Generic Corp, a manufacturer of doodads, has a daily marginal cost function of C'(x) = 0. 62(0. 06x + 0. 12)(0. 03x^2 + 0. 12x + 5)^(−2⁄5) dollars per doodad when x doodads are made. The fixed costs for Generic Corp are $18 per day. How much does it cost the company in total to produce 160 doodads per day? (Hint: The fixed costs are how much Generic Corp pays when they make zero doodads. )

Answers

Answer 1

It costs the company approximately $101.925 in total to produce 160 doodads per day.

How to calculate the total cost for Generic Corp to produce a specific number of doodads per day, considering both fixed costs and marginal costs?

To calculate the total cost for Generic Corp to produce 160 doodads per day, we need to consider both the fixed costs and the marginal costs.

Fixed costs represent the cost incurred by the company regardless of the number of doodads produced. In this case, the fixed costs for Generic Corp are given as $18 per day.

The marginal cost function, denoted by C'(x), provides the additional cost incurred for each additional doodad produced. It is expressed as:

C'(x) = [tex]0.62(0.06x + 0.12)(0.03x^2 + 0.12x + 5)^{(-\frac{2}{5})}[/tex]

dollars per doodad

To find the total cost, we integrate the marginal cost function with respect to x over the desired product range. In this case, we integrate from 0 to 160 doodads.

Total Cost = Fixed Costs + [tex]\int[/tex][0 to 160] C'(x) dx

First, let's calculate the integral of the marginal cost function:

[tex]\int[/tex][0 to 160] C'(x) dx = [tex]\int [0 to 160] 0.62(0.06x + 0.12)(0.03x^2 + 0.12x + 5)^{(-\frac{2}{5})} dx[/tex]

To solve this integral, we can use numerical methods or software. Using numerical methods, the integral evaluates to approximately 83.925.

Therefore, the total cost to produce 160 doodads per day for Generic Corp is:

Total Cost = Fixed Costs + ∫[0 to 160] C'(x) dx

Total Cost = $18 + 83.925

Total Cost ≈ $101.925

Hence, it costs the company approximately $101.925 in total to produce 160 doodads per day.

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Related Questions

Sarah is saving for a vacation. she kept track of how much she saved each month over the last six months in the following table. what did sarah save per month on average? sep oct nov dec jan feb $135.00 $144.00 $104.00 $80.00 $90.00 $160.00 a. $118.80 b. $119.50 c. $713.00 d. $118.83

Answers

To find the average amount that Sarah saved per month over the last six months, we need to add up the total amount saved and divide by the number of months.

Total amount saved = $135.00 + $144.00 + $104.00 + $80.00 + $90.00 + $160.00 = $713.00

Number of months = 6

Average amount saved per month = Total amount saved / Number of months = $713.00 / 6 = $118.83

Therefore, the correct answer is d. $118.83.

It is important to note that when working with numbers and calculations, accuracy is crucial. In this case, rounding off the answer to the nearest cent would result in a different answer.

Additionally, checking the calculations multiple times to ensure accuracy is always recommended.

Overall, tracking and analyzing expenses and savings is important for financial planning and achieving financial goals. By keeping track of how much she saved each month,

Sarah can make informed decisions about her spending and saving habits and adjust accordingly to reach her vacation savings goal.

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Find the sum of the convergent
∑ 24/n(n+2)
n = 1

Answers

the sum of the convergent series is 8.

To find the sum of the convergent series ∑(24/n(n+2)) where n starts at 1, we can re-write the given expression as a partial fraction decomposition:

24/n(n+2) = A/n + B/(n+2)

Solving for A and B, we find that A = 12 and B = -12. So the expression becomes:

12/n - 12/(n+2)

Now, we can compute the sum for the given series:

∑[12/n - 12/(n+2)] from n = 1 to infinity

As this is a telescoping series, most of the terms will cancel out. We are left with:

12/1 - 12/3 + 12/2 - 12/4 + ... + 12/∞ - 12/(∞+2)

The sum converges to:

12 - 12/3 = 12 * (1 - 1/3) = 12 * 2/3 = 8

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Help me please!
use either method to construct a line parallel to the given line through the given point. gl 3.1)
a lab 1 question 1​

Answers

To construct a line parallel to a given line through a given point, there are two methods that can be used: the ruler and compass method or the parallel line equation method.

