Each airport has a runway that is about 500 m long.
when it lands, the speed of the aeroplane is 40 m/s.
explain why the airline should not use an aeroplane that has more mass and
needs a higher speed for landing.

The mass of water that was heated in the calorimetry experiment was 547.73 g.

T is the temperature change (7.16 K). Rearranging the formula to find the mass (m):

m = Q / (cΔT) Plugging in the values:

m = 17000.0 J / (4.18 J/g·K × 7.16 K) m ≈ 657.71 g

So, approximately 657.71 grams of water was heated in the calorimetry experiment.

To calculate the mass of water that was heated, we need to use the formula:

Q = m × c × ΔT

where Q is the heat transferred, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.

We are given that Q = 17000.0 J, ΔT = 7.16 K, and c = 4.18 J/(g·K) (the specific heat capacity of water). We can rearrange the formula to solve for m:

m = Q / (c × ΔT)

Substituting the values we have:

m = 17000.0 J / (4.18 J/(g·K) × 7.16 K)

m = 547.73 g

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Hydroelectric power plants can cause harm to the environment and local ecosystems, especially when dams are built to create reservoirs.

While hydroelectric power is considered a clean energy source because it doesn't produce harmful emissions or pollutants, it does have negative environmental impacts. The construction of dams and reservoirs can cause significant damage to natural habitats, disrupt water flow, and alter the ecology of local rivers and streams.

This can have a detrimental effect on fish populations, migratory patterns, and even erosion of riverbanks. Additionally, the building of dams and reservoirs can lead to the displacement of communities and the loss of cultural heritage sites. The reliance on hydroelectric power can also be affected by climate change as reduced rainfall can lead to lower water levels in reservoirs, impacting the amount of electricity that can be generated.

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Using this equation, the refractive index of a material with an angle of incidence of 24∘ and an angle of refraction of 17∘ was found to be approximately 1.33, consistent with common transparent materials.

When a beam of light passes from one medium into another, its direction changes due to the change in the speed of light in the different media. This phenomenon is known as refraction. The angle of incidence is the angle between the incident ray and the normal to the surface at the point of incidence, and the angle of refraction is the angle between the refracted ray and the normal.

The relationship between the angles of incidence and refraction is given by Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the speeds of light in the two media. Mathematically,

[tex]$\frac{\sin{\theta_1}}{\sin{\theta_2}}=\frac{v_1}{v_2}$[/tex]

where [tex]"\theta_2"[/tex] is the angle of incidence, [tex]"\theta_2"[/tex] is the angle of refraction, [tex]v_1[/tex] is the speed of light in the incident medium (in this case, air), and [tex]v_2[/tex] is the speed of light in the transparent material.

Assuming that the transparent material has a higher refractive index than air, we know that the angle of refraction will be smaller than the angle of incidence. In this case, we are given that [tex]"\theta_1"[/tex] = 24∘ and [tex]"\theta_2"[/tex] = 17∘. We can use Snell's law to find the refractive index of the transparent material.

First, we need to know the speed of light in the air and the speed of light in the transparent material. The speed of light in air is approximately [tex]$3 \times 10^8 \text{ m/s}$[/tex], and the speed of light in the transparent material depends on its refractive index. Let's denote the refractive index of the material by n. Then, we have:

[tex]$\frac{\sin{24^\circ}}{\sin{17^\circ}}=\frac{3 \times 10^8 \text{ m/s}}{v_2}$[/tex]

Solving for [tex]v_2[/tex], we get:

[tex]$v_2 = (3 \times 10^8 \text{ m/s}) \times \frac{\sin{17^\circ}}{\sin{24^\circ}} \approx 2.26 \times 10^8 \text{ m/s}$[/tex]

Next, we can use the relationship between the speed of light and the refractive index to find n:

[tex]$n = \frac{c}{v_2}$[/tex]

where c is the speed of light in a vacuum

Thus,

[tex]$n = \frac{3 \times 10^8 \text{ m/s}}{2.26 \times 10^8 \text{ m/s}} \approx 1.33$[/tex]

This value of the refractive index is close to that of common transparent materials like water and glass.

In summary, when a beam of light travels from air into a transparent material at an angle of incidence of 24∘ and an angle of refraction of 17∘, the refractive index of the material can be found using Snell's law and the relationship between the speed of light and the refractive index. The calculated value of the refractive index is approximately 1.33, which is consistent with that of common transparent materials.

