Describe the end behavior for the graph of y=-x³- ax + 3, if a is a constant.

Answer:

false fake false false false.............

Step-by-step explanation:

.....,........................

The approximate appreciation or depreciation we might see in the MXN/JPY cross exchange rate is 3%.

The term depreciation refers to an accounting method used to allocate the cost of a tangible or physical asset over its useful life. Depreciation represents how much of an asset's value has been used.

The approximate appreciation or depreciation we might see in the MXN/JPY cross exchange rate can be stated using the following 3 steps.

Step 1. State the initial exchange rates of the currency pairs.

Let first assume the initial exchange rates are as follows:

USD1 = JPY1

USD1 = MXN1

Therefore, we have the initial cross rate as follows:

MXN1 = USD1 = JPY1

MXN1 = JPY1

Step 2. Determine the new exchange rates

The new exchange rates can be determined as follows:

When the USD depreciates 2% versus the JPY, this implies that

USD1 X (100% + 2%) = USD1.02

has to be exchanged for JPY1.

Therefore, we now have:

USD1.02 = JPY1, or

USD1 = JPY1/1.02

USD1 = JPY0.98

Also, when The USD appreciates 1% versus the MXN, this implies that USD1  X  (100% - 1%) = USD0.99

has to be exchanged for MXN1.

Therefore, we now have:

USD0.99 = MXN1, or

USD1 = MXN1/0.99

USD1 = MXN1.01

Therefore, we have the new cross rate as follows:

MXN1.01 = USD1 = JPY0.98

MXN1.01 = JPY0.98

MXN1.01 / 1.01 = JPY0.98/1.01

MXN1 = JPY0.97, or

MXN1/0.97 = JPY0.97/0.97

MXN1.03 = JPY1

Therefore, the new exchange rates are as follows:

USD1.02 = JPY1

USD0.99 = MXN1

MXN1.03 = JPY1

c. Determination of appreciation or depreciation we might see in the MXN/JPY

Percentage of depreciation of MXN against JPY = ((Initial MXN/JPY - New MXN/JPY) / Initial MXN/YPY)  X 100 = ((1.03 - 1) / 1) * 100 = 3%

Since the percentage of depreciation of MXN against JPY is 3%, this also implies that the percentage of appreciation of JPY against MXN is 3%.

Thus, the approximate appreciation or depreciation we might see in the MXN/JPY cross exchange rate is 3%.

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Answer:

put 1/2as a value of x in the equation and then solve .then the answer will be -1

Answer:

[tex]C.\ f\left( \frac{1}{2} \right) =-1[/tex]

Step-by-step explanation:

[tex]f\left( x\right) =\frac{\sqrt{2x+3} }{6x-5}[/tex]

In order to calculate f(1/2) ,all we have to do

is replacing x by 1/2 in the expression of f.

Then

[tex]f\left( \frac{1}{2} \right) =\frac{\sqrt{2\left( \frac{1}{2} \right) +3} }{6\left( \frac{1}{2} \right) -5 }[/tex]

        [tex]=\frac{\sqrt{1+3} }{3-5}[/tex]

        [tex]=\frac{\sqrt{4} }{-2}[/tex]

        [tex]=\frac{2}{-2}[/tex]

        [tex]=-1[/tex]

The value could the length of the third side will be 11,12,13,15. Options B, D, E, and F are the correct answers.

A triangle is a three-sided polygon. It is one of the most fundamental geometric forms.

According to the triangle Inequality theorem, any two triangle sides must add up to more than the third side's length.

You may get the potential length of a triangle by multiplying the sum of two sides by the difference between two sides.

Therefore,

Let x is the possible length of the third side of a triangle.

14-4<x<15+4

10<x<19

The values of the third side is lies between the 10 and 19.The value could the length of the third side will be 11,12,13,15

Hence, options B, D, E, and F are the correct answers.

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Answer:

99°F

Step-by-step explanation:

The high temperature in city A was 93° F. On the same day, the high temperature in city B was -6° F.

The difference in temperature will be:

= 93 - (-6)

= 93 + 6

= 99

Answer:

[tex]9600cm^{2}[/tex]

Step-by-step explanation:

Get the area of the triangle and the rectangle, then subtract the triangle's area for the rectangle's

The next number in the sequence 7, 11, 2, 18, -7, would be -11.

A number pattern is a pattern in a series of numbers that represents the common relationship between the numbers.

Given sequence;

7, 11, 2, 18, -7,

We can see that the fifth term is similar to the first term, except for the negative.

So, we can conclude that the integers start from the fifth term and leads to the next term as a negative of the second one.

Therefore, The next number in the sequence 7, 11, 2, 18, -7, would be -11.

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This can be represented by [tex]\boxed{10(x+y)}[/tex]

The zeroes of the function will be [tex]\rm -1 \pm \dfrac{\sqrt{78}}{6}}[/tex]

A quadratic function is given by ax² +bx+c = f(x)

The given quadratic function is

f(x) = 6x² +12x - 7

The zeroes of the function will be given by

f(0) = 0

6x² +12x - 7 = 0

The zeroes are given by

[tex]\rm \dfrac {-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]

here

a = 6

b = 12

c = -7

Therefore the zeroes of the function will be

[tex]\rm \dfrac {-12 \pm \sqrt{12^2 -4*6*(-7)}}{2 *6}[/tex]

[tex]\rm \dfrac {-12 \pm \sqrt{312}}{12}[/tex]

[tex]\rm -1 \pm \dfrac{\sqrt{78}}{6}}[/tex]

Therefore these are the two zeroes of the function.

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Answer: -35/16

Step-by-step explanation:

[tex]f(8)=-5\\\\f(-8)=30\\\\\frac{f(8)-f(-8)}{8-(-8)}=\frac{-5-30}{16}=\boxed{-\frac{35}{16}}[/tex]

Answer:

11/4 Pi

Step-by-step explanation:

because 1.= 70/180.       (180.=Pi)

so 495 x 70/180

=11/4 Pi

The statement (d) Alaric's maths grade is the response variable is correct because maths grade is a dependent variable.

It is defined as the variable which is independent. They show the expected results and the result is known as the response variable which is dependent on the explanatory variable.

We have given:

Alaric wants to determine if he can get a better grade in maths by studying for longer periods of time.

The duration of the experiment is 4 weeks which is known or constant.

But the number of hours she studied is a variable, and it is independent.

The maths grade is the dependent variable which is on the number of hours Alaric study variable.

Thus, the statement (d) Alaric's maths grade is the response variable is correct because maths grade is a dependent variable.

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A bag contains 3 blue, 7 green and 1 purple counter. One counter is picked at random, the probability of selecting a green or purple counter is 8/11.

Probability is a measure of the likelihood or chance of an event occurring. It is usually expressed as a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to occur.

There are a total of 11 counters in the bag, 3 of which are blue, 7 are green, and 1 is purple.

The probability of selecting a green or purple counter is the sum of the probabilities of selecting a green counter and a purple counter, since the events are mutually exclusive (a counter cannot be both green and purple at the same time).

So the probability of selecting a green or purple counter is:

Probability = (Number of green counters + Number of purple counters) / Total number of counters

Probability = (7 + 1) / 11

Probability = 8/11

Therefore, the probability of selecting a green or purple counter is 8/11.

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Answer:

110

Step-by-step explanation:

Suppose lines EH and BD are parallel:

Angle <GFE and angle <ABC are supplementary so their sum is equal to 180

2x + 10 + x  + 20 = 180 add like terms

3x + 30 = 180 subtract 30 from both sides

3x = 150 divide both sides by 3

x = 50

We are asked the value of <ACD

<ABD and <ACD are also supplementary so we can find the value od <ACD:

x + 20 + <ACD = 180 we know x = 50 so we can replace x with that

50 + 20 + <ACD = 180

70 + <ACD = 180 subtract 79 from both sides

<ACD = 110

The farmer should purchase 2 bags of soil for his farm.

A parallelogram is a two-dimensional figure with four sides. It is a special case of the quadrilateral, where opposite sides are equal and parallel. The area of a parallelogram is the space enclosed within its four sides. Area is equal to the product of length and height of the parallelogram.

The shape of the farm, according to the picture is a parallelogram. Therefore, the total area can be calculated as follows:

Area = base X height

where

b = base

h = height

base = 6.5 + 2.5 = 9.0 yards

height = 6 yards

Area = 6 × 9 = 54 square yards.

40 square yards requires 1 bag of soil .

54 square yards will require ?

Bags required = 54 / 40 = 1.35 bag

Thus, the farmer will require 2 bags of soil for his farm.  

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Step-by-step explanation:

volume= l×w×h

1.1/3×1/2×2/3

=1/9

2. 3/4×1/8×13/16

=39/512

3. 1/12×7/8×1/4

=7/384

4. 3/2×1/7×7/8

=3/16

5. 1/5×9/10×2/3

=3/25

6.6/7×7/8×1/2

=3/8

Answer:

ai) m = 17, applicable past x = 23/17; aii) m = 4; applicable past 3 dad jokes

Step-by-step explanation:

to calculate slope you use the (y2 - y1) / (x2 - x1) equation

so for the first one

(62 - 11) / (5 - 2)

51 / 3 = 17

the equation for this is y = 17x + b

plug in values to find b

11 = 34 + b

b is -23

y = 17x - 23

because distance cannot be negative we must find when x is exactly 0 to find where it is applicable

17x = 23

x = 23/17

for the second one we can subtract again

(10 - 2) / (5 - 3)

8 / 2

4 is the slope

like before we must find b and then find where y is 0

y = 4x + b

2 = 12 + b

b = -10

y = 4x - 10

4x = 10

x = 5/2

since you cannot have 1/2 a dad joke we round up from 2 1/2 to 3

Answer:

420

Step-by-step explanation:

Answer:

V = 340 cm3

Step-by-step explanation:

Calculate the volume of the prism without the gap, then subtract the volume of the gap.

[tex]V=(5)(10)(8)-(3)(2)(10)=400-60=340cm^{3}[/tex]

Hope this helps

Answer: -8

Step-by-step explanation:

[tex]y=8-2(8)=\boxed{-8}[/tex]

Differentiate using the Quotient Rule –

[tex]\qquad[/tex][tex]\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\[/tex]

According to the given question, we have –

Let's solve it!

[tex]\qquad[/tex][tex]\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\[/tex]

[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\[/tex]

[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\[/tex]

[tex]\qquad[/tex][tex] \pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\[/tex]

[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\[/tex]

[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\[/tex]

[tex]\qquad[/tex][tex]\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\[/tex]

[tex]\qquad[/tex][tex]\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\[/tex]

[tex]3x+6-2 = 6x-( \frac{7}{2} \times \frac{9}{0} ) \\ \\ 3x + 4 = 6x - \frac{63}{0} \\ \\ 3x + 4 = 6x - 0 \\ \\ 4 + 0 = 6x - 3x \\ \\ 3x = 4 \\ \\ x = \frac{4}{3} .[/tex]

The value of x is 4/3 .

Answer: No Solution

Why?

Any number divided by 0 is not defined, but we are given 9/0 in the question. Hence we cannot solve the equation for the value of ‘x’.

The answer is (-1,1) and (1,5)

Using simple interest, it is found that the present value of the cash inflow is of 947.

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

In this problem, the parameters are given as follows:

r = 0.08, t = 4, A(t) = 1250.

We have to solve for A(0) to find the present value, hence:

A(t) = A(0)(1 + rt)

1250 = A(0)(1 + 0.08 x 4)

A(0) = 1250/1.32

A(0) = 947.

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Answer:

Cubic expression

Step-by-step explanation:

Polynomials with a degree of 3 are known as cubics.

Answer:

cubic expression

Step-by-step explanation:

it is cubic when raised to the power of 3

Answer:

Step-by-step explanation:

1/8

Answer:

x = -3

Explanation:

[tex]\rightarrow \sf \sqrt[3]{\sf 3x + 1} = -2[/tex]

[tex]\rightarrow \sf \sf 3x + 1 = (-2)^3[/tex]

[tex]\rightarrow \sf \sf 3x + 1 = -8[/tex]

[tex]\rightarrow \sf \sf 3x = -8-1[/tex]

[tex]\rightarrow \sf \sf 3x = -9[/tex]

[tex]\rightarrow \sf \sf x = -3[/tex]

Answer:

[tex]\sqrt[3]{3x+1} =-2\\(\sqrt[3]{3x+1})^{3} =(-2)^{3} \\3x+1=-8\\3x=-9\\x=-3[/tex]

Hope it helps!

Answer:

g-1(x)=5×-9, (g-1g) (1)=1, h-1(3)= -

Step-by-step explanation: