Emma notices that since her credit card balance compounds monthly, she is charged more than


15% of her initial loan amount in interest each year. She wants to know how much she would p


the card were compounded annually at a rate of 15%. Which expression could Emma use to


evaluate her balance with an annual compounding interest rate?


300(1. 15)12t


300(1. 015)12


300(1. 0125)


300(1. 15)

The solution is: 14 karat gold is 58.3333...% gold

We have given that;

75% gold and 50% gold and we need to make 200 grams of 58.3333...% gold.

Since, A percentage is a number or ratio that can be expressed as a fraction of 100. A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", although the abbreviations "pct.", "pct" and sometimes "pc" are also used. A percentage is a dimensionless number; it has no unit of measurement.

Here, we have,

A) x + y = 200

B) .75x + .50y = ( (14/24) * 200)

We multiply equation B) by -1.3333... and get

B) -x -.6666...y = -155.5555... then adding A)

A) x + y = 200  we get

.3333...y = 44.4444...

y = 133.3333... grams 12 karat gold

x = 66.6666... grams  18 karat gold

Double-Checking the answer

133.3333... * .5 = 66.6666...

66.6666 * .75 = 50.0000...

Hence, Concentration of final solution = (66.6666... + 50) / 200 = 58.3333...% which is 14 karat gold

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A graph of polygon GREAT and its image after a counterclockwise rotation of 90° around the origin is shown in the image attached below.

In Mathematics and Geometry, the rotation of a point 90° about the center (origin) in a counterclockwise (anticlockwise) direction would produce a point that has these coordinates (-y, x).

By applying a rotation of 90° counterclockwise around the origin to vertices W, the coordinates of the vertices of the image ΔA'B'C' are as follows:

(x, y)                               →            (-y, x)

Ordered pair G = (-3, -2) → Ordered pair G' = (2, -3)

Ordered pair R = (-4, 4) → Ordered pair R' = (-4, -4)

Ordered pair E = (0, 1) → Ordered pair E' = (-1, 0)

Ordered pair A = (1, -2) → Ordered pair A' = (2, 1)

Ordered pair T = (-1, -3) → Ordered pair T' = (3, -1)

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△ABC and △DEF are similar triangles if they have corresponding sides that are proportional and the corresponding angles are all congruent. Thus, the options that are applied are B and C.

Similar shapes are enlargements or shortening of other shapes using a scale factor.

Two triangles are said to be similar if the corresponding sides are proportional and the corresponding angles are the same. There are the following similarity criteria:

1. AA or AAA where all the angles are equal

2. SSS where all the sides are proportional to the corresponding sides

3. SAS where the corresponding sides and the angle between are proportional and congruent.

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If you paid $25,000 for your car and you sell it after owning the car for 3 years, then the worth of the car is t₃=$7,910. 15 (option c).

To find the value of your car after owning it for 3 years, we need to evaluate the function at t=3. This means we need to substitute t=3 into the function and simplify the expression.

f(3) = 0.75(3) = 2.25

The output of the function when t=3 is 2.25. But what does this number mean? It represents the fraction of the original value of the car that remains after owning it for 3 years.

To find the actual value of the car, we need to multiply this fraction by the original value of the car, which is given as $25,000.

Value of car after 3 years = 2.25 x $25,000 = $56,250

Therefore, the value of the car after owning it for 3 years is $7,910.15. This is the option (C) in the given choices.

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This is the derivative of the given function f(x) = (3x + 1)^5(3x - 1)^6 using the Generalized Power Rule.

To find the derivative of the function f(x) = (3x + 1)^5(3x - 1)^6 using the Generalized Power Rule, we will need to apply both the Product Rule and the Chain Rule.

The Product Rule states that if you have a function f(x) = g(x)h(x), then f'(x) = g'(x)h(x) + g(x)h'(x).