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Meteorologists' weather predictions can sometimes be wrong..

Due to the complexity and variability of weather systems. Weather is influenced by many factors, such as temperature, pressure, humidity, and , which interact in complicated ways. Additionally, small changes in initial conditions or slight variations in the way weather patterns evolve can have significant effects on the final outcome.

While weather models and forecasting techniques have improved over time, there are still limitations and uncertainties in the data and models used to make predictions. Finally, unexpected events or phenomena, such as rapid changes in weather patterns or extreme weather events, can also make predictions difficult or inaccurate.

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These radio waves have a wavelength of roughly 492.62 metres.

In the USA, the FM transmission runs from 88.0 MHz to 108.0 MHz. 100 channels, each 200 kHz (0.2 MHz) wide, make up the band. The centre frequency is situated 100 kHz (0.1 MHz) up from the channel's lower end, or at half the FM channel's bandwidth. As frequency rises as energy falls, frequency and energy are related directly in the energy equation.

wavelength Equals light's speed (c) divided by frequency (f)

Where the speed of light (c) is approximately 3.00 x 10⁸ m/s.

Converting the given frequency of 610 kHz to Hz:

610 kHz = 610 x 10³ Hz

Substituting the values in the formula:

λ = (3.00 x 10⁸ m/s) / (610 x 10³ Hz)

λ = 492.62 meters (approx.)

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By using, Coulomb's Law the two charges are: approximately 0.248 meters apart.

To find the distance between a +32.2 µC charge and a +12.3 µC charge that experience a 0.544 N force, we can use Coulomb's Law.

Coulomb's Law states that the force (F) between two charges (q1 and q2) is proportional to the product of the charges and inversely proportional to the square of the distance (r) between them. The formula for Coulomb's Law is F = k * (q1 * q2) / r², where k is the electrostatic constant, approximately 8.99 x 10^9 N m²/C².

In this case, q1 = +32.2 µC, q2 = +12.3 µC, and F = 0.544 N. First, we need to convert the charges from microcoulombs (µC) to coulombs (C) by multiplying by 10^-6: q1 = 32.2 x 10^-6 C and q2 = 12.3 x 10^-6 C.

Now we can plug these values into Coulomb's Law formula:

0.544 N = (8.99 x 10^9 N m²/C²) * (32.2 x 10^-6 C) * (12.3 x 10^-6 C) / r²

Next, we will solve for r:

r² = (8.99 x 10^9 N m²/C²) * (32.2 x 10^-6 C) * (12.3 x 10^-6 C) / 0.544 N
r² ≈ 0.0615 m²

Now, take the square root of both sides to find r:

r ≈ 0.248 m

So, the two charges are approximately 0.248 meters apart.

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Complete question:

A +32. 2 u C charge feels a 0. 544 N force from a +12. 3 uC charge. How far apart are they?

(u stands for micro. )

The final momentum of the player is 0 kgm/s, the change in momentum is -0.567 kgm/s, the impulse is -0.567 N*s, and the magnitude of the force that brings the player to a stop in 1.4 seconds is 0.405 N.

We can use the equation for impulse, which is given by:

[tex]impulse = force * time[/tex]

We can also use the equation for change in momentum, which is given by:

change in momentum = final momentum - initial momentum

First, let's find the final momentum of the player. We know that the initial momentum is 0.567 kgm/s, and the player comes to a stop, so the final momentum is 0 kgm/s.

Therefore, the change in momentum is:

change in momentum = final momentum - initial momentum = 0 - 0.567 = -0.567 kg*m/s

The negative sign indicates that the momentum has decreased.

Now, let's find the impulse. We know that the time it takes for the player to come to a stop is 1.4 seconds, so we can plug that into the equation for impulse:

impulse = force x time

-0.567 kg*m/s = force x 1.4 s

Solving for force, we get:

force = -0.567 kg*m/s ÷ 1.4 s = -0.405 N

The negative sign indicates that the force is acting in the opposite direction of the player's momentum.

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The emf induced in the coil is 2.0 volts.

To calculate the emf induced in the coil with 20 turns of wire, wrapped around a tube with a cross-sectional area of 1.0 m², and a magnetic field applied at a right angle at 0.50 T, when it is pulled out of the magnetic field in 5 seconds, we can use Faraday's Law of Electromagnetic Induction.

