For the function M(x) = 2x⁴ - 5x-3, find the value of M"' (2) M(x) = 2x⁴ -5x-3 M''' (2) = M'G)= M''(x)= 2. Find dy/dx for the relation x² = -3x³y⁴- 4y³ 15-3x'y". ty? 3. Find dy/dt for the function y = 3x⁴ - 8x² + 4 Evaluate dy/dt when dx/dt = -2 and x = -10 y = 3x⁴ - 8x²+4

The correct way to evaluate the integral of (25x² + 46x + 13)dx is:

∫(25x² + 46x + 13)dx = 4ln|x + 1| + 21ln|x - 1| + C

Here, ln represents the natural logarithm. The arbitrary constant, denoted by C, represents any constant value that could be added to the antiderivative without changing its derivative.
To evaluate the given integral, we will first rewrite it using the correct mathematical notation:

∫(25x² + 46x + 13) dx

Now, we will use integration techniques to find the antiderivative. In this case, we can apply the power rule and linearity of the integral:

∫(25x²) dx + ∫(46x) dx + ∫13 dx

Now we will evaluate each integral separately:

(25/3)x³ + (46/2)x² + 13x + C

Now, we can simplify the expression:

(25/3)x³ + 23x² + 13x + C

So the evaluated integral is:

(25/3)x³ + 23x² + 13x + C

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Lillian would have approximately $14,599 in her account after 3 years, to the nearest dollar.

To find out how much Lillian would have in her account after 3 years, we need to use the future value of a series formula, which is:

[tex]FV = P \frac{(1 + r)^nt - 1)}{r}[/tex]

where:
FV = future value of the series
P = monthly deposit ($430)
r = monthly interest rate (annual interest rate / 12)
n = number of times interest is compounded per year (12)
t = number of years (3)

First, we need to find the monthly interest rate by dividing the annual interest rate (4.5%) by 12:
[tex]r =\frac{0.045}{12} = 0.00375[/tex]

Now we can plug the values into the formula:
[tex]FV = 430 \frac{(1 + 0.00375)^{12x3}  - 1)}{0.00375}[/tex]

Calculating the future value:
[tex]FV = 430\frac{(1.127334 - 1) }{0.00375} = 430 \frac{0.127334}{ 0.00375} = 430 (33.955)[/tex]
[tex]FV =14,598.65[/tex]

So, Lillian would have approximately $14,599 in her account after 3 years, to the nearest dollar.

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4.87% of toddlers at home had behavioral problems, according to the parents surveyed.

The Illinois study examined the effect of day care on the behavior of toddlers by surveying randomly selected parents. There were two groups of parents: those with a toddler in full-time day care and those with a toddler at home.

In the first group, 987 parents with a toddler in full-time day care were surveyed. Among these parents, 212 reported that their child had behavioral problems. To calculate the percentage of children with behavioral problems in this group, we can use the following formula:

(212/987) x 100 = 21.48%

In the second group, 349 parents with a toddler at home were surveyed. Among these parents, 17 reported that their child had behavioral problems. To calculate the percentage of children with behavioral problems in this group, we can use the following formula:

(17/349) x 100 = 4.87%

The study found that 21.48% of toddlers in full-time day care had behavioral problems, whereas 4.87% of toddlers at home had behavioral problems, according to the parents surveyed.

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The unit multiplier for the conversion is 24 ft/min = (24 ft² / 1 min) * (12 inch / ft) * (12 inch / ft) * (1 min / 60 sec)

An exponential equation is an expression that shows how numbers and variables using mathematical operators.

1 minutes = 60 seconds

1 foot = 12 inch

The unit multiplier for the conversion of 24 square feet per minute to square inches per second

24 ft/min = (24 ft² / 1 min) * (12 inch / ft) * (12 inch / ft) * (1 min / 60 sec)

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The estimated daily cost of increasing production to 42 televisions is $3717. Therefore, the closest answer choice is B) $3919.

