Carlos spots an airplane on radar that is currently approaching in a straight line, and that will fly directly overhead. the plane maintains a constant altitude of 7275 feet. carlos initially measures an angle of elevation of 20°
∘
to the plane at point aa. at some later time, he measures an angle of elevation of 37°
∘
to the plane at point bb. find the distance the plane traveled from point aa to point bb. round your answer to the nearest foot if necessary.

The value of the investment at the end of 6 years is $6,359.77 if the interest is compounded annually, $6,416.52 if it is compounded quarterly, and $6,437.70 if it is compounded monthly.

[tex]A = P(1 + r/n)^{nt}[/tex]

where A is the final amount, P is the initial investment, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the number of years.

A. If the interest is compounded annually, we have:

A = [tex]5,500(1 + 0.0155/1)^{1*6}[/tex] = $6,359.77

B. If the interest is compounded quarterly, we have:

A = [tex]5,500(1 + 0.0155/4)^{4*6[/tex] = $6,416.52

C. If the interest is compounded monthly, we have:

A = [tex]5,500(1 + 0.0155/12)^{12*6[/tex] = $6,437.70

Therefore, the value of the investment at the end of 6 years is $6,359.77 if the interest is compounded annually, $6,416.52 if it is compounded quarterly, and $6,437.70 if it is compounded monthly.

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Pythagorean Theorem: a^2 + b^2 = c^2

---a and b are the legs of the triangle

---c is the hypotenuse/diagonal

a = 6

b = 1

c = ?

(6)^2 + (1)^2 = c^2

36 + 1 = c^2

37 = c^2

c = 6.0827

c (rounded) = 6.1

Answer = 6.1 meters

To find the volume of the solid generated by revolving the given region about the y-axis, we can use the method of cylindrical shells.

First, we need to sketch the region and the axis of rotation to visualize the solid. The region is a parabolic shape that extends from y = -4 to y = 4, and the axis of rotation is the y-axis.

Next, we need to set up the integral that represents the volume of the solid. We can slice the solid into thin cylindrical shells, each with radius r = x and height h = dy. The volume of each shell is given by:

dV = 2πrh dy

where the factor of 2π accounts for the full revolution around the y-axis. To express r in terms of y, we can solve the equation x = v5y2 for x:

x = v5y2
r = x = v5y2

Now we can integrate this expression for r over the range of y = -4 to y = 4:

V = ∫-4^4 2πr h dy
 = ∫-4^4 2π(v5y2)(dy)
 = 80πv5

Therefore, the volume of the solid generated by revolving the given region about the y-axis is 80πv5 cubic units.
To find the volume of the solid generated by revolving the region enclosed by x = √(5y²), x = 0, y = -4, and y = 4 about the y-axis, we can use the disk method.

The disk method involves integrating the area of each circular disk formed when the region is revolved around the y-axis. The area of each disk is A(y) = πR², where R is the radius of the disk.

In this case, the radius is the distance from the y-axis to the curve x = √(5y²), which is simply R(y) = √(5y²).

So the area of each disk is A(y) = π(√(5y²))² = 5πy²

Now, we can find the volume by integrating A(y) from y = -4 to y = 4:

Volume = ∫[A(y) dy] from -4 to 4 = ∫[5πy² dy] from -4 to 4

= 5π∫[y²2 dy] from -4 to 4

= 5π[(1/3)y³] from -4 to 4

= 5π[(1/3)(4³) - (1/3)(-4³)]

= 5π[(1/3)(64 + 64)]

= 5π[(1/3)(128)]

= (5/3)π(128)

= 213.67π cubic units

The volume of the solid generated by revolving the region enclosed by x = √(5y²), x = 0, y = -4, and y = 4 about the y-axis is approximately 213.67π cubic units.

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Without a specific set of scatterplots to examine, I can provide some general guidelines for labeling scatterplots based on their association:

1. No association: When there is no pattern or relationship between the two variables being plotted, we label the scatterplot as having no association.

2. Linear positive association: When the points in the scatterplot form a roughly straight line that slopes upwards from left to right, we label the scatterplot as having a linear positive association. This means that as the value of one variable increases, the value of the other variable also tends to increase.

