Given: a || b, transversal k
Prove <3 = <6

Answer:

7

Step-by-step explanation:

for you to get the missing number just take the complete numbers and minus them then you'll get the incomplete digit needed good day.

Answer:

[tex] \sqrt{10} [/tex]

Step-by-step explanation:

Rule: [tex] \sqrt{a} \times \sqrt{b} = \sqrt{ab} [/tex]

[tex] \sqrt{5} \times \sqrt{2} = \sqrt{5 \times 2} = \sqrt{10} [/tex]

Answer:

A^32

Step-by-step explanation:

Done

Answer:

Option D:  a³²

Step-by-step explanation:

Powers in this case multiply, 8*4=32

therefore answer D a³² is correct

Answer:

12 + [tex]4\sqrt{5}[/tex] approximates to 20.944

Step-by-step explanation:

VU - 8 units

UW - 4 units

VW - [tex]\sqrt{64+16} = \sqrt{80} =4\sqrt{5}[/tex]

12 + 4sqrt(5)

Answer:

6 (2 + √5) units

Step-by-step explanation:

Finding the length of the 3rd side :

*Applying Pythagorean Theorem*

The perimeter :

Answer: 180

Step-by-step explanation: 200 % 2 = 100

9/10 = 90/100

90 * 2 = 180

Answer:

20 students

If 9 out of 10 student prefer math over lunch, then 1 out of ten DO NOT. With this information you can set up a simple proportion: [tex]\frac{1}{10} =\frac{x}{200}[/tex].

To solve for x, you cross multiply as follows:

1*200=10x

200=10x

20=x

Hence, x equals 20, and 20 students do not prefer math over lunch.

Hope I helped!!!!!!!!!!!!!:)

Composite functions occur when we take two functions and input one into the other as x.

Example:

[tex]f(x) = 2x[/tex]

[tex]g(x) = 3x^2[/tex]

[tex](f\circ g)(x)=f(g(x))[/tex]

[tex](f\circ g)(x) = 2(3x^2)[/tex]

We're given:

To find [tex](f\circ g)(x)[/tex], input g into f as x:

[tex]f(x)= 3x +2[/tex]

[tex](f\circ g)(x)=3(x^2+1) +2\\(f\circ g)(x)=3x^2+3 +2\\(f\circ g)(x)=3x^2+5[/tex]

[tex](f\circ g)(x)=3x^2+5[/tex]

Hassan is incorrect because √0.15  is less than 0.4, and the value of  √0.15 is 0.3872 option third is correct.

Iteration is the process of repeating a procedure in order to produce a series of results.

We have:

= √0.15

[tex]= \rm \sqrt{{\dfrac{15}{100}}}[/tex]

[tex]= \rm \sqrt{{\dfrac{3}{20}}}[/tex]

= (1.732)/(4.472)

= 0.3872

√0.15 is less than 0.4.

Thus, Hassan is incorrect because √0.15  is less than 0.4, and the value of  √0.15 is 0.3872 option third is correct.

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Answer:

C

Step-by-step explanation:

Answer:

Given - AC is parallel to DE

angle 3y + 28 = angle X ( Vertically opposite angles are equal).

3y + 28 = X

X + Y = 180° ( supplementary angles).

3y - X = (-28)

Solving both the equation we get

multiply eq 1 with 3

3x + 3y = 540

-X + 3y = (-28)

subtracting

4x = 568

x = 142°

3y + 28 = 142

3y = 142 - 28

3y = 114

y = 38°

Answer:

2200 + 0.5x >= 2500

Step-by-step explanation:

x is the amount of sales

The least number of sweaters that must be produced each hour to earn a profit of at least $100 is 37.

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have:

A clothing manufacturer produces one type of sweater that earns $4 profit for each one sold.

Let x be the number of sweaters that must be produced each hour to earn a profit of at least $100

Total selling price if earns $4 profit for each one sold = 4x

The expenses for running the machine are $45 per hour.

4x - 45 ≤ 100

4x ≤ 145

x ≤ 145/4

x ≤ 36.25

Number of sweater(estimate value) = 37

Thus, the least number of sweaters that must be produced each hour to earn a profit of at least $100 is 37.

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The list of equations is shown in the picture which equation has No Solution, One Solution, and Infinitely Many Solutions.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have given a linear equation in one variable.