First, let's identify g(x) and h(x) in your function:
g(x) = (3x + 1)^5
h(x) = (3x - 1)^6

Next, we'll find the derivatives g'(x) and h'(x) using the Chain Rule, which states that if you have a function y = [u(x)]^n, then y' = n[u(x)]^(n-1) * u'(x).

For g'(x):
u(x) = 3x + 1
n = 5
u'(x) = 3
g'(x) = 5(3x + 1)^(5-1) * 3 = 15(3x + 1)^4

For h'(x):
u(x) = 3x - 1
n = 6
u'(x) = 3
h'(x) = 6(3x - 1)^(6-1) * 3 = 18(3x - 1)^5

Now, we apply the Product Rule:
f'(x) = g'(x)h(x) + g(x)h'(x) = 15(3x + 1)^4(3x - 1)^6 + (3x + 1)^5 * 18(3x - 1)^5

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Answer:

Let's solve this in steps:

1. Convert mixed numbers to fractions:

```

3 1/2 = 7/2

9 3/4 = 39/4

```

2. Perform the subtraction:

```

7/2 - 39/4 = -11/4

```

3. Divide by -2.5:

```

-11/4 / -2.5 = 4.4

```

Therefore, the value of the expression is **4.4**.

The length of diagonal ac is approximately 15.58 cm, and the length of diagonal bd is approximately 12.22 cm

Rhombus is a special type of parallelogram in which all four sides are congruent. The opposite angles of a rhombus are also congruent, and the diagonals bisect each other at right angles.

Now, let's consider the given rhombus abcd, where ad = 8cm and m∠ade=20°. We need to determine the length of diagonals ac and bd.

First, let's use the law of cosines to find the length of side ae. We know that ad = 8cm, and m∠ade=20°, so we can use the formula:

ae² = ad² + de² - 2ad(de)cos(m∠ade)

Substituting the values, we get:

ae² = 8² + de² - 2(8)(de)cos(20°)

Next, we can use the fact that a rhombus has all sides congruent to find the length of side de. Since abcd is a rhombus, we know that ac and bd are also congruent diagonals that bisect each other at right angles. Therefore, we can draw diagonal ac and use the Pythagorean theorem to find the length of ac:

ac² = (ae/2)² + (de/2)²

Substituting ae² from the previous equation, we get:

ac² = ((8² + de² - 2(8)(de)cos(20°))/4) + (de/2)²

Simplifying the equation and using the fact that ac and bd are congruent, we get:

bd² = ac² = (8² + de² - 2(8)(de)cos(20°))/2

Finally, we can use the Pythagorean theorem to find the length of diagonal bd:

bd² = ab² + ad²

Substituting ab = ac/2 and ad = 8cm, we get:

bd² = (ac/2)² + 8²

Substituting ac² from the previous equation, we get:

bd² = ((8² + de² - 2(8)(de)cos(20°))/8)² + 8²

Simplifying the equation, we get:

bd ≈ 12.22 cm

Similarly, we can solve for ac using the equation we derived earlier:

ac² = ((8² + de² - 2(8)(de)cos(20°))/4) + (de/2)²

Substituting de ≈ 9.84cm (which we can solve for from the equation ae² = 8² + de² - 2ad(de)cos(m∠ade)), we get:

ac ≈ 15.58 cm

Therefore, the length of diagonal ac is approximately 15.58 cm, and the length of diagonal bd is approximately 12.22 cm

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C. Yes; the graph passes the vertical line test.

The correct answer is C. Yes; the graph passes the vertical line test.

To determine whether a graph represents a function, we apply the vertical line test. The vertical line test states that for a graph to represent a function, no vertical line should intersect the graph in more than one point.

In this case, the graph passes the vertical line test if each vertical line crosses the graph at most once. If this condition is satisfied, then each x-value corresponds to a unique y-value, indicating that the graph represents a function.

Since the question states that the graph passes the vertical line test, we can conclude that it represents a function.

