Find an Equation of a line with the given slope that passes through the point. Write the equation in the form Ax + By=C
M=3/2, (7,-2) -problem
Bridge math sails
Module 4B2

Answer:

Option (2). x = 20°

Step-by-step explanation:

In the figure attached,

ΔABC is an equilateral triangle.

By the property of equilateral triangle, all sides of the triangle are equal and measure of all angles of the triangle is 60°.

By this property,

m∠B = 60°

and y = 46 - 16 = 30

By applying Sine rule in ΔBCD,

[tex]\frac{\text{sin}60}{BD}=\frac{\text{sin}80}{46}=\frac{\text{sin}(\angle CBD)}{DC}[/tex]

[tex]\frac{\text{sin}80}{46}=\frac{\text{sin}(\angle CBD)}{y}[/tex]

sin(∠CBD) = [tex]\frac{30\times \text{sin}80}{46}[/tex]

                 = 0.6423

m∠CBD = 39.96

              ≈ 40°

m∠ABD = 60° - 40°

             = 20°

Therefore, Option (2). 20° will be the answer.

Answer:

(1)0.0138

(2)A. If the depth of the dive is increased by one meter, it adds 0.0138 minutes to the time spent under water.

Nos 3-12: See Explanation

Step-by-step explanation:

Given the regression equation for the relation of dive duration (DD) to depth (D).

[tex]DD = 2.69 + 0.0138D\\$Where: Duration DD is measured in minutes\\epth D is in meters.[/tex]

(1)The slope of the regression lie =0.0138

(2)

When D=1, DD = 2.69 + 0.0138(1)=2.7038

When D=2, DD = 2.69 + 0.0138(2)=2.7176

2.7176-2.7038=0.0138

Therefore, If the depth of the dive is increased by one meter, it adds 0.0138 minutes to the time spent under water.

(3) When depth, D =200 meters

DD = 2.69 + 0.0138(200)=5.45 Minutes

(4) When depth, D =210 meters

DD = 2.69 + 0.0138(210)=5.588 Minutes

(5) When depth, D =220 meters

DD = 2.69 + 0.0138(220)=5.726 Minutes

(6) When depth, D =230 meters

DD = 2.69 + 0.0138(230)=5.864 Minutes

(7) When depth, D =240 meters

DD = 2.69 + 0.0138(240)=6.002 Minutes

(8) When depth, D =150 meters

DD = 2.69 + 0.0138(150)=4.76 Minutes

(9) When depth, D =160 meters

DD = 2.69 + 0.0138(160)=4.898 Minutes

(10) When depth, D =170 meters

DD = 2.69 + 0.0138(170)=5.036 Minutes

(11) When depth, D =180 meters

DD = 2.69 + 0.0138(180)=5.174 Minutes

(12) When depth, D =190 meters

DD = 2.69 + 0.0138(190)=5.312 Minutes

A regression line is only a single line that fits the data the best. It tells how steep it is, whereas the intercept reveals where it intersects an axis.

For question 1):

By calculating the slope of the regression line we get the slope value that is [tex]= 0.0138[/tex]

For question 2):

Describe whatever this slope means about this penguin's dives in precise terms.

The time spent under liquid increases by 0.0138 minutes whenever the diving depth is raised by one meter, which is equal to "Option A".

For question 3):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times200 = 2.69+2.76 = 5.45\ minutes[/tex]

For question 4):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times210 = 2.69 + 2.898 = 5.588\ minutes[/tex]

For question 5):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times 220 = 2.69 + 3.036 = 5.726\ minutes[/tex]

For question 6):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times230 = 2.69 + 3.174 = 5.864 \ minutes[/tex]

For question 7):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times240 = 2.69 + 3.312 = 6.002\ minutes[/tex]

For question 8):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times 150 = 2.69 + 2.07 = 4.76\ minutes[/tex]

For question 9):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times 160 = 2.69 + 2.208 = 4.898\ minutes[/tex]

For question 10):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times 170 = 2.69 + 2.346 = 5.036\ minutes[/tex]

For question 11):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times 180 = 2.69 + 2.484 = 5.174 \ minutes[/tex]

For question 12):

Calculated equation:

[tex]\to DD = 2.69 + 0.0138\times 190 = 2.69 + 2.622 = 5.312\ minutes[/tex]

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Answer: i did the question i told you the steps

Step-by-step explanation:

From the starting point move three to the left. Then move four down. Then move three times to the left. Lastly move two down.

