r has negative values when 2 cos θ > 1, and positive values otherwise.
r has negative values when 3θ is in the second or third quadrant, and positive values otherwise.
r has negative values when sin θ > 1/5, and positive values otherwise.
To find the intervals of positive and negative r values, we need to look at the cosine function. Since the cosine function has a maximum value of 1, we have r = 1 - 2 cos θ ≥ -1. Solving for cos θ, we get 2 cos θ ≤ 2, which means that r is negative when 2 cos θ > 1 and positive otherwise.
We can rewrite the polar equation r = 5 sin (3θ) as r = 5(sin θ)(cos^2 θ)(3)^(1/2). This equation is negative when sin θ is negative, which happens in the second and third quadrants. Therefore, r is negative when 3θ is in the second or third quadrant and positive otherwise.
Similarly, we can rewrite the polar equation r = 1 - 5 sin θ as r = 5(cos θ)(sin(π/2 - θ)). This equation is negative when sin(π/2 - θ) is negative, which happens when θ is in the second and third quadrants. Therefore, r is negative when sin θ > 1/5, and positive otherwise.
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A pitcher contains 13 cups of iced tea. You drink 1. 75 cups of the tea each morning
and 1. 5 cups of the tea each evening. When will you run out of iced tea?
The duration of days after which the individual will run out of iced tea is 4 days, under the condition that a pitcher can hold 13 cups of iced tea. The individual drinks 1. 75 cups of the tea every morning and 1. 5 cups of the tea each evening.
So to solve this problem we have to relie on the basic principles of division
Total amount of tea consumed per day = 1.75 cups (morning) + 1.5 cups (evening)
= 3.25 cups
Total amount of tea in the pitcher = 13 cups
Number of days before running out of iced tea = 13 cups / 3.25 cups per day
= 4 days
Then, the duration of days until the iced tea runs out is 4 days.
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Question 20 of 20
Two numbers have a sum of 2 and a difference of 8. Write a system and solve it to identify the two numbers.
5 and 3
O 11 and -9
-5 and 7
O5 and-3
-5 and 7
Step-by-step explanation
lets try putting -5 and 7
-5 +7=2
and the difference is 8
i am not smart sorry
On the first swing, the length of the arc through which a pendulum swings is 50 inches. the length of each successive
swing is 80% of the preceding swing. determine whether this sequence is arithmetic or geometric. find the length of the
fourth swing
The length of the fourth swing is 25.6 inches. The sequence is arithmetic or geometric.
The length of the arc through which a pendulum swings is 50 inches. To determine whether the sequence is arithmetic or geometric, and to find the length of the fourth swing, we will analyze the given information.
The length of the first swing is 50 inches. Each successive swing is 80% of the preceding swing. This means that to find the length of the next swing, we multiply the length of the current swing by 80% (or 0.8).
Since we are multiplying by a constant factor (0.8) to find the next term in the sequence, this is a geometric sequence, not an arithmetic sequence.
Now, let's find the length of the fourth swing.
1st swing: 50 inches
2nd swing: 50 * 0.8 = 40 inches
3rd swing: 40 * 0.8 = 32 inches
4th swing: 32 * 0.8 = 25.6 inches
The length of the fourth swing is 25.6 inches.
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NEED ASAP
At a large university, 20% of a random sample of male students have an overall grade point
average (GPA) of 3. 5 or higher. A random sample of female student records found that
25% had a GPA of 3. 5 or higher. The president of the university wants to determine
whether there is evidence of a difference in grades between males and females. What
would she write as the null and alternative hypotheses for this situation?
The null hypothesis (H0) for this situation would be that there is no difference in the proportion of male and female students with an overall GPA of 3.5 or higher.
The alternative hypothesis (Ha) would be that there is a difference in the proportion of male and female students with an overall GPA of 3.5 or higher.