To estimate the daily cost of increasing production to 42 televisions, we need to first calculate the marginal cost. The marginal cost is the derivative of the cost function:

[tex]C'(x) = -0.009x^2 + 0.2x + 71[/tex]

We can then evaluate the marginal cost at x=40 to find the cost of producing one additional television:

[tex]C'(40) = -0.009(40)^2 + 0.2(40) + 71 = $33.40[/tex]

This means that the cost of producing one additional television when 40 are already being produced is $33.40. To estimate the daily cost of increasing production to 42 televisions, we can multiply the marginal cost by 2 (since we want to produce 2 additional televisions):

[tex]2*$33.40 = $66.80[/tex]

Finally, we can add this estimated cost to the current cost of producing 40 televisions:

[tex]C(40) = -0.003(40)^3 + 0.1(40)^2 + 71(40) + 540 = $3650[/tex]

$3650 + $66.80 = $3716.80

Rounding to the nearest dollar, the estimated daily cost of increasing production to 42 televisions is $3717. Therefore, the closest answer choice is B) $3919.

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The distance traveled is 8ft and the displacement is 0ft.

The distance traveled is equal to the total distance that the ball travels, in this case it starts 4ft above the ground, then goes to the ground, and then returns to the initial position which is 4ft above the ground, then the total distance is 4ft + 4ft = 8ft

The displacement is equal to the difference between the final position and the inital one, here we know that both are the same, thus, the displacement is  0ft.

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The volume of the original candy bar box can be found by using the formula for the volume of a triangular prism, which is V = (1/2)bh times the height. Since the base of the triangular prism has sides of 1.5 inches, we can use this to calculate the base area, which is (1/2)(1.5)(1.5) = 1.125 square inches.

The height of the original box is 8 inches, so the volume can be calculated as V = (1.125)(8) = 9 cubic inches.

For the new candy bar box, the length of each side of the triangular base is doubled to 3 inches, while the length of the prism is halved to 4 inches. Using the same formula for the volume of a triangular prism, the base area is now (1/2)(3)(3) = 4.5 square inches. The height of the new box is 4 inches, so the volume can be calculated as V = (4.5)(4) = 18 cubic inches.

Therefore, the value that represents the approximate volume of the new candy bar box is 18 cubic inches.

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The figure after changing the scale of the grid is added as an attachment

From the question, we have the following parameters that can be used in our computation:

Old scale: 1 unit = 4 ft

New scale: 1 unit = 8 ft

Using the above as a guide, we have the following:

Scale = Old scale/New Scale

Substitute the known values in the above equation, so, we have the following representation

Scale: (1 unit = 4 ft)/(1 unit = 8 ft)

Evaluate

Scale: 1/2

This means that the figure on the new grid will be half the side lengths of the old grid

Next, we draw the figure

See attachment for the new figure

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The inequality represents the number of flowers, Truman would buy at Flowers Galore is f < 8.

Price of teddy bear = $13

Price of the flower = $0. 75

Florist charges the price of a teddy bear = $13

The florist charges the price of the flower = $1.25

Assume that number of flowers Truman buys = f

The total cost of purchasing teddy bears and flowers at Flowers Galore =

C1 = 13 + 0.75f

The total cost of purchasing teddy bears and flowers at  Famous Florist is C2 = 9 + 1.25f

The inequality for Flowers Galore can be written as:

C1 < C2

13 + 0.75f < 9 + 1.25f

0.5f < 4

Dividing on both sides by 0.5,

f < 8

Therefore, we can conclude that the inequality represents the number of flowers, Truman would buy is f < 8.

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If the mid-point of AB is M(-1,-4), then the coordinate of B is (1,-1).