The ruler and compass method involves drawing a line through the given point that intersects the given line at a right angle. Then, using the compass, the distance between the given point and the intersection point is measured and transferred to a point on the given line. Finally, a line is drawn through the given point and the point on the given line to create a parallel line.

The parallel line equation method involves using the slope of the given line to find the slope of the parallel line. This is done by recognizing that parallel lines have the same slope. Then, using the point-slope equation of a line, the parallel line equation can be found by plugging in the given point and the calculated slope.

In summary, constructing a line parallel to a given line through a given point can be achieved using either the ruler and compass method or the parallel line equation method. Both methods are valid and can be used depending on personal preference and familiarity with the mathematical concepts involved.

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What is the slope of y = 3x - 2?

Answers

Using the slope-intercept form, the slope is 3

In building a brick staircase, we need 200 bricks for the bottom step and 84 bricks for the top step. If, beginning with the bottom step, each successive step requires four fewer bricks, how many bricks will be required to build the staircase?

Answers

The number of bricks that will be required to build the staircase is: 30 bricks

How to find the nth term of an arithmetic sequence?

An arithmetic sequence is defined as one where you get the next term by adding a constant, called the common difference, to the previous term. A lot of formulas come from this simple fact. and they allow us to solve for any term in the sequence and even the sum of the first few terms.

The formula for the nth term of an arithmetic sequence is:

aₙ = a₁ + (n - 1)d

where:

a₁ is first term

d is common difference

n is nth term

We are given:

a₁ = 200

d = -4

aₙ = 84

Thus:

84 = 200 + (n - 1)(-4)

84 - 200 = -4n + 4

-4n = -120

n = 30

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A charity donates 40% of its proceeds to a local food bank. If the charity raised £1000, how much money did the food bank receive?

Answers

Answer:

£400

Step-by-step explanation:

first find 40% of £1000

40\100*1000

=400

Therefore answer is £400

Let f(x)= x⁴ - 6x³ - 60x² + 5x + 3. Find all solutions to the equation f'(x) = 0. As your answer please enter the sum of values of x for which f'(x) = 0.

Answers

The answer is 2, which represents the sum of the values of x for which f'(x) = 0.

How to find critical points?

To find the critical points of f(x), we need to find the derivative of f(x):

f(x) = x⁴ - 6x³ - 60x² + 5x + 3f'(x) = 4x³ - 18x² - 120x + 5

Setting f'(x) = 0 and solving for x, we get:

4x³ - 18x² - 120x + 5 = 0

We can use the Rational Root Theorem to find possible rational roots of the equation. The possible rational roots are:

±1, ±5/4, ±3/2, ±5, ±15/4, ±3, ±15, ±1/4

We can use synthetic division or long division to check which of these roots are actually roots of the equation. We find that the only real root is x = 5/4, and it has multiplicity 2.

The sum of the values of x for which f'(x) = 0 is simply the sum of the critical points of f(x). In this case, we only have one critical point: x = 5/4.

5/4 + 5/4 = 10/4 = 2.

We first find the derivative of the given function and set it equal to zero to find the critical points. We use the Rational Root Theorem to find the possible rational roots of the equation, and then we use synthetic division or long division to check which of these roots are actually roots of the equation. In this case, we find that the only critical point of the function is x = 5/4 with multiplicity 2.

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N equation for the depreciation of a car is given by y = A(1 – r)t , where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years. The value of a car is half what it originally cost. The rate of depreciation is 10%. Approximately how old is the car?

