Explanation:
Examples for effect of force - example
1) Can change the state of an object(rest to motion/ motion to rest):For example, pushing a heavy stone in order to move it. 2) May change the speed of an object if it is already moving. ... 3) May change the direction of motion of an object.
3) El motor de una moto le imprime una velocidad de 90 km/h al aplicar sobre ella una fuerza de 240 N. ¿Cuál es la potencia de la moto en vatios?
Answer:
P = 6000 W
Explanation:
The given question is "The motor of a motorcycle gives it a speed of 90 km / h when a force of 240 N is applied to it. What is the power of the motorcycle in watts?"
Given that,
Speed of a motorcycle, v = 90 km/h = 25 m/s
Force applied to the motorcycle, F = 240 N
We need to find the power of the motorcycle. We know that,
Power = Fv
So,
P = 240 N × 25 m/s
= 6000 W
So, the required power of the motorcycle is equal to 6000 W.
AWARDING BRAINLIEST (～￣▽￣)～
The thread around a screw is a lever.
Please select the best answer from the choices provided
T
F
About 40,000 J of energy is stored in a typical 1.5-V D-cell battery. If two such batteries are joined to produce a total of 3.0 V in a flashlight circuit and cause 2.0 A of current to flow through the flashlight bulb, how long will the batteries be able to deliver power to the flashlight at this level?
URGENT PLS HELP
Answer:
Time = 13333.33 s = 222.22 min = 3.7 h
Explanation:
The total amount of energy in two cells combined will be:
[tex]Total\ Energy = 40000\ J + 40000\ J\\Total\ Energy = 80000\ J\\[/tex]
Now, we calculate the power of the batteries:
[tex]Power = (Voltage)(Current)\\Power = (3\ V)(2\ A)\\Power = 6\ Watt[/tex]
Now, we use the following formula to calculate the time the batteries will be able to deliver the power to the flashlight:
[tex]Total\ Energy = (Power)(Time)\\\\Time = \frac{Total\ Energy}{Power}\\\\Time = \frac{80000\ J}{6\ Watt}[/tex]
Time = 13333.33 s = 222.22 min = 3.7 h
Displacement is used to measure
A.
weight
B.
mass
C.
distance
D.
volume
Answer:
D. Volume
Hope this helped <3
State advantages and disadvantages of expansion of solid
Answer:
One of the most useful use of expansion by heat is for switches on many types of machinery and home appliances Thermostats in the millions of cars are operated by using the expansion of metal Thermometers are another example,
The disadvantages are just as common Railway lines need free movement d will buckle without sufficient clearance. Internal combustion engines need to be designed to allow for expansion and contraction of metal parts
A 0.17 kg softball moving at 30 m/s is caught by a player. If the average force on the
player's hands during the catch is 500 N, find the time in which the ball came to a stop.
Answer:
0.35
Explanation:
ur dogwater
distinguish between speed and velocity
Speed has no direction.
Velocity has one.
Analyze the data from Data Table 2. As the mass of an object doubles, its kinetic energy
1. is halved
2. doubled
3. quadrupled
4. does not change
Answer: 2- doubled
Explanation:
Given
for m=0.02 kg, v=5 m/s, kinetic energy is 0.25 J
for same velocity and double mass i.e.
m=0.04 kg, v=5 m/s, kinetic energy is 0.50 J
same is with
m=0.08 kg, v=5 m/s , kinetic energy is double to [tex]2\times 0.5=1\ J[/tex]
So, on doubling the mass, kinetic energy is doubled
* science*Name the two types of neutron stars.
Answer:
Radio pulsars and Recycled pulsars
Because fluid pressure increases witj depth, there is more fluid pressure_____ of a submerged object than on the ____
Answer:
Because fluid pressure increases with depth, there is more fluid pressure___outside__ of a submerged object than on the _inside___
Explanation:
As the object is submerged means that it is under water and not on the surface. It tells that water pressure exerting on the object from the outside is higher than inside which is why the object is submerged.
In the other case, the object will not remain submerged if its internal pressure is high, it will float on water.
A lifeguard on a beach observes that waves have a speed of 2.60 m/s and a distance of 2.50 m between wave crests. What is the period of the wave motion? Please show all work. (ref: p.382-387)
Answer:
T = 0.96 seconds
Explanation:
Given that,
The speed of wave, v = 2.6 m/s
The distance between wave crests, [tex]\lambda=2.5\ m[/tex]
We need to find the period of the wave motion. Let T be the period. So,
[tex]v=\dfrac{\lambda}{T}\\\\T=\dfrac{\lambda}{v}\\\\T=\dfrac{2.5}{2.6}\\\\T=0.96\ s[/tex]
So, the period of the wave motion is equal to 0.96 seconds.
The period of the wave motion is 0.96 seconds. Using the formula:
v = λ / T
where v is the velocity of the wave, λ is the wavelength and T is the period of the wave.