In order to find the coordinate of point B, we use the midpoint formula, which states that the midpoint of a line segment with endpoints (x₁, y₁) and (x₂, y₂) is : ((x₁ + x₂)/2, (y₁ + y₂)/2);

In this case, we are given that the midpoint of the line segment AB is M(-1, -4), and the coordinate of point A is (-3, -7) = (x₁, y₁)

Let the coordinate of the end-point B be : (x₂, y₂),

Substitute these values into the formula and solve for the unknown coordinate of B : ((x₁ + x₂)/2, (y₁ + y₂)/2) = M(-1, -4),

Substituting the values,

We get,

((-3 + x₂)/2, (-7 + y₂)/2) = (-1, -4)

-3 + x₂ = -2,    and     -7 + y₂ = -8  

x₂ = 1,              and    y₂ = -1

Therefore, the coordinate of point-B is (1, -1).

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The accurate comparison of diameters of the given planets is 7, under the given condition that Neptune is  5 x 10⁴ kilometers in diameter. Mars is  7 x 10³ kilometers in diameter.

Therefore the correct answer for the given question is Option A

The diameter of Neptune is approximately counted to be  50,000km while the diameter of Mars is approximately  counted to be 7,000 km.

The ratio of the diameters of Neptune and Mars is given as:

diameter of Neptune / diameter of Mars

= 50,000km / 7,000km

= 7.14

≈ 7 times

The  Neptune diameter is 7 times greater Mars  diameter.

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The complete question is

Neptune is approximately 5 x 10⁴ kilometers in diameter. Mars is approximately 7 x 10³ kilometers in diameter. Which is an accurate comparison of the diameters of these two planets?

A. The diameter of Neptune is more than 7 times greater than the diameter of Mars.

B. The diameter of Mars is more than 7 times greater than the diameter of Neptune.

C. The diameter of Neptune is about 1.4 times greater than the diameter of Mars.

D. The diameter of Mars is about 1.4 times greater than the diameter of Neptune. ​

Step-by-step explanation:

Each circle has area   pi r^2   =   (pi)( 1.9)^2  in        ( 1.9 is the RADIUS)

  there are two of them so total circle area =  2 pi (1.9)^2    in^2

Then there is the rectangle

  one  of its dimensions is the CIRCUMFERENCE of the circles

      = pi * d  = pi * 3.8   in  

            and the other dimension is 3

               area of rectangle = pi * 3.8 * 3   in^2

Add all of the areas for the total area       2 pi (1.9)^2 + pi * 3.8*3   in^2 =

                                       = 18.62 pi   in^2

The mean travel time is 60 minutes, the standard deviation is approximately 6.08 minutes, and the probability that Alice will not be late for her class is 0.50 or 50%.

To find the mean travel time, we need to add up the mean times for each stage of Alice's journey. Let's calculate it step by step:

Step 1: Alice's walking time from home to the bus stop:

Mean walking time = 13 minutes

Step 2: Waiting time for the bus to arrive:

Mean waiting time = 5 minutes

Step 3: Bus journey time from the bus loop:

Mean bus journey time = 24 minutes

Step 4: Walking time from the bus loop to the lecture theatre:

Mean walking time = 18 minutes

Now, let's calculate the total mean travel time:

Mean travel time = Mean walking time + Mean waiting time + Mean bus journey time + Mean walking time

= 13 + 5 + 24 + 18

= 60 minutes

So, the mean travel time is 60 minutes.

To find the standard deviation of Alice's travel time, we need to calculate the variance for each stage and then sum them up. Finally, we take the square root to get the standard deviation. Let's calculate it step by step:

Step 1: Alice's walking time from home to the bus stop:

The variance of walking time = 4 minutes squared

Step 2: Waiting time for the bus to arrive:

The standard deviation of waiting time = 2 minutes

Step 3: Bus journey time from the bus loop:

The standard deviation of bus journey time = 5 minutes

Step 4: Walking time from the bus loop to the lecture theatre:

The variance of walking time = 4 minutes squared

Now, let's calculate the total variance of travel time:

Variance of travel time = Variance of walking time + Variance of waiting time + Variance of bus journey time + Variance of walking time

= 4 + 4 + 25 + 4

= 37 minutes squared

Finally, the standard deviation of travel time is the square root of the variance:

The standard deviation of travel time = [tex]\sqrt(37)[/tex]

≈ 6.08 minutes (rounded to 2 decimal places)

So, the standard deviation of Alice's travel time is approximately 6.08 minutes.