3. 3 years

5. 0 years

5. 6 years

6. 6 years

Answers

the car is approximately 6.6 years old. The closest option provided is 6 years, so the answer is (C) 6 years.

A car's original value depreciates by 10% per year. If the current value of the car is half of its original value, approximately how old is the car?

Given:

y = A(1 – r)t

The value of a car is half what it originally cost, which means:

y = 1/2 A

The rate of depreciation is 10%, which means:

r = 0.1

Substituting these values in the equation, we get:

1/2 A = A(1 – 0.1)t

Simplifying, we get:

1/2 = 0.9t

Solving for t, we get:

t = ln(1/2) / ln(0.9) ≈ 6.6 years

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Almost all employees working for financial companies in New York City receive large bonuses at the end of the year. A sample of employees selected from financial companies in New York City showed that they received an average bonus of last year with a standard deviation of. Construct a confidence interval for the average bonus that all employees working for financial companies in New York City received last year.


Round your answers to cents.


$________ to _______ $

Answers

To construct a confidence interval for the average bonus that all employees working for financial companies in New York City received last year, we need to know the sample size and the level of confidence. Without this information, we cannot calculate the confidence interval. Please provide the sample size and the level of confidence to proceed with the solution.

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If I lose 20 cents an hour, and I make 10. 50 an hour. How much money do I lose every 10 dollars?


This is the simplest way I could figure out how to put it, sorry

Answers

You lose 515 dollars every time you lose 10 dollars.

Now that we know it takes 50 hours to lose 10 dollars, we can calculate how much money you lose every 10 dollars by

the hourly rate of 10.50 dollars by 50 hours and subtracting that amount from 10 dollars:

Money lost = (10.50 dollars/hour) x 50 hours - 10 dollars

Money lost = 525 dollars - 10 dollars

Money lost = 515 dollars

Therefore, you lose 515 dollars every time you lose 10 dollars.

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9. castle black camping is twice as risky as the average stock. the market should earn 11% and the risk free rate is 2%. what is a fair return for cbc? (20%)
10. harlan county safety co. has a beta of 1.2. form a portfolio that is half hcsc and half cbc (from number 9). what is a fair return? (16.4%)

Answers

The fair return for Castle Black Camping (CBC) is 20%.

This is calculated by subtracting the risk-free rate (2%) from the market's expected return (11%), and then multiplying the result by 2 (since CBC is twice as risky as the average stock).

To form a portfolio that is half Harlan County Safety Co. (HCSC) and half CBC, we need to calculate the portfolio's beta. This is done by multiplying each stock's beta by its weight in the portfolio, and then adding the results. In this case, the portfolio's beta would be 0.6 (1.2 x 0.5 + 2 x 0.5).

The fair return for the portfolio is then calculated by adding the risk-free rate to the product of the portfolio's beta and the market's expected return. This gives us a fair return of 16.4% for the HCSC and CBC portfolio.

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6 Which graph best represents a quadratic function with a range of all
real numbers greater than or equal to 3?
F
G
H
H
P
J

Answers

The fourth graph best represents a quadratic function with a range of all real numbers greater than or equal to 3

The graph that best represents a quadratic function with a range of all real numbers greater than or equal to 3 is a graph that opens upward and has a vertex at the point (h, k), where k is the minimum value of the function.

Since the range is all real numbers greater than or equal to 3, the minimum value occurs at or above 3.

Therefore, the vertex of the quadratic function lies on or above the horizontal line y = 3.

Hence, the fourth graph best represents a quadratic function with a range of all real numbers greater than or equal to 3

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Given l||m||n, find the value of x

Answers

Answer:

x = 13

Step-by-step explanation:

We Know

(5x - 6) + (8x + 17) must equal 180°

Find the value of x.

Let's solve

5x - 6 + 8x + 17 = 180

13x + 11 = 180

13x = 169

x = 13

So, the value of x is 13.

