Enter the electron configuration for I+ using noble gas shorthand notation.
In the first box enter the noble gas (notice the brackets). In the following boxes enter the number that goes in front of the orbital followed by the superscript.
For example, the electron configuration for sulfur is: [Ne]3s2 3p4
so the first box would have Ne in it followed by 3, then 2, then 3 then 4.
If you do not need an orbital, just enter 0 (zero) in the boxes for the coefficient and superscript.
[ ] s f d p
Find the element in the periodic table and count over
to the right the number of negative charges on your anion.
This element has the same electron configuration as your anion.
Which noble gas precedes the element? Knowing the s, p, d, and f blocks
of elements in the periodic table, deduce the the electron configuration
of the element from the preceding noble gas. Remember that the
1p 1d, 2d, 1f, 2f, and 3f orbitals are forbidden energy levels (they do not exist).

Answer: 90.04°C

Explanation: Calorimeter is a device measures the amount of heat of a chemical or physical process. An ideal calorimeter is one that is well-insulated, i.e., prevent the transfer  of heat between the calorimeter and its surroundings. So, the net heat change inside the calorimeter is zero:

[tex]q_{1}+q_{2}=0[/tex]

Rearraging, it can be written as

[tex]q_{1}=-q_{2}[/tex]

showing that the heat gained by Substance 1 is equal to the energy lost by Substance 2.

In our case, water is gaining heat, because its temperature has risen and so, brass is losing energy:

[tex]q_{water}=-q_{brass}[/tex]

Calculating:

[tex]m_{w}.c_{w}.\Delta T=-[m_{b}.c_{b}.\Delta T][/tex]

[tex]100.4.18.(18.4-15)=-[52.9.0.375.(18.4-T)][/tex]

Note: final temperature is the same as the substances are in thermal equilibrium.

Solving:

418(3.4)= - 365.01 + 19.8375T

19.8375T = 1786.21

T = 90.04

The initial temperature for the sample of brass was 90.04°.

Answer:

The limiting reagent is the reactant that is used up completely. This stops the reaction and no further products are made. ... The limiting reagent can also be derived by comparing the amount of products that can be formed from each reactant.

Answer:

The limiting reagent is the reactant that is used up completely. This stops the reaction and no further products are made. ... The limiting reagent can also be derived by comparing the amount of products that can be formed from each reactant.

Explanation:

Disclaimer not my answer I looked it up

Answer:

1

Explanation seems right

The magma and sediments formed in the great plains are came from the rocks of the rocky mountains. Therefore, claim 1 is correct.

Sedimentation is the geographical process of accumulation or deposition of the minerals and organic particles from the earth's surface is called sedimentation. This process results in the formation of sedimentary rocks.

Weathering or erosion of rocks by wind, water or other chemicals leads to the geological debris which then move to other places  deposits somewhere.

Rocks in the rocky mountains undergo erosion and the mass movements created by wind or water leads to the sedimentation of these rocky solids to other places. The rocks in the Great planes are reached there by the mass movement of the rocks of rocky mountains. Hence, claim 1 is correct.

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Answer:

CaCl2

Explanation:

Cacl2 would have greatest freezing point depression because in this case the vant Hoff factor is 2

More will be the value of vant Hoff factor more will be the depression in freezing point when concentration of all electrolyte is same

Answer:

78.4

Explanation:

Answer:

RCl

Explanation:

Here, let us take ROH to represent the formula of our alcohol where R is the alkyl group.

The reaction of ROH with  tosyl chloride yields an ester called a tosylate. It is the O-H bond not the C-O bond that is cleaved when the tosylate is formed.

Tosylates are good leaving groups, attack of a nucleophile such as Cl^- completes the mechanism leading to the formation of RCl.

Answer:

119 g.

Explanation:

Answer:

a. During incomplete metamorphosis, the nymph molts its exoskeleton. During complete metamorphosis, the larva forms a chrysalis or cocoon.

Explanation:

The first stage of incomplete metamorphosis is the egg. During this time, the insect will hatch into a form called a nymph. The nymph is basically a small version of the adult insect. This is very similar to how a child looks like his or her parents.

The correct statement that describes components of complete and incomplete metamorphosis is: d. Incomplete and complete metamorphosis both have three major stages.

Metamorphosis is a biological process that some animals undergo to transform from one developmental stage to another, typically from a juvenile form to an adult form. This process involves a series of physical and physiological changes that can be dramatic and even complete.

Incomplete metamorphosis consists of three stages: egg, nymph, and adult. The nymph hatches from the egg and looks similar to the adult but lacks wings and reproductive organs. The nymph molts its exoskeleton several times and gradually develops into an adult.

