Given the following:

Measurement Reaction 1 (Mg + HCl)
Mass of HCl (g) 100.50
Mass of solid (g) 0.20
Total mass of reactants, m (g) (add the masses above) 100.70
Initial Temperature (°C) 22.5
Temperature furthest from initial temperature(°C) 31.3
∆T(°C) Subtract the two temperatures above) 8.8

Given Reaction 1: Mg(s) + 2HCl(aq) ⟶ MgCl2(aq) + H2(g)

What is the ∆H (kJ/mol)?

question 1 water question 2 instant tea question 3 mixture

Answer:

Explanation:

TiO2 + C + 2 CI2 → TiCI4 + CO2

(a)

(2.16 mol TiO2) x (2 mol CI2 / 1 mol TiO2) x ( 70.9064 g C/mol) = 306 g CI2

(b)

(2.16 mol TIO2) x (1 mol C / 1 mol TiO2) x ( 12.01078 g C/mol)n= 25.9 g C

(c)

Use the law of conservation of mass:

(2.16 mol TiO2) x ( 79.8660 g TiO2/mol) + (306 g CI2 + 25.9 g C = 504 g total.

Hope this help!:)

Answer:

16.9 mmoles are needed to add to the solution

Explanation:

To solve this, we can apply the Henderson Hasselbach equation:

Acetic acid → CH₃COOH

CH₃COOH  +  H₂O  ⇄  CH₃COO⁻   +  H₃O⁺             Ka

That is the acid base equilibrium, to determine the amount:

pKa of acetic acid is 4.74

Henderson Hasselbach formula is:

pH = pKa + log (base/acid)

We replace  →  4.97 = 4.74 + log (B / 10mmoles)

Let's verify mmoles of B

4.97 - 4.74 = log (B/10)

0.23 =  log (B/10)

10^(0.23) = 10^(log (B/10)

1.698 = B/10

B = 1.698 . 10 → 16.9 mmoles

Answer:

The correct answer is - yes, 4.57 g of solute per 100 ml of solution

Explanation:

The correct answer is yes we can calculate the solubility of X in the water at 22.0°C. The salt will remain after the evaporate from the dissolved and cooled down at 26°C.

Then, the amount of solute dissolved in the 700 ml solution at 26°C is the weighed precipitate: 0.032 kg = 32 g.

Then solublity will be :

32. g solute / 700 ml solution = y / 100 ml solution

⇒ y = 32. g solute × 100 ml solution / 700 ml solution = 4.57 g.

Thus, the answer is 4.57 g of solute per 100 ml of solution.

10 joules

hope that helps^^

Answer:

10 joules im not sure tho

Answer:

3 atoms

Explanation:

there is one calcium and two chlorine

Answer:

The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.

The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.

Domain and range restrictions must be observed.

Explanation:

Calibration curves are tools necessary in understanding the instrumental response for any analyte.

A calibration curve is obtained by preparing a set of  standard solutions with known concentrations of the analyte. The instrument response for each concentration is measured  and plotted against the concentration of the standard solution. The linear portion of this plot may be used to determine the unknown concentration of a sample of the analyte.  

The equation of the best-fit line is  used to determine the concentration of the unknown sample.

Answer:

-86.02 kJ/ mole

Explanation:

The moles of the acid used = Molarity × Volume (L) =

= 0.50 (0.0372 L)

= 0.0186 moles

The heat released = -1.6 kJ

∴ 0.0186 moles neutralization of HA heat is: -1.6 kJ

The molar heat of neutralization due to one mole of the unknown acid = -1.6/0.0186

= -86.02 kJ/ mole

The molar heat of neutralization for the unknown acid is -86.02 kJ/ mole.

The moles of the acid used = Molarity × Volume (L) =

= 0.50 (0.0372 L)

= 0.0186 moles

Thus, the moles of the acid used is 0.0186.

The heat released = -1.6 kJ

Thus,  0.0186 moles neutralization of HA heat is: -1.6 kJ

Molar heat of Neutralization: It is the amount of heat each mole of base added to the acid (or vice versa) causes the reaction to give off.

The molar heat of neutralization due to one mole of the unknown acid = [tex]\frac{-1.6}{0.0186}=-86.02kJ/mole[/tex]

So, the molar heat of neutralization is -86.02kJ/mole.

Find more information about Moles here:

brainly.com/question/13314627

Answer:

The correct one is dynamite fishing

Answer:

1700 mL / 84 mLs

Explanation:

Given that:

Volume of blood pumped per minute = 84 /mLs

Time it takes to circulate 1700 mL of blood :

Time taken = Volume of blood circulate / Rate

Hence, to circulate 1700 mL of blood :

Time taken = 1700 mL / 84 mLs

Answer: the baseball bat transfor its energy in the ball.

Explanation: you hit it with one and find out and tell me what you think what happen.

Answer:

Hydrogen 2 is called deuterium, Hydrogen 3 is called Tritium

Explanation:

Hydrogen is the only element whose isotopes have different names in common use today: the 2H (or hydrogen-2) isotope is deuterium and the 3H (or hydrogen-3) isotope is tritium.

