DNA forms two strands. One of the strands of a piece of a DNA molecule has the bases ATA.

Which bases does the other strand have?
Select one:

A: CAC.

B: TAT.

C: GTG.

D: ATA.

Answers

Answer 1

Answer:

b

Explanation:

Combinations between two strands:

T - A

A - T

C - G

G - C

(so if one strand has A for example, then the other strand must have T in the same spot)

Answer 2

Bases   which are present on the other strand of DNA are TAT.

What is DNA?

DNA or deoxyribonucleic acid is a hereditary material present in humans as well as all living beings. Almost every cell present in the body has DNA. Most DNA are located inside the cell , that is in the nucleus of the cell. But a small portion of DNA  can be found in the mitochondria of the cell as well.

The information in DNA is stored as a code which is composed of four chemical bases 1) adenine 2)guanine 3) cytosine  4) thymine . The human DNA consists of 3 billion bases . The order of of these bases determine information which is used for building and maintaining an organism.

The DNA bases can pair with each other .Adenine pairs with thymine   and guanine with cytosine to form units which are called as base pairs.Each base apart from other complementary base it also attaches itself to a sugar and a phosphate molecule.

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Related Questions

The pain reliever morphine contains 17.900 g C, 1.680 g H, 4.225 g O, and 1.228 g N. Determine the empirical Formula.

Answers

Answer: The empirical formula is [tex]C_{17}H_{19}O_3N[/tex]

Explanation:

Mass of C= 17.900 g

Mass of H = 1.680 g

Mass of O = 4.225 g

Mass of N = 1.228 g

Step 1 : convert given masses into moles.

Moles of C =[tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{17.990g}{12g/mole}=1.5moles[/tex]

Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.680g}{1g/mole}=1.680moles[/tex]

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{4.225g}{16g/mole}=0.264moles[/tex]

Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{1.228g}{14g/mole}=0.087moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = [tex]\frac{1.5}{0.087}=17[/tex]

For H = [tex]\frac{1.680}{0.087}=19[/tex]

For O =[tex]\frac{0.264}{0.087}=3[/tex]

For N = [tex]\frac{0.087}{0.087}=1[/tex]

The ratio of C : H: O: N = 17: 19: 3: 1

Hence the empirical formula is [tex]C_{17}H_{19}O_3N[/tex]

19. 1 mole = _____________________ _________________ g

Answers

Answer:

344.1g

Explanation:

What is the difference between an introduced species and an invasive species?

Answers

Answer and Explanation:

The introduced species is, literally, a species that was introduced into an environment by human action. In other words, an introduced species is one that is not native to a region, does not occur naturally, but has been taken by humans to that region.

An invasive species, on the other hand, is one that was introduced naturally in an environment, but multiplied in a harmful way, causing a strong imbalance in the region.

Enter the electron configuration for I+ using noble gas shorthand notation.
In the first box enter the noble gas (notice the brackets). In the following boxes enter the number that goes in front of the orbital followed by the superscript.
For example, the electron configuration for sulfur is: [Ne]3s2 3p4
so the first box would have Ne in it followed by 3, then 2, then 3 then 4.
If you do not need an orbital, just enter 0 (zero) in the boxes for the coefficient and superscript.
[ ] s f d p
Find the element in the periodic table and count over
to the right the number of negative charges on your anion.
This element has the same electron configuration as your anion.
Which noble gas precedes the element? Knowing the s, p, d, and f blocks
of elements in the periodic table, deduce the the electron configuration
of the element from the preceding noble gas. Remember that the
1p 1d, 2d, 1f, 2f, and 3f orbitals are forbidden energy levels (they do not exist).

Answers

Answer:

[Kr] 4d10 5s2 5p4

Explanation:

The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5

However the question requested for the configuration of I+.

I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4

Using Noble gas shorthand representation, we have;

[Kr] 4d10 5s2 5p4

looking at the pure subtances :water,oxygen,copper, can you tell by looking at them if it is pure or not ? explain your answer using example...​

Answers

Answer:

Yes water is a pure, Water, H2O, is a pure substance, a compound made of hydrogen and oxygen. Although water is the most abundant substance on earth, it is rarely found naturally in its pure form. Most of the time, pure water has to be created. Pure water is called distilled water or deionized water.

Oxygen is a chemical element – a substance that contains only one type of atom. Its official chemical symbol is O, and its atomic number is 8, which means that an oxygen atom has eight protons in its nucleus. Oxygen is a gas at room temperature and has no colour, smell or taste

Usually by pure substances we mean either pure elements (all one type of atom), regular crystals (atoms arranged in a repeating pattern), or things made of only one type of molecule (a tightly bound structure of one or more types of atoms). So copper is a pure substance in any form (only copper atoms).

Indicate whether each structure is aromatic, nonaromatic, or antiaromatic. Assume planarity. Compound A is a 5 membered heterocyclic ring containing two pi bonds. On one of the pi bonds is a sulfur with one lone pair and a positive charge. There is an N H group between the two pi bonds with one lone pair. Compound B is a 6 membered ring with three pi bonds. One of the ring atoms is a protonated oxygen with one lone pair. Compound C is an 8 membered ring with a double bond between carbons 2 and 3, between carbons 5 and 6 and between carbons 7 and 8. There is a positive charge on carbon 4 and a negative charge and lone pair on carbon 1. Compound D is a 7 membered ring with three pi bonds. In between two alkenes is a boron attached to a hydrogen. Comppound E is a 7 membered ring with three pi bonds. In between two alkenes is a negative charge with a lone pair.

Answers

Answer:

this some next level stuff homie

Explanation:

imma just guess 7?

The thing being described is shaped like a ring with five parts. Inside the ring, there are two special types of bonds. This has a sulfur that is positively charged and has one unshared pair, also it has an NH group with one unshared pair.

What is the structure

Compound B is a substance that is made up of two or more different elements or molecules.

The thing being described has a ring with six members and three pi bonds. It has an oxygen atom with an extra proton and one extra electron. This substance is not aromatic.

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MnO4 - is a stronger oxidizing agent than ReO4 - . Both ions have charge-transfer (LMCT) bands; however, the charge-transfer band for ReO4 - is in the ultraviolet, whereas the corresponding band for MnO4 - is responsible for its intensely purple color. Are the relative positions of the charge-transfer absorptions consistent with the oxidizing abilities of these ions? Explain

Answers

Answer:

[tex]$MnO^-_4$[/tex]  is a strong oxidizing agent.

Explanation:

The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of [tex]$ReO^-_4$[/tex].

Also, since the molecular orbitals are derived primarily from  3d orbitals of [tex]$MnO^-_4$[/tex] are lower in energy than the corresponding MO's of   [tex]$ReO^-_4$[/tex], [tex]$MnO^-_4$[/tex]  is better able to accept the electrons.

So it is a better oxidizing agent.

The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.

The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.

The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.

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When a chemical reaction occurs, what happens to the atoms of the two substances?

Answers

Answer:

In a chemical reaction, only the atoms present in the reactants can end up in the products. No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

In a chemical reaction, only the atoms present in the reactants can end up in the products. No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Consider the reaction: S(s) O2(g)SO2(g) Write the equilibrium constant for this reaction in terms of the equilibrium constants, Ka and Kb, for reactions a and b below: a.) 2 S(s) 3 O2(g) 2 SO3(g) Ka b.) SO2(g) 1/2 O2(g) SO3(g) Kb

Answers

Answer:

[tex]Ka=\frac{[SO_3]^2}{[O_2]^3} \\\\Kb=\frac{[SO_3]^3}{[SO_2][O_2]^{1/2}}[/tex]

Explanation:

Hello!

In this case, according to the reactions:

a.) 2 S(s) 3 O2(g) ⇔ 2 SO3(g) Ka

b.) SO2(g) + 1/2 O2(g) ⇔ SO3(g) Kb

Thus, according to the law of mass action, we can write Ka and Kb as follows:

[tex]Ka=\frac{[SO_3]^2}{[O_2]^3} \\\\Kb=\frac{[SO_3]^3}{[SO_2][O_2]^{1/2}}[/tex]

Whereas solid carbon is not inserted in the equilibrium expression.

Best regards!

Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 12 moles of Al react with 12 moles of HBr, what is the limiting reactant?

Answers

Answer:

the limiting reactant is HBr

Explanation:

if you tried to make the products using 12 mol Al and 12 mol HBr, the HBr will run out first

How does the chemical formula relate to the number of particles that result from the dissociation of a molecule

Answers

The chemical formula would dictate how many ions are present in a solution. It tells how many of what ion would dissociate in the solution. In every chemical reaction or dissociation reaction, it is important to remember that the number of each atoms on each side would be equal.

The proteins of all living things require
geometry of amino acids.

Answers

As the building blocks of proteins , amino acids are linked to almost every life process, but they also have key roles as precursor compounds in many physiological processes.

Answer:

L

Explanation:

1. What would be the molarity of the sodium ion in solution.​

Answers

Therefore, the molar concentration of sodium ions is just 1 TIMES the molar concentration of sodium chloride. 1 times 0.110 equals 0.110. Therefore: [Na+] = 0.110. Na+ with square brackets around it is read as "molar concentration of Na+".



Detection of iron ions Fe+3 and Fet+2​

Answers

Answer:

The diffrence between Fe2+ and Fe3+ is the Fe2+has a pale green color and turns violet when water is added to it. While Fe3+ forms blood red when it reacts with thiocyanate ions.

Fe2+ has paramagnetic properties whereas

Fe3+ has diamagnetic properties.

Explanation:

I may not be correct.

Answer:

ok                                     ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

Methyl isocyanate, shown as resonance structure 1, can also be represented by other resonance structures. Draw the next most important resonance contributor. Then add curved arrows to each structure to show delocalization of electron pairs to form the other structure.

Include lone pairs of electrons, formal charges, and hydrogen atoms. You can add condensed hydrogens using the More menu, selecting +H and clicking on the carbon as many times as needed.

Answers

Solution :

Structure I

The formal charge on both Carbon (C) atom is = 4 valance [tex]$e^-$[/tex] - bonds = 0

Formal charge (O) = 6 V.E - 2 bonds - 4 non bonding electrons = 0

Formal charge on (N) = 5 V.E - 3 bonds - 2 non bonding electrons = 0

F.C. on H = 1 V.E. - 1 bond = 0

Overall charge on the molecule = 0 charge

Structure II

Formal charge on both C atom = 4 valence [tex]$e^-$[/tex] - 4 bonds = 0

Formal charge (O) = 6 V.E. - 1 bonds - 6 non bonding electrons = -1 charge

Formal charge on (N) = 5 V.E. - 4bonds - 0 non bonding electrons = +1 charge

F.C on H = 1 V.E. - 1 bond = 0

Overall charge on the molecule = +1 -1

                                                     = 0 charge

What is the molar mass of Ammonium Carbonate?

Answers

Explanation:

Molar mass

96.09 g/mol

glad to help....

What is the half life of the graphed material?

Answers

Answer:

3 hours

Explanation:

To know the the correct answer to the question given above, it is important we know the definition of half-life.

The half-life of a substance is simply defined as the time taken for half the substance to decay.

Considering the diagram given above, the initial mass of the substance is 100 g.

Half of the initial mass = 100 / 2 = 50 g

Now, we shall determine the time from the graph taken to get to 50 g.

Considering the diagram given above, the time taken to get to 50 g is 3 hours.

Therefore, the half-life of the material is 3 hours.

In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water bath and the fastest trial done at room temperature in the cold water bath?

Answers

Answer:In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water bath and the fastest trial done at room temperature in the cold water bath?

Explanation:

A chemist determined by measurements that 0.0650 moles of gallium participated in a chemica reaction. Calculate the mass of gallium that participated in the chemica reaction

Answers

Answer:

4.53gm

Explanation: n=m/M

n is # of moles

m is mass

M is molar mass

so m=n*M when you rearrange the equation

Why do you think the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene?

Answers

Answer:

See explanation

Explanation:

The reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate as well as the reaction of  tetraphenylcyclopentadienone and diphenylacetylene are  Diels Alder reactions. The former is performed in presence of a solvent while the former is performed neat.

The reaction of tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate leads to the formation of a more resonance-stabilized aromatic ring(lower energy product) compared to the reaction of  tetraphenylcyclopentadienone and diphenylacetylene.

Hence, the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene.

Tengo que resolver con procedimiento
1. Un automóvil viaja a una velocidad de 100 Km/h durante dos horas. Calcular la distancia recorrida.



2. Un automóvil viaja a una velocidad de 68 Km/h durante tres horas. Calcular la distancia recorrida.





3. Un auto recorre 154 Km en dos horas. ¿Cuál fue su velocidad?



4. Un auto recorre 1500 Km, si lo hace a una velocidad de 70 Km/h, ¿cuánto tardo en hacerlo?.​

Answers

Answer:

Distance = 200 km

Distance = 204 km

Speed = 77 km/h

Time = 21.42 h

Explanation:

Given:

A.

Speed = 100 km/h , Time = 2 h

Find:

Distance

B.

Speed = 68 km/h , Time = 3 h

Find:

Distance

C.

Distance = 154 km , Time = 2 h

Find:

Speed

D.

Distance = 1500 km speed = 70 km/h

Find:

Time

Computation:

Speed = distance / time

A.

Distance = 100 x 2

Distance = 200 km

B.

Distance = 68 x 3

Distance = 204 km

C.

Speed = 154 / 2

Speed = 77 km/h

D.

Time = 1500 / 70

Time = 21.42 h

How are algae and polyps related?
The polyps receive carbon dioxide from the algae.
The polyps receive shelter from the algae.
The polyps get most of their food from the algae.
The polyps embed themselves in the flesh of the algae.

Answers

Answer:

The polyps get most of their food from the algae.

Explanation:

If a solution containing 24.0 g of a substance reacts by first-order kinetics, how many grams remain after three half-lives?