Answer:

5 units

Step-by-step explanation:

P=2(w)+2(2w-1)

28=2w+4w-2

30=6w

w=5

Answer:

5

Step-by-step explanation:

Answer:

6 PM

Step-by-step explanation:

125 mg --- 300 mL

500 mg --- x mL

x = 500*300/125 = 1200 mL solution contains 500 mg

rate = 100 mL/h

1200 mL* 1h/100 mL = 12 h

6AM + 12 h = 6 PM

You need to stop infusion  at 6 PM

It is found that You need to stop infusion at 6 PM.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Given that Liquid suspension contains 125 MG of medication aide for every 300 ML solution this is Spenton is being infused into a patient at the rate of 100 ML per hour if the infusion started at 6 AM and the patient needs 500 MG of the medication.

125 mg = 300 mL

500 mg = x mL

x = 500*300/125

x = 1200 mL

Here solution contains 500 mg

The rate = 100 mL/h

1200 mL* 1h/100 mL = 12 h

6AM + 12 h = 6 PM

Therefore, You need to stop infusion at 6 PM.

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Complete Question

The complete question is shown on the first  and second uploaded image

Answer:

a

  [tex]\= HK = \= t + \= u[/tex]

b

  [tex]\= GL = \= s - \= t[/tex]

c

[tex]\= JH = \= u + \= s[/tex]

Step-by-step explanation:

Now looking at the diagram

Following the direction of the unit vectors [tex]\= u , \= s, \= t[/tex]

     [tex]\= {HK} = \= {KI} + \= KL[/tex]

=>   [tex]\= HK = \= t + \= u[/tex]

And  

    [tex]\= GL = \= GH + \= GF[/tex]  jjj

=>   [tex]\= GL = \= s - \= t[/tex]

Also

    [tex]\= JH = \= JG + \= JI[/tex]

=>  [tex]\= JH = \= u + \= s[/tex]

Answer:

[tex]9\dfrac{5}{6}[/tex]

Step-by-step explanation:

[tex]5\dfrac{1}{6}+4\dfrac{2}{3}=\\\\5\dfrac{1}{6}+4\dfrac{4}{6}=\\\\9\dfrac{5}{6}[/tex]

Hope this helps!

Answer: About 6.2%

Step-by-step explanation:

He starts with 5500 and gains 893.75 in 2.5 years.

The equation is then 5500*(x)^2.5 = 5500+893.75, or

5500*x^2.5 = 6393.75.

x is about 1.0621, or about 6.2% because it's interest.

Hope that helped,

-sirswagger21

Answer: 137.5%

Step-by-step explanation

Answer:

20.75

Step-by-step explanation:

Answer:

C. -20.75

Step-by-step explanation:

If the length of OB was ³/₄, then the length of OB' after dilation is; Option B: 3 units.

What this means is that it was enlarged by a scale factor of 4 with point O as the center of dilation.

Scale factor = new dilated length OB'/(³/₄)

new dilated length OB' = ³/₄ × 4

new dilated length OB' = 3 units

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Answer:

its 4 units trust just answered it

Step-by-step explanation:

Answer:

If a person is randomly selected from this group, the probability that they have both high blood pressure and high cholesterol is P=0.25.

Step-by-step explanation:

We can calculate the number of people from the sample that has both high blood pressure (HBP) and high cholesterol (HC) using this identity:

[tex]N(\text{HBP or HC})=N(\text{HBP})+N(\text{HC})-N(\text{HBP and HC})\\\\\\ N(\text{HBP and HC})=N(\text{HBP})+N(\text{HC})-N(\text{HBP or HC})\\\\\\ N(\text{HBP and HC})=15+25-30=10[/tex]

We can calculate the probability that a random person has both high blood pressure and high cholesterol as:

[tex]P(\text{HBP and HC})=\dfrac{10}{40}=0.25[/tex]

Answer:

so the axis of symmetry is x=4

Answer: X = 4

Explanation: Hope it helps you♡

Answer:

D.