To find the probability that Alice will not be late for her class, we need to calculate the z-score for the desired arrival time and then find the corresponding probability from the standard normal distribution table. Let's calculate it step by step:

Step 1: Calculate the total travel time from home to the lecture theatre:

Total travel time = Mean travel time = 60 minutes

Step 2: Calculate the difference between the desired arrival time and the total travel time:

Time difference = 8 am - 7 am = 1 hour = 60 minutes

Step 3: Calculate the z-score using the formula:

z = (Time difference - Mean travel time) / Standard deviation of travel time

z = [tex]\frac{(60 - 60) }{ 6.08}[/tex]

z = 0

Step 4: Find the probability corresponding to the z-score from the standard normal distribution table.

Since the z-score is 0, the probability is 0.50 (or 50%).

Therefore, the probability (to 2 decimal places) that Alice will not be late for her class is 0.50 or 50%.

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The greater number is 455.

There are 197 women in the party.

The geometric ratio of the old and current price of the suit is 25/27.

The first problem requires the application of geometric ratios and algebraic manipulation to determine the greater of the two numbers. Geometric ratios are ratios between two quantities that are constant throughout.

We are also given that their difference is 35, which can be expressed as x - y = 35. We can use algebraic manipulation to solve for the values of x and y.

From the first equation, we can express x in terms of y as x = (13/6)y. Substituting this value of x into the second equation, we get (13/6)y - y = 35. Simplifying this equation, we get y = 210.

To find the value of x, we can substitute y = 210 into the equation x/y = 13/6, giving us x = 455. Therefore, the greater number is 455.

The second problem involves using ratios to find the number of women in a party. We are given that the ratio of men to women is 9 to 7, which can be expressed as 9x/7x, where x is a constant. We are also told that there are 45 men. We can use this information to solve for the number of women.

Therefore, the total number of parts is 45/9 = 5.

We can use this information to find the number of women, which is 7 parts of the ratio, or

=>  7x = (7/16) * 5 * 45 = 196.875.

Since we cannot have a fraction of a person, we round this value up to the nearest whole number, which is 197.

Therefore, there are 197 women in the party.

The third problem involves finding the geometric ratio of the old and current price of a men's suit. We are given that the suit cost $250,000 last year and that a dozen of these suits cost $3,250,000 this year. We can use the information provided to find the geometric ratio.

Since a dozen of the suits cost $3,250,000, one suit costs $3,250,000/12 = $270,833.33. The ratio of the old price to the new price is 250,000/270,833.33, which simplifies to 25/27.

Therefore, the geometric ratio of the old and current price of the suit is (25/27)¹ = 25/27.

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Complete Question:

The geometric ratio of two numbers is 13/6 and their difference is 35. What is the greater number?

At a party the ratio of men to women is 9 to 7. If 45 men are counted, how many women are there?

A men's suit cost $250,000 last year. This year a dozen of these suits cost $3,250. 000 What is the geometric ratio of the old and current price of the suit?

The age of the specimen with half-life 5760 years, to the nearest hundred years is 3184 years.

To find the age of the specimen, we can use the formula:

A = ([tex]A_{1}[/tex])[tex]2^{(-t/5760)}[/tex]

Where [tex]A_{1}[/tex] is the original amount of carbon-14 (120 milligrams), A is the current amount of carbon-14 (100 milligrams), t is the time elapsed since the organism died, and 5760 is the half-life of carbon-14.