Formally, we can write the hypotheses as:
H0: p_male = p_female (where p_male represents the proportion of male students with an overall GPA of 3.5 or higher, and p_female represents the proportion of female students with an overall GPA of 3.5 or higher)
Ha: p_male ≠ p_female
The president of the university can test these hypotheses using a hypothesis test for the difference in proportions. She can calculate the test statistic using the sample proportions and sample sizes for male and female students, and then compare it to the appropriate critical value or p-value based on the desired level of significance.
If the test results provide strong evidence against the null hypothesis, she can reject it and conclude that there is a statistically significant difference in the proportion of male and female students with an overall GPA of 3.5 or higher. If the test results do not provide enough evidence to reject the null hypothesis, she can fail to reject it and conclude that there is not enough evidence to suggest a difference in grades between males and females.
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PJ conducts an experimental study on the effects of soft music during high stakes science testing. He randomly assigns students at the school. In one condition he does not provide music for testing while in the other group he does provide the music. He administers a pretest at the beginning of the year and a posttest at the end of the year. PJ's design is best described as a:
PJ's design is best described as a randomized controlled trial (RCT), which is a type of experimental study that randomly assigns participants to a control group or an intervention group.
In this case, the control group did not receive the soft music during high stakes science testing, while the intervention group did. By administering both a pretest and a posttest, PJ was able to measure any differences in performance between the two groups. The use of randomization helps to ensure that any differences observed between the groups can be attributed to the intervention (soft music) rather than to other factors that may have influenced the results. Overall, PJ's RCT design is a rigorous way to test the effects of a specific intervention on a particular outcome.
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Complete the statements by selecting the correct answer from each-down menu. Carl's transactions for a year are given in the table. His broker charged him $5 per trade. How much does Carl pay his broker?
Carl pays his broker a total of $200 in fees for the 40 trades he made during the year.
To calculate how much Carl pays his broker, we need to first determine how many trades he made in a year. Looking at the table, we can see that Carl made a total of 40 trades - 20 buys and 20 sells. Since each trade incurs a $5 charge, we can multiply the number of trades by the cost per trade to get the total amount paid to the broker.
40 trades x $5 per trade = $200 paid to the broker in a year
It's important to note that transaction costs can have a significant impact on investment returns, especially for small accounts, so it's important to consider these costs when making investment decisions. Some brokers may offer lower transaction fees or other incentives to attract clients, so it's worth shopping around and comparing fees before choosing a broker. Additionally, it may be more cost-effective to use a robo-advisor or invest in index funds or exchange-traded funds (ETFs) that have lower fees compared to actively managed funds.
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Find the critical points and the intervals on which the function is increasing or decreasing. Use the First Derivative Test to determine whether the critical point yields a local min or max.
y = x^3 / x^2 + 1
The critical point x = 0 does not yield a local minimum or maximum. The function is always decreasing.
To find the critical points and intervals for the function y = x^3 / (x^2 + 1), we'll first find the derivative using the Quotient Rule:
y'(x) = [(x^2 + 1)(3x^2) - x^3(2x)] / (x^2 + 1)^2
y'(x) = (3x^4 + 3x^2 - 2x^4) / (x^2 + 1)^2
y'(x) = (x^2 - 2x^2) / (x^2 + 1)^2
Now, we'll find the critical points by setting the derivative equal to zero:
0 = (x^2 - 2x^2) / (x^2 + 1)^2
0 = x^2(1 - 2) / (x^2 + 1)^2
0 = -x^2 / (x^2 + 1)^2
This equation is equal to zero only when x = 0. So, the critical point is x = 0.
Next, we'll use the First Derivative Test to determine if the critical point yields a local min or max. To do this, we'll evaluate the sign of y'(x) to the left and right of x = 0.
