Answer:
(8/√2)^2 = 64/2 = 32 square inches
The volume of a cone 69,120π cm cubed. The diameter of the circular base is 96 cm, what is the height of the cone?
Answer:
h = 30 cm
Step-by-step explanation:
Given:
V (volume) = 69,120π cm^3
d (diameter) = 96 cm (r (radius) = 0,5 × 96 = 48 cm
Find: h (height) - ?
[tex]v = \frac{1}{3} \times \pi {r}^{2} \times h[/tex]
[tex] \frac{1}{3} \times \pi \times {48}^{2} \times h = 69120\pi[/tex]
Multiply the whole equation by 3 to eliminate the fraction:
[tex]2304\pi \times h = 69120\pi[/tex]
[tex]h = 30[/tex]
1. Given the function: f(x)=-2x+7 and g(x)=5x-16
Find the function for h(x)=f(x)+g(x)
The function h(x) can be represented by -3x-9 .
Linear Equation
An equation can be represented by a linear function. The standard form for the linear equation is: y= mx+b , for example, y=7x+6. Where:
m= the slope.
b= the constant term that represents the y-intercept.
For the given example: m=7 and b=6.
The question gives two linear equations that represent two functions: f(x)=-2x+7 and g(x)=5x-16.
For solving this you should sum both equations. See below
h(x)=f(x)+g(x)
h(x)=-2x+7 +5x-16
h(x)=-3x-9
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If JM=10 and LM=14, what is KM?
Write your answer as a whole number or as a decimal rounded to the nearest hundredth.
KM =
The calculated value of the length of segment KM is 11.83
Calculating the length of KMFrom the question, we have the following parameters that can be used in our computation:
JM = 10
LM = 14
Using the similar triangle ratio, we have
JM/KM = KM/LM
substitute the known values in the above equation, so, we have the following representation
10/KM = KM/14
So, we have
KM^2 = 10 * 14
Evaluate
KM^2 = 140
This gives
KM = 11.8321595662
As a decimal rounded to the nearest hundredth, we have
KM = 11.83
HEnce, the value of KM is 11.83
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Simplify the expression five to the third power +3(5-3)
Answer:
Step-by-step explanation:
The expression +3(5-3) can be simplified using the order of operations (PEMDAS) as follows: first, we need to perform the exponentiation operation, which gives us 125.
Then, we need to perform the operation inside the parentheses, which gives us 6. Finally, we multiply 3 by 6, giving us 18. Therefore, the simplified expression is 125 + 18 = 143.
To further explain this solution, we use the order of operations, which is a set of rules that dictate the order in which operations must be performed when evaluating an expression. The acronym PEMDAS stands for Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction, which represents the order of operations from left to right.
In this expression, we first need to evaluate the exponentiation operation, which is 5 to the third power. This gives us 125. Next, we need to perform the operation inside the parentheses, which is 5-3. This gives us 2. We then multiply 3 by 2, which gives us 6. Finally, we add 125 and 6, giving us 131.
It is important to follow the order of operations when simplifying an expression to ensure that we obtain the correct result. By using PEMDAS, we can systematically simplify an expression step-by-step, avoiding any potential errors and obtaining a clear and concise solution.
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Find the moment of inertia about the y-axis of the
first-quadrant area bounded by the curve y=9−x^2
and the coordinate axes find ly (answer as a fraction)
To find the moment of inertia about the y-axis of the first-quadrant area bounded by the curve y=9−x^2 and the coordinate axes, we can use the formula:
I = ∫y² dA
where I is the moment of inertia, y is the distance from the y-axis to the infinitesimal element of area dA, and the integral is taken over the first-quadrant area.
