Create a program that asks the user to enter grade scores. Use a loop to request each score and add it to a total. Continue accepting scores until the user enters a negative value. Finally, calculate and display the average for the entered scores.

Answer:

This program is written using python

It uses less comments (See explanation section for more explanation)

Also, see attachments for proper view of the source code

Program starts here

#Prompt user for price of package 1

price1 = int(input("Enter Price 1: "))

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

#Prompt user for weight of package 1

weight1 = int(input("Enter Weight 1: "))

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

#Calculate Unit of Package 1

unit1 = float(price1/weight1)

print("Unit cost of Package 1: "+str(unit1))

#Prompt user for price of package 2

price2 = int(input("Enter Price 2: "))

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

#Prompt user for weight of package 2

weight2 = int(input("Enter Weight 2: "))

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

#Calculate Unit of Package 2

unit2 = float(price2/weight2)

print("Unit cost of Package 2: "+str(unit2))

#Compare units

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Explanation:

price1 = int(input("Enter Price 1: ")) -> This line prompts the user for price of package 1

The following while statement is executed until user inputs a value greater than 1 for price

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

weight1 = int(input("Enter Weight 1: ")) -> This line prompts the user for weight of package 1

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

unit1 = float(price1/weight1) -> This line calculates the unit cost (per weight) of package 1

print("Unit cost of Package 1: "+str(unit1)) -> The unit cost of package 1 is printed using this print statement

price2 = int(input("Enter Price 2: ")) -> This line prompts the user for price of package 2

The following while statement is executed until user inputs a value greater than 1 for price

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

weight2 = int(input("Enter Weight 2: ")) -> This line prompts the user for weight of package 2

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

unit2 = float(price2/weight) -> This line calculates the unit cost (per weight) of package 2

print("Unit cost of Package 2: "+str(unit2)) -> The unit cost of package 2 is printed using this print statement

The following if statements compares and prints which package has a better unit cost

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Answer:

Raid

Explanation:

Answer: provided in the explanation section

Explanation:

// code to copy

Car.java

public class Car {

  public void m1()

  {

  System.out.println("car 1");

}

  public void m2() {

      System.out.println("car 2");

}

  public String toString()

  {

  return "vroom";

}

}

Truck.java

public class Truck extends Car{

  public void m1()

  {

  System.out.println("truck 1");

  }

  public void m2()

  {

  super.m1();

  }

  public String toString()

  {

      return super.toString() + super.toString();

  }

}

MonsterTruck​​​​​​​.java

public class MonsterTruck extends Truck

{

  public void m1() {

System.out.println("monster 1");

}

public void m2() {

super.m1();

super.m2();

}

public String toString() {

return "monster " + super.toString();

}

public static void main(String[] args) {

  MonsterTruck mt=new MonsterTruck();

  mt.m1();

  mt.m2();

  System.out.println(mt);

}

}

cheers i hope this helped !!!

Answer:

yooooooooooooooooooooo

Explanation:

Answer:

Here is the Python program.

characters = 0

words = 0

lines = 0

def file_stats(in_file):

   global lines, words, characters

   with open(in_file, 'r') as file:

       for line in file:

           lines = lines + 1

           totalwords = line.split()

           words = words + len(totalwords)

           for word in totalwords:

               characters= characters + len(word)

file_stats('created_equal.txt')

print("Number of lines: {0}".format(lines))

print("Number of words: {0}".format(words))

print("Number of chars: {0}".format(characters))

Explanation:

The program first initializes three variables to 0 which are: words, lines and characters.

The method file_stats() takes in_file as a parameter. in_file is the name of the existing text file.

In this method the keyword global is used to read and modify the variables words, lines and characters inside the function.

open() function is used to open the file. It has two parameters: file name and mode 'r' which represents the mode of the file to be opened. Here 'r' means the file is to be opened in read mode.

For loop is used which moves through each line in the text file and counts the number of lines by incrementing the line variable by 1, each time it reads the line.

split() function is used to split the each line string into a list. This split is stored in totalwords.

Next statement words = words + len(totalwords)  is used to find the number of words in the text file. When the lines are split in to a list then the length of each split is found by the len() function and added to the words variable in order to find the number of words in the text file.

Next, in order to find the number of characters, for loop is used. The loop moves through each word in the list totalwords and split each word in the totalwords list using split() method. This makes a list of each character in every word of the text file. This calculates the number of characters in each word. Each word split is added to the character and stored in character variable.

file_stats('created_equal.txt')  statement calls the file_stats() method and passes a file name of the text file created_equal.txt as an argument to this method. The last three print() statements display the number of lines, words and characters in the created_equal.txt text file.

The program along with its output is attached.

Answer:

Insertion query for first row :

INSERT into Invoice_Line_Items (invoice_sequence, account_number, line_item_amount, line_item_description) Values (1, 160, '$180.23', "Hard drive Exchange");

Insertion query for second row :

INSERT into Invoice_Line_Items (invoice_sequence, account_number, line_item_amount, line_item_description) Values (2, 527, '$254.35', "Server update");

Explanation:

* In SQL for insertion query, we use INSERT keyword which comes under DML (Data manipulation Language).

