determine how many grams of N2 are produced from the reaction of 8.73
g of H2O2 and 5.16
g of N2H4.

For the reactants,

For the products,

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: [tex]\text{H}_{3}\text{AsO}_{4}[/tex]

formula of the reducing agent: [tex]\text{H}_{2}\text{C}_{2}\text{O}_{4}[/tex]

Answer:

Neither accurate not precise

The Correct option is A. octahedral

because the molecule has 6 sigma bonds that results into sp³d² hybridization.

and octahedral structure is formed

Answer:

Octahedral

Explanation:

You have a atom connected to 6 others and each of the bonds are similar

C= 87.8 : 12 = 7.316

H= 12.2 : 1 = 12.2

C : H = 1 : 1.667 =  3 : 5

C₃H₅

The percentage of the area under the normal distribution curve would lie above 98.02 on the x-axis is 2.5 % , option C is the answer.

Normal Distribution is a probability distribution which is symmetric about the mean , The frequency is more near the mean and less far from the mean.

It is given in the data that

10,000 more observations were collected

the percentage of the observations would be greater than 98.02 = ?

According to the 68-95-99.7 rule,

It states that approximately

68% of the observations lie within σ of µ

95% of the observations lie within 2σ of µ.

99.7% of the observations lie within 3σ of µ.

The percentage of the observation between various intervals is attached in the image in the answer.

2.1 percent of the population is distributed in the intervals between two and three standard deviations , which is the zone above 2SD and below 3SD.

As 2.1 % is approximate , Therefore from the given option , 2.5%

The percentage of the area under the normal distribution curve would lie above 98.02 on the x-axis is 2.5 % , option C is the answer.

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From the calculations, the concentration of the acid is 0.24 M.

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

VA =  50 mL

VB = 20 mL

NA = 1

NB = 2

CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

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If a snail crawls at a rate of 228.16cm/s, Its speed in miles per hour will 5.10 miles/hour

The rate at which someone or something moves or operates or is able to move or operate.

Snail covers distance in 1 seconds = 228.16 cm

It covers in 60 seconds (1 min) = 228.16 cm x 60 = 6mtrs

It covers in 60 minutes (1 hour) = 228.16 cm x 60 x 60 = 821376 cm

Now, lets convert cm to miles :

As,                    1 cm = 6.21371 x 10⁻⁶ miles

Thus,     821376 cm = 5.10 miles

hence, If a snail crawls at a rate of 228.16cm/s, Its speed in miles per hour will 5.10 miles/hour

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A catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy without itself being consumed by the reaction.

Answer:

[tex]\fbox {2 moles}[/tex]

Explanation:

Relation between grams of Carbon and moles :

[tex]\fbox {12 g Carbon = 1 mole}[/tex]

Multiply both sides by 2 :

⇒ 1 x 2 moles = 12 x 2 g

⇒ 2 moles = 24 g

This is because fall has more weather patterns which are repetitive than summer.

This is defined as the atmospheric condition of a particular place at a given period of time.

The repetitive weather patterns have various effects on the stars which is why they were studied.

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The experimental absolute zero value is less when compared to the accepted value of absolute zero.

Absolute zero is defined as the temperature in which the lowest energy possible is attained in a thermodynamic system.

Absolute zero temperature has an accepted values of 0 Kelvin or -273.15 degrees Celsius.

At absolute zero, it is assumed that the volume of an ideal gas becomes zero. However, it has not been possible to cool any gas to absolute zero.

Based on the graph of temperature against volume of gases, the experimental absolute zero extrapolated from the graph where volume of the gases becomes zero is -285 degrees Celsius.

Therefore, the experimental absolute zero value is less when compared to the accepted value.

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Answer:

The experimental absolute zero value is less when compared to the accepted value of absolute zero.What is absolute zero?Absolute zero is defined as the temperature in which the lowest energy possible is attained in a thermodynamic system.Absolute zero temperature has an accepted values of 0 Kelvin or -273.15 degrees Celsius.At absolute zero, it is assumed that the volume of an ideal gas becomes zero. However, it has not been possible to cool any gas to absolute zero.Based on the graph of temperature against volume of gases, the experimental absolute zero extrapolated from the graph where volume of the gases becomes zero is -285 degrees Celsius.Therefore, the experimental absolute zero value is less when compared to the accepted value.

Explanation:

5.50M NaOH must be added to 680.0 mL of a buffer, The amount of NaOH  is mathematically given as

V=2.107mL

Generally, the equation for Chemical Reaction is mathematically given as

CH3COOH+OH^{-} ⇄ CHCOO^{-} + H2O

Therefore

pka=-log(1.8*10{-5})

pKa=5-0.25527

pKa=4.3447

Hence

[tex]pH=pKa+log\frac{CH3COO}{CH3COOH}\\\\0.75=4.7447+log\frac{0.01564+x}{0.01428-x}[/tex]

x=0.0115898

Volume of NaOH

V=0.0021072L

V=2.107mL

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Answer:

C. electricity conductive

The possible action your solution might contain is amongst [tex]Ag^+[/tex], [tex]Pb^{2+}[/tex], or [tex]Ca^{2+}[/tex].

A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.

NaCl: 20 drops of NaCl were used and no precipitate was formed.

No precipitation formed means the [tex]Cl^-[/tex] cation is soluble in water. From your chart, you might see the halide of [tex]Ag^+[/tex] and [tex]Pb^{2+}[/tex] is insoluble in water, which means they should have formed precipitation but you didn't. This means there's less possibility it contains [tex]Ag^+[/tex] or [tex]Pb^{2+}[/tex], so we are left with only [tex]Ca^{2+}[/tex]. Let's confirm it with the rest.

[tex]Na_2SO_4[/tex] : 20 drops of [tex]Na_2SO_4[/tex] were used yellow precipitate was produced.

Even though all other sulfates form precipitation ( Insoluble in water)

[tex]Na_2CO_3[/tex] : 20 drops of sodium carbonate were used and the silver-blue precipitate was produced.

It seems all of their Carbonate is insoluble in nature. ( which is our case too ).

From the above result, only the reaction with NaCl was deemed to be decisive and it indeed contains [tex]Ca^{2+}[/tex] ions. Means you are correct.

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Answer:

Solution Density of aluminium = 2.7 g/Cm 3 In kg/ m 3 = 27 × 1000 10 =2700 kg/ m 3

Explanation:

Not much of one

The phenomenon known as "salting-out" occurs at very high ionic strengths, when protein solubility declines as ionic strength rises. As a result, salting out may be used to segregate proteins according to how soluble they are in salt solutions.

Because large levels of sodium chloride disturb the bonds and structure of the active site, the rate of enzyme activity will gradually decrease as the concentration of sodium chloride rises. As a result, some of the active sites get denaturized and the starch loses its ability to attach to them. As more enzymes get denatured and eventually cease to function, enzyme activity will steadily wane.

Answer:

1.46 moles NaCl

Explanation:

To find the moles of NaCl, you need to multiply the given value (0.731 moles BaCl₂) by the mole-to-mole ratio of the two relevant molecules. This ratio is made up of the coefficients in the balanced reaction. The numerator should contain moles NaCl to allow for the cancellation of moles BaCl₂. The final answer should have 3 sig figs to reflect the given value.

1 BaCl₂(aq) + Na₂SO₄(aq) ---> BaSO₄(s) + 2 NaCl(aq)

0.731 mole BaCl₂           2 moles NaCl
---------------------------  x  -------------------------  = 1.46 moles NaCl
                                         1 mole BaCl₂

If 0.731 mol of BaCl₂ is allowed to react with an excess of Na₂SO₄, 1.462  moles of NaCl will be produced.

The balanced chemical equation is:

BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)

The mole ratio of BaCl₂  to NaCl is 1:2. This means that 1 mole of BaCl2 will produce 2 moles of NaCl.

Moles of BaCl₂  = 0.731 mol

Mole ratio BaCl₂:NaCl = 1:2

Moles of NaCl = 0.731 mol * 2 = 1.462 mol

If we have 0.731 moles of BaCl₂, then we will produce 2 * 0.731 = 1.462 moles of NaCl.

Therefore, 1.462 moles of NaCl will be produced.

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Answer:

1 C₂H₆O

Explanation:

The given equation:

C₂H₆O + 3 O₂ ---> 2 CO₂ + 3 H₂O

Reactants: 2 carbon, 6 hydrogen, 7 oxygen

Products: 2 carbon, 6 hydrogen, 7 oxygen

As you can see, the amount of each element on both sides is identical. Therefore, the reaction is already balanced. This means that the coefficient in front of C₂H₆O is 1. When writing the equation, writing the one is insignificant and usually left out.

The northern slope will have the least precipitation if winds blow against a mountain from the south.

This is referred to as the degree of steepness on a surface such as rocky areas etc.

When wind blows on the southern part of a mountains, it gets stuck which is why the northern slope have the least precipitation.

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The specific heat of the metal object with a mass of 22.7g heated to to temperature of 97.0°C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C is 0.815J/g°C

How to calculate specific heat?

The specific heat capacity of a metal can be calculated using the calorimetry equation as follows:

Q = mc∆T

Where;

Q = quantity of heat absorbed

m = mass of substance

c = specific heat capacity

∆T = change in temperature

mc∆T (water) = -mc∆T (metal)

84.7 × 4.18 × 3.8 = - (22.7 × c × -72.7)

1345.375 = 1650.29c

c = 0.815J/g°C

Therefore, the specific heat of the metal object with a mass of 22.7g heated to to temperature of 97.0°C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C is 0.815J/g°C.

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Answer/Explanation:

The boy's muscle energy changes into potential energy due to the height. it then converts into kinetic energy as it goes further upwards into the air.

Answer:

6PbO +O2 --> 2Pb3O4

Explanation:

The question is incomplete I assume it is

PbO + 02 - Pb304

The amount of nitrogen oxide in the air sample is determined as 7.01 ppb.

The amount of Nitrogen oxide (NO2) in the air in parts per billion (ppb) is calculated as follows;

12 micrograms of NO2 = 12 μg = 12 x 10⁻⁶ g

PV = nRT

V = nRT/P

Where;

n = m/M

M = molar mass of NO2 = 46

n =  12 x 10⁻⁶/46

n = 2.73 x 10⁻⁷ mole

V = (2.73 x 10⁻⁷ x 0.082057 x 313)/(1)

V = 7.01 x 10⁻⁶ L

V =  7.01 x 10⁻⁹ m³

= (Volume of NO2)/(volume of air) x 10⁹

= (7.01 x 10⁻⁹)/(1) x  10⁹

= 7.01 ppb

Thus, the amount of nitrogen oxide in the air sample is determined as 7.01 ppb.

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The empirical formula of the hydrocarbon is [tex]C_2H_3[/tex] if combustion of 8.60 g of a hydrocarbon produced 26.5 g of [tex]CO_2[/tex] and 12.2 g of [tex]H_2O[/tex].

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule [tex]CH_2O[/tex] is the empirical formula for glucose.

1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.

Hence, in this case the mass of carbon in 8.46 g of [tex]CO_2[/tex]:

([tex]\frac{12}{44}[/tex]) × 8.46 = 2.3073 g

1 mole of water contains 18 g, out of which 2 g is hydrogen;

Therefore, 2.6 g of water contains;

([tex]\frac{2}{18}[/tex] × 2.6 = 0.2889 g of hydrogen.

Therefore, with the amount of carbon and hydrogen from the hydrocarbon, we can calculate the empirical formula.

We first calculate the number of moles of each,

Carbon = [tex]\frac{2.3073}{12}[/tex]  = 0.1923 moles

Hydrogen = [tex]\frac{0.2889}{1}[/tex]= 0.2889 moles

Then, we calculate the ratio of Carbon to hydrogen by dividing by the smallest number value;

            Carbon : Hydrogen

               [tex]\frac{0.1923}{0.1923}[/tex] : [tex]\frac{0.2889}{0.1923}[/tex]

                      1 :  1.5

                     (1 : 1.5) 2

                    = 2 : 3

Hence, the empirical formula of the hydrocarbon is [tex]C_2H_3[/tex].

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350 Kcal is equals to 350000 calorie and 1464400 Joule.

The equation for calculating the energy content of a food source via calorimetry is as follows: Energy (joules) = Mass of water (g) × 4.2 (J/gºC) × Temperature increase (ºC)

1 Kcal = 1000 calorie

Therefore,

35 Kcal = 350 x 1000

            = 350000 calorie

Now,

1 calorie = 4.184 joule

Therefore,

35000 calorie = 350000 x 4.184

                        = 1464400 joule

Hence, 350 Kcal is equals to 350000 calorie and 1464400 Joule.

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