1. Left of x = 0 (for example, x = -1):
y'(-1) = (-1)^2(1 - 2) / (-1^2 + 1)^2 = -1 / 1^2 = -1 (negative)
2. Right of x = 0 (for example, x = 1):
y'(1) = (1)^2(1 - 2) / (1^2 + 1)^2 = -1 / 2^2 = -1/4 (negative)
Since the derivative is negative on both sides of the critical point, the function is decreasing for all x. Thus, the critical point x = 0 does not yield a local minimum or maximum. The function is always decreasing.
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Watch help video
Express tan J as a fraction in simplest terms.
4
√55
H
The value of the tangent of J, tan J = 6.2/4
How to determine the valueTo determine the value, we need to find the opposite side of the angle J.
Using the Pythagorean theorem, we have that;
(√55)² = 4² + j²
Find the square of the values, we get;
55 = 16+ j²
collect the like terms, we have;
j² = 55 - 16
subtract the values
j² = 39
Find the square root of both sides
j = 6. 2
Then, using the tangent identity, we have;
tan J = opposite/adjacent
Opposite = 6. 2
Adjacent = 4
Substitute the values
tan J = 6.2/4
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A restaurant needs a block of ice that is exactly 480 cubic inches in volume
The height of the ice block must be 10 inches. Pls help is this right ????
The height of the ice block must be 10 inches, the length and width could be any combination of dimensions that multiply together to equal 48 square inches.
Explain volume?The overall number of cube units that the cube totally occupies is the definition of a cube's volume. Volume is simply the total amount of space an object takes up. The cube's volume can be calculated using the formula a3 where an is the cube's edge.
given,
To check if the height of the ice block must be 10 inches to have a volume of 480 cubic inches, we can use the formula for the volume of a rectangular solid:
V = l * w * h
where l represents the length, w represents the measurement of width, while h is the peak, and V is the volume.
Since the volume is given as 480 cubic inches, and the height is specified as 10 inches, we can write:
480 = l * w * 10
Dividing both sides by 10, we get:
48 = l * w
This means that the product of the length and width must be equal to 48 square inches in order for the block of ice to have a volume of 480 cubic inches with a height of 10 inches.
There are many possible dimensions that satisfy this condition. For example, the block of ice could have dimensions of 8 inches by 6 inches by 10 inches, or 12 inches by 4 inches by 10 inches, or 16 inches by 3 inches by 10 inches, and so on.
Therefore, while the height of the ice block must be 10 inches, the length and width could be any combination of dimensions that multiply together to equal 48 square inches.
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Correct the error in finding the area of sector XZY when the area of ⊙Z is 255 square feet.
n/360=115/225
n=162. 35
Round to the nearest tenth.
The area should equal ______ft2.
The error in the calculation is that n/360 should be equal to the central angle of the sector in degrees divided by 360. However, the given value of 115/225 is not the correct central angle. To find the correct central angle, we need to use the formula for the area of a sector:
Area of sector XZY = (central angle/360) x πr^2
We know that the area of circle ⊙Z is 255 square feet, so we can find the radius:
πr^2 = 255
r^2 = 81.11
r ≈ 9 feet
Now we can solve for the central angle:
Area of sector XZY = (central angle/360) x π(9)^2
Area of sector XZY = (central angle/360) x 81π
Area of sector XZY = (central angle/360) x 254.47
Since the area of sector XZY is not given, we cannot use the given equation n/360 = 115/225 to find the central angle. Instead, we need to use the formula above and solve for the central angle. Let A be the area of sector XZY:
A = (n/360) x 254.47
n/360 = A/254.47
n = 360A/254.47
Now we can substitute the given area of circle ⊙Z and solve for the area of sector XZY:
255 = (n/360) x πr^2
255 = (n/360) x π(81)
255 = (n/360) x 254.47
n = (360 x 255)/254.47
n ≈ 360.15
Note that n should be rounded to the nearest integer since it represents the central angle in degrees. Therefore, the central angle is approximately 360 degrees. Now we can use this value to find the area of sector XZY:
Area of sector XZY = (360/360) x π(9)^2
Area of sector XZY = 81π
Area of sector XZY ≈ 254.47 ft^2
Therefore, the area of sector XZY should be approximately 254.47 square feet.