* Statement is given below -

INSERT into Table_name  (column1, column2, ....column N) Values (value1, value2, .....value N);

* With the use of INSERT query we can insert value in multiple rows at a same time in a table which reduces our work load.

Answer:

Following are the algorithm to this question:

Find_Heavier_Coins(Coin[9]):

   i) Let Coin[] Array represent all Coins.  

   ii) Divide coin[] into 3 parallel bundles and each has three coins, example 0-2, 3-5, 6-8 indicate a1 a2 a3

   iii) Randomly select any two bundles and place them in balance [say a1 and a2]

   iv) If Weigh of a1 and a2 has same:

           // checking that if a3 has heavier coin

           Choose any two 6-8 coins and place them onto balance [say 6 and 8]

           If those who weigh has the same weight:

               Third coin is coin heavier [say 7]

           else:  

               The coin [6 or 8] is the one which is heavier on the balance

       else:

           //The coin has the package which would be heavier on the balance [say a1]

           Select any two coins on balance from of the heavier package [say 0 and 1]

   If they weigh the same weight:

       Third coin is coin heavier [say 2]

   else:

       The coin that is heavier on the balance is the [or 0]

Explanation:

In the above-given algorithm code, a method Find_Heavier_Coins is declared which passes a coin[] array variable in its parameters. In the next step, if conditional block is used that checks the values which can be described as follows:

Explanation:

search engine because it helps to search find what you are expecting to search in the google.

Answer: Provided in the explanation section

Explanation:

The Question says;

Identify a logical operation (along

with a corresponding mask) that, when

applied to an input string of 8 bits,

produces an output string of all 0s if and

only if the input string is 10000001.​

The Answer (Explanation):

XOR, exclusive OR only gives 1 when both the bits are different.

So, if we want to have all 0s, and the for input only 10000001, then we have only one operation which satisfies this condition - XOR 10000001. AND

with 00000000 would also give 0,

but it would give 0 with all the inputs, not just 10000001.

Cheers i hope this helped !!

Answer:

i think html

Explanation:

Answer:

Web browser

Explanation:

Answer:

The csharp program is given below.

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;

namespace WindowsFormsApplication1

{

   public partial class Form1 : Form

   {

       public Form1()

       {

           InitializeComponent();

      }

       private void button6_Click(object sender, EventArgs e)

       {

           int total = (Convert.ToInt32(textBox1.Text) +  Convert.ToInt32(textBox2.Text) + Convert.ToInt32(textBox3.Text) + Convert.ToInt32(textBox4.Text) + Convert.ToInt32(textBox5.Text));

           int dozen = total / 12;

           int eggs = total % 12;

           textBox6.Text = dozen.ToString();

           textBox7.Text = eggs.ToString();

       }

       private void button7_Click(object sender, EventArgs e)

       {

           textBox1.Text = "";

           textBox2.Text = "";

           textBox3.Text = "";

           textBox4.Text = "";

           textBox5.Text = "";

           textBox6.Text = "";

           textBox7.Text = "";

       }

        private void button8_Click(object sender, EventArgs e)

       {

           Close();

       }

    }

}

Explanation:

1. The integer variables are declared for total eggs, number of dozens and number of eggs.

2. The input of each text box is converted into integer by using the Convert.ToInt32() method on the value of that particular text box.

3. All the inputs are added and the sum is assigned to variable, total.

4. The number of dozens are obtained by dividing total by 12 and assigning the value to the variable, dozen.

5. The number of extra eggs are obtained by taking the modulus of total and 12 and the value is assigned to the variable, eggs.

6. The integer values in the variables, dozen and eggs, are converted into string using the ToString() function with that particular value.

dozen.ToString();

eggs.ToString();

7. The text boxes are assigned the respective values of dozens and number of eggs.

textBox6.Text = dozen.ToString();

textBox7.Text = eggs.ToString();

8. Two additional buttons, clear and exit, are also added.

9. The clear button erases the contents of all the text boxes. The Text property of each textbox is set to “” thereby clearing all the text fields.

10. The exit button closes the application using Close() function.

11. The program is made in visual studio and the output is attached.

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Answer and Explanation:

Therefore, the load-balancing requirements for keeping about the same number of threads would be retained and the meaningful matter of top priority thread would also be retained.

Based on the information given, it is important to give higher priority to the queue that contains the high priority thread.

Also, once an element from the high priority queue is dequeued, then dequeue one thread from the queue containing low priority thread and this will be enqueued into the queue having high priority thread in order to balance the number of threads.

Since the priority queue automatically adjusts the thread, hence the removal of the thread from one priority queue to another is not a problem.

