divide to 7 digits after the decimal point. Do not round your answer 3.1 divided by 6

The actual rocket height is 1080 inches and the height of the actual rocket is 90 feet.

If the 1/20 scale model of the rocket stands 54 inches high, we can find the height of the actual rocket by multiplying the height of the model by 20:

Actual rocket height = 54 inches x 20 = 1080 inches

In order to convert inches to feet, we divide by 12:

Actual rocket height = 1080 inches / 12 = 90 feet

Therefore, the height of the actual rocket is 90 feet.

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The 1/20 scale model of the rocket stood 54 inches high What was the height of the actual rocket?

(b) Find the height of the actual rocket in feet.

2nd and 4th is correct. Hope you got it!

The value of,

Given function f(x) = cx for 1 ≤ x ≤ 2

a) To find the value of constant x, we have to use the following p.d.f condition as shown below,

[tex]\int\limits^a_b {x} \, dx =1[/tex]

here, a is -∞ and b is ∞.

From the above condition to find the value of c,

[tex]\int\limits^2_1{cx^2} \, dx[/tex] = 1

c * [[tex]\frac{x^3}{3}[/tex]]²₁ = 1

c * [8/3 - 1/3] = 1

c * 7/3 = 1

c = 3/7.

b) To find the value of P(x>3/2) we have to substitute the value of 3/2 in the given expression of f(x) = 3/7 * x²

f(3/2) = 3/7 * (3/2)²

         = 3/7 * 9/4

         = 27/28.

From the above solution, we solved both problems.

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The rocket will hit the ground after 19.09 seconds.

a) The height of the rocket can be describe as:

h(t) = -16t² + 210t + 75

where

t = time in seconds

h(t) = height of the rocket in feet

b) To find the time at which the rocket reaches its maximum height, we need to find the vertex of the parabolic function. The vertex is given by the formula:

t = -b/(2a)

where

a = -16

b = 210

Substituting these values, we get:

t = -210/(2(-16)) = 6.5625 seconds

To find the maximum height, we substitute this value of t back into the equation for h(t):

h(6.5625) = -16(6.5625)² + 210(6.5625) + 75 = 690.625 feet

This means that the rocket reaches its maximum height of 690.625 feet after 6.5625 seconds.

c) We need to find the time interval during which the height of the rocket is greater than 721 feet. We set the height function h(t) greater than 721 and solve for t:

-16t² + 210t + 75 > 721

-16t² + 210t - 646 > 0

Solving for t using the quadratic formula, we get:

t < 2.975 or t > 14.038

Therefore, the rocket will be more than 721 feet above ground level between 0 and 2.975 seconds, and between 14.038 and infinity seconds.

d) To find the time at which the rocket hits the ground, we set h(t) equal to 0 and solve for t:

-16t² + 210t + 75 = 0

Solving for t using the quadratic formula, we get:

t = [tex]\frac{-b \± \sqrt{b^{2} - 4ac } }{2a}[/tex]

a = -16, b = 210, c = 75

t = [tex]\frac{-210 \± \sqrt{210^{2} - 4(16)(75) } }{2(-16)}[/tex]

t = [tex]\frac{-210 \± \sqrt{22225} }{-32}[/tex]

t = [tex]\frac{-210 \± 149}{-32}[/tex]

t = 2.53125 or t = 13.53125

Since the rocket was launched from the top of a 75-foot building, it will hit the ground after an additional time of:

t + 2.53125 = 5.09375 seconds or t + 13.53125 = 19.09375 seconds

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The transformation of f(x) that will produce g(x) is given as follows:

g(x) = f(x)/4.

If we observe at the table, we have that each value of g(x) is one fourth of the value of the function f(x).

Hence the transformation of f(x) that will produce g(x) is given as follows:

g(x) = f(x)/4.

The transformation means that the function g(x) is a vertical compression by a factor of 4 of the function f(x).

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Answer:

Step-by-step explanation:

The size of each interior angle of the polygon is 4x+28 °

The value of x is 34 degree and y is 56 degree.

Tangents to circles are lines that cross the circle at a single point. Point of tangency refers to the location where a tangent and a circle converge. The circle's radius, where the tangent intersects it, is perpendicular to the tangent. Any curved form can be considered a tangent.

here, we have,

We have, BOA is an isosceles triangle.

< CBO = 90°

So, < DBO = 90 - 56

<DBO = 34

and, <ODB = 34°

Now, let the angle ODB be x

As, from the figure < EBD is also 90°

So, <y = 180 - (90+34)  (Angle sum property)

<y = 56

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complete question:

Work out the size of angle x and work out the size of angle y

B = (715x) / (h^2)

Step 1: Get rid of the denominator by multiplying both sides by h^2

(B)(h^2) = 715x

Step 2: Isolate x by dividing both sides by 715

(Bh^2) / 715 = x

Answer: x = Bh^2 / 715

Hope this helps!

Rounding to three decimal places, the confidence interval is (0.419, 0.574).

The sample proportion, p′ = 0.842, which is the point estimate of the population proportion, must be determined in order to calculate the confidence interval. Given that CL = 0.95 is the requested confidence level, = 1 - CL = 1 - 0.95 = 0.05 ( 2) ( 2) = 0.025.

Confidence interval=proportion±margin of error

CI = p ± ME

The proportion is:

p = x / n

p = 55/110

p = 0.5

Margin of error=critical value × standard error

ME = CV × SE

n > 30, so we can approximate CV with a normal distribution.

At P=88%, CV=1.55.

SE = √(pq / n)

SE = √(0.5 (1−0.5)/110)

SE = 0.048

So the margin of error is:

ME = 1.55 × 0.048

ME = 0.074

So the confidence interval is:

CI = 0.5 ± 0.074

CI = (0.426, 0.574)

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Question:

Use the given degree of confidence and Sample data to construct income confidence interval for the population proportion p. n=110, x=55; 88% confidence

A) 0.426 B)0.442 C)0.425 D)0.421

The area of the shaded region is 51.75 in².

From the figure

Radius of semicircle = √25² - 20²

                                  =√625-  400 = 15 inch

Now, Area of Trapezium = 1/02 ( a +b ) h

= 1/2 (17 + 37) x 15

= 1/2 (54) x 15

= 27 x 15

= 405 in²

Then, Area of Shaded region

= Area of Trapezium -  Area of semicircle

= (405 - πr²)

= 405 - 353.25

= 51.75 in²

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Heracio used the computer 4 more hours to do homework than shop online.

To find out how many more hours Heracio used the computer to do homework than shop online, we first need to calculate the number of hours he spent on each activity.

Let's start by calculating the number of hours Heracio spent on each activity:

Shopping: 10% of 40 hours = 4 hours

Videos: 15% of 40 hours = 6 hours

Homework: 20% of 40 hours = 8 hours

Games: 20% of 40 hours = 8 hours

Social media: 25% of 40 hours = 10 hours

Now, to find out how many more hours Heracio used the computer to do homework than shop online, we need to subtract the number of hours spent shopping from the number of hours spent on homework:

8 hours (homework) - 4 hours (shopping) = 4 hours

Therefore, Heracio used the computer 4 more hours to do homework than shop online.

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Answer:

5 baby goats

Step-by-step explanation:

4 + 1 = 5 pints total

each baby goat gets 1 pint

The station earned $1485 in revenue from selling the gas.

In this problem, we are given two vectors, v and w, representing the number of gallons of gas sold at a station and the corresponding prices per gallon, respectively. We are asked to find the dot product of these two vectors, which is a scalar quantity known as the "Vw". We will then interpret the meaning of this dot product in practical terms.

To find the dot product of v and w, we will use the formula:

Vw = v . w = (210)(2.8) + (300)(2.99)

Vw = 588 + 897 = 1485

Therefore, the value of Vw is 1485.

Practical terms: The dot product of two vectors is a scalar quantity that represents the "projection" of one vector onto the other. In this case, the dot product Vw represents the total revenue earned by selling regular and premium gasoline at the given station.

The components of v represent the number of gallons of regular and premium gas sold, while the components of w represent the respective prices per gallon for each kind of gas. Multiplying the number of gallons sold by the price per gallon gives the total revenue earned for each type of gas. Adding these two values together gives the total revenue earned for both types of gas.

Therefore, the dot product Vw represents the total revenue earned by selling all the gas at the given station. In practical terms, this means that the station earned $1485 in revenue from selling the gas.

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Step-by-step explanation:

58 g = 660 g * ( 1/2)^n

58 / 660 = (1/2) ^n       LOG both sides

-1.056 = n log 1/2

n = 3.508 half lives  

     3. 508  x 10 min = ~ 35.1 min

[tex]\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\dotfill & 58\\ P=\textit{initial amount}\dotfill &660\\ t=minutes\dotfill &t\\ h=\textit{half-life}\dotfill &10 \end{cases} \\\\\\ 58 = 660\left( \cfrac{1}{2} \right)^{\frac{t}{10}} \implies \cfrac{58}{660}=\left( \cfrac{1}{2} \right)^{\frac{t}{10}}\implies \cfrac{29}{330}=\left( \cfrac{1}{2} \right)^{\frac{1}{10}\cdot t}[/tex]

[tex]\log\left( \cfrac{29}{330} \right)=\log\left[ \left( \cfrac{1}{2} \right)^{\frac{1}{10}\cdot t} \right]\implies \log\left( \cfrac{29}{330} \right)=t\log\left[ \left( \cfrac{1}{2} \right)^{\frac{1}{10}} \right] \\\\\\ \cfrac{ ~~ \log\left( \frac{29}{330} \right) ~~ }{\log\left[ \left( \frac{1}{2} \right)^{\frac{1}{10}} \right]}=t\implies 35.1\approx t[/tex]

Answer: 2.303

Explanation: In image

In this circumstance, the sample consists of 1,200 inhabitants living within a ten-mile radius of the movie theater that were selected for random deliberation by the overseer.

Samples are frequently utilized to gain information concerning a larger population through the study of a single set of individuals or objects. The aim of selecting a sample is to inspect the populace by delving into a representative, relatively small group.

Surveys, polls, and experiments often utilize samples to make evidence-based inferences regarding the target population. For exact and dependable results, an instance should be randomly chosen, accurately mirroring those present in the whole population so as to reduce prejudice and fully optimize the evaluation.

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Answer:

Step-by-step explanation:

An inequality can be represented graphically as a region on one side of a line. Inequalities that use < or > symbols are plotted with a dashed line to show that the line is not included in the region. Inequalities that use ≤ or ≥ symbols are plotted with a solid line to show that the line is included in the region.

Unit fractions are the fraction in which the value of numerator is 1. The multiple of the given fraction are,

1/9 = 2/9, 3/9, 4/9,5/9         ......so on.

Here, we have,

To find the multiple of the fraction 1/9 we need to know about the multiple of fraction.

We have,

Multiple of fraction is the number which is n times of the original function. Here  can be any whole or fraction number.

The given number in the problem is the fraction number which is,

The above number is the unit fraction.

Unit fraction-

Unit fractions are the fraction in which the value of numerator is 1.

The multiple of unit fraction is in times the original function. For the given fraction the multiple fraction can be given as,

1/9 = 2/9, 3/9, 4/9,5/9            .......so on.

Hence the multiple of the given fraction are,

1/9 = 2/9, 3/9, 4/9,5/9             ......so on.

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So it would take A 10 days to do the whole job alone.

An equation is a statement that asserts the equality of two expressions. It typically contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, exponentiation, etc. The goal of solving an equation is to find the values of the variables that make the equation true. Equations are used in a variety of mathematical contexts, including algebra, calculus, and geometry, as well as in physics, engineering, and many other fields.

Here,

Let's denote A's speed as "a" and B's speed as "b" (in units of work per day). Then, we know that:

In 5 days, A and B together completed the job, so we can write: 5(a + b) = 1 (where 1 represents the whole job).

If A worked at twice the speed (2a) and B worked at half the speed (0.5b), then they would complete the job in 4 days, so we can write: 4(2a + 0.5b) = 1.

We can simplify the second equation by multiplying out the brackets and collecting like terms:

8a + 2b = 1

Now we have two equations with two unknowns. We can solve for one of the variables in terms of the other, and substitute the result into the other equation to find the value of the remaining variable. Let's solve for "b" in terms of "a" from the first equation:

5(a + b) = 1

5b = 1 - 5a

b = (1/5) - a

Now we can substitute this expression for "b" into the second equation:

8a + 2b = 1

8a + 2((1/5) - a) = 1

8a + (2/5) - 2a = 1

6a = (3/5)

a = (1/10)

So A can do 1/10 of the job in one day. To find out how long it would take A to do the whole job alone, we can use the formula:

time = amount of work / rate

Since A can do the whole job alone, the amount of work is 1, and A's rate is 1/10. Therefore:

time = 1 / (1/10)

= 10 days

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The image point of the coordinate X after the rotation is (-1, 5).

When a point is rotated 90° clockwise around the origin, the new point will be formed by switching the x and y-coordinates and then negating the new x-coordinate.

So for point X (-5, -1), the new x-coordinate will be -1, and the new y-coordinate will be -(-5) = 5, giving the new point (-1, 5).

Therefore, after a rotation of 90° clockwise, point X (-5, -1) will be at the new location (-1, 5).

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Answer:

No, i do not believe i have learned this yet so good luck bestiee

The total amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark is 720 liters.  

The amount of fluid that moves through a pipe or other container over a given amount of time.

The amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark can be calculated using the equation for the rate at which the water is flowing.

Given that the rate at which the water is flowing at time t is r(t)=200-4t liters per minute and that 0≤t<50, the total amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark can be calculated as follows:

Total amount of water = ∫r(t)dt  

                   = ∫(200 - 4t)dt  

                   = (200t - 4t²)  

                   = (200(37) - 4(37²)) - (200(7) - 4(7²))  

                   = 1924 - 1204  

                   = 720 liters

The rate of flow decreases linearly with time, which means that the total amount of water flowing from the tank at any given time is equal to the area under the graph of the rate of flow.

This means that the total amount of water that flows from the tank between the 7 minute mark and the 37 minute mark can be calculated by integrating the rate of flow function over the given time interval.

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Answer:

B.

Step-by-step explanation:

As the steps imply,

The probability of rolling an even or divisible by 3 numbers is 2/3

When a single fair die is rolled, there are six possible outcomes:

1, 2, 3, 4, 5, or 6.

Of these outcomes, three are even (2, 4, and 6) and two are divisible by 3 (3 and 6). However, since the number 6 is both even and divisible by 3, we must count it only once to avoid overcounting. Thus, four outcomes are either even or divisible by 3: 2, 3, 4, and 6.

The probability of rolling an even or divisible by 3 number is the sum of the probabilities of these four outcomes, which is:

P(even or divisible by 3) = P(2) + P(3) + P(4) + P(6)

= 1/6 + 1/6 + 1/6 + 1/6

= 4/6

= 2/3

Therefore, the probability of rolling an even or divisible by 3 numbers is 2/3

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Answer:

Step-by-step explanation:

-9+6-1-2-3-4+5-6

-3-3-7-1

-6-8

-14

Answer:

The answer is -14.

Step-by-step explanation:

-(9 - 6) + (-1 -2) - (3 + 4) + (5 - 6)

Subtract 6 from 9 to get 3.

-3 -1 -2 - (3 + 4) + 5 - 6

Subtract 1 from -3 to get -4.

-4 - 2 - (3 + 4) + 5 - 6

Subtract 2 from -4 to get -6.

-6 - (3 + 4) + 5 - 6

Add 3 and 4 to get 7.

-6 - 7 + 5 - 6

Subtract 7 from -6 to get -13.

-13 + 5 - 6

Add -13 and 5 to get -8.

-8 - 6

Subtract 6 from -8 to get -14.

-14.

The solutions to this quadratic equation are x = √(73/3) + 5 or x = -√(73/3) + 5.

In Mathematics and Geometry, the standard form of a quadratic equation is represented by the following equation;

ax² + bx + c = 0

Next, we would solve the given quadratic equation by using the completing the square method;

3x² - 30x = -2

By dividing all through by 3, we have:

x² - 10x = -2/3

In order to complete the square, we would have to add (half the coefficient of the x-term)² to both sides of the quadratic equation as follows:

x² - 10x + (-10/2)² = -2/3 + (-10/2)²

x² - 10x + 25 = -2/3 + 25

x² - 10x + 25 = 73/3

By simplifying, we have;

(x - 5)² = 73/3

x = √(73/3) + 5 or x = -√(73/3) + 5

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The area of a shape is calculated by calculating the amount of space on the shape

By definitinon, the area of a shape is the amount of space on the shape

using the above as a guide, we have the following:

There are several formulas to calculate area

The formula to use is dependent on the shape whose area is being calculated

This means that the area of trapezoid cannot be calculated using the area of parallelogram

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Answer:

Step-by-step explanation:

y=-3x-1

format for formula:

y=mx+b

b=1  that is your y-intercept.  where it hits the y-axis

m= -3    this is your slope    [tex]\frac{rise}{run} =\frac{-3}{1}[/tex]  

from a point you have, the y-intercept, you go down 3 (because of the negative in front of it), this is your rise,
and to the right 1, this is your run

The probability of rolling a 4 on a single throw of a fair 6-sided die is 1/6, since there is only one way to roll a 4 and there are 6 equally likely outcomes in total.

The probability of rolling an even number on a single throw of a fair 6-sided die is 3/6, or 1/2, since there are three even numbers (2, 4, and 6) out of six possible outcomes.

To find the probability of rolling a 4 or an even number on a single throw, we can add the probabilities of these two events:

P(4 or even) = P(4) + P(even) - P(4 and even)

where P(4 and even) is the probability of rolling a 4 and an even number on the same throw. Since there is only one outcome (rolling a 4), which is not even, this probability is 0.

Therefore:

P(4 or even) = P(4) + P(even) - P(4 and even)

             = 1/6 + 1/2 - 0

             = 2/3

So the probability of rolling a 4 or an even number on a single throw of a 6-sided die is 2/3.

If the die is thrown 2 times, the probability of rolling a 4 or an even number on both throws is the product of the probabilities of rolling a 4 or an even number on each throw:

P(4 or even on both throws) = P(4 or even) × P(4 or even)

                           = (2/3) × (2/3)

                           = 4/9

Therefore, the probability of rolling a 4 or an even number on both throws of a 6-sided die is 4/9.

The accrued value of the account in 10 years is $641.75

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

Amount = P * (1 + 0.25r)ᵗ

Where

P = Principal = 600

r = Rate = 2.7% = 0.27

t = time = 10

Substitute the known values in the above equation, so, we have the following representation

Amount = 600 * (1 + 0.25 * 0.27)¹⁰

Evaluate

Amount = 641.75

Hence, the amount is 641.75

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Answer:

351 cm^3

Step-by-step explanation:

The base of a right prism ABC is an isosceles triangle with AB = BC and m∠ACB 35°. The diagonal of lateral face ABA is 18 cm and m∠BAB = 50°. Find the volume of the prism. Round your answer to the nearest cm

ChatGPT

Let AB = BC = x be the base of the isosceles triangle ABC. Then, the third side AC is:

AC = 2x * sin(35°)

Using the sine rule in triangle ABA, we have:

AB / sin(50°) = 18 / sin(80°)

Solving for AB, we get:

AB = 18 * sin(50°) / sin(80°)

The height of the prism is AB * cos(35°). Therefore, the volume of the prism is:

V = (1/2) * x^2 * 2x * sin(35°) * AB * cos(35°)

Substituting the values we have calculated, we get:

V = (1/2) * x^2 * 2x * sin(35°) * [18 * sin(50°) / sin(80°)] * cos(35°)

V ≈ 351 cm^3

Therefore, the volume of the prism is approximately 351 cubic centimeters.