Genie is making cookies and brownies. Each cookie uses 8 grams of flour and each brownie uses 12 grams of flour. She wants to
make more than 125 cookies and brownies altogether. If Genie has a total of 2,000 grams of flour, which system of inequalities
models correctly the number of cookies, c, and brownies, b, she can make
A)
C + b > 125
8C + 12b = 2000
B)
C + b 2 125
8C + 12b = 2000
C)
C + b < 125
8C + 12b = 2000
D
D)
C + b S 125
8C + 12b = 2000

The left side is equivalent to

[tex]\displaystyle \sum_{k=1}^n \frac1{k(k+1)}[/tex]

When n = 1, we have on the left side

[tex]\displaystyle \sum_{k=1}^1 \frac1{k(k+1)} = \frac1{1\cdot2} = \frac12[/tex]

and on the right side,

[tex]1 - \dfrac1{1+1} = 1 - \dfrac12 = \dfrac12[/tex]

so this case holds.

Assume the equality holds for n = N, so that

[tex]\displaystyle \sum_{k=1}^N \frac1{k(k+1)} =1 - \frac1{N+1}[/tex]

We want to use this to establish equality for n = N + 1, so that

[tex]\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac1{N+2}[/tex]

We have

[tex]\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = \sum_{k=1}^N \frac1{k(k+1)} + \frac1{(N+1)(N+2)}[/tex]

[tex]\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac1{N+1} + \frac1{(N+1)(N+2)}[/tex]

[tex]\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac{N+2}{(N+1)(N+2)} + \frac1{(N+1)(N+2)}[/tex]

[tex]\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac{N+1}{(N+1)(N+2)}[/tex]

[tex]\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac1{N+2}[/tex]

and this proves the claim.

Answer:

The length is 16 and the width is 19.

Step-by-step explanation:

We'll represent width with the letter w, and length with l.

w = l + 3

The perimeter is all four sides, so perimeter = 70ft = (2w) + (2l)

We will replace w with l + 3.

70 = 2(l + 3) + (2l)

2 (l + 3) = (l + 3) + (l + 3)

and 2l = l + l, so

70 = l + 3 + l + 3 + l + l = 4l + 6

We subtract 6 from both sides.

64 = 4l

then we divide both sides by 4

16 = l

Remember width = length + 3, so

16 + 3 = w

19 = w

Just to check:

2(length) + 2(width) = perimeter

2(16) + 2(19) = 70

32 + 38 = 70

Answer:

64

Step-by-step explanation:

because the formula for the volume of a cube is edge (4) to the power of 3

4 to the power of 3 is 64

Answer:

3

Step-by-step explanation:

Answer:

(23)(39)

Step-by-step explanation:

When you have to look for the "product" of two numbers, it implies multiplication.

With this, get rid of 23 + 39 = 62 as an answer.

Now simply enough, multiply 23 by 39,

23 * 39 = 897

Meaning that A. (23)(39) = 897 is the answer.

Answer:

the slope is 4/5. y-intercept: ( 0,-2)

Step-by-step explanation:

I hope this is what you wanted!!

Answer:

x>99/4

Step-by-step explanation: hope this helps :)

3/4x+2/3x

1 5/12x

Step-by-step explanation:

9/12x + 8/12x= 17/12x = 1 5/12x

Full question

8. Which of the following is NOT a role of gravity in erosion?

A. It moves glaciers down slope.

C. In mountains, it moves down large slabs of rocks.

D. It acts as agents of mass wasting like landslides, fall, mudflows, and avalanches​

Answer:

4

Step-by-step explanation:

(x1,y1)(x2,y2)

(2,8)   (0,0)

0-8 / 0-2 = -8/-2

simplify -8/-2 = 4

Answer:

4.

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

-  that is rise / run.

We use the points (2, 8) and (2,0) ( - the last point is vertically below (2,8) and is on the x axis)

Here y2 = 8, y1 = 0, x2 = 2 and x1 = 0.

So the slope = (8-0)/(2-0)

= 4

Answer:

TanQ=20/21

Step-by-step explanation:

since we know that

TanQ= opposite/Adjacent

so we are going to calculate for the adjacent using Pythagoras theorem

a^2+b^2=c^2

20^2+b^2=29^2

400 + b^2=841

b^2=841-400

√b^2=√441

b=21

so our tanQ= opp/adj

tanQ=20/21

Answer:

x>1

Step-by-step explanation:

20 < 5x +15

20 - 15 < 5x

5 < 5x

1< x

x>1

Answer:

we have the sides of the triangle, which are 14, 5, and 12 inches.

in a right angled triangle, the longest side is the hypotenuse

and pythagoras’s theorem is used/ can be used.

a^b + b^2 = c^2 where c is the hypotenuse

so we know a = 12, b = 5, and c = 14

now check whether the statement is true

we should get c = 14 if it’s a right triangle

12^2 + 5^2 = c^2

144 + 25 = c^2

169 = c^2

√169 = 13 = c

so since we got 13 for c and it’s not 14

we know that this isn’t a right angled triangle

Answer:32.5

Step-by-step explanation:

Using triangle concepts, it is found that the length of the third side of Damaris’s triangle could be any value greater than 3 inches and less than 15 inches.