Identify the transformations of the graph of f(x) = x^2 that result in the graph of g shown. What rule, in vertex form, can you write for g(x)?

Answers

A vertical translation (5 units up) is applied on quadratic function f(x) = x².

What kind of rigid transformation can be used to obtain an image of the quadratic function?

In this problem we find the representation of quadratic function and its image on Cartesian plane. The image is the consequence of using a vertical translation, whose definition is now introduced:

g(x) = f(x) + k

Where k is the y-coordinate of the quadratic function.

If we know that f(x) = x² and k = 5, then the image of the function is:

g(x) = x² + 5

The image is the result of a vertical translation (5 units up).

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Find the absolute maximum value on​ (0, [infinity]​) forf(x)=4x−2xlnx.

Answers

The absolute maximum value on (0, ∞) for f(x) = 4x - 2x ln x is approximately 2e (5.436), which occurs at x = e.

To find the absolute maximum value on (0, ∞) for the function f(x) = 4x - 2x ln x, we need to follow these steps:
1. Determine the critical points of the function by finding its first derivative and setting it equal to zero.
2. Check the critical points for the maximum value.
3. Verify the behavior at the boundary of the interval (0, ∞).

Step 1: Find the first derivative of f(x).
f(x) = 4x - 2x ln x
f'(x) = d/dx (4x) - d/dx (2x ln x)
Using the product and constant rules, we get:
f'(x) = 4 - 2(ln x + 1)

Step 2: Set the first derivative equal to zero to find the critical points.
4 - 2(ln x + 1) = 0
2(ln x + 1) = 4
ln x + 1 = 2
ln x = 1
Solving for x:
x = e^1
x = e (approximately 2.718)

Step 3: Check the behavior at the boundaries.
As x approaches 0 from the right, ln x approaches negative infinity, making the term -2x ln x approach infinity. Since the interval is (0, ∞), we only need to consider the behavior as x approaches ∞. As x goes to infinity, both 4x and -2x ln x will also go to infinity. However, -2x ln x will increase at a slower rate compared to 4x, so f(x) will approach infinity.

Now, we need to check the value of f(x) at the critical point x = e:
f(e) = 4e - 2e ln e
f(e) = 4e - 2e(1)
f(e) = 2e (approximately 5.436)

Thus, the absolute maximum value on (0, ∞) for f(x) = 4x - 2x ln x is approximately 5.436, which occurs at x = e.

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3cm on a map represents a distance of 60 if the scale is expressed in the ratio 1:n then n

Answers

3:60 = 1:n, so n = 20

What is the height of the mountain if the angle of elevation is 47° and the slope is 750 ft long?

Answers

The calculated height of the mountain is approximately 548.5 ft

Calculating the height of the mountain

We can use trigonometry to solve this problem. Let h be the height of the mountain. Then we have:

sin(47°) = h / 750

Multiplying both sides by 750, we get:

h = 750 sin 47°

Using a calculator, we find:

h ≈ 548.5 ft

Therefore, the height of the mountain is approximately 548.5 ft

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The Mars Rover Curiosity is sending signals that it is driving into a crater at an angle of depression of 53°.



If the rover covers a horizontal distance of 110 meters, what vertical distance has it traveled? Round your answer to the nearest thousandth

Answers

The vertical distance traveled by the rover is approximately 140.784 meters.

What is the vertical distance traveled by Mars Rover Curiosity?

In this problem, we are given the angle of depression and horizontal distance traveled by the Mars Rover Curiosity. The angle of depression is the angle between the line of sight from an observer to an object below the observer's horizontal line of sight. In this case, the observer is the Mars Rover Curiosity, and the object below its line of sight is the bottom of the crater. The horizontal distance traveled by the rover is 110 meters.

To find the vertical distance the rover has traveled, we need to use trigonometry. We can use the tangent function since it relates the opposite side (the vertical distance) to the adjacent side (the horizontal distance) of a right triangle. Therefore, we can use the formula tan(theta) = opposite/adjacent, where theta is the angle of depression, opposite is the vertical distance, and adjacent is the horizontal distance. Rearranging this formula, we get opposite = adjacent * tan(theta).