Given that v = 2.60 m/s, λ = 2.5 m, hence:
2.6 = 2.5/T
T = 0.96 s
The period of the wave motion is 0.96 seconds.
Find out more on period at: https://brainly.com/question/10843932
A 5 kg object experiences a horizontal force, which
causes it to accelerate at 2 m/s2, moving it a distance of
10 m horizontally. How much work is done by the force
on the object?
Answer:
The work is done by the force 100 NM.
Explanation:
=5kg * 2 m/s^2
=5* 2 N (kg*m/s^2=N)
=10N
Work done = force* distance
=10N* 10
= 100 NM
For an object of mass 5 kg accelerating at the rate of 2 m/s², then the work done by the force on the object will be 100 Nm.
What is Work?In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.
The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given information in the question,
Mass of the object, m = 5 kg
Acceleration, a = 2 m/s²
Distance, d = 10 m
W = f × d
W = m × a × d
W = 5 × 2 × 10
W = 100 Nm
To know more about Work:
https://brainly.com/question/13662169
#SPJ2
A boy pushes his baby sister on a swing in the playground. At the top
of the baby's path, she has a potential energy of 200 J.
How much potential energy will she have at the bottom of her path?
How much kinetic energy will she have at the bottom of her path?
Answer:
* If there is no friction U = 0, K = 200 J
* If there is friction U = 0, K = 200 - W
Explanation:
For this exercise we must make an assumption.
* If there is no friction
The energy of the system is conserved therefore the energy is transformed.
The potential energy is
U = m g h
at the bottom of the road there is no height therefore
U = 0
and all the energy has been transformed into kinetic energy
K = 200 J
* If there is friction, which can come from the internal friction of the car, the friction force between the car and the floor, etc.
in this case there is a loss of energy due to the work of non-conservative forces (friction).
The potential energy at the bottom of the path is hedron because there is no height U = 0
The kinetic energy is
K = U -W
K = 200 - W
where W is the work of the friction force.
Which is the graph of the polar equation r = 4 cos3 theta
Answer:
B
Explanation:
The correct answer is B on edge
(Looks like a flower with 3 petals with the most right petal covering the x-axis.)
Answer: Just pray for me, thank you.
4.3.11 QC
100% correct
1. Use the image to answer the question.
Select the equation that represents the graph.
Which table best represents the graph of the equation θ = 45°
Answers:
1. r= 4 which is C
2. A table
3. D (4.24, pi/4)
4. D Radius 1 and center (1,0)
5. B symmetrical about the vertical axis
Explanation: I did it!
Which statement about the mass of a falling object is correct? A.It decreases as the object falls. B.It increases as the object falls. C.It is equal to the weight of the object. D.It stays the same as the object falls.
Answer:
D.It stays the same as the object falls.
A girl who is watching a plane fly tells her friend that the plane isn't moving at all. Describe a frame of reference in which the girl's description would be true.
The girl's reference frame must be moving with the same speed as the plane.
If an observer is stationary and he watches a car moving he can observe that the car has a momentum and is moving with certain speed. But if the observer is in the car or moving with same speed, the car does not appear to move away form the observer. Likewise, two observers moving with different speed will have different observation about the same car.
Similarly, if the girl describes the plane is not moving that means either she is in the plane or moving with the same speed along with the plane.
Learn more about frame of reference:
https://brainly.com/question/20897534
What do you call the material or "stuff" that a wave travels through
A medium
B wave
C decibel
D doppler
how are a grassland ecosystem and a pond ecosystem connected?
Answer:
terrestrial ecosystem and pond ecosystem is an aquatic ecosytem, hence both their abiotic and biotic components would be different.
Explanation:
Explain why gases are more compressible than solid
Answer:
If we put pressure on a solid or a liquid, there is essentially no change in volume. ... The kinetic-molecular theory explains why gases are more compressible than either liquids or solids. Gases are compressible because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.
Explanation:
10) Challenge: A student is pushing a 50 kg cart, with a force of 600 N. Another student measures the speed
of the cart, and finds that the cart is only accelerating at 3 m/s2. How lar is the force pushing back on the car?
Hint: Draw a diagram showing the cart, and the two forces acting on it.
The explanation is shown in the picture. Hope it helps!
Edit: where I wrote "m/s" , I should have wrote m/s^2
A body falling freely on the moon the acceleration due to gravity there is 1.7 m/s2.
a. its displacement at t = 3s
b. the time for it to reach a speed of 25 m/s
c. the time required for it to fall 300 m
d. its speed after falling 70 m
Answer:
a) 7.65 m
b) 14.71s
C) 15.43 m/s
Explanation:
a) s = ut + 0.5at²
s= ?
u = 0
t = 3s
a = 1.7 m/s²
s = 0 + 0.5 × 1.7 × 3²
s = 7.65 m
b) v = u + at
v = 25m/s
u = 0 m/s
a = 1.7 m/s ²
t = ?
v=at
t = v / a
t = 25 / 1.7
t = 14.71s
c) v² = u² + 2as
s = 70m
a = 1.7m/s²
u = 0 m/s
v = ?
v² = 2as
v = √238
v = 15.43 m/s
Once a player has stopped dribbling, how many steps are they allowed to take at maximum?