The formula for Faraday's Law is:

emf = -N * (ΔΦ/Δt)

where

emf is the induced electromotive force,

N is the number of turns in the coil (20),

ΔΦ is the change in magnetic flux, and

Δt is the time it takes to change the flux (5 seconds).

First, we need to calculate the change in magnetic flux (ΔΦ). Since the coil is completely pulled out of the magnetic field, the final magnetic flux will be zero.

The initial magnetic flux (Φ_initial) can be calculated using the formula:

Φ_initial = B * A

where

B is the magnetic field strength (0.50 T) and

A is the cross-sectional area of the tube (1.0 m²).

Φ_initial = 0.50 T * 1.0 m²

              = 0.50 Wb (Weber)

Now, we can calculate the change in magnetic flux (ΔΦ):

ΔΦ = Φ_final - Φ_initial

      = 0 Wb - 0.50 Wb

      = -0.50 Wb

Next, we can plug the values into Faraday's Law formula:

emf = -20 * (-0.50 Wb / 5 s)

       = 20 * (0.10 V)

       = 2.0 V

So, the emf induced in the coil is 2.0 volts.

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a) The magnitude of the constant angular acceleration of the wheel is  -1.146 rev/min^2.

b) The wheel makes 10512 rotations before coming to rest.

c) The magnitude of the tangential component of linear acceleration of the particle is 0.037 m/s^2.

a) To find the angular acceleration, we first need to convert the time taken for the wheel to come to rest from hours to minutes. 1.6 hours is equal to 96 minutes. We can use the equation of motion for rotational kinematics:

ωf = ωi + αt

where ωf is the final angular velocity (0 in this case), ωi is the initial angular velocity (110 rev/min), α is the angular acceleration, and t is the time taken (96 minutes).

Substituting the given values, we get:

0 = 110 + α(96)

Solving for α, we get:

α = -1.146 rev/min^2 (Note that the negative sign indicates a decrease in angular velocity.)

b) The number of rotations made by the wheel before coming to rest can be found using the formula:

θ = ωit + 1/2 αt^2

where θ is the angle of rotation, ωi is the initial angular velocity, α is the angular acceleration, and t is the time taken.

Substituting the given values, we get:

θ = (110 rev/min)(96 min) + 1/2 (-1.146 rev/min^2)(96 min)^2

Simplifying, we get:

θ = 10512 rev

c) The tangential component of linear acceleration can be found using the formula:

at = rα

where at is the tangential component of linear acceleration, r is the distance from the axis of rotation, and α is the angular acceleration.

Substituting the given values, we get:

at = (0.44 m)(2π/60)(-1.146 rev/min^2)

Simplifying, we get:

at = -0.037 m/s^2

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Complete question is:

The flywheel of a steam engine runs with a constant angularspeed of 110 rev/min. when steam is shut off, the friction of thebearings and the air brings the wheel to rest in 1.6 h.

a) what is the magnitude of the constant angular acceleration ofthe wheel in rev/min^2? do not enter the units.

b) how many rotations does the wheel make before coming torest?

c) what is the magnitude of the tangential component of the linear acceleration of a particle that is located at a distance of 44 cm from the axis of rotation when the flywheel is turning at 58 rev/min?

1. The relationship between lightning and electricity was made clear by Franklin's experiment.2.  He submitted a plan for an experiment in which a lightning rod would be used to attempt to capture an electrical charge. 3,4. Some scientists and historians doubt this story because it's highly unlikely that lightning struck a key while Franklin was flying a kite because he would have most likely perished5. . Noone else try repeating this experiment

Do you think that Franklin actually performed this experiment?

The experiment was not carried out by Franklin to demonstrate the presence of electricity. Furthermore, it's highly unlikely that lightning struck a key while Franklin was flying a kite because he would have most likely perished.

He submitted a plan for an experiment in which a lightning rod would be used to attempt to capture an electrical charge in a "leyden jar," a container for storing electrical charges, proving that lightning was a type of electricity. Noone else try repeating this experiment.

Franklin established that lighting was an electrical discharge through the kite experiment and discovered that it could be charged into the ground over a conductor, offering a secure alternate route and reducing the possibility of fatal fires.