Answers

Answer:

3.0g remain

Explanation:

The half-life is defined as the time required for a reactant to decrease its concentration in exactly the half of the initial amount of reactant. Having this in mind:

In one half-life, the mass will be:

24.0g / 2 = 12.0g

In two half-lifes:

12.0g / 2 = 6.0g

And in three half-lifes, the mass that remain is:

6.0g / 2 =

3.0g remain

Excess silver(I) nitrate was added to a 8.500 g mixture containing some amount of barium chloride, and 7.123 g of silver chloride was obtained. The unbalanced equation is
AgNO3 + BaCl2(aq) --> Ba(NO3)2(aq) + AgCl(s).
What is the mass% of BaCl2 in the mixture?

Answers

Answer:

60.88%

Explanation:

The balanced equation of the reaction is given as;

2 AgNO3 (aq) + BaCl2 (aq) → 2 AgCl (s) + Ba(NO3)2 (aq)

Since AgNO3 is in excess, the limiting reactant is BaCl2. From the reaction;

1 mol of BaCl2 produces 2 mol of AgCl

Converting to masses;

Mass = Number of mol * Molar mass

BaCl2;

Mass = 1 * 208.23 g/mol = 208.23 g

AgCl;

Mass = 2 * 143.32 g/mol = 286.64 g

208.23 g BaCl2 produces 286.64 g of AgCl

x g BaCl2 produces 7.123 g of AgCl

Solving for x;

x = 7.123 * 208.23 / 286.64 = 5.1745 g

Mass percent = Mass / Total mass of Mixture  * 100

Mass Percent = 5.1745 / 8.500 = 0.6088 * 100 = 60.88%

1) _PA+ __02 → _P,03

Answers

hwyheheygegtwgt.............



I have calculated 23 grams of water in a laboratory. What is the amount of molecules

present in this amount?

a. None of the above

b. 8.3x10^24 molecules

c. 6.9x10^23 molecules

d. 7.7x10^23 molecules

e. 5.6x10^25 molecules

Answers

Answer:

d. 7.7x10^23 molecules

Explanation:

Given the following data:

Mass of water (H2O) = 23g

To find the number of molecules;

First of all, we would determine the number of moles;

[tex] Number \; of \; moles = \frac {mass}{molar mass} [/tex]

Molar mass of water (H2O) = (1 * 2) + 16 = 18 g/mol

Substituting into the equation, we have

[tex] Number \; of \; moles = \frac {23}{18} [/tex]

Number of moles = 1.2778 moles

Now, to find the number of water molecules;

We know that Avogadro constant is equal to 6.02 * 10^23 mol¯¹

Number of water molecules = number of H2O moles * Avogadro constant

Substituting into the equation, we have;

Number of water molecules = 1.2778 × 6.02 * 10^23

Number of water molecules = 7.7 × 10^23 atoms.

A sample of acid rain turned
universal indicator yellow. What would you expect its pH to be? Is it a strong or a weak acid?

Answers

Answer:

i think it would be 3 or lower

Answer:

A universal indicator shows a greenish-yellow colour for pH 6 and orange yellow for pH 5. This means that if the indicator turns yellow, the pH should be between these two values. Hence, it must have a pH value between 5 and 6. As the pH is closer to 7 (between 5 and 6), it is a weak acid.

Explanation:

Trust the correct answer

How might the shoot systems and the digestive system in a human be similar? Help please

Answers

Answer: The both Deal with digesting and getting rid of waste

Explanation:

Digestive system deals with getting rid of waste in your body and breaking down food.

The digestive system in a human is similar to the shoot system in a plant because both systems are involved in the transport of food materials and waste products in the organism.

The plant is composed of the root system and shoot system. The root system is beneath the ground while the shoot system is above the ground.

In humans, the digestive system carries food materials and waste from the alimentary canal to the small intestine. In plants, the shoot system also performs the same function of carrying food materials and waste products.

Hence, In the shoot system in plants performs a similar function to the digestive system in humans.

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No pain no gain . which figure of speech is this​

Answers

Answer:

No pain, no gain is a proverb that means in order to make progress or to be successful, one must suffer. This suffering may be in a physical or mental sense. The phrase no pain, no gain was popularized in the 1980s by the American actress, Jane Fonda.

Oxygen and hydrogen are both elements that are found as gases at room temperature. When oxygen combines with hydrogen, they produce the compound water according to the chemical equation below.
O2 + 2 H2 2 H2O

Water is a liquid at room temperature. This example shows that in a chemical equation, the substance that is produced

A.
has properties that are different from the original substances.
B.
can only contain a single type of element.
C.
contains fewer types of elements than the original substances.
D.
always has the same properties as the original substances.

Answers

Answer:

A

Explanation:

has properties that are different from the original substances.

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