Expression Math problem...help and get 15 pts!

The linear equation that satisfy the data in the table is: A. y = −4x − 4.

Given the table attached below, find the slope (m) = change in y / change in x using two pairs of values, say, (-1, 0) and (0, -4):

Slope (m) = (-4 - 0)/(0 - (-1)) = -4/1 = -4

Find the y-intercept (b), which is the value of y when x = 0. From the table, when x = 0, y = -4.

b = -4.

Substitute m = -4 and b = -4 into y = mx + b

y = -4x + (-4)

y = -4x - 4

The equation that satisfy the data is: A. y = −4x − 4.

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The inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

a(n) =  3n - 30

To find make subject n and solve

a(n) + 30 = 3n

[tex]\rm n = \dfrac{a(n) + 30}{3}[/tex]

Plug n = n(a) and a(n) = a

[tex]\rm n(a) = \dfrac{a + 30}{3}[/tex]

Thus, the inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.

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Answer:

According to the given function, the value of h(-1) is -1, h(-0.5) is 0 and h(1) is 1.

Step-by-step explanation:

The given function says that:

If the range of the values of x is x∈(-2,-1], then the value of the function is -1.

If the range of the values of x is x∈(-1,0], then the value of the function is 0.

If the range of the values of x is x∈(0,1], then the value of the function is 1.

If the range of the values of x is x∈(1,2], then the value of the function is 2.

In the first case, we have x = -1. This satisfies the first condition. So accordingly, the value that the function will give is -1.

In the second case, we have x = -0.5. This satisfies the second condition. So accordingly, the value that the function will give is 0.

In the third case, we have x = 1. This satisfies the third condition. So accordingly, the value that the function will give is 1.

So, h(-1) = -1, h(-0.5) = 0 and h(1) = 1.

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Answer:

the answer for this problem is A, big

The  values of x and y would make the following expression represent a real number is 4 and -5 respectively

The standard form of writing a complex number is given asl

z= x + iy

where

x is the real part

y is the imaginary part

Given the expression below;

(4 +5i)(x + yi)

Expand

4x + 4yi + 5ix + 5y(-1)

4x + 4yi + 5ix - 5y

Hence the  values of x and y would make the following expression represent a real number is 4 and -5 respectively

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Answer:

yes

Step-by-step explanation:

Answer:

1.37

Step-by-step explanation:

3^1=3/2=1.5

2^(1/3)=1.26

1.5×1.26=1.89

1.89^(1/2)=1.37

Answer:

don't know is is mathematics or any other subject

[tex]\angle P = \angle S \Rightarrow \angle S = 42 &^\circ\\\angle Q = \angle T \Rightarrow \angle S = 86 &^\circ\\\angle R = \angle U\\[/tex]

Sum of all angles in a triangle equals 180:

[tex]\angle R = 180 - (86 + 42) = 180 - 128 = 52[/tex]

Answer:

[tex]U = 52 &^ \circ[/tex]

The function in this graph is increasing in the interval   –2 ≤ x ≤ 3 , Option D is the right answer.

A function is a mathematical statement used to relate a dependent and an independent variable.

From the graph it can be seen that the graph is increasing in the interval

–2 ≤ x ≤ 3

The graph is said to be increasing when the value of y is getting more and more positive

As  –2 ≤ x ≤ 3 , y varies from -3 to +3

Therefore Option D is the right answer.

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Answer:

–2 ≤ x ≤ 3

Step-by-step explanation:

The proper steps for the construction are given as 1, 2 4, and then 3.

The proper steps for the construction are;

1. Place the compass needle on the external point R. Make the compass width greater than the distance from R to the given line.

2. Draw an arc cutting the given line at two points. Mark and label the points of intersection P and Q.

3. Move the compass needle to P and make an arc below the line. Keep the compass width, and move the compass needle to Q. Draw an arc below the line crossing the other arc. Mark and label the point of intersection S.

4. Draw a line from the external point R to the points where the arcs intersect, S. Line RS is perpendicular to line PQ and passes through the external point R.

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Answer:

Domain: All real number
Range: y≤-4

Using a trigonometric identity, it is found that the equivalent expression is given by 1.

Relating sine and cosine, we have that:

[tex]\sin^{2}{\beta} + \cos^{2}{\beta} = 1[/tex]

Then:

[tex]\cos^{2}{\beta} = 1 - \sin^{2}{\beta}[/tex]

For the tangent, we have that:

[tex]\tan{\beta} = \frac{\sin{\beta}}{\cos{\beta}}[/tex].

For the secant, we have that:

[tex]\sec{\beta} = \frac{1}{\cos{\beta}}[/tex].

In this problem, the expression is:

[tex]\frac{(1 - \sin{\beta})(1 + \sin{\beta})}{\cos^{2}{\beta}} = \frac{1 - \sin^2{\beta}}{\cos^2{\beta}} = \frac{\cos^2{\beta}}{\cos^2{\beta}} = 1[/tex]

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Notice that the difference in the absolute values of consecutive coefficients is constant:

|-7| - 1 = 6

13 - |-7| = 6

|-19| - 13 = 6

and so on. This means the coefficients in the given series

[tex]\displaystyle \sum_{i=1}^\infty c_i a^{i-1} = \sum_{i=1}^\infty |c_i| (-a)^{i-1} = 1 - 7a + 13a^2 - 19a^3 + \cdots[/tex]

occur in arithmetic progression; in particular, we have first value [tex]c_1 = 1[/tex] and for [tex]n>1[/tex], [tex]|c_i|=|c_{i-1}|+6[/tex]. Solving this recurrence, we end up with

[tex]|c_i| = |c_1| + 6(i-1) \implies |c_i| = 6i - 5[/tex]

So, the sum to [tex]n[/tex] terms of this series is

[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 \underbrace{\sum_{i=1}^n i (-a)^{i-1}}_{S'} - 5 \underbrace{\sum_{i=1}^n (-a)^{i-1}}_S[/tex]

The second sum [tex]S[/tex] is a standard geometric series, which is easy to compute:

[tex]S = 1 - a + a^2 - a^3 + \cdots + (-a)^{n-1}[/tex]

Multiply both sides by [tex]-a[/tex] :

[tex]-aS = -a + a^2 - a^3 + a^4 - \cdots + (-a)^n[/tex]

Subtract this from [tex]S[/tex] to eliminate the intermediate terms to end up with

[tex]S - (-aS) = 1 - (-a)^n \implies (1-(-a)) S = 1 - (-a)^n \implies S = \dfrac{1 - (-a)^n}{1 + a}[/tex]

The first sum [tex]S'[/tex] can be handled with simple algebraic manipulation.

[tex]S' = \displaystyle \sum_{i=1}^n i (-a)^{i-1}[/tex]

[tex]\displaystyle S' = \sum_{i=0}^{n-1} (i+1) (-a)^i[/tex]

[tex]\displaystyle S' = \sum_{i=0}^{n-1} i (-a)^i + \sum_{i=0}^{n-1} (-a)^i[/tex]

[tex]\displaystyle S' = \sum_{i=1}^{n-1} i (-a)^i + \sum_{i=1}^n (-a)^{i-1}[/tex]

[tex]\displaystyle S' = \sum_{i=1}^n i (-a)^i - n (-a)^n + S[/tex]

[tex]\displaystyle S' = -a \sum_{i=1}^n i (-a)^{i-1} - n (-a)^n + S[/tex]

[tex]\displaystyle S' = -a S' - n (-a)^n + \dfrac{1 - (-a)^n}{1 + a}[/tex]

[tex]\displaystyle (1 + a) S' = \dfrac{1 - (-a)^n - n (1 + a) (-a)^n}{1 + a}[/tex]

[tex]\displaystyle S' = \dfrac{1 - (n+1)(-a)^n + n (-a)^{n+1}}{(1+a)^2}[/tex]

Putting everything together, we have

[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 S' - 5 S[/tex]

[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 \dfrac{1 - (n+1)(-a)^n + n (-a)^{n+1}}{(1+a)^2} - 5 \dfrac{1 - (-a)^n}{1 + a}[/tex]

[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} =\boxed{\dfrac{1 - 5a - (6n+1) (-a)^n + (6n-5) (-a)^{n+1}}{(1+a)^2}}[/tex]

Answer:  The equation is   y = 4x+3

Slope = 4

y intercept = 3

========================================================

Explanation:

Let's start off by finding the slope.

[tex]A = (x_1,y_1) = (0,3) \text{ and } B = (x_2,y_2) = (4,19)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{19 - 3}{4 - 0}\\\\m = \frac{16}{4}\\\\m = 4\\\\[/tex]

The slope is 4.

The y intercept is 3 because of the point (0,3)

We go from y = mx+b to y = 4x+3

m = slope

b = y intercept

---------------

Check:

Plug in x = 0 and we should get to y = 3

y = 4x+3

y = 4(0)+3

y = 0+3

y = 3

That works out. Now try x = 4. It should lead to y = 19

y = 4x+3

y = 4(4)+3

y = 16+3

y = 19

The answer is confirmed.

Answer:

140km

Step-by-step explanation:

Distance = Speed x Time

= 70km/h x 2 hours

= 140km

Answer:

The chain of the length 7 inches weighs 112 ounces.

Step-by-step explanation:

As we know there are 12 inches in a foot and 16 ounces in a pound

That is 1 foot = 12 inches.

and 1 pound = 16 ounces.

Given that the weight of the chain that is 1 foot long = 12 pounds

So weight of the chain per inch is = 12/12

which is equal to 1 pound

and according to the formula 1 pound = 16 ounces

So weight of the chain per inch is =  16 ounces

therefore weight of the chain that is 7 inch long = 7 × 16

that is 112 ounces.

The chain of the length 7 inches weighs 112 ounces.

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Answer:

Step-by-step explanation:

7 marks

6 same colors

from 12 red 6 same exactly the same

12 x 11 x 10 x 9 x7 x6

1 remainig

from 9 green 6 saem exactly the same

9 x 8 x 7 x 6 x5 x4

1 remaining

add the results above to get your final answer

26 markers in total

6 to be chosen of the same color from 7

Answer:

600/100*20=6*20=120

600-120=480$

Answer:

x=−2 and y=−1

Step-by-step explanation:

Problem:

Solve y=x2;y=−x−3

Steps:

I will solve your system by substitution.

y=1/2x;y=−x−3

Step: Solve y= 1/2x for y:

Step: Substitute 1/2 x for y in y=−x−3:

y=−x−3

1/2x= =−x−3

1/2x+x=−x−3+x(Add x to both sides)

3/2x = -3

3/2x/3/2 = -3/3/2 (Divide both sides by 3/2)

x=−2

Step: Substitute −2 for x in y=1/2x:

y=1/2x

y=1/2(-2)

y=−1(Simplify both sides of the equation)

Answer:

x=−2 and y=−1

The correct answer is option A which is the number of cars sold for the price range of $4000 to $4999 will be 15.

A histogram is a graph for the representation of the data on the plot of the rectangular boxes. It has the data sets on the horizontal and the vertical axes.

As we can see from the histogram data we will conclude that the price range of $4000 to $4999 is shown by the third block and this third block reaches the height of 15.

Therefore the correct answer is option A which is the number of cars sold in the price range of $4000 to $4999 will be 15.

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Answer:

3.160

Step-by-step explanation:

You can solve for x using logarithm.

Rewrite in logarithm form

[tex]log_{6}4=2x\\\\x=\frac{log_64}{2}\\x=\frac{\frac{log4}{log6}}{2}\\x=\frac{log4}{log6} * \frac{1}{2}\\x=\frac{log4}{log6 * 2}\\x\approx0.386852807\\36^{6(0.386852807)-2} \approx3.160[/tex]

The surface area of the given composite figure is; 528 ft²

To get the surface area of the attached composite shape, we will have to break the object down into smaller shapes to get;

Surface area 1 = 2(15 * 4) = 120 ft²

Surface area 2 = 2(9 * 4) = 72 ft²

Surface area 3 = 2(6 * 4) = 48 ft²

Surface area 4 = 2((15 * 15) - (9 * 9)) = 288 ft²

Thus;

Total surface area = 120 + 72 + 48 + 288

Total surface area = 528 ft²

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Answer:

[tex](a) \: 3.1563 \times {10}^{6} = 31563 \times {10}^{6} \times {10}^{ - 4} = 31563 \times {10}^{6 - 4} = 31563 \times {10}^{2} = 3156300[/tex]

__o__o__

[tex](b) \: 5.65 \times {10}^{ - 4} = 565 \times {10}^{ - 4} \times {10}^{ - 2} = 565 \times {10}^{ - 4 - 2} = 565 \times {10}^{ - 6} = 0.000565[/tex]

Answer: 925

Step-by-step explanation:

This is an arithmetic series with first term 1 and last term 3(25)-2=73, with a total of 25 terms.

Using the sum of an arithmetic series formula, we get the sum is:

[tex]\frac{25}{2}(1+73)=\boxed{925}[/tex]

Answer:

C

Step-by-step explanation:

The correct statement is option C.

A real number and an imaginary number are effectively combined to create a complex number. The complex number is written as a+ib, where a and ib are real and imaginary numbers, respectively. Additionally, i = √-1 and both a and b are real numbers.

Since we know that

Complex number is of the form a+ib

Where,

a is real number belongs to real axis

And b is also a real number belongs to imaginary axis.

And the value of i = √-1

Thus,

The set of all numbers of the form a+bi, where a and b are any

real numbers and i equals √-1 is the correct statement.

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The horizontal distance from the point where it was launched is 7.143.

We have given that,

The path of the marshmallow can be modeled by the quadratic y=−0.07x^2+x+2.2,

x represents the horizontal distance from the point it is launched, in feet.

Horizontal distance means the distance between two points measured at a zero percent slope.

(1) Put x = 7.143 in given equation

y= -0.07(7.143)^2+7.143+2.2

y= 2.2

y= 5.771

We have to determine the what is its horizontal distance from the point where it was launched.

The value of x is called horizontal distance.

Therefore the horizontal distance from the point where it was launched is 7.143.

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