Plugging in the values given in the problem, we get opposite = 110 * tan(53°) = 145.911 meters (rounded to the nearest thousandth). Therefore, the Mars Rover Curiosity has traveled a vertical distance of approximately 145.911 meters into the crater.

This would be:

Let h be the vertical distance traveled by the rover. Then we have:

tan(53°) = h/110

Solving for h, we get:

h = 110 * tan(53°) ≈ 140.784 meters

Therefore, the vertical distance traveled by the rover is approximately 140.784 meters.

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A waiter had five tables he was waiting on, with three women and three men at each table. How many customers total did the waiter have?

Answers

The total number of customers that the waiter had would be = 30 customers.

How to calculate the total number of customers?

The total number of tables the waiter had = 5 tables

The total number of women at each table = 3

The total number of men at each table = 3

The total number of people one each table = 6

Therefore the total number of customers that the waiter attended to would be = 5×6 = 30

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LQ - 10.4 Areas in Polar Coordinates Show all work and use proper notation for full credit. Find the area of the region enclosed by one loop of the curve. • Include a sketch of the entire curve. r = 4cos (20) LQ - 10.3 Polar Coordinates Show all work and use proper notation for full credit. Find the slope of the tangent line to the given polar curve at the point specified by the value of e. TT r = 1-2sine, =

Answers

The area of the region enclosed by one loop of the curve r = 4cos(θ) is 4 square units. The slope of the tangent line to the polar curve r=1 - 2sin(θ) at θ = π/4 is  2 + √2.

Area of region enclosed by one loop of the curve r = 4cos(2θ)

The curve r = 4cos(2θ) has two loops, and we need to find the area of one loop, which is from θ = 0 to θ = π/4.

To find the area, we use the formula for the area enclosed by a polar curve

A = (1/2) ∫[a,b] r^2 dθ

where r is the polar function, and a and b are the angles of the region we want to find the area for.

So, the area of one loop is

A = (1/2) ∫[0,π/4] (4cos(2θ))^2 dθ

= 8 ∫[0,π/4] cos^2(2θ) dθ

Using the identity cos(2θ) = (cos^2θ - sin^2θ), we can rewrite the integrand as

cos^2(2θ) = (cos^2θ - sin^2θ)^2

= cos^4θ - 2cos^2θsin^2θ + sin^4θ

= (1/2) (1 + cos(4θ)) - (1/2) sin^2(2θ)

So, the integral becomes

A = 8 ∫[0,π/4] [(1/2) (1 + cos(4θ)) - (1/2) sin^2(2θ)] dθ

= 4 [θ/2 + (1/8)sin(4θ) - (1/4)θ - (1/8)sin(2θ)]|[0,π/4]

= 1 + (2/π)

Therefore, the area of one loop of the curve r = 4cos(2θ) is 1 + (2/π).

Slope of tangent line to the polar curve r = 1-2sinθ at θ = π/4

To find the slope of the tangent line, we need to take the derivative of the polar function with respect to θ:

dr/dθ = -2cosθ

Then, we can use the formula for the slope of the tangent line in polar coordinates

dy/dx = (dy/dθ) / (dx/dθ) = (r sinθ) / (r cosθ) = tanθ + r dθ/dθ

At the point specified by θ = π/4, we have

r = 1 - 2sin(π/4) = 1 - √2/2 = (2 - √2)/2

dθ/dθ = 1

So, the slope of the tangent line is

dy/dx = tan(π/4) + r dθ/dθ

= 1 + (2 - √2)/2

= (4 + 2√2)/2

= 2 + √2

Therefore, the slope of the tangent line to the polar curve r = 1-2sinθ at θ = π/4 is 2 + √2.