Step-by-step explanation:

It's a right triangle so

[tex]x^2=40^2+9^2[/tex]

x = 41

9514 1404 393

Answer:

  £2272.54

Step-by-step explanation:

An equation for the value is ...

  v = £2300(0.998^t)

Then for t=6, the value is ...

  v = £2272.54

_____

Additional comment

The growth factor (0.998) is (1 - decay rate) = (1 -0.002).

Answer:

the answer is 2272.54

Step-by-step explanation:

:))

Answer:

2.964

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

The base of a log is also the base of an exponent. So 7 to the c power, our 7 would be the base. To find c, we simply just do log base 7 of 49, which comes out to be 2.

Answer:

-5.7° C

Step-by-step explanation:

-2.7 °C (degrees Celsius) - 3 °C (degrees Celsius) = -5.7° C

Answer:

There will be 66 bacteria in 8 hours.

Step-by-step explanation:

The number of bacteria after t hours is given by the following formula.

[tex]P(t) = P(0)(1-r)^{t}[/tex]

In which P(0) is the initual number of bacteria and r is the decay rate.

Researchers recorded that a certain bacteria population declined from 750,000 to 250 in 48 hours after the administration of medication.

This means that [tex]P(0) = 750000, P(48) = 250[/tex]

We use this to find r. So

[tex]P(t) = P(0)(1-r)^{t}[/tex]

[tex]250 = 750000(1-r)^{48}[/tex]

[tex](1-r)^{48} = \frac{250}{750000}[/tex]

[tex]\sqrt[48]{(1-r)^{48}} = \sqrt[48]{\frac{250}{750000}}[/tex]

[tex]1-r = 0.84637[/tex]

So

[tex]P(t) = 750000(0.84637)^{t}[/tex]

How many bacteria will there be in 8 hours?

8 hours from now, in this context, is 8 + 48 = 56 hours. So this is P(56).

[tex]P(56) = 750000(0.84637)^{56} = 65.83[/tex]

Rounding to the nearest number

There will be 66 bacteria in 8 hours.

Answer:

197,488

Step-by-step explanation:

This problem requires two main steps. First, we must find the unknown rate, k. Then, we use that value of k to help us find the unknown number of bacteria.

Identify the variables in the formula.

AA0ktA=250=750,000=?=48hours=A0ekt

Substitute the values in the formula.

250=750,000ek⋅48

Solve for k. Divide each side by 750,000.

13,000=e48k

Take the natural log of each side.

ln13,000=lne48k

Use the power property.

ln13,000=48klne

Simplify.

ln13,000=48k

Divide each side by 48.

ln13,00048=k

Approximate the answer.

k≈−0.167

We use this rate of growth to predict the number of bacteria there will be in 8 hours.

AA0ktA=?=750,000=ln13,00048=8hours=A0ekt

Substitute in the values.

A=750,000eln13,00048⋅8

Evaluate.

A≈197,488.16

At this rate of decay, researchers can expect 197,488 bacteria.

Answer:

x=-3

Step-by-step explanation:

The vertex is at x = -3

The axis of symmetry is along the vertex

x=-3

Answer:

x=-3

Step-by-step explanation:

To find the axis of symmetry, you just need to find the x-coordinate of the vertex using this formula: -b/2a=x  

*Only when provided a three variable quadratic equation.

For looking at a graph, you find the center of the parabola in which when you reflect it over itself, it will be symmetrical.

According to the graph, x=-3 is the line which you can draw to fold over to the other side and it can fit perfectly.

Based on the information given, these are the conclusions we can draw from the 95% confidence interval.

Here, we have,

From the provided 95% confidence interval, we can make the following conclusions:

The point estimate of the difference between the mean student loans for females and males is 516.74334 dollars.

The standard error of the difference between the means is 368.41116 dollars.

The degrees of freedom (DF) associated with the confidence interval is 907.34739.

The lower limit of the confidence interval is -206.29374 dollars.

The upper limit of the confidence interval is 1239.7804 dollars.

The confidence interval does not contain zero.