To set up the integral, we need to express y in terms of x for the curve y=9−x². Solving for y, we get:
y = 9 - x²
The area element dA is given by:
dA = y dx
Substituting y in terms of x, we get:
dA = (9 - x²) dx
Now we can express the moment of inertia as an integral:
I = ∫y² dA
= ∫(9 - x²)² dx (limits of integration: x = 0 to x = 3)
To evaluate the integral, we can expand the integrand using the binomial theorem:
I = ∫(81 - 36x² + x⁴) dx
= 81x - 12x³ + (1/5)x⁵ (limits of integration: x = 0 to x = 3)
Finally, we can substitute the limits of integration and simplify:
I = (81(3) - 12(3)³ + (1/5)(3)⁵) - 0
= 243 - 108 + 27
= 162
Therefore, the moment of inertia about the y-axis is 162 units^4.
To find the moment of inertia (Iy) about the y-axis for the first-quadrant area bounded by the curve y = 9 - x^2 and the coordinate axes, we need to integrate the expression for the moment of inertia using the limits of the region.
The curve intersects the x-axis when y = 0, so:
0 = 9 - x²
x² = 9
x = ±3
Since we're in the first quadrant, we're interested in x = 3.
The moment of inertia about the y-axis is given by the expression Iy = ∫x²dA, where dA is the area element. In this case, we'll use a vertical strip with thickness dx and height y = 9 - x². Therefore, dA = y dx.
Now, let's integrate Iy:
Iy = ∫x²(9 - x²) dx from 0 to 3
To solve this integral, you may need to use polynomial expansion and integration techniques:
Iy = ∫(9x² - x⁴) dx from 0 to 3
Iy = [3x³/3 - x⁵/5] from 0 to 3
Iy = (3(3)³/3 - (3)⁵/5) - (0)
Iy = (81 - 243/5)
Iy = (405 - 243)/5
Iy = 162/5
So the moment of inertia about the y-axis for the first-quadrant area bounded by the curve y = 9 - x^2 and the coordinate axes is Iy = 162/5.
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Shea wrote the expression 5(y + 2) + 2 to show the amount of money five friends paid for snacks at a basketball game. Which expression is equivalent to the one Shea wrote?
a 5 + y + 5 + 2 + 4
b 5 x y x 5 x 2 +4
c 5 x y x 4 + 5 x 2 x 4
d 5 x y + 5 x 2 + 4
The expression that is equivalent to the one Shea wrote is b 5 x y x 5 x 2 +4
Which expression is equivalent to the one Shea wrote?From the question, we have the following parameters that can be used in our computation:
5(y + 2) + 2 shows the amount of money five friends paid for snacks at a basketball game
This means that
Amount = 5(y + 2) + 2
When expanded, we have
Amount = 5 * y + 5 * 2 + 2
Using the above as a guide, we have the following:
The expression that is equivalent to the one Shea wrote is b 5 x y x 5 x 2 +4
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Part B
Yasmina wants to earn money at her school's Spring Fair by offering horseback
rides for children. She calls a few places about renting a horse.
Polly's Ponies charges $100 for a small pony. Yasmina can charge children $2
for a ride on one.
Sally's Saddles charges $240 for a larger horse. Yasmina can charge children
$3 for a ride on one.
Select the choices that correctly complete the statements from the drop-down
menus.
The price of using the two companies would be equal if children took a total of
Choose. V rides.
If Yasmina expects to give 200 rides, she should use Choose. Pollys Ponies or Sally's Saddles
Based on the given information, Yasmina should use Sally's Saddles if she expects to give 200 rides and wants to make the most profit.
To determine which company Yasmina should use to offer horseback rides at her school's Spring Fair, we need to compare the costs and revenues associated with each option.
First, let's consider Polly's Ponies. They charge $100 for a small pony and Yasmina can charge children $2 for a ride. To break even with this option, Yasmina would need to give 50 rides ($100 / $2 per ride). If she expects to give 200 rides, she would earn $400 in revenue ($2 per ride x 200 rides) and have a profit of $300 ($400 revenue - $100 rental fee).
Next, let's consider Sally's Saddles. They charge $240 for a larger horse and Yasmina can charge children $3 for a ride. To break even with this option, Yasmina would need to give 80 rides ($240 / $3 per ride). If she expects to give 200 rides, she would earn $600 in revenue ($3 per ride x 200 rides) and have a profit of $360 ($600 revenue - $240 rental fee).