Learn more about threads on:

https://brainly.com/question/8798580

Answer:

=PMT(C6,C8,C4)

Put that in cell c9

Then use the lower right of the cell to drag it from D9:F9

In this exercise we have to use excel knowledge, so we have to:

=PMT(C6,C8,C4) in the cell C9 and extended to D9:F9

PMT, one of the financial functions, calculates the payment for a loan based on constant payments and a constant interest rate. Use the Excel Formula Coach to figure out a monthly loan payment.

For this we need to put the form as:

=PMT(C6,C8,C4)

See more about excel at brainly.com/question/12788694

Answer: Provided in the explanation section

Explanation:

C++ Code

#include<iostream>

#include<fstream>

#include<string>

using namespace std;

// read plain text from file

void readPlaneText(char *file,char *txt,int &size){

  ifstream inp;

  inp.open(file);

  // index initialize to 0 for first character

  int index=0;

  char ch;

  if(!inp.fail()){

      // read each character from file  

      while(!inp.eof()){

          inp.get(ch);

          txt[index++]=ch;

      }

  }

  // size of message

  size=index-1;

}

// read key

int **readKey(char *file,int **key,int &size){

  ifstream ink;

  //

  ink.open(file);

      if(!ink.fail()){

          // read first line as size

      ink>>size;

      // create 2 d arry

      key=new int*[size];

      for(int i=0;i<size;i++){

          key[i]=new int[size];

      }

      // read data in 2d matrix

      for(int i=0;i<size;i++){

          for(int j=0;j<size;j++){

              ink>>key[i][j];

          }  

      }

  }

  return key;

}

// print message

void printText(string txt,char *msg,int size){

  cout<<txt<<":\n\n";

  for(int i=0;i<size;i++){

      cout<<msg[i];

  }

}

// print key

void printKey(int **key,int size){

  cout<<"\n\nKey matrix:\n\n";

  for(int i=0;i<size;i++){

      for(int j=0;j<size;j++){

          cout<<key[i][j]<<" ";

      }  

      cout<<endl;

  }

}

void encrypt(char *txt,int size,int **key,int kSize,char *ctxt){

  int *data=new int[kSize];

  for(int i=0;i<size;i=i+kSize){  

  // read key size concecutive data

      for(int a=0;a<kSize;a++){

          data[a]=txt[i+a]-'a';

      }

      // cipher operation

      for(int a=0;a<kSize;a++){

          int total=0;

          for(int b=0;b<kSize;b++){

              total+=key[a][b]*data[b];

          }  

          total=total%26;

          ctxt[i+a]=(char)('a'+total);

      }      

  }

}

int main(int argc,char **argv){

  char text[10000];

  char ctext[10000];

  int **key;

  int keySize;

  int size;

  // input

  key=readKey(argv[1],key,keySize);

  readPlaneText(argv[2],text,size);

  encrypt(text,size,key,keySize,ctext);

  // output

  printKey(key,keySize);

  cout<<endl<<endl;

  printText("Plaintext",text,size);

  cout<<endl<<endl;

  printText("Ciphertext",ctext,size);

  return 0;

}

cheers i hope this helped !!!

Answer:

Explanation:

To begin, i will like to break this down to its simplest form to make this as simple as possible.

Let us begin !

Here statement can be translated as: ∃x (P(x) ∧ M(x))

we require the Negation: ¬∃x (P(x) ∧ M(x))

De morgan's law can be stated as:

1) ¬(a ∧ b) = (¬a ∨ ¬b)

2) ¬(a v b) = (¬a ∧ ¬b)

Also, quantifiers are swapped.

Applying De Morgan's law, we have: ∀x (¬P(x) ∨ ¬M(x)) (∃ i swapped with ∀ and intersecion is replaced with union.)

This is the translation of above

English: Every patient was either not given the placebo or did not have migrane(or both).

cheers i hope this helped !!

Answer:

A.) True is the answer hope it helps

Answer: Provided in the explanation section

Explanation:

import java.util.Scanner;

public class commission

{

   public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

        int totals[]={0,0,0,0,0,0,0,0,0};          

      int n,sales,i,index;

       double salary;

        System.out.print("how many salesmen do you have? ");                          

      n=input.nextInt();

        for(i=1;i<=n;i++)

           {System.out.print("Salesman "+i+" enter sales: ");

            sales=input.nextInt();

            salary=200+(int)(.09*sales);

               System.out.printf("Salary=$%.2f\n",salary);

            index=(int)salary/100-2;

            if(index>8)

                index=8;

            totals[index]++;

            }

        System.out.println("SUMMARY\nSALES\t\tCOUNT");

        for(i=0;i<8;i++)

           System.out.println("$"+(i*100+200)+"-"+(i*100+299)+"\t"+totals[i]);

        System.out.println("$1000 and over\t"+totals[i]);

       }                                

   }

cheers i  hope this helped !!      

Answer:

#include<iostream>

using namespace std;

int main()

{

float price;

float discount;

cout<<"enter price : ";

cin>>price;

discount=price - (price * 20 / 100);

cout<<"discount rate is :"<<discount;

}

Explanation: