Erythropoietin (EPO) is a banned drug used by athletes to increase the oxygen-carrying capacity of their blood. New tests for EPO were first introduced prior to the 2000 Olympic Games held in Sydney, Australia. Chance (Spring 2004) reported that of a sample of 830 world-class athletes, 159 did not compete in the 1999 World Championships (a year prior to the new EPO test). Similarly, 133 of 82:5 potential athletes did not compete in the 2000 Olympic Games. Was the new test effective in deterring an athlete's participation in the 2000 Olympics? If so, then the proportion of nonparticipating athletes in 2000 will be greater than the proportion of nonparticipating athletes in 1999, Use a 98% confidence interval to compare the two proportions and make the proper conclusion.

Answer:

Step-by-step explanation:

Solve for y to put the equation in slope-intercept form.

  3x = 4y -4 . . . . . eliminate parentheses, collect terms

  3x +4 = 4y . . . . . add 4

  y = 3/4x +1 . . . . . divide by 4

The slope is the x-coefficient: 3/4.

The y-intercept is the constant: 1.

Answer: Cylinder

Step-by-step explanation:

Two bases first: that rules out cone and rectangular pyramid.

One lateral face: the only one with that is cylinder.

Hope that helped,

-sirswagger21

The figure which has two bases and one lateral face that is rectangular is, ''Cylinder.''

Any triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.

Given that;

The shape have two bases and one lateral face that is rectangular.

We know that;

In a Cylinder,

It is a three-dimensional solid that contains two parallel bases connected by a curved surface.

And, The bases are usually circular in shape. The perpendicular distance between the bases is denoted as the height “h” of the cylinder and “r” is the radius of the cylinder.

Thus, The figure which has two bases and one lateral face that is rectangular is, ''Cylinder.''

Learn more about the triangle visit;

brainly.com/question/1058720

#SPJ6

Answer:

46/ 67

Step-by-step explanation:

The numbers of students irrespective of grades is;

The sum of the last roll of numbers:

10+24+ 33+ 67 = 134

The number of males irrespective of grades is the sum of the numbers in the male row ;

7 +20+ 14 +41= 82

The numbers of students with grade A is the first column at the last row and is 10;

Hence;

the probability that the student was male OR got an 'A' is

the probability that the student was male plus the probability that he/she got an 'A'.

The probability that it's a male is ;

Number of males/ total number of students

=82/134

The probability that he got an A is;

The number of students that got A/ the total number of students;

10/134

Hence

the probability that the student was male OR got an 'A' is;

82/ 134 + 10/134 = 92/134 = 46/ 67

Answer:

127.5

Step-by-step explanation:

Multiply 170 by 0.75

127.5

Answer:

3 divided by 4 = 0.75 = 3/4

0.75 x 170 = 127.5

or

170/1 x 3/4 = 510/4 = 127 1/2

1/2 = 0.5 = 1 divided by 2

127 + 0.5 = 127.5

127.5 is the answer

Hope this helps

Step-by-step explanation:

Answer:

Step-by-step explanation:

BRUH YOU STUPID

Answer:

0

[tex] \\ solution \\ - 2( -5) - 7 + 1( - 3) \\ = 10 - 7 + ( - 3) \\ = 10 - 7 - 3 \\ = 3 - 3 \\ = 0 \\ hop \: it \: helps...[/tex]

Answer:

7/10 or 70% left

Step-by-step explanation:

total cakes=  30

Gave to Sali

Gave to Jane

Cakes left:

Cakes left fraction:

Answer:

7/10

Step-by-step explanation:

Cakes Simon gave to Sali = 30*1/5

= 6

Cakes Simon Gave to Jane = 30 * 1/10

= 3

Cakes left = 30 - (6-3)

= 21

21 cakes were left, so in terms of a fraction, it'd be 21/30, which can be reduced to 7/10

Hope this helps!

Answer:

Step-by-step explanation:

The given data is expressed as

1204, 1206, 1345, 1306, 1207, 1078, 1357, 1232, 1228, 1302, 1189, 1177, 1083, 1094, 1326, 1071, 1427, 1348, 1420, 1253, 1270

The number of items in the data, n is 21. The lowest value is 1071 while the highest value is 1427. The convenient starting point would be 1070.5 and the convenient ending point would be 1427.5

The number of class intervals is

√n = √21 = 4.5

Approximately 5

The width of each class interval is

(1427.5 - 1070.5)/5 = 72

The end of each class interval would be

1070.5 + 72 = 1142.5

1142.5 + 72 = 1214.5

1214.5 + 72 = 1286.5

1286.5 + 72 = 1358.5

1358.5 + 72 = 1430.5

The frequency for the fifth class, that is between 1358.5 to 1430.5 would be 2

Answer:

(D)9.5 Units

Step-by-step explanation:

We have two chords CD and AB intersecting at E.