Substituting the given values, we get:

100 = (120)[tex]2^{(-t/5760)}[/tex]

Taking the natural logarithm of both sides, we get:

ln(100) = ln(120) - t/5760 * ln(2)

Solving for t, we get:

t = -5760 * ln(100/120) / ln(2)

t ≈ 3183.7 years

Therefore, the age of the specimen is approximately 3184 years, rounded to the nearest hundred years.

It's worth noting that radiocarbon dating is only accurate up to a certain point, as the amount of carbon-14 in a specimen eventually becomes too low to measure accurately. The maximum age that can be reliably determined through radiocarbon dating is around 50,000 to 60,000 years. Beyond that, other methods such as dendrochronology (tree-ring dating) or uranium-thorium dating may be used.

Correct Question :

An archaeologist can determine the approximate age of certain ancient specimens by measuring the amount of carbon-14, a radioactive substance, contained in the specimen. The formula used to determine the age of a specimen is A = ([tex]A_{1}[/tex])[tex]2^{(-t/5760)}[/tex] where A is the amount of carbon-14 that a specimen contains, [tex]A_{1}[/tex] is the original amount of carbon-14, t is time, in years, and 5760 is the half-life of carbon-14. A specimen that originally contained 120 milligrams of carbon-14 now contains 100 milligrams of this substance. What is the age of the specimen, to the nearest hundred years?

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The area of the union of two disks with radius 1 and centers one unit apart is (5/3)π + (√(3))/4.

To find the area of the union of the two disks, we can use calculus to integrate over the area of overlap. The area of the union of the two disks is equal to the sum of the areas of C₁ and C₂ minus the area of their overlap. Each disk has a surface area of π(1)² = π, and a distance of 1 between their centers. We can use the law of cosines here,

The law of cosines states that c² = a² + b² - 2ab cos(θ), where c is the distance between the centers of the disks (1), a and b are the radii of C₁ and C₂ (1), respectively. Simplifying, we have,

cos(θ) = (1 - 1² - 1²)/(-211)

= -1/2,  so,

θ = 120 degrees.

The area of the overlap is equal to the area of a sector of C₁ with angle 120 degrees minus the area of the triangle formed by the centers of the disks and the point of intersection of the disks. The area of the sector is (120/360)π(1)² = (1/3)π, and the area of the triangle is,

(1/2)(1)(1)(sin(120)) = (√(3))/4.

Therefore, the area of the overlap is (1/3)π - (√(3))/4. The area of the union of the two disks is,

π + π - [(1/3)π - (√(3))/4]

= (5/3)π + (√(3))/4.

Thus, the area of the union of the two disks is (5/3)π + (√(3))/4.

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Answer:

8.5y

Step-by-step explanation:

you add what's in the parentheses, 0.5+8, it's 8.5

You then do 8.5*y, and you get

8.5y

There are 109 terms in given series.

Here, we have,

According to the statement

we have given that the sum of series is AP series and

This is 19 20.5 22 23.5 ... 181

And the sum of series is 10,900

Now, we have to find the number of terms in the series.

Then we use the summation formula which is

S = n/2 (a + L)

Substitute the all given values in it like

L = 181

A = 19 and S= 10,900

then

10,900= n/2(19+181)

10,900= n/2(200)

After solve the equation for n

10,900= 100n

n = 10,900 / 100

n = 109

There are 109 terms in given series.

So, There are 109 terms in given series.

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The significance level is the key indicator of whether or not a hypothesis can be supported. (option c)

In statistical analysis, there are several key indicators that are used to determine whether a hypothesis can be supported. One of these indicators is the significance level, which is denoted by the symbol alpha (α).

Another key indicator is the critical value, which is a value that is determined from a statistical distribution and is used to determine whether the observed data is statistically significant.

The test compares the observed frequencies of the categories to the expected frequencies, assuming that there is no association between the variables. The degrees of freedom refer to the number of categories minus one.