Answer:

MgO +H2SO4

Explanation:

use photomath

Explanation:

number of moles = mass /relative molecular mass

n = 25,92/mr(N2)

n=25,92/14×2

n=25,92/28

n=0.93moles

Answer:

If all the objects are placed at the same angle.

Explanation:

If all the objects are placed at the same angle so all the light from the flashlight shine comes back to the flashlight. If the A object is placed at the specific location at which the mirror X reflects the light after hitting it, then the other E object is placed at the location where the light comes after reflecting the A object then the light comes back to the flashlight if the angle between objects placement is right.

Answer:

d

Explanation:

Answer:

?????

Explanation:

...? what...?

Answer:

A.

1.5

B

Explanation:

Answer:

Hello the table required is missing attached below is the missing table

Answer : 1299.05 k

Explanation:

Given data :

concentration of carbon ( Cx ) at a position 3.9mm below surface = 0.35

concentration of carbon ( Co ) = 0.20

surface carbon ( Cs ) = 1

Determine the temperature at which the treatment was carried out

first we will determine the value of Z in the table attached

given that the value of erf ( Z ) for Z = 0.8125 from the table

= [tex]\frac{Z- 0.9}{0.95-0.9} = \frac{0.8125-0.797}{0.8209-0.797}[/tex]

 make Z subject of the equation

Z = 0.932

next calculate the diffusion coefficient using the relation below

Z = [tex]\frac{x}{2\sqrt{Dt} }[/tex]   ----- ( 1 )  where ; z = 0.932 , x = 3.9 mm , t = 48h

0.932 =

x = 3.9 mm = 0.0039 m

t = 48 h = ( 48 *60* 60 ) = 172800 secs

Insert values into equation 2

0.932 = [tex]\frac{0.0039}{2\sqrt{D * 172800} }[/tex]  

[tex]\sqrt{D*172800}[/tex] = (0.0039 / 0.932 ) / 2

      172800 * D  =( 0.0021 )^2

therefore D = 2.55 * 10^-11 m^2/s

Finally calculate the temperature at which the treatment was carried out

D = [tex]Do exp(\frac{-Qd}{RT} )[/tex]  ----- ( 3 )

D = 2.55 * 10^-11 m^2/s ,

Do = 2.3*10^-5  m^2/s ( gotten from Diffusion data table )

Qd = 148000 J/mol ( gotten from Diffusion data table )

R = 8.31 J/mol k ( gotten from Diffusion data table )

back to equation 3

D / Do = exp ( -17810 / T )

1.11 * 10^-6 = exp ( -17810 / T )

therefore T =  -17810 / ln( 1.11 * 10^-6 )

                   = - 17810 / -13.71  =   1299.05 k

Answer:

Vascular tissue transports water, minerals, and sugars to different parts of the plant. Vascular tissue is made of two specialized conducting tissues: xylem and phloem. Xylem tissue transports water and nutrients from the roots to different parts of the plant, and also plays a role in structural support in the stem.

Explanation:

HOPE THIS HELPS!

Answer:

1.47 atm

Explanation:

Step 1: Given data

Step 2: Calculate the final pressure of the gas

We can calculate the final pressure of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

P₂ = P₁ × V₁ × T₂ / T₁ × V₂

P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm

Answer:

im not doing your whole homework. but ill give you  one cent ;>, whats ur paypal

Explanation:

Answer:

snow is made up of a variety of mostly organic matter, including dead or dying animals and phytoplankton, protists, fecal matter, sand, and other inorganic dust.

Explanation:

I hope I helped!!

Plz mark me brainliest it would really make my day!

Answer:

I think its organic unless we are talking about this snow storm then no

The dicotyledons, also known as dicots, are one of the two groups into which all the flowering plants or angiosperms were formerly divided. The name refers to one of the typical characteristics of the group, namely that the seed has two embryonic leaves or cotyledons.

28 mol CaF

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 1.7 × 10²⁵ molecules CaF

[Solve] moles CaF

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

28.2298 mol CaF ≈ 28 mol CaF

Answer:

6.4g

Explanation:

32g of O2 produce 36g of H2O/5.70g of O2 produce x the answer is 6.4g

Answer:

ionic compound

Explanation:

An ionic compound and a covalent compound react differently when dissolved in water (H2O).

The ionic compounds when dissolved in H2O, undergo a physical change called dissociation. In this change the molecules of water surround the ionic compound and ions of ionic compound disperse  uniformly in the water. The complete dissociation of ionic compounds in H2O makes it a strong electrolyte and solution will conduct an electric current.

Some of the covalent compounds also conduct electricity as when they dissolve in H2O, the molecule of covalent compound react chemically with the solvent to produce ions. Generally, covalent compounds are weak electrolytes and do not conduct much electricity as ionic compounds but exception are their such as HCl and benzene.

Answer:

A Brønsted-Lowry acid.

A Brønsted-Lowry base.

Ammonia is an acceptor of proton.

Explanation:

A Brønsted-Lowry acid is any atom that can donate a proton (H +) to another atom or molecule whereas Brønsted-Lowry base is any species that can accept a proton from another atom or molecule or in other words, a Brønsted-Lowry acid is a proton donor, while on the other hand, a Brønsted-Lowry base is a proton acceptor. The ammonia molecule accepts the hydrogen ion is considered as the Brønsted-Lowry base.