3 → (2)

Substitute y = - 3x + 5 into (2)

5x - 4(- 3x + 5) = - 3 ← distribute and simplify left side

5x + 12x - 20 = - 3

17x - 20 = - 3 ( add 20 to both sides )

17x = 17 ( divide both sides by 17 )

x = 1

Substitute x = 1 into (1) for corresponding value of y

y = - 3(1) + 5 = - 3 + 5 = 2

solution is (1, 2 )

Answer:

x = 1 and y = 2

Step-by-step explanation:

y + 3x = 5 -------------> (1)

-4y + 5x = -3 -------------> (2)

(1) * 4

=> 4y + 12x = 20 --------> (3)

(3) + (2)

=> 0y + 17x = 17

=> 17x = 17

by dividing both sides by 17

=> x = 1

by putting x = 1 into (1)

=> y + 3*1 = 5

=> y + 3 = 5

=> y = 5 - 3

=> y = 2

Answer:

First Game: She wins

Second game: She loses

Third game: She loses

Step-by-step explanation:

If the graph go down she loses, if it goes up she win.

for example on the first try she won so she gets 1 point there is a dot at 1, for the second try she loses so she gets 0 points, the mean score which is (1+0)/2 is .5

on the third try she lost again so she gets another 0 point so (1+0+0)/3 = .33

and so on

Answer:

a) How many of the pets were birds and how many were fish?

Number of birds = x = 28

Number of fish = y = 202

b) Equation for pets?

x + y = 230....... Equation 1

c) Equations for cost?

9x + 4y = 1060...... Equation 2

Step-by-step explanation:

The pet store has an abundance of birds and fish and is selling them at a great price there are 230 of these pets In the store the cost for a bird is $9 and the cost per fish is $4 the store sold all the pets in a weekend blow out sale and made $1060 how many of the pets were birds and how many were fish? Equation for pets? Equations for cost?

Let us represent:

Number of birds = x

Number of fish = y

The pet store has an abundance of birds and fish and is selling them at a great price there are 230 of these pets

x + y = 230....... Equation 1

x = 230 - y

In the store the cost for a bird is $9 and the cost per fish is $4 the store sold all the pets in a weekend blow out sale and made $1060

$9 × x + $4 × y = $1060

9x + 4y = 1060...... Equation 2

We substitute 230 - y for x

9(230 - y) + 4y = 1060

2070 - 9y + 4y = 1060

Collect like terms

- 9y + 4y = 1060 -2070

-5y = -1010

y = -1010/-5

y = 202

Solving for x

x = 230 - y

x = 230 - 202

x = 28

Therefore,

Number of birds = x = 28

Number of fish = y = 202

Answer:

thank you lil shawty

Step-by-step explanation:

Answer:

7 miles per day

Step-by-step explanation:

Solve:

84 divided by 12

Check:

12 multiplied by 7

Hope this helps!

Answer: 1:13 or for every 10 games they will lose one game

Step-by-step explanation:

Answer:

19 in. and 20 in.

Step-by-step explanation:

18^2 = 18 * 18 = 324

19^2 = 19 * 19 = 361

20^2 = 20 * 20 = 400

369 is between 361 and 400, so the side of the table is between 19 in. and 20 in.

Answer:

19 in. and 20 in.

Step-by-step explanation:

18^2 = 18 * 18 = 324

19^2 = 19 * 19 = 361

20^2 = 20 * 20 = 400

369 is between 361 and 400, so the side of the table is between 19 in. and 20 in.

Answer:

They did 44 miles per hour

Step-by-step explanation:

308 / 7 = 44

Answer:

B ) c = 0.65n

Step-by-step explanation:

To find how much a single pound costs, divide the total cost by the total weight (2.60 ÷ 4). So, the cost (c), equals $0.65 per pound.

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

r/1000-(7)=0

Step by step solution :

STEP1:

r

Simplify ————

1000

Equation at the end of step1

r

———— - 7 = 0

1000

STEP 2

Rewriting the whole as an Equivalent Fraction

2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 1000 as the denominator :

7 7 • 1000

7 = — = ————————

1 1000

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

r - (7 • 1000) r - 7000

—————————————— = ————————

1000 1000

Equation at the end of step 2

r - 7000

———————— = 0

1000

STEP 3

When a fraction equals zero :

3.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

r-7000

—————— • 1000 = 0 • 1000

1000

Now, on the left hand side, the 1000 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

r-7000 = 0

Solving a Single Variable Equation:

Solve : r-7000 = 0

Add 7000 to both sides of the equation :

r = 7000

One solution was found :

r = 7000

Step-by-step explanation:

Hope it is helpful.....

Answer:

$6.76 million

Step-by-step explanation:

The computation of the profit of the year in 2011 is shown below:

Given that

In year 2007, it made $4 million profits

And it would be increased by 14% till 2011

So,

= $4 million × (1 + 0.14)^4

= $4 million × 1.68896016

= $6.76 million

Answer:

B. z+7.5 is the answer I chose

Answer:

Hose A fills at a rate of 10 gal per min

Hose B fills at a rate of 8 gal per min

Hose B fills at a faster rate

Step-by-step explanation:

Answer:

Hose A=10 gal per min

Hose B=8 gal per min

Hose A is faster

Step-by-step explanation:

A) 160 gallon/16 minutes=10 gallons per minute

B) 240 gallon/30 minutes=8 gallons per minute

Answer:

Some plants need certain things in their environment, so if their environment changes it could make the plants not grow. Animals would most likely either move to a different area or would get used to the change.