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Answer:

The graph on the top right

Step-by-step explanation:

The slope-intercept form is y = mx + b

m = the slope

b = y-intercept

The equation is y = 1/2x + 2

The y-intercept in this equation is 2, meaning the graph has a point (0,2) on it.  Looking at the options, the only graph that has a point (0,2) is the map on the top right, and that is the answer.

The proportion of this word problem is 6 : 1 where Neil Armstrong weighed approximately 27.5 pounds on the moon.

The proportion of a word problem represents the relationship between two or more quantities. In this case, the proportion can be set up as:

Weight on Earth : Weight on Moon = 6 : 1

Using the information provided in the problem, we know that Neil Armstrong weighed 165 pounds on Earth. We can use this information to find his weight on the moon by setting up a proportion:

165 : x = 6 : 1

where x represents his weight on the moon. To solve for x, we can cross-multiply and simplify:

165 * 1 = 6 * x

x = 165/6

x ≈ 27.5

Therefore, Neil Armstrong weighed approximately 27.5 pounds on the moon.

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To find the approximate area of the shaded region in this figure, we need to subtract the area of the smaller circle from the area of the larger circle. The radius of the larger circle is 6 feet and the radius of the smaller circle is 3 feet.

The formula for the area of a circle is A = πr^2, where π is approximately 3.14 and r is the radius.

So, the area of the larger circle is A = 3.14 x 6^2 = 113.04 square feet.
The area of the smaller circle is A = 3.14 x 3^2 = 28.26 square feet.

To find the area of the shaded region, we subtract the area of the smaller circle from the area of the larger circle:

Area of shaded region = 113.04 - 28.26 = 84.78 square feet (rounded to two decimal places).

Therefore, the approximate area of the shaded region in this figure is 84.78 square feet.

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Considering the route as a curve of a quadratic function, the information should be completed as follows;

In Mathematics and Geometry, the vertex form of a quadratic function is represented by the following mathematical equation (formula):

y = a(x - h)² + k

Where:

Based on the information provided about this quadratic function, we can logically deduce that a mathematical equation which quickly reveals the vertex of the quadratic function is given by:

y = a(x - h)² + k

0 = a(2.9 - (-1))² + 4

3.9a = -4

a = -4/3.9

a = -1.03

Therefore, the required quadratic function is given by:

y = a(x - h)² + k

y = -1.03(x - (-1))² + 4

y = -1.03(x + 1)² + 4

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The explanation on why △ACF is 30°-60°-90° triangle is given below.

With a regular hexagon, each of its sides and angles are equal in measure. Consider the centre of the encompassing circle, connected to two neighbouring vertices - labeled A and B here. This then creates a radius wherein the length of AB is basically equal to any other side, denoted as 's'. Furthermore, △ABF will be an isosceles triangle (with AB = BF).  

From these facts, we can produce △ACF which is a right angled triangle – with AC being its hypotenuse, A F and FB both equating to s/2, finally concluding that ∠AFB is equivalent to 120°/2 = 60° while establishing that ∠ACF is also a right angle constituent making △ACF essentially a 30°-60°-90° triangle.

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To use the GCF and distributive property to find the sum of 22 + 33, we first need to identify the GCF of both numbers, which is 11.

We can then write each number as a product using the GCF as a factor: 22 = 11 x 2 and 33 = 11 x 3. Next, we can apply the distributive property by multiplying the GCF by the sum of the other factors in each number: 11 x (2 + 3).

Finally, we can simplify the expression by adding the sum of the other factors, which is 5: 11 x 5 = 55. Therefore, the sum of 22 + 33 using the GCF and distributive property is 55.

In summary, to find the sum of 22 + 33 using the GCF and distributive property, we first identify the GCF as 11 and write each number as a product using the GCF as a factor.

We then apply the distributive property by multiplying the GCF by the sum of the other factors in each number. Finally, we simplify the expression by adding the sum of the other factors and arrive at the answer of 55. This method can be helpful when working with larger numbers or more complex expressions.

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When allowing repetition, you can make 676,000 passwords, and without repetition, you can make 468,000 passwords.