Therefore, if Yasmina wants to make the same amount of profit regardless of which company she uses, she would need children to take a total of 125 rides ((($240 rental fee for Sally's Saddles - $100 rental fee for Polly's Ponies) / ($3 per ride - $2 per ride)). If she expects to give 200 rides, she should use Sally's Saddles since she will make a higher profit of $360 compared to $300 with Polly's Ponies.
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Question 1. 4. The survey results seem to indicate that Imm Thai is beating all the other Thai restaurants among the voters. We would like to use confidence intervals to determine a range of likely values for Imm Thai's true lead over all the other restaurants combined. The calculation for Imm Thai's lead over Lucky House, Thai Temple, and Thai Basil combined is:
We know that when you have this data, you can proceed with calculating the confidence intervals to determine IMM Thai's lead.
Hi there! The survey results seem to indicate that IMM Thai is indeed ahead of the other Thai restaurants among the voters.
To determine a range of likely values for IMM Thai's true lead over Lucky House, Thai Temple, and Thai Basil combined, you would need to calculate confidence intervals.
Unfortunately, I cannot provide specific calculations without the necessary data (sample size, mean, standard deviation, etc.).
Once you have this data, you can proceed with calculating the confidence intervals to determine IMM Thai's lead.
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Maya is designing a quilt. Each piece will be in the shape of a parallelogram. She wants the base, b, of each piece to be 6 inches. The area, A, must be 42 square inches. What length should Maya use for the height, h?
The required height for which the base is 6 inches and the area of 42 square inches is 7 inches.
Each piece will be in a shape of a parallelogram so we know that the area of the parallelogram is given as
area= height * base
Now we are provided with the base of the parallelogram that is 6 inches. The area of the piece is also given as 42 sq inches. So, we can solve and get the height from the above equation.
Height (h) = area/ base
Height (h)= 42/6
Height (h)= 7 inches.
Therefore, Maya should use a height of 7 inches for each piece in order to achieve a base of 6 inches and an area of 42 sq inches.
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Identify the random variable in each distribution, and classify it as
discrete or continuous. Explain your reasoning.
1) The number of hits for the players of a baseball team.
2) The distances traveled by the tee shots in a golf
The random variable in the first situation is the number of hits for the players of a baseball team and in the second situation is the distance traveled by the tee shots in a golf game.
1) The random variable in this distribution is the number of hits for the players of a baseball team. This is a discrete random variable because hits are counted as whole numbers and cannot take on non-integer values.
2) The random variable in this distribution is the distance traveled by the tee shots in a golf game. This is a continuous random variable because the distances traveled can take on any value within a certain range, including non-integer values. The exact distance traveled by a tee shot can be measured to any degree of precision, and there are infinitely many possible distances within the range of possible outcomes. Therefore, it is a continuous random variable.
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Last year, Jane opened an investment account with . At the end of the year, the amount in the account had decreased by . How much is this decrease in dollars? How much money was in her account at the end of last year?
Decrease in amount:
Year-end amount:
1. The dollar decrease of Jane's investment account is $2,166.
2. The amount in Jane's account at the end was $5,434.
How much is this decrease in dollars?To get the decrease in dollars, we need to calculate 28.5% of $7,600.
The dollar decrease will be:
= 0.285 x $7,600
= $2,166
How much money was in her account?To find the amount, we must subtract the decrease from the initial amount. So, the end balance will be:
= $7,600 - $2,166
= $5,434
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Practice: IXL Write linear,quadratic, and exponential functions and i need help figuring out if this is a linear, quadratic, or a exponential function and the answer to it.
The linear equation is y = 4x + 2, the quadratic equation is y = 4x² - 2x + 2 , and the exponential equation is y = 2(3ˣ).
Let's use the first two points on the table: (0, 2) and (1, 6).
The slope is (6 - 2) / (1 - 0) = 4.
To find the y-intercept, we can plug in one of the points and solve for b in the equation y = mx + b.
Let's use (0, 2): 2 = 4(0) + b, so b = 2.