Using the theorem of intersecting chords

AE X EB =CE X ED

AB=AE+EB

16=10+EB

EB=16-10=6

Therefore:

AE X EB =CE X ED

10 X 6 = 4 X ED

ED =60/4 =15

Therefore:

CD=CE+ED

=4+15

CD=19

Recall that CD is a diameter of the circle and;

Radius =Diameter/2

Therefore, radius of the circle =19/2 =9.5 Units

Answer:

The substance's half-life is 6.4 days

Step-by-step explanation:

Recall that the half life of a substance is given by the time it takes for the substance to reduce to half of its initial amount. So in this case, where they give you the constant k (0.1088) in the exponential form:

[tex]N=N_0\,e^{-k\,*\,t}[/tex]

we can replace k by its value, and solve for the time "t" needed for the initial amount [tex]N_0[/tex] to reduce to half of its value ([tex]N_0/2[/tex]). Since the unknown resides in the exponent, to solve the equation we need to apply the natural logarithm:

[tex]N=N_0\,e^{-k\,*\,t}\\\frac{N_0}{2} =N_0\,e^{-0.1088\,*\,t}\\\frac{N_0}{2\,*N_0} =e^{-0.1088\,*\,t}\\\frac{1}{2} =e^{-0.1088\,*\,t}\\ln(\frac{1}{2} )=-0.1088\,t\\t=\frac{ln(\frac{1}{2} )}{-0.1088} \\t=6.37\,\,days[/tex]

which rounded to the nearest tenth is: 6.4 days

Answer:

6.4

Step-by-step explanation:

I did it on the same site and got it correct

Answer:

8 + 15i

Step-by-step explanation:

(-2 + 3i) + 2(5 + 6i) =

= -2 + 3i + 10 + 12i

= 8 + 15i

Answer:

(0,34)

Step-by-step explanation:

I graphed the coordinates of the table on the graph below to find the y-intercept.

Step-by-step explanation:

-23d + 81 < - 98d + 1

81 - 1 < - 98d + 23d

80 < - 75d

80/ - 75 < d

10/ - 3 < d

Answer:

The event of picking a number from 1 to 3 consists of:

Pick number 1

Pick number 2

Pick number 3

The event of choosing red or white card consists of:

Choose a red card

Choose a white card

=> The sample space for picking a number from 1 to 3 and choosing red or white card:

Pick number 1 and choose a red card

Pick number 1 and choose a white card

Pick number 2 and choose a red card

Pick number 2 and choose a white card

Pick number 3 and choose a red card

Pick number 3 and choose a white card

Hope this helps!

:)

Answer:

10.03% probability of getting a cup weighing more than 8.64oz

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 8, \sigma = 0.5[/tex]

What is the probability of getting a cup weighing more than 8.64oz

This is the 1 subtracted by the pvalue of Z when X = 8.64. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{8.64 - 8}{0.5}[/tex]

[tex]Z = 1.28[/tex]

[tex]Z = 1.28[/tex] has a pvalue of 0.8997

1 - 0.8997 = 0.1003

10.03% probability of getting a cup weighing more than 8.64oz

Answer:

D. F(x) = 2(x-3)^2 + 3

Step-by-step explanation:

We are told that the graph of G(x) = x^2, which is a parabola centered at (0, 0)

We are also told that the graph of the function F(x) resembles the graph of the function G(x) but has been shifted and stretched.

The graph of F(x) shown is facing up, so we know that it is multiplied by a positive number. This means we can eliminate A and C because they are both multiplied by -2.

Our two equations left are:

 B. F(x) = 2(x+3)^2 + 3

 D. F(x) = 2(x-3)^2 + 3

Well, we can see that the base of our parabola is (3, 3), so let's plug in the x value, 3, and see which equation gives us a y-value of 3.

y = 2(3+3)^2 + 3 =

2(6)^2 + 3 =

2·36 + 3 =

72 + 3 =

75

That one didn't give us a y value of 3.

y = 2(3-3)^2 + 3 =

2(0)^2 + 3 =

2·0 + 3 =

0 + 3 =

3

This equation gives us an x-value of 3 and a y-value of 3, which is what we wanted, so our answer is:

D. F(x) = 2(x-3)^2 + 3

Hopefully this helps you to understand parabolas better.

