Answer:
[tex]F = kx \\ k = \frac{F }{x} [/tex]
so the answer is a
How high is the image of a 1.5 mm high object that is magnified by a 20X lens system?
Answer:
Explanation:
1.5(20) = 30 mm
A raindrop of mass 3.35 * 10-kg falls vertically at constant speed under the influence of gravity and air resistance. Model the drop as a particle. As it falls 100m, what is the work done on the raindrop (a) by the gravitational force and (b) by air resistance?
Answer:
a) Wnet = 0
b) W, = 32.9mJ
c) Wresistance = -32.9mJ
Explanation:
in pic
________________________
(hope This helps can I pls have brainlist (crown)☺️)
A physics class pushes a small wagon along a flat horizontal parking lot with a force of 81.17 N. Starting from rest the wagon travels 11.6 meters in 9.8 seconds. What is the wagon's acceleration?
Answer:
Explanation:
s = ½at²
a = 2s/t²
a = 2(11.6) / 9.8²
a = 0.2415660...
a = 0.24 m/s²
Acceleration of the wagon is 0.241 m/s²
Force exerted on the wagon, F = 81.17 N
Displacement of the wagon, S = 11.6 m
Time taken by the wagon to travel this distance, t = 9.8 s
Using the second equation of motion,
S = ut + 1/2 at²
where u is the initial velocity and a is the acceleration of the wagon.
Since the wagon was initially at rest, u = 0.
So,
S = 1/2 at²
Therefore acceleration of the wagon,
a = 2S/t²
a = 2 x 11.6/(9.8)²
Acceleration, a = 0.241 m/s²
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1) The unit of power is
A. Watt
B. Joules
C. Newton
D. Meter
2) How long does Samah need to do 100J of work with 50W?
A. 2s
B. 0.5s
C. 5000s
D. None of the above
Answer:
1) the unit of power is A.Watt
2)100J=50W
100=50s
divide both sides by 50s
S=2s(A)
A jumbo jet needs to reach a speed of 364 km/hr on the runway for takeoff. Assuming a constant acceleration and a
runway 1.5 km long, what minimum acceleration (in units of m/s2 ) from rest is required?
Answer:
Diaplacement s=1.80km
Final velocity v=360km/h
It starts from rest. So, initial velocity u=0
We need to find the constant acceleration (a).
using the equation of motion v
2
=u
2
+2as
360
2
=0
2
+2×a×1.8
a=
3.6
360×360
a=36000km/h
2
a parking lot is going to be 50m wide and 150m long. which dimensions could be used for a scale model of the lot
Answer:
5m and 15m
Explanation:
What factors affect how an object moves in an environment with air?
Answer:
The factors that affect how an object moves through the air are force, friction, interia, and momentum.
Explanation:
If a radio is connected between the open wire and the circuit is closed, what happens?
Analog signals and storage are used in most modern electronics.
True
False
Analog signals and storage are used in most modern electronics is a false statement.
Analog signals and storage are not used in most modern electronics because analog signals are used in old instruments and technologies while on the other hand, in modern electronics digital signals and storage system are used that have higher speed, compatibility and space for storage.
Analog signals and storage were used in old electronics and can't be used in modern electronics due to non-compatibility so we can conclude that digital signals and storage are used in modern electronics.
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Answer each of the following questions regarding energy and heat transfer: 1. Explain why it is important to understand conductors. 2. Give a real world example where thermal conductors are used. 3. Explain why it is important to understand insulators. 4. Give a real world example where thermal insulators are used. 5. Suppose you do not have electricity or gas for heating up food and you are hungry. Explain what would you do to maximize thermal energy transfer in this situation to safely cook you something to eat.
Question 1 (2 points)
What is gravitation?
Question 1 options:
the tendency of objects to move downward
the attraction of any two objects because of their mass
the attraction or repulsion of objects because of their electric charge
the effect of air pressure in pushing objects to the ground
Question 2 (2 points)
Which of these was discovered by Newton?
Question 2 options:
The acceleration caused by gravity is�9.8�m/s/s.
Gravity keeps the planets in their orbits.