Therefore, the linear equation is y = 4x + 2.
We need to find the values of a, b, and c. Let's use the first three points on the table: (0, 2), (1, 6), and (2, 18).
We can create a system of equations by plugging in these points:
2 = a(0)² + b(0) + c,
6 = a(1)² + b(1) + c, and
18 = a(2)² + b(2) + c.
Simplifying these equations, we get
c = 2, a + b + c = 6, and 4a + 2b + c = 18.
Solving this system of equations, we get
a = 4, b = -2, and c = 2.
Therefore, the quadratic equation is y = 4x² - 2x + 2.
We can use the formula for exponential growth, which is y = abˣ, where a is the initial value and b is the growth factor. Let's use the first two points on the table: (0, 2) and (1, 6).
The initial value is 2, so the equation is y = 2bˣ.
To find the growth factor, we can divide the y-values: 6/2 = 3 = b¹, so b = 3. Therefore, the exponential equation is y = 2(3ˣ).
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Review the equation used in writing a partial fraction decomposition.
StartFraction negative 15 x + 10 Over (5 x minus 2) squared EndFraction = StartFraction A Over 5 x minus 2 EndFraction + StartFraction B Over (5 x minus 2) squared EndFraction
Which system of equations can be used to determine the values of A and B?
The answer is B. 5A=-15 -2A+B=10
have a lovely day my darlings <3
To determine the values of A and B, we can use the following system of equations: 1. 5A = -15 2. -2A + B = 10 This system of equations can be used to find the values of A and B.
To review the equation used in writing a partial fraction decomposition, we start with a fraction that has a denominator that can be factored into linear or quadratic factors. The partial fraction decomposition separates the fraction into a sum of simpler fractions, each with a single linear or quadratic factor in the denominator.
The equation you provided for partial fraction decomposition is:
StartFraction negative 15 x + 10 Over (5 x minus 2) squared EndFraction = StartFraction A Over 5 x minus 2 EndFraction + StartFraction B Over (5 x minus 2) squared EndFraction
This equation shows that the original fraction can be decomposed into two simpler fractions, one with a linear factor of (5x - 2) in the denominator (A/(5x - 2)), and one with a quadratic factor of (5x - 2)² in the denominator (B/(5x - 2)²).
To determine the values of A and B, we need to solve for them using a system of equations. In this case, we can use the coefficients of x in the numerator of each fraction to create the following system of equations:
5A = -15
-2A + B = 10
We get the first equation by setting the numerator of the first fraction (A/(5x - 2)) equal to -15x + 10, and the second equation by setting the numerator of the second fraction (B/(5x - 2)²) equal to -15x + 10 and subtracting the first equation from it.
Solving this system of equations gives us:
A = -3
B = 5
Therefore, the partial fraction decomposition of the original fraction is:
StartFraction negative 15 x + 10 Over (5 x minus 2) squared EndFraction = StartFraction -3 Over 5 x minus 2 EndFraction + StartFraction 5 Over (5 x minus 2) squared EndFraction
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colleen's photo is 9 inches long and 7 inches wide. is it larger or smaller than ali's photo? explain how you know.
By calculations, Colleen's photo is smaller than Ali's photo
Determining if Colleen's photo larger or smaller than Ali's photo?From the question, we have the following parameters that can be used in our computation:
Area of Ali's photo = 91 square inches.
For Colleen's photo, we have
9 inches by 7 inches
This means that
Area of Colleen's photo = 9 * 7 square inches.
Evaluate
Area of Colleen's photo = 63 square inches.
63 square inches is lesser than 91 square inches
This means that Colleen's photo is smaller than Ali's photo
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Find the unique function f(x) satisfying the following conditions: f" (x) = x2 f(1) 4 f(2) = 1 f(x) =
To find the unique function f(x) satisfying the given conditions, we will use the method of undetermined coefficients.
Assume that f(x) is a polynomial of degree n. Then, f"(x) is a polynomial of degree n-2. Therefore, x^2 f(x) is a polynomial of degree n+2.