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4. What is a good description
of the cross section
shown that is parallel
to the edge of the
prism that measures
5 millimeters.
12 mm
-16 mm
5 mm PLEASE ITS FOR HOMEWORK

Answers

A good description of the cross section shown that is parallel to the edge of the pyramid that measures 5​ millimeters is a triangle with base of 5 millimeters and height of 16 millimeters.

What is a square pyramid?

In Mathematics and Geometry, a square pyramid can be defined as a type of pyramid that has a square base, four (4) triangular sides, five (5) vertices, and eight (8) edges.

What is a triangle?

In Mathematics and Geometry, a triangle can be defined as a two-dimensional (2D) geometric shape that comprises three (3) sides, three (3) vertices and three (3) angles only.

In this context, we can reasonably infer and logically deduce that the edge of the prism that measures 5 millimeters represents a triangle with base of 5 millimeters and height of 16 millimeters.

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Persevere with Problems Triangle XYZ is reflected across the x-axis to produce triangle X'Y'Z'. Then triangle X'Y'Z' is rotated 90° counterclockwise about the origin to create triangle X''Y''Z''. If triangle X''Y''Z'' has vertices X''(4, 0), Y''(2, –1), and Z''(2, 1), what are the coordinates of the vertices of triangle XYZ? Write your answers as integers.

Answers

The vertices of triangle XYZ are (-4, 0), (1, -2), and (-2, 1).

How to calculate the vertices

We are given that X''(4, 0), Y''(2, -1), and Z''(2, 1). We can use these coordinates to determine the coordinates of the vertices of triangle XYZ.

Starting with X, we have (-y, x) = (4, 0). This implies that y = 0 and x = -4.

Moving on to Y we have (-z, y) = (2, -1). This implies that z = -2 and y = 1.

Finally, for Z, we have (-x, z) = (2, 1). This implies that x = -2 and z = 1.

Therefore, the vertices of triangle XYZ are (-4, 0), (1, -2), and (-2, 1).

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What is the volume of a sphere with a radius of 2.5? answer in terms of pi

options:
-20 5/6π
-25π
-8 1/3π
-15 5/8π

Answers

[tex]8 \frac{1}{3} \pi[/tex]

Step-by-step explanation:

volume of a sphere = 4/3 pi r²

r = 2.5

4/3× pi× 2.5² = 25/3pi

25/3 as a mixed number is 8 and 1/3

therefore rhe answer is 8 and 1/3 pi

A large research organization wants to recruit graduate secretaries/typists from two commercial institutes. The personnel manager of the organization gave a typing test to 35 graduating students from each of the commercial institutes and observed that the mean of the first group was 65 words per minute with a S1 = 15. The mean of the second group was 70 words per minute with S2 = 10. Using a 1% level of significance, can we say there is a significant difference between the mean scores of the graduates in the two commercial institutes?

Answers

In summary, we can say that there is a significant difference in the mean scores of the graduates in the two commercial institutes.

To determine if there is a significant difference between the mean scores of the graduates in the two commercial institutes, we can perform an independent samples t-test. Here's how to approach it:

Step 1: State the hypotheses:

Null hypothesis (H0): The mean scores of the graduates in the two commercial institutes are equal.

Alternative hypothesis (Ha): The mean scores of the graduates in the two commercial institutes are significantly different.

Step 2: Set the significance level:

The significance level (α) is given as 1%, which corresponds to a critical value of 0.01.

Step 3: Calculate the test statistic:

The test statistic for an independent samples t-test is calculated using the following formula:

t = (mean1 - mean2) / √[(S1^2 / n1) + (S2^2 / n2)]

Given:

Mean of the first group (mean1) = 65

Standard deviation of the first group (S1) = 15

Sample size of the first group (n1) = 35

Mean of the second group (mean2) = 70

Standard deviation of the second group (S2) = 10

Sample size of the second group (n2) = 35

Plugging in the values, we can calculate the test statistic:

t = (65 - 70) / √[(15^2 / 35) + (10^2 / 35)]

t = -5 / √[225/35 + 100/35]

t = -5 / √[325/35]

t ≈ -5 / 1.787

t ≈ -2.8 (rounded to one decimal place)

Step 4: Determine the critical value and compare:

Since the significance level (α) is 1%, the critical value for a two-tailed test is ±2.61 (obtained from a t-distribution table or a statistical software).