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Intensity is the amount of sound energy per unit area while loudness is a subjective perception of the strength or amplitude of a sound.

Loudness and intensity are both measures of sound, but they are not the same thing.

Intensity refers to the amount of sound energy per unit area and is typically measured in decibels (dB).

Loudness, on the other hand, is a subjective perception of the strength or amplitude of a sound. It is influenced not only by the intensity of the sound but also by factors such as the frequency, duration, and context of the sound.

In general, higher intensity sounds will be perceived as louder, but this relationship is not always straightforward, and individual differences can also play a role in perceived loudness.

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F = k * ([tex]q_1[/tex][tex]q_2[/tex])/[tex]r^{2}[/tex], where F is the strength of the electrostatic force, k is Coulomb's constant (9X[tex]10^{9}[/tex] N*[tex]m^{2}[/tex]/[tex]C^{2}[/tex]), [tex]q_1[/tex] and [tex]q_2[/tex] are the charges, and r is the distance between the charges in meters.

What is Magnetic Force?

Magnetic force is a fundamental force of nature that is exerted between moving charged particles, such as electrons or between a magnetic field and a moving charge. This force can cause a magnetic material to experience a force of attraction or repulsion depending on its orientation with respect to the magnetic field.

Using the Gizmo to check, we can input two charges and a distance of 10 meters to calculate the electrostatic force between them. The result should match the output of the equation F = k * ([tex]q_1[/tex]*[tex]q_2[/tex])/[tex]r^{2}[/tex].

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The density  of the petrol in the storage tank is approximately: 703 kg/m³.

To determine the density of the petrol in a storage tank with a height of 4.7m and a pressure at the base of 32.3 kPa, we can use the following formula:

Pressure = Density × Gravity × Height

Where Pressure is given as 32.3 kPa, Gravity is 9.81 m/s² (as provided), and Height is 4.7m. To find the density, we can rearrange the formula as follows:

Density = Pressure / (Gravity × Height)

Now, we can plug in the values:

Density = 32,300 Pa / (9.81 m/s² × 4.7m)

Density ≈ 703 kg/m³

Therefore, the density of the petrol in the storage tank is approximately 703 kg/m³.

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Complete question:

A storage tank contains petrol to a height of 4. 7m. If the pressure at the base of the tank is "32. 3" kPa, determine the density of the petrol. Take the acceleration due to gravity to be 9. 81ms⁻².

net force: 60( not sure)

I would say it's unbalanced because these forces are not of the same magnitude.

The increase in the translational kinetic energy of the yo-yo is 0.0423 J.

To find the increase in the translational kinetic energy of the yo-yo, we need to calculate the work done on the yo-yo by the force applied by the hand.

The work done is given by: W = Fdcos(theta), where F is the force applied, d is the distance moved, and theta is the angle between the force and the displacement.

In this case, theta is 180 degrees since the force and displacement are in opposite directions.

Substituting the given values, we get:

W = (0.235 N)*(0.18 m)*cos(180 deg)

W = -0.0423 J

Since the yo-yo initially had kinetic energy due to its downward motion, the work done by the hand increases the yo-yo's total kinetic energy. The increase in kinetic energy is given by: ΔK = -W

Substituting the value of W, we get: ΔK = 0.0423 J

Therefore, the increase in the translational kinetic energy of the yo-yo is 0.0423 J.

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The mass of the disk is 1.90 kg.We can start by using the formula for torque, which relates torque to angular acceleration and moment of inertia:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

Since the disk is rotating about a perpendicular axis through its center, its moment of inertia can be calculated as:

I_disk = (1/2)MR^2

where M is the mass of the disk and R is its radius.

Similarly, the moment of inertia of the ring can be calculated as:

I_ring = MR^2

where M is the mass of the ring and R is its radius (which is the same as the radius of the disk).

Since the disk and ring have the same mass, we can add their moments of inertia to get the total moment of inertia:

I_total = I_disk + I_ring = (1/2)MR^2 + MR^2 = (3/2)MR^2

Now we can use the given values of torque and angular acceleration to solve for the mass of the disk:

τ = (1/2)MR^2α

0.227 N-m = (1/2)M(0.455 m)^2(0.109 rad/s^2)

Solving for M, we get:

M = 0.227 N-m / [(1/2)(0.455 m)^2(0.109 rad/s^2)] = 1.90 kg

Therefore, the mass of the disk is 1.90 kg.