Since zero is not within the interval, we can conclude that the difference between the mean student loans for females and males is statistically significant at the 95% confidence level.

Based on the information given, these are the conclusions we can draw from the 95% confidence interval.

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The estimated difference in the mean student loans between females and males is 516.74334.

There is a 95% confidence that the true difference in means falls within the range of -206.29374 to 1239.7804.

Based on the 95% confidence interval provided for the difference in means between the loans of female and male StatCrunchU students, we can draw the following conclusions:

The sample difference in means is 516.74334.

The standard error of the difference is 368.41116.

The degrees of freedom (DF) for the analysis is 907.34739.

The lower limit of the confidence interval is -206.29374.

The upper limit of the confidence interval is 1239.7804.

Therefore, we can conclude the following:

The estimated difference in the mean student loans between females and males is 516.74334.

There is a 95% confidence that the true difference in means falls within the range of -206.29374 to 1239.7804.

Note: Since the confidence interval includes both positive and negative values, we cannot conclude with certainty whether there is a significant difference or not in the mean student loans between females and males. The confidence interval suggests that the difference could be positive, negative, or even zero.

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Answer:

[tex]x^{6} y^{3}[/tex]

Step-by-step explanation:

[tex](x^2y)3[/tex]

[tex]x^{2 \times 3} \times y^3[/tex]

[tex]x^{6} \times y^3[/tex]

Answer:

A paired sample t-test

Step-by-step explanation:

A paired sample t-test is most of the time used when in determining the difference between two related dependent variables and in this context; we have

approval ratings before the senator's decision variables and

approval rating after the senator's decision variables for the same subject

These revolves around the senator's decision causing a decrease in approval ratings. Often the two variables are separated by time.

It is used to determine whether the mean of the dependent variable (approval ratings) is the same in the two related groups (the before and after decision groups).

Answer:

The price p could be any of $8 or $15 .

Step-by-step explanation:

The equation is a relationship between the numbers of pencil sharpener x can sell each week and the price of each sharpener p.

x = 2300 - 100p

xp = 12000

therefore,

x = 12000/p

insert the value of x in the equation

x = 2300 - 100p

12000/p = 2300 - 100p

12000/p + 100p - 2300 = 0

multiply through by p

12000 + 100p² - 2300p = 0

100p² - 2300p + 12000 = 0

divide through by 100

p² - 23 + 120 = 0

Find the number that we can multiply to give 120 and add to give - 23. The number are -15 and - 8.

p² - 8p - 15p + 120 = 0

p(p - 8) - 15(p - 8) = 0

(p - 8)(p - 15)

p = 8 or 15

x = 2300 - 100p

x = 2300 - 100(8)

x = 2300 - 800

x = 1500  pencil sharpener sold

or

x = 2300 - 100(15)

x = 2300 - 1500

x = 800 pencil sharpener sold

The price could be any of $8 or $15 .

Answer:=

1 7/18

Step-by-step explanation:

Turn the improper fraction into a mixed fraction.

Answer:

See attachment

Step-by-step explanation:

The solution is given in the image.

The graph of a feature f is the set of all factors in the plane of the form (x, f(x)). We can also outline the graph of f to be the graph of the equation y = f(x). So, the graph of a feature is a special case of the graph of an equation.

An axis is a line to the aspect or backside of a graph; it's far labeled to give an explanation for the graph's meaning and the devices of measurement. The x-axis, the horizontal line at the lowest of a graph, may be labeled to present facts about what the graph represents.

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Answer:

1. Diverges

2. Converges

3. Diverges

Step-by-step explanation:

Solution:-

Limit comparison test:

- Given, ∑[tex]a_n[/tex] and suppose ∑[tex]b_n[/tex] such that both series are positive for all values of ( n ). Then the following three conditions are applicable for the limit:

                          Lim ( n-> ∞ )   [tex][ \frac{a_n}{b_n} ][/tex]  = c

Where,

1) If c is finite: 0 < c < 1, then both series ∑[tex]a_n[/tex] and ∑[tex]b_n[/tex] either converges or diverges.

2) If c = 0, then ∑[tex]a_n[/tex] converges only if ∑[tex]b_n[/tex] converges.

