Chris is constructing a diagram for a deck he is restructuring in his backyard. The deck will be in the shape of a square, and he
has labeled a side length with the equation below, where x represents the original deck area.
side length = V1 + 12

Answer:

y = 1/2x + 4

Step-by-step explanation:

Slope intercept form is y = mx + b, where m is the slope and b is the y-intercept.

When we count rise over run, we find that the slope is 1/2

y = 1/2x + b

The line intersects the y-axis at 4, so the y-intercept is 4.

y = 1/2x + 4

I hope this helps :))

Tell me if it is right

Answer:

213, 123

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Because it would have less weight to carry

Answer:

Number line A.

Step-by-step explanation:

|-5x| - 11 = -1

Add 11 to both sides.

|-5x| = 10

-5x = 10 or -5x = -10

x = -2 or x = 2

Answer: Number line A.

Answer: 95 degrees

Step-by-step explanation:

We can infer than angles 1, 4, 5, 8 are all equal and angles 2, 3, 6, 7 are also equal to eachother. These two sets of angles are supplementary(you’d get 180 by adding them)

So 3x+10=4x-15

if you rearrange you'll get

x=25

therefore angle 1 equals

3*25+10=85

angle 1 and 7 are supplementary

thus angle 7 equals

180-85=95

Answer:

9.52% probability of getting both candies green

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the candies are selected is not important. They are also selected without replacement. So we use the combinations formula to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Find the probability of getting both candies green

Desired outcomes:

2 green, from a set of 5. So

[tex]D = C_{5,2} = \frac{5!}{2!3!} = 10[/tex]

Total outcomes:

2 from a set of 4+5+6 = 15. So

[tex]T = C_{15,2} = \frac{15!}{2!13!} = 105[/tex]

Probability:

[tex]p = \frac{D}{T} = \frac{10}{105} = 0.0952[/tex]

9.52% probability of getting both candies green

Answer: it is b because 2.5 lbs = 40 oz. then i know that 40 is half of 80 then there is not way it is the 1000 pound choice

Step-by-step explanation:

Answer:

all real x

Step-by-step explanation:

-3(x-1) > -3x - 2​

Distribute

-3x +3> -3x -2

Add 3x to each side

-3x +3 +3x > -3x+3x - 2​

3 > -2

This is always true so the inequality is true for all x

Answer:

157.6

Step-by-step explanation:

Use PEMDAS! In this rule, it is stated that we should always add/subtract before multiplying/dividing. Also, whatever you do on one side of an equation, you do to another. Therefore, in order to get rid of the -2/5, add 2/5 so we can get rid of it. We also (according to the rule), have to add it to the other side in order to balance out. So add the 2/5 to 39. Then the other side is now 39.4. Now we have to get x by itself. Divide both sides by 1/4 (or multiply by 4 on both sides) in order to get x=157.6

Answer:

28.45.

Step-by-step explanation:

5 x 5.69

Answer: LIKLEY

Step-by-step explanation:

Formula : Probability [tex]=\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}[/tex]

A standard cube has six numbers on it (1,2,3,4,5 and 6).

P( NOT 6) =[tex]\dfrac{\text{Numbers that are not 6}}{\text{Total numbers}}[/tex]

[tex]=\dfrac{5}{6}=0.8333[/tex]

We know that when the probability of any event lies between 0.5 and 1then the event is said to be likely to happen.

Since , P(not 6)=0.8333 which lies between 0 and 0.5.

That means, it is likely to happen.

Note :

When probability of having A = 0 , we call A as uncertain event.

When probability of having A = 1 , we call A as certain event.

When probability of having A = 0.5 , we call A as equally likely event.

When probability of having A lies between 0 and 0.5 , we call A as unlikely event.

When probability of having A lies between 0.5 and 1 , we call A as likely event.

Answer:

2044

Step-by-step explanation:

just follow the story

a person uses a

hanger (2)

to pop a

ball  (0)

then flies

two kites (44)

Answer:

1). 2044

Step-by-step explanation:

The story includes: a hanger, a ball, and two kites (in that order)

From the information given, a hanger is 2, a ball is 0, and a kite is 4.

So it would be 2044.