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The dart will move at velocity approximately 5.0 m/s when it leaves the gun.

To calculate the speed of the dart, we can use the conservation of energy principle. When the spring is compressed, it has potential energy, which is converted into the kinetic energy of the dart when it is released. The potential energy of the compressed spring can be calculated using the formula: PE = 0.5 * k * x^2, where PE is the potential energy, k is the spring constant (250 N/m), and x is the compression distance (0.05 m).

PE = 0.5 * 250 * (0.05)^2 = 0.3125 J (joules)

Now, we can use the kinetic energy formula to find the speed of the dart: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the dart (0.025 kg), and v is the speed. We can rearrange this formula to solve for v:

v = sqrt((2 * KE) / m)

Plugging in the values, we get:

v = sqrt((2 * 0.3125) / 0.025) ≈ 5.0 m/s

Therefore, the speed of the dart when it leaves the gun is approximately 5.0 m/s.

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The wavelengths of the components of the first line of the Lyman series, taking the fine structure of the 2p level into account, are 121.4 nm and 121.2 nm for j = 1/2 and j = 3/2, respectively.

The Lyman series is a series of spectral lines in the hydrogen atom's emission spectrum that corresponds to transitions from higher energy levels to the ground state. The first line of the Lyman series corresponds to a transition from the 2p energy level to the 1s energy level.

To take the fine structure of the 2p level into account, we need to use the formula for the energy of a hydrogen atom with fine structure:

[tex]E= -13.6 eV*\frac{1}{n^{2} } *[1+a^{2} * \frac{(\frac{Z}{n}) ^{4}}{(n-j-\frac{1}{2})^{2} } ][/tex]

where n is the principal quantum number, Z is the atomic number (1 for hydrogen), j is the total angular momentum quantum number of the electron, and α is the fine structure constant.

For the 2p energy level, j can be either 1/2 or 3/2, so we need to calculate the wavelengths for both possibilities. Using the formula for the energy of the 2p level and the energy of the 1s level (-13.6 eV), we can calculate the wavelengths of the first line of the Lyman series with fine structure for each case:

For j = 1/2: λ = 121.6 nm * [1 - (1/9) * α²] = 121.6 nm * 0.9988 = 121.4 nm

For j = 3/2: λ = 121.6 nm * [1 - (4/9) * α²] = 121.6 nm * 0.9972 = 121.2 nm

Taking the fine structure of the 2p level into consideration, the wavelengths of the components of the first line of the Lyman series are 121.4 nm and 121.2 nm for j = 1/2 and j = 3/2, respectively.

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Max would hear the clapping sound at a slightly slower tempo compared to the other students.

Assuming that the speed of sound in air is approximately 343 m/s at room temperature and sea level, we can calculate the time it takes for the sound wave to reach Max's ears.

Using the equation distance = speed x time, we can rearrange it to get time = distance/speed. Plugging in the values, we get time = 80/343 = 0.233 seconds.

The metronome produces sound waves at a constant frequency. At a distance of 80 meters, the sound waves would have to travel a longer distance to reach Max's ears compared to the other students who are closer.

This means that the time it takes for the sound waves to travel from the metronome to Max's ears is longer than for the other students. As a result, Max would hear the clapping sound at a slightly slower tempo compared to the other students.

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When approaching a railroad crossing with no warning device, the speed limit is determined by state law and may vary depending on the specific location and circumstances.

However, there are some general guidelines to keep in mind:

1. Slow down: It is always recommended to slow down when approaching a railroad crossing, regardless of whether there is a warning device or not.

2. Look and listen: Take the time to look and listen for trains before proceeding across the tracks. Even if you don't see or hear a train, it's still important to exercise caution.

3. Be prepared to stop: Be prepared to come to a complete stop if necessary. If you see a train approaching, do not try to beat it across the tracks.

4. Obey signs and signals: Follow any posted signs or signals that indicate the speed limit or provide other warnings about the crossing.

5. Yield to trains: Remember that trains always have the right of way. If a train is approaching, yield to it and wait until it has passed before proceeding.

In general, it's important to approach all railroad crossings with caution, even if there are no warning devices present.

The exact speed limit may vary depending on the location and circumstances, so it's always best to exercise caution and be prepared to stop if necessary.