Therefore, to answer the original question, option (c)

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Since the limit of the ratio is less than 1 (1/3 < 1), the series is absolutely convergent (Option A). To determine the convergence of the series, we can use the Ratio Test. The series in question is:

Σ (3n² + 3) / (3n³ + 1)
First, we find the ratio between consecutive terms:
R = (a_(n+1)) / a_n = ((3(n+1)² + 3) / (3(n+1)³ + 1)) / ((3n² + 3) / (3n³ + 1))
R = (3(n+1)² + 3)(3n³ + 1) / ((3n² + 3)(3(n+1)³ + 1))
Now, as n goes to infinity:
lim (n -> ∞) R = lim (n -> ∞) (9n² + 6n + 3)(3n³ + 1) / (9n² + 3)(9n³ + 3n² + 3n + 1)
In this case, the highest power of n in the numerator and denominator is n⁵. To simplify, we can divide both the numerator and denominator by n⁵:
lim (n -> ∞) (9 + 6/n + 3/n²)(3 + 1/n²) / (9 + 3/n)(9 + 3/n² + 3/n + 1/n³)
As n approaches infinity, the terms with n in the denominator approaches zero:
lim (n -> ∞) (9)(3) / (9)(9) = 27 / 81 = 1/3
Since the limit of the ratio is less than 1 (1/3 < 1), the series is absolutely convergent (Option A).

To determine whether the series 3n² +  3n³ +1 is absolutely convergent, conditionally convergent, or divergent, we can use the ratio test.
Using the ratio test, we have:
lim n→∞ |(3(n+1)² + 3)/(3n² + 3n³ +1)
= lim n→∞ |(3n² + 6n + 3)/(3n³ + 3n² +1)
= lim n→∞ |(n² + 2n + 1)/(n³ + n²)
= 0
Since the limit is less than 1, the series is absolutely convergent. Therefore, the answer is A. Absolutely convergent.

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The particular solution Yp(t) is found by following these steps and combining it with the complementary solution Yc(t) to get the general solution Y(t) = Yc(t) + Yp(t).

To find the particular solution to [tex]y'' + y' - 12y = -340sin(t)[/tex] using variation of parameters, follow these steps:
1. Find the complementary solution Yc(t) for the homogeneous equation [tex]y'' + y' - 12y = 0[/tex]. The characteristic equation is[tex]r^2 + r - 12 = 0[/tex], which has roots r1 = -4 and r2 = 3. Thus, [tex]Yc(t) = C1e^(-4t) + C2e^(3t)[/tex].

2. Assume the particular solution Yp(t) is in the form [tex]Yp(t) = u1(t)e^(-4t) + u2(t)e^(3t)[/tex]. Calculate the Wronskian [tex]W(Y1, Y2) using Y1 = e^(-4t) and Y2 = e^(3t).[/tex]  3. Find u1'(t) and u2'(t) using the given nonhomogeneous equation: -340sin(t) = -Y1(t)u1'(t) + Y2(t)u2'(t).

4. Integrate u1'(t) and u2'(t) to find u1(t) and u2(t).
5. Plug u1(t) and u2(t) back into the particular solution [tex]Yp(t) = u1(t)e^(-4t) + u2(t)e^(3t[/tex]).

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The distance between the points (1, 1) and (1, -4) is 5 units and the reflection of the coordinate points is (-4, 6.2).

(a) We need to find the length between the pair of points which are (1, 1) and (1, −4). It can be determined by using the distance formula. The formula to find the distance between two points (x1, y1) and (x2, y2) is given as,

[tex]d = √(x2−x1)²+(y2−y1)²[/tex]

Given data:

The first points are = (1, 1)

second points are =(1, −4)

Substituting the first and second values into the distance formula, we get:

= √(1−1)²+(−4−1)²

= √0+(−5)²

= √25​

= 5

Therefore, The distance between the points (1, 1) and (1, -4) is 5 units.

(b )We need to find the reflection of the coordinate point. According to the reflection rule when a point is reflected across the y-axis, the x-coordinate changes sign while the y-coordinate remains the same. The reflected point will be,

= (x, y) = (-x, y).

Given Data:

Coordinate points = (4, 6.2)

According to the rule, it is given as:

= (4, 6.2)

= (-4, 6.2)

Therefore, the reflection of the coordinate points is (-4, 6.2)

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Answer:

1. x = 5

2. x = [tex]\sqrt 7 \approx[/tex] 2.65

Step-by-step explanation:

To solve these problems, we can use the diagram below, as well as Pythagoras's Theorem, which states:

[tex]\boxed{\mathrm{a^2 = b^2 + c^2}}[/tex],

where a is the hypotenuse (longest side) of a right-angled triangle, and b and c are the legs of the triangle.

1. x is the hypotenuse:

From the diagram below, we can see that, if x is the hypotenuse of the triangle, then 3 and four are the legs of the triangle. Therefore, using the above equation:

[tex]x^2 = 3^2 + 4^2[/tex]

⇒ [tex]x = \sqrt{3^2 + 4^2}[/tex]      [Taking the square root of both sides of the equation]

⇒ [tex]x = \sqrt{25}[/tex]

⇒ [tex]x = \bf 5[/tex]

2. x is one of the legs:

From the diagram below, we can see that when x is one of the legs, the hypotenuse is 4, and the other leg is 3.

The hypotenuse isn't 3 because the hypotenuse is the longest side in a right-angled triangle, and 4 is longer than 3.

Therefore,

[tex]4^2 = x^2 + 3^2[/tex]

⇒ [tex]x^2 = 4^2 - 3^2[/tex]             [Subtracting 3² from both sides]

⇒ [tex]x = \sqrt{4^2 - 3^2}[/tex]          [Taking the square root of both sides of the equation]

⇒ [tex]x = \sqrt{7}[/tex]

       [tex]\approx \bf 2.65[/tex]

The correct answer for an angle coterminal to -497° within the interval 0°≤θ≤360° is 223°.

What are Coterminal angles?

Coterminal angles are angles that share the same initial and terminal sides when drawn in the standard position (starting from the positive x-axis) on the coordinate plane. In other words, coterminal angles are angles that differ by an integer multiple of 360° or 2π radians.

To find an angle coterminal to within the interval use the fact that to add or subtract a multiple of to an angle does not change its position on the unit circle.

To make the angle positive, add  360°  repeatedly until an angle within the desired interval is obtained:

= -497° +360°

= -137°

adjust this angle to be within the interval 0°≤θ≤360°, and add another 360°:

= -137° + 360°

= 223°

The required angle is 223°.

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An angle θ coterminal to -497 degrees, where 0 ≤ θ < 360 degrees, is 223 degrees.

Given that; the angle is, -497 degrees.

Now, for an angle coterminal to -497 degrees within the range 0≤θ<360 degrees, add or subtract multiples of 360 degrees until we get an angle within the desired range.

Now, add multiples of 360 degrees until we get a positive angle:

-497 + 360 = -137

Now we have an angle of - 137 degrees, but it is still not within the desired range of 0 ≤ θ < 360 degrees.

To adjust the angle, add 360 degrees to it:

-137 + 360 = 223

Now an angle of 223 degrees, which is within the desired range.

Therefore, an angle θ coterminal to -497 degrees, where 0 ≤ θ < 360 degrees, is 223 degrees.

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The length of the diagonal of the house is 23.43 meters based on the dimensions of the John's guest house.

The diagonal of the house will be calculated using Pythagoras theorem. We know that diagonal will be hypotenuse and length and width will be base and perpendicular.