Answer:

Thus; the slope is positive

Step-by-step explanation:

Given that :

the sample size = 20

for the slope; the degree of freedom df = n - 2

= 20 -2

= 18

Using ∝ = 0.05

From t -table , one tailed, at df =18)

[tex]t_{\alpha , df}}= t_{0.05, df = 18} = 1.734[/tex]

Thus the t- critical for the right tailed test is 1.734. This simply refers to the fact that the critical region is test statistics.

Incorporating the Excel Formula [ T.INV (1 - 0.05).18) = 1.734063607

≅ 1.734

Answer:

Classifications would include

Rational; Fraction; Can be turned into Decimal; Positive

Those would be classifications

Answer: rational number, 0.375

Step-by-step explanation:

Answer:

Step-by-step explanation:

We will first translate the situation to propositional logic. First, some notation is needed: [tex]\lor[/tex] is the or logical operation and [tex]\implies[/tex] is the symbol for logical implication. Define the following events:

J: Jose took the jewelry. L: Mrs Krasov lied, C: a crime was committed. T: Mr Krasov  was in town.

We will symbol the propositions in logical symbols. Recall that [tex]\neg[/tex] means negation

If Jose took the jewelry or Mrs. Krasov lied, then a crime was committed: [tex]J\lor L \implies C[/tex]

Mr. Krasov was not in town: [tex]\neg T[/tex]

If a crime was committed, then Mr. Krasov was in town: [tex]C\implies T[/tex]

We want to check if the conclusion Jose did not take the jewerly: [tex]\neg J[/tex] can be deduced from the premises.

First, recall the following:

- if [tex] a\implies b[/tex] and a is true, then b is true.

- [tex] a\implies b[/tex] is logically equivalent to [tex]\neg b \implies a[/tex]

Coming back to the problem, we have the following premises

[tex]J\lor L \implies C, \neg T, \neg T \implies \neg C, \neg C \implies \neg(J\lor L)[/tex]

where the equivalence for the logical implication was applied. REcall that the negation of an or  statement is g iven by

[tex] \neg( a \lor b ) = \neg a \land \neg b [/tex] where [tex] \land[/tex] is the and logical operator.

USing this, we get the premises

[tex]J\lor L \implies C, \neg T, \neg T \implies \neg C, \neg C \implies \neg J\land \neg L[/tex]

Since [tex]\neg T[/tex], by having [tex]\neg T \implies \neg C[/tex], then it must be true that [tex]\neg C[/tex]. Since [tex]\neg C \implies \neg J\land \neg L[/tex], then it must be true that [tex] \neg J\land \neg L[/tex]. This final conclusion implies that it is true that [tex]\neg J[/tex] which is the statement that Jose did not take the jewelry.

Answer:

A. Schaid draws a white sock and a green sock. It did not talk about no green sock

Step-by-step explanation:

Answer:

y = 1/4x + (any number)

Step-by-step explanation:

m = -8/2 = -4, the equation shown is y = -4x + 8

perpendicular is  y = 1/4x + (any number), you didn't say where the line was perpendicular.

Answer:

1 ton = 2,000 pounds

Step-by-step explanation:

With that said, 22,000 pounds is 11 tons because 2,000 x 11 = 22,000.

So 22,000 pounds is 11 tons.

Hope it helps and pls mark me brainliest if it did! :)

Answer:

At a significance level of 0.05, there is enough evidence to claim that there is a significant relationship between x and y.

P-value = 0.003.

Step-by-step explanation:

If we perform a regression analysis relating x and y, we get the best fitting line with equation:

[tex]y=15.82x+92.9[/tex]

and a correlation coefficient r:

[tex]r=0.693[/tex]

We have to test the hypothesis, where the alternative hypothesis claims that there is a relationship between these two variables, and the null hypothesis claiming there is no relationship (meaning that the correlation is not significantly different from 0).

This can be written as:

[tex]H_0: \rho=0\\\\H_a:\rho\neq0[/tex]

where ρ is the population correlation coefficient for x and y.

The significance level is assumed to be 0.05.

The sample size is n=16.

The degrees of freedom are df=14.

[tex]df=n-2=16-2=14[/tex]

The test statistic can be calculated as:

[tex]t=\dfrac{r\sqrt{n-2}}{\sqrt{1-r^2}}=\dfrac{0.693\sqrt{14}}{\sqrt{1-(0.693)^2}}=\dfrac{2.593}{0.721}=3.597[/tex]

For a test statistic t=2.05 and 14 degrees of freedom, the P-value is calculated as:

[tex]\text{P-value}=2\cdot P(t>3.597)=0.003[/tex]

The P-value (0.003) is smaller than the significance level (0.05), so the effect is significant enough.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to claim that there is a significant relationship between x and y.