Let's first find the second derivative of f(x):
f''(x) = (d^2/dx^2) f(x)
Since we assumed that f(x) is a polynomial of degree n, we can write:
f''(x) = n(n-1) a_n x^(n-2)
where a_n is the leading coefficient of f(x).
Now, let's substitute the given values of f(1) and f(2):
f(1) = a_n
f(2) = a_n 2^n
Therefore, we have two equations:
n(n-1) a_n = x^2 f(x)
a_n = 4
a_n 2^n = 1
Solving for n and a_n, we get:
n = 3/2
a_n = 4/3^(3/2)
Thus, the unique function f(x) that satisfies the given conditions is:
f(x) = (4/3^(3/2)) x^(3/2) - (4/3^(3/2)) x^2 + 1/2
It seems that your question is incomplete or contains some errors. However, based on the information provided, I understand that you are looking for a function f(x) that satisfies given conditions involving its second derivative and specific values of f(1) and f(2).
To assist you properly, please provide the complete and correct version of the question with all the necessary conditions.
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A statistics class weighed 20 bags of grapes purchased from the store. The bags are advertised to contain 16 ounces, on average. The class calculated the 90% confidence interval for the true mean weight of bags of grapes from this store to be (15. 875, 16. 595) ounces. What is the sample mean weight of grapes, and what is the margin of error?
The sample mean weight is 15. 875 ounces, and the margin of error is 16. 595 ounces.
The sample mean weight is 16. 235 ounces, and the margin of error is 0. 360 ounces.
The sample mean weight is 16. 235 ounces, and the margin of error is 0. 720 ounces.
The sample mean weight is 16 ounces, and the margin of error is 0. 720 ounces
0.180 is the sample mean weight of grapes, and what is the margin of error
The sample mean weight is the midpoint of the confidence interval:
sample mean = (lower limit + upper limit) / 2 = (15.875 + 16.595) / 2 = 16.235
Therefore, the sample mean weight of grapes is 16.235 ounces.
The margin of error is half of the width of the confidence interval:
margin of error = (upper limit - sample mean) = (16.595 - 16.235) / 2 = 0.180
Therefore, the margin of error is 0.180 ounces.
So the correct answer is: "The sample mean weight is 16.235 ounces, and the margin of error is 0.180 ounces."
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Solve for x. Round to the nearest tenth of a degree, if necessary.
Answer:
40.7, my answer needs to be 20+ characters sooo....
A baker paid $15. 05 for flour at a store that sells flour for $0. 86 per pound.
How many pounds of flour did the baker buy? :)
The baker bought approximately 17.5 pounds of flour.
Let's use algebra to solve the problem. Let x be the number of pounds of flour that the baker bought. We know that the cost of the flour is $15.05 and the price per pound is $0.86. So we can set up the equation:
$15.05 = $0.86 x
To solve for x, we can divide both sides by $0.86:
x = $15.05 ÷ $0.86
x ≈ 17.5
Therefore, the baker bought approximately 17.5 pounds of flour.
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Mr Mensah starts a job with an
annual salary of € 6400. 00 which increases by
€ 240. 00 every year After working for eight years
Mr Mensah is promoted to a new post with an
annual salary of ¢ 9500. 00 which increases by
€ 360. 00 every year Calculate
i) Mr. Mensah's Salary in the fifteenth year of service
ii) Mensah's total earnings at the end the fifteenth
year of service
Mr. Mensah's total earnings at the end of the fifteenth year of service is €1920.00 + €2520.00 = €4440.00.
To calculate Mr. Mensah's salary in the fifteenth year of service, we need to determine the pattern of salary increase over the years.
We know that Mr. Mensah's salary starts at €6400.00 and increases by €240.00 every year for the first eight years. After that, he is promoted to a new post with an annual salary of €9500.00, which increases by €360.00 every year.
Let's break it down:
For the first eight years, the salary increases by €240.00 per year:
After 1 year: €6400.00 + €240.00 = €6640.00
After 2 years: €6640.00 + €240.00 = €6880.00
...