The planets move in elliptical orbits around the sun.
The earth orbits the sun, rather than the reverse.
Question 3 (2 points)
How was the gravitational constant�G�first determined?
Question 3 options:
by measuring the force of gravity between two planets
by observing the moon's orbit
by measuring the force of gravity between two objects on the earth
by knowing that the acceleration caused by gravity is�9.8�m/s/s
Question 4 (2 points)
The force of gravity between any two ordinary objects on the earth is __________.
Question 4 options:
always downward
stronger when closer to the earth
stronger if the objects are more massive
stronger than the force of gravity from the earth
Question 5 (2 points)
Which of these statements is true about the International Space Station in orbit around the earth?
Question 5 options:
The space station exerts a force on the earth toward the space station.
The earth's gravity acts on the space station, but not the reverse.
There is no gravity acting at the height of the space station.
The force of gravity produces the same acceleration for the earth and the space station.
Question 6 (2 points)
Suppose a planet has twice the mass of the Earth and twice the earth's radius. What is the acceleration of an object in free fall on this planet?
Question 6 options:
twice as much as on Earth.
four times as much on Earth.
one half as much as Earth.
one fourth as much as Earth.
Question 7 (2 points)
Which of these does Newton's law of universal gravitation imply?
Question 7 options:
Force is mass times acceleration squared.
There is no gravity inside a space station in orbit.
The earth attracts the moon more strongly than the moon attracts the earth.
The force of the earth's gravity on an object at sea level is stronger than at the top of a mountain.
Question 8 (2 points)
What is a gravitational field?
Question 8 options:
a region of space-time with constant gravity
the region of space-time where the force is equal to�6.67�10?11�N
a region of space-time with a property at each point determined as the gravitational force on any object divided by its mass�m
the force of gravity between any two objects
Question 9 (2 points)
A gravitational field can be represented by
Question 9 options:
field vector arrows pointing in the direction of the gravitational force.
field vector arrows pointing in the direction of the electrical force.
a photo of a large, green field filled with heavy grass.
field vector arrows pointing in random directions based on their mass.
Question 10 (2 points)
What is the magnitude of a gravitational field at a location where an 80 kg astronaut weighs 25 percent what he would weigh on the earth?
Question 10 options:
10 N/kg
2.5 N/kg
20 N/kg
200 N/kg
Question 11 (2 points)
What causes gravitational force in Einstein's theory of general relativity?
Question 11 options:
the way an object with mass placed on a surface bends the surface
the way mass bends space and time
the existence of black holes
reference frames moving at a constant relative velocity
Question 12 (2 points)
A mass of 10.0 kg is in a gravitational field of�3.50�N/kg�. What force acts on the mass?
Question 12 options:
0.35 N
9.8 N
35.0 N
21.6 N
We have several questions about gravity, the answers are:
The first question is, what is gravitation?
We define gravitational force as the attraction force between two objects with mass. From this, we can see that the correct option is:
"the attraction of any two objects because of their mass"
The second question is, which of the following was discovered by Newton?.
Newton concluded that the forces between objects with masses were what defined the orbits in the solar system, so the correct option here is:
"Gravity keeps the planets in their orbits."
The third question is: How the gravitational constant was first determined?
It was originally measured by Cavendish in 1978, he actually measured Earths density, and by knowing that the acceleration was roughly 9.8m/s^2, he could estimate the constant, so here the correct option is:
"by knowing that the acceleration caused by gravity is 9.8 m/s/s"
The fourth question is: The force of gravity between any two ordinary objects on the earth is?
Remember, gravity is an attractive force that depends on the mass of the objects. Here the only option that is always correct is:
"stronger if the objects are more massive"Question 5:Here the correct option is:"
For question 5 we have that the correct one is:
"The space station exerts a force on the earth toward the space station" Gravity acts on both objects, the earth and space station, just that the planet has a lot more mass than the space station, thus the force that it causes in the planet is negligible.
Question 6:
Gravity increases linearly with mass and decreases quadratically with distance, so if we double the mass and the radius, we can expect that the gravity at the surface to be near half of that one we have on Earth, then the correct option is:
"one half as much as Earth."