3. Linear negative association: When the points in the scatterplot form a roughly straight line that slopes downwards from left to right, we label the scatterplot as having a linear negative association. This means that as the value of one variable increases, the value of the other variable tends to decrease.

4. Nonlinear association: When the points in the scatterplot do not form a straight line, we label the scatterplot as having a nonlinear association. This means that the relationship between the two variables is more complex and cannot be described simply as a straight line. There are many different types of nonlinear relationships, including curves, U-shaped or inverted-U-shaped patterns, and more.

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The probability that a student at Kennedy High School plays on the football team given that they already play in the band is 2/1 or simply 2.

To solve this problem, we can use conditional probability. We want to find the probability that a student plays on the football team given that they already play in the band.

Let's use the formula for conditional probability:

P(Football | Band) = P(Football and Band) / P(Band)

We know that P(Band) = 0.15, and P(Football and Band) = 0.3.

So,

P(Football | Band) = 0.3 / 0.15

Simplifying, we get:

P(Football | Band) = 2

Therefore, the probability that a student at Kennedy High School plays on the football team given that they already play in the band is 2/1 or simply 2.

Note: This answer may seem unusual because probabilities are typically expressed as fractions or decimals between 0 and 1. However, in this case, we can interpret the result as saying that students who play in the band are twice as likely to also play on the football team compared to the overall population of students.

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The ratio of hours spent at soccer practice to hours spent at a birthday party can be represented as 2 for every 3

To provide an accurate ratio, I would need the specific number of hours spent at both soccer practice and the birthday party.

Once you provide that information, you can create the ratio by putting the two numbers in the form 2 for every 3.

For example, if you spent 3 hours at soccer practice and 2 hours at a birthday party, the ratio would be 3:2. This means that for every 3 hours spent at soccer practice, you spent 2 hours at the birthday party.

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The table shows how many hours Sara spent at several activities one Saturday.

Activity "Hours

Soccer practice 2

Birthday party 3

Science project 1

What is the ratio of hours spent at soccer practice to hours spent at a birthday party?

Choose 1 answer:

1 for every 2

B

2 for every 1

2 for every 3

3 for every 2

The theoretical probability of rolling a one or two on a number cube is 2/5 or 0.4.

To find the theoretical probability of rolling a one or two on a number cube, we need to determine the number of outcomes that correspond to rolling a one or two, and divide that by the total number of possible outcomes.

From the table, we can see that Alexandria rolled a one or two a total of 24 times out of 60 rolls. This means that the probability of rolling a one or two is: P(1 or 2) = 24/60

Simplifying the fraction by dividing both the numerator and denominator by the greatest common factor, we get: P(1 or 2) = 4/10

This can be further reduced to: P(1 or 2) = 2/5

Therefore, the theoretical probability of rolling a one or two on a number cube is 2/5 or 0.4.

In summary, the theoretical probability is the expected probability of an event occurring, based on mathematical reasoning. Here, we used the number of favorable outcomes to calculate the probability of rolling a one or two, and expressed the answer as a fraction in simplest form.

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using the given similar triangles, the length of the lake is approximately 26.05 meters.

We have,

In the given similar triangles, we have the following information:

Length of the longer side of the larger triangle: AC = 215m

Length of the longer side of the smaller triangle: A'C = 50m

Length of the corresponding shorter side of the smaller triangle: A'B = 112m

Let's denote the length of the lake (the longer side of the smaller triangle) as x.

Now, we can set up a proportion between the sides of the two triangles:

AC / A'C = A'B / x

Substitute the given values:

215 / 50 = 112 / x

Now, solve for x:

215x = 50 * 112

Divide both sides by 215:

x = (50 * 112) / 215

x ≈ 26.05

Thus,

The length of the lake is approximately 26.05 meters.

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The complete question:

To measure the length of a lake, the following similar triangles were built, in which it is necessary to: AC = 215m, A'C= 50m, A'B=112m. What is the length of the lake?

All the Bruces together weigh a total of 154 pounds.

If each Bruce weighs 11 pounds and there are 14 Bruces, we can calculate the total weight by multiplying the weight of each Bruce by the number of Bruces.

Weight of each Bruce: 11 pounds

Number of Bruces: 14

To find the total weight, we multiply 11 pounds by 14 Bruces:

Total weight = 11 pounds/Bruce * 14 Bruces

           = 154 pounds

Therefore, all the Bruces together weigh a total of 154 pounds.