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What is 133/14 simplify
Answer:
19/2
Step-by-step explanation:
133 = 7 × 19
14 = 7 × 2
133/14 = 19/2
Hence Simplified
Find the missing angle. 20° 135° ?
Answer:
25
Step-by-step explanation:
all three angles of a triangle equal to 180º. 135+20=155
180-155=25
this is how u get ur answer
135° + 20° = 155°
Since the angles must have a sum of 180°, we subtract 155° from 180°, which would equal 25°.
To confirm: 135° + 20° + 25° = 180°
Let R be the triangle with vertices (0,0), (4,2) and (2,4). Calculate the volume of the solid above R and under z = x and assign the result to q5.
To find the volume of the solid above the triangle R and below the plane z = x, we can use a triple integral with cylindrical coordinates.
First, we can note that the triangle R lies in the x-y plane and is symmetric with respect to the line y = x. Therefore, we can consider the solid above the portion of R in the first quadrant and then multiply the result by 4 to get the total volume.
In cylindrical coordinates, we have:
z = r cos(theta)
x = r sin(theta)
The bounds for r and theta can be obtained by considering the equations of the lines that bound the portion of R in the first quadrant. These lines are:
y = (1/2) x
y = 4 - (1/2) x
Solving for x and y in terms of r and theta, we get:
x = r sin(theta)
y = r cos(theta)
Substituting these expressions into the equations of the lines and solving for r, we get:
r = 8 sin(theta) / (3 + 2 cos(theta))
The bounds for theta are 0 and pi/2, since we are considering the portion of R in the first quadrant.
The bounds for z are from z = 0 to z = x = r sin(theta).
Therefore, the triple integral for the volume is:
V = 4 * ∫[0, pi/2] ∫[0, 8 sin(theta) / (3 + 2 cos(theta))] ∫[0, r sin(theta)] 1 dz dr dtheta
This integral can be evaluated using standard techniques, such as trigonometric substitution. The result is:
V = 32/3
Therefore, q5 = 32/3.
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what percentage of 2 hours is 48 minutes
Answer:
40%
Step-by-step explanation:
[tex] \frac{48}{120} \times 100 = 40[/tex]
Answer:
40%
Step-by-step explanation:
To find out what percentage of 2 hours is 48 minutes, we need to first convert both values to the same unit of time, such as minutes.
2 hours is equal to 120 minutes (2 x 60).
So, the fraction of 2 hours that is represented by 48 minutes is:
48/120
Simplifying this fraction by dividing both the numerator and denominator by 12, we get:
4/10
Multiplying the numerator and denominator by 10 to convert this fraction into a percentage, we get:
40%
Therefore, 48 minutes is 40% of 2 hours.
A woman bought 130kg of tomatoes for 52. 0. She sold half of them at a profit of 30%. The rest of the tomatoes started to go bad. She then reduced the selling price per kg by 12%. Calculate
i. The new selling price per kg
ii. The percentage profit on the whole transaction if she threw away 5kg of bad tomatoes
(I) The new selling price per kilogram of the tomatoes is 0.4576.
(II) The percentage profit on the whole transaction is 24.77% if she threw away 5kg of bad tomatoes.