Question 7:
Again, force decreases with distance squared, then if you are closer to the planet, let's say, at sea level, the force will be greater than if you are on top of a mountain. The correct option is:
"The force of the earth's gravity on an object at sea level is stronger than at the top of a mountain."
Question 8.
By definition of gravitational field, the correct option is the last one:
"a region of space-time with a property at each point determined as the gravitational force on any object divided by its mass"
Question 9:
The field defines the force, thus the arrows should point in the same direction that the force acts, the correct option is:
"field vector arrows pointing in the direction of the gravitational force."
Question 10:
The correct option is 2.5 N/kg
Notice that N/kg = m/s^2
To get this, you just need to compute the 25% of Earth's gravitational acceleration.
Question 11:
The correct option is:
"the way an object with mass placed on a surface bends the surface"
Gravity is thought as a deformation in the space plane.
Question 12:
We just multiply the mass by the field:
10kg*3.5 N/kg = 35N
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si Ana camina sobre una cuerda que la sostiene dos edificios separados 10m, la soga tiene un angulo de 10grados, La masa de Ana es de 50kg ¿cual es la tension de la cuerda?
On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 94.0 cm and diameter 2.75 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g
Answer:
Explanation:
Wt = ρVg
Wt = ρ(πD²/4)hg
Wt = 7800(π0.0275²/4)0.94(9.81)
Wt = 42.72152359...
Wt = 42.7 N
what is the angular speed, w, of the snowball after it has traveled a distance D down the slope of the roof
Newton's second law and the kinematics of rotation allow us to find the angular velocity of the snowball as it rolls across the roof is:
w = [tex]\frac{2g}{R}[/tex]
The kinematics of rotational motion studies the rotational motion of bodies.
w = w₀ + 2 α θ
Where w and w₀ are the current and initial angular velocities, α the angular acceleration and θ the angle traveled.
Newton's second law establishes a relationship between the force, mass, and acceleration of the body.
The linear and rotational moviments are related.
a = α R
Where a and α are the linear and rotational accelerations, respectively, and R is the radius of the body.
Let's find the linear acceleration of the body, in the attached we see a diagram of the forces, let's use trigonometry to decompose the weight.
[tex]sin \theta = \frac{W_x}{W}[/tex]
Wₓ = W sin θ
Wₓ = m a
mg sin θ = m a
a = g sin θ
Now we can find the angular acceleration.
α = a / R
α = [tex]\frac{g}{ R \ sin \theta }[/tex]
The body is released therefore its initial velocity is zero, we substitute in the kinematics expression.
[tex]w = 2 ( \frac{g}{R \ sin \theta }) \ \theta[/tex]
in rotational motion the angles are measured in radians We use trigonometry to find the relationship between the angle and the distance traveled
[tex]\theta = \frac{h}{D}[/tex]
Where h is the height of the ceiling and D is the distance traveled. Let's substitute.
[tex]w = 2 \frac{g}{R sin \theta } \frac{h}{D}[/tex]
Let's tirgonmetry.
sin θ = [tex]\frac{h}{D}[/tex]
w = [tex]\frac{2g}{R}[/tex]
In conclusion, using Newton's second law and the kinematics of rotation, we can find the angular velocity of the snowball when rolling on the roof is:
w = [tex]\frac{2g}{R}[/tex]
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A remote-control car has batteries that store 1.8 kJ of energy. When the car is
driven across a sports field there is friction dragging on the car, producing a force
of 2 N.
Complete the following sentence: If the car is 100% efficient , it could travel a
distance of ……….metres on a single battery charge.
Answer:
Explanation:
If the car is 100% efficient , it could travel a
distance of 900 metres on a single battery charge.
1800 J = 2 N•d m
d = 900 m
a car stopped at a red light, not moving?
a) 1st Newton's law
b) 2nd Newton's law
c) 3rd Newton's law
I think it's a) 1st Newton's law... so sorry if it's wrong...