After 8 years: €6400.00 + (8 * €240.00) = €6400.00 + €1920.00 = €8320.00
From the ninth year onwards, the salary increases by €360.00 per year:
After 9 years: €9500.00 + €360.00 = €9860.00
After 10 years: €9860.00 + €360.00 = €10220.00
...
After 15 years: €9500.00 + (7 * €360.00) = €9500.00 + €2520.00 = €12020.00
Therefore, Mr. Mensah's salary in the fifteenth year of service is €12,020.00.
To calculate Mr. Mensah's total earnings at the end of the fifteenth year of service, we need to sum up his salaries from year 1 to year 15.
For the first eight years, the total earnings can be calculated as follows:
Total earnings = (Salary in year 1 + Salary in year 2 + ... + Salary in year 8) = 8 * €240.00 = €1920.00
From the ninth year onwards, the total earnings can be calculated as follows:
Total earnings = (Salary in year 9 + Salary in year 10 + ... + Salary in year 15) = 7 * €360.00 = €2520.00
Therefore, Mr. Mensah's total earnings at the end of the fifteenth year of service is €1920.00 + €2520.00 = €4440.00.
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The slant height if the cone is 13 cm. What is the volume of a cone having a radius of 5 cm and a slant height of 13 cm.
Thus, the volume of cone for the given slant height and radius is found as: 314 cu. cm.
Explain about the slant height of cone:The distance from a cone's apex to its outer rim is referred to as the segment's slant height. It is corresponding to the hypotenuse's length of a right triangle that creates the cone.
Given data:
slant height of cone l = 13 cm
radius r = 5 cm
Let h be the height
So, using Pythagorean theorem, find height.
l² = h² + r²
h² = l² - r²
h²= 13² - 5²
h² = 169 - 25
h = 12 cm
volume of a cone = 1/3 *π*r²*h
volume of a cone = 1/3 *3.14*5²*12
volume of a cone = 3.14*25*4
volume of a cone = 314 cu. cm
Thus, the volume of cone for the given slant height and radius is found as: 314 cu. cm.
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1. For the solid bounded by the panes 2 = 1 - x and z=1-y in the first octant (which is the same as being bounded by x = 0, y = 0, 2 = 0), one triple integral that describes the volume of the solid is: 1- SL | 1 d:dyds + C5 .** 1 dzdyudar 0 lo z , Z=1-4 ។ Z=1- х Find three other orders of integration that describe this solid. You need not find the volume. 2. Compute by switching the order of integration: dyd.x 3. Write the following integral in polar coordinates, then solve. arctan ( dyda ", 1.
1. For the solid bounded by the panes 2 = 1 - x and z=1-y in the first octant, one triple integral that describes the volume of the solid. The region is bounded by the x-axis and the curve y = √(2x-x^2), which is the top half of a circle centered at (1,0) with radius 1.
One possible order of integration is:
∫0^1 ∫0^(1-x) ∫0^(1-y) dzdydx
This means we integrate over z first, then y, then x. Another order of integration could be:
∫0^1 ∫0^x ∫0^(1-x-y) dzdydx
Here we integrate over z first, then x, then y.
Another possible order of integration is:
∫0^1 ∫0^1-x ∫0^1-y dzdxdy
Here we integrate over z first, then x, then y. This order of integration can also be rewritten in polar coordinates as:
∫0^(π/4) ∫0^(secθ-1) ∫0^(cscθ-1) r dzdrdθ
2. Compute by switching the order of integration:
∫0^2 ∫0^√(2x-x^2) dydx
First, let's sketch the region of integration. The region is bounded by the x-axis and the curve y = √(2x-x^2), which is the top half of a circle centered at (1,0) with radius 1.