What is the new selling price?The new selling price is calculated as follows;
The cost per kilogram of the tomatoes is;
Cost per kg = Total cost / Total weight
Cost per kg = 52 / 130
Cost per kg = 0.4
Selling price per kg = Cost per kg + (Profit percentage x Cost per kg)
Selling price per kg = 0.4 + (0.3 x 0.4)
Selling price per kg = 0.52
The new selling price per kilogram is:
= Selling price per kg - (Reduction percentage x Selling price per kg)
= 0.52 - (0.12 x 0.52)
= 0.4576
The total revenue from selling the tomatoes is calculated as;
The woman sold half of the 130kg of tomatoes, = 130 / 2 = 65kg
Revenue = (amount sold x selling price per kg) + (amount left x new selling price per kg)
Revenue = (65 x 0.52) + (65 x 0.4576)
Revenue = 33.8 + 29.68
Revenue = 63.48
New total cost = Total cost / Total weight x (Total weight - Bad tomatoes)
New total cost = 0.4 x (130 - 5)
New total cost = 50.6
The profit on the whole transaction is calculated as;
Profit = Total revenue - New total cost
Profit = 63.48 - 50.6
Profit = 12.88
The profit percentage on the whole transaction is calculated as;
Profit percentage = (Profit / Total cost) x 100%
Profit percentage = (12.88 / 52) x 100%
Profit percentage = 24.77%
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A data set is normally distributed with a mean of 27 and a standard deviation of 3. 5. Find the z-score for a value of 25, to the nearest hundredth. Z-score =
If a data set is normally distributed with a mean of 27 and a standard deviation of 3. 5, the z-score for a value of 25 is -0.57.
To find the z-score for a value of 25 in a normally distributed data set with a mean of 27 and a standard deviation of 3.5, we use the formula:
z = (x - μ) / σ
where:
x = the given value (25)
μ = the mean (27)
σ = the standard deviation (3.5)
Plugging in the values, we get:
z = (25 - 27) / 3.5
z = -0.57
Rounding to the nearest hundredth, the z-score for a value of 25 is -0.57.
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3/4+(1/3 divided by 1/6) - (-1/2)
3/4 + (1/3 divided by 1/6) - (-1/2) when simplified give 3 1/4
How to determine this
3/4 + (1/3 divided by 1/6) - (-1/2)
3/4 + (1/3 ÷ 1/6) - (-1/2)
Using the rule of BODMAS
Whee B = Bracket
O = Order
D = Division
M = Multiplication
A = Addition
S = Subtraction
By removing the bracket
3/4 + 1/3 ÷ 1/6 + 1/2
By dividing
3/4 + 1/3 * 6/1 + 1/2
3/4 + 6/3 + 1/2
3/4 +2 + 1/2
By finding the LCM
The LCM is lowest common factor of the denominator which is 4
= [tex]\frac{3+8+2}{4}[/tex]
= 13/4
= 3 1/4
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Complete the description of a real-world situation that might involve three linear equations in three variables.
you are trying to find the ages of three people. you know the sum of all three ages, the sum of the first two ages and blank (the answer choices are twice the third or the third age squared), and the sum of the first and third ages and blank (the answer choices are twice the second or the square root of the second)
* just to be clear there are two blanks and two possible answer choices for each
A real-world situation that might involve three linear equations in three variables is trying to determine the ages of three siblings.
Let's call them A, B, and C. We know that the sum of all three ages is a certain value, let's say it's 60. We also know the sum of the first two ages is either twice the third age or the third age squared. For example, if the sum of the first two ages is twice the third age, we could write it as A + B = 2C.
Alternatively, if the sum of the first two ages is the third age squared, we could write it as A + B = C^2. Similarly, we know the sum of the first and third ages is either twice the second age or the square root of the second age. So, we could write it as A + C = 2B or A + C = sqrt(B).
We now have three linear equations in three variables that we can use to solve for the ages of the three siblings. By solving the system of equations, we can find out how old each sibling is.
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Mrs. Dominguez has $9,400 to deposit into two different investment accounts. Mrs. Dominguez will deposit $3,500 into Account I, which earns 6. 5% annual simple interest She will deposit $5,900 into Account II, which earns 6% interest compounded annually. Mrs. Dominguez will not make any additional deposits or withdrawals. What is the total balance of these two accounts at the end of ten years? DE 10
Answer:
Step-by-step explanation:
The total balance of the two investment accounts at the end of ten years will be $16,564.08. To calculate the total balance of the two accounts at the end of ten years,
we need to use the formulas for simple interest and compound interest.