$5012.02 is the value of the car after 10 years

Depreciation is the reduction in the value of an asset over time

Given that: the present value of a car is $18,000 and it's depreciating at a rate of 12% per year

The exponential function is given as

Y= a ( 1 - r )^t

where a = present value of a car, r =  depreciation rate and t = number of years

Y = 18,000 (1-0.12)¹⁰

Y = $ 5012.02

Therefore, the value of the car after 10 years is $ 5012.02

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Answer:

the anwser is (60-50)

Step-by-step explanation:

took the test

Answer:

Y=MX+C is the equations of a straight line where C is the constant (y intercept)

Looking at a and b and the two graphs c and d

The function c represents the lowest value of the y intercept which is at -3

Answer: B (The cost of a notebook is $0.75, and the cost of a folder is $0.25.)

Step-by-step explanation:

No need for explanation. i know i’m right!!

Answer:

A y-intercept is were your line (on a graph) starts.

Answer:

39/30= 13/10

Step-by-step explanation:

You would need to make all numbers have a common denominator. The least common denominator for them is 30. So multiply the 1/6 by 5. the 4/5 by 6 and the 2/3 by 10. And the answer will come out to be a mixed number.

Answer:

The equation is d=5l

As the number of LAPS increases, the number of DOLLARS also increases

Step-by-step explanation:

Edge 2021 on assignment

Answer:

d=5l

laps

dollars

Step-by-step explanation:

i did it and its correct

Answer:

11 over 24  = 0.458

Step-by-step explanation:

Answer: 736

Step-by-step explanation: Hope that helps!!!!

Happy valentines day and have a great day!

Answer:

1/4

Step-by-step explanation:

A P E X

Answer:       I’m a goofy goober yeah your a goofy goober yeah

Step-by-step explanation:

Answer:

k = -18

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given the function

f(x) = 4(4x + 3)(x + 1)² (x^2– 3)

The x-intercept occurs at a point where f(x) = 0

f(x) = 4(4x + 3)(x + 1)² (x^2– 3)

4(4x + 3)(x + 1)² (x^2– 3) = 0

4x+3 = 0

4x = -3

x = -3/4

(x + 1)² = 0

x + 1 = 0

x = 0-1

x = -1

x^2-3 = 0

x^2 = 0+3

x^2 = 3

x  = ±√3

hence the x intercepts are -3/4, -1, √3 and -√3. This shows that there are 4 x intercepts

Answer:

1. diameter=8 kilometres

2. area=98.96 inches

3. 37m

Step-by-step explanation:

1. diameter= 2*radius

2. area of sector=θ out of 360*π[tex]r^{2}[/tex] where θ is the angle

3. area of garden=π[tex]r^{2}[/tex]

        706.5=π[tex]r^{2}[/tex]

     [tex]r^{2}[/tex]=706.5/π

        = 225(nearest whole)

     r=[tex]\sqrt{225}[/tex]=15m

we now use Pythagoras theorem to find length of each pathway

[tex]40^{2} =15^{2} +x^{2}[/tex]

1600=225+[tex]x^{2}[/tex]

[tex]x^{2}[/tex]=1600-225=1375

x=[tex]\sqrt{1375}[/tex]=37 m (to nearest whole)

The tangent pathways from the entrance form right triangles from which

the length of the pathway which are the sides of the triangle, can be found.

Reasons:

1. The radius of the particle accelerator = 4 kilometers

The diameter of the particle accelerator = 2 × The radius

Therefore;

The diameter = 2 × 4 km = 8 km

The accelerator's diameter is 8 kilometers

2. The area of a sector of a circle is A = [tex]\displaystyle \frac{\theta}{360^{\circ}} \times \pi \cdot r^2[/tex]

The angle subtended by the sector, θ = 140°

The radius of the sector, r = 9 inches

Therefore;

[tex]\displaystyle A = \frac{140^{\circ}}{360^{\circ}} \times \pi \times 9^2 = \mathbf{ 31.5 \cdot \pi}[/tex]

The area of the shaded sector, A = 31.5·π in.² ≈ 98.96 in.²

3. The distance from the center to the main entrance, d = 40 m

Area of the circular garden, A = 706.5 m²

Solution:

The radius of the garden, r = √(A ÷ (π))

Therefore;

r = √(706.5 ÷ (π)) ≈ 15

The tangent pathways are perpendicular to the radius of the circular garden.

Therefore, the pathway from the entrance, the 40 m. distance from the center to the entrance and the radius form a right triangle.

Where;

The 40 m. distance = The hypotenuse side

By Pythagorean theorem, we have;

40² = r² + (Length of the pathway)²

Which gives;

40² = 15² + (Length of the pathway)²

Length of the pathway ≈ √(40² - 15²) ≈ 37.1

The length of each pathway is approximately 37.1 m.

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