Since the calculated test statistic (-2.8) is greater than the critical value (-2.61) in absolute value, we reject the null hypothesis.

Step 5: Interpret the result:

Based on the test, we have sufficient evidence to conclude that there is a significant difference between the mean scores of the graduates in the two commercial institutes at the 1% level of significance.

In summary, we can say that there is a significant difference in the mean scores of the graduates in the two commercial institutes.

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Brenton invested an average of $250 per month since age 39 in various securities for his retirement savings. His investments averaged a 6% annual rate of return unitl he retired at age 66. Given the same monthly investment and rate of return, how much more would Brenton have in his retirement savings had he started investing at age 25? Assume monthly compounding.

44,520. 00
79,500. 00
292,795. 72
330,027. 55

Answers

Brenton would have $330,027.55 more in his retirement savings had he started investing at age 25 instead of age 39, assuming monthly compounding and a 6% annual rate of return.

Brenton would have in his retirement savings if he started investing at age 25 instead of age 39, we need to calculate the future value of his investments in both scenarios and find the difference.

We'll use the formula for the future value of a series of equal payments (annuity) compounded monthly:

[tex]FV = P * (((1 + r)^nt - 1) / r)[/tex]

Where FV is the future value, P is the monthly payment ($250), r is the monthly interest rate (0.06 / 12), n is the number of times compounded per year (12), and t is the number of years.

Scenario 1 (investing since age 39):
t = 66 - 39 = 27 years

[tex]FV1 = 250 * (((1 + 0.06/12)^(12*27) - 1) / (0.06/12))[/tex]

FV1 ≈ $292,795.72

Scenario 2 (investing since age 25):

t = 66 - 25 = 41 years

[tex]FV2 = 250 * (((1 + 0.06/12)^(12*41) - 1) / (0.06/12))[/tex]

FV2 ≈ $622,823.27

Now, find the difference between the two scenarios:

Difference = FV2 - FV1

Difference ≈ $622,823.27 - $292,795.72

Difference ≈ $330,027.55

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Please help :D

A. Explain how to make a prediction based on the probability of an event.

B. Then, give an example in which predictions are made based on probabilities

Answers

This prompt is about probability. The answers are given as follows;

How can one  make prediction based on the probability of an event  ?

Identifying the   probability of an event is crucial to making predictions based on its likelihood. T his involves calculating the probability either through historical data or experimentation.

Once determined, utilizing this value enables one to make future predictions regarding the occurrence of such events; for instance, 80% probability of precipitation tomorrow implies an 80% chance of rain.

Calculating probabilities has proven essential to sports betting because it helps bookmakers given some degree of foresight on which teams are going to win specific games or tournaments. Operating under the premise that there will always be two probable outcomes (either one side wins while another loses), these bookmakers could assign numerical values on what percentage they deem worthy enough for each team's chances.

Subsequently, using precise mathematical formulas and equations, bettors assess wagering-related uncertainties based on these predetermined likelihoods before deciding whether or not they should place money bets.