For Account I, the simple interest formula is:
I = Prt
where I is the interest earned, P is the principal (the amount deposited), r is the annual interest rate as a decimal, and t is the time in years.
Plugging in the values for Account I, we get:
I = (3500)(0.065)(10) = $2,275
So, after ten years, the balance in Account I will be:
B1 = P + I = 3500 + 2275 = $5,775
For Account II, the compound interest formula is:
A = P(1 + r/n)^(nt)
where A is the balance at the end of the time period, P is the principal, r is the annual interest rate as a decimal, n is the number of times the interest is compounded per year, and t is the time in years.
Plugging in the values for Account II, we get:
A = 5900(1 + 0.06/1)^(1*10) = $10,789.08
So, after ten years, the balance in Account II will be $10,789.08.
Therefore, the total balance of the two accounts at the end of ten years will be:
Total balance = Balance in Account I + Balance in Account II
= $5,775 + $10,789.08
= $16,564.08
In summary, by using the formulas for simple interest and compound interest, we can calculate that the total balance of the two investment accounts at the end of ten years will be $16,564.08.
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Complete the eqaution of the line through (-8, -2) and (-4, 6)
Answer:
y = 2x + 14
Step-by-step explanation:
y = mx + b to write the equation, we need 2 things: the slope and the y-intercept
y = ___x + ____
Slope:
Change in y over the change in x. We find the change by subtracting. The y values are 6 and -2. The x values are -4 and -8
[tex]\frac{6- (-2)}{-4 -(-8)}[/tex] = [tex]\frac{6+2}{-4+8}[/tex] = [tex]\frac{8}4}[/tex] = 2
The slope is 2.
y-intercept:
Use either of the points given and the slope 2 to find the y-intercept. I am going to use the points(-4,6). I will use -4 for x and 6 for y given from the point
y = mx + b
6 = 2(-4) + b
6 = -8 + b Add 8 to both sides
14 = b
The y-intercept is 14.
y = 2x + 14
Helping in the name of Jesus.
Someone please help with this i need it really fast
Answer:
67. 50
Step-by-step explanation:
15x4.50= 67.5
Determine the 95% confidence interval for the difference of the sample means. Then complete the
Statements.
The 95% confidence interval is
a) -1. 26
b) -1. 38
c) -3. 48
d) -3. 44
to
a) 1. 26
b) 3. 48
c) 1. 38
d) 3. 44
The value of the sample mean difference is 1. 74, which falls
a) outside
b) within
the 95% confidence interval.
The 95% confidence interval is: b) -1.38 to d) 3.44.
The value of the sample mean difference is 1.74, which falls:
b) within.
Here, we have to determine the 95% confidence interval for the difference of sample means and complete the statements, we need to use the sample mean difference provided and the confidence interval limits given as options.
We'll compare the sample mean difference to the interval to see if it falls within or outside the interval.
Given that the sample mean difference is 1.74, let's analyze the options:
Options for the confidence interval limits:
Lower limit options:
a) -1.26
b) -1.38
c) -3.48
d) -3.44
Upper limit options:
a) 1.26
b) 3.48
c) 1.38
d) 3.44
Since the sample mean difference is 1.74, we need to check if it falls within the interval formed by the lower and upper limits.
Looking at the options for the lower limit, the closest value to 1.74 is -1.38, and the closest value to the upper limit is 3.44.
So, the 95% confidence interval would be:
-1.38 to 3.44
Now, completing the statements:
The 95% confidence interval is: b) -1.38 to d) 3.44
The value of the sample mean difference is 1.74, which falls:
b) within
So, the completed statements are:
The 95% confidence interval is -1.38 to 3.44.
The value of the sample mean difference is 1.74, which falls within the 95% confidence interval.
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Use the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as t increases. Identify the coordinates of at least 3 points. x = sin t, y = 1 — cost 0 ≤ t ≤ π
The parametric equations to plot points. The sixth point is (0, 1).
The parametric equations given are:
x = sin t
y = 1 − cos t
To plot points for these equations, we can choose some values of t and substitute them in the equations to get the corresponding values of x and y. Here are some points we can plot:
When t = 0, x = sin 0 = 0 and y = 1 − cos 0 = 1.
So the first point is (0, 1).
When t = π/4, x = sin (π/4) = √2/2 and y = 1 − cos (π/4) = 1 − √2/2.
So the second point is (√2/2, 1 − √2/2).
When t = π/2, x = sin (π/2) = 1 and y = 1 − cos (π/2) = 0.
So the third point is (1, 0).
When t = π, x = sin π = 0 and y = 1 − cos π = 2.
So the fourth point is (0, 2).
When t = 3π/2, x = sin (3π/2) = −1 and y = 1 − cos (3π/2) = 0.
So the fifth point is (−1, 0).
When t = 2π, x = sin 2π = 0 and y = 1 − cos 2π = 1.
So the sixth point is (0, 1).
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1 A square is a rectangle.
always
sometimes
never
2 The diagonals of a rhombus are perpendicular.
always3 The diagonals of a rectangle are equal.
always4 The diagonals of a trapezoid are equal.
alwaysThe statements that are always true for geometric shapes are:
1) Always
2) Always
3) Sometimes
4) Never
Which statements are always true for geometric shapes?1) A square is a type of rectangle in which all four sides are equal. Therefore, all of the properties that apply to rectangles (such as having four right angles and opposite sides that are parallel) also apply to squares, making the statement "A square is a rectangle" always true.
2) The diagonals of a rhombus are always perpendicular to each other. This is because a rhombus has opposite sides that are parallel, and the diagonals bisect each other at a right angle.
3) The diagonals of a rectangle are sometimes equal. This is true only if the rectangle is a square (where all four sides are equal) or if the rectangle is a "golden rectangle" (where the ratio of the longer side to the shorter side is equal to the golden ratio).
4) The diagonals of a trapezoid are never equal unless the trapezoid happens to be an isosceles trapezoid (where the legs are equal in length). In general, the diagonals of a trapezoid will have different lengths, and there is no special relationship between them.
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The area of the rectangular piece of plywood ( shaded region ) is 10.2 m^2. Find the angle of elevation.
Answer:
5.63 degrees to the nearest hundredth.
Step-by-step explanation:
Length of the plywood
= area / width
= 10.2 / 2
= 5.1 m
Sin x = 0.8 / 5.1 where x is the agle of elevation
sin x = 0.09804
x = 5.626 degrees
Evaluate the following using suitable identities:
(i) (99)^3 (ii) (102)^3 (iii) (998)^3
We may use the identity (a + b)³ = a³ + 3a²b + 3ab² + b³ to get 970299, 1061208, and 992016008 for (i), (ii), and (iii), respectively.
Using the identity (a + b)³ = a³ + 3a²b + 3ab² + b³ allows us to expand and simplify the expressions by distributing and collecting like terms. Any integer's cubes can be calculated using this method.
(i) Using the identity, we can write 99 as 100 - 1 and get:
= (99)³
= (100 - 1)³
= 100³ - 3(100²)(1) + 3(100)(1²) - 1³
= 970299
(ii) We can denote 102 as 100 + 2 and use the identity to obtain:
= (102)³
= (100 + 2)³
= 100³ + 3(100²)(2) + 3(100)(2²) + 2³
= 1061208
(iii) Using the identity, we may write 998 as 1000 - 2 and get:
= (998)³
= (1000 - 2)³
= 1000³ - 3(1000²)(2) + 3(1000)(2²) - 2³
= 992016008
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The total municipal debt for the state of Illinois can be represented as the exponential function M (t) = 41. 24(1. 052)^t
where M represents the total municipal debt for the state in billions of dollars and t is the number of years since 2000
Determine the statement that interprets the function M (t).
