Answer:
Convection
Explanation:
Answer:
C. Convection
Explanation:
I just did it
In an illustration, lines of force are drawn around a magnet to illustrate the magnetic
O field.
O induction.
O poles.
O force.
Need help now
Answer: A. Field
Explanation: Magnetic Field is the correct answer.
Answer:
A
Explanation:
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what do you meant by significant figure?give different rules to clarify significant figure.
why are elements important
Answer: Scientists believe that about 25 of the known elements are essential to life. Just four of these – carbon, oxygen, hydrogen, and nitrogen– make up about 96% of the human body. Six common elements that are important in living things are carbon, hydrogen, oxygen, nitrogen, sulfur, and phosphorus. These large molecules make up the structures of cells and carry out many many processes essential to life.
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While you were at the skate park, what did you notice about potential and kinetic energy
Answer: I only know that the skater riding down the ramp increeses it's kinetic energy.
Explanation:
How do compounds differ from mixtures such as lemonade
Answer:
A mixture is a combination of two or more substances in any proportion. This is different from a compound, which consists of substances in fixed proportions. ... The lemonade pictured above is a mixture because it doesn't have fixed proportions of ingredients.
Explanation:
Which of the following is NOT a benefit of cool down activities?
Answer:
Blood is moved away from the brain
Explanation:
Took the test
Complete this problem so that it can be solved using the concept listed Angela is playing basketball
A. Acceleration
B. Speed
how can water be boiled in a paper cup?
Answer:
if you place a glass of boiling water in a paper cup filled with hot pads
Explanation:
am I thinking too deeply into this or does it make sense
Sometimes we will want to write vectors in terms of a coordinate grid. To show a vector points
horizontally (along the x-axis), place an x after the magnitude of the vector. To show a vector point
vertically (along the y-axis), place a y after the magnitude.
4) Using the notation above,
i. How would you write d1?
ii. How would you write d2?
iii. How would you write dtotal?
d1=(0,5)
d2=(5,5)
Answer:
III) [tex]d_{1}+ d_{2}=d_{t}[/tex]
Explanation:
I) coordinate (0,5) is the head for [tex]d_{1}[/tex] I will put the tail coordinate as (0,0) but it could be any other number in the x just not in the 5 with the the y being any other value.
II) coordinate (5,5) is the head for [tex]d_{2}[/tex] the tail needs to be in the head of [tex]d_{1}[/tex] being (0,5)
III) coordinates for [tex]d_{t}[/tex] is connecting the tail from [tex]d_{1}[/tex] and the head of [tex]d_{2}[/tex] making it (0,0)[tex](tail)[/tex] and (0,5)[tex](head)[/tex] and is written as [tex]d_{1}+ d_{2}=d_{t}[/tex]
(i) using coordinate grid notation to represent d₁, d₁ = 5y
(ii) using coordinate grid notation to represent d₂, d₂ = 5x + 5y
(ii) The sum of d₁ and d₂ is written as 5x + 10y
In order to show the horizontal direction of a vector, we will place x after the magnitude of the vector.
Also, to show the vertical direction of a vector, we will place a y after the magnitude of the vector.
(i) Using coordinate grid to represent d₁ = (0, 5)
[tex]d_1 = 0(x) + 5(y)\\\\d_1 = 5y[/tex]
(ii) Using coordinate grid to represent d₂ = (5, 5)
[tex]d_2 = 5x + 5y[/tex]
(iii) The total vector is written as;
[tex]d_1 + d_2 = 5y + (5x + 5y)\\\\d_1 + d_2 = 5y + 5x + 5y\\\\d_1 + d_2 = 5x + 10y[/tex]
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Question 7
Identify the correct Earth System in order from #1-4.
Reorder answers
1.Atmosphere
Reorder answers
2.Geosphere
Reorder answers
3.Hydrosphere
Reorder answers
4.Biosphere
Answer:
2, 3, 4, 1
Explanation:
geosphere, hydrosphere, biosphere, and atmosphere
Answer:
Lithosphere hydrosphere biosphere atmosphere
Explanation:
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Two vectors have magnitudes 20 m and 44 m. Which of the following cannot possibly be the magnitude of the resultant of the two vectors ?
Answer:
44M 64M
Explanation:
How many strings of length 10 over the alphabet (a, b, c, d] have at least one b somewhere in the string?
a) 310
b) 410 - 310
c) 10.4
d) 10.39
Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct option is B
Explanation:
The number of alphabet is n= 4 (a , b , c , d )
Generally the total number of string of length 10 over the 4 alphabets is
[tex]N = 4^{10}[/tex]
Gnerally the number of string of length 10 that does not include b is
[tex]T = 3^{10}[/tex]
Generally the number of strings of length 10 over the 4 alphabets that have at least one alphabet b somewhere in the string is
[tex]G = N - T[/tex]
=> [tex]G = 4^{10} - 3^{10}[/tex]
Electric Charge andStatic ElectricityIt was known as early as 600BCEthat objects could become charged by rubbing fur on various substances such as amber. Charged objects could be used to attract light objects such as hair. In the 1700s, it was determined that charge came in two varieties that could cancel each other out. Charles-Augustin de Coulomb established a quantitativerelation in 1783 that describes how charged objects interact via the electric force. The electric force:
Answer:
Explanation:
In 1785, Coulomb investigated quantitatively, the force exerted between point charges.
The Coulomb's Law states that: "The force of attraction or repulsion between two, point charges is directly proportional to the product of magnitude of the charges and inversely proportional to the square of the distance between them. "
If q₁ and q₂ are two, point charges and r is the distance between them, then the electric force of attraction or repulsion F between them, according to Coulomb’s law will be:
F ∝ q₁q₂ ________________________ eqn (1)
F ∝ 1/r² ________________________ eqn (2)
Combining eqn (1) and eqn (2), we get:
F ∝ (q₁ q₂)/r²
F = (kq₁q₂)/r²
where,
k = constant of proportionality = 9 x 10⁹ N.m² / C²
Scott travels north 2 miles and then goes west 5 miles before coming straight back south 7 miles what is his displacement
Answer:
Displacement is 5√2 miles
Explanation:
From south, Scott travelled 2 miles north and then 5 miles west then he came back south by 7 miles.
I've attached a diagram to indicate Scott's path travelled
Now, displacement is a vector quantity that tells us the overall change in position by Scott i.e distance from his initial position to his current final position while distance is a scalar quantity and tells us how much ground Scott covered in his motion over the entire trip.
Now, from the attached image, the displacement is denoted by "d".
d can be found from pythagoras theorem.
Thus;
d² = 5² + 5²
d = √50
d = 5√2 miles
1. A diver running 4 m/s dives out horizontally from the edge of a vertical cliff and lands 32 meters
from the cliff. How long was the diver in the air before they hit the water?
a. 125 seconds
c. 36 seconds
b. 8 seconds
d. 128 seconds
4. A teacher throws the stapler at her students 23 m in 1.2 seconds. What speed must the teacher throw the
stapler and what will be the staplers highest point during its flight?
dy = - 42gt2
dx = Vyt
Answer:
dy
Explanation:
My guess of guts.
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Compare the kinetic energy of a 21,000 kg truck moving at 130 km/h with that of an 84.0 kg astronaut in orbit moving at 28,000 km/h.
Answer:
K.E of the Astronaut is greater
Explanation:
Mathematically;
K.E = 1/2 * m * v^2
For the truck, the kinetic energy will be
1/2 * 21,000 * 130^2 = 177,450,000 J
while for the astronaut, his K.E will be
1/2 * 84 * 28,000^2 = 3.2928 * 10^10
This shows that the K.E of the astronaut is greater
A daring stunt woman sitting on a tree limb
wishes to drop vertically onto a horse gallop-
ing under the tree. The constant speed of the
horse is 6.8 m/s, and the woman is initially
1.91 m above the level of the saddle.
How long is she in the air? The acceleration
of gravity is 9.8 m/s.
Answer in units of s.
Answer:
she is in the air for approximately 0.62 seconds
Explanation:
We want to find the time for a free fall under the acceleration of gravity, covering a distance of 1.91 m, and considering that the woman doesn't impart initial velocity in the vertical direction. So we use the kinematic equation:
[tex]d=v_i\,t+ \frac{g}{2} \,t^21.91 = 0 +4.9\, t^2\\t^2=1.91/4.9\\t=\sqrt{1.91/4.9} \\t\approx 0.624\,\,sec[/tex]
Then she is in the air for approximately 0.62 seconds
According to American Heart Association, your target heart rate is__________.
Group of answer choices
A .all of the above
B. 85% - 95% of your max heart rate
C. 20%-30% of your max heart rate
D. 50%-85% of your max heart rate
Answer:
B
Explanation:
A normal heart rate is from 85-95% the other heart rate is not normal because your heart is beating more than normal
PLEASE HELP
A sharpshooter fires a 0.22 caliber rifle horizontally at 100 m/s at a target 75m away. How far does the
bullet drop by the time it reaches the target?
This question involves the concept of semi-projectile motion. It can be solved using the equations of motion in the horizontal and the vertical motion.
The bullet drops "2.76 m" by the time it reaches the target.
First, we will analyze the horizontal motion. We assume no air resistance, so the horizontal motion will be uniform. Hence, using the equation of uniform motion here to find the total time to reach the target:
[tex]s = vt\\\\t = \frac{s}{v}[/tex]
where,
s = distance = 75 m
v = velocity = 100 m/s
t = time = ?
Therefore,
[tex]t = \frac{75\ m}{100\ m/s}[/tex]
t = 0.75 s
Now, we will analyze the vertical motion of the bullet. We will use the second equation of motion in the vertical direction to find the height dropped by the bullet.
[tex]h = v_it+\frac{1}{2}gt^2[/tex]
where,
h = height dropped = ?
vi = initial vertical speed = 0 m/s
t = time interval = 0.75 s
g = acceleration due to gravity = 9.81 m/s²
therefore,
[tex]h = (0\ m/s)(0.75\ s)+\frac{1}{2}(9.81\ m/s^2)(0.75\ s)^2[/tex]
h = 2.76 m
Learn more about equations of motion here:
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The attached picture shows the equations of motion in the horizontal and vertical directions.
In the absence of a gravitational field, you could determine the mass of an object (of unknown composition) by:
A) applying a known force and measuring it's acceleration.
B) measuring the volume.
C) weighing it.
Answer:
A) By applying a known force, and measuring it's acceleration.
Explanation:
This is actually something that astronauts do in space as a mathmatical exercise when calculating the mass of an object since F = m × a.
Once the force, and acceleration are applied, the only unknown is the mass which can be solved by dividing force over acceleration. This is because inertial mass is equal to gravitational mass.
A force of 41 N acts on an object which has a mass of 2.4 kg. What acceleration (in m/s2) is produced by the force
Answer:
The acceleration is [tex] a = 17.083 \ m/s^2 [/tex]
Explanation:
From the question we are told that
The force is [tex]F = 41 \ N[/tex]
The mass of the object is [tex]m = 2.4 \ kg[/tex]
Generally the force is mathematically represented as
[tex]F = m* a[/tex]
=> [tex] 41 = 2.4* a[/tex]
=> [tex] a = 17.083 \ m/s^2 [/tex]
The velocity of a body travelling in a circular path can be measured with an uncertainty estimated at 4%. The Radius R of the circular path can be measured within 2%. What is the uncertainty associated with the determination of normal acceleration, a, from a = v^2/R Would it make much difference if the radius could be measured within 1%?
Answer:
a) uncertainty percentage = 10%
b) if R could be measured within 1%, uncertainty percentage is 9%,
it wouldn't make much difference
Explanation:
Given that;
velocity v = 4%
radius R = 2%
using calculation on errors / uncertainties in mumber,
To find error/uncertainty in aₙ
aₙ = V² / R
= V₂ × 1/R
V × V × 1/R
let U + V be x and relative error ΔV/V = 4% = 0.04
also, let R be Y and error (relative) ΔR/R = 2% = 0.02
so aₙ = V²/R = x² / y --------------------- let this be equ 1
Δaₙ/aₙ = ΔV/V + ΔR/R + ΔV/V {V×V×1/R}
Δaₙ/aₙ = 0.4 + 0.02 + 0.4
Δaₙ/aₙ = 0.1
so 0.1 × 100 = 10%
therefore uncertainty percentage = 10%
if R could be measured within 1%
Δaₙ/aₙ = (0.04 × 2) + 0.01
= 0.08 + 0.01
= 0.09
so 0.09 × 100
= 9%
therefore if R could be measured within 1%, uncertainty percentage is 9%,
it wouldn't make much difference
The current is suddenly turned off. How long does it take for the potential difference between points a and b to reach one-half of its initial value
Complete Question
The complete question is shown on the first uploaded image
Answer:
Explanation:
From the question we are told that
The original voltage is [tex]V_o[/tex]
The new voltage is [tex]V =\frac{V_o}{2}[/tex]
The capacitance is [tex]C = 150\ nF = 150 *10^{-9} \ F[/tex]
The first resistance is [tex]R_i = 26 \Omega[/tex]
The second resistance is [tex]R_E = 200 \Omega[/tex]
Generally the equivalent resistance is
[tex]R_e = R_1 + R_E[/tex]
=> [tex]R_e = 26 +200 [/tex]
=> [tex]R_e = 226 \ \Omega [/tex]
Generally the time constant is mathematically represented as
[tex]\tau = RC[/tex]
=> [tex]\tau = 226 * 150 *10^{-9}[/tex]
=> [tex]\tau = 3.39 *10^{-5} \ s [/tex]
Generally the voltage is mathematically represented as
[tex]V = V_o e^{-\frac{t}{\tau} }[/tex]
=> [tex]\frac{V_o}{2} = V_o e^{-\frac{t}{\tau} }[/tex]
=> [tex]0.5 = e^{-\frac{t}{\tau} }[/tex]
=> [tex]ln(0.5) = {-\frac{t}{ 3.39 *10^{-5} } }[/tex]
=> [tex]ln(0.5) * 3.39 *10^{-5} = -t [/tex]
=> [tex]t = 2.35*10^{-5} \ s [/tex]
Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley on frictionless bearings. The other end of this string supports a second similar pulley, over which passes a second string supporting a mass of 3m at one end and m at the other. Using two suitable generalized coordinates, set up the Lagrangian and use the Lagrange equations to find the acceleration of the mass 4m when the system is released. Explain why the top pulley rotates even though it carries equal weights on each side.
Answer:
Hello your question is incomplete attached below is the complete question
Answer : x ( acceleration of mass 4m ) = [tex]\frac{g}{7}[/tex]
The top pulley rotates because it has to keep the center of mass of the system at equilibrium
Explanation:
Given data:
mass suspended = 4 meters
mass suspended at other end = 3 meters
first we have to express the kinetic and potential energy equations
The general kinetic energy of the system can be written as
T = [tex]\frac{4m}{2} x^2 + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2[/tex]
T = [tex]4mx^2 + 2my^2 -2mxy[/tex]
also the general potential energy can be expressed as
U = [tex]-4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant[/tex]
The Lagrangian of the problem can now be setup as
[tex]L =4mx^2 +2my^2 -2mxy +2mgy + constant[/tex]
next we will take the Euler-Lagrange equation for the generalized equations :
Euler-Lagrange equation = [tex]4x-y =0\\-2y+x +g = 0[/tex]
solving the equations simultaneously
x ( acceleration of mass 4m ) = [tex]\frac{g}{7}[/tex]
The top pulley rotates because it has to keep the center of mass of the system at equilibrium
dimensional formula of stress is same as
Dimensional formula of stress is same as pressure.
Consider the trajectories of a projectile that experiences drag due to air resistance. Maximum range is achieved by launching the projectile at ________.
a. An angle less than 45 degrees.
b. An angles of 45 degrees.
c. An angle greater than 45 degrees.
d. An angle that depends on the launch speed
Answer:
Maximum range is achieved by launching the projectile at an angles of 45 degrees.
so the answer is B
Explanation:
What is the range of a projectile?
this can be defined as the maximum horizontal distance covered by a projectile
R=v^2sin(2θ)/2g
Why is 45 degrees maximum range?
"The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range puts 2θ = 90 degrees and, therefore, θ = 45 degrees."
Hence a projectile, travels the farthest when it is launched at an angle of 45 degrees
A cat chases a mouse for a distance of 9.0 m over 16 s before getting tired. What is the cats average speed?
Answer:
The answer is 0.56 m/sExplanation:
The speed of the cat can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{9}{16} = \\ = 0.5625[/tex]
We have the final answer as
0.56 m/sHope this helps you
A lamp of mass m hangs from a spring scale which is attached to the ceiling of an elevator. When the elevator is stopped at the fortieth floor, the scale reads mg. What does it read as the elevator slows down to stop at the ground floor?
a. more than mg
b. mg
c. less than mg
d. zero
e. can't tell
Answer:
The correct answer is (a)
Explanation:
A spring scale measures the weight of an object not the mass because according to hooke's law the extension of a spring is directly proportional to the load or force attached/applied to it. The force of gravity acting on the mass of any substance as it goes up actually reduces and increases as it comes down.
If F = ma, as a increases, F will also increase and vice versa
Where F = force
m = mass
a = acceleration (due to gravity in this case)
From the above explanation, it can be deduced that the scale will read more than mg as it gets to the ground because of an increase in the force of gravity (which also increases a) as it approaches the ground.
The drawing shows two identical airplanes at an air show. The airplanes are flying at the same speed. Airplane W is flying 50 m higher than airplane X. Which statement best describes the energy of the two airplanes?
Answer:
Airplane X has more gravitational potential energy than Airplane W
Explanation:
Gravitational potential energy is defined as "the energy acquired by an object due to its positional change in presence of gravitational force."
That being said, gravitational potential energy depends on the height of an object above the ground. It also depends on the mass of the object and even further, the amount of gravitational force that is applied.
And if we take a look at the question again, we'd agree that the two airplanes are flying at different heights, this means their gravitational potential energy will be different. And as such, Airplane X has more gravitational potential energy than Airplane W
