Fossils remains of Cynognathus , a triassic land reptile, have been found at both South America And Africa . What does this imply?
A. these continents used to be connected and later moved apart
B . People can find really cool fossils in random locations
C . the Cynognathus reptile evolved independently on 2 separate continents
D . the Cynognathus is found on both continents because it swam across the ocean
Answers
The discovery of fossils remains of Cynognathus at both South America And Africa suggests that these continents used to be connected and later moved apart.
What is the continental drift theory?According to continental drift theory:
"All of the continents were once together as a single continent named Pangaea, which was surrounded by a Mega Ocean known as Panthalassa."
Who proposed this theory?The continental drift theory was first proposed by Abraham Ortelius in 1596, and Alfred Wegener developed it in 1912.
If continental drift had not occurred what would be the explanation?On distinct continents, the species evolved independently. orTo form a second population, they swam to the opposite continent in breeding pairs.To learn more about fossils, continents, continental drift, and Pangaea here,
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Related Questions
Everything in the Universe originated from a single point. How was it possible for everything in the Universe to have occupied a
single point?
OA. Only protons and electrons existed in the Universe, and they were pulled together by gravity.
OB. Only single atoms existed in the Universe, and they were squeezed together by magnetic fields.
OC.
All mass in the Universe was in the form of gases, and gases take up minimal space.
OD
All mass in the Universe was once energy, and energy does not take up space.
Answers
Answer:
d
Explanation:
Fast and safe heart rate for workouts is called muscular strength? True or false
Answers
Answer:
False
Explanation:
Answer:
False
Explanation:
Hope this helped, Have a Wonderful Day/Night!!
Describe which relationships in Ohm’s law are DIRECT and which are INVERSE. Use examples to support your answer. You can use calculations, drawings, or graphs to make your point more clear
Answers
Answer:
I like to memorize excerpt from articles to solve and answer questions like these. I hope this can help, it's from study.com: "The relationship between voltage, current, and resistance is described by Ohm's law. This equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r."
Your friend clams that objects do not have to be thouching for a magnetic force to cause motion. How would you support your friends claim? Due today
Answers
Hoped this helped :)
Can the brain perform two separate tasks at the same time
yes or no
Answers
Answer:
yes
Explanation:
the brain perform two separate tasks at the same time
What do you do abt onion eyes (MY EYES ARE BURNING BADDD)
Answers
Answer:
Leave onions in cold water for about 15 minutes! Takes out the chemical reaction in the onion's defense system.
Explanation:
This is what people NEED to know for cooking... Lol :)
a 15-n force and a 45-n force act on an object in opposite directions. what is the magnitude of the net force on the object?
Answers
Answer: 30 N (in the direction of the 45 N force)
Explanation:
You have to choose a positive and negative direction since the question says the forces are in opposite directions.
Lets assume:
- <----------> +
<------ 15 N
45 ------->
45-15=30
PLZZ HELP
How many kg are there in 335 m
Answers
Equilibrium can occur only if
Answers
Answer:
Equilibrium is when the rate of the forward reaction equals the rate of the reverse reaction. All reactant and product concentrations are constant at equilibrium.
Explanation:
A flat coil is in a uniform magnetic field. What angle between the magnetic field and the plane of the coil produces the maximum flux, and what angle produces 90% of the maximum flux
Answers
This question is incomplete, the complete question is;
A flat coil is in a uniform magnetic field. What angle between the magnetic field and the plane of the coil produces the maximum flux, and what angle produces 90% of the maximum flux
A) max: 0°
90% of max: 90°
B) max: 90°
90% of max: 45°
C) max: 90°
90% of max: 64°
D) max: 0°
90% of max: 26°
E) max: 90°
90% of max: 80°
Answer:
Option C) max: 90°
90% of max: 64° is the correct Answer
Explanation:
from the Suppose Area is A.
then flux at angular position O is
Ф = BAsin∅
⇒ Ф = βmaxSin∅
flux will be max when sin∅ = 1
therefore sin∅ = 1
∅ = sin⁻¹ 1
∅ = 90°
Now at 90% of max flux
Ф ⇒ 0.9βmax = βmax sin∅
0.9 = sin∅
∅ = sin⁻¹ (0.9)
∅ = 64.15° ≈ 64°
Therefore Max ∅ = 90°
90% flux = 64°
Option C) max: 90°
90% of max: 64° is the correct Answer
What is the difference in
momentum between a 0.216 kg bird
flying 5.87 m/s and a 7.29 kg baby
crawling 0.234 m/s?
Answers
Answer:
0.438kg/ms-¹
Explanation:
Momentum, denoted by p, can be calculated by using the formula;
p = mv
Where;
m = mass (kg)
v = velocity (m/s)
Momentum (p) of bird = 0.216 kg × 5.87 m/s = 1.268kg/ms-¹
Momentum (p) of crawling baby = 7.29 kg kg × 0.234 m/s = 1.706kg/ms-¹
Having calculated the momentum of the bird to be 1.268kg/ms-¹, and the momentum of the baby to be 1.706kg/ms-¹, the difference in momentum between the flying bird and the crawling baby is:
{1.706kg/ms-¹ - 1.268kg/ms-¹} = 0.438kg/ms-¹
A 4.80 g bullet moves with a speed of 170 m/s perpendicular to the Earth's magnetic field of 5.00×10−5T.
Part A
If the bullet possesses a net charge of 1.06×10−8 C , by what distance will it be deflected from its path due to the Earth's magnetic field after it has traveled 1.00 km ?
Answers
Answer:
[tex]3.24\times 10^{-7}\ \text{m}[/tex]
Explanation:
m = Mass of bullet = 4.8 g
v = Velocity of bullet = 170 m/s
B = Magnetic field of Earth = [tex]5\times 10^{-5}\ \text{T}[/tex]
q = Charge of bullet = [tex]1.06\times 10^{-8}\ \text{C}[/tex]
a = Acceleration
Time the bullet will be in the air for is [tex]t=\dfrac{1000}{170}=5.88\ \text{s}[/tex]
Force is given by
[tex]F=ma[/tex]
Magnetic force is given by
[tex]F=qvB[/tex]
So
[tex]ma=qvB\\\Rightarrow a=\dfrac{qvB}{m}\\\Rightarrow a=\dfrac{1.06\times 10^{-8}\times 170\times 5\times 10^{-5}}{4.8\times 10^{-3}}\ \text{m/s}^2[/tex]
From the linear equations of motion we have
[tex]s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0+\dfrac{1}{2}\times \dfrac{1.06\times 10^{-8}\times 170\times 5\times 10^{-5}}{4.8\times 10^{-3}}\times 5.88^2\\\Rightarrow s=3.24\times 10^{-7}\ \text{m}[/tex]
The defelection of the bullet is [tex]3.24\times 10^{-7}\ \text{m}[/tex]
Who determined how stars are powered?
Answers
Answer:
NEWTON
Explanation:
ISSAC NEWTON
HOPE IT HELP U
Answer:
hans bethe
Explanation:
Hans Bethe
In 1939, in a paper entitled "Energy Production in Stars", Hans Bethe analyzed the different possibilities for reactions by which hydrogen is fused into helium. He defined two processes that he believed to be the sources of energy in stars.
i looked it up and thats what it said
A motor lifts a 500kg elevator a height of 100 m at a constant speed in 50 secs. How much power did the motor supply
Answers
Answer:
9,800 watts
Explanation:
The first step is to calculate the force
F= mg
= 500 × 9.8
= 4,900 N
The next step is to calculate the work done
= 4,900 × 100
= 490,000 joules
Therefore the power can be calculated as follows
Power= work done /time
= 490,000/50
= 9,800 watts
please help
A toy rocket having a mass of 10 kg and weighing 100 N provides an applied upward thrust force of 400 N. What is the upward acceleration of the rocket? Fair = 400N Fw = 100N 5 m/s2 50 m/s2 40 m/s2 4 m/s² 30 m/s2 3 m/s2
Answers
We are given:
Mass of the rocket = 10 kg
Weight of the Rocket = 100 N
Upward thrust applied by the rocket = 400 N
Net upward force on the rocket:
We are given that gravity pulls the rocket with a force of 100 N
Also, the rocket applied a force of 400N against gravity
Net upward force = Upward thrust - Force applied by gravity
Net upward force = 400 - 100
Net upward force = 300 N
Upward Acceleration of the Rocket:
From newton's second law:
F = ma
replacing the variables
300 = 10 * a
a = 30 m/s²
define the term energy density of a body under strain
Answers
Answer:
Please mark as Brainliest!!
Explanation:
Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation. When the applied force is released, the whole system returns to its original shape.
When light is reflected, the incident rays are bent and change direction.
True
False
Answers
Answer: True
Explanation: When light is reflected off lets say a mirror it is bent and changes direction to bounce off of another wall or object. For example if you take a flash light and shine it into a mirror the light reflects into a different direction your welcome
When light is reflected, the incident rays return back in straight direction and never bends and make the material gleaming. Hence, the statement is false.
What is reflection ?Reflection is the phenomenon that, when waves incident on a material it returns back in straight direction. Both sound wave and light wave can be reflected. But, lightwaves are only reflected from transparent materials.
Reflection of light ray make the material surface gleaming like in a mirror. Similarly reflection of sound waves produces echos. The phenomenon in which the light wave bends in its direction when moving from one medium to the other is called refraction.
The measure of bending of light in a medium is called the refractive index of that medium. Hence, bending of light is not reflection and it is termed as refraction. Thus, the statement is false.
To find more on reflection, refer here:
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A weight lifter lifts a 280-N set of weights from ground level to a position over his head, a vertical distance of 1.60 m. How much work does the weight lifter do, assuming he moves the weights at constant speed?
Answers
Given :
A weight lifter lifts a 280-N set of weights from ground level to a position over his head, a vertical distance of 1.60 m.
To Find :
How much work does the weight lifter do, assuming he moves the weights at constant speed.
Solution :
We know, work done is given by :
[tex]W= Fdcos\ \theta[/tex]
Here, F = 280 N and d = 1.60 m
Since, weight lifer is applying and upward force and displacement is also in upward direction.
[tex]\theta = 0^{\circ}\\cos\ 0^{\circ} = 1[/tex]
Putting all these in above equation, we get :
[tex]W = 280\times 1.6\times 1\\\\W = 448\ J[/tex]
Therefore, work done by weight lifter 448 J.
Hence, this is the required solution.
You apply 741 J of energy to lift a box a distance of 2.83 meters, what
is the weight of the box?
Answers
Answer:
261.84 N.
Explanation:
From the question given above, the following data were obtained:
Energy (E) = work (W) = 741 J
Distance (d) = 2.83 m
Force (F) =?
Work is simply defined as the product of force and the distance moved in the direction of the the force. Mathematically, it is expressed as:
Work (W) = Force (F) × distance (d)
W = F × d
Thus, we obtained the weight of the object using the above formula.
Work (W) = 741 J
Distance (d) = 2.83 m
Force (F) =?
W = F × d
741 = F × 2.83
Divide both side by 2.83
F = 741 / 2.83
F = 261.84 N
Since force and weight has the same unit of measurement i.e Newton (N), the weight of the object is 261.84 N
how do I find the x and y components and the resultant force?
Answers
Explanation:
1) the diagonal force times the sine of the angle it makes will give you the vertical component or y component . use this to get the vertical components of all the diagonal forces . add all the vertical components as well as the vertical forces together
2) the diagonal force times the cosine of the angle it makes gives the horizontal component or x component. do this to get the x component of all the diagonal forces.
add all the x components as well as the horizontal forces together to get the final x component
3)using the triangle of vectors, the resultant force is calculated
sum of y component = 3.2N
sum of x component= 5.7N
resultant force = 6.5N
A balloon was filled to a volume of 2.50 LL when the temperature was 30.0∘C30.0∘C. What would the volume become if the temperature dropped to 11.0∘C11.0∘C.
Answers
Answer:
The volume would become 2.34 L if the temperature dropped to 11.0 °C
Explanation:
From the question, A balloon was filled to a volume of 2.50 L when the temperature was 30.0 °C.
To determine what the volume will become if the temperature dropped to 11.0 °C, we will use one of the Gas laws that relates Volume and Temperature. The Gas law that relates Volume and Temperature is the Charlse' law which states that, "the Volume of a fixed mass of gas is directly proportional to its Temperature ( in Kelvin) provided that the Pressure remains constant"
That is
V ∝ T ( at constant pressure)
Where V is the Volume
and T is the Temperature in Kelvin
Then, we can write that
V = kT
Where k is the constant of proportionality
Then,
[tex]\frac{V}{T} = k[/tex]
Hence, we can write that
[tex]\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} } = \frac{V_{3} }{T_{3} } ...[/tex]
∴ [tex]\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }[/tex]
Where [tex]{V_{1} }[/tex] is the initial volume
[tex]{T_{1} }[/tex] is the initial temperature
[tex]{V_{2} }[/tex] is the final volume
and [tex]{T_{2} }[/tex] is the final temperature
From the question,
[tex]{V_{1} }[/tex] = 2.50 L
[tex]{T_{1} }[/tex] = 30.0 °C = 30.0 + 273.15 K = 303.15 K
[tex]{V_{2} }[/tex] = ??
[tex]{T_{2} }[/tex] = 11.0 °C = 11.0 + 273.15 K = 284.15 K
Putting the values into the equation, we get
[tex]\frac{2.50}{303.15} = \frac{V_{2} }{284.15}[/tex]
∴ [tex]V_{2} = \frac{2.50 \times 284.15}{303.15}[/tex]
[tex]V_{2} = 2.34 L[/tex]
Hence, the volume would become 2.34 L if the temperature dropped to 11.0 °C.
The final volume of the balloon is equal to 0.92 Liter.
Given the following data:
Initial volume = 2.50 LInitial temperature = 30°CFinal temperature = 11°CTo determine the final volume of the balloon, we would apply Charles's law:
Mathematically, Charles law is given by the formula;
[tex]\frac{V}{T} =k\\\\\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]
Where;
T is the temperature of an ideal gas.V is the volume of an ideal gas.Substituting the given parameters into the formula, we have;
[tex]\frac{2.5}{30} = \frac{V_2}{11} \\\\2.5 \times 11 = 30V_2\\\\27.5 = 30V_2\\\\V_2 = \frac{27.5}{30}[/tex]
Final volume = 0.92 Liter.
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Repeat the demonstration on a paved surface such as a driveway or sidewalk and document the differences. With no soil to absorb this water, what would happen in a heavy rainstorm? How would an engineer in charge of a city’s flood control system prepare for the runoff generated on paved parking lots and roads in a heavy rainstorm?
Answers
Answer:
can I see like the actual activity on a computer or book?
Identify the charges that are negative.
A B C D
Answers
Answer:
b and c
Explanation:
The metric unit of power is _____.
Answers
Answer:
Watt
Explanation:
Power is defined as the work done by an object per unit time. Its mathematical form is given by :
[tex]P=\dfrac{W}{t}[/tex]
The SI unit of work done is Joules (J) and that of time is seconds (s).
J/s is equal to watts. Watt is the metric unit of power.
The girl climbs the ladder with the painting in 5 seconds. How much work does
she perform? How much power does she use? *
Answers
But anyway.
Work = Force x distance
Power = work / time
Why does a watched pot never boil?
Answers
How many energy levels does hydrogen have?
Answers
A diffuser is an adiabatic device that decreases the kinetic energy of the fluid by slowing it down. What happens to this lost kinetic energy?
Answers
Answer:
Kinetic energy is converted to internal energy
Explanation:
We are required to explain what happens to this decreased kinetic energy in this question.
Here is what a diffuser does, this device increases the pressure of a fluid and in so doing it slows it down. The lost kinetic energy would then be converted to internal energy. This is the correct answer to the question.
Thank you
Just before it landed on the moon, the Apollo 12 lunar lander had a mass of 1.4×104 kg. What rocket thrust was necessary to have the lander touch down with zero acceleration?
Answers
Answer:
[tex]\mathbf{F_{thrust} \simeq 2.3 \times 10^4 \ N}[/tex]
Explanation:
For a lunar lander acceleration in an upward direction, the net force that acts on it can be expressed as:
[tex]F_{net} = F_{thrust} - F_{g(moon)}[/tex]
The equation for the net force that acts on the lunar lander is:
[tex]F_{net} = m_La[/tex]
For the lander touch down to be zero acceleration, it implies that the acceleration of the moving rocket is zero(a free body fall)
i.e. a = 0
We can now regard the Apollo 12 lunar as a freely falling body
However; the force of gravity as a result of the moon acting on the lunar rocket is:
[tex]F_{g(moon)} = m_Lg_m[/tex]
Then; the equation for the thrust force of the lunar rocket is:
[tex]F_{net} = F_{thrust} - F_{g(moon)}[/tex]
[tex]m_La = F_{thrust}-m_Lg_m[/tex]
[tex]m_L(0)= F_{thrust}-m_Lg_m[/tex]
[tex]0= F_{thrust}-m_Lg_m[/tex]
[tex]-F_{thrust}= -m_Lg_m[/tex]
[tex]F_{thrust}= m_Lg_m[/tex]
Finally; the thrust force of the lunar rocket can be determined as:
[tex]F_{thrust}= m_Lg_m[/tex]
Acceleration due to gravity ot the surface of the moon = 1.625 m/s²
[tex]F_{thrust}=(1.4 \times 10^{4} \ kg) (1.625 \ m/s^2)[/tex]
[tex]F_{thrust}=2.275 \times 10^4 \ N[/tex]
[tex]\mathbf{F_{thrust} \simeq 2.3 \times 10^4 \ N}[/tex]
A thrust force of 22680N will be necessary to to have the lander touch down with zero acceleration.
Given the data in the question;
Mass of Apollo 12 lunar lander; [tex]m_L = 1.4 * 10^4 kg[/tex]
Using the expression for the net-force that acts on the lander when it is accelerated in the upward direction:
[tex]F_{net} = F_{thrust} - F_{g(moon)}[/tex] ------- Let this be equation 1
Also, the net-force that acts on the lunar lander can be expressed as:
[tex]F_{net} = m_L*a[/tex] ------- Let this be equation 2
Where [tex]m_L[/tex] is the mass of the lunar lander and a is the acceleration ( 0 ),
( the acceleration of the moving rocket is zero and its freely falling )
Also, Force of gravity due to moon that acts on the lunar lander is expressed as:
[tex]F_{g(moon)} = m_L * g_m[/tex] ------- Let this be equation 3
Where [tex]m_L[/tex] is the mass of the lunar lander and [tex]g_m[/tex] is the moon's gravity ( [tex]1.62m/s^2[/tex] )
Lets substitute equation 2 and 3 into 1
[tex]m_L * a = F_{thrust} - (m_L * g_m)\\\\m_L * 0= F_{thrust} - (m_L * g_m)\\\\0=F_{thrust} - (m_L * g_m)\\\\ F_{thrust} = m_L * g_m[/tex]
We substitute our values into the equation
[tex]F_{thrust} = (1.4*10^4kg) * 1.62m/s^2\\\\F_{thrust} = 22680 kg.m/s^2\\\\F_{thrust} = 22680N[/tex]
Therefore, a thrust force of 22680N will be necessary to to have the lander touch down with zero acceleration.
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A man walks 400 m in the direction 45° north of east. Represent this vector graphically by
selecting a scale and drawing a coordinate system.
Answers
Answer:
Explanation:
Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.
Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.
scale = [tex]\frac{length on drawing}{original length}[/tex]
= [tex]\frac{10}{400}[/tex]
= [tex]\frac{1}{40}[/tex]
scale = 1:40
This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.
The man's direction is [tex]45^{o}[/tex] north of east.
The graphical drawing of the vector is herewith attached to this answer.