We can switch the order of integration to integrate over x first, then y:
∫0^1 ∫0^(2-2y^2) dxdy
To find the limits of integration for x, we set y = √(2x-x^2) and solve for x:
y^2 = 2x - x^2
x^2 - 2x + y^2 = 0
(x-1)^2 = 1 - y^2
x = 1 ± √(1-y^2)
Since the curve is the top half of the circle, we take the positive square root:
x = 1 + √(1-y^2)
So the limits of integration for x are 0 to 2-2y^2. Integrating with respect to x first gives:
∫0^1 ∫0^(2-2y^2) dxdy = ∫0^1 (2-2y^2)dy = 4/3
3. Write the following integral in polar coordinates, then solve:
arctan (dy/dx)
We can write dy/dx in terms of polar coordinates using the chain rule:
dy/dx = (dy/dr)(dr/dθ)(1/dx/dθ)
Using the relationships x = rcosθ and y = rsinθ, we have:
dx/dθ = -rsinθ
dy/dθ = rcosθ, So
dy/dx = (dy/dr)(dr/dθ)(1/dx/dθ) = (cosθ)/(sinθ) = cotθ
Therefore, the integral becomes:
∫arctan(cotθ) dθ
To solve this integral, we use the identity arctan(x) + arctan(1/x) = π/2 for x > 0:
arctan(cotθ) = π/2 - arctan(tanθ)
So the integral becomes:
∫(π/2 - arctan(tanθ)) dθ
Integrating, we get:
(π/2)θ - ln|cosθ| + C
Where C is the constant of integration.
1. To find three other orders of integration for the solid bounded by the planes z = 1 - x, z = 1 - y, x = 0, y = 0, and z = 0 in the first octant, we can rearrange the given triple integral, which is given as:
∫∫∫_D dz dy dx
Now, we can find three other orders of integration:
a) ∫∫∫_D dx dz dy
b) ∫∫∫_D dy dx dz
c) ∫∫∫_D dy dz dx
2. To compute the volume of the solid by switching the order of integration, we can rewrite the given integral ∫∫ dy dx as: ∫∫ dx dy
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If f(9) = 9, f'(9) = 4, limit x→9√(f(x))-3/√(x)-3 =
A. 1
B. 1/4
C. 1/2
D. -1/2
The answer is A. 1. We can use L'Hopital's rule to evaluate the limit:
limit x→9√(f(x))-3/√(x)-3 = limit x→9 (f(x)-9)/(x-9) / (√(f(x))-3)/(√(x)-3)
Now, we know that f(9) = 9 and f'(9) = 4, so we can use the definition of the derivative to write:
f(x) - f(9) = f'(9)(x-9) + o(x-9)
where o(x-9) represents a term that goes to 0 faster than x-9 as x approaches 9. Plugging this into the numerator, we get:
f(x) - 9 = 4(x-9) + o(x-9)
Plugging this into the denominator, we get:
√(f(x)) - 3 = √(4(x-9) + o(x-9)) = 2√(x-9) + o(1)
√(x) - 3 = √(x-9) + o(1)
Therefore, the limit becomes:
limit x→9 (4(x-9) + o(x-9))/(√(x-9) + o(1)) / (2√(x-9) + o(1))/(√(x-9) + o(1))
Simplifying this expression, we get:
limit x→9 2(4(x-9) + o(x-9))/(√(x-9) + o(1))^2
limit x→9 8 + 2o(1)/(x-9)
As x approaches 9, the o(1) term goes to 0, so the limit becomes:
8 + 2*0/0 = 8
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20. MP MODELING REAL LIFE The dot plot shows the lengths of earthworms.
.:
:
15 16 17 18 19 20 21 22 23 24 25 26 27 28
Length
a. Find and interpret the number of data values on the dot plot.
b. How can you collect these data? What are the units?
c. Write a statistical question that you can answer using the
dot plot. Then answer the question. PLS HELP
On the day their son peter was born, madeline and ben invested $1500 for his education at 6.7% interest, compounded quarterly. today it’s peters birthday. he is 19 years old and wants to go to college
Based on the information provided, Madeline and Ben invested $1500 for their son Peter's education on the day he was born at an interest rate of 6.7% compounded quarterly. Since Peter is now 19 years old and wants to go to college, we can calculate the current value of his education fund.