To create a password that starts with two letters from the alphabet, followed by three digits (for example, AB-123), you can make a different number of passwords depending on whether you are allowed to repeat letters or numbers.

1. If you are allowed to repeat letters or numbers, you can make:
- 26 (alphabet letters) x 26 (alphabet letters) x 10 (digits 0-9) x 10 (digits 0-9) x 10 (digits 0-9) = 676,000 passwords.

2. If you don't repeat any letters or numbers, you can make:
- 26 (alphabet letters) x 25 (remaining alphabet letters) x 10 (digits 0-9) x 9 (remaining digits 0-9) x 8 (remaining digits 0-9) = 468,000 passwords.

Your answer: When allowing repetition, you can make 676,000 passwords, and without repetition, you can make 468,000 passwords.

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The volume of the cube-shaped speaker is 42.875 cubic inches. The volume of the package is 68 cubic inches. Subtracting the volume of the speaker from the volume of the package gives the empty space remaining, which is 25.125 cubic inches.

The volume of the cube-shaped speaker is given by V₁ = (edge length)³ = 3.5³ = 42.875 cubic inches.

The volume of the square prism-shaped package is given by V₂ = (base area) x (height) = 16 x 4.25 = 68 cubic inches.

Therefore, the empty space remaining in the package after the speaker is placed in it is V₂ - V₁ = 68 - 42.875 = 25.125 cubic inches.

So, the empty space remaining in the package is 25.125 cubic inches.

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To determine how many times a day we would need to fill the container shown below, we need to calculate its capacity in cubic centimeters. Let's assume that the container is a rectangular prism with dimensions of 30 centimeters (length) x 20 centimeters (width) x 25 centimeters (height). The formula for calculating the volume of a rectangular prism is:

Volume = length x width x height

Plugging in the values we have, we get:

Volume = 30 cm x 20 cm x 25 cm

Volume = 15,000 cubic centimeters

Therefore, the container has a capacity of 15,000 cubic centimeters. To determine how many times we would need to fill it each day, we need to divide the amount of pellets and hay we feed the okapi daily (5,024 cubic centimeters) by the capacity of the container (15,000 cubic centimeters):

5,024 / 15,000 = 0.3356

This means that we would need to fill the container approximately 0.3356 times a day, which is not a practical answer. We need to round this up to the nearest whole number.

The options given to us are 80 times, 40 times, 16 times, and 4 times. Out of these options, the closest whole number to 0.3356 is 1, which means we would need to fill the container once a day.

Therefore, the answer is that we would need to fill the container shown below 1 time a day to feed the okapi their daily amount of pellets and hay.

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7 is the slope of BD in Quadrilateral.

What in arithmetic is a quadrilateral?

Four sides, four vertices, and four angles make up a quadrilateral, which is a two-dimensional form. Concave and convex are the two most common forms. Additionally, there are several subgroups of convex quadrilaterals, including trapezoids, parallelograms, rectangles, rhombus, and squares.

                                 There are four closed sides to a quadrilateral. Quadrilaterals are the following figures: produced by Raphael. a quadrilateral form. The form features a single pair of parallel sides and no right angles.

points A(4, 9) and C(3, 2)

      slope = y₂ - y₁/x₂ - x₁

                =  2 - 9/3 - 4

                = - 7/-1

                = 7

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the final answer is 27/125.

To evaluate [tex](3/5)^3[/tex], we simply need to multiply (3/5) by itself three times:

[tex](3/5)^3 = (3/5) * (3/5) * (3/5)[/tex]

To simplify, we can first multiply the numerators together and the denominators together:

[tex](3/5)^3 = 27/125[/tex]

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Purab initially had 17 rose plants in his lawn before buying the new ones.

Purab initially had a certain number of rose plants in his lawn. He bought twice that number, but had to discard 3 plants as they turned bad

After planting the new ones, there were a total of 48 plants in the garden.

To determine how many plants he had earlier, let's use a variable x to represent the initial number of plants.