Answer:

1) cpk < 1.33, therefore it is not capable

b) cpk = 1.33, therefore it is capable

c) cpk < 1.33, therefore it is not capable

2) Cpk can never be greater than the Cp, but can be equal to it

Step-by-step explanation:

Upper limit (USL) = 47 minutes and Lower limit (LSL) = 30 minutes

1)

a) mean (μ) = 37 minutes, standard deviation (σ) = 3 minutes

[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-37}{3*3},\frac{37-30}{3*3} )=min(1.11,0.78)=0.78[/tex]

[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*3}=0.94[/tex]

cpk < 1.33, therefore it is not capable

b) mean (μ) = 38 minutes, standard deviation (σ) = 2 minutes

[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-38}{3*2},\frac{38-30}{3*2} )=min(1.5,1.33)=1.33[/tex]

[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*2}=1.42[/tex]

cpk = 1.33, therefore it is capable

c) a) mean (μ) = 38.5 minutes, standard deviation (σ) = 2.9 minutes

[tex]cpk=min(\frac{USL-\mu}{3\sigma}, \frac{\mu - LSL}{3\sigma})=min(\frac{47-38.5}{3*2.9},\frac{38.5-30}{3*2.9} )=min(0.98,0.98)=0.98[/tex]

[tex]cp=(\frac{USL-LSL}{6\sigma})=\frac{47-30}{6*2.9}=0.98[/tex]

cpk < 1.33, therefore it is not capable

2) Cpk can never be greater than the Cp, but can be equal to it

Answer:

t

Step-by-step explanation:

both t and s represent x axis value, t is greater as is on the right side from s  

Answer: t

Step-by-step explanation: khan academy

Multiply her savings by the percent spent:

850 x 0.35 = 297.50

The tv cost $297.50

Answer:

the price of TV is = 297.5$

Step-by-step explanation:

all money= 850$

purchased money= 35% of all money ==> 850 ( 35%) = 297.5$

Answer:

25% decrease

Step-by-step explanation:

Take the original price and subtract the new price

450-337.50 =112.50

Divide by the original price

112.50/450=.25

Multiply by 100% to change to percent form

25%

Answer:

Slope is 4

slope of the line perpendicular to it: x=-1/4

Answer:

18×18×36

Step-by-step explanation:

According to the Question

108≥ 4h + w

Volume V is given by

V = wh^2

⇒V= (108-4h)h^2

⇒V= 108h^2 - 4h^3

Now differentiating and keeping = 0 we get

V' = 216h - 12h^2 = 0

h = 216/12 = 18

w = 108 - 4×18 = 36

V = 36×18^2 = 11664 from a box of 18×18×36.

Answer:

Rectangle C is 14 cm longer than B

Step-by-step explanation:

Let  x be the length of Rectangle A. Rectangle B is ¹/₅ longer than A Block B,

Therefore the length of rectangle B is:

[tex]x+\frac{1}{5}x[/tex]

Rectangle C is ¹/₃ longer than B, therefore the length of rectangle c is:

[tex]x+\frac{1}{5}x+\frac{1}{3}(x+\frac{1}{5}x) =x+ \frac{1}{5}x+\frac{1}{3}x+\frac{1}{15}x=x+\frac{9}{15}x[/tex]

The total length of all three rectangles is 133 cm.

Length of rectangle A + Length of rectangle B + Length of rectangle C = 133 cm

[tex]x+x+\frac{1}{5}x +x+\frac{9}{15}x=133\\x+x+x+\frac{1}{5}x +\frac{9}{15}x=133\\3x+\frac{12}{15}x=133\\ 45x+12x=1995\\57x=1995\\x=35cm[/tex]

Therefore the length of rectangle A is 35 cm, the length of rectangle B is [tex]35+\frac{1}{5}*35=42\ cm[/tex] and the length of rectangle C is [tex]35+\frac{9}{15}*35=56\ cm[/tex]

Rectangle C is ¹/₃ longer than B, which is 14 cm (42\3) longer than B

Answer:

D :)

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Braily please