Describe the transformations f(x)= square root 4x

Answer:

let amount of games won and lost be x and y respectively

y+18=x

x+y=78

y+y+18=78

2y=78-18

2y=60

y=30

x=30+18

x=48

thus, games won is 48

Answer:

Step-by-step explanation:

625

The closest answer choice is  [tex]27.52 units^2.[/tex]

The area of the circle, we need to find the area of one sector and then multiply it by 16 since there are 16 congruent sectors.

To find the area of one sector, we use the formula:

[tex]Area of sector = (angle/360) * \pi*r^2[/tex]

Since we know the base and height of the highlighted sector, we can use the Pythagorean theorem to find the radius of the circle:

[tex]r^2 = (1.56/2)^2 + (3.92)^2[/tex]

r ≈ 3.969 units

Now we can find the angle of one sector using the formula:

angle = (base/radius) x 180/π

angle ≈ 22.5 degrees

Plugging in the values for angle and radius in the area of sector formula, we get:

[tex]Area of sector =(22.5/360) *\pi (3.969)^2[/tex]

Area of sector ≈ 0.491π

Multiplying this by 16, we get the approximate area of the circle:

Approximate area of circle ≈ 16 x 0.491π

Approximate area of circle ≈ 7.8π

Using a calculator to approximate π as 3.14, we get:

Approximate area of circle ≈ [tex]24.46 units^2[/tex]

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The distance between the two scout patrols is approximately 11.66 kilometers.

We can see that the situation forms a right triangle with the hypotenuse representing the distance between the two scout patrols. Let's call this distance d.

Each patrol initially hikes 5 kilometers in opposite directions. This means that the distance between them at this point is 10 kilometers (5 km + 5 km).

Then, each patrol turns 90 degrees to their right and hikes 6 kilometers. This means that they travel along the legs of the right triangle, which have a length of 6 kilometers.

Using the Pythagorean theorem, we can solve for the hypotenuse:

d² = 10² + 6²

d² = 136

d ≈ 11.66 km

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Since it's a scale, we can take the backsides of both buses. They read 2in and 10ft

12 inches are in one foot, so 120 inches are in 10ft

Next we'll divide [tex]120\div2[/tex] and we get 60.

That's means we can multiply [tex]7 \times 60[/tex], getting 420 inches

To get it back to feet, we divide by 12

[tex]420\div12[/tex] = 35 feet

Therefore, The actual length of the bus is 35 feet

Answer:

its 35

Step-by-step explanation:

Flo ate more of the sandwich than Arnie.

Option A is the correct answer.

We have,

We need to compare the values 3/4 and 2/3 to determine which fraction represents a larger amount of sandwiches eaten.

To make the fractions comparable, we need to find a common denominator.

The least common multiple of 4 and 3 is 12.

So we can rewrite 3/4 and 2/3 with 12 as the denominator:

3/4 = 9/12

2/3 = 8/12

Comparing these fractions, we see that 9/12 (or 3/4) is greater than 8/12

(or 2/3).

Therefore,

Flo ate more of the sandwich than Arnie.

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The calculated width of the scale drawing is 0.67 cm and the missing side length is undefined

We have the following statements from the question

The above statements means that the width of the scale is

Scale width = 335 cm  * 1/500

When the products are evaluated, we have the following

Scale width = 0.67 cm

This means that the width of the scale drawing is 0.67 cm

Also, the missing side length of the original plot of land in meters cannot be calculated

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Answer:

BC= 47.424

I believe that’s correct, but if you really need an answer just get a triangle calculator

The missing number for box a transaction amount account balance are a = 10, b = 210, c = 210.

Using the information provided in the table, we can fill in the missing numbers as follows:

For transaction 3: The account balance after transaction 2 was $100, and transaction 3 had an amount of $90. Therefore, the account balance after transaction 3 is $190. Hence, the missing number in box a is 190.

For transaction 4: The account balance after transaction 3 was $190, and transaction 4 had an amount of -$200. Therefore, the account balance after transaction 4 is -$10. Hence, the missing number in box b is -10.

For transaction 5: The account balance after transaction 4 was -$10, and transaction 5 had an amount of $c. Therefore, the account balance after transaction 5 is 0. Hence, the missing number in box c is 10.

Therefore, the completed table is:

transaction amount account balance

1 150 150

2 50 100

3 90 190

4     -200-10

5 10 0

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Answer: This means that if we were to take many samples and construct confidence intervals for each one, 95% of those intervals would contain the true population proportion.