Answer:
2 steps
Explanation:
:)
this makes basketball interesting
Answer:
2 steps tops. If it is more that is called "traveling".
Explanation:
Out in the ocean, a wave crest 3.2 m high meets a wave trough from another direction which is 2.6 m deep. How high is the resulting wave??
Answer:
Height of resulting wave = 0.6 meters
Explanation:
Let the higher wave (wave crest) be A while the lower wave (wave trough) be B.
Given the following data;
A = 3.2m
B = 2.6m
To find the height of the resulting wave;
Height = A + B
But the lower wave becomes negative because it is below i.e on the lower trough.
Height = 3.2 + (-2.6)
Height = 3.2 - 2.6
Height of resulting wave = 0.6 meters
Please help....
Genetics Practice Problems
1. AA = HoD Ee = He Ii = He Mm = He
Bb = He ff = HoR Jj = He nn = HoR Cc = He
GG = HoD kk = HoR OO = HoD Dd = He
HH = HoD Ll = He Pp = He
This is the molecule in cells that forms part of the protein.
A. rRNA
B. mRNA
C .tRNA
D. DNA
What is the direction of the magnetic force on a positive charge if:
1. V= downward; B= out of the page
2. V=upward; B=right
3. V=right; B=into the page
4. V=into the page; B=upward
5. V=out of the page; B=left
Explanation:
1) left ⬅️
2) into the page
3) upward ⬆️
4) right ➡️
5) downward ⬇️
What force can be seen when North Pole is brought near to South Pole
Answer:
Explanation:
The answer is magnetic force
Answer:
Magnetic forces which causes attraction between the two poles
A bobsled is on an inclined sheet of ice that is frictionless. What must be the angle of the incline if the acceleration of the bobsled is 2.77m/s^2?
Answer:
θ = 73.6º
Explanation:
To solve this exercise, let's use Newton's second law. Let's set a reference system where the x-axis is parallel to the inclined plane
with trigonometry we can find the components of the weight
sin θ = Wₓ / W
cos θ= W_y / W
Wₓ = W sin θ
W_ = W cos θ
Y axis
N - W_y = 0
N = W_y
X axis
Wₓ - fr = m a
mg cos θ - fr = m a
indicate that friction is zero, fr = 0
cos θ = a / g
θ = cos⁻¹ [tex]\frac{a}{g}[/tex]
let's calculate
θ = cos⁻¹ [tex]\frac{2.77}{9.8}[/tex]
θ = 73.6º
Glasses, cameras, flashlights, binoculars, telescopes and peepholes are all made using_lenses.
les ))
Answer:
convex
Explanation:
hope you have a good day!
A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distance d. When the block is released, it slides across a surface that is frictionless except for a rough patch of width 5.0 cm that has a coefficient of kinetic friction = 0.44. Find d, such that the block's speed after crossing the rough patch is 2.3 m/s.
Answer:
Compression distance: [tex]d \approx 0.102\,m[/tex]
Explanation:
According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy ([tex]K[/tex]), in joules, at the expense of elastic potential energy ([tex]U[/tex]), in joules, and overcoming work losses due to friction ([tex]W_{l}[/tex]), in joules:
[tex]K + W_{l} = U[/tex] (1)
By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:
[tex]\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}[/tex] (2)
Where:
[tex]m[/tex] - Mass of the block, in kilograms.
[tex]v[/tex] - Final velocity of the block, in meters per second.
[tex]\mu[/tex] - KInetic coefficient of friction, no unit.
[tex]g[/tex] - Gravitational acceleration, in meters per square second.
[tex]s[/tex] - Width of the rough patch, in meters.
[tex]k[/tex] - Spring constant, in newtons per meter.
[tex]d[/tex] - Compression distance, in meters.
If we know that [tex]m = 1.2\,kg[/tex], [tex]v = 2.3\,\frac{m}{s}[/tex], [tex]\mu = 0.44[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]s = 0.05\,m[/tex] and [tex]k = 730\,\frac{N}{m}[/tex], then the compression distance of the spring is:
[tex]\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}[/tex]
[tex]m\cdot v^{2} + 2\cdot m\cdot g \cdot s = k\cdot d^{2}[/tex]
[tex]d = \sqrt{\frac{m\cdot (v^{2}+2\cdot g\cdot s)}{k} }[/tex]
[tex]d \approx 0.102\,m[/tex]