Complete metamorphosis also consists of three stages: egg, larva, pupa, and adult. The larva hatches from the egg and looks completely different from the adult, often worm-like in appearance. The larva undergoes a series of molts and grows larger, then forms a pupa or chrysalis. Inside the pupa or chrysalis, the larva undergoes a complete transformation and emerges as an adult.

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Answer: 190.9K

Explanation:

5.6(14) = 5(.0821)T  or  (5.6*14)/(5(.0821))

78.4 = 0.4105T

190.9K = T

Answer:

0.156 M

Explanation:

The neutralization reaction between hydrobromic acid (HBr) and sodium hydroxide (NaOH) is the following:

HBr(ac) + NaOH(aq) → NaBr(aq) + H₂O(l)

As we can see, 1 mol of HBr reacts with 1 mol NaOH. During a titration, at the equivalence point, the number of moles of NaOH added reacts completely with the number of moles of HBr:

moles of NaOH = moles of HBr

The moles of each reactant is calculated as the product of the molarity (M) and the volume (V):

M(NaOH) x V(NaOH) = M(HBr) x V(HBr)

We have the following data:

base: V(NaOH) = 13.5 mL

acid: M(HBr) = 0.104 M;  V(HBr) = 20.2 mL

Thus, we calculate M(NaOH) from the equivalent point equation:

M(NaOH) = (M(HBr) x V(HBr))/(V(NaOH) = (0.104 M x 20.2 mL)/(13.5 mL) = 0.1556 M ≅ 0.156 M

Answer:

240 g/mol

Explanation:

We'll begin by writing the chemical formula of Disodium sulfide nonahydrate. This is illustrated below:

The molecular formula of disodium sulfide nonahydrate is Na₂S.9H₂O

Finally, we shall determine the molar mass of disodium sulfide nonahydrate, Na₂S.9H₂O. This can be obtained by adding the individual molar mass of the element present in the compound as illustrated below:

Molar mass of Na₂S.9H₂O = (23×2) + 32 + 9[(2×1) + 16]

= 46 + 32 + 9[2 + 16]

= 46 + 32 + 9[18]

= 46 + 32 + 162

= 240 g/mol

Thus, the molar mass of disodium sulfide nonahydrate, Na₂S.9H₂O is 240 g/mol

Answer:

Turning off the water while brushing teeth, watching shower time.

Explanation:

Answer:

Take shorter showers.

Install water-saving shower heads or flow restrictors.

Turn off the water while brushing your teeth.

Turn off the water while shaving.

Explanation:

have a nice day

Answer:

neutral and current

Explanation:

sorry if im wrong ;(

This question is incomplete, the complete question is;

The enthalpy change for the reaction between two molecules of carbon oxysulfide (COS) to form one molecule of CO₂ and one molecule of CS₂, as shown below, is -3.2 x 10⁻²⁴ kJ per molecule of COS.

The bond energy for the C-S bond in C=S has been determined to be 552 kJ/mol.

What is the apparent bond energy of a carbon-sulfur bond in COS?

NOTE: A C=O bond adjacent to another double bond is not the same as a C=O bond that is not adjacent to another double bond.  

Answer:

The apparent bond energy of a carbon–sulfur bond is 550.1 kJ/mole

Explanation:

Given the data in the question and the figure 8.122 in the image below;

the given reaction can be written as follows;

2COS -----→ CO₂ + CS₂

Δ[tex]H_{rxn}[/tex] = ∑ Bond Energy ( reactants) - ∑ Bond Energy (products)

= [ (2 × C=O) + (2 × C=S) ] - [ (2 × C=O) + ( 2 × C=S) ]

we know that;

Δ[tex]H_{rxn}[/tex]  = -3.2 x 10⁻²⁴ kJ per molecule

= -3.2 x 10⁻²⁴ kJ × 2 × 6.023 × 10²³ kJ/mole

= -3.85 kJ/mole

Hence;

-3.85 kJ/mole = (2 × C=S)[tex]_{reactant}[/tex] - ( 2 × C=S)[tex]_{product}[/tex]

-3.85 kJ/mole = (2 × C=S)[tex]_{reactant}[/tex] - ( 2 × 552 kJ/mole)

(2 × C=S)[tex]_{reactant}[/tex] = -3.85 kJ/mole + 1104 kJ /mole

(2 × C=S)[tex]_{reactant}[/tex]  = 1100.15 kJ/mole

2 × ( C=S)[tex]_{reactant}[/tex] = 1100.15 kJ/mole

( C=S)[tex]_{reactant}[/tex] = 1100.15 kJ/mole / 2

( C=S)[tex]_{reactant}[/tex] = 550.1 kJ/mole

Therefore, the apparent bond energy of a carbon–sulfur bond is 550.1 kJ/mole

The apparent bond energy of a carbon-sulfur bond in COS is equal to 550.08 kJ/mol.