Step-by-step explanation:

a) To calculate the margin of error for this sample, we can use the formula:

Margin of error = Z√(p(1-p)/n)

where:

Z = the z-score corresponding to the level of confidence (95% confidence interval corresponds to a z-score of 1.96)

p = the sample proportion (290/400 = 0.725)

n = the sample size (400)

Plugging in these values, we get:

Margin of error = 1.96√(0.725(1-0.725)/400) ≈ 0.049

So, the margin of error for this sample is approximately 0.049 or 4.9%.

b) To construct a 95% confidence interval for the proportion of employed adults that live in San Luis and travel to Yuma or nearby to get to their workplaces, we can use the formula:

Confidence interval = p ± Z*(√(p*(1-p)/n))

where:

p = the sample proportion (0.725)

Z = the z-score corresponding to the level of confidence (1.96)

n = the sample size (400)

Plugging in these values, we get:

Confidence interval = 0.725 ± 1.96*(√(0.725*(1-0.725)/400)) ≈ (0.678, 0.772)

Therefore, we can say with 95% confidence that the proportion of employed adults that live in San Luis and travel to Yuma or nearby to get to their workplaces is between 0.678 and 0.772.

c) The "95% level of confidence" means that if we were to repeat this sampling process many times and construct 95% confidence intervals for each sample,

we would expect that 95% of those intervals would contain the true population proportion of employed adults that live in San Luis and travel to Yuma or nearby to get to their workplaces.

d) The confidence interval we constructed in (b) tells us that we can be 95% confident that the true population proportion of employed adults that live in San Luis and travel to Yuma or nearby to get to their workplaces is between 0.678 and 0.772.

This means that if we were to take many samples and construct confidence intervals for each one, 95% of those intervals would contain the true population proportion.

Based on this interval, we can conclude that it is likely that at least 65% of employed adults that live in San Luis travel to Yuma or nearby to get to their workplaces, as the lower bound of the interval is above 65%.

e) Whether or not it is worth it to invest in the new highway depends on many factors beyond just the proportion of employed adults that live in San Luis and travel to Yuma or nearby to get to their workplaces.

The decision to invest in the highway should be based on a careful cost-benefit analysis that takes into account factors such as the expected traffic volume, the expected economic benefits, and the cost of the project.

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The number of nickels and pennies in the pocket is 5 and 16 respectively.

To find the number of coins, Let's assume the number of nickels is x and the number of pennies is y.

According to the problem, we have two equations:

The total value of the coins is $0.41:

0.05x + 0.01y = 0.41

The total number of coins is 21:

x + y = 21

Now we can solve this system of equations to find x and y. One way to do this is to use substitution.

Solving the second equation for y, we get:

y = 21 - x

Substituting this into the first equation, we get:

0.05x + 0.01(21 - x) = 0.41

Simplifying:

0.05x + 0.21 - 0.01x = 0.41

0.04x = 0.2

x = 5

So we have 5 nickels.

Substituting this into the equation y = 21 - x, we get:

y = 21 - 5 = 16

So we have 16 pennies.

Therefore, the number of nickels and pennies in the pocket is 5 and 16 respectively.

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The distance between the airplane and the tower is approximately 1864.5 meters.

To solve this problem, we can use trigonometry. Let's draw a diagram to help us visualize the situation:

```
   T
  /|
 / |
/  | 500m
/a  |
--------
  x
```

In this diagram, "T" represents the control tower, "a" represents the airplane, and "x" represents the distance between them. We know that the height of the airplane is 500m, and the angle of depression from the tower to the airplane is 15 degrees. This means that the angle between the horizontal ground and the line from the tower to the airplane is also 15 degrees.

Using trigonometry, we can set up the following equation:

```
tan 15 = 500 / x
```

We can solve for "x" by multiplying both sides by "x" and then dividing by tan 15:

```
x = 500 / tan 15
```

Using a calculator, we can find that tan 15 is approximately 0.2679. Therefore:

```
x = 500 / 0.2679
x ≈ 1864.5m
```

So the distance between the airplane and the tower is approximately 1864.5 meters.

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The volume of the oblique cylinder whose base and height is given would be = 9,646.08 m³. That is option B.

To calculate the volume of a cylinder, the formula that should be used is given as follows:

Volume of a cylinder = πr²h

π = 3.14

R = diameter/2 = 16/2 = 8m

Height = 8²+48² (using the Pythagorean formula)

= 64+2304

=√ 2368

= 48.66cm³

The volume of the cylinder = 3.14 × 8×8×48.66

= 9,646.08 m³

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Answer:

Trapezoid.

Step-by-step explanation:

The equation Claude created is: 10 * (1.5)^t = 200,000,000, where t represents the number of hours.

Let A be the initial area of the fungus that covers the 10 square mile section of the planet.

After 1 hour, the fungus increases in size by 50%, which means it multiplies by 1.5. Thus, the area covered by the fungus after 1 hour is:

A + 1.5A = 2.5AAfter 2 hours, the fungus increases again by 50%, so its area becomes:

2.5A + 1.5(2.5A) = 6.25A

In general, after n hours, the area of the fungus becomes: A(1.5)^n

Since we want the fungus to cover the entire planet, we need to solve the following equation: A(1.5)^41 = 200,000,000

Simplifying, we get:

A = 200,000,000 / (1.5)^41

Therefore, the equation that Claude created is:

A(1.5)^n = 200,000,000

where n is the number of hours it takes for the fungus to cover the planet.

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The direction of fastest increase in temperature at the point (1, 3, 1) is given by the unit vector (-5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10)).

To find the direction of fastest increase in temperature at the point (1, 3, 1), we need to find the gradient of the temperature function T(x, y, z) at that point.

The gradient of a function is a vector that points in the direction of steepest increase, and its magnitude is the rate of change in that direction. So, we can find the gradient vector ∇T(x, y, z) as follows:

∇T(x, y, z) = ( ∂T/∂x , ∂T/∂y , ∂T/∂z )

=[tex]( -20xe^(-2x^2-y^2-3z^2) , -2ye^(-2x^2-y^2-3z^2) , -6ze^(-2x^2-y^2-3z^2) )[/tex]

Therefore, at the point (1, 3, 1), the gradient of T(x, y, z) is:

∇T(1, 3, 1) = [tex]( -20e^(-8) , -6e^(-8) , -18e^(-8) )[/tex]

To find the direction of fastest increase, we need to normalize this vector to a unit vector. The magnitude of the gradient vector is:

|∇T(1, 3, 1)| = sqrt( (-[tex]20e^(-8))^2 + (-6e^(-8))^2 + (-18e^(-8))^2 )[/tex]

= sqrt( 640e^(-16) )

= 8e^(-8) sqrt(10)

So, the unit vector in the direction of fastest increase is:

( -20e^(-8) / (8e^(-8) sqrt(10)) , -6e^(-8) / (8e^(-8) sqrt(10)) , -18e^(-8) / (8e^(-8) sqrt(10)) )

= ( -5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10) )

Therefore, the direction of fastest increase in temperature at the point (1, 3, 1) is given by the unit vector (-5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10)).

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To find the scale factor that takes polygon N to polygon P, you need to divide the corresponding side lengths of the two polygons.

To find the scale factor that takes polygon N to polygon P, you need to divide the corresponding side lengths of the two polygons.

For example, if one of the sides of polygon N is 6 units long, and the corresponding side of polygon P is 9 units long, then the scale factor is 9/6 or 1.5. This means that polygon P is 1.5 times larger than polygon N in all dimensions.

To determine the scale factor for all the corresponding sides of the polygons, you can compare each pair of sides and divide the length of the corresponding side of polygon P by the length of the corresponding side of polygon N.

It's important to note that when finding the scale factor between two polygons, you must compare corresponding sides. That is, you can't just choose any two sides to compare; you must compare the sides that are in the same position in the two polygons.

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The exact distance between the planes, using radicals as needed, is d = 6√62 / 62.

To find the distance d between the two planes 6x + 5y + z = 54 and 6x + 5y + z = 48, we can use the formula for the distance between parallel planes:

d = |C1 - C2| / √(A^2 + B^2 + C^2)

where A, B, and C are the coefficients of the x, y, and z terms respectively, and C1 and C2 are the constants in the two equations.

In this case, A = 6, B = 5, C = 1, C1 = 54, and C2 = 48. Plugging these values into the formula, we get:

d = |54 - 48| / √(6^2 + 5^2 + 1^2)
d = 6 / √(36 + 25 + 1)
d = 6 / √62

So the distance between the two planes is d = 6/√62. You can simplify this expression by rationalizing the denominator:

d = (6/√62) * (√62/√62)
d = 6√62 / 62

Thus, the exact distance between the planes, using radicals as needed, is d = 6√62 / 62.

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Answer:3,15,18.

Step-by-step explanation:

6:1:5 total ratio =6+1+5=12 so you’ll take all the numbers at different times so 6 will be divided by 12 and multiplied by36 (6/12)36= 18so the first number is nine do the same thing for the next ratio (1/12)36=3 thirdly(5/12)36=15 now add the three numbers to check whether they sum up to36(18+3+15=36)

To calculate the second derivative of a function, we need to take the derivative of the first derivative. The second derivative gives us information about the curvature of the function. A positive second derivative indicates that the function is concave up, while a negative second derivative indicates that the function is concave down. A second derivative of zero indicates that the function has no curvature at that point.

In the first example given, y = -5x^2 + x, we first find the first derivative by taking the derivative of the function with respect to x. This gives us dy/dx = -10x + 1. To find the second derivative, we take the derivative of dy/dx with respect to x. This gives us d²y/d²x = -10. This indicates that the function has a constant negative curvature, meaning it is concave down everywhere.

In the second example given, y = 7/x, we first find the first derivative by taking the derivative of the function with respect to x. This gives us dy/dx = -7/x^2. To find the second derivative, we take the derivative of dy/dx with respect to x. This gives us d²y/dx² = 14/x^3. This indicates that the function is concave up for positive values of x and concave down for negative values of x. The second derivative is undefined at x = 0, indicating a point of inflection.

Overall, the second derivative gives us important information about the behavior of a function and can help us identify points of inflection and concavity.
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Answer:

25%

Step-by-step explanation:

one 4th of 8,000 is 2,000 convert it to a percent and there you go!

Give brainliest please! Enjoy your night!

Answer:

b=18.7

Step-by-step explanation:

sin112°/37=sin28°/b

b=sin28°/(sin112°/37)

b=18.7

Sam can give pencils and pens to 14 classmates, with each classmate receiving 3 pencils and 4 pens (since 42 divided by 14 is 3, and 56 divided by 14 is 4).

Sam has 42 pencils and 56 pens, and he wants to distribute them equally among his classmates. To find the greatest number of classmates, we need to find the greatest common divisor (GCD) of 42 and 56.

The GCD of 42 and 56 is 14. Therefore, the greatest number of classmates Sam can give pencils and pens to is 14.

Each classmate will receive:
- 42 pencils / 14 classmates = 3 pencils per classmate
- 56 pens / 14 classmates = 4 pens per classmate

So, each of the 14 classmates will receive 3 pencils and 4 pens.

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The Rohe Theorem can be applied to on the dood inter - 2x-) -1.31 WS. No, because it is not continuous on the closed intervals.

To determine whether Rolle's Theorem can be applied to the given function (ignoring typos and irrelevant parts), we need to consider the requirements for Rolle's Theorem: the function must be continuous on a closed interval and differentiable on an open interval within that closed interval.
Your answer: B. No, because the function is not continuous on the closed intervals. This is due to the presence of irrelevant parts in the given function, which makes it impossible to determine its continuity and differentiability. Therefore, Rolle's Theorem cannot be applied in this case.

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The utility maximizing units of consumption are approximately 1 or 15 units, depending on other factors such as budget constraints and the specific preferences of the individual.

To find the utility maximizing units of consumption, we need to calculate the first derivative of the utility function (U) with respect to q and set it equal to zero. Here's the utility function:

U = 18q + 7q^2 - (1/3)q^3

Now, we'll find the first derivative (dU/dq):

dU/dq = 18 + 14q - q^2

To find the utility maximizing units, set dU/dq to zero and solve for q:

0 = 18 + 14q - q^2

Rearrange the equation:

q^2 - 14q + 18 = 0

Now, we'll solve for q using the quadratic formula:

q = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 1, b = -14, and c = 18. Plug these values into the formula:

q = (14 ± √((-14)^2 - 4 * 18)) / 2

q = (14 ± √(196 - 72)) / 2

q = (14 ± √124) / 2

The two possible solutions for q are:

q1 ≈ 1.27
q2 ≈ 14.73

Since the individual consumes discrete units, the utility maximizing consumption will be the whole number closest to these values.

Therefore, the utility maximizing units of consumption are approximately 1 or 15 units, depending on other factors such as budget constraints and the specific preferences of the individual.

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The value of the simplified expression is -15.

The simplification of the expression is determined by substituting the appropriate values of the variables into the equation.

The given expression; = 54/g - 8h

The value of g = 6 and the value of h = 3,

The value of the expression is calculated as follows;

= 54/g - 8h

= 54/6 - 8(3)

= 9 - 24

= - 15

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The complete question is below:

54/g - 8h, when g = 6 and h=3

The length of side AB is 6.3 units.

The length of side AB is solved using the distance formula below

AB = √((x₂ - x₁)² + (y₂ - y₁)²

where

(x₁, y₁) = (-9, 0) and

(x₂, y₂) = (-3, 2).

AB = √((-3 - (-9))² + (2 - 0)²)

AB = √(6² + 2²)

AB = √(40)

AB = 2√(10)

AB = 6.3245

AB = 6.3 to the nearest tenth

Therefore, the length of side AB is 6.3 units.

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Answer:

The population proportion is given as 58% or 0.58 in decimal form.

The sample size is given as 50 Americans.

Yes, the normal approximation can be used with this distribution because the sample size is sufficiently large (n=50) and the underlying population is assumed to be large enough to satisfy the independence requirement.

The mean of the sampling proportion (o) can be calculated using the formula:

mean = population proportion = 0.58

Therefore, the mean of the sampling proportion is 0.58 or 58%.

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Answer:

Here is the complete magic square:

-3 4 -1

2 0 -2

1 -4 3

Every row, column, and long diagonal adds to 0.