Answer:

both rotational and reflectional

Answer: both rotational and reflectional

Step-by-step explanation: a p e x

Answer:

The real number 'a' = 32

The real number 'b' = 0

Step-by-step explanation:

Product of a number of a number and its conjugate = a + bi

The number is = -4 + 4i

Conjugate of this number is = -4 - 4i

Product of the number and it's conjugate

= (-4 + 4i)(-4 - 4i)

= -4(-4 - 4i) + 4i(-4 - 4i) [By distributive property]

= 16 + 16i - 16i - 16i²

= 16 - 16(-1)

= 16 + 16

= 32

a + bi = 32 + (0)i

By comparing both the sides,

a = 32

b = 0

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that [tex]p = 0.5[/tex]

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

[tex]P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039[/tex]

[tex]P(X = 1) = C_{8,1}.(0.5)^{1}.(0.5)^{7} = 0.0313[/tex]

[tex]P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094[/tex]

[tex]P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188[/tex]

[tex]P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734[/tex]

[tex]P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188[/tex]

[tex]P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0039 + 0.0313 + 0.1094 + 0.2188 + 0.2734 + 0.2188 = 0.8556[/tex]

85.56% probability that less than 6 of them have a high school diploma

Answer:

Yeah btw is this a question?

Answer:

[tex]74.8m[/tex]

Step-by-step explanation:

[tex]A=a^2\\P=4a\\P=4\sqrt{A} \\=4*\sqrt{349.69} \\=74.8m[/tex]

Answer:

[tex]n = - 3[/tex]

Second answer is correct

Step-by-step explanation:

[tex]11(n - 1) + 35 = 3n \\ 11n - 11 + 35 = 3n \\ 11n - 3n = 11 - 35 \\ 8n = - 24 \\ \frac{8n}{8} = \frac{ - 24}{8} \\ n = - 3[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

To solve a polynomial inequality, we factor the polynomial into irreducible factors and find all the real _zeros_ polynomial. Then we find the intervals determined by the real _zeros and use test points in each interval to find the_ sign of the polynomial on that interval.

If P(x) = x(x+2)(x-1)

And P(x) ≥ 0

We see that P(x) ≥ 0 on the intervals (-2, 0) and (1, ∞).

Step-by-step explanation:

The complete question is attached to this solution

To solve inequality of a polynomial, we first obtain the solutions of the polynomial. The solutions of the polynomial are called the zeros of the polynomial.

If P(x) = x(x+2)(x-1)

The solutions of this polynomial, that is the zeros of this polynomial are 0, -2 and 1.

To now solve the inequality that arises when

P(x) ≥ 0

We redraw the table and examine the intervals

The intervals to be examined as obtained from the zeros include (-∞, -2), (-2, 0), (0, 1) and (1, ∞)

Sign of | x<-2 | -2<x<0 | 0<x<1 | x>1

x               | -ve | -ve | +ve | +ve

(x + 2)       | -ve | +ve | +ve | +ve

(x - 1)         | -ve | -ve | -ve | +ve

x(x+2)(x-1) | -ve | +ve | -ve | +ve

The intervals that satisfy the polynomial inequality P(x) = x(x+2)(x-1) ≥ 0 include

(-2, 0) and (1, ∞)

Hope this Helps!!!

Answer:

So the answer is going to be B. AKA 22.5

Step-by-step explanation:

I took the test on ed and got this answer right! hth (hope this helps)

Answer:

B, second option, 22.5

Step-by-step explanation:

1.)because

2.)i'm

3.)kinda

4.)smart

answer=22.5:))))))))

Answer:

0.004% probability the student will pass

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

In this problem, we have that:

[tex]n = 50, p = \frac{1}{4} = 0.25[/tex]

So

[tex]\mu = E(X) = np = 50*0.25 = 12.5[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{50*0.25*0.75} = 3.06[/tex]

If a student guesses on every question, what is the probability the student will pass

Using continuity correction, this is [tex]P(X \geq 25 - 0.5) = P(X \geq 24.5)[/tex], which is 1 subtracted by the pvalue of Z when X = 24.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{24.5 - 12.5}{3.06}[/tex]

[tex]Z = 3.92[/tex]

[tex]Z = 3.92[/tex] has a pvalue of 0.99996

1 - 0.99996 = 0.00004

0.004% probability the student will pass

Answer:

2±√13

Step-by-step explanation:

9/x=x-4

x² -4x - 9=0

x² -4x +4- 13=0

(x -2)²=13

x-2= ±√13

x= 2±√13

Answer: The answers are in the steps hopes it helps.

Step-by-step explanation:

40% * x = 23   convert 40% to a decimal

0.4 * x = 23     multiply 0.4 is by x

0.4x = 23    divide both sides by 0.4

x= 57.5  

Check:  

57.5 * 40% = ?

57.5 * 0.4 = 23

Answer:

X=4

Step-by-step explanation:

1. Distribute 3 to 2x and -9

2. You will get "6x-27 = -3"

3. Next, add 27 to -27 and -3

4. You will get "6x = 24"

5. Then, you will divide 6x and 24 by 6

6. You will get "6x/6 = 24/6"

7. The 6 will cancel the 6 in 6x.

8. Then, you will divide 24 and 6. which will give you the answer of 4

9. Add the "X=..." and...

10. You will get the answer of "X=4"