Given the following data:

Scientific data:

To determine the apparent bond energy of a carbon-sulfur bond in COS:

First of all, we would write a balanced chemical equation for the chemical reaction as follows:

                                   [tex]2COS \rightarrow CO_2 + CS_2[/tex]

The enthalpy change of two (2) moles of COS is:

[tex]\Delta H_{rxn} = -3.2 \times 10^{-24}\times 2 \times 6.02 \times 10^{23}\\\\\Delta H_{rxn} =-3.85\;kJ/mol.[/tex]

Mathematically, the enthalpy change of a chemical reaction is given by this equation:

[tex]\Delta H_{rxn} = \sum Bond\;Energy_{(reactansts)} - \sum Bond\;Energy_{(products)}\\\\\Delta H_{rxn} = [(2\times C=O)+ (2\times C=S)]- [(2\times C=O)+ (2\times C=S)][/tex]

Substituting the parameters into the equation, we have;

[tex]-3.85 = (2\times C=S)- [2\times 552]\\\\(2\times C=S)=1104-3.85\\\\(2\times C=S)=1100.15\\\\(C=S)=\frac{1100.15}{2} \\\\(C=S)=550.08\;kJ/mol[/tex]

Therefore, the apparent bond energy of a carbon-sulfur bond in COS is equal to 550.08 kJ/mol.

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Complete Question:

The enthalpy change for the reaction between two molecules of carbon oxysulfide (COS) to form one molecule of [tex]CO_2[/tex] and one molecule of [tex]CS_2[/tex], as shown below, is [tex]-3.2 \times 10^{-24}[/tex] kJ per molecule of COS.  The bond energy for the C-S bond in C=S has been determined to be 552 kJ/mol. What is the apparent bond energy of a carbon-sulfur bond in COS?

[Note: A C=O bond adjacent to another double bond is not the same as a C=O bond that is not adjacent to another double bond.]

Answer:

Follows are the solution to this question:

Explanation:

Please find the complete solution in the attached file.

Answer:

table A

Explanation:

its table A because it requires less force push. the less force used the less friction there is.

the less friction there is the more smooth a surface is.

Answer:

ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹

Explanation:

The equation for the reaction is given as;

C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)

In order to determine the entropy change, we have to use the entropy valuues for the species in the reaction. This is given as;

S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹

S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹

S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹

S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹

The unit of entropy is J K⁻¹ mol⁻¹

Entropy change for the reaction is given as;

ΔS°reaction = ΔS°product - ΔS°reactant

ΔS°reaction = [(4 * 188.8) + (3 * 213.7)] - [269.9 + (5 * 205.1)]

ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹

The entropy change for the combustion of gaseous propane, under standard state conditions  100.9 J K⁻¹.

The equation for the combustion of gaseous propane is given as follows:-

C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)

In order to determine the entropy change, we have to use the entropy values for the species in the reaction. This is as follows:-

S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹

S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹

S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹

S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹

The unit of entropy is J K⁻¹ mol⁻¹

Entropy change for the reaction is given as;

ΔS°reaction =nproduct ΔS°product - nreactantΔS°reactant

ΔS°reaction = [(4mol * 188.8 J K⁻¹ mol⁻¹) + (3 mol * 213.7 J K⁻¹ mol⁻¹)] - [(1 mol*269.9J K⁻¹ mol⁻¹ )+ (5 mol* 205.1  J K⁻¹ mol⁻¹)]

ΔS°reaction = 100.9 J K⁻¹

So, the entropy change for the combustion of gaseous propane is 100.9 J K⁻¹ .

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Answer:

23.6 moles

Explanation:

From the question given above, the following data were obtained:

Mass of air = 3.6 Kg

Mass percentage of O₂ = 21%

Number of mole of O₂ =?

Next, we shall convert 3.6 Kg of air to grams (g). This can be obtained as follow:

1 kg = 1000 g

Therefore,

3.6 Kg = 3.6 Kg × 1000 / 1 kg

3.6 Kg = 3600 g

Next, we shall determine the mass of O₂ in the air. This can be obtained as follow:

Mass of air = 3600 g

Mass percentage of O₂ = 21%

Mass of O₂ =?

Mass of O₂ = 21% × 3600

Mass of O₂ = 21/100 × 3600

Mass of O₂ = 756 g

Finally, we shall determine the number of mole of O₂ in the sample of air. This can be obtained as follow:

Mass of O₂ = 756 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Number of mole of O₂ =?

Mole = mass /Molar mass

Number of mole of O₂ = 756 / 32

Number of mole of O₂ = 23.6 moles

Thus, the number of mole of O₂ in the

sample of air is 23.6 moles

Answer:

Ca, Zn, Ni, Al, Fe

Explanation:

The activity series is an arrangement of metals in order of decreasing reactivity.

Metals that are high up in the activity series are very reactive. They displace metals that are lower in the activity series from an aqueous solution of their salts.

The metals; Ca, Zn, Ni, Al, Fe are all above Pb in the activity series hence they will cause Pb2+ ions to come out of solution as solid Pb.

A more reactive metal displaces the less reactive metals in the solution.  Ca, Al, Zn, and Fe can be accomplished to take out the [tex]\bold{ Pb^2^+}[/tex] from the solution as solid Pb.

Metal displacement Reaction:

In this type of reaction a more reactive metal displaces the less reactive metals in the solution.

The metal reactivity series

Ca > Al > Zn > Fe > Ni > Pb > Ag > Au

The lead ( Pb) is less reactive than the Ca, Al, Zn, and Fe.

Therefore,  Ca, Al, Zn, and Fe can be accomplished to take out the [tex]\bold{ Pb^2^+}[/tex] from the solution as solid Pb.

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Answer:

B, C, D, E

Explanation:

According to Henry's law, as the pressure is increased, the solubility of a given gas increases. So, solubility is directly proportional to pressure.

Thus, the following statements are correct:

B. More gas molecules are soluble as pressure is increased.

Is correct because as the pressure is increased, the solubility increases.

C. The solubility of a gas decreases with a decrease in pressure.

Is correct because solubility and pressure are directly proportional: if the pressure is decreased, the solubility will be decreased.

D. The solubility of nitrogen gas at 2.00 atm is twice the solubility of the gas at 1.00 atm.

Is correct because 2.00 atm is twice 1.00 atm, so if the pressure is increased twice, the solubility is increased twice.

E. The concentration of gas particles in the solution is higher at 4.25 atm than at 1.00 atm.

Is correct because 4.25 atm>1.00 atm (the higher the pressure, the higher the solubility, and therefore the concentration of gas particles in solution).

The remaining options (A, G) are incorrect. They contradict Henry's law.

Answer:

665.22

Explanation:

you see wich numbers after the decimal points have the least numbers, the one with the least u have to round your answer to that

After performing the required mathematical operation (addition), the answer is equal to 665.22.

In Mathematics, significant figures can be defined as the number of single digits or numerical values in the coefficient of a mathematical expression that are important and meaningful.

Since "653.12" has two (2) significant figures, we must ensure that 12.10247 also has two (2) significant figures as follows:

12.10247 to 2 S.F = 12.10.

Next, we would perform the required mathematical operation (addition):

653.12 + 12.10 = 665.22.

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Answer:

Future tense.

Explanation:

The different tenses in grammar are used to denote the time or condition of when the action occurs. This means that tenses tell us the form or condition of the verbs.

The present tense tells us about a present scene while the past tense tells us about an action that happened in the past. Likewise, the future tense tells us about an event that will happen in the future. This means that future tenses are used to describe events that have not taken place, and are yet to happen.

Answer:

il got this from goglle

Explanation:

hope it helps

Answer:

2. A 3.C

Explanation:

Answer:

any of these

Explanation:

kinetic energy: kinetic is motion, or released energy

Potential energy: porential energy is the energy of position or stored energy.

Thermal energy: is heat energy, it is stored energy that creats heat.

Answer:

See explanation and image attached

Explanation:

The mechanism for both the hydroboration of 2-methyl-1-pentene and acid-catalyzed hydration are shown i the image attached to this answer.

The both processes involve addition reaction. Hydroboration  is similar to hydration but the orientation of addition is anti - Markovnikov in nature.

The acid-catalyzed hydration of  2-methyl-1-pentene yields a minor product and a major product. The major product is  an accordance with Markovnikov  rule as shown by the reaction mechanism. The minor product is anti - Markovnikov.

Answer:

ex.1

1.The water in the test tube expands as it is heated. There is only one direction to expand in, the glass tube. This glass tube is narrow so that a small change in volume will result in a considerable change in height; your signal is amplified. This is the same phenomenon as in thermometers with a glass bulb on the lower end.

2. there will be a thermal expansion will happened.

Answer:

Volume = 19.68 ml

Explanation:

The equation of the reaction is given as;

HNO3 + KOH ---> KNO3 + H2O

1 mol of HNO3 reacts 1 mol of KOH

Converting 0.276 g of KOH to mol;

Number of moles = Mass / Molar mass

Number of moles = 0.276g / 56.1056 g/mol

Number of moles = 0.00492

Since the mole relationship is 1 = 1;

This means 0.00492 mol of HNO3 reacts with 0.00492 mol of KOH

The relationship between molarity and volume id given as;

Molarity = Number of moles / Volume

Volume = Number of moles / Molarity = 0.00492 mol / 0.250 M

Volume = 0.01968 L

Volume = 19.68 ml