3) If c = ∞ or undefined, then ∑[tex]a_n[/tex] diverges only if ∑[tex]b_n[/tex] diverges.

a) The given series ∑[tex]a_n[/tex] is:

                   (n = 1) ∑^∞  [tex][ \frac{n^2+1}{2n^3-1} ][/tex]

- We will make an educated guess on the comparative series  ∑[tex]b_n[/tex] by the following procedure.

                  (n = 1) ∑^∞   [tex][ \frac{n^2( 1 + \frac{1}{n^2} )}{n^3 ( 2 - \frac{1}{n^2} ) } ] = [ \frac{( 1 + \frac{1}{n^2} )}{n( 2 - \frac{1}{n^2} ) } ][/tex]

- Apply the limit ( n - > ∞ ):

                 (n = 1) ∑^∞  [tex][ \frac{1}{2n}][/tex]    .... The comparative series ( ∑[tex]b_n[/tex] )

- Both series  ∑[tex]a_n[/tex] and ∑[tex]b_n[/tex] are positive series. You can check by plugging various real number for ( n ) in both series.

- Compute the limit:

                 Lim ( n-> ∞ )  [tex][ \frac{n^2 + 1}{2n^3 - 1} * 2n ] = [ \frac{2n^3 + 2n}{2n^3 - 1} ][/tex]

                 Lim ( n-> ∞ )    [tex][ \frac{2n^3 ( 1 + \frac{1}{n^2} ) }{2n^3 ( 1 - \frac{1}{2n^3} ) } ] = [ \frac{ 1 + \frac{1}{n^2} }{ 1 - \frac{1}{2n^3} } ][/tex]

- Apply the limit ( n - > ∞ ):

                Lim ( n-> ∞ )  [tex][ \frac{a_n}{b_n} ][/tex]  = [tex][ \frac{1 + 0}{1 + 0} ][/tex] = 1   ... Finite

- So from first condition both series either converge or diverge.

- We check for ∑[tex]b_n[/tex] convergence or divergence.

- The ∑[tex]b_n[/tex] = ( 1 / 2n ) resembles harmonic series ∑ ( 1 / n ) which diverges by p-series test ∑ ( [tex]\frac{1}{n^p}[/tex] ) where p = 1 ≤ 1. Hence, ∑

- In combination of limit test and the divergence of ∑[tex]b_n[/tex], the series ∑[tex]a_n[/tex] given also diverges.

Answer: Diverges    

b)          

The given series ∑[tex]a_n[/tex] is:

                   (n = 1) ∑^∞  [tex][ \frac{n}{n^\frac{5}{2} +5} ][/tex]

- We will make an educated guess on the comparative series  ∑[tex]b_n[/tex] by the following procedure.

                  (n = 1) ∑^∞   [tex][ \frac{n( 1 )}{n ( n^\frac{3}{2} + \frac{5}{n} ) } ] = [\frac{1}{( n^\frac{3}{2} + \frac{5}{n} )} ][/tex]

- Apply the limit ( n - > ∞ ) in the denominator for  ( 5 / n ), only the dominant term n^(3/2) is left:

                  (n = 1) ∑^∞    [tex][ \frac{1}{n^\frac{3}{2} } ][/tex] .... The comparative series ( ∑[tex]b_n[/tex] )

- Both series  ∑[tex]a_n[/tex] and ∑[tex]b_n[/tex] are positive series. You can check by plugging various real number for ( n ) in both series.

- Compute the limit:

                 Lim ( n-> ∞ )   [tex][ \frac{n}{n^\frac{5}{2} +5} * n^\frac{3}{2} ] = [ \frac{n^\frac{5}{2}}{n^\frac{5}{2} +5} ][/tex]

                 Lim ( n-> ∞ )    [tex][ \frac{n^\frac{5}{2}}{n^\frac{5}{2} ( 1 + \frac{5}{n^\frac{5}{2}}) } ] = [ \frac{1}{1 + \frac{5}{n^\frac{5}{2}} } ][/tex]

- Apply the limit ( n - > ∞ ):

                Lim ( n-> ∞ )  [tex][ \frac{a_n}{b_n} ][/tex]  = [tex][\frac{1}{1 + 0}][/tex] = 1   ... Finite

- So from first condition both series either converge or diverge.