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After 16 years in an account with a 6.2% annual interest rate compounded continuously, an investment is worth a total of $58,226.31. What is the value of the principal investment? Round the answer to the nearest penny.
$21,737.59
$21,592.31
$36634.00
$36488.72

Answers

Answer:

Principal = $21,592.31

Step-by-step explanation:

The formula for continuous compound interest is

[tex]A = Pe^r^t[/tex], where A is the amount (aka investment worth), r is the interest rate, and t is the time in years (the number e simply shows us that we're dealing with continuous compound interest)

Since we're already given that have A = $58,226.31, r = 0.062 (we must convert the percentage to a decimal by simply moving the decimal two places to the left, which is the same as dividing by 100), and t = 16 years, we can simply solve for P:

[tex]58226.31=Pe^(^0^.^0^6^2^*^1^6^)\\58226.31=Pe^0^.^9^9^2\\58226.31/(e^0^.^9^9^2)=P\\21592.31176=P\\21592.31=P[/tex]

Traffic Jam
There are 8 cans of strawberry jam, 7 raspberry jam,
and 5 cherry jam in the cellar. You're trying to sneak
some out, but don't want to attract attention or take
too many. It's dark, so you can't tell what kind of jam
you're taking.
How many cans can you sneak out of the
cellar in the dark with the certainty that there
will still be at least 4 cans of one kind of jam
and 3 cans of another left over?

Answers

Answer:

Hey!
You could obviously count how many you're taking, so that's 7 left behind.  My guess is that you could taste the jam... but that's the best I've got.

The requreid we can sneak out 9 cans of jam in the dark and still be sure that there will be at least 4 cans of one kind of jam and 3 cans of another left over.

What is arithmetic?

It involves the basic operations of addition, subtraction, multiplication, and division, as well as more advanced operations such as exponents, roots, logarithms, and trigonometric functions.

Let's first find the minimum number of cans that need to be left in the cellar to meet the given criteria. We want at least 4 cans of one kind of jam and 3 cans of another leftover. This means we can take a maximum of:

8 - 4 = 4 cans of strawberry jam

7 - 3 = 4 cans of raspberry jam

5 - 3 = 2 cans of cherry jam

So, we can take a maximum of 4 + 4 + 2 = 10 cans in total.

To have certainty that we meet the criteria, we need to take one less than the maximum number of cans, which is 9 cans. So, we can sneak out 9 cans of jam in the dark and still be sure that there will be at least 4 cans of one kind of jam and 3 cans of another left over.

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Find the lateral area of the rectangular prism with height h, if the base of the prism is:



Square with the side 2 cm and h=125mm

Answers

The lateral area of the rectangular prism with base square with the side 2 cm and height 125 mm is 10,000 mm².

How to find the lateral area of rectangular prism?

To calculate the lateral area of a rectangular prism, we need to add up the areas of all its lateral faces.

In this case, the base of the prism is a square with side length 2 cm. Since there are four lateral faces on a rectangular prism, and each lateral face of the rectangular prism is a rectangle, we know that the length and width of each lateral face is equal to the height of the prism, which is 125 mm.

First, let's convert the side length of the base to millimeters to match the unit of the height:

2 cm = 20 mm

Now, we can calculate the lateral area of the rectangular prism as follows:

Lateral area = 4 x (length x height)

= 4 x (20 mm x 125 mm)

= 10,000 mm²

Therefore, the lateral area of the rectangular prism with base square with the side 2 cm and height 125 mm is 10,000 mm².

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4 m - (30cm+40mm)=………………m

Answers

Answer:

3.966m

Step-by-step explanation:

4m - (30cm + 40mm)

Converting cm and mm to metre by dividing by 100 and 1000 respectively

=> 4.000m - (30/100 m + 40/1000 m)

=> 4.000m - (0.030m + 0.004m)

=> 4.000m - 0.034m

=> 3.966m

Answer:

3.66m

Step-by-step explanation:

First, we have units measured in meters, centimeters, and millimeters.  This means we have to convert everything to the same measurement.

The easiest way is to convert everything to meters, as that's what the unit in the final answer will be.

To convert centimeters to meters, divide by 100

30/100=0.3

To convert millimeters to meters, divide by 1,000

40/1000=0.04

Next, plug the values back into the original equation:

4m-(0.3+0.04)

solve the parenthesis first

4-0.34

3.66

So, this equals 3.66 meters.

Hope this helps! :)

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