Purab bought 2x plants, and after removing the 3 bad plants, he had (2x - 3) good plants.

Adding these to the initial number of plants, the equation becomes:

x + (2x - 3) = 48

Combining like terms, we get:

3x - 3 = 48

Next, we add 3 to both sides:

3x = 51

Finally, we divide by 3: x = 17

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The probability that the coin will show tails at least once is 0.56.

To find the probability that the coin will show tails at least once, you can sum the probabilities of getting 1, 3, or 4 tails, as shown in the table:

Probability of 1 tail: 0.25
Probability of 3 tails: 0.25
Probability of 4 tails: 0.06

Now, add these probabilities together:

0.25 + 0.25 + 0.06 = 0.56

So, the probability that the coin will show tails at least once is 0.56.

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The perimeter of Koch's snowflake fractal will be infinite.

Koch's snowflake fractal is created by adding triangular bumps to the sides of an equilateral triangle at progressively smaller scales. At each stage, the number of sides of the resulting figure increases by a factor of 4, and the perimeter of the figure increases as well.

To see how the perimeter changes as bumps are added to all sides of the figure, we can use the fact that each bump adds a segment of length 1/3 to the original side. So if we start with a triangle of side length 1 and add a bump to each side, the new perimeter is:

P = 3(1 + 1/3) = 4

Now we have a figure with 12 sides. If we add a bump to each of these sides, the new perimeter is:

P = 12(1 + 1/3 + 1/9) = 16/3

In the next stage, we have 48 sides, and each side has a length of 1/3^2, so the new perimeter is:

P = 48(1 + 1/3 + 1/9 + 1/27) = 64/3

At each stage, we can see that the perimeter is multiplied by a factor of 4/3. So if we carry on this process forever, the perimeter of Koch's snowflake fractal will be infinite.

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The size of the measure of the angle X is calculated to be equal to 37° to the nearest degree using trigonometric ratios of sine

The trigonometric ratios is concerned with the relationship of an angle of a right-angled triangle to ratios of two side lengths.

The basic trigonometric ratios includes;

sine, cosine and tangent.

For the given triangle;

sin X = 3/5 {opposite/hypotenuse}

X = sin⁻¹(3/5) {cross multiplication}

X = 36.8699°

Therefore, the measure of the angle X is calculated to be equal to 37° to the nearest degree using trigonometric ratios of sine

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The searchlight should be 1/3 feet deep at the edge of the opening. Since the paraboloid is a continuous surface, the depth will increase gradually from the edge of the opening to the vertex at (0,0,1).

Determine the depth of the searchlight shaped like a paraboloid of revolution, we need to use the equation for the standard form of a paraboloid of revolution:
z = (x^2 + y^2) / (4f)
where z is the depth, x and y are the horizontal and vertical coordinates, and f is the focal length of the paraboloid.
We know that the light source is located 1 feet from the base along the axis of symmetry, which means that the vertex of the paraboloid is at (0,0,1).
We also know that the opening is 6 feet across, which means that the horizontal distance from one side of the opening to the other is 3 feet.
Using this information, we can find the value of f:
f = (d/2)^2 / 2r
where d is the diameter of the opening (6 feet), and r is the radius of curvature at the vertex (1 foot).
f = (6/2)^2 / 2(1) = 4.5 feet
Now we can plug in the values for x, y, and f to solve for z:
z = (x^2 + y^2) / (4f)
z = (x^2 + y^2) / (4(4.5))
z = (x^2 + y^2) / 18
Since the opening is 6 feet across, we know that the maximum value of x is 3 feet. Therefore, we can use the maximum value of y (also 3 feet) to find the depth at the edge of the opening:
z = (3^2 + 3^2) / 18
z = 6/18
z = 1/3 feet
So the searchlight should be 1/3 feet deep at the edge of the opening. However, since the paraboloid is a continuous surface, the depth will increase gradually from the edge of ×the opening to the vertex at (0,0,1).