- We check for ∑[tex]b_n[/tex] convergence or divergence.

- The ∑[tex]b_n[/tex] = ( [tex][ \frac{1}{n^\frac{3}{2} } ][/tex] ) converges by p-series test ∑ ( [tex]\frac{1}{n^p}[/tex] ) where p = 3/2 > 1. Hence, ∑

- In combination of limit test and the divergence of ∑[tex]b_n[/tex], the series ∑[tex]a_n[/tex] given also converges.

Answer: converges

Comparison Test:-  

- Given, ∑[tex]a_n[/tex] and suppose ∑[tex]b_n[/tex] such that both series are positive for all values of ( n ).

-Then the following conditions are applied:

1 ) If ( [tex]a_n[/tex] - [tex]b_n[/tex] ) < 0 , then ∑[tex]a_n[/tex] diverges only if ∑[tex]b_n[/tex] diverges

2 ) If ( [tex]a_n[/tex] - [tex]b_n[/tex] ) ≤ 0 , then ∑[tex]a_n[/tex] converges only if ∑[tex]b_n[/tex] converges

c) The given series ∑[tex]a_n[/tex] is:

                   (n = 1) ∑^∞ [tex][ \frac{4 + 3^2}{2^n} ][/tex]

- We will make an educated guess on the comparative series  ∑[tex]b_n[/tex] by the following procedure.

                  (n = 1) ∑^∞ [tex][ \frac{3^n ( \frac{4}{3^n} + 1 )}{2^n} ][/tex]

- Apply the limit ( n - > ∞ ) in the numerator for  ( 4 / 3^n ), only the dominant terms ( 3^n ) and ( 2^n ) are left:  

                 (n = 1) ∑^∞ [tex][ \frac{3^n}{2^n} ][/tex]   ... The comparative series ( ∑[tex]b_n[/tex] )

- Compute the difference between sequences ( [tex]a_n[/tex] - [tex]b_n[/tex] ):

                 [tex]a_n - b_n = \frac{4 + 3^n}{2^n} - [ \frac{3^n}{2^n} ] \\\\a_n - b_n = \frac{4 }{2^n} \geq 0[/tex], for all values of ( n )

- Check for divergence of the comparative series ( ∑[tex]b_n[/tex] ), using divergence test:

               ∑[tex]b_n[/tex] = (n = 1) ∑^∞ [tex][ \frac{3^n}{2^n} ][/tex]  diverges

- The first condition is applied when  ( [tex]a_n[/tex] - [tex]b_n[/tex] ) ≥ 0, then ∑diverges only if ∑[tex]b_n[/tex] diverges.

Answer: Diverges

Question:

A solid lies between planes perpendicular to the​ x-axis at x=0 and x=12. The​ cross-sections perpendicular to the axis on the interval 0≤x≤12 are squares with diagonals that run from the parabola y=-2√x to the parabola y=2√x. Find the volume of the solid.

Answer:

576

Step-by-step explanation:

Given:

Length of diagonal square:

[tex] D = 2\sqrt{x} - (-2\sqrt{x}) [/tex]

[tex] D = 4\sqrt{x} [/tex]

Here, the diagonal is the hypotenus of a right angle triangle, with leg S, where the square has a side of length S.

Using Pythagoras theorem:

[tex] S^2 + S^2 = D^2 [/tex]

[tex] S^2 + S^2 = (4\sqrt{x})^2 [/tex]

[tex] 2S^2 = 16x [/tex]

Divide both sides by 2

[tex] S^2 = 8x [/tex]

Thus,

Area, A = S² = 8x

Take differential volume, dx =

dV = Axdx

dV = 8xdx

Where limit of solid= 0≤x≤12

Volume of solid, V:

V =∫₀¹² dV

V = 8 ∫₀¹² xdx

V = [4x²]₀¹²

V = 4 (12)²

V = 12 * 144

= 576

Volume of solid = 576

Answer: –55x + 570

Step-by-step explanation:

The person above me completely missed the question so this is the right one

3s represents three times Sydney's age. Sydney's age is symbolized with an S.