Enter the amplitude of the function. f(x)=2sin x

If Richards Corporation uses the FIFO method of process costing. The  equivalent units of materials is 294,000.

Using this formula

Equivalent unit of material (FIFO) =[(Beginning inventory×Percentage complete)+Units started and complete+ (Ending inventory× Percentage complete as to materials)]

Let plug in the formula

Equivalent unit of material (FIFO) = [80,000×40%+250,000+30,000×40%]

Equivalent unit of material (FIFO) = 32,000+250,000+12,000

Equivalent unit of material (FIFO) = 294,000

Therefore the equivalent units of materials is 294,000.

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Answer:

2 5/7 5/7 -1/7, -5/7, 1 2/7, -2 2/7, -1 5/7

Answer: f(-3)=g(-3)

Step-by-step explanation:

The graphs intersect at x = -3.

The correct option is f(-3) = g(-3).

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Given that two lines are intersecting at point (-3, -4)

Therefore the system of equations of these two have a solution at (-3, -4)

So, if taking the lines as function,

We have f(x) and g(x),

so both of them are intersecting at (-3, -4) so the range when the domain is -3 will be equal.

Hence the correct option is f(-3) = g(-3).

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Answer:

105.6397

ROUNDED ANSWER:

105

The quadratic equation in standard form is:

[tex]y = 2x^2 - 8x + 6[/tex]

Here we have the quadratic equation:

[tex]y = 2*(x - 2)^2 - 2[/tex]

Here we need to expand the right side, remember:

[tex](a + b)^2 = a^2 + 2ab + b^2[/tex]

Using that, we get:

[tex]y = 2*(x - 2)^2 - 2 = 2*(x^2 - 4x + 4) - 2\\\\y = 2x^2 - 8x + 8 - 2\\\\y = 2x^2 - 8x + 6[/tex]

This is the quadratic equation in standard form.

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Answer:

y = -5

Step-by-step explanation:

Isolate y:

-3x + 9y = -57

9y = -57 + 3x

y = (-57/9) + (3/9)x

Substitute for x:

y = (-57/9) + (3/9)(4)

y = (-57/9) + (12/9)

y = (-45/9)

y = -5

Answer:

[tex]\mathsf {y = -5}[/tex]

Step-by-step explanation:

[tex]\textsf {Given :}\\\textsf {-3x + 9y = -57}[/tex]

[tex]\textsf {Divide throughout by 3 :}[/tex]

[tex]\mathsf {\frac{1}{3} \times (-3x + 9y) = \frac{1}{3} \times -57}[/tex]

[tex]\mathsf {-x + 3y = -19}[/tex]

[tex]\textsf {Substitute x = 4 :}[/tex]

[tex]\mathsf {-(4) + 3y = -19}[/tex]

[tex]\mathsf {3y = -15}[/tex]

[tex]\textsf {Divide by 3 on both sides :}[/tex]

[tex]\mathsf {\frac{3y}{3} = \frac{-15}{3} }[/tex]

[tex]\mathsf {y = -5}[/tex]

Answer:

the answer is 24

Step-by-step explanation:

6x - 48 = 4x

6x - 4x - 48 = 0

2x - 48 = 0

2x = 0 + 48

2x = 48

x = 24

The Sales Volume Variance of the car manufacturer for the twelve-month period is $96,000.

The sales volume variance measures the financial impact of not meeting or exceeding the budgeted sales for a period.

It can be computed by finding the difference between actual and budgeted sales quantities and then multiplied by the unit selling price.

Budgeted sales units = 50,000

Actual sales units = 48,000

Sales price per unit = $60

Actual sales revenue = $2,904,000

Budgeted sales revenue = $3,000,000 ($60 x 50,000)

Sales volume variance = $96,000 ($3,000,000 - $2,904,000)

Thus, the Sales Volume Variance is $96,000.

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The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

Parameters

[tex]$x^{2}=4 p y$[/tex]

[tex]$y=h$[/tex]

[tex]\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\[/tex]

Generally, the equation for the Area is mathematically given as

[tex]& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\[/tex]

[tex]&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

In conclusion,  the equation for the Area is

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

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The number of picture books does Annette have is 76 books.

Given the ratio of picture books , encyclopedias and fairy tales books is 3:4:5 and she have half of her encyclopedias to her brother and  he gave her 5 books of fairytales

We need to find the number of picture books does she have

According to the statement the total number of books does Annette have is

3k+4k+5k = 12k

Where k is total number of books

Now , Picture book she have = 3/12k = 1/4k

Encyclopedia she have = 4/12k = 1/3k

Fairy tale she have = 5/12k

Here,

Encyclopedia +14 = Fairy tale

Substituting the values of Encyclopedia and Fairy tale

(1/3 -1/2)k +14 = (5/12k -5 )

Therefore.

(1/6k+14) = (5k/12-5)

Therefore,

14+5 = 5k/12 - k/6

Therefore,

19 = 3k/12

19*4=k

76 = k

Here k = 76 books

Hence the total number of picture books does she have is 76

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Answer:

X = 14

Let the unknown no. be X

mean= sum of all no. / no. of terms

17 = 15 + 17 + 20 + 22 + X+ X / 6

17 * 6 = 74 + 2X

102 - 74 = 2X

28 = 2X

28/2 = X

14= X

The correct answer is A.

Step - by - step answer:

Mario will travel a distance equal to 1 circumference of the wheel for each complete revolution of the wheel.

Circumference of Mario's wheel, C = πD, where D is the diameter of the circle.

Hence, C = 26π inches

Speed = Distance / Time

Distance for 200 revolutions in ft = 26π x 200 x 1/12

Time in sec = 60

So, speed =  (26π x 200)/(12 x 60)

= 65π/9

=22.69 is the average speed.

P.s: Answer is copied from https://www.myactguide.com/math/mario-was-riding-a-bicycle-with-wheels-26-inches-in-diameter

Let x be multiple-choice questions
Let y be short-answer questions

x + y = 28

3x + 5y = 100

The difference in the given functions is 2x^3 + 6x^2 -8x + 1

Given the following function a shown

f(x)= 2x^3 + 6x^2 -5x - 3

g(x)= 3x-4

Take the difference

(f-g)(x) = f(x) - g(x)

Substitute

(f-g)(x)  = 2x^3 + 6x^2 -5x - 3 - (3x - 4)

Expand

(f-g)(x)  = 2x^3 + 6x^2 -5x - 3 - 3x + 4

(f-g)(x) = 2x^3 + 6x^2 -8x + 1

Hence the difference in the given functions is 2x^3 + 6x^2 -8x + 1

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The amount in the new checking account is 600 dollars

The operation (5 α 3) + (7 α 5) is 46.

She had 1000 dollars in her checking account. she had a loan of 800 dollars to pay.

After paying her loan form her checking account the balance of the loan reduce to half.

Therefore, she paid 800 / 2 = 400 dollars for her loan

Hence,

Her new checking account = 1000 - 400 = 600 dollars

a α b = ab - a + b

Therefore,

(5 α 3) + (7 α 5)

(5 α 3) = 5(3) - 5 + 3 = 13

(7 α 5) = 7(5) - 7 + 5 = 33

Therefore,

(5 α 3) + (7 α 5) = 13 + 33 = 46

Note: I can't use the at symbol because it is a swear word.

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Answer:

Let first check the coordinates of the points

A = (1 , -6)

B = (2 , -4)

C = (2, -2)

D = (4, -2)

E = ( 6, 0)

Option 4 is correct..

Explanation -

to find the coordinates we have to find the distance of that point from x Axis and then y axis. from origin.

The answer to this question is (A) left.

Answer:

The very last one is a function

Step-by-step explanation:

The last one is a function because there are no y values that repeat. For example, If the points on one graph are like this; (1, 3) (2, 3); then it cannot be a function, the y values cannot repeat if it is a function.

To make things easier, just try to imagine vertical drawing lines through each point in every graph, if this imaginary vertical line passes more than one point in any graph, then that graph is not a function.

I hope this helps!! :D

Answer:

The last graph represents a function.

Explanation:

A function cannot be one-to-many, i.e., one value of x cannot produce multiple values of y.

In the first graph, when x = 1, y = 3 and y= -2, so it is not a function.

In the second graph, when x = 2, y = 2 and y = -2, so it's not a function.

In the third graph, when x = -3, y = 2 and y = -2, so it's not a function.

∴ In all the graphs except the last, single values of x give multiple values of y on the graph, so they are not functions.

Answer:

y = (3/2)x - (1/2)

Step-by-step explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m" (3/2). To find the value of "b", you should plug "m" into the equation in addition to the "x" and "y" values from the given point (1,1)

(1,1) ----> x = 1, y = 1

m = 3/2

y = mx + b                                <----- Slope-intercept form

y = (3/2)x + b                            <----- Plug (3/2) into "m"

1 = (3/2)(1) + b                           <----- Plug values into "x" and "y" from point

1 = (3/2) + b                              <----- Multiply (3/2) and 1

(2/2) = (3/2) + b                        <----- Change 1 into common denominator

(-1/2) = b                                  <----- Subtract (3/2) from both sides

Because you now have values for both variables, you can construct your final equation.

y = (3/2)x - (1/2)

(a) X ≈ N (0.10 , 0.02²)

(b) The probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.

(c) The 60th percentile is 11%.

A. X ~ N( , )  

B. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11%.

C. Find the 60th percentile for this distribution.

According to the question,

The random variable X is defined as the THC content for a bag of marijuana that is sold on the street.

(a)The random variable X is Normally distributed with mean, μ = 0.10 and standard deviation, σ = 0.02.

Therefore, X ≈ N (0.10 , 0.02²)

(b) The value of P (X > 0.11) as follows:

P (X > o.11_ = P(X -μ/a > [tex]\frac{0.11-0.10}{0.02} \\[/tex])

= P(Z > 0.50)

= 1 -P (Z <0.50)

= 1- 0.69146

= 0.30854 ≈ 0.31

Hence,

the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.

(c)Let x represent the 60th percentile value.

Then, P (X < x) = 0.60.

⇒ P (Z < z) = 0.60

The value of z is,

z = 0.26.

Now put the value of x as follows:

z = x - μσ

0.26 = x - 0.100.02

x = 0.10+ ( 0.26 x 0.02)

x = 0.1052

x ≈ 0.11

Therefore,

The 60th percentile is 11%

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The quotient [tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex] is [tex]x^3 + 2x - 3[/tex]

The quotient can be represented as:

[tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex]

Start by expanding the dividend

[tex]x^5 + 2x^3 - 5x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex]

Rewrite as:

[tex]x^5 + 2x^3 - 3x^2 - 5x^3 - 10x + 15 \div x^2 - 5[/tex]

Factorize the dividend

[tex]x^2(x^3 + 2x - 3) - 5(x^3 + 2x - 3) \div x^2 - 5[/tex]

Factor out x^3 + 2x - 3

[tex](x^2- 5)(x^3 + 2x - 3) \div x^2 - 5[/tex]

Cancel out the common factor

[tex]x^3 + 2x - 3[/tex]

Hence, the quotient [tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex] is [tex]x^3 + 2x - 3[/tex]

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Answer: x3 + 2x – 3

Step-by-step explanation:

The y-coordinate of the other endpoint is 10 units.

The given coordinates are H (-5, 2) and G (–9, –6).

We need to find the y-coordinate of the other endpoint.

The mid-point formula is  [tex](x, y)=(\frac{x_{1}+x_{2} }{2} , \frac{y_{1}+y_{2} }{2})[/tex]

Now, [tex](-5, 2)=(\frac{x_{1} +(-9)}{2} , \frac{y_{1} +(-6)}{2})[/tex]

⇒[tex]2=\frac{y_{1}-6 }{2}[/tex]

⇒[tex]4=y_{1}-6[/tex]

⇒[tex]y_{1}=10[/tex]

Therefore, the y-coordinate of the other endpoint is 10 units.

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The number of girls are significantly low.

Probability is the study of likeliness of an event to happen.

It is given that

900 births are randomly selected

The probability of birth of a boy or a girl is 1/2 = 0.5

Total chances of a girl is 900 * 0.5 = 450

The birth of girl observed is 4

Therefore the number of girls are significantly low.

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The solution for the first inequality is a ≥ 2 or a ∈ [2, ∞), and for the second inequality the solutions are b < -5 or b ∈ (-∞, -5)

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have two inequalities:

a.) -12a +7 ≤31

b.) -9 > 3b +6

a)  -12a +7 ≤ 31

-12a ≤ 31 - 7

-12a ≤ 24

-a ≤ 2

a ≥ 2  (sign changed because multiplied by a negative number)

a ∈ [2, ∞)

b.) -9 > 3b +6

-15 > 3b

-5 > b

or

b < -5

b ∈ (-∞, -5)

Thus, the solution for the first inequality is a ≥ 2 or a ∈ [2, ∞), and for the second inequality the solutions are b < -5 or b ∈ (-∞, -5)

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There is a 75% chance that it will rain here or on Mars is false because there is a 25% chance that it will rain here and not on Mars.  

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have:

There is a 50% chance of rain here and a 25% chance of rain on Mars. Therefore, there is a 75% chance that it will rain here or on Mars.

The probability that it will rain here:

P(rain here) = 50%

P(rain on mars) 50%

P(not rain here) = 100 - 50 = 50%

P(not rain on mars) = 100 - 50 = 50%

P(rain here and not on mars) = 0.5×0.5 = 0.25 or 25%

Thus, there is a 75% chance that it will rain here or on Mars is false because there is a 25% chance that it will rain here and not on Mars.  

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The equation of a=P(1.3)^{x/x} is mathematically given as

a=1.3P or P=a/1.3

Generally, the equation for the statement is mathematically given as

a=P(1.3)^{x/x}

Therefore,

a=P(1.3)^{x/x}

a=P(1.3)^1

a=Px1.3

a=1.3P or P=a/1.3

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Answer:

0.0085× 100= 0.85℅

Step-by-step explanation:

okay so you want 3/8 from 44 as percentage but how can you put the 3/8 on top of the 44 to multilply it by 100 to get the percentage, ofcourse we will have to change the 3/8 into a whole number. To do that we are going to do the following.

= 3 ÷ 8 = 0.375, so here you got a number that you can put on the 44.

Now to get the percentage we are going to do this:

0.375/44 × 100

= 0.0085 × 100 ( I solved the 0.375/44 as you know that division always comes first in maths)

= 0.85℅ ( I solved the 0.0085 × 100)

°•°•° I hope this helped sorry for taking long °•°•° May I get brainliest if you liked my ans im trying to lvl up ty and its okay if you don't want to