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Point B is not the midpoint of line AC, because angle AOB is not half of angle  AOC.

If point B is the midpoint of line AC, then angle AOB must be equal to angle  BOC.

The value of angle AOC is calculated as follows;

let angle AOC = θ

cos θ = 100 yds / 500 yds

cos θ = 0.2

θ = cos⁻¹ (0.2)

θ = 78.5⁰

The value of length AC is calculated as follows;

AC = √ (500² - 100²)

AC = 489.9

If point B is the midpoint, then AB = BC = 489.9/2 = 244.95

The value of angle AOB is calculated as follows;

tan β = AB/AO

tan β = 244.95/100
tan β = 2.4495

β = arc tan (2.4495)

β = 67.8⁰

Half of angle AOC = 78.5⁰/2 = 39.25⁰

β  ≠ 39.25⁰

So point B is not midpoint of line AC, since angle AOB is not half of angle  AOC.

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Lee's total cost for the leaf blower was $215.50.

First, let's find the selling price of the leaf blower before sales tax was added:

The leaf blower was marked up by 150%, so the selling price is:

= [tex]80 + (\frac{150}{100}) 80[/tex]

= 80 + 120

= 200

So the selling price of the leaf blower before sales tax was $200.

Next, we need to find the amount of sales tax that Lee paid. To do this, we need to multiply the selling price by the sales tax rate:

Sales tax = 7.75% ($200)

= 0.0775 ($200)

= $15.50

Finally, we can find Lee's total cost by adding the selling price and the sales tax:

Total cost = Selling price + Sales tax

= $200 + $15.50

= $215.50

Therefore, Lee's total cost for the leaf blower was $215.50.

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Answer:

Step-by-step explanation:

the point at which the lines representing the linear equations intersect

The number of 6-card hands  in which at least one card from each suit is equal to 8,184,220.

Total number of 6-card hands that can be formed from a deck of 60 cards is,

Using combination formula,

C(60, 6) = 50,063,860

Now, subtract the number of 6-card hands that do not contain at least one card from each suit.

There are 5 ways to choose the suit that will be missing from the hand.

Once this suit is chosen, there are 48 cards remaining in the other suits.

Choose 6 cards from this set, so the number of 6-card hands that do not contain any cards from the chosen suit is,

C(48, 6) = 12,271,512

Overcounted the number of hands that are missing more than one suit.

There are C(5, 2) ways to choose 2 suits that will be missing from the hand.

Once these suits are chosen, there are 36 cards remaining in the other 3 suits.

Choose 6 cards from this set, so the number of 6-card hands that do not contain any cards from the chosen suits is,

C(36, 6) = 1,947,792

We cannot have a 6-card hand that is missing more than 2 suits.

3 suits with no cards in the hand, which is not allowed.

Number of 6-card hands that have at least one card from each suit is,

C(60, 6) - 5×C(48, 6) + C(5, 2)×C(36, 6)

=50,063,860 - 5×  12,271,512 + 10 × 1,947,792

= 50,063,860 -61,357,560 + 19,477,920

= 8,184,220

Therefore, there are 8,184,220 of 6-card hands that have at least one card from each suit.

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The expression for the area of the new square is y² + 10y + 25.

To find the expression that represents the area of the new square, we need to consider that when each side of a square is increased by 5 units, the new side length becomes y + 5. The area of the new square is then given by:

(New side length)² = (y + 5)²

Expanding the square, we get:

(y + 5)² = y² + 10y + 25

Therefore, the expression that represents the area of the new square is y² + 10y + 25.

So, the correct option is:

O y² + 10y + 25

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The equation for line P such that the system has an infinite number of solutions is given as follows:

3) 2x + 2y = -2.

The first equation for the system of equations is given as follows:

x + y = -1.

A system of equations has an infinite number of solutions when the two equations are multiples.

Multiplying the equation by 2, we have that:

2x + 2y = -2.

Meaning that equation 3 is correct.

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