Find the domain of the function

Answer:

The phrase “ y varies directly as x” or “ y is directly proportional to x” means that as x gets bigger, so does y, and as x gets smaller, so does y. That concept can be translated in two ways. for some constant k. The k is called the constant of proportionality. Therefore a chance of probability is a binary table.

Step-by-step explanation:

Answer:

The formula is: y = y•e^(-k•x)

In this specific case the function is: 512•e^(-x/1.44)

The number of players in the round 7 is 4

Answer:

12

Step-by-step explanation:

1.5 is 1 1/2 in decimal form

1.5×8=12

The average time taken to travel to Toronto by  the swarm of Rasberry Crazy Ants  is 12,947 Years

To arrive at the solution above, we need to look at the information given and the information assumed.

Step 1 - Information given:

Step 2 - Information assumed:

The swarm are travelling to the location of the student which is assumed to be Toronto.

Hence,

Time taken for the swam to get to Toronto (TTS) =

Distance between Austin, Texas and Toronto (DBTT) / Average distance covered per day by the Rasberry Ants. (ADC)

Estimated distance between Austin Texas and Toronto = 2592.6 Kilometers

Time travelled per day by the ants (In Km) = 0.00054864

Thus,

TTS  = DBTT/ADC

= 2592.6 /0.00054864

≈ 4,725,503.06 days or

≈ 12,947 Years

The answer to both questions is NO.

The average life expectancy in Toronto (as at 2022) is 80 years. Assuming I was born today, it is expected that the time between now and when my last grand child will die is about:

80 x 3 = 240 years.

Given that the ants have to travel 12,947  to get to Toronto, the possibility of my grand children seeing them is zero.

Besides, even if they by chance got to Toronto and infested my grandchildren's residence, they would have nothing to worry about because Rasberry Crazy Ants are 100% harmless.

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The length of the side c, to the nearest integer is 12.

Cosine law is a formula relating the length of the sides of a triangle to the cosine of one angle of the triangle.

u² = s² + t² - 2(s)(t)·cos U

In ΔABC, m < C = 50* , a = 14 and b = 15.

We can solve for the length of side a to the nearest whole number using the Laws of Cosines

c² = b² + a²- 2ba CosC

Solving for the value of a, we have:

c² = 15² + 14²- 2(15)(14)cos50°

c² = 225 + 196 - 269.97

c² = 151.029

c = 12.28

Hence, The length of the side c, to the nearest integer is 12.

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Answer:

Define different tipes of discontuinity of a function .also,write the condition for increasing, decreasing and concave of function

Answer:

1650 Cubic Centimeters

Step-by-step explanation:

To get the volume of the cereal boxes, you must multiply their 3 dimensions together.

Box A:

25×20=500

500×9=4500

Box B:

25×19=475

475×6=2850

Now, to find the difference of these volumes, you want to subtract the smaller volume from the larger volume.

4500-2850=1650

The answer is 1650 cubic centimeters.

Answer:

Step-by-step explanation:

The domain is the set of x-values and the range is the set of y-values.

The attached diagram represents the Venn diagram of the sets

The sets are given as:

From the above representation, we have the following highlights:

Using the above highlights, we can now draw the Venn diagram

See attachment for the Venn diagram

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\texttt{Yes, there's a local maximum at -9,} [/tex] [tex] \texttt{and it is 9} [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

By Observing the graph, we can easily conclude that there's a local maxima at -9

[tex] \textsf{And f(-9) = 9} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The quotient is -27m/ 55.

Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols.

Given:

(9mn²)(−3m*6n)÷33m*10n³

=9mn² *(-18mn) / 330mn³

= -162m²n³/ 330mn³

= -27m/ 55

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Answer:

9.1

Step-by-step explanation:

3(9.1)=27.3

27.3÷3=×

×=9.1

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: [ - 10,- 8] \cup[ - 2,0] \cup[2,5][/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

The intervals in which a function is decreasing has a negative slope. and for given graph, the required intervals are :

[tex]\qquad \tt \rightarrow \: [ - 10,- 8] \cup[ - 2,0] \cup[2,5][/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Considering that the mean of the normal distribution is the same as the median, the median is of 88%.