To do this, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = the final amount
P = the principal (initial investment)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the time in years
In this case, we have:
P = $1500
r = 6.7% = 0.067 (as a decimal)
n = 4 (since the interest is compounded quarterly)
t = 19 (since Peter is now 19 years old)
So, the current value of Peter's education fund is:
A = $1500(1 + 0.067/4)^(4*19)
A = $1500(1.01675)^76
A = $1500(2.4826)
A = $3,723.90
Therefore, the current value of Peter's education fund is $3,723.90. This should help Madeline and Ben determine how much more they need to save for Peter's college expenses.
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if 4y= 2.6,find the value of 20y + 3
Answer:
16
Step-by-step explanation:
4y = 2.6
y = 0.65
20y + 3
= 20 × 0.65 + 3
= 13 + 3
= 16
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For y = 126 sqrt(x), find dy, given x = 9 and Δx = dx = 0.17.
For the given function y = 126 \sqrt(x), dy is 3.57 if x = 9 and Δx = dx = 0.17.
To find the change in y (or dy), we need to use the formula:
dy = f'(x) * dx
where f'(x) is the derivative of y with respect to x.
The given function is y = 126 \sqrt(x).
To find the derivative, we can use the power rule and chain rule of differentiation.
y = 126x^{1/2}
Taking the derivative of y with respect to x:
dy/dx = 1/2 * 126x^(-1/2)
Simplifying, we get:
dy/dx = 63/(\sqrt(x))
Now, we can substitute x = 9 into this expression to get the value of the derivative at that point:
dy/dx = 63/(\sqrt(9)) = 63/3 = 21
Next, we can use the given value of dx, which is 0.17, to find the change in y or dy.
dy = f'(x) * dx ≈ 21 * 0.17 ≈ 3.57
Therefore, the change in y or dy is approximately 3.57.
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To find the quotient of 4. 082 and 10,000, move the decimal point 4. 082_places to the_
The quotient of the given division is 0.4082, under the condition that dividend is 4.082 and divisor is 10,000.
The count of zeros in 10,000 is 4, then we have to transfer the decimal point four places to the left to divide by 10,000. Here, we have to relie on the basic principles involved in division.
Then, in order to find the quotient of 4.082 and 10,000, we have to divide 4.082 by 10,000. To perform this, we expand the number by moving the decimal point forward of 4.082.
That is,
[tex] \frac{4.082 }{10000} [/tex]
= 0.4082
The quotient is 0.4082
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Which recursive formula defines the sequence of f(1)=6, f(4)=12, f(7)=18
The recursive formula for this sequence is f(n) = f(n-3) + 6n - 18.
How did get the formula?We can use the method of finite differences to find a possible recursive formula for this sequence.
First, let's compute the first few differences:
f(4) - f(1) = 6
f(7) - f(4) = 6
Since the second differences are zero, we can assume that the sequence is a quadratic sequence. Let's write it in the form f(n) = an^2 + bn + c. We can solve for the coefficients using the given values:
f(1) = a(1)^2 + b(1) + c = 6
f(4) = a(4)^2 + b(4) + c = 12
f(7) = a(7)^2 + b(7) + c = 18
Solving for a, b, and c, we get:
a = 1
b = 5
c = 0
Therefore, the recursive formula for this sequence is f(n) = f(n-3) + 6n - 18.
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I need help with this problem.
Please and thank you.
Answer:
Step-by-step explanation:
Find the volume of this cone.
Round to the nearest tenth.
7in
4in
The volume of the cone is 117.3 (Round to the nearest tenth).
To find the volume of this cone with a height of 7 inches and a radius of 4 inches, and round to the nearest tenth, follow these steps:
1. Use the formula for the volume of a cone: V = (1/3)πr²h, where V is the volume, r is the radius, and h is the height.
2. Plug in the given values: V = (1/3)π(4²)(7)
3. Calculate the volume: V = (1/3)π(16)(7) = (1/3)(112π)
4. Multiply and round to the nearest tenth: V ≈ 117.3 cubic inches
So, the volume of this cone is approximately 117.3 cubic inches.
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