In a triangle, the sum of the lengths of the two smaller sides has to be greater than the length of the greater side.

Considering 6 inches and 9 inches the smallest sides:

[tex]x < 6 + 9[/tex]

[tex]x < 15[/tex]

Considering 9 inches as the greater side:

[tex]x + 6 > 9[/tex]

[tex]x > 9 - 6[/tex]

[tex]x > 3[/tex]

The length of the third side of Damaris’s triangle could be any value greater than 3 inches and less than 15 inches.

A similar problem is given at https://brainly.com/question/24175053

Answer:

B.Between 2 and 3

Step-by-step explanation:

60÷40

=3/2

No, -1 is less than 32.

-1<32

-1 is in the negatives, so its less

Hope that helped:)

[tex]\red{➤}\:[/tex][tex]\sf \dfrac{6+8x}{2} = 5x[/tex]

[tex]\\[/tex]

[tex]\orange{☛}\:[/tex][tex]\sf Value \:of \: x [/tex]

[tex]\\[/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf \frac{6+8x}{2} = 5x \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 6+8x= 5x×2 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 6+8x= 10x \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 8x-10x= -6 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf -2x = -6 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf x = \frac{-6}{-2} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\quad\longrightarrow\quad\boxed{\sf {x = 3}} \\\end{gathered} [/tex]

On Transfering the terms to other side of equation-

+ changes to -

- changes to +

× changes to ÷

÷ changes to ×

Step-by-step explanation:

[tex] = \lim \limits_{x \to - 4} \frac{ \sqrt{x + 20} - \sqrt{12 - x} }{ {x}^{2} + 3x - 4 } [/tex]

[tex] = \lim \limits_{x \to - 4} \frac{ \sqrt{x + 20} - \sqrt{12 - x} }{(x + 4)(x - 1)} \times \frac{ \sqrt{x + 20} + \sqrt{12 - x} }{ \sqrt{x + 20} + \sqrt{12 - x } } [/tex]

[tex] = \lim \limits_{x \to - 4} \frac{ {( \sqrt{x + 20} )}^{2} - {( \sqrt{12 - x} )}^{2} }{(x + 4)(x - 1)( \sqrt{x + 20} + \sqrt{12 - x} )} [/tex]

[tex] = \lim \limits_{x \to - 4} \frac{x + 20 - 12 + x }{(x + 4)(x - 1)( \sqrt{x + 20} + \sqrt{12 - x} )} [/tex]

[tex] = \lim \limits_{x \to - 4} \frac{2x + 8}{(x + 4)(x - 1)( \sqrt{x + 20} + \sqrt{12 - x} )} [/tex]

[tex] = \lim \limits_{x \to - 4} \frac{2 \cancel{(x + 4)}}{ \cancel{(x + 4)}(x - 1)( \sqrt{x + 20} + \sqrt{12 - x} )} [/tex]

[tex] = \lim \limits_{x \to - 4} \frac{2}{(x + 1)( \sqrt{x + 20} + \sqrt{12 - x} )} [/tex]

[tex] = \frac{2}{( - 4 + 1)( \sqrt{ - 4 + 20} + \sqrt{12 + 4} ) } [/tex]

[tex] = \frac{2}{( - 3)( \sqrt{16} + \sqrt{16}) } [/tex]

[tex] = \frac{2}{( - 3)(4 + 4)} [/tex]

[tex] = \frac{2}{( - 3)(16)} [/tex]

[tex] = \frac{1}{( - 3)(8)} [/tex]

[tex] = - \frac{1}{24} [/tex]

Answer:

He can sell 12 bracelets.

Step-by-step explanation:

6.35/0.5 will give u your answer!

Answer:

+5%

Step-by-step explanation:

Trayvon's guess, 63, is 3 higher than the actual number of balls.  We compare 3 to 60:  3/60, or 1/20.  Multiplying this result by 100%, we get 5%.  The percent error is 5%.

Answer:

Step-by-step explanation:

Because he do be sussing

Answer:

The answer is C. 6

Step-by-step explanation:

36/6=6

or

6x6=36

42/7=6

or

7x6=42

I hope this helped. I wouldn't mind a brainlist either!

Answer:

Two parallel lines

Step-by-step explanation:

the slopes are the same: slope = 3

f(x) 3x + 5                          g(x) = 3x - 2

Pick at least three x values and find their corresponding values for y. Remember the f(x)  and g(x) represent y

                                   f(x) = 3x + 5                           g(x) = 3x - 2

                                    y = 3x + 5                              y = 3x - 2

let x = 0                       y = 3(0) + 5                              y = 3(0) - 2

                                     y = 5                                         y   =  -2

Ordered pair                (0, 5)                                        (0, -2)

Let x = 1                      y = 3(1) +5                                y  = 3(1) - 2

                                  y = 8                                         y = 1

ordered pair                (1, 8)                                        (1, 1)

Let x = -1                  y = 3(-1) + 5                               y = 3(-1) - 2                  

                                  y = 2                                        y =  -5

ordered pair             (-1, 2)                                         ( -1, -5)

Locate the ordered pairs and draw the graph on the lines.  

you will graph two parallel lines