[tex]\rm \dfrac{1}{2}y + 3.2y = 20[/tex]

After solving:

y = 5.40   (one solution)

[tex]\rm \dfrac{15}{2}+ 2z -\dfrac{1}{4}=4z+\dfrac{29}{4} -2z[/tex]

After solving:

[tex]\rm \dfrac{15}{2} -\dfrac{1}{4}=\dfrac{29}{4}[/tex]

[tex]\rm \dfrac{29}{4}=\dfrac{29}{4}[/tex] (Infinitely Many Solutions)

3z + 2.5 = 3.2 + 3z

2.5 = 3.2  (no solution)

Similarly, we can identify which equation has No Solution, One Solution, and Infinitely Many Solutions.

Thus, the list of equations is shown in the picture which equation has No Solution, One Solution, and Infinitely Many Solutions.

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Answer:

7, 616 because there is no floating point

Answer:

an= -3+5(n-1)

Step-by-step explanation:

Try writing out the terms and finding a pattern. In this case, inserting any plotted x-value into the sequence -3+5(n-1) produces the correct y-value.

Answer:

A.) an = -3 + 5(n - 1)

Explanation:

Given: (1, -3), (2, 2), (3, 7), (4, 12), (5, 17)

Arithmetic Series: a + (n - 1)d

['a' is first term, 'n' determines term position, 'd' is common difference]

Determine the following:

Putting into equation:

Answer:

56

Step-by-step explanation:

all your doing is removing the .053 to get your whole number

Answer:

Last choice, [tex]\sqrt{15}[/tex] is irrational and [tex]\sqrt{0.001}[/tex] is rational

Step-by-step explanation:

Rational Numbers: Any number that can be written as a ratio (or fraction) of two integers, ex. 0.4

Irrational Numbers: A type of real number which cannot be represented as a simple fraction (non ending decimal), ex. 0.4161446

[tex]\sqrt{15} = 3.8729[/tex] making it irrational

[tex]\sqrt{0.001} = 1/1000[/tex] making it rational

Hence, the last choice is correct

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The merchant needs to fill 60 litres of all types of oils .

What is HCF ?

HCF is the highest common factor, it is the factor in common in more than two numbers.

It is given in the question that

A merchant has 120 litres of oil of one kind, 180 litres of another kind, and 240 litres of the third kind.

He wants to sell the oil by filling the three kinds of equal capacity.

To find the greatest capacity of such a tin , we have to find the highest common factor of the individual capacity.

120=2×2×2×3×5

180=2×2×3×3×5

240=2×2×2×2×3×5

HCF=2×2×3×5=60

The greatest capacity = 60 litres

So the merchant needs to fill 60 litres of all types of oils .

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Answer:

[tex]\textsf{C.} \quad \left(3,\dfrac{5}{2}\right)[/tex]

Step-by-step explanation:

Midpoint between two points

[tex]\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)[/tex]

Define the endpoints of the line segment:

[tex]\textsf{Let }(x_1,y_1)=(-1,2)[/tex]

[tex]\textsf{Let }(x_2,y_2)=(7,3)[/tex]

Substitute the defined endpoints into the midpoint formula and solve:

[tex]\implies \textsf{Midpoint}=\left(\dfrac{7+(-1)}{2},\dfrac{3+2}{2}\right)[/tex]

[tex]\implies \textsf{Midpoint}=\left(3,\dfrac{5}{2}\right)[/tex]

Midpoint

Answer:

Or if you don't want any rounding it will be 115.38461538461

Therefore the f is continuous on R , i.e. real numbers and f is not differentiable at 0 ,Option A and D is the correct answer.

A function is a mathematical statement which find relation between independent variable and dependent variable.

It always comes with a defined range and domain.

It is given that :

[tex]\rm f(x) = x^{1/3}\\\\LHD (at\; x = 0) = RHD (at \; x = 0)\\\\\= \lim_{x\rightarrow 0}\dfrac{f(x)-f(0)}{x-0}\\\\=\lim_{h\rightarrow 0}\dfrac{f(0-h)-f(0)}{0-h-0}[/tex]

[tex]=\lim_{h\rightarrow 0}\dfrac{f(0-h)-f(0)}{0-h-0} \\\\= \lim_{h\rightarrow 0}\dfrac{(-h)^{1/3}}{-h}\\\\\lim_{h\rightarrow 0}\dfrac{(-1)^{1/3}(h)^{1/3}}{-1*h}\\\\\lim_{h\rightarrow 0} (-1)^{-2/3}h^{-2/3}[/tex]

if we substitute h = 0 ,

Here, LHD and RHD does not exist at x = 0 So, f(x) is not differentiable at x = 0 .