Diagonal = ✓length² + width²

Keep the values in formula

Diagonal = ✓18² + 15²

Taking square

Diagonal = ✓324 + 225

Adding the values

Diagonal = ✓549

Taking square root

Diagonal = 23.43 meters

Hence, the diagonal of the house is 23.43 meters.

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The equilibrium level of output in the economy can be calculated using the following formula:

Y = C + I + G + NX

Where:

Y = Equilibrium level of output

C = Consumption

I = Investment

G = Government spending

NX = Net exports

We can calculate consumption using the marginal propensity to consume (MPC) and autonomous spending (A):

C = MPC(Y - T) + A

Where:

T = Taxes (assumed to be 0 in this case)

Substituting in the given values:

C = 0.8(Y - 0) + 2000

C = 0.8Y + 2000

Substituting in the given values for investment, government spending, and net exports:

Y = 0.8Y + 2000 + 7500 + 10000 - 1000

Y = 0.8Y + 19500

Solving for Y:

0.2Y = 19500

Y = 97500

Therefore, the equilibrium level of output in the economy is $97,500.

If net exports increase by $1000, then the new value of net exports (NX) is 0.

Substituting the new value of NX into the formula:

Y = 0.8Y + 2000 + 7500 + 10000 - 0

Y = 0.8Y + 19500

Solving for Y:

0.2Y = 19500

Y = 97500

Therefore, the equilibrium level of output in the economy is still $97,500.

The multiplier is calculated as:

Multiplier = 1 / (1 - MPC)

Substituting in the value of MPC:

Multiplier = 1 / (1 - 0.8)

Multiplier = 5

Therefore, the multiplier in this case is 5.

The Lagrange Error Bound for P3(x) is |R3(x)| ≤ 0.00012, where f(x) = [tex]e^x[/tex]and x = 0.

To find the Lagrange Error Bound for the third-degree Taylor polynomial, we need to use the formula: |Rn(x)| ≤ (M / (n + 1)) * [tex]|x - a|^{(n+1)[/tex]

where M is an upper bound for [tex]|f^{(n+1)(x)}|[/tex]on the interval [a,x], and Rn(x) is the remainder or error term in the Taylor series.

For the given function f(x) = [tex]e^x[/tex], we have:

f(x) = [tex]e^x[/tex]

f'(x) = [tex]e^x[/tex]

f''(x) = [tex]e^x[/tex]

f'''(x) = [tex]e^x[/tex]

Since[tex]f^{(4)}(x) = e^x[/tex] is also [tex]e^x[/tex], the maximum value of |f^(4)(x)| on the interval [-0.25,0.25] is [tex]e^{0.25[/tex].

Thus, we can set [tex]M = e^{0.25[/tex] and a = 0. Then, using n = 3 (for the third-degree Taylor polynomial), we have:

|R3(x)| ≤ [tex](e^{0.25 / (3 + 1)}) * |x - 0|^4[/tex]

Simplifying, we get:

|R3(x)| ≤ 0.000125 * x⁴

Since x = 0.25 for this problem, we get:

|R3(0.25)| ≤ 0.000125 * 0.25⁴ = 0.00012

Therefore, the Lagrange Error Bound for P3(x) is |R3(x)| ≤ 0.00012, where f(x) =[tex]e^x[/tex] and x = 0. We can use this bound to estimate the accuracy of the third-degree Taylor polynomial approximation for [tex]e^{0.25[/tex].

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The complete relative frequency table include the following missing values:

Early bird Night Owl Total

Coffee. 0.21 0.44 0.65

Tea. 0.19. 0.16. 0.35

Total. 0.4. 0.6. 1

The total of each column is being determined from the grand total which can then be use to fill in the various missing parts of the relative frequency table.

For coffee;

To determine the total = 1-0.35 = 0.65

Coffee early Bird = 0.65-0.44 =0.21

For tea ;

Tea night owl = 0.35-0.19 = 0.16

For grand total = 1-0.6 = 0.4

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