It states that, for a normally distributed random variable:

For the normal distribution, the median is the same of the mean, that is, the median is of 88%.

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Answer

(0,3)

Step-by-step explanation:

Answer:

leaning at 3 degrees off of normal (to the nearest whole degree)

Step-by-step explanation:

To visualize, let's assume the tower is leaning to the right, (as viewed by us).

If the rope is dropped from the top to the ground, the tower, the rope and the ground (between the rope and the tower) form a right triangle.

The height and base of the triangle are given

Often we're looking for the angle near the ground, but here, we're looking for the angle between the rope and the tower because the angle is congruent to the angle that the tower forms with it's original vertical position (alternate interior angles).  If the tower was standing straight up and hadn't been leaning at all, we wouldn't say that the tower was leaning 90°... we would say it was leaning 0°.  Whereas if the tower fell over and was laying flat on the ground, we would say it was leaning at 90°.  So, we're not measuring the angle between the tower and the ground, but rather the angle between the tower where it should be, and where it is... which is the same angle as the rope forms with the tower.

Recall that [tex]tan(\theta)=\dfrac {opp}{hyp}[/tex]

Since we know the two legs of the right triangle, one can setup a tangent relationship with the two legs, but remember that the "opposite" side is going to be the ground, and the "adjacent side" will be the rope.

[tex]tan(\theta)=\dfrac {ground}{rope}\\tan(\theta)=\dfrac {3ft}{57ft}\\tan(\theta)=\frac {3}{57}\\\theta=tan^{-1}(\frac {3}{57})\\\theta=3.012787504^o\\\theta \approx 3^o\\[/tex]

[tex]\dfrac{x!-(x-3)!}{23}=1\\x!-(x-3)!=23\\(x-3)!((x-2)(x-1)x-1)=23\\(x-3)!((x^3-x^2-2x^2+2x)-1)=23\\(x-3)!((x^3-3x^2+2x)-1)=23[/tex]

23 is a prime number, therefore there are two possibilities:

[tex]\text{I.}\, (x-3)!=1 \wedge x^3-3x^2+2x-1=23[/tex]

or

[tex]\text{II.}\, (x-3)!=23 \wedge x^3-3x^2+2x-1=1[/tex]

[tex]\text{I.}\\(x-3)!=1\\x-3=0 \vee x-3=1\\x=3 \vee x=4[/tex]

Now, we check if any of these solutions is also a solution to the second equation:

[tex]3^3-3\cdot3^2+2\cdot3-1=23\\27-27+6-1-23=0\\ -18=0[/tex]

Therefore, 3 is not a solution.

[tex]4^3-3\cdot4^2+2\cdot4-1=23\\64-48+8-1-23=0\\0=0[/tex]

Therefore, 4 is a solution.

[tex]\text{II.}[/tex]

[tex](x-3)!=23[/tex]

We know that [tex]3!=6[/tex] and [tex]4!=24[/tex], therefore there isn't any [tex]n\in\mathbb{N}[/tex], for which [tex]n!=23[/tex], so there's no solution.

So, the only solution is [tex]x=4[/tex].

Inequalities help us to compare two unequal expressions. The inverse of p>q is p<q.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

Given the inequality that p is greater than q, therefore, the inverse of it will be p smaller than q. Thus, The inverse of p>q is p<q.

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The scenario can be described using a piecewise function like:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Remember that the limit only exists if the limit from left and the limit from the right give the same value.

Then, we can just define a piecewise function of the form:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Clearly, this is not a continuous function.

Notice that:

[tex]f(c) = c.\\\\ \lim_{x \to c^{-}} f(x) = 1/c\\\\ \lim_{x \to c^{+}} f(x) = 1/(c + 73)[/tex]

So the limits from left and right are different, then:

[tex]\lim_{x \to c^{}} f(x)[/tex]

Does not exist.