Therefore the f is continuous on R , i.e. real numbers

and f is not differentiable at 0

Option A and D is the correct answer.

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The changes in account balances for Elder Company for 2021 are net income will be $160000

We have given debt common stock = $680000

Credit liabilities = 350000

Credit paid in capital = 190000

And an excess of par 30,000 credit Assuming the only changes in retained earnings

So 680000 = 350000+190000+30000+ retained earning

Net income is an entity's income minus the cost of goods sold, expenses, depreciation and amortization, interest, and taxes for an accounting period.

So retained earning = $110000

Dividend paid = $50000

So Net income = dividend paid + retained earning

Net income = $110000+$50000

Net income = $160000

So option (c) will be the correct answer.

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Answer:

y = 2

Step-by-step explanation:

Addition Method:

4x - 2y = 6

2x + y = 7

-2(2x + y) = -2(7)

4x - 2y = 6

-4x - 2y = -14

-4y = -8

y = 2

Substitution Method:

4x - 2y = 6

2x + y = 7

-2y = 6 - 4x

2y = 4x - 6

y = 2x - 3

2x + (2x - 3) = 7

4x - 3 = 7

4x = 10

x = 2.5

2(2.5) + y = 7

5 + y = 7

y = 2

Brainliest, please :)

Answer:

look the attachment in the above

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: x = 3[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: log_{2}(x - 1) log_{2}(x + 5) = 4[/tex]

[tex]\qquad \tt \rightarrow \: log_{2} \{(x - 1)(x + 5) \} = 4[/tex]

[ log (x) + log (y) = log (xy) ]

[tex]\qquad \tt \rightarrow \: ( x - 1)(x + 5) = {2}^{4} [/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 5x - x - 5 = 16[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 4x - 5 - 16 = 0[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 4x -21 = 0[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 7x - 3x - 21 = 0[/tex]

[tex]\qquad \tt \rightarrow \: x(x + 7) - 3(x + 7) = 0[/tex]

[tex]\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0[/tex]

[tex]\qquad \tt \rightarrow \: x = - 7 \: \: or \: \: x = 3[/tex]

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

[tex]\qquad \tt \rightarrow \: x = 3[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The transformation of a function may involve any change. The transformation of the function is Right shift by 90 units.

The transformation of a function may involve any change.

Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs) etc.

If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:

Horizontal shift (also called phase shift):

Left shift by c units:

y=f(x+c) (same output, but c units earlier)

Right shift by c units:

y=f(x-c)(same output, but c units late)

Vertical shift:

Up by d units: y = f(x) + d

Down by d units: y = f(x) - d

Stretching:

Vertical stretch by a factor k: [tex]y = k \times f(x)[/tex]

Horizontal stretch by a factor k: [tex]y = f\left(\dfrac{x}{k}\right)[/tex]

Since the function is transformed from f(x)=x to g(x)=x-90, therefore, the transformation of the function is Right shift by 90 units.

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Answer: (1, -4) or y = -4

Step-by-step explanation:

    Given:

y = 3x - 7

    Plug in the value of 1 for x - given to us by "(1, ?)

y = 3x - 7

y = 3(1) - 7

    Multiply:

y = 3 - 7

    Subtract:

y = -4

               y = -4

Answer:

OD.(x-3)(x-2)

Step-by-step explanation:

we need two numbers (negative ir positive) that multiply to get 6 abd add to get -5.

so its OD

as -3×-2=6

and -3+-2=-5

Answer:

(6,4)

Step-by-step explanation:

^^^

Answer:

470.88 N

Step-by-step explanation:

F = ma

  48 ( 9.81) = 470.88 N      ( 105.958 lbs)

Answer:

this is pretty easy we just replace the x with -1 so

(-1)^2+(-1)9+10

-1*-1=1

-1*9=-9

1+-9=-8

-8+10=2

f(-1)=2

Hope This Helps!!!