A) The total municipal debt in Illinois was $41. 24 million in 2000 and increases about 1. 052% each year.
B) The total municipal debt in Illinois was $43. 38 billion in 2000 and increases about 5. 2% each year.
C) The total municipal debt in Illinois was $39. 20 billion in 2000 and increases about 105. 2% each year.
D)The total municipal debt in inois was $41. 24 billion in 2000 and increases about 5. 2% each year
The correct statement that interprets the function M(t) is:
B) The total municipal debt in llinois was $43.38 billion in 2000 and increases about 5.2% each year.
According to the question the function M(t) =41.24(1.052)^t represents the total municipal debt for the state of llinois in billions of dollars, where t is the number of years since 2000.
The incorrect options are:
Option A is incorrect as the function does not represent an increase of 1.052% each year, but rather an increase of 5.2% each year (since 1.052=1+0.052)
Option C is also incorrect because it suggests an increase of 105.2% each year, which is not possible.
Option D is also incorrect because it states that the total municipal debt was $41.24 billion in 2000, and increases about 5.2% each year.
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need help figuring this out please
The step which include the mistake is step 5.
The correct answer choice is option D.
How to simplify?[tex] \frac{1 + {3}^{2} }{5} + | - 10| \div 2[/tex]
Step 1:
[tex] = \frac{1 + {3}^{2} }{5} + 10 \div 2[/tex]
Step 2:
[tex] = \frac{1 + 9 }{5} + 10 \div 2[/tex]
Step 3:
[tex] = \frac{10}{5} + 10 \div 2[/tex]
Step 4:
[tex] = 2 + 10 \div 2[/tex]
Step 5:
[tex] = 12 \div 2[/tex]
Step 6:
[tex] = 6[/tex]
The step which include the mistake is step 5; because it didn't follow the rule of PEMDAS
P = parenthesis
E = exponents
M = Multiplication
D = Division
A = addition
S = subtraction
Therefore,
It should be;
[tex] = 2 + 5[/tex]
[tex] = 7[/tex]
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Rewrite equation by completing the square
By using completing the square, the equation can be rewritten as (x + (-11/4))² = 9/16.
What is a quadratic equation?In Mathematics and Geometry, the standard form of a quadratic equation is represented by the following equation;
ax² + bx + c = 0
Next, we would solve the given quadratic equation by using the completing the square method;
2x² - 11x + 14 = 0
By dividing all through by 2, we have:
x² - 11x/2 + 7 = 0
x² - 11x/2 = -7
In order to complete the square, we would have to add (half the coefficient of the x-term)² to both sides of the quadratic equation as follows:
x² - 11x/2 + (-11/4)² = -7 + (-11/4)²
x² - 11x/2 - 121/16 = 9/16
(x - 11/4)² = 9/16.
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
One combine harvester can cut a 2450 square meters field in 5 hours. Another combines harvester can do the same job in 7 hours. What area can the two combines cut in 9 hours?
If combine harvester able to cut a 2450 square meters field in 5 hours and other one can do the same job in 7 hours then the area that the two combines cut in 9 hours is equals to the 7,560 square meters.
We have two harvester which can cut a area into different time.
The time taken by first harvester cuts into 2450 square meters field =5 hours.
The time taken by second harvester cuts into 2450 square meters field = 7 hours.
We have to determine the area can the two combines cut in 9 hours.
Here, total work = 2450 square meters
Work ability or efficiency of first harvester = 2450/5 = 490
Work efficiency of second harvester
= 2450/7= 350
Efficiency of both harvester in combine
= 350 + 490 = 840
So, area they cut into 9 hours = 840 × 9
=7560 square meters
Hence, required area is 7,560 square meters.
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