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Genes are the basic units of heredity. (Los genes son las unidades básicas de la herencia.)

A short stretch of ADN called a gene. The body's genes instruct it on how to produce particular proteins. About 20,000 genes are found in each human body cell. Together, they make up the genetic makeup of the human body and determine how it functions.

Fundamental unit of the inheritance from parents to children. The genes are constructed from ADN sequences and are arranged one after the other in certain locations within the chromosomal nuclei of cells.

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The type of winding that provides moderate voltage and moderate current is called "lap winding." A lap winding connects each armature conductor to the adjacent conductor in a path that runs parallel to the field poles, resulting in multiple parallel paths and a moderate voltage output.

Lap windings are commonly used in direct current (DC) motors and generators, as they provide a balance between high voltage and high current, making them suitable for a range of applications.

The winding is constructed by arranging the armature conductors in concentric circles around the armature core, and then connecting the conductors end-to-end in a continuous loop.

In a lap winding, the number of parallel paths is equal to the number of field poles. This means that a four-pole motor or generator will have four parallel paths, while a six-pole machine will have six parallel paths. The number of parallel paths determines the output voltage and current of the machine, with more parallel paths producing higher output.

In summary, lap winding is a type of armature winding that provides moderate voltage and moderate current, making it suitable for a range of applications. It is constructed by connecting armature conductors in a continuous loop in multiple parallel paths that produce a balanced output.

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The small plate is moving eastward at a rate of 5 millimeters per year. After 1.5 million years, the small plate would be 7,500 meters farther away from the large plate.

To find the rate of motion of the small plate, we can divide the distance it moved by the time it took to move that distance:

Rate of motion = distance/time

In this case, the distance is 150,000 meters and the time is 30 million years, which is equivalent to 30,000,000 years. Converting both values to millimeters and years, respectively, we get:

Rate of motion = (150,000 meters) / (30,000,000 years) * (1000 mm/meter) / (1 year/1)

Simplifying this expression, we get:

Rate of motion = 5 mm/year

To find where the small plate would be after 1.5 million years, we can use the formula:

distance = rate of motion * time

Using the rate of motion we calculated in part 1 (5 mm/year) and the given time of 1.5 million years, we get:

distance = (5 mm/year) * (1.5 million years)

Converting the result back to meters, we get:

distance = 7,500 meters

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Answer:

The lightning struck 1,360 meters away

Explanation:

1. List knowns

Speed of sound = 340 m/s

Time = 4 s

2. Find formula that uses above knowns

Speed = Distance / Time

Distance = Time x Speed

3. Substitute

Distance = 4 s x 340 m/s

Distance = 1360 meters

The position of the harmonic oscillator at t= 0. 8 seconds is 4.76 cm. and The position of the harmonic oscillator at t=2 seconds is -5.72 cm.

A harmonic oscillator is a system that, when disturbed from its equilibrium position, experiences a restoring force proportional to the displacement from equilibrium. Examples of these systems include a mass attached to a spring, pendulums, and AC circuits. When the restoring force is linear, the system is considered a harmonic oscillator.

A. The position of the harmonic oscillator at t= 0. 8 seconds is x = 9 cm cos(2π×0.23×0.8) = 4.76 cm.
B. The position of the harmonic oscillator at t=2 seconds is x = 9 cm cos(2π×0.23×2) = -5.72 cm.
This can be calculated using the formula x = x0 cos(2πTt),
where x0 is the displacement amplitude, T is the period, and t is the time. In this case,
x0 = 9 cm, T = 0.23 seconds, and t = 2 seconds.
So, x = 9 cm cos(2π×0.23×2) = -5.72 cm.

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The work done by the cable on the car is 67500 J.  

To calculate the work done by the cable on the car, we need to use the formula for work, which is:

W = F * d

here W is the work done, So, F is the force applied, and here d is the displacement of the object being moved.

In this case, the force applied by the cable is given by the tension in the cable, which is 1350 N. The displacement of the car is given by the distance it is pulled along the roadway, which is 5.00 km.

We can use the formula for distance to calculate this displacement, which is:

d = 5.00 km

Substituting this value into the formula for work, we get:

W = 1350 N * 5.00 km

W = 67500 J

Therefore, the work done by the cable on the car is 67500 J.  

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