Scoring a bogey on a hole means that you were:
1. One over par
2. One under par
3. Right on par
4. Nowhere near par
Answer: One over par
Answer:
Dear questioner;
Paddington's Answer is One over par that's he see in his book and Aunt Lucy help him
A solid sphere with a radius of 5cm initially at rest rolls 270cm down a slope 37° above the horizontal. What is its velocity (rad/s) at that point? [PS: it has not reached the foot of the slope]
This question involves the concepts of the law of conservation of energy, kinetic energy, potential energy, and moment of inertia.
The angular velocity of the solid sphere at this point is "95.44 rad/s".
According to the law of conservation of energy:
Loss in Potential Energy = Gain in Rotational Kinetic Energy + Gain in Translational Kinetic Energy
[tex]mgh = \frac{1}{2}I\omega^2+\frac{1}{2}mv^2[/tex]
where,
m = mass of sphere
g = acceleration due to gravity = 9.81 m/s²
h = loss in height = (270 cm) Sin 37° = 162.5 cm = 1.625 m
r = radius of sphere = 5 cm = 0.05 m
ω = angular speed of sphere = ?
v = linear speed of sphere = rω
I = moment of inertia of sphere = [tex]\frac{2}{5}mr^2[/tex]
Therefore,
[tex]mgh=\frac{1}{2}\frac{2}{5}mr^2\omega+\frac{1}{2}m(r\omega)^2\\\\gh=\frac{1}{5}r^2\omega^2+\frac{1}{2}r^2\omega^2\\\\(9.81\ m/s^2)(1.625\ m)=(\frac{1}{5}+\frac{1}{2})(0.05\ m)^2\omega^2\\\\\omega=\sqrt{\frac{15.941\ m^2/s^2}{0.00175\ m^2}}[/tex]
ω = 95.44 rad/s
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The attached picture explains the law of conservation of energy.
The surface of the sun has a temperature of about 5800K and consists largely of hydrogen atoms. Find the rms speed of a hydrogen atom at this temperature. (The mass of a single hydrogen atom is 1.67×10−27kg.) The escape speed for a particle to leave the gravitational influence of the sun is given by (2GM/R)1/2, where M is the sun's mass, R its radius, and G the gravitational constant. The sun`s mass is M=1.99×1030kg, its radius R=6.96×108m and G=6.673×10−11N⋅m2/kg2. Calculate the escape speed for the sun.
This question involves the concepts of kinetic energy, escape velocity, and rms speed.
a) The rms speed of hydrogen atom at 5800 K is "11991 m/s".
b) The escape velocity for the Sun is "6.18 x 10⁵ m/s".
a)
We will use the formula of the average kinetic energy of gas molecules to find out the rms speed of the hydrogen atom. rms speed is the root mean square speed of an atom:
[tex]K.E = \frac{3}{2}KT=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{3KT}{m}}[/tex]
where,
v =rms speed = ?
K = Boltzman's Constant = 1.38 x 10⁻²³ J/k
T = absolute temperature = 5800 k
m = mass of hydrogen atom = 1.67 x 10⁻²⁷ kg
Therefore,
[tex]v=\sqrt{\frac{3(1.38\ x\ 10^{-23}\ J/k)(5800\ k)}{1.67\ x\ 10^{-27}\ kg}}[/tex]
v = 11991 m/s
b)
The escape velocity of the Sun is given by the following formula:
[tex]v_e=\sqrt{\frac{2GM}{R}}[/tex]
where,
ve = escape velocity = ?
G = Gravitational Constant = 6.673 x 10⁻¹¹ N.m²/kg²
M = Mass of Sun = 1.99 x 10³⁰ kg
R = radius of Sun = 6.96 x 10⁸ m
Therefore,
[tex]v_e=\sqrt{\frac{2(6.673\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{6.96\ x\ 10^8\ m}}[/tex]
[tex]v_e = 6.18\ x\ 10^5\ m/s[/tex]
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d. If they are dropped from their original heights at the same time, will the melon or
the pomegranate hit the ground first? Explain. (1 point)
Answer:
Melon
Explanation:
The melon will hit the ground first because it has a greater mass and therefore greater gravitational pull than the pomegranate, which weighs less.
Both melon and the pomegranate will reach the ground at the same time
What is gravitational force ?The force between all masses in the universe, especially the force of the earth's mass for bodies near its surface is called gravitational force
Both melon and the pomegranate will reach the ground at the same time ,because melon is heavier hence it will have greater gravitational force on it but it will also has lower acceleration but pomegranate have lighter mass hence will have lower gravitational force but have higher acceleration , so these two effects will cancel each other and allow both melon and pomegranate to reach the ground at same time .
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Q1. How much gravitational potential energy do you gain when you walk up the CN Tower stairs (346 m)? What type of energy/energies transformed into GPE in this scenario?
The characteristics of the gravitational potential energy allows to find the results for the energy change when climbing the stairs are:
The energy change is: ΔU = 3390.8m. If the mass is m = 1kg the energy is ΔU = 3390.8 J This energy is a system configuration energy type.
Potential energy is a configuration energy of the system, the system has the ability to perform work. The gravitational potential energy is:
U = mg y - U₀
Where U is the gravitational potential energy and m the mass of the body, g the acceleration of gravity and y the height, Uo is the zero of the energy that must be defined for each case.
Indicates that the body rises a height of y = 346 m, the energy increases.
ΔU = U-U₀ = m g y
ΔU = m 9.8 346
ΔU = 3390.8 m
Where m is the mass of the body. If we assume that the mass is m = 1kg.
ΔU = 3390.8 J
This energy is due to the height therefore it is due to the configuration of the system, consequently it is a configuration energy.
In conclusion, using the characteristics of gravitational potential energy we can find the results for the energy change when climbing the stairs are:
The energy change is ΔU = 3390.8m. If the mass is m = 1kg the energy is ΔU = 3390.8 J Potential energy is a system configuration wnwegy type.
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At what speed does the squid eject the water?
Answer:
3.5 m/s
Explanation:
As a passenger balloon rises, its gas bag tends to A. Become smaller B. Leak C. Distort D. Expand E. Remain unchanged
Answer:
I think it expands
Explanation:
Answer:
E. remain unchanged
Explanation:
Three identical clay balls collide as in the diagram below. Two of the clay balls come in at equal angles of 35 degrees and equal (unknown) speeds, and strike the third (stationary) ball simultaneously. All three stick together and move off together without rotating. There are no forces on the balls of clay other than those that they exert on each other. Find the fraction of the original energy of the system that becomes thermal?
Answer:
Explanation:
Let the initial velocity of the two moving balls be u
Let the mass of one ball be m
Let the velocity after collision be v
Initial kinetic energy is
2(½mu²) = mu²
Assuming the 35° is measured above and below a common axis,
conservation on momentum.
the vertical portion of that velocity and momentum will be equal and will cancel out.
the horizontal momentum will be
m(ucos35) + m(ucos-35) + m(0) = 3mv
v = (2/3)ucos35 = 0.5461u
final kinetic energy is
½(3m)(0.5461u²) = 0.44734mu²
so the fraction of kinetic energy converted to heat energy is
(mu² - 0.44734mu²) / mu² = 0.5526599... = 0.55
100 POINTS PLEASE answer ASAP
Answer:
uhmmm
Explanation:
uhmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
A 2 kg block is in equilibrium on a 36 degree incline. What is the normal force acting on the block?
15.9 N
Explanation:
Let's assume that the downward direction on the inclined is the (+)-direction. Since the block is in equilibrium, the x-component of its weight is pointing in the +x-direction and the frictional force [tex]f_s[/tex] is pointing up the incline. So the net force acting parallel to the incline can be written as
[tex]mg\sin36 - f_s = 0 \Rightarrow \mu N = mg\sin36[/tex]
where N is the normal force.
The net force perpendicular to the incline can be written as
[tex]N - mg\cos36 = 0 \Rightarrow N = mg\cos36[/tex]
or
[tex]N = (2\:\text{kg})(9.8\:\text{m/s}^2)\cos36 = 15.9\:\text{Newtons}[/tex]
A rotating furnace has been developed recently to give a rough para-
bolic curve to molten glass. This makes the manufacture of very large
telescope mirrors easier and more economical than ever before. The
largest mirror made in this furnace to date has a radius of 4.2 m. While
in the furnace, the centripetal acceleration of the molten glass for this
mirror was 2.13 m/s?. What was the tangential speed at the edge of the
molten glass?
The definition of centripetal acceleration allows to find the result for the linear velocity of the body is:
v = 2.99 m / s
Kinematics studies the movement of bodies, the centripetal acceleration is the acceleration that a body has where all the energy is used to change the direction of the speed, leaving its modulus constant.
[tex]a= \frac{v^2}{R}[/tex]
Where a is the acceleration ccentripette, v the modulus of the velocity and R the radius of gyration.
They indicate that the radius is R = 4.2 m and the centripetal acceleration is a = 2.13 m / s, let's find the modulus of the velocity.
[tex]v= \sqrt{a R}[/tex]
Let's calculate
v = [tex]\sqrt{2.13 \ 4.2}[/tex]
v = 2.99 m / s
In conclusion using the definition of centripetal acceleration we can find the result for the tangential velocity of the body is:
v = 2.99 m / s
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Two blocks, which can be modeled as point masses, are connected by a massless string which passes through a hole in a frictionless table. A tube extends out of the hole in the table so that the portion of the string between the hole and M1 remains parallel to the top of the table. The blocks have masses M1 = 1.9 kg and M2 = 2.8 kg. Block 1 is a distance r = 0.95 m from the center of the frictionless surface. Block 2 hangs vertically underneath. find the speed of m1 assume m2 does not move relative to the table.
The speed of the block m1 on the frictionless table is 1.34 m/s.
The given parameters;
mass of the first block, m1 = 1.9 kgmass of the second block, m2 = 2.8 kgdistance of block m1, R = 0.95 mThe net torque on both blocks is calculated as;
[tex]\tau _{net} = I \alpha[/tex]
[tex]T_2R- T_1 R_1 = I \alpha \\\\[/tex]
where;
T₁ is the tension on first blockI is the moment of inertia of point massα is the angular acceleration[tex]T_1 = m_1 g + m_1 a\\\\T_2 = m_2 g - m_2 a[/tex]
The acceleration of both blocks is calculated as follows;
[tex]R(T_ 2- T_1) = MR^2 \times (\frac{a}{R} )\\\\R(T_2 -T_1) = MRa\\\\T_2 - T_1 = Ma\\\\(m_2g - m_2 a) - (m_1 g + m_1 a) = Ma\\\\m_2 g - m_1 g - m_2 a - m_1 a = Ma\\\\g(m_2 - m_1) = Ma + m_2a+ m_1a\\\\g(m_2 - m_1) = a(M+ m_2 + m_1)\\\\where;\\\\M \ is \ mass \ of \ string = 0 \\\\g(m_2 - m_1) = a (0+ m_2 + m_1)\\\\g(m_2 - m_1) = a(m_1 + m_2)\\\\a = \frac{g(m_2 - m_1)}{m_1 + m_2} \\\\a = 1.88 \ m/s^2[/tex]
The speed of the block m1 is calculated as follows;
[tex]a = \frac{v^2}{r} \\\\v^2 = ar\\\\v = \sqrt{a r} \\\\v = \sqrt{1.88 \times 0.95} \\\\v = 1.34 \ m/s[/tex]
Thus, the speed of the block m1 on the frictionless table is 1.34 m/s.
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Saturn orbits the Sun at a radius of about 1.4×109 km. At this distance the force of gravity on Saturn due to the Sun is 3.7×1022 N. Assuming Saturn's orbit to be perfectly circular, how much work grav does the Sun's gravity do on Saturn in one year?
Explanation:Saturn is the second largest planet of the solar system in mass and size and the sixth nearest planet in distance to the Sun.
In the night sky Saturn is easily visible to the unaided eye as a non twinkling point of light.
What force acting on an object would cause it’s weight to change
Answer:
The Force Of Gravity