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Answer:

(x^2+5x)

Step-by-step explanation:

Answer:

The Equation of the line is y = [tex]\frac{-1}{3}[/tex]x + [tex]\frac{11}{3}[/tex]

Step-by-step explanation:

Multiplication of slope of two perpendicular lines is = -1

first line is  y= [tex]\frac{1}{3}[/tex]x +6

slope of this line is [tex]\frac{1}{3}[/tex]

So the slope of the second line is : [tex]\frac{-1}{3}[/tex]

Equation of line would be written by using :

(y - y1) = m(x - x1)

here the line passing through (-4,5)

put the values in equation

y -5 =[tex]\frac{-1}{3}[/tex][x - (-4)]

3y - 15 = -x -4

3y = -x +11

y = [tex]\frac{-1}{3}[/tex]x + [tex]\frac{11}{3}[/tex]

So The Equation of the line is y = [tex]\frac{-1}{3}[/tex]x + [tex]\frac{11}{3}[/tex]

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The adjusted cash Balance is $8060 .

The amount of money in a person's account at any given time is the Bank Balance of that person's account.

Unadjusted bank balance       6000

Difference in the electricity bill    -180

Add: Deposit in transit               2510

Less: Outstanding Checks         -270

Adjusted cash balance                8060

So answer is a) $8060

Therefore the adjusted cash Balance is $8060 .

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Answer:

1/2(6-8), 1/2(-3+7)=-1,2

Answer: C - (-1, 2)

Step-by-step explanation:

Answer:

D -6, 15

Step-by-step explanation:

Because 3,11 is the middle, and 12,7 is the other end, you can do

12 - 3 = 9

3 - 9 = 6

then

11 - 7 = 4

11 + 4 = 15

so

6 is you x and 15 is your y

El costo en la opción uno es menor que el de la opción dos, asi que la primera es la más conveniente.

En la primera opción, el par de zapatos cuesta $90, y el segundo par tiene un descuento del 25%.

Entonces el costo por 2 pares es:

C = ($90 + $90)*(1 - 25%/100%)

Donde le aplicamos un descuento del 25% al total del costo de los dos zapatos, resolviendo esto obtenemos:

C = ($180)*(0.75) = $135.

En la segunda opcion tenemos que los pares cuestan $90, pero esta vez le aplicamos un descuento del 40% al segundo par.

C = $90 + $90*(1 - 40%/100%) =

C = $90 + $90*(0.6) = $144

Así, vemos que en la primera opción el costo es menor, entonces esa es la mejor opción.

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[tex]\triangleright[/tex]Hii! [tex]\triangleleft[/tex]

     _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _

[tex]\stackrel\star{\rightsquigarrow\circ\boldsymbol{\underbrace{Answer}}}\circ\leftharpoonup[/tex] Equation: [tex]\bullet[/tex] y=43x-3 ✅

[tex]\stackrel\star{\rightsquigarrow\circ\boldsymbol{\underbrace{Explanation}}}\circ\leftharpoonup[/tex]

Do you need to know the equation of the line with a slope of -43 and a y-intercept of (0,-3)? No problem! Luckily, there's a formula to find it! (:

The slope intercept formula, [tex]\boldsymbol{y=mx+c}[/tex], comes in handy when we need to find the equation of a line!

In this formula,

--                                         ↩

This particular question provides us both "m" and "c."

Stickin the values

[tex]\boldsymbol{y=43x+(-3)}[/tex]

Simplify!

[tex]\boldsymbol{y=43x-3}[/tex]

--

Hope that this helped! Best wishes.

[tex]\textsl{Reach far. Aim high. \: Dream big. }[/tex]

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The area of the sector, to 4 decimal places, is: 78.6794 cm².

Area of sector = ∅/360 × πr².

Given the following:

Area of sector = 46/360 × π(14²)

Area of sector ≈ 78.6794 cm²

The area of the sector is approximately 78.6794 cm².

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Answer:

50 – (3x + 4y + 25)

Step-by-step explanation:

To see how much change she is gonna receive we need to find how much she spent on the items and add them all up:

The calculator was $25

The price of pens and notebooks are unknown so they are represented with x and y respectively.

With given information we can write the following equation to see the change she will receive:

50 – (3x + 4y + 25)