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The perimeter and area of the shape is 18cm² and 12cm respectively.

The perimeter of a shape is the total measurement of all the edges of a shape. Area is defined as the total space taken up by a flat (2-D) surface or shape of an object.

The perimeter of the shape = 4+4+5+5 = 8 +10

= 18cm.

The area of the shape is = b×h

the base = 4cm and height is 3cm

A = 4× 3

= 12cm²

therefore the perimeter and the area of the shape is 18cm² and 12cm² respectively.

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Answer: 161.2

Step-by-step explanation:

Plug into formula

6.9² = 13²+17.8²-2(17.8)(13) cos C      >simplify numbers

-438.23 = -2(17.8)(13) cos C               >Divide both sides by  -2(17.8)(13)

cos C=.947                                         > use   [tex]cos^{-1}[/tex] C  to solve for angle

<C=180-18.75 = 161.2                          > neded to subtract from 180 for this                    

                                                                one

To draw a line segment with endpoint at 1.6 and length 1.2, draw a number line and mark 1.6. Measure 1.2 units to left of 1.6 and mark the starting point. Connect the starting and endpoint.

To draw a line segment with an endpoint at 1.6 and a length of 1.2, we can follow these steps

Draw a number line and mark the point 1.6.

From the point 1.6, measure a distance of 1.2 units in the direction of the negative numbers.

Mark the endpoint of the line segment at the point where the distance of 1.2 units ends.

Draw the line segment connecting the endpoint at 1.6 to the starting point.

In the diagram, the starting point is marked with at 0.4, and the endpoint is marked with at 1.6, which is 1.2 units away from the starting point. The line segment connecting the starting point to the endpoint is shown as a horizontal line.

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Answer:

0.80x400

Step-by-step explanation:

The radius of the lake is approximately 17.89 feet.

To find the radius of the lake, we can use the information given and apply the properties of tangents to circles.

Since point B is the point of tangency, the line segment AB is tangent to the circle. A radius drawn to the point of tangency, in this case from the center of the lake (point O) to point B, will be perpendicular to the tangent line (line AB).

Now, let's use the given measurements. The distance from the duck (point C) to the point of tangency (point B) is 16 feet, and the distance from the duck (point C) to the edge of the lake in the direction of A (line AC) is 8 feet. We can form a right-angled triangle OBC with the given information.

Since OB is perpendicular to AB, we have a right-angled triangle with legs CB and OC. Using the Pythagorean theorem, we can find the length of the hypotenuse, which is the radius of the lake:

OC^2 + CB^2 = OB^2
(8 feet)^2 + (16 feet)^2 = OB^2
64 + 256 = OB^2
320 = OB^2
OB = √320
OB ≈ 17.89 feet

So, the radius of the lake is approximately 17.89 feet.

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The answer is not 9 > 6, as that is a comparison between two numbers, but rather g ≤ 6, as it sets a limit on the number of goldfish that can be in the tank.

The correct inequality that represents the situation is g ≤ 6. The problem states that the maximum number of goldfish that can live in a small tank is 6, meaning that the number of goldfish must be less than or equal to 6.

The symbol ≤ represents "less than or equal to", while the symbol > represents "greater than".

Therefore, the answer is not 9 > 6, as that is a comparison between two numbers, but rather g ≤ 6, as it sets a limit on the number of goldfish that can be in the tank.

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Answer:

To estimate the positive solution to the equation x⁴ – x = 3 using Newton's Method, we can start by taking the derivative of the equation, which is 4x³ - 1. Then we can use the formula X1 = X0 - f(X0) / f'(X0), where X0 = 1, f(X0) = 1⁴ - 1 - 3 = -3, and f'(X0) = 4(1)³ - 1 = 3. Plugging these values into the formula, we get:

X1 = 1 - (-3) / 3

X1 = 2

Now we can repeat the process using X1 as our new X0:

X2 = X1 - f(X1) / f'(X1)

X2 = 2 - (2⁴ - 2 - 3) / (4(2)³ - 1)

X2 ≈ 1.7708

Therefore, the positive solution to the equation x⁴ – x = 3, rounded to four decimal places, is approximately 1.7708.

Step-by-step explanation:

The positive solution to the equation x⁴ – x = 3, estimated using Newton's Method with x₀ = 1 and x₂ as the final estimate, is approximately 1.5329, rounded to four decimal places.

To use Newton's Method to estimate the positive solution to the equation x⁴ – x = 3, we need to find the derivative of the function f(x) = x⁴ – x. This is given by:

f'(x) = 4x³ - 1

We can then use the formula for Newton's Method:

x(n+1) = x(n) - f(x(n)) / f'(x(n))

where x(n) is the nth estimate of the solution.

Starting with x₀ = 1, we can plug this into the formula to get:

x₁ = 1 - (1^4 - 1 - 3) / (4(1^3) - 1) ≈ 1.75

We can then repeat this process using x₁ as the new estimate, to get:

x₂ = 1.75 - (1.75^4 - 1.75 - 3) / (4(1.75^3) - 1) ≈ 1.5329

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Charlie drove 90 miles between San Antonio and Houston.

Nicholas and Rose each drove 2/5 of the total distance (190 miles). To find the distance they drove together, multiply 190 miles by 2/5 twice (once for each person):

190 x (2/5) = 76 miles (Nicholas)
190 x (2/5) = 76 miles (Rose)

Together, Nicholas and Rose drove 76 + 76 = 152 miles. To find the remaining distance Charlie drove, subtract this combined distance from the total distance:

190 miles (total) - 152 miles (Nicholas and Rose) = 38 miles (Charlie).

Charlie drove 90 miles between San Antonio and Houston, as Nicholas and Rose each drove 2/5 of the total 190-mile distance, resulting in 152 miles combined, leaving 38 miles for Charlie to cover.

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Answerx = 131.25

Step-by-step explanation:f x varies directly as T, then we can use the formula for direct variation:

x = kT

where k is the constant of proportionality.

To find k, we can use the given values:

x = 105 when T = 400

105 = k(400)

k = 105/400

k = 0.2625

Now that we have the value of k, we can use the formula to find x when T = 500:

x = kT

x = 0.2625(500)

x = 131.25

Therefore, when T = 500, x is equal to 131.25.

To simplify the expressions and arrange the terms by their degree, we can write:

$\longrightarrow\sf\textbf\:f(x)\:= -x^4\:+\:2x^2\:-\:5x\:+\:3$

$\longrightarrow\sf\textbf\:=\:-x^4 + 2x^2 - x - 4x + 3$

$\longrightarrow\sf\textbf\:=\:-x(x^3 - 2x + 1) - 4x + 3$

$\longrightarrow\sf\textbf\:g(x)\:=\:x^4 + 4x^2 + 2x + 1$

$\longrightarrow\sf\textbf\:x^4 + 4x^2 + 2x + 1 - 2 + 2$

$\longrightarrow\sf\textbf\:x^4 + 4x^2 + 2x - 1 + 2$

$\longrightarrow\sf\textbf\:x^4 + 4x^2 + 2x - 1 + 2$

$\longrightarrow\sf\textbf\:x^4 + 4x^2 + 2x + 1 - 2$

$\longrightarrow\sf\textbf\:(x^2 + 1)^2 - 2$

Therefore, we can express the simplified forms of ${\sf{\textbf{f(x)}}}$ and ${\sf{\textbf{g(x)}}}$ as:

$\longrightarrow\sf\textbf\:f(x)\:=\:-x(x^3 - 2x + 1) - 4x + 3$

$\longrightarrow\sf\textbf\:g(x)\:=\:(x^2 + 1)^2 - 2$

[tex]\huge{\colorbox{black}{\textcolor{lime}{\textsf{\textbf{I\:hope\:this\:helps\:!}}}}}[/tex]

[tex]\begin{align}\colorbox{black}{\textcolor{white}{\underline{\underline{\sf{Please\: mark\: as\: brillinest !}}}}}\end{align}[/tex]

[tex]\textcolor{blue}{\small\textit{If you have any further questions, feel free to ask!}}[/tex]

[tex]{\bigstar{\underline{\boxed{\sf{\textbf{\color{red}{Sumit\:Roy}}}}}}}\\[/tex]

The length of GC is 22.5

Here we know that the triangles GHC and JKC are similar, we know that the corresponding angles are congruent.

That is, angle GHC is equal to angle JKC, angle HGC is equal to angle KJC, and angle CHG is equal to angle CKJ.

∠GHC = ∠JKC

∠HGC = ∠KJC

∠CHG = ∠CKJ

We can denote this as:

ΔGHC ~ Δ JKC

Using the concept of similarity, we can write the following proportion:

GC/ JK = HC/ KC

Here, GC represents the length of the corresponding side of triangle GHC, and JK represents the length of the corresponding side of triangle JKC. HC and KC represent the lengths of the other sides that are also proportional.

We can cross-multiply to get:

GC × KC = HC × JK

Now, we can substitute the values we know.

=> x * 20 = 18 x 25

=> x = 22.5

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To find the values of a and b, we need to ensure that the function is differentiable at x = 1. Thus, the function defined by f(x) = x^2 + 3x + a, x <= 1 and bx + 2, x >= 1 differentiable at x = 1 are a = 3 and b = 5.

First, we need to check that the function is continuous at x = 1. Since the function has different definitions for x <= 1 and x >= 1, we need to check that the limit of the function as x approaches 1 from both sides is the same.

Limit as x approaches 1 from the left (x <= 1):

f(x) = x^2 + 3x + a

lim x->1- f(x) = lim x->1- (x^2 + 3x + a) = 1^2 + 3(1) + a = 4 + a

Limit as x approaches 1 from the right (x >= 1):

f(x) = bx + 2

lim x->1+ f(x) = lim x->1+ (bx + 2) = b + 2

For the function to be continuous at x = 1, these two limits must be equal.

4 + a = b + 2

a = b - 2

Now we need to check that the derivative of the function at x = 1 exists and is equal from both sides.

Derivative of the function for x <= 1:

f(x) = x^2 + 3x + a

f'(x) = 2x + 3

f'(1) = 2(1) + 3 = 5

Derivative of the function for x >= 1:

f(x) = bx + 2

f'(x) = b

f'(1) = b

For the function to be differentiable at x = 1, these two derivatives must be equal.

5 = b

Substituting b = 5 into the equation we found earlier for a, we get:

a = 5 - 2 = 3

Therefore, the values of a and b that make the function defined by f(x) = x^2 + 3x + a, x <= 1 and bx + 2, x >= 1 differentiable at x = 1 are a = 3 and b = 5.
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Answer:

It is a trapezoid

Step-by-step explanation:

Yes, the given points represent the vertices of a trapezoid.

A trapezoid is a quadrilateral with one set of parallel sides. In this case, the parallel sides are AB and CD. The other two sides, AD and BC, are not parallel.

The trapezoid is not isosceles because the two non-parallel sides are not congruent. AD has a length of 6 units, while BC has a length of 4 units.

Here is a diagram of the trapezoid:

A(-4,-1)

B((-4,6)

C(2,6)

D(2,-4)

A trapezoid is a quadrilateral with at least one pair of parallel sides. In this case, sides AB and CD are parallel because they have the same slope. So, the given points do represent the vertices of a trapezoid.

An isosceles trapezoid has two congruent legs (non-parallel sides). In this case, the length of side AD is `sqrt((-4-2)^2+(-1+4)^2)=sqrt(36+9)=sqrt(45)` and the length of side BC is `sqrt((-4-2)^2+(6-6)^2)=sqrt(36+0)=sqrt(36)`. Since `sqrt(45)` is not equal to `sqrt(36)`, the trapezoid is not isosceles.

The given ordered pairs (4, 0.5), (2.5, 4.5), (0.5,3), and (2, 0) are plotted on the coordinate plane as shown in the graph below.

From the question, we are to plot the given ordered pairs on the coordinate plane

To plot the given ordered pairs, we will determine the location of the point on the coordinate plane

We will look at the first number in the ordered pair (the x-coordinate) and find that value on the x-axis. Also, we will look at the second number (the y-coordinate) and find that value on the y-axis.

Now, we will plot the point where the x-coordinate and y-coordinate intersect. The point is represented by a dot.

The ordered pairs are plotted on the coordinate plane as shown in the graph below.

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Answer:

1,400

Step-by-step explanation:

its the same thing as 7 times 200

The number of monkeys when number of monkeys varies inversely to the number of clowns is 45.  

Inverse proportion is a mathematical relationship between two variables, in which an increase in one variable causes a proportional decrease in the other variable, and a decrease in one variable causes a proportional increase in the other variable.

In other words, the two variables vary in such a way that their product remains constant.

Here we have

10 monkeys vary inversely when there are 18 clowns.

We can set up the inverse variation equation as:

=> monkey ∝ 1/clown

If k is the constant of proportionality.

=> Monkey (clown) = k

It is given that when there are 10 monkeys, there are 18 clowns, so we can write:

=> (10)(18) = k

Solving for k, we get:

k = (10 x 18) = 180

Now we can use this value of k to find the number of monkeys when there are 4 clowns:

=> monkey = k/clown = 180/4 = 45

Therefore,

The number of monkeys when number of monkeys varies inversely to the number of clowns is 45.  

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The slope of the line that is represented by the given data in the question is 3/4.

To find the slope of a line, we need to use the formula:

slope = (change in y) / (change in x)

We can choose any two points on the line and use their coordinates to calculate the change in y and the change in x. Let's choose the points (-9, 4) and (7, 16) from the given data.

Change in y = 16 - 4 = 12

Change in x = 7 - (-9) = 16

Plugging these values into the slope formula, we get:

slope = 12 / 16 = 3 / 4

We can also interpret this slope as the rate of change of y with respect to x. For every increase of 1 in x, y increases by 3/4. Similarly, for every decrease of 1 in x, y decreases by 3/4.

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The only value of x where f'(x) = 0 is x = 0.

Let's find all values of x where the derivative of f(x) = [tex]arcsin(e^(2x) – 2x)[/tex] is equal to 0.

Step 1: Find the derivative f'(x) using the chain rule.

For this, we'll need to differentiate [tex]arcsin(u)[/tex] with respect to u, which is [tex](1/√(1-u^2))[/tex], and then multiply by the derivative of u [tex](e^(2x) – 2x)[/tex]with respect to x. So, f'(x) = [tex](1/√(1-(e^(2x) – 2x)^2)) * d(e^(2x) – 2x)/dx[/tex]

Step 2: Find the derivative of e^(2x) – 2x with respect to x. Using the chain rule and the derivative of [tex]e^u: d(e^(2x) – 2x)/dx = 2e^(2x) – 2[/tex]

Step 3: Combine the derivatives. f'(x) =[tex](1/√(1-(e^(2x) – 2x)^2)) * (2e^(2x) – 2)[/tex]

Step 4: Set f'(x) equal to 0 and solve for x. [tex](1/√(1-(e^(2x) – 2x)^2)) * (2e^(2x) – 2) = 0[/tex]

Since the first part of the product [tex](1/√(1-(e^(2x) – 2x)^2))[/tex] is never 0, we can focus on the second part: [tex]2e^(2x) – 2 = 0[/tex]

Step 5: Solve for x. [tex]2e^(2x) = 2 e^(2x) = 1[/tex]

The only way this is true is when 2x = 0, since [tex]e^0 = 1: 2x = 0 x = 0[/tex]

So, the only value of x where f'(x) = 0 is x = 0.

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Answer:

a^4 - b^4

Step-by-step explanation:

a(a - b) + b(a - b) + (a - b)^2  -->  Given

a^2 - ab + b(a - b) + (a - b)^2  -->  Distributive Property

a^2 - ab + ba - b^2 + (a - b)^2  -->  Distributive Property

a^2 - ab + ba - b^2 + a^2 - b^2  -->  Distributive Property

a^4 - ab + ba - b^2 - b^2  -->  Combine Like Terms

a^4 + 0 - b^2 - b^2  -->  Combine Like Terms (a * b = b * a)

a^4 - b^4 -->  Combine Like Terms

The temperature of City A and City B on that day was 4°C and 3°C respectively.

Let x represent the temperature of city A and y represent the temperature of city B.

Four times the temperature of City A was 7° C more than three times the temperature of City B, hence:

4x = 3y + 7

4x - 3y = 7       (1)

The temperature of City A minus three times the temperature of City B was −5° C, hence:

x - 3y = -5        (2)

From both equations, solving simultaneously:

x = 4, y = 3.

The temperature of City A and City B on that day was